Answer:
Explanation:
a )
While breaking initial velocity u = 62.5 mph
= 62.5 x 1760 x 3 / (60 x 60 ) ft /s
= 91.66 ft / s
distance trvelled s = 150 ft
v² = u² - 2as
0 = 91.66² - 2 a x 150
a = - 28 ft / s²
b ) While accelerating initial velocity u = 0
distance travelled s = .24 mi
time = 19.3 s
s = ut + 1/2 at²
s is distance travelled in time t with acceleration a ,
.24 = 0 + 1/2 a x 19.3²
a = .001288 mi/s²
= 2.06 m /s²
c )
If distance travelled s = .25 mi
final velocity v = ? a = .001288 mi / s²
v² = u² + 2as
= 0 + 2 x .001288 x .25
= .000644
v = .025 mi / s
= .0025 x 60 x 60 mi / h
= 91.35 mph .
d ) initial velocity u = 59 mph
= 86.53 ft / s
final velocity = 0
acceleration = - 28 ft /s²
v = u - at
0 = 86.53 - 28 t
t = 3 sec approx .
A 500 kg car is moving at 30 m/s. The driver sees a barrier ahead. If the car takes 100 m to come to rest, what is the magnitude of the force necessary to stop the car?
How do you solve this question?
Answer:
F = 2250 [N]
Explanation:
In order to solve this problem, we must first use the following equation of kinematics.
\(v_{f}^{2} =v_{o}^{2}-2*a*x\)
where:
Vf = final velocity = 0 (come to rest)
Vo = initial velocity = 30 [m/s]
a = acceleration or desaceleration [m/s²]
x = distance = 100 [m]
\((0)=30^{2} -2*a*100\\900 = 200*a\\a = 4.5 [m/s^{2}]\)
Now we must use the following equation of kinetics, which is based on Newton's second law that explains that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force [N]
m = mass = 500 [kg]
a = acceleration = 4.5 [m/s²]
\(F = 500*4.5\\F = 2250 [N]\)
Which of the following describes the role of C6H12O6 in the Calvin cycle?
Answer:
C6H12O6 is the final product of Calvin cycle light independent reactions
Explanation:
* steps in Calvin cycle
: carbon fixation
: reduction
: regeneration
for C6H12O6 it requires 2 molecules of PGAL or G3P
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If you exert 6 N across a distance of 2 m in 3 s you'll deliver a power of
Answer:
power = 4 watt
Explanation:
work done = force * distance
=6*2
=12 joule
power = work done/time taken
=12/3
=4 watt
As the force is exerted across the given distance and time, the power delivered 4Watts.
Power and WorkPower is simply referred to as the quantity of energy transferred per unit time.
It is expressed as;
P = Work done / time elapsed = W / t
Work is simply the measure of energy transfer that takes place when an object is moved over a given distance by a push or pull force.
It is expressed as;
W = Force × distance = F × d
Hence;
Power P = W / t
Power P = ( F × d ) / t
Given the data in the question;
Force exerted F = 6N = 6kgm/s²Distance covered d = 2mTime elapsed t = 3sPower P = ?To determine the power delivered, we substitute our given values into the derived equation above.
P = ( F × d ) / t
P = ( 6kgm/s² × 2m ) / 3s
P = ( 12kgm²/s² ) / 3s
P = 4kgm²/s³
P = 4Watts
Therefore, as the force is exerted across the given distance and time, the power delivered 4Watts.
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The input and output forces for four machines are shown in the table. Machine Forces Machine Input Force (N) Output Force (N) 1 5 50 2 10 50 3 25 50 4 50 50 Which machine would have the greatest mechanical advantage? Responses 1 1 2 2 3 3 4
Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.
Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10
Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5
Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2
Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1
Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.
Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.
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Which describes any compound that has at least one element from group 17? Halide;noble gas; metalliod; transition metal
Answer:
Halide
Explanation:
It has at least one element from the halogen group (17)
Halide describes any compound that has at least one element from group 17, therefore the correct option is option A.
What are halides?When the elements belonging to group 17 of the periodic table form ionic compounds with other electropositive elements, then these compounds are known as halides.
