According to Newton’s law of universal gravitation, in which of the following situations does the gravitational attraction between two bodies always increase

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

Third one. It will increase the number of frequencies that satellites can use to communicate with Earth.

It will increase the number of frequencies that satellites can use to communicate with Earth. The correct option is C.

Satellite communication is the utilization of artificial satellites to give communication links among various points on Earth in telecommunications.

Satellite communications are critical components of the global telecommunications system.

Satellites communicate by sending signals to Earth's antennas via radio waves. The antennas then capture those signals and process the information they contain.

Satellites collect data on the Earth's clouds, oceans, land, and air. They can also see wildfires, volcanoes, and smoke.

All of this data assists scientists in forecasting weather and climate. It assists farmers in determining which crops to plant.

When severe solar weather continues for an extended period of time, it increases the number of frequencies that satellites can use to communicate with Earth.

Thus, the correct option is C.

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The average velocity of the car is 100 kilometers/hour south. This means that, on average, the car is traveling 100 kilometers per hour in the south direction relative to its starting point.

To determine the average velocity of the car, we need to calculate the displacement and divide it by the time taken. Velocity is defined as the rate of change of displacement with respect to time.

In this case, the car is traveling south, and its displacement is 200 kilometers from its starting point after 2 hours.

The average velocity is given by the formula:

Average velocity = Displacement / Time

The displacement is 200 kilometers south, and the time is 2 hours. Therefore, we have:

Average velocity = 200 kilometers south / 2 hours

Simplifying the calculation:

Average velocity = 100 kilometers/hour south

Hence, the correct answer is B. 100 kilometers/hour south. This indicates that the car's average velocity is 100 kilometers per hour towards the south direction.

It's important to note that velocity is a vector quantity and includes both magnitude (speed) and direction. In this case, the direction is specified as south, which indicates that the car is moving towards the south relative to its starting point.

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Answer:

When a load resistance is connected, current flows through the cell and a voltage develops across the internal resistance. This voltage is not available to the circuit so it is called the lost volts, .

Explanation:

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Answer:

250 N/m²

Explanation:

Pressure = Force / Area

P = 1500 / 6

P = 250

Answer:

25 m

Explanation:

Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition

\(a= \frac{\Delta v}{\Delta t} = \frac{10-0(\frac ms)}{5 s} = 2 \frac m{s^2}\)

Now we can write the equation of motion

\(s(t)= s_0 + v_0t + \frac12at^2\)

where, the two terms \(s_0\ v_0\) represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)

\(s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m\)

The speed after 2.29 s if it accelerates uniformly at −4.56 m/s² with an initial speed of 7.7 m / s is - 2.74 m / s

v = u + at

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

u = 7.7 m / s

t = 2.29 s

a = - 4.56 m / s²

v = 7.7 + ( - 4.56 * 2.29 )

v = 7.7 - 10.44

v = - 2.74 m / s

The negative symbol in final velocity means that the object has changed directions from which it originally started. Considering a was negative and u was positive, the object must has decelerated in positive direction.

Therefore, the final speed is - 2.74 m / s

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In the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

The Five-factor model is a scientific theory that states traits of the personality of an individual are due to its biology and therefore they respond to adaptations, which are central in the biology field.

In conclusion, in the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

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The work done in the spring is calculated to be 2.8 J

Hooke's law states that, the extension of a given material is directly proportional to the applied force as long as the elastic limit is not exceeded . First, we must bear in mind that the material must remain within the elastic limit for us to apply the Hooke's law in solving the problem.

Now;

From Hooke's law;

F = Ke

F = force applied

K = force constant

e = extension

F = W = mg =  2.50 - kg * 9.8 m/s^2 = 24.5 N

K = 24.5 N/ 2.76 * 10^-2

K = 888 N/m

e = F/K

F = W =  1.25 - kg * 9.8 m/s^2 = 12.25 N

e = 12.25 N/ 888 N/m = 0.014 m or 1.4 cm

Work done by an external agent = 1/2 Kx^2

= 0.5 * 888 * (8 * 10^-2)^2

= 2.8 J

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Answer:

partecls

Explanation:

because they are to small to see with plain eyes

The liquid's surface tension in N/m is determined as 0.25 N/m.

Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Mathematically, the formula for surface tension of a liquid is given as;

γ = F/L

γ = F/2x

where;

From Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.

F = kx

where;

The final equation for the surface tension of the liquid film becomes;

γ = F/2x

γ = kx/2x

γ = k/2

γ = (0.5 N/m) / 2

γ = 0.25 N/m

Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.

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The velocity of the third piece is 124.02 m/s at 1.05⁰ below the horizontal.

