According to Newton's third law, what other force must be happening?

It is a true statement that the three categories that American Imperialism sought to enhance were political, military, and economic.

The term imperialism has to do with a situation in which a country that tends to be more powerful continues to control a smaller country owing to the depends of the smaller country on the larger country for aid even though it is fully independent.

We can see that imperialism continues around the world especially in the developing and the less developed countries and this has continued to be an object of intense debate in many quarters.

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Answer:

SI

Explanation:

When doing a kinetic research utilizing the method of starting rates, the reaction is repeated several times. While the concentration of one reactant fluctuates, the other is maintained constant.

You can determine what more solute has been dispersed in the solvent by looking at the level of the solution's concentration. For instance, the concentration may be stated as 1 teaspoon of salt per 2 cups of water if you add 1 teaspoon to 2 cups of water.

Molarity, a typical measurement used for this, is utilized. Molarity (M) is calculated by dividing the volume of the solution (V) in liters by the quantity of moles for solute (n). It's critical to remember that its molarity is determined by the moles of the solute in liter fluid.

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The complete question is-

When using the method of initial rates for a kinetic study, the reaction is performed ____. One reactant concentration is kept constant, and the other _____.

The percentages of the change in frequency depends on the speed of the wave, and wavelength much greater when sound waves are used instead of radio waves in these experiments.

The percentage change in frequency and wavelength of a wave depends on the speed of the wave, the original frequency and wavelength of the wave, and the medium through which the wave is traveling. In general, the percentage change in frequency and wavelength of a wave will be greater when the speed of the wave is lower, the original frequency and wavelength of the wave are lower, and the medium through which the wave is traveling is less dense. In the case of sound waves and radio waves, the speed of the wave, the original frequency and wavelength of the sound wave, and the medium through which the wave is traveling are all different. Sound waves are mechanical waves that travel through a solid, liquid, or gas medium, while radio waves are electromagnetic waves that travel through a vacuum or a medium with a very low density (such as the Earth's atmosphere).

The speed of sound waves in a medium depends on the density and elasticity of the medium. The speed of sound is slower in denser and less elastic media, and faster in less dense and more elastic media. For example, the speed of sound in air is about 343 meters per second, while the speed of sound in water is about 1480 meters per second. The speed of radio waves in a vacuum is the speed of light, which is approximately 299,792,458 meters per second. However, the speed of radio waves in a medium with a low density (such as the Earth's atmosphere) is slightly slower than the speed of light due to the interactions between the radio waves and the medium. The original frequency and wavelength of a wave also affect the percentage change in frequency and wavelength. In general, the percentage change in frequency and wavelength will be greater for waves with lower frequencies and longer wavelengths.

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فرض

Please mark my answer as brainlist..

The S.I units of K so that the equation Velocity = K × density is dimensionally correct is M^-1.L^3.T^-1 [L^3.M^-1.T^-1]

The most extensively used system of measuring in the world is the International System of Units, sometimes known as the SI system and abbreviated SI in all languages. It is the current version of the metric system.

Attached in this answer is the straightforward solution of the question and this shows the dimensional correctness needed after the equation Velocity = K × density has been solved,.

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Answer:750

Explanation:

50 times 15

Answer:

750 j

Explanation:

I took the test in k12

All of the above reasons make it an extremely unlikely scenario for a civilization to exist on a planet orbiting a close binary star system consisting of a red giant star and a black hole.

The ultraviolet radiation emitted by a hot star would make it difficult for life to develop, and any nearby planet would have been destroyed by the supernova explosion that created the black hole. Additionally, the star that created the black hole would have been short-lived, which means that life would not have had enough time to develop on a nearby planet before the star went supernova.

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Explanation:

\(\text{Velocity is defined by the average displacement per unit time. In the time interval }t=8\text{s to }t=12\text{s,}\)

\(\text{the velocity, or equivalently the slope of the graph is }\frac{(-4)-(-4)}{12-8}=0\)

\(\text{Therefore, the velocity at }t=10\text{s is }0\)

Answer:

0 m/s

Explanation:

The object from 8s to 12s stays at -4m, meaning that it doesn't move in that interval and therefore has zero velocity. Hope this helps!

If we consider the cantilever to be a perfect, massless spring, then K = 5.952N/m is its effective force constant.

The meaning of the term "force" is obvious. At about this point, it's perfectly permissible to describe a force as shoving or pulling. An object doesn't "have a force in it" or "contain a force." A force is applied to one thing by another.

A force can be a push or a pull, and it affects how we go about our daily lives because we can't open or close items, raise our legs or arms or accomplish a lot more without it.

