Answer:
According to coulomb's law their potential energy will increase and the particles will repel each other.
Which brain region or part of the brain is responsible for hearing the sounds of a crowd in a baseball game?
Answer:
I think it's the auditory cortex or the temporal lobe
Which of these objects converts light to chemical energy?
Nuclear power plant
light bulb
Plant
solar cell/panel
From a laboratory process designed to separate water into hydrogen and oxygen gas, a student collected 10.0 g of hydrogen and 79.4 g of oxygen. What is the initial mass of water reacted?
According to law of conservation of mass and stoichiometry, 89.4 g of water initially reacted to produce 10 g hydrogen and 79.4 g oxygen.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.
According to the concept of law of conservation of mass, mass of reactants is equal to that of products.
So for the above reaction, mass of water will be equal to the sum of masses of hydrogen and oxygen.
The sum of mass of oxygen and hydrogen = mass of water
That is, 79.4+10=89.4 g of water.
Hence, the initial mass of water reacted is 89.4 g to yield 10 g hydrogen and 79.4 g oxygen.
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Convert 96.3g of calcium sulfate,CaSO4 into moles
Answer:
0.7073569530323789
Explanation:
They prob want it rounded tho so 0.71
How many mmol of iron are there in 650 mg of iron? O A. 11.6 mmol Fe B. 363.02 mmol Fe C. 55.85 mmol Fe D. 8.95 mmol Fe
There are 11.6 mmol of iron in 650 mg of iron.
Given the mass of iron as 650 mg. The molar mass of iron is 55.85 g/mol.
We need to calculate how many millimoles (mmol) are present in the given amount of iron.
We will use the following conversion:
1 g = 1000 mg
1 mol = molar mass in grams
1 mmol = 0.001 mol
Number of moles of iron
= 650 mg ÷ 1000 mg/g
= 0.65 g ÷ 55.85 g/mol
= 0.0116 mol
Number of millimoles of iron
= 0.0116 mol ÷ 0.001 mol/mmolar mass of iron
= 11.6 mmol
Hence, there are 11.6 mmol of iron in 650 mg of iron. Therefore, the correct option is A. 11.6 mmol Fe.
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One cup of milk contains 318 mg of calcium. A student drinks 0.318 L of milk in one day. How many mg of calcium does the student get in one day? (1 cup = 236.6 mL). Express your answer in 3 sig fig and scientific notation.
Answer:
426 mg = 4.26 x 10² mg
Explanation:
1 cup = 237.6 mL x 1 L/1000 mL = 0.2376 L
We divide the liters of milk the student drinks into the volume in liters of a cup to calculate the number of cups the student drinks per day:
number of cups per day = 0.318 L/0.2376 L = 1.34 cup
Now, we multiply the number of cups by the amount of calcium that a cup of milk has:
amount of calcium = 1.34 cup x 318 mg = 426 mg = 4.26 x 10² mg
Therefore, the student gets 426 mg (or 4.26 x 10² mg) of calcium in one day.
Draw the structure (s) - 1-bromo-1-chloropropane show wedges and dashes. Draw highest Newman projection looking down th C1-C2 bond
1-Bromo-1-chloropropane has a bromine atom bonded to the first carbon (C1), a chlorine atom bonded to the second carbon (C2), and the remaining carbons connected in a chain. The highest Newman projection looking down the C1-C2 bond shows the C1 atom in the front, the C2 atom at the back, and the other atoms (Br, C3, and Cl) attached to the C1 atom.
Here's the structure of 1-bromo-1-chloropropane, showing wedges and dashes:
Br
|
C
/
C
/
C - Cl
To draw the highest Newman projection looking down the C1-C2 bond, we need to imagine looking along that bond with the C1 atom in front and the C2 atom at the back. The attached atoms (Br, C1, C3, and Cl) will be represented as circles.
Here's the highest Newman projection:
Br
|
C3
/
C1
/
C2
/
Cl
The C1 atom is represented by the intersection of the horizontal and vertical lines, while the C2 atom is shown as the circle at the end of the vertical line. The other atoms (Br, C3, and Cl) are attached to the C1 atom, and their positions are represented by their corresponding circles.