The velocity of the third piece is calculated from the principle of conservation of linear momentum.

mu = m₁u₁ + m₂u₂ + m₃u₃

where;

6(22)sin(0) = 2(10)sin32 - 1(8)sin(28) + 3u₃y

0 = 6.84 + 3u₃y

u₃y = -6.84/3

u₃y = -2.28 m/s

ΔP = Pf - Pi = J

where;

2640(0.1) = 2(10)cos32 +  1(8)cos(28) + 3u₃x - 6(22)

264 = -108 + 3u₃x

3u₃x = 372

u₃x = 372/3

u₃x = 124 m/s

u₃ = √(124² + 2.28²)

u₃ = 124.02 m/s

tanθ = u₃y/u₃x

tanθ = 2.28/124

tanθ = 0.018

θ = 1.05⁰ (below the horizontal)

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Answer:

The four primary types of encoding are visual, acoustic, elaborative, and semantic. Encoding of memories in the brain can be optimized in a variety of ways, including mnemonics, chunking, and state-dependent learning.

Explanation:

You want to start a climb at 160 knots while cruising at 190 mph. It would be reasonable to perform the initial pitch change upon starting the climb (full panel) by increasing the rear elevator pressure until the Attitude indicator displays.

Once the knots are set, you can adjust the pressure until the pitch attitude indicator approximates the pitch attitude required for the 160-knot climb. The approximate pitch attitude needed for the 160-knot climb. You want to start a climb at 130 knots while cruising at 160 knots. It is proper to make the initial pitch change while starting a climb (full panel) by increasing the back elevator pressure until the attitude indicator displays the approximate pitch attitude needed for a 130-knot ascent. You want to start a climb at 130 knots while cruising at 160 knots. It is proper to adjust the initial pitch while commencing the climb (full panel) by raising the back elevator pressure till the end.

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Answer:

What was it

Explanation:

It would increase; g is inversely proportional to the square of the radius of the Earth. The correct option is A.

A current idea in geology that describes how the earth's crust is made up of a few big, hard plates that move independently of one another, causing deformation, volcanism, and seismic activity along their boundaries.

Because it explains how mountain ranges, earthquakes, volcanoes, shorelines, and other features often emerge where the moving plates contact along their boundaries, plate tectonics provides "the overall picture" of geology.

The Earth has been shrinking as it gradually cools, according to some geological hypotheses from the nineteenth century that have now been completely debunked.

If that were the case, it would rise since g is inversely proportional to the square of the Earth's radius.

Thus, the correct option is A.

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Answer:

The  value is  \(B = 0.0043 \ T\)

Explanation:

From the question we are told that

   The  length of the solenoid is  \(l = 63.5 = 0.635 \ m\)

    The number of turns is  \(N = 960 \ turns\)

    The  current is  \(I = 2.28 \ A\)

Generally the magnetic field is mathematically represented as

      \(B = \mu _o * n * I\)

Where  n is the number of turn per unit length which is mathematically evaluated as

      \(n = \frac{N}{l}\)

     \(n = \frac{960}{0.635}\)

     \(n = 1512 \ turns /m\)

and  \(\mu_o\) is the permeability of free space with value  \(\mu_o = 4\pi * 10^{-7} N/A^2\)

So  

    \(B = 4\pi * 10^{-7} * 1512 * 2.28\)

    \(B = 0.0043 \ T\)

Answer:

Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3.07 x 10^3 m/s.

Explanation:

A geosynchronous circular orbit is an orbit in which a satellite revolves around the Earth once every 24 hours so that it appears to be stationary in the sky relative to an observer on the ground. The radius of such an orbit is known as the geostationary radius and is approximately 42,164 km or 3.58 x 10^7 m above the surface of the Earth.

To find the orbital speed of a satellite in a geosynchronous circular orbit, we can use the formula:

v = (GM / r)^0.5

Where v is the orbital speed, G is the gravitational constant (6.674 x 10^-11 N m^2/kg^2), M is the mass of the Earth (5.97 x 10^24 kg), and r is the distance from the center of the Earth to the satellite (in this case, r = 3.58 x 10^7 m + radius of the Earth).

The radius of the Earth is approximately 6,371 km or 6.371 x 10^6 m. Therefore, the distance from the center of the Earth to the satellite is:

r = 3.58 x 10^7 m + 6.371 x 10^6 m

r = 4.217 x 10^7 m

Now we can plug in the values for G, M, and r into the formula and solve for v:

v = (GM / r)^0.5

v = [(6.674 x 10^-11 N m^2/kg^2) x (5.97 x 10^24 kg) / (4.217 x 10^7 m)]^0.5

v = 3.07 x 10^3 m/s

Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3.07 x 10^3 m/s.

