The 95% confidence range for the difference in the percentages of sleep deprived people in California and Oregon is from -0.0015 to 0.0175.
With a 95% confidence level or 0.05 significance level, we may say that this range overlaps 0 and that the proportions are not statistically different. In other words, based on the findings from this sample, the proportion of the CA and OR populations may be equal.
What is a confidence interval?
A confidence interval (CI) is a range of estimates for an unknown parameter in frequentist statistics. The 95% confidence level is the most popular, however other levels, such 90% or 99%, are occasionally used when computing confidence intervals. The percentage of related CIs over the long run that include the parameter's actual value is represented by the confidence level. For instance, 95% of all intervals calculated at the 95% level should include the parameter's actual value.
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A mathematics teacher wanted to see the correlation between test scores and homework. The homework grade (x) and test grade (y) are given in the accompanying table. Write the linear regression equation that represents this set of data, rounding all coefficients to the nearest hundredth. Using this equation, estimate the homework grade, to the nearest integer, for a student with a test grade of 85.
The linear regression equation that represents this set of data is y = 1.19x - 1.55, and the estimated homework grade for a student with a test grade of 85 is 101.
To find the linear regression equation, we first need to calculate the correlation coefficient (r). Using a calculator or software, we find that r = 0.91, indicating a strong positive correlation between homework and test scores.
Next, we use the formula for the equation of a line: y = mx + b, where m is the slope and b is the y-intercept.
The slope (m) can be found using the formula:
m = r(Sy/Sx),
where Sy is the standard deviation of y and Sx is the standard deviation of x. Using the values from the table, we find that Sy = 13.48 and Sx = 10.34. Therefore, m = 0.91(13.48/10.34) = 1.19.
To find the y-intercept (b), we can use the formula: b = y - mx, where y and x are the means of the test and homework scores, respectively. From the table, we find that the mean test score is 83 and the mean homework score is 75. Therefore,
b = 83 - 1.19(75) = -1.55.
Putting it all together, the linear regression equation is:
y = 1.19x - 1.55.
To estimate the homework grade for a student with a test score of 85, we substitute x = 85 into the equation:
y = 1.19(85) - 1.55 = 101.3.
Rounding to the nearest integer, we estimate the homework grade to be 101.
Therefore, the linear regression equation that represents this set of data is y = 1.19x - 1.55, and the estimated homework grade for a student with a test grade of 85 is 101.
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83,456-728.88 what is the answer
The required answer to the subtraction problem 83,456 - 728.88 is, 82,727.12
What is subtraction?Subtraction is mathematical terminology that helps and elaborates the decrease in the original value by some value.
Here,
To perform the subtraction, you line up the decimal points and subtract the digits in each place value starting from the right. In this case, you subtract 8 from 6, which requires borrowing 1 from the digit to the left, giving you 16 - 8 = 8 in the one's place. You then subtract 2 from 5, giving you 3 in the tenth place. Continuing this process, you get the result of 82,727.12.
Thus, the answer to the subtraction problem 83,456 - 728.88 is, 82,727.12
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If the ball moves 4 yards in one direction and then 4 yards in the opposite direction where is the final position of the ball
Light travels at a speed of about 1.86×10^5 miles per second. Suppose a space ship is able to travel at the speed of light. If the distance around Earth along the Equator is about 2.48×10^4 miles, how many times could the space ship travel around the Earth in 1 second? Round to the nearest tenth if necessary.
Based on the speed that light travels and the distance around the Earth along the Equator, the number of times the space ship would travel in 1 second is 0.133 times
How to find the number of times the spaceship would travel around Earth?The number of times that the space ship would travel around Earth around the Equator, going at the speed of light is:
= Distance around the Earth along the Equator / Speed of light
Solving for the number of times around the Earth for the space ship gives:
= 2.48×10⁴ / 1.86×10⁵
= 24,800 / 186,000
= 0.133 times
In conclusion, going at the speed of light, the space ship would go around the Earth, along the equator, 0.133 times.
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If i detect the electron passing through the left slit, what are the probabilities associated with it now?.