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Consider the balanced equation. PCl3 + 3H2O Right arrow. H3PO3 + 3HCl What is the percent yield of HCl if 42.0 g of HCl are produced from the reaction of 62.0 g of PCl3? Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100..
Answer:
Percient yield of reaction: 85 %
Explanation:
The reaction is:
PCl₃ + 3H₂O → H₃PO₃ + 3HCl
We only have data from the chloride, so we assume water is in excess. We convert the mass to moles:
62 g . 1mol / 137.32 g = 0.452 mol
If ratio is 1:3, from 0.452 mol we would produce three times as big, that amount. (0.452 . 3) = 1.36 moles of HCl.
We convert the amount to mass.
1.36 mol . 36.45g / 1mol = 49.4 g
This value of produced HCl is the theoretical yield. To determine the percent yield we make:
(Yield produced / Theoretical yield) . 100
(42 g / 49.4g) . 100 = 85%
Answer:
Yes it is 85.0%
Explanation:
Consider the first reaction in the first proton-proton chain (PPI): 11H+11H→12H+e++νe (a) [5] Evaluate the Gamow energy EG in units of keV. (b) [5] Evaluate the energy E0 at which the reaction is most likely, assuming a temperature T=1.6×107 K. Express your result in keV and also evaluate kT in keV. (c) [5] Find the values of C1 and ΔE (again in keV ) in the Gaussian approximation. (d) [10] For these values of EG and T, appropriate for the first step of the dominant set of fusion reactions in the core of the Sun, plot the following quantities versus E/kT. (Put them on the same plot.) (i) The term that dominates the dependence of the integrand in equation (2.8.41) on energy E, namely exp(−EEG−kTE) 75 (ii) The approximation in equation (2.8.43), C1exp[−(ΔE/2E−E0)2] Normalize both functions to the maximum value (i.e. divide by the value at E=E0) and use linear scales on the axes.
Consider the first reaction in the first proton-proton chain (PPI):
11H+11H→12H+e++νeEG is Gamow energy, E0 is the energy at which the reaction is most likely, T is the temperature, C1 is the normalization constant, and ΔE is the half-width of the Gaussian approximation.(a) Evaluating the Gamow energy EG in units of keV:
EG = (π2/2) [(me/mH) (Z1Z2 e2/ħc)] (kT)where, me = mass of electron, mH = mass of hydrogen atom = 1.67 × 10-27 kg,Z1 = atomic number of H = 1, Z2 = atomic number of H = 1, e = electronic charge, ħ = Planck's constant / 2π, c = speed of light, k = Boltzmann constant, and T = temperature.= (π2/2) [(9.11 × 10-31 kg / 1.67 × 10-27 kg) (1 × 1 e2 / (1.054 × 10-34 J s × 2.998 × 108 m/s))] (1.602 × 10-19 J)= (π2/2) × 5.31 × 10-41 × 2.306 × 10-28= 1.44 × 10-3 keV.(b) Evaluating the energy E0 at which the reaction is most likely:
From equation (2.8.39) in the textbook,ln[(C1) (EG2) / (E0)2] = − (ΔE)2 / (4k2T2) + EG/kTln[(C1) (EG2) / (E0)2] = − (ΔE)2 / (4k2T2) + ln(exp(EG/kT))ln[(C1) (EG2) / (E0)2 exp(-EG/kT)] = − (ΔE)2 / (4k2T2)ln[(C1) (EG2 / exp(EG/kT)) / (E0)2] = − (ΔE)2 / (4k2T2)ln[(C1) (EG / kT)2 / (E0)2] = − (ΔE)2 / (4k2T2) - ln(exp(EG/kT))ln[(C1) (EG / kT)2 / (E0)2 exp(-EG/kT)] = − (ΔE)2 / (4k2T2)Evaluating the above equation for T = 1.6 × 107 K, EG = 1.44 × 10-3 keV, and using k = 8.62 × 10-5 eV/K= - 5.45ln[(C1) (1.44 × 10-3 keV / (1.38 × 10-5 eV/K × 1.6 × 107 K))2 / (E0)2 exp(-1.44 × 10-3 keV / (1.38 × 10-5 eV/K × 1.6 × 107 K))]= - 5.45ln[(C1) (1.04 × 1021) / (E0)2 (0.951)]= - 3.15 + ln[(C1) / (E0)2]ln[(C1) / (E0)2] = 8.6Evaluating the above equation for the maximum value of ln[(C1) / (E0)2], i.e., 8.6, we get,(C1) / (E0)2 = 3.53 × 108C1 = (E0)2 × 3.53 × 108Putting T = 1.6 × 107 K in the equation for kT,kT = 1.38 × 10-23 J/K × 1.6 × 107 K / 1.602 × 10-19 J/eV= 13.8 keV.(c) Finding the values of C1 and ΔE in the Gaussian approximation:
Using the normalization condition,∫(C1) exp[-(E - E0)2 / (2ΔE2)] dE = 1Putting C1 = (E0)2 × 3.53 × 108,∫(E0)2 × 3.53 × 108 exp[-(E - E0)2 / (2ΔE2)] dE = 1(ΔE) (E0) √(π/2) × 3.53 × 108 = 1ΔE = 5.97 × 10-4 keV.C1 = 5.39 × 1012.(d) Plotting the given quantities:
Normalized Gaussian function = (C1 / (E0)2) exp[-(E - E0)2 / (2ΔE2)] / (C1 / (E0)2) at E = E0 = 6.4 keV = 1.Exponential function = exp[-(E - E0) / EG] exp[-(E - E0) / kT] / exp[-(E0 - E0) / EG] exp[-(E0 - E0) / kT] at E = E0 = 6.4 keV = 1.(Note that exp[-(E - E0) / kT] ≈ 1 for E ≈ E0.)Using linear scales on the axes, we get the following graph.About ReactionA chemical reaction is a process in which a substance or reactant is changed into a different substance and is called a product, a chemical reaction rearranges the atomic composition of the reactants so as to make a different substance as a product. A chemical reaction can occur when there are effective collisions with sufficient energy between the molecules of the reacting substances. The chemical reactions that take place can be identified by changes in temperature, color, and the formation of precipitates and gases. The chemical reactions that take place can be identified by changes in temperature, color, and the formation of precipitates and gases.
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Glass has a hardness that is in the middle of the hardness scale What is the hardness of Glass
Hardness 9
Hardness 8
Hardress 5
tardress 10
The correct answer is option c. Glass has a hardness that is in the middle of the hardness scale. So, the hardness of Glass is 5.
Glass possess high hardness levels compared to many other materials. The majority of glass varieties are brittle in nature, which makes them susceptible to breaking. The high hardness level of glass is due to silicon dioxide's robust Si-O chemical bonds. Glass imperfections, like bubbles and such as surface flaws, like scratches, mostly affects glass strength that reduce it more as they do for other fragile materials.
The hardness of glass can be measured by "Mohs Test," that compares the "scratch hardness" of 10 reference minerals. A mineral's hardness is defined as a measure of its relative resistance to scratching. It is measured by scratching the mineral against another substance of known hardness on the Mohs Hardness Scale.
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chemicals that accumulate in soil and water as a result of car emissions, improperly disposed waste, industry, and agriculture are known as
The chemicals that accumulate in soil and water as a result of car emissions, improperly disposed waste, industry, and agriculture are known as persistent organic pollutant.
What is persistent organic pollutant ?Organic molecules that are resistant to environmental deterioration through chemical, biological, and photolytic processes are persistent organic pollutants, sometimes referred to as "forever chemicals."
They are dangerous compounds that have a negative impact on the environment and human health all over the world.
POPs are compounds that are persistent in the environment, bioaccumulate in the food chain, and have the potential to have negative impacts on both human health and the ecosystem.
Thus, persistent organic pollutants are hazardous compounds that have a negative impact on the environment and human health all over the world.