Explanation:

The orbital speed of a satellite in a circular orbit around the Earth can be found using the following formula:

v = sqrt(G*M/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the distance from the center of the Earth to the satellite's orbit.

For a geosynchronous orbit, the satellite has a period of 24 hours, which means it completes one orbit in 24 hours. This corresponds to an orbital radius of:

R = 3.58 x 10^7 m + 6.38 x 10^6 m = 4.22 x 10^7 m

where 6.38 x 10^6 m is the radius of the Earth.

The mass of the Earth is approximately 5.97 x 10^24 kg, and the gravitational constant is approximately 6.6743 x 10^-11 N*(m/kg)^2. Substituting these values into the equation above, we get:

v = sqrt(GM/R) = sqrt(6.6743 x 10^-11 N(m/kg)^2 * 5.97 x 10^24 kg / 4.22 x 10^7 m) = 3074 m/s

Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3074 m/s.

The most logical conclusion to make in light of the facts available is that the electric field is directed to the left. This conclusion may be drawn from the fact that a negative test charge, which is attracted to positive charges and repels other negative test charges, feels a force to the right.

The force applied to the negative test charge suggests the presence of positive charges in the electric field, indicating that the field lines begin with positive charges and end on negative charges since opposing charges attract.

The assumption that electric field lines originate from positive charges and end on negative charges is supported by this deduction. As a result, in this situation, the electric field is directed leftward.

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Answer:

Group 1A (or IA) of the periodic table are the alkali metals: hydrogen (H), lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

Explanation:

Hope it helps! Correct me if I am wrong :>

Answer:

b. they are in free fall

Explanation:

-

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

All the three concurrent forces acting on a body will not produce equilibrium.

The given parameters:

1. 1 N, 3 N and 5 N

2. 2N, 2N and 2 N

3. 3N, 4N and 5 N

4. 4N, 4N and 5 N

Concurrent forces lie on the same plane and their line of action pass through a common point.

A body under concurrent forces is in equilibrium if the resultant of the forces on the body is zero.

\(\Sigma F = 0\\\\F_1 + F_2 + F_3 = 0\\\\F_1 + F_ 2 = - F_3\)

where;

\(F_3\) is the equilibrant force

First set of concurrent forces;

\(1 \ N \ + \ 3\ N = 4 \ N\\\\F_ 3 = 5 \ N\\\\5 \ N > 4 \ N\)

Second set of concurrent forces;

\(2 \ N \ + \ 2 \ N = 4 \ N\\\\F_ 3 = 2 \ N\\\\4 \ N > 2 \ N\)

Third set of concurrent forces;

\(3 \ N \ + \ 4 \ N = 7 \ N\\\\F_ 3 = 5 \ N\\\\7 \ N > 5 \ N\)

Fourth set of concurrent forces;

\(4 \ N \ + \ 4 \ N = 8 \ N\\\\F_ 3 = 5 \ N\\\\8 \ N > 5 \ N\)

Thus, we can conclude that all the three concurrent forces acting on a body will not produce equilibrium.

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Tire inflation should be checked when the tires are cold.

Tire inflation can be defined as a phenomenon in which the amount of air pressure (compressed air) in the tire of an automobile vehicle is greater than the recommended (standard) amount of air pressure that is required by the manufacturer, in order to enhance safety.

This ultimately implies that, tire inflation is a measure of the total amount of air pressure (compressed air) in the tire of an automobile vehicle as recommended by the manufacturer of the vehicle.

Additionally, proper tire inflation enhances safety and it can greatly influence gasoline mileage of an automobile vehicle. However, it is only appropriate to check tire inflation when the tire is cold.

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mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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Answer:

which of the cars are speeding up: c

which of the cars or slowing down: a

which of the cars are maintaning a constant speed: b

Explanation:

Answer:

Explanation:

I gave a good enough explanation in your other posting. I'm sorry that I'm eating up your points.

The orange line is speeding up

The blue line is neither speeding up nor slowing down. It's speed is constant.

The green line is starting from 4 m/s and is slowing down to 0.

The diagram helps a lot. Thank you for that.

The sequence that correctly lists earthquake waves from strongest to weakest is : ( C ) P waves -- S waves-- Surface waves

P waves are the strongest waves because they move more rapidly inside the incompressible earth core sending its energy at a hazardous rate, while the S waves are slower and produces vertical movement of the earth surface.

The weakest waves are the S waves which sweeps across the outer surface of the earth and they are also the slowest of all the waves.

Hence we can conclude that the sequence that correctly lists earthquake waves from strongest to weakest is P waves -- S waves-- Surface waves

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