Numerous E coli bacteria, m = 7.10 × 10⁻¹⁶

frequency =17.1 MHz

frequency of vibration, F = 1/2π√K/M

17.1×10⁶= 1/2π√K/ 7.10 × 10⁻¹⁶

K/ 7.10 × 10⁻¹⁶ = 7.10 ×10¹⁵

K = 5.952N/m

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Tenemos un problema de termodinamica sobre gases ideales, los cuales pueden ser descritos por la ecuación de estado del gas ideal

\(P*V = n*R*T\)

donde:

P = presión

V = volumen

n = número de moles

R = constante de los gases

T = temperatura.

1) Para el primer problema podemos pensar que el gas dentro del globo es un gas ideal:

Originalmente sabemos que n = 4 y V = 5.0 L

Entonces tendremos:

\(P*(5.0 L) = (4 moles)*R*T\)

Ahora decidimos agregar 8 moles más, dejando constante la presión y la temperatura, entonces podemos reescribir la ecuación de arriba como:

(5.0L)/(4 moles) = R*T/P

Y como R, T y P son constantes, entonces:

R*T/P es una constante.

Esto quiere decir que cuando agreguemos 8 moles, para tener un total de 12 moles, tendremos que:

V'/(12 moles) = R*T/P = (5.0L)/(4 moles)

Donde V' es el nuevo volumen final del globo, y es lo que queremos obtener.

V'/(12 moles) =  (5.0L)/(4 moles)

V' =   (5.0L)*(12 moles)/(4 moles) = (5.0 L)*3 = 15.0 L

2) Queremos obtener la densidad en gramos sobre litro de un gas con una masa molar de 60g/mol, a P = 0.75 atm y T = 25°C.

Primero pasemos la temperatura a grados kelvin:

T = 25°C = (25 + 273.15)°K = 298.15°K

Planteamos la ecuación del gas ideal:

\(P*V = n*R*T\)

reemplazando R = 0.082 (atm*L/mol*k), además de la presión y la temperatura para un solo mol de gas:

\((0.75 atm)*V = (1 mol)*(0.082 (atm*L/mol*k))*(298.15°K)\)

Resolviendo para V obtenemos que:

\(V = (1 mol)*(0.082 (atm*L/mol*k))*(298.15°K)/(0.75 atm) = 32.597 L\)

Así, vemos que un mol de este gas ocupa un volumen de  32.597 L

Y también sabemos que un mol de este gas pesa 60 gramos.

Recordando que la densidad es el cociente entre la masa y el volumen, podemos ver que la densidad del gas será:

\(d = 60g/(32.597 L) = 1.84 g/L\)

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To calculate the masses of stars in a binary system, we must measure their orbital characteristics.

Binary stars are two stars that are gravitationally bound to each other and orbit around a common center of mass.

The masses of the two stars in a binary system can be calculated by measuring their orbital characteristics, such as their orbital period (the time it takes for the stars to orbit each other), their orbital radius (the distance between the stars at their closest approach), and their orbital eccentricity (a measure of the deviation of the orbit from a perfect circle). By analyzing these characteristics, astronomers can use the laws of gravity to calculate the masses of the stars in the system.

Other techniques for measuring the masses of stars include observing the spectra of the stars (which can reveal their surface gravity and temperature), observing the motion of the stars (which can reveal their mass through their acceleration), and observing the stars' interaction with other objects (such as planets or disks of dust and gas).

\(\bold{ \: \purple{Hope \: This \: Helps \: You!}}\)

Answer: Cool! Thanks!

The power radiated by a sphere into empty space can be calculated using the Stefan-Boltzmann law, which states that the power radiated is proportional to the fourth power of the temperature and the surface area of the object and is given by:

Power = emissivity x Stefan-Boltzmann constant x surface area x temperature^4

Here, the sphere has a radius of 10 cm, so its surface area can be calculated as:

Surface area = 4 x π x radius^2 = 4 x π x (0.1 m)^2 = 0.04π m^2

Substituting the given values into the equation and solving for power, we get:

Power = 1.0 x 5.67 x 10^-8 x 0.04π x (400 K)^4 = 69.98 W

Therefore, the power radiated by the sphere is approximately 70 W, which is option B.

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Answer:

I think it is better if you read and shortly write my explanation

Explanation:

simple pendulum with no friction, mechanical energy is conserved. Total mechanical energy is a combination of kinetic energy and gravitational potential energy. As the pendulum swings back and forth, there is a constant exchange between kinetic energy and gravitational potential energy.

The present value of $2,000 to be received four years from now will decreases with increase in the discount rate.

This is because the discount rate represents the opportunity cost of money - in other words, the rate of return that could be earned by investing the money elsewhere.

When you calculate the present value of a future sum of money, you discount it back to the present using the discount rate. The more the discount rate, the high the future cash flow is discounted, and the lesser its present value.