These elements from group 17 are also known as halogens. Generally, these halides have very high electronegativity as they reside on the right side of the periodic table.
Generally, the valency of the halogens element involved in the halide compound is one and they form ionic compounds with the alkali and alkaline earth metals.
Thus, halides are compounds that have at least one element from group 17.
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On what part of the eye are rods and cones found?
Answer:
retina.
Explanation:
Do electrons flow easier with
HIGH resistance or LOW
resistance?
A. low
B.high
Answer:
low.
Explanation:
it makes the flow easier if its lower because, the resistance isn’t pushing as hard against the flow which means that the flow is easier.
A rock has a gravitational potential energy 1960 J at 100 meters high. What is the mass of the rock?
According to the information, the mass of the rock is found to be 2 kg.
What is Potential energy?Potential energy may be defined as a type of stored energy that depends upon the relative position of various parts of a system. This energy is held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
According to the question, the potential energy is calculated with the help of the following formula:
Potential energy (P.E) = m × g × h.where, P.E = 1960 J, g = 9.8 m/sec, and height = 100 m, mass = ?
mass = P.E / g × h = 1960/980 = 2 kg.
Therefore, the mass of the rock is found to be 2 kg.
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Part F
Imagine you were a sportscaster at the Olympics. You'd created a mathematical model similar to the one you just did. Imagine that you had a
computer program that could do an instantaneous analysis of video motion using that model. How could you use it in your sportscast?
A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.
Why will a program be needed?A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.
Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience
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Your son forgets to do his chores before leaving for hockey practice. You scold him later that evening when he returns (which he does NOT enjoy). This is an example of...
The scenario presented is an example of negative punishment.
Negative punishment involves the removal of a desirable stimulus or the addition of an aversive stimulus in response to a behavior, with the goal of decreasing the likelihood of that behavior occurring again in the future.
In this case, the desirable stimulus that was removed is the son's ability to engage in leisure activities like playing hockey, and the aversive stimulus that was added is the scolding from the parent. By experiencing this consequence, the son may be less likely to forget his chores in the future in order to avoid the negative outcome.
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or this assignment, you submit answers by question parts. The number of submissions remaining for each
ssignment Scoring
our last submission is used for your score.
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Compute the density in g/cm³ of a piece of metal that has a mass of 0.470 kg and a volume of 77 cm³.
X g/cm³
Enter a number.
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The density of the metal is determined as 6.1 g / cm³.
What is the density of the metal?
The density of the metal is defined as the ratio of the mass per unit volume of the metal.
Mathematically, the formula for density is given as;
ρ = m / V
where;
m is the mass of the metalV is the volume of the metalThe density of the metal is calculated as follows;
ρ = ( 0.47 kg x 1000 g/kg ) / ( 77 cm³ )
ρ = 6.1 g / cm³
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A weight is hung from the ceiling of an elevator by a massless string. Under which circumstances will the tension in the cord be the greatest?1) The elevator rises with decreasing speed.2) The elevator rises with increasing speed.3) The elevator is at rest.4) The elevator descends with increasing speed.
Free body diagram when the elevator is going up;
The free-body equation is given as,
\(T_1-mg=ma\)Here, T_1 is the tension in the rope while the elevator is going up, m is the mass of the body hanging from the ceiling, g is the acceleration due to gravity and a is the acceleration of the elevator.
Therefore, the tension in the rope while the elevator is going up is given as,
\(T_1=ma+mg\ldots(1)\)Free body diagram when the elevator is going down:
The free-body equation is given as,
\(\begin{gathered} mg-T_2=ma \\ T_2=mg-ma\ldots(2) \end{gathered}\)Here, T_2 is the tension in the rope while the elevator is going down.
On comparing equations (1) and (2) it is concluded that,
\(T_1>T_2\)Therefore, the tension in the cord is the greatest when the elevator rises with increasing speed. Hence, option (2) is the correct choice.
A large mining dump truck has a mass of 40,000 kg. If its engine produces
20,000N of force, how fast will the truck accelerate?