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I NEED HELP PLEASE THANK YOUUU
I think the answer is c if not then try a
Answer: B
Explanation:
About which other carbon–carbon bonds may rotation occur on 2 methylhexane
Check all that apply.
C-1−C-2 bond
C-2−C-3 bond
C-4−C-5 bond
C-5−C-6 bond
C-2−C-7 bond
The carbon-carbon bonds where rotation can occur on 2-methylhexane are the C-1−C-2 bond, C-2−C-3 bond, and C-5−C-6 bond.
Rotation is possible around single bonds, and in 2-methylhexane, these bonds are all single bonds. The C-1−C-2 bond, C-2−C-3 bond, C-4−C-5 bond, and C-5−C-6 bond are all single bonds, allowing for free rotation. On the other hand, the C-2−C-7 bond is not present in 2-methylhexane and therefore rotation cannot occur on that specific bond.
In 2-methylhexane, rotation can occur around the following carbon-carbon bonds:
C-1−C-2 bond: Yes, rotation can occur around this bond.
C-2−C-3 bond: Yes, rotation can occur around this bond.
C-4−C-5 bond: No, rotation cannot occur around this bond because it involves the methyl group attached to the second carbon, which creates a hindered rotation.
C-5−C-6 bond: Yes, rotation can occur around this bond.
C-2−C-7 bond: No, rotation cannot occur around this bond because it involves the methyl group attached to the second carbon, which creates a hindered rotation.
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Why do some substances float on water?
they are less dense
than water
they are warmer
than water
they are more
dense than water
FILL THE BLANK. the ________________ statement immediately halts execution of the current method and allows us to pass back a value to the calling method.
The "return" statement immediately halts execution of the current method and allows us to pass back a value to the calling method. When encountered in a method, the return statement exits the method's execution flow and transfers control back to the caller.
It is a fundamental mechanism for returning a result or value from a method. By specifying the return keyword followed by the desired value or variable, we can effectively terminate the current method and provide the desired output to the calling code.
The returned value can be utilized in various ways, such as assigning it to a variable, using it in expressions, or passing it as an argument to another method.
Overall, the return statement plays a crucial role in controlling program flow and enabling the exchange of information between methods in a structured manner.
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What is the pH of a 0.10 M solution of carbonic acid?
The pH of a 0.10 M solution of carbonic acid is 3.12.
To calculate the pH of a solution, we use the equation pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. In the case of carbonic acid, the dissociation equation is:
H2CO3 → H+ + HCO3-
The concentration of hydrogen ions in the solution is equal to the concentration of carbonic acid, which is 0.10 M. Plugging this value into the equation for pH, we get:
pH = -log[0.10]
pH = 3.12
Therefore, the pH of a 0.10 M solution of carbonic acid is 3.12.
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How many chlorine atoms in 3ZnCl2
Answer:
6 Cl atoms
Explanation:
In one molecule of ZnCl2, we have 2 atoms of Cl
Therefore, in 3 molecules of ZnCl2, we'll have 3(2) atoms of Cl = 6 atoms of Cl.
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what is sodium acetate formula?
The chemical formula for sodium acetate is NaC₂H₃O₂.
Sodium acetate is the sodium salt of acetic acid (also known as ethanoic acid), and it is commonly used in the food industry, as a buffer in chemical reactions, and as a component in heating pads. The formula indicates that the molecule contains one sodium (Na) ion, one acetate ion (C₂H₃O₂⁻), and a total of three oxygen atoms.
sodium acetate is a white crystalline powder that is soluble in water. It has a slightly salty and vinegar-like taste, and it is commonly used as a food seasoning, particularly in snack foods like chips and popcorn.
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Does heat flow out of the atmosphere (Hout) change during a day?
Answer: The heat flows into Earth's atmosphere which changes as the Sun rises and sets, which increases during the day.
Explanation:
Does indium react with acid?
what type of element is always radioactive?
Jim went for a 3.75 hour run. How many minutes did he run?
The average speeds of gas molecules in cylinders A, B, C, and D are 0. 001 m/s, 0. 05 m/s, 0. 1 m/s, and 0. 0005 m/s respectively. Which cylinder contains gas that is closest to absolute zero? A B C D.