For example, let's say the discount rate is 5% per year. The present value of $2,000 to be received four years from now would be

PV = $2,000 / \((1+0.05)^{4}\)

PV = $2,000 / 1.2155

PV = $1,646.57

Now let's say the discount rate increases to 10% per year. The present value of the same $2,000 cash flow would be

PV = $2,000 / \((1+0.1)^{4}\)

PV = $2,000 / 1.4641

PV = $1,364.87

As you can see, the present value has decreased from $1,646.57 to $1,364.87 as the discount rate has increased from 5% to 10%. This is because the higher discount rate reduces the value of future cash flows in today's dollars.

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Copper-nickel (Cu-Ni) alloys are high-strength and corrosion-resistant alloys that are used in a wide range of applications, including electrical applications. The electrical conductivity of a Cu-Ni alloy is dependent on a variety of factors, including the alloy composition, temperature, and mechanical properties, such as the yield strength.A Cu-Ni alloy that has a yield strength of 140 MPa may have a different electrical conductivity compared to another Cu-Ni alloy that has a different yield strength.

However, in general, Cu-Ni alloys are known for their high electrical conductivity, with electrical conductivity values ranging from 7 to 45% International Annealed Copper Standard (IACS).Cu-Ni alloys have excellent electrical conductivity because copper is an excellent conductor of electricity, while nickel improves the alloy's resistance to corrosion and oxidation. Additionally, Cu-Ni alloys have good thermal conductivity, making them useful in applications where heat transfer is necessary. Overall, determining the electrical conductivity of a Cu-Ni alloy requires an understanding of the specific alloy's composition, temperature, and mechanical properties. However, in general, Cu-Ni alloys are known for their high electrical conductivity and are used in many electrical applications.

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The wavelength and speed of a wave will be the same regardless of the density of the medium.

The wavelength of a wave is determined by the source and frequency of the wave and is independent of the medium through which it travels. Similarly, the speed of a wave is determined by the properties of the medium, such as its elasticity and inertia, and not directly by its density. Therefore, when comparing the wave characteristics of a wave in two different ropes, the wavelength and speed will be the same irrespective of the density of the medium. The density of the medium may affect other properties of the wave, such as the amplitude or intensity, but not the wavelength and speed.

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Answer:

7.5secs

Explanation:

Using the equation of motion

v = u + at

v is the final velocity = 0m/s

u is the initial velocity = 9m/s

a is the deceleration = -1.2m/s²

t is the required time

Substitute;

0 = 9 + 1.2(t)

-9 = -1.2t

t = -9/-1.2

t = 7.5secs

hence it takes the child 7.5secs to stop

Part 1) The width of the river is approximately 120.46 meters and the current speed is approximately 3.37 m/s. Part 2)  The shortest time to cross the river is approximately 20.08 seconds and the boat would land approximately 67.74 meters downstream from the starting point on the far bank of the river.

Part 1: To determine the width of the river and the current speed, we can analyze the motion of the boat in both the northbound and southbound directions.

Let's assume the width of the river is represented by "d" and the current speed is represented by "v." Since the boat's speed relative to the river is 6.00 m/s in the northbound direction and 7.40 m/s in the southbound direction, we can set up the following equations based on the time it takes to cross the river:

For the northbound direction:

d = (boat's speed relative to the river) * (time taken to cross the river)

d = 6.00 m/s * 20.1 s

d = 120.6 m

For the southbound direction:

d = (boat's speed relative to the river + current speed) * (time taken to cross the river)

d = (7.40 m/s + v) * 11.2 s

Now we have two equations with two variables (d and v). Solving these equations simultaneously will give us the values of d and v.

120.6 m = (7.40 m/s + v) * 11.2 s

Simplifying the equation:

120.6 m = 82.88 m/s + 11.2v

11.2v = 120.6 m - 82.88 m/s

11.2v = 37.72 m/s

v = 37.72 m/s / 11.2

v ≈ 3.37 m/s

Now that we have the current speed (v ≈ 3.37 m/s), we can substitute this value back into one of the earlier equations to find the width of the river:

d = (7.40 m/s + v) * 11.2 s

d = (7.40 m/s + 3.37 m/s) * 11.2 s

d = 10.77 m/s * 11.2 s

d ≈ 120.46 m

Part 2: To find the shortest time to cross the river, we need to take into account the current. Since the current is flowing from east to west, we should aim to reach the far bank downstream from our initial position.