Answer:
0.5 m/s²
Explanation:
Net force = mass × acceleration
∑F = ma
20,000 N = (40,000 kg) a
a = 0.5 m/s²
Answer:
which one will not start moving faster
Explanation:
Mass is also described by physics. If you apply the same amount of force to a small sports car and to a big garbage truck.
a
A particle starts at the origin and is deflected by another particle with a like charge. In 0.5 s the first particle has moved 30 min a positive direction. What is its
displacement?
A.
30 m
B. 60 m
C. 30
D
-30 m
Answer:
C I believe if I’m wrong I’m sorry
Explanation:
Mass movements occur on slopes because of the pull of gravity.
a. True
b. False
Answer:
true
Explanation:
A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.49 radians with the horizontal. The frictional coefficients between the crate and plane are (s = 0.66, k = 0.21 ). What is the magnitude of the acceleration (in meters/second2) of this crate as it slides up the incline?
The acceleration of the crate as it slides up the incline is 2.06 m/s².
What is the acceleration of the crate?
The acceleration of the crate as it slides up the inclined plane is calculated as follows;
Apply the principle of Newton's second law of motion to determine the acceleration of the crate.
Ff = ma
kmg = ma
kg = a
where;
k is the coefficient of kinetic frictiong is acceleration due to gravitya is the acceleration of the cratea = (0.21 x 9.8 m/s²)
a = 2.06 m/s²
Thus, the acceleration of the crate as it slides up the incline depends on the coefficient of kinetic friction since the crate is in motion.
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1 If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed?
a The screen would remain dark because no radiation would reach the screen.
b One bright band would appear in the center of the screen.
c A series of light and dark bands would appear on the screen.
d Two bright bands would appear on the screen in line with the slits.
2 Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true?
a Waves that make up the radiation collide with each other so that they add together or cancel each other out.
b Particles that make up the radiation collide with each other and scatter randomly.
c Particles that make up the radiation collide with each other so that they add together or cancel each other out.
d Waves that make up the radiation do not interact with each other.
3 Which statement about the observed results of the double-slit experiment is true?
a Waves that are out of phase constructively interfere to create bright bands.
b Waves that are in phase destructively interfere to create bright bands.
c Waves that are out of phase constructively interfere to create bright bands.
d Waves that are in phase constructively interfere to create bright bands.
4 Which statement about the observed results of the double-slit experiment is true?
a Waves that are in phase constructively interfere to form dark bands.
b Waves that are out of phase constructively interfere to form dark bands.
c Waves that are in phase destructively interfere to form dark bands.
d Waves that are out of phase destructively interfere to form dark bands.
5 A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true about the new interference pattern seen on the screen compared to the original interference pattern?
a The spacing between the dark fringes will increase.
b The spacing between the bright fringes will increase.
c The spacing between the bright fringes will decrease.
d The spacing between the dark fringes will remain the same.
6 Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light?
a 789 nm
b 420 nm
c 581 nm
d 591 nm
Answer:
1. Two bright bands would appear on the screen in line with the slits.
2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.
3. Waves that are in phase constructively interfere to create bright bands.
4. Waves that are out of phase destructively interfere to form dark bands.
5. The spacing between the bright fringes will decrease.
6. 581 nm
Explanation:
an airbubble at the bottom of a lake 90 m deep has a volume of 1.5 cm³. what will be the volume just below the surface if atmospheric pressure is equivalent to a height of 10m of water
The volume of the air bubble just below the surface of the lake would be 0.000015 m³ = 1.5 cm³.
How do we calculate?V₁ = 1.5 cm³
P₁ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
To convert V₁ to m³:
Volume₁ = 1.5 cm³ * (1 m / 100 cm)³ = 0.000015 m³
we then substitute the values into the equation:
Volume ₂ = 0.000015 m³ * (P₂ / (1000 kg/m³ * 9.8 m/s² * 10 m))
Pressure ₂ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
We then substitute the value of P₂ into the equation for Volume 2:
V₂ = 0.000015 m³ * ((1000 kg/m³ * 9.8 m/s² * 10 m) / (1000 kg/m³ * 9.8 m/s² * 10 m))
Volume₂ = 0.000015 m³
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Pulse transfers a
disturbance. while wave is a
disturbance that transfers energy.