The cylinder that contains gas closest to absolute zero temperature is cylinder D.
The correct option is cylinder D, 0. 0005 m/s.
What is gas?Gas is one of the four states of matter. Gas is made up of individual atoms. The molecules of gas are very far from each other.
There are many gases present in the atmosphere.
The speed of gas depends on the temperature of the cylinder. The lower the temperature, the slower the speed of the molecule of gas.
Thus, cylinder D (0. 0005 m/s) has the slowest speed, which is related to low temperature absolute zero.
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What is generally the best approach when liquid from a large reagent bottle is needed in an experiment
Answer:
See the answer below
Explanation:
The best approach would be to pour the liquid from the large reagent bottle into a small-size beaker or reagent bottle first, before measuring the required quantity out into the reaction vessel. This is necessary in order to maintain safety in the laboratory.
Pouring the liquid directly from the large reagent bottle into the measuring cylinder or directly into the reaction bottle can compromise safety in the laboratory. The liquid might splash out and cause harm to the handler or create other harmful circumstances in the laboratory.
The information regarding the liquid should be explained below;
The following information should be considered;
The best approach should be to pour the liquid from the large reagent bottle into a small-size beaker or reagent bottle first, prior determining the required quantity out into the reaction vessel. This is necessary in order to maintain safety in the laboratory.Learn more: https://brainly.com/question/5566317?referrer=searchResults
what do the letters in the boxes of the periodic table represent
Answer:
The letters are a one- or two-letter symbol assigned to each element.
Explanation:
If an atmosphere consisting of an ideal gas were indeed homogeneous (constant density) all the way to the top at z = H, find the temperature at that top. Could such an atmosphere actually exist, even in principle? Why or why not?
The temperature at the top of an atmosphere consisting of an ideal gas with constant density can be found using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Assuming the density of the gas is constant throughout the atmosphere, we can express the pressure as P = ρgh, where ρ is the density, g is the acceleration due to gravity, and h is the height.
Since the atmosphere is homogeneous, the pressure at the top (P_top) is the same as the pressure at the bottom (P_bottom), so we have P_top = P_bottom = ρgh.
Using the ideal gas law, we can write ρghV = nRT, where V is the volume of the gas.
Assuming the volume of the gas is constant, we can cancel out V, and rearranging the equation, we get T_top = (nRT_bottom)/(nR) = T_bottom.
Therefore, the temperature at the top of the atmosphere would be the same as the temperature at the bottom.
In practice, however, it is not possible for an atmosphere to have constant density all the way to the top. As we go higher in the atmosphere, the density decreases due to decreasing pressure and temperature. This is because gravity becomes weaker at higher altitudes. Therefore, in reality, the temperature would decrease as we move higher in the atmosphere.
So, while a homogeneous atmosphere with constant density all the way to the top cannot exist in practice, it can be considered as an idealized scenario for understanding certain aspects of atmospheric behavior.
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please someone explain this I dont get it at all. how do we know that the 4th electron came from 2p because it's at 4th ionisation? why is it talking about 3s?? how do overall know that aluminium is in group 3 from the table??? thanks
WILL GIVE BRAINLIEST PLS HELP
Answer: I think the answer is B
What is the dominant imf in the molecule ch3ch oh cooh?
The dominant IMF in the molecule CH3CH OH COOH is H-bonding.
The attraction between molecules known as hydrogen bonding is a unique form of dipole-dipole attraction; it is not a covalent bind to an individual hydrogen atom. It comes about as a result of the attraction between two extremely electronegative atoms, such as N, O, or F, and a hydrogen atom that is covalently bound to one of them.
Both CH3CH and CH3CH2OH can form hydrogen bonds, however, CH3CH2OH has more CH bonds and can interact with dispersion forces more strongly. The higher boiling point, therefore, belongs to the CH3CH2OH.
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Please help me out this is a test.
The imaje shows a plate baundary. Arrows have been added to indicate the movement if the plates.