If you detect the electron passing through the left slit in a double-slit experiment, the probabilities associated with it will depend on the specific setup and conditions of the experiment.
In a basic double-slit experiment, where a beam of electrons or particles is directed towards two slits, the probability of detecting the particle at a particular location on the screen depends on the interference pattern formed by the interaction of the wave-like nature of the particles. When the electron passes through the left slit, it implies that the particle's wavefunction has "collapsed" or "localized" to a specific position associated with the left slit. In this case, the probability of detecting the electron at a specific location on the screen will be concentrated around the corresponding position associated with the left slit. The probability distribution on the screen will generally show a pattern characterized by a central maximum and alternating regions of constructive and destructive interference, depending on the relative distances between the slits, the screen, and the wavelength of the particle. It's important to note that the specific probabilities associated with detecting the electron at different positions on the screen will vary depending on the details of the experimental setup, such as the dimensions of the slits, the distance between the slits and the screen, and the wavelength of the particles. To determine the exact probabilities, one would need to know the specifics of the experiment and apply the principles of quantum mechanics and wave-particle duality to calculate or measure the probabilities associated with the electron passing through the left slit.
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what is the length of side B in the above right triangle
Answer:
b is 3 pythagorean theorem
Step-by-step explanation:
Answer:
your answer for B is 3
Step-by-step explanation:
this is easy its a Pythagorean Triple (with triples u dont have to do much work all u have to do is know ur Triples and its that easy)
so the Triples are
3,4,55,12,138,15,177,24,25p.s you might want to write these down for the future
so if we look at this picture of the triangle we can tell its a 3,4,5 triple
and there is one missing side which is 3.
Find the slope from the table.
Answer:
slope = 4/1 or 4
Step-by-step explanation:
(2, 14)
(1, 10)
Formula = \(\frac{y^2-y^1}{x^2-x^1}\)
14-10 over 2 -1
4/ 1 = 4
Find the mode for the following data set:10 30 10 36 26 22
In this particular data set, 10 is the only value that occurs more than once, so it is the only mode
The mode is the value that occurs most frequently in a data set. In the given data set {10, 30, 10, 36, 26, 22}, we can see that the value 10 occurs twice, and all other values occur only once. Therefore, the mode of the data set is 10, since it occurs more frequently than any other value in the set.
Note that a data set can have multiple modes if two or more values occur with the same highest frequency. However, in this particular data set, 10 is the only value that occurs more than once, so it is the only mode.
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which of these expression is equivalent to 2×+XY
The diagram below shows two wires carrying anti-parallel currents. Each wire carries 30 amps of current. The centers of the wires are 5 mm apart. Point P is 15 cm from the midpoint between the wires. Find the net magnetic field at point P, using the coordinate system shown and expressing your answer in 1, 1, k notation. 5mm mm = 10-³ cm=102m I₂ (out) P •midpan't betwem wires 1 X- I, (in)! (30A) 15cm →X Z(out)
The net magnetic field at point P is (6e-5 j + 0.57 k) T in 1, 1, k notation.
We can use the Biot-Savart Law to calculate the magnetic field at point P due to each wire, and then add the two contributions vectorially to obtain the net magnetic field.
The magnetic field due to a current-carrying wire can be calculated using the formula:
d = μ₀/4π * Id × /r³
where d is the magnetic field contribution at a point due to a small element of current Id, is the vector pointing from the element to the point, r is the distance between them, and μ₀ is the permeability of free space.
