Acceleration is the change in speed over the time
taken. A hungry cheetah spots a gazelle and decides to
chase it. The cheetah accelerates at 10 m/s² from rest
until it reaches 20 m/s. How long did this take?

Answer:  momentum is determined and conserved.

Answer:

monument is determined

Answer:

m = 350474 [kg]

Explanation:

In order to solve this problem we must remember the definition of kinetic energy, which can be easily calculated by means of the following equation.

\(E_{k}=\frac{1}{2} *m*v^{2} \\\)

where:

Ek = kinetic energy = 9.76*10^9[J]

m = mass [kg]

v = velocity = 236 [m/s]

Now replacing and solving the equation.

9.76*10^9 = 0.5*m*(236)^2

m = 9.76*10^9 / (0.5*236^2)

m = 350474 [kg]

The coefficient of kinetic friction between the box and the floor is 0.87.

The coefficient of kinetic friction between the box and the floor is calculated by applying the formula for net force on the box.

F(net) = ma

where;

at a constant velocity, the acceleration of the box, a = 0

F(net) = 0

The net force is obtained from the applied force and force of friction;

Fcosθ - μmg = 0

where;

μmg  = Fcosθ

μ = Fcosθ / mg

μ = (485 x cos55) / (32.6 x 9.8)

μ = 0.87

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An incandescent bulb produces light that comes from the heating of a filament. A compact fluorescent bulb produces light when a substance is hit by electromagnetic radiation. Compact fluorescent bulbs are more efficient than incandescent bulbs.

The first law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic processes. Therefore, a system with lower heat emissions would be more efficient.

The second law of thermodynamics states that the total entropy of an isolated system (the thermal energy per unit temperature that is unavailable for doing useful work) can never decrease. In our context, it means that the system with the least amount of losses would be more efficient. As a conclusion the fluorescent bulb would be more efficient.

Answer:

0.392

Explanation:

Mm = 0.11Me

Rm = 0.53Re

g = GM / r^2

G = 6.67 * 10^-11

gmars = (G * 0.11Me) / (0.53Re)^2

Recall:

gearth = GMe /Re^2

Hence, gmars in terms of gearth equals

gmars = gearth * (0.11 / 0.53^2)

gmars = gearth * 0.3915984

gmars = 0.392gearth

Answer:

B

Explanation:

Monucles work in different shapes

Answer: the answer would be C trust me i took the test if its not that its b

hope that helps

Explanation: i took the test

answer:

a) lower because the sound-wave fronts reach the platform at a frequency lower than the frequency at which they are produced

explanation :3

If the train is leaving the train station, then the people who are standing on the platform would hear a sound with a lower frequency since the train is moving further away. ^^

Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.

The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.

The force applied is the weight of the bag, which is given by:

F = m * g

where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:

F = 50 kg * 9.81 m/s²

F = 490.5 N

The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:

v = (10 * 30 cm) / 10 s

v = 30 cm/s

The power of the porter is the rate at which work is done, which can be calculated as:

P = W / t

where W is the work done and t is the time taken. Substituting the values, we get:

P = F * d * v / t

P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s

P = 441,450 J/s

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The delivery man exerts a force of approximately 3,012,987 N on the pizza to lift it a height of 3.85 cm.

The work done on the pizza to lift it a level of 3.85 cm can be determined utilizing the equation W = Power*d, where W is the work done, F is the power applied, and d is the distance moved. We are given W = 116 kJ and d = 3.85 cm.

To find the power , we want to switch the distance over completely to meters and the work to joules. 3.85 cm is equivalent to 0.0385 m, and 116 kJ is equivalent to 116,000 J.

Presently we can substitute the qualities in the equation and address for F:

W = Power * d

116,000 J = F0.0385 m

F = 116,000 J/0.0385 m

F = 3,012,987.01 N

Hence, the conveyance man applies a power of roughly 3,012,987 N on the pizza to lift it a level of 3.85 cm.

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The energy that is required by the space probe is 2.94 * 10^14 J.

Let us recall that the gravitational potential energy is the energy that is possessed by a body by virtue of the position of the body in space. We know that the energy that is possessed by the space probe is the gravitational potential energy and we have to obtain the energy required.

Recall that energy required = Work done = mgh

m = mass of the object

g = acceleration due to gravity

h = distance covered

Then;

100-kg * 9.8 m/s^2 *  3 × 10^11 m

= 2.94 * 10^14 J

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Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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Answer: A

Explanation: We know that f=p*n

f=50*300=15000 Hz = 15kHz.

Have a great day! <3

If the number of revolutions is 300 and the paired poles are 50 , then the frequency would be 15 kHz, therefore the correct answer is option A.

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,

F = 1 / T

As given in the problem, we have to calculate frequency if the number of revolutions is 300 and the paired poles are 50.

F = 300 × 50

  = 1500 kHz

Thus, If the number of revolutions is 300 and the paired poles are 50, then the frequency would be 15 kHz, therefore the correct answer is option A.

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Answer:

The distance traveled by the particle after 1 second is 9m.

Explanation:

Given;

velocity of the particle, v = 4 m/s

acceleration of the particle, a = 10 m/s²

time of motion of the particle, t = 1 second

distance traveled by the particle, d = ?

The distance traveled by the particle is given by;

d = vt + ¹/₂at²

d = (4 x 1) + ¹/₂(10)(1)²

d = 9 m

Therefore, the distance traveled by the particle after 1 second is 9m.

Approximate the instantaneous velocity by computing the average velocity of the car over the interval [1.95, 2.05] (i.e. the interval centered at t = 2 s with length 0.1 s).

