A
Determine if the following two structures are
identical, isomers, or unrelated?
CH3
CH3-
identical
B
isomers
C
unrelated

From the calculation, there are 1.5 g of water produced in the reaction.

An equation shows the chemical transformation that takes place in a reaction vessel. In this case, the equation is; C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O.

Now;

Number of moles of glucose = 2.5g/180 g/mol = 0.014 moles

Since 1 mole of glucose produces 6 moles of water

0.014 moles of glucose produces 0.014 moles * 6 moles/ 1 mole

= 0.084 moles

Mass of water produced = 0.084 moles * 18 g/mol = 1.5 g of water

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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A balanced chemical equation for the standard formation reaction of liquid chloroform is :

CH₄   +   3Cl₂   ----->   CHCl₃   +     3HCl

The methane combine with chlorine form the trichloro methane or the chloroform.

CH₄   +   Cl₂   ----->   CHCl₃   +     HCl

to balance the equation , the number of atoms in the product side is equal to the reactant side :

               reactant            product

C                     1                      1

H                     4                      2

Cl                     2                     4

to balance the equation miltiply 3 in Cl₂ and 3 in HCl, we get :

CH₄   +   3Cl₂   ----->   CHCl₃   +     3HCl

now the number of atoms in the product side is equal to the reactant side .

Thus, A balanced chemical equation for the standard formation reaction of liquid chloroform is :

CH₄   +   3Cl₂   ----->   CHCl₃   +     3HCl

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Answer:

The answer is true.

Explanation:

The deeper you go the more water there's on top of you pushing down.

Answer:

True

Explanation:

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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ANSWER

The volume of the gas in liters is 2.016 Liters

STEP-BY-STEP EXPLANATION:

Given parameters

The mole of the given gas = 0.090 mole

Recall that, 22.4L is equivalent to 