Answer:
Pulse transfers a single disturbance, while wave is a continuous disturbance that transfers energy.
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Calculate the speed (V) of the electron so that it has double the resting mass.
The relationship between the mass, resting mass, and speed of an electron is given as:
\(m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}\)If the mass is double the resting mass
m = 2m₀
Substitute this into the equation
\(2m_0=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}\)\(undefined\)The speed (V) of the electron so that it has double the resting mass is = \(2.598\)×\(10^{8} m/s\)
The mass of an electron at speed V is given by the following equation:-
\(M = \frac{Mo}{\sqrt{1-\frac{V^{2} }{C^{2} } } }\)
where Mo is the rest mass.
If, M = 2Mo,
\(2Mo = \frac{Mo}{\sqrt{1-\frac{V^{2} }{C^{2} } } }\)
\(2 = \frac{1}{\sqrt{1-\frac{V^{2} }{C^{2} } } }\)
or, \(1- \frac{v^{2} }{c^{2} } = \frac{1}{4}\)
or, \(V = (\frac{\sqrt{3} }{2} )C\)
\(V = 2.598\)×\(10^{8} m/s\)
where \(C = 2.997\)×\(10^{8} m/s\)
Hence, the speed of electron = \(V = 2.598\) ×\(10^{8} m/s\)
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What kind of wave interactions is caused by a change in the speed of the wave
Answer:Refraction
Explanation:
or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.
10. In a laboratory experiment, students recorded the
following length data: 12.2 cm, 12.1 cm, 12 cm,
11.9 cm, and 12.20 cm. (a) Determine the average
length and express the answer using the correct
number of significant figures. (b) Based on your
average length calculation in part (a), discuss the
importance of recording measurements to the
appropriate number of significant figures.
a) 12.1 Average.
B) It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.
What does the average?A data set's mean (average) is calculated by summing all of the numbers in the set, then dividing by the total number of values in the set. When a data collection is ranked from least to greatest, the median is the midpoint.The mean, median, and mode are the three primary varieties of average. Each of these methods operates slightly differently and frequently yields values typically a little off. The average that is most frequently used is the mean. You add all the values and divide this sum by the total number of values to obtain the mean value.Averages are mostly used to track changes over time within a sample group or cohort.Since averages can be used to compare different quantities of the same category, we employ them. The calculation of averages has limits since it cannot reveal how something is distributed among individuals. For instance, the distribution of income is not shown by per capita income.A) Determine the average length and express the answer using the correct number of significant figures:
12.2+12.1+12=36.3/3 = 12.1 Average.
B) Based on your average length calculation in part a, discuss the importance of recording measurements to the appropriate number of significant figures:
It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.
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For the simple harmonic oscillation where k = 19.6
N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v =
(0.808 m/s) sin 8.08t, determine (a) the total energy, (b)
the kinetic and potential energies as a function of time,
(c) the velocity when the mass is 0.050 m from
equilibrium, (d) the kinetic and potential energies at
half amplitude (x = A/2).
a. Total energy is 0.098 J
b. Potential and Kinetic Energies is 0.032 sin^2(8.08t) J
c. Velocity at x is -0.808 sin(8.08t) m/s
d. Potential and Kinetic Energies at x is 0.016 sin^2(8.08t) J
Step by step explanationWe can use the following formulas for the energy, velocity, and potential and kinetic energies of a simple harmonic oscillator:
Total Energy: E = 1/2 k A^2Velocity: v = -ωA sin(ωt)Potential Energy: U = 1/2 k x^2Kinetic Energy: K = 1/2 m v^2where ω = √(k/m) is the angular frequency.