The shortest time to cross the river can be achieved by pointing the boat at an angle that maximizes the effect of the current to carry us downstream. This angle can be determined using trigonometry. Let's call this angle θ.

tan(θ) = (current speed) / (boat's speed relative to the river)

tan(θ) = 3.37 m/s / 6.00 m/s

θ ≈ 29.23 degrees

By pointing the boat at an angle of approximately 29.23 degrees downstream, we can minimize the impact of the current and maximize our speed across the river. The boat's speed relative to the river is still 6.00 m/s, so the shortest time to cross the river would be the time it takes to cover the width of the river (120.46 m) at this speed:

Shortest time = distance / speed

Shortest time = 120.46 m / 6.00 m/s

Shortest time ≈ 20.08 s

As for the landing point on the far bank, it would be downstream from the starting position by a distance equal to the current speed multiplied by the

shortest time:

Landing point = (current speed) * (shortest time)

Landing point ≈ 3.37 m/s * 20.08 s

Landing point ≈ 67.74 m

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Given data:

Initial velocity,

Angle of projection,

The maximum height achieved by the projectile is given as,

Here, g is the acceleration due to gravity.

Substituting all known values,

Therefore, the maximum height achieved by the projectile is 2.86 m.

There is no change in the velocity of the ball after 10 seconds and one hour due to no external force on it.

If a ball floating in outer space was pushed and attain a velocity of 4 m/s, then after 10 seconds as well as after an hour, it has the same velocity because in space there is no forces on the ball. This ball moves with the same velocity until external force is applied on it.

So we can conclude that there is no change in the velocity of the ball after 10 seconds and one hour due to no external force on it.

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Answer:

a. y = (tanθ)x - 1/2gx²/(v₀cosθ)²

b. Range R = v₀²sin2θ/g

c. Time of flight T = 2v₀sinθ/g

Explanation:

a. Show that the path followed by the object is parabolic

Let the vertical component of its velocity be v₁ = v₀sinθ and the horizontal component of its velocity be v₂ = v₀cosθ where v₀ = initial velocity of the projectile.

Now, for its vertical displacement Δy = v₁t - 1/2gt²   (1)

Its horizontal displacement Δx = v₂t  (2)

From (2) t = Δx/v₂

Substituting t into (1), we have

Δy = v₁(Δx/v₂) - 1/2g(Δx/v₂)²

= (v₁/v₂)Δx - 1/2g(Δx)²/(v₂)² =

= (v₀sinθ/v₀cosθ)Δx - 1/2g(Δx)²/(v₀cosθ)²  

If we assume the initial position is at the origin, then Δx = x - 0 = x and Δy = y - 0 = y. So,

y = (tanθ)x - 1/2gx²/(v₀cosθ)² .

This is the required equation and it is a quadratic equation in x. Thus, the path followed by the projectile is parabolic.

b. The Range, R

The range, R is obtained when y = 0

So, 0 = (tanθ)x - 1/2gx²/(v₀cosθ)²

[(tanθ) - 1/2gx/(v₀cosθ)²]x = 0

x = 0 or (tanθ) - 1/2gx/(v₀cosθ)² = 0

x = 0 or (tanθ) = 1/2gx/(v₀cosθ)²

x = 0 or (tanθ)(v₀cosθ)² = 1/2gx

x = 0 or x = 2(sinθ/cosθ)(v₀cosθ)²/g

x = 0 or x = v₀²(2sinθ/cosθ)/g

x = 0 or x = v₀²sin2θ/g      [sin2θ = 2sinθ/cosθ]

So its range R = x = v₀²sin2θ/g    

c. Time of flight, T

The time of flight, T is obtained from (1) when Δy = 0 and t = T

So, 0 = v₁T - 1/2gT²

(v₁ - 1/2gT)T = 0

T = 0 or (v₁ - 1/2gT) = 0

T = 0 or v₁ = 1/2gT

T = 0 or T = 2v₁/g = 2v₀sinθ/g

So, the time of flight T = 2v₀sinθ/g

The number of orders that one can see the entire visible speed is 5 orders.

From the information given, it should be noted that the grating with 250 grooves mm is used and the visible spectrum range in wavelength from 400nm to 700nm. Therefore, the grating spacing will be:

d = (1.00 × 10^-4) / 250

d = 4000nm

Therefore, the number of times that are needed to complete the order will be the same as the number of orders which the long wavelength time will be visible. This will be:

= (4000 × sin 90°)/700

= 5.71

Therefore, the maximum orders will be 5.

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Answer: work done is: 700 J.

the formula of work done is : work=force × distance

here, the distance car being pulled is 56.0 m and the force applied on it is 12.5 n. so the work done to pulled a car id : = 12.5 × 56.0

=700.0 j.

Answer:

The statement that "electromagnetic waves require a medium to travel through" is incorrect. Electromagnetic waves do not require a medium to travel through and can propagate through a vacuum. This was one of the key insights of James Clerk Maxwell's theory of electromagnetism.