A
stone moving on a circle with a radius of 60 cm has a centripetal
acceleration whose module is worth 90 m/s2. How long does it take
him to do 8 laps?

Refraction results from differences in light's speed. The correct answer is C) speed.

Refraction is the term for the bending of light as it passes through transparent materials (it also occurs with sound, water, and other waves). We are able to create lenses, magnifying glasses, prisms, and rainbows because to this bending caused by refraction.

Refraction occurs when light passes through different mediums and changes its speed. This change in speed causes the light to bend, creating the effect of refraction.

This is why objects appear to be in different positions when viewed through water or a lens. The frequency and incident angles of the light do not affect refraction, only the speed of the light does.

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Various examples of drag, elastic and tension forces are mentioned.

Elastic force is a type of force that occurs when an object is stretched or compressed, and it resists the deformation of the object. This force is proportional to the amount of stretching or compression, and it causes the object to return to its original shape when the force is removed.

Tension force is a type of force that is transmitted through a string, rope, wire or cable when it is pulled tight by forces acting at either end. This force acts to transmit the tension through the length of the string, keeping it taut and preventing it from breaking.

A person biking into a headwind experiences air resistance, which is a type of drag force.

A stretched rubber band or a compressed spring both exhibit elastic force.

A person pulling a wagon by a rope exerts a tension force on the rope. Another example of tension force can be observed when a weight is hung from a rope or chain, creating tension within the rope or chain.

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The momentum of Bobby having a mass of 50 kg is 235 kgm/s.

Momentum can be defined as the product of mass and velocity of a body.

To calculate the momentum of the of Bobby, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the momentum of Bobby is 235 kgm/s.

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When comparing and contrasting how sound is heard by a person observing a moving car versus a person moving with the car, the primary difference lies in the Doppler effect, this occurs when the source of sound is moving relative to the observer and the sound intensity.

For the person observing the moving car, the pitch of the sound will change due to the car's motion. As the car approaches the observer, the sound waves compress, resulting in a higher pitch. Conversely, as the car moves away, the sound waves expand, leading to a lower pitch. In contrast, for the person moving with the car, the sound remains constant because the relative motion between the sound source and the observer is the same, this individual will not experience the Doppler effect and will hear the car's sound at its original pitch.

Furthermore, the observer at rest may experience varying sound intensity due to the car's changing distance. On the other hand, the person moving with the car will have a relatively consistent sound intensity, as their distance from the sound source remains constant. Overall, the Doppler effect and sound intensity are the key factors that differentiate the auditory experience between these two scenarios.

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Answer:

The mechanical advantage (M.A) of a real machine is always less than its velocity ratio(V.R) because mechanical advantage decreases due to the friction and weight of moving parts of the machine whereas the velocity ratio remains constant.

The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.

The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.

Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.

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Answer:

A unit of pressure equal to the air pressure at sea levels is called 1atm. • 1atm = 760mmHg at 0°Celsius under the standard gravitational force or you can say standard gravity. • 1atm is also equal to 14.7 pounds per sq. Inch ( 1.01325 × 105 pascals )

Explanation:

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Answer:

A mole of carbon-12 atoms has 6.022 x 1023 carbon-12 atoms. A mole of apples has 6.022 x 1023 apples.

Explanation:

When a rock is transported from the moon to the earth, both mass and weight are changed.

Explanation:

The reason why both mass and weight are changed when a rock is transported from the moon to the earth is that the gravitational field on the surface of the earth is stronger than that on the surface of the moon.

This means that the rock's mass, which is the measure of the amount of matter that an object contains, will remain the same.

However, the rock's weight, which is the force with which an object is attracted to the earth due to gravity, will be different since the gravitational pull on the moon is much weaker than that on the earth. This implies that when the rock is transported from the moon to the earth, it will experience a higher gravitational force which will cause it to weigh more compared to when it was on the moon.

Therefore, both mass and weight will change when a rock is transported from the moon to the earth.

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Answer:

Revolutions made before attaining angular velocity of 30 rad/s:

θ = 3.92 revolutions

Explanation:

Given that:

L(final) = 10.7 kgm²/s

L(initial) = 0

time = 8s

Torque is the rate of change of angular momentum:

\(T = \frac{L(final)-L(initial)}{t}\\T = \frac{10.7-0}{8}\\T=1.34 Nm\)

We know that

T = Iα

α = T/I

where I = moment of inertia = 2.2kgm²

α = 1.34/2.2

α = 0.61 rad/s²

We know that angular equation of motion is:

ω²(final) = ω²(initial) +2αθ

(30 rad/s)² = 0 + 2(0.61 rad/s²)θ

θ = (30 rad/s)²/ 2(0.61 rad/s²)

θ = 24.6 radians

Convert it into revolutions:

θ = 24.6/ 2π

θ = 3.92 revolutions

Answer:

So 960m in 2min

Explanation:

10-2=8

so 8m/s

8m/s times 60=480 times two because it is two so 960

Answer:

If the basket ball appears orange then it can be said that it reflects orange light

Explanation:

The color of the object reflected by an object is the color which is viewed by a viewer. Hence, if the basket ball reflects the orange color light , then the ball will appear orange in color to the viewer.