By definition, average velocity is given by

v = ∆x / ∆t

So we have

v(2 s) ≈ (x(2.05 s) - x(1.95 s)) / (0.1 s) ≈ 13.94 m/s

Answer:

600 J

Explanation:

900 j = 300j = 600 j lost due to friction

Energy lost due to friction is 600 J.

The kinetic energy before and after friction is given as 900J and 300J.

   The force that resists the sliding or rolling over one object with another is called friction. The energy which possess in virtue of being in motion is said to be Kinetic Energy.

                                   f = μN

                      Energy lost = 900J - 300J

                                          =  600J

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Answer:Do not now

Explanation:Beacuse i do not care

Answer:

From the SUN

Explanation:

Hope it helps!!!

Follow me if you want :)

Answer: heat is transferred to and from objects -- such as you and your home -- via three processes: conduction, radiation, and convection.

Explanation:

Hopes this helps!

Answer:

Let's define t = 0s (the initial time) as the moment when Car A starts moving.

Let's find the movement equations of each car.

A:

We know that Car A accelerations with a constant acceleration of 5m/s^2

Then the acceleration equation is:

\(A_a(t) = 5m/s^2\)

To get the velocity, we integrate over time:

\(V_a(t) = (5m/s^2)*t + V_0\)

Where V₀ is the initial velocity of Car A, we know that it starts at rest, so V₀ = 0m/s, the velocity equation is then:

\(V_a(t) = (5m/s^2)*t\)

To get the position equation we integrate again over time:

\(P_a(t) = 0.5*(5m/s^2)*t^2 + P_0\)

Where P₀ is the initial position of the Car A, we can define P₀ = 0m, then the position equation is:

\(P_a(t) = 0.5*(5m/s^2)*t^2\)

Now let's find the equations for car B.

We know that Car B does not accelerate, then it has a constant velocity given by:

\(V_b(t) =20m/s\)

To get the position equation, we can integrate:

\(P_b(t) = (20m/s)*t + P_0\)

This time P₀ is the initial position of Car B, we know that it starts 100m ahead from car A, then P₀ = 100m, the position equation is:

\(P_b(t) = (20m/s)*t + 100m\)

Now we can answer this:

1) The two cars will meet when their position equations are equal, so we must have:

\(P_a(t) = P_b(t)\)

We can solve this for t.

\(0.5*(5m/s^2)*t^2 = (20m/s)*t + 100m\\(2.5 m/s^2)*t^2 - (20m/s)*t - 100m = 0\)

This is a quadratic equation, the solutions are given by the Bhaskara's formula:

\(t = \frac{-(-20m/s) \pm \sqrt{(-20m/s)^2 - 4*(2.5m/s^2)*(-100m)} }{2*2.5m/s^2} = \frac{20m/s \pm 37.42 m/s}{5m/s^2}\)

We only care for the positive solution, which is:

\(t = \frac{20m/s + 37.42 m/s}{5m/s^2} = 11.48 s\)

Car A reaches Car B after 11.48 seconds.

2) How far does car A travel before the two cars meet?

Here we only need to evaluate the position equation for Car A in t = 11.48s:

\(P_a(11.48s) = 0.5*(5m/s^2)*(11.48s)^2 = 329.48 m\)

3) What is the velocity of car B when the two cars meet?

Car B is not accelerating, so its velocity does not change, then the velocity of Car B when the two cars meet is 20m/s

4)  What is the velocity of car A when the two cars meet?

Here we need to evaluate the velocity equation for Car A at t = 11.48s

\(V_a(t) = (5m/s^2)*11.48s = 57.4 m/s\)

Answer:

c

Explanation:

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

With the use of below formula, at 879 °C,  velocity will be double the velocity at 15 °C.

The velocity of sound waves in air is proportional to the square root of Thermodynamic temperature. That is, V = K\(\sqrt{T}\)

Given that the temperature at which the velocity of sound in air is twice its velocity at 15°C, Let us make use of the formula;

(v2/v1) = √(T2 / T1)

Where

Recall that absolute temperature = °C + 273.

If v2 = 2 × v1 and temperature in degree Celsius = 15°C, then,

Temperature in Kelvin K = 15 + 273 = 288

Substitute all the parameters into the formula

(2 × v1)/v1 = √(T2/288)

2 = √ (T2 /288)

Square both sides

4 = (T2/288)

T2 = 4 × 288

T2 = 1152K

Temperature in degrees Celsius = 1152 - 273 = 879 °C.

Therefore, at 879 °C,  velocity will be double the velocity at 15 °C.

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Answer:

0.5 mA,  step-up transformer

Explanation:

Power is constant

V * I = constant

500 V * 10 mA = 10,000 V * I

so I = 0.5 mA

From 500 V increases to 10,000 V, so it is a step-up transformer

Here, we are required to determine which element has atoms with Valence electrons in a higher energy level than those of calcium.

The Valence electrons of the Caesium, Cs atoms has higher energy level than those of Calcium.

First, we need to determine the electronic configuration of each of the elements

Among the elements in the option, the Valence electrons of the Caesium, Cs atoms has higher energy level than those of Calcium.

This is so because the only Valence electron of Cs is located in the 6s orbital and as such has the highest energy level amongst all of the elements.

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Answer:

(Question 1) 5

(Question 2) They have valence electrons in the same energy level

(Question 3) Helium atoms have 2 valence electrons, while atoms of the other elements in the group all have 8 valence electrons

(Question 4) cesium (Cs)

(Question 5) There are two electrons in the first energy level and seven electrons in the second energy level

Explanation:

just finished the quick check, enjoy UwU

Answer:

Hi there!

Your answer is:

A. Linear

Explanation:

Linear measurement is when you measure things in a straight line using tools such as a ruler, yardstick or tape measure. To measure height, they are using a ruler, which is a form of linear measurement!

I hope this helps!