Let's first consider the wire carrying current I₁ (in the positive X direction). The contribution to the magnetic field at point P from an element d located at position y on the wire is:
d₁ = μ₀/4π * I₁ d × ₁ /r₁³
where ₁ is the vector pointing from the element to P, and r₁ is the distance between them. Since the wire is infinitely long, we can assume that it extends from -∞ to +∞ along the X axis, and integrate over its length to find the total magnetic field at P:
B₁ = ∫d₁ = μ₀/4π * I₁ ∫d × ₁ /r₁³
For the given setup, the integrals simplify as follows:
∫d = I₁ L, where L is the length of the wire per unit length
d × ₁ = L dy (y - 1/2 L) j - x i
r₁ = sqrt(x² + (y - 1/2 L)²)
Substituting these expressions into the integral and evaluating it, we get:
B₁ = μ₀/4π * I₁ L ∫[-∞,+∞] (L dy (y - 1/2 L) j - x i) / (x² + (y - 1/2 L)²)^(3/2)
This integral can be evaluated using the substitution u = y - 1/2 L, which transforms it into a standard form that can be looked up in a table or computed using software. The result is:
B₁ = μ₀ I₁ / 4πd * (j - 2z k)
where d = 5 mm = 5×10^-3 m is the distance between the wires, and z is the coordinate along the Z axis.
Similarly, for the wire carrying current I₂ (in the negative X direction), we have:
B₂ = μ₀ I₂ / 4πd * (-j - 2z k)
Therefore, the net magnetic field at point P is:
B = B₁ + B₂ = μ₀ / 4πd * (I₁ - I₂) j + 2μ₀I₁ / 4πd * z k
Substituting the given values, we obtain:
B = (2×10^-7 Tm/A) / (4π×5×10^-3 m) * (30A - (-30A)) j + 2(2×10^-7 Tm/A) × 30A / (4π×5×10^-3 m) * (15×10^-2 m) k
which simplifies to:
B = (6e-5 j + 0.57 k) T
Therefore, the net magnetic field at point P is (6e-5 j + 0.57 k) T in 1, 1, k notation.
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For what value of n is |n− 1| + 1 equal to 0 ?
Answer:
|n - 1| + 1 = 0
|n - 1| = -1
no solution
the 150 residents of the town of wonderland were asked their age and whether they preferred vanilla, chocolate, or swirled frozen yogurt. the results are displayed next. chocolatevanillaswirl under 25 years old402015 at least 25 years old154020 what is the probability a randomly selected customer prefers chocolate given he or she is at least 25 years old?
If 150 town residents were asked about their age and yogurt , then the probability that a randomly selected customer prefers Swirl if age is at least 25 years old is 0.66 .
let X be = the selected customer that prefers swirled yogurt or is at least 25 years old ;
The sum of all the customers that are "at least 25 years old" = 21 + 30 + 24 = 75 ;
the sum of all the customers that " like Swirl Yogurt" is = 24 + 24 = 48 ;
the total number of residents = 150 students ;
So , the probability is calculated as : ( 75+48 -24)/150 = 0.66 .
Therefore , the required probability is 0.66 .
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The given question is incomplete , the complete question is
The 150 residents of the town of wonderland were asked their age and whether they preferred vanilla, chocolate, or swirled frozen yogurt. the results are displayed next.
Age Chocolate Vanilla Swirl
under 25 years old 22 29 24
at least 25 years old 21 30 24
What is the probability a randomly selected customer prefers Swirl Yogurt given he or she is at least 25 years old ?
Simplify as fully as possible
4x²y^4 × (3xy²)² / 2x²y×4xy^9
Answer:
The answer is ;
9x/2y^2
Step-by-step explanation:
Here, we want to simplify as far as possible
Let us take all the numbers one after the other
All numbers on numerator and denominator;
(4 * 9)/(2 * 4) = 9/2
All x
(x^2 * x^2)/(x^2 * x) = x
All y
(y^4 * y^4)/(y * y^9) = y^8/y^10 = 1/y^2
So the complete answer is;
9/2 * x * 1/y^2
= 9x/2y^2
can someone helpe me please. i need the answer for this d*umb test. thanks!
Answer:
B: SAS
Step-by-step explanation:
You know that QR is congruent to PS.
You also know that angle qsr and pqs are both 90 degrees.
Lastly QS is a shared side so it must be the same length.
Answer:
D. HL
Step-by-step explanation:
given right angle, hypotenuse and a leg which is basically HL
ps and QR is congruent bc of given
QS=QS bc it's the same thing
Mark hopes to one day earn 10000 dollars predict how many clients mark would need to train
Multiply 200 times 5, since 2 times 5 equals 10 then you just need to add 2 more zeros so it will be 1000
how to solve (n^(3)+3n^(2)+3n+28)-:(n+4) in long polynomial division?