Given that k = 19.6 N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v = (0.808 m/s) sin 8.08t, we can find the values of E, U, and K as follows:
(a) Total Energy:
E = 1/2 k A^2 = 1/2 * 19.6 * 0.1^2 = 0.098 J
(b) Potential and Kinetic Energies:
U = 1/2 k x^2 = 1/2 * 19.6 * (-0.1 cos(8.08t))^2 = 0.098 cos^2(8.08t) J
K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.032 sin^2(8.08t) J
(c) Velocity at x = 0.050 m:
When x = 0.050 m, cos(8.08t) = -0.5, so we have:
v = -ωA sin(ωt) = -ω(0.1) sin(8.08t) = -0.808 sin(8.08t) m/s
(d) Potential and Kinetic Energies at x = A/2:
When x = A/2 = 0.050 m, cos(8.08t) = -0.5, so we have:
U = 1/2 k x^2 = 1/2 * 19.6 * (0.050)^2 = 0.0245 J
K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.016 sin^2(8.08t) J
Note that the sum of potential and kinetic energies at any point in time is equal to the total energy, which is constant.
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Derive the expression of the mechanical energy for under damped system.
Answer: the expression of the mechanical energy for under damped system is;
x(t)=Ae−γ/2tcos(ωdt+ϕ), where ωd=ω02−γ2/4
γ = damping rate, and
ω0 = the angular frequency of the oscillator without damping.
Explanation:
The physical situation in mechanical energy defined through out the world has three possible results depending on the value of a (which is a constant value), which depends on the value of what is under our radical. This expression can either be positive, negative, or equal to zero which will result in overdamping, underdamping, and critical damping, as the case may be.
γ2 >4ω²0 This is the Over Damped case. Here, the system returns to equilibrium by exponentially decaying towards zero, and the system will not pass that equilibrium position more than once.
γ² < 4ω²0 this is the Under Damped case. Here, the system moves back and forth as it slowly returns to equilibrium and the amplitude of the system decreases over time.
Finally, γ² = 4ω²0
This is the Critically Damped case. Here, the system returns to equilibrium very fast without moving back and forth and without passing the equilibrium position at all.
A 50gram bracelet is suspected of not being pure gold. It is dropped into a glass of water and 4 cm3of water overflows. Is the bracelet pure gold? How do you know?
Since, density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
To know if the bracelet is pure gold, we calculate the density of the bracelet and compare it to the density of pure gold (19.3 g/cm³).
That is, for the bracelet to pure gold,
Density of bracelet ≈ 19.3 g/cm³
What is Density?Density can be defined as the ratio of the mass and the volume of a substance.
The formula of Density is give as
D = m/v................... Equation 1⇒ Where:
D = Density of the braceletm = mass of the braceletv = volume of the braceletFrom the question,
⇒ Given:
m = 50 gv = 4 cm³ (an object displace an amount of water equal to it's own volume)⇒ Substitute these values into equation 1
D = 50/4D = 12.5 g/cm³Hence, since the density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
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what are the factors affecting center of mass in an object
How will the magnet being farther away from the coil of wire affect the strength of an electromagnet?
Answer:
intensity of this field around the conductor is proportional to the distance from it with the strongest point being next to the conductor and progressively getting weaker further away from the conductor
25. Spider-Man Spider-Man holds the bottom of an elevator with one hand.
With his other hand, he holds a spider cord attached to a 50-kg box of
explosives at the bottom of the cord. Determine the force that the cord
exerts on the box if (a) the elevator is at rest; (b) the elevator accelerates up
at 2.0 m/s2; (c) the upward-moving elevator's speed decreases at a rate of
2.0 m/s2; and (d) the elevator falls freely.
Answer:
Explanation:
a) F = m(g + a) = 50(10 + 0.0) = 500 N
b) F = m(g + a) = 50(10 + 2.0) = 600 N
c) F = m(g + a) = 50(10 - 2.0) = 400 N
d) F = m(g + a) = 50(0.0 + 0.0) = 0.00 N
Why does a watched pot never boil?
BERE
Which describes the positions on a horizontal number line?
0
O All points to the left of one are positive.
O All points to the right of one are positive.
O All points to the left of zero are negative.
O All points to the right of zero are negative.
Mark this and return
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Answer:
All points to the left of zero are negative
Explanation:
Answer:
C
Explanation:
on edge