The light absorbed by the object has no role in deciding the color of the object visible to a viewer.

hence, if the basket ball appears orange then it can be said that it reflects orange light.

Answer:he's not applying force or motion

Explanation:

p=f & m

Answer:

1.Tackle

2.helmet

3.touchdown

4.quarterback

5.interference

6.touchback

7.safety

8.cornerback

9.handoff

10.lateral

11. reciever

12.completion

13.interception

14.center

15.referee

16.huddle

17.overtime

18. facemask

19.pigskin

20.penalty

Explanation:

The correct words are "Tackle, Theme, Touchdown, Quarterback, Interference, Touchdown, Safety, Cornerback, Offhand, Aerial, Receiver, Completion, Receptionist, Center, Referee Huddle, Overtime, Safesmack, Kicking, and  Penalty."

A football word scramble is a game where a series of letters are provided in a scrambled order, and the goal is to rearrange those letters to form words related to football. Players need to unscramble the letters to identify the correct football-related terms, such as positions, equipment, or actions in the game. It is a fun and engaging activity that challenges players' knowledge and word-solving skills while connecting to the theme of football.

1. Tackle

2. Theme

3. Touchdown

4. Quarterback

5. Interference

6. Touchdown

7. Safety

8. Cornerback

9. Offhand

10. Aerial

11. Receiver

12. Completion

13. Receptionist

14. Center

15. Referee

16. Huddle

17. Overtime

18. Safesmack

19. Kicking

20. Penalty

Therefore, The correct answers are "Tackle, Theme, Touchdown, Quarterback, Interference, Touchdown, Safety, Cornerback, Offhand, Aerial, Receiver, Completion, Receptionist, Center, Referee, Huddle, Overtime, Safesmack, Kicking, and  Penalty."

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Answer:

The change in the linear momentum is 225 kg.m/s and the force exerted on the tennis ball is 22,500 N.

Explanation:

Linear momentum is the measure of a body's motion. Every object that has mass and moves at any velocity has linear momentum. Here are some examples of everyday life: falling balls, launching rockets, driving a car etc.

Now let's attack the problem.

First, we got to write the data down:

\(\bullet \quad m=3\,kg\\\\\bullet \quad v_o=40\,m/s\\\\\bullet \quad v=35\,m/s\\\\\bullet \quad \Delta t =0.01\,s\)

We can write the change in linear momentum of the tennis ball as follows:

\(\Delta p = p-p_o\)

The ball's momentum is equal to its mass times its velocity. Hence:

\(\Delta p= m\cdot v-m\cdot v_o\)

Let's set the reference system as positive to left (see picture attached). For that purpose, when the ball bounces back its velocity changes sign.

Now, we are able to plug in the data:

\(\Delta p = 3\cdot 35 - 3\cdot(-40)\\\\\\\Delta p = 105+120\\\\\\\therefore \boxed{\Delta p =225\,kg\cdot m/s}\)

To calculate the exerted force, we must apply the impulse theorem, which states that impulse equals the change in linear momentum of an object. We get:

\(\mathbb{I}=\Delta p\)

Hence,

\(F \cdot \Delta t=\Delta p\\\\\\F\cdot 0.01=225\\\\\\F=\dfrac{225}{0.01}\\\\\\\therefore \boxed{F=22,\!500\,N}\)

Conclusion: the change in linear momentum is 225 kg . m/s and the exerted force is 22,500 N.

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Answer:

Mid-ocean ridges around the globe are linked by plate tectonic boundaries and the trace of the ridges across the ocean floor appears similar to the seam of a baseball.

Explanation:

Answer:

1.2 A

Explanation:

From the diagram attached, The three resistors are parallel because the each ends of the resistors are connected together. Since they are in parallel, the voltage across each resistor is the same. The voltage source connected in parallel to the resistors is 60 V. Therefore the voltage across the 50 Ω resistor is 60 V. Using ohm law:

Voltage (V) = Current (I) × Resistance (R)

V = IR

I = V/R

I = 60 V/ 50 Ω

I = 1.2 A

The current in the 50 Ω resistor is 1.2 A

After slowing down by 15 miles per hour and reducing the speed by one third, you are now going at 60 miles per hour.

If you are initially driving at a rate of one and a half miles per minute, it means you are traveling at a speed of 90 miles per hour (since there are 60 minutes in an hour).

In the second step, you slow down by 15 miles per hour. This reduces your speed to 75 miles per hour.

Finally, you reduce your speed by one third, which means you need to subtract one third of 75 from 75. One third of 75 is 25, so subtracting 25 from 75 gives you a speed of 50 miles per hour.