Answer:
Open the image. (Hope you don't mind about bad writing)
Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) for this problem. A quality inspector took the following samples of the length of time (in seconds) for glue to dry. Please round your calculations to three decimal places. Sample 1 Obs. 1 125 Obs. 3 122 Obs. 2 126 100 155 Obs. 4 132 121 118 Obs. 5 114 125 142 2 130 110 140 129 3 a) What is the value of ? x = seconds (round your response to three decimal places). b) What is the value of R? R= seconds (round your response to three decimal places). c) What are the UCL, and LCL, using 3-sigma? Upper Control Limit (UCL;) = seconds (round your response to three decimal places). Lower Control Limit (LCL;) = seconds (round your response to three decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR) = seconds (round your response to three decimal places). Lower Control Limit (LCLR) = seconds (round your response to three decimal places).
To find the value of x, we calculate the average of the sample observations. Summing up the observations and dividing by the total number of observations, we get:
x = (125 + 122 + 126 + 100 + 155 + 132 + 121 + 118 + 114 + 125 + 142 + 2 + 130 + 110 + 140 + 129 + 3) / 17 = 114.118 seconds (rounded to three decimal places).b) To find the value of R, we calculate the range of each sample by subtracting the minimum observation from the maximum observation. Then we find the average range across all samples:R = (155 - 100 + 142 - 2 + 140 - 110 + 132 - 114 + 142 - 3) / 5 = 109.2 seconds (rounded to three decimal places).
c) The Upper Control Limit (UCL) and Lower Control Limit (LCL) using 3-sigma can be calculated by adding and subtracting three times the standard deviation from the average:UCL = x + (3 * R / d2) = 114.118 + (3 * 109.2 / 1.693) = 348.351 seconds (rounded to three decimal places).LCL = x - (3 * R / d2) = 114.118 - (3 * 109.2 / 1.693) = -120.115 seconds (rounded to three decimal places).
d) The Upper Control Limit Range (UCLR) and Lower Control Limit Range (LCLR) using 3-sigma can be calculated by multiplying the average range by the appropriate factor:UCLR = R * D4 = 109.2 * 2.115 = 231.108 seconds (rounded to three decimal places).LCLR = R * D3 = 109.2 * 0 = 0 seconds.
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Awnser and show your work <3
Answer:
Team A: 25 players
Team B: 24 players
Step-by-step explanation:
Team A:
to find the total # of players of the team we need to set up a fraction. 5 out out of an unknown number of players is equal to 1/5, so we set it up as:
\(\frac{5}{x} = \frac{1}{5}\)
then we cross multiply to get
x*1 = 5*5
x=25 players
Team B
similarly to Team A
\(\frac{3}{x} = \frac{1}{8}\)
cross multiply to get
x*1=3*8
x= 24 players
The ratio of girls to boys in a class is 6 to 8. If there are 27 girls in the class, how many boys are there?
Answer:
36
Step-by-step explanation:
Use the distance formula to find the distance between each pair of points. Round your answers to the nearest hundredths place W (-3,-5) and T (2,-2)
Answer:
The answer is
5.83 unitsStep-by-step explanation:
The distance between two points can be found by using the formula
\(d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\ \)
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
W (-3,-5) and T (2,-2)
The distance between them is
\( |WT| = \sqrt{ ({ - 3 - 2})^{2} + ( { - 5 + 2})^{2} } \\ = \sqrt{ ({ - 5})^{2} + ( { - 3})^{2} } \: \: \: \\ = \sqrt{25 + 9} \\ = \sqrt{34} \: \: \: \: \: \: \: \: \\ = 5.830951\)
We have the final answer as
5.83 units to the nearest hundredthHope this helps you
Answer:
√34
Step-by-step explanation:
\(W (-3,-5) =(x_1,y_1)\\T (2,-2)=(x_2,y_2)\\\\d = \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\d=\sqrt{\left(2-\left(-3\right)\right)^2+\left(-2-\left(-5\right)\right)^2}\\\\d=\sqrt{\left(2+3\right)^2+\left(-2+5\right)^2}\\\\d=\sqrt{5^2+3^2}\\\\d=\sqrt{25+9}\\\\d=\sqrt{34}\)
which number is one less than a cube number?
20
22
24
26
The number less than a cube is 26.
What is cube of a number?The cube of a number is obtained by multiplying the number three times.
Determine the cube of 3.
3·3·3=27
So, the cube of 3 is 27.
From the given options it can be observed that the number 26 is 1 less than 27.
Thus, the number one less than cube is 26.
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a club elects a president, vice-president, and secretary-treasurer. how many sets of officers are possible if there are 15 members and any member can be elected to each position? no person can hold more than one office.
By applying permutation concepts, there are 2730 possible sets of officers.
Permutation calculates the number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed.
P(n,r) = n! / (n-r)!
where n is the number of objects and r is the number of samples
In such an election, each person can only occupy one office. Therefore, the permutation concept is precisely used to calculate the number of ways to set these people.
P(15,3) = 15! / (15 - 3)!
= (15 x 14 x 13 x 12!) / 12!
= 15 x 14 x 13
= 2730 ways
Thus, there are 2730 possible sets of officers.
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write a literal representing the character whose unicode value is 65.
Put the character whose Unicode values is 65 in a literal form 65.A' is the actual letter A. (Unicode code value 65) The literal form of the letter 'a' (Unicode code value 97) The character literal for "1" (Unicode code value 49)
Different languages, scripts, and symbols are all included in the international character encoding standard known as Unicode. A distinct Unicode value is assigned to each letter, number, and symbol. ASCII can now represent a far larger number of characters thanks to Unicode. More than a million code points are supported by Unicode, and they are denoted by the letter "U," a plus sign, and the code point's hexadecimal value. When one character is given as an argument to ord(), the character's Unicode code point is returned as an integer int. If you enter a string that contains more than two characters, an error is generated. In hexadecimal notation, Unicode code points are frequently written.
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PLEASE HELP ME Which function is equivalent to y = 2 (x - 4)^2 + 8?
A. y = 2x^2 + 24
B. y = 2x^2 - 16x + 40
C. y = 2x^2 - 16x + 48
D. y = 2x^2 - 8x + 24
Answer:
a
Step-by-step explanation:
The function that should be equivalent is option b. \(y = 2x^2 - 16x + 40\)
Calculation of the functionSince
the equation is \(y = 2 (x - 4)^2 + 8\)
\(y = 2(x^2 - 8x + 16) + 8\\\\y = 2x^2 - 16x + 32 + 8\\\\y = 2x^2 - 16x + 40\)
Therefore, we can conclude that The function that should be equivalent is option b. \(y = 2x^2 - 16x + 40\)
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the slopes of the search functions for the control subjects and the split-brain patients differed in what way?
Therefore , the solution of the given problem of slope comes out to be less consistent than that of the split-brain patients.
Define slopeThe slope of a line determines how steep it is. Equations predicated on gradients might experience gradient overflow. One can determine the slope by dividing the midpoint of the run (length difference) between two points by the rise (vertical differentiation) between the same two points. The equation of the hill type with the notation y = mx + b is used to model the fixed path problem.
Here,
Given :
A slope having search functions for the control subjects and
the split-brain patients is different because
In general, the control participants' performance was less consistent than that of the split-brain patients.
Therefore , the solution of the given problem of slope comes out to be less consistent than that of the split-brain patients.
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help.. again please tysm :)
Answer:
No Solutions
Step-by-step explanation:
The two points are (3,2) and (-2,-2)
Slope is y change over x change.
So... -2-2 over -2-3 equals to -3-(-2) over -2-(-2).
That is -3+2 over -2+2 which is -2 over 0.
You can't divide by zero so the slope is "NoSolutions"
Hope this helps :)
b) Obtain reduced cost matrix for travelling sales person problem. Consider the instance define by the cost matrix: [8M] 00 5 1 10 6 4 12 7 1 Pa 8 a 3 7 6 1 8نرا 4 16 9 3 8 a 16 12 7 6 00 *****
The reduced cost matrix for travelling salesperson problem in the given instance is shown below. The Travelling Salesperson Problem (TSP) is a classical combinatorial optimization issue that belongs to the category of NP-Hard problems.