Therefore, after slowing down by 15 miles per hour and then reducing your speed by one third, you are now traveling at a speed of 50 miles per hour.

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Answer:

A,B,D,E,F

Explanation:

i took the test

Answer: A, B, D, and F all fit the description of professionals in the

Architecture and Construction career cluster

Explanation: Hope this helps!

The work done by the man in pushing the crate up the ramp at a constant speed is approximately 2223.32 Joules.

The work done by the man, we can use the formula:

Work = Force × Distance × cos(theta)

Given:

Mass of the man (m) = 95 kg

Distance (d) = 4.5 m

Angle of the ramp (theta) = 17°

Force (F) = 520 N

First, let's calculate the component of the force parallel to the ramp:

Force parallel to the ramp = Force × cos(theta)

Force parallel to the ramp = 520 N × cos(17°)

Now, let's calculate the work done:

Work = Force parallel to the ramp × Distance

Work = (520 N × cos(17°)) × 4.5 m

Calculating the numerical value:

Work ≈ (520 N × 0.9537) × 4.5 m

Work ≈ 2223.32 J

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The Moon and Sun, along with all other celestial objects, appear to travel across the sky from east to west as the Earth spins on its axis from west to east.

The Moon, however, orbits Earth in the same direction as our planet rotates when seen from above. So the Moon does move through our sky from west to east, albeit so slowly that we hardly ever observe it.

But during a total solar eclipse, we can observe the Moon's actual motion as it moves from west to east across the face of the Sun.

The Moon's shadow follows it as it moves in the same direction and creates a path across the surface of the Earth. Because it is tidally locked to our planet, the Moon always seems the same to us from here on Earth.

Therefore, The Moon and Sun, along with all other celestial objects, appear to travel across the sky from east to west as the Earth spins on its axis from west to east.

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The thymocyte developmental checkpoint that tests the functionality of the recombined beta chain of the pre-T cell receptor (pre-TCR) is called Beta selection.

During T cell development in the thymus, thymocytes undergo several checkpoints to ensure proper maturation and functionality. Beta selection is one such checkpoint that occurs at the double-negative stage of thymocyte development. At this stage, the recombined beta chain of the pre-TCR is tested for its functionality.

The pre-TCR, composed of the beta chain and a surrogate alpha chain, plays a crucial role in thymocyte development and selection. Beta selection specifically assesses the ability of the recombined beta chain to pair with the surrogate alpha chain and form a functional pre-TCR complex.

If the recombined beta chain is functional and capable of pairing with the surrogate alpha chain, signaling through the pre-TCR occurs, leading to positive selection. Positive selection allows thymocytes with functional pre-TCRs to survive and progress further in development.

On the other hand, if the recombined beta chain is non-functional or unable to properly pair with the surrogate alpha chain, signaling through the pre-TCR does not occur, resulting in negative selection. Thymocytes that fail the beta selection checkpoint are eliminated through apoptosis.

In summary, the beta selection checkpoint in thymocyte development is responsible for testing the functionality of the recombined beta chain of the pre-TCR. It determines whether thymocytes progress through positive selection or undergo negative selection based on the ability of the recombined beta chain to form a functional pre-TCR complex.

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Answer:

1200

Explanation:

The relationship between the mass of a rotating object and its velocity is that the greater the mass, the greater the inertia, and the greater the inertia, the slower the velocity. To further explain, Inertia is the resistance an object has to changing its state of motion. Therefore, the greater the mass of a rotating object, the greater its inertia, and the slower its velocity will be.

The relationship between the mass of a rotating object and its velocity is described by the equation Iω = mvr, where I is the moment of inertia, ω is the angular velocity, m is the mass, v is the tangential velocity, and r is the radius of the rotating object.

This equation shows that the mass of a rotating object is directly proportional to its velocity. This means that as the mass of a rotating object increases, its velocity also increases. Conversely, as the mass of a rotating object decreases, its velocity decreases.

In addition, the equation also shows that the moment of inertia and the radius of the rotating object are also important factors in determining the relationship between the mass and velocity of a rotating object. The moment of inertia is a measure of an object's resistance to rotational motion, and the radius is the distance from the center of rotation to the point at which the mass is located.

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The answer is yes

They are isotopes.

Answer:

Hey Friend....

Explanation:

This is ur answer....

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When a weightless spring scale is attached to two equal weights, the reading on the scale will be zero. This is because the weights on both sides are balanced, resulting in no net force acting on the scale.

The reason for this is Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, when one weight exerts a downward force on the spring scale, the other weight exerts an upward force of the same magnitude on the scale.

These opposing forces cancel each other out, resulting in a net force of zero. As a result, the spring scale does not experience any deformation and the reading remains at zero.

It is important to note that this only applies when the two weights are equal. If the weights were different, there would be an imbalance in the forces, causing the spring scale to register a non-zero reading.

In summary, when a weightless spring scale is attached to two equal weights, the reading on the scale will be zero due to the balanced forces acting on it.

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