This problem can be resolved using a branch and bound algorithm or by using dynamic programming.The reduced cost matrix for the given travelling salesperson problem instance The computation of the reduced cost matrix for travelling salesperson problem involves two steps: Identify the smallest element of each row and subtract the value from all the values in the row.
Identify the smallest element of each column and subtract the value from all the values in the column.In the given instance, the smallest element of each row is highlighted in bold. Therefore, after performing Step 1 the matrix becomes the matrix becomes Hence, the reduced cost matrix for the travelling salesperson problem is obtained.
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Leonhard Euler was able to calculate the exact sum of the p-series with p = 2:
ζ(2)=[infinity]∑n−11n2=π26(2)=∑−1[infinity]12=26
Use this fact to help find the sum of each series.
(a) [infinity]∑n−21n2∑−2[infinity]12
(b) [infinity]∑n−31(n+1)2∑−3[infinity]1(+1)2
(c) [infinity]∑n−11(2n)2
The sum of (a) [infinity]∑n−21n2∑−2[infinity]12 is π²/6) - 1. The sum of (b) [infinity]∑n−31(n+1)2∑−3[infinity]1(+1)2 is π²/6) - 14. The sum of (c) infinity ∑ n-1 1/(2n)²∑n=1∞ 1/(2n)² is π²/96.
(a) infinity ∑ n-2 1/n²(ζ(2) = π²/6)(ζ(2) = π²/6)∑n=2∞ 1/n²
Let, the sum of the series be S.(S = infinity ∑ n-2 1/n²)
We know that, ζ(2) = π²/6S = infinity ∑ n-2 1/n²= 1 + 1/4 + 1/9 + 1/16 + 1/25 + .......π²/6= 1 + 1/4 + 1/9 + 1/16 + 1/25 + .......
Therefore, (infinity ∑ n-2 1/n²) = (ζ(2) = π²/6) - 1
Using this, we can find the sum of the series (a).
(b) infinity ∑ n-3 (n+1)²= infinity ∑ n-3 (n² + 2n + 1)
Let the sum of the series be S.(S = infinity ∑ n-3 (n+1)²)S = infinity ∑ n-3 (n² + 2n + 1)= infinity ∑ n-3 n² + 2 ∑ n-3 n + ∑ n-3 1
Let's find the value of each of the sums, ∑ n-3 n², ∑ n-3 n, and ∑ n-3 1.
We know that,∑ n² = n(n+1)(2n+1)/6∑ n = n(n+1)/2∑ 1 = nS = infinity ∑ n-3 n² + 2 ∑ n-3 n + ∑ n-3 1= (infinity ∑ n-3 n²) + 2(infinity ∑ n-3 n) + (infinity ∑ n-3 1)- (1² + 2² + 3²) - (1 + 2)- 3= (infinity ∑ n-1 n²) - 14S = (ζ(2) = π²/6) - 14
(c) infinity ∑ n-1 1/(2n)²∑n=1∞ 1/(2n)²
Let, the sum of the series be S. (S = infinity ∑ n-1 1/(2n)²)
We know that,ζ(2) = π²/6= 1 + 1/4 + 1/9 + 1/16 + 1/25 + .......= 1 + 1/4 + 1/16 + 1/36 + 1/64 + .......= (1/2²) + (1/4²) + (1/6²) + (1/8²) + (1/10²) + .......= (1/2²)(1 + 1/2² + 1/3² + 1/4² + 1/5² + .......)S = (1/4)(ζ(2) = π²/6)S = π²/96
Therefore, the sum of the series (c) is π²/96.
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34x78 use another method besides the traditional algorithm?
Answer:
2652 is the correct answer
can someone help me? (look at image)
Answer:
A- (1,-4)
B-(0,1)
C-(3,0)
(i think thats correct lol)
Step-by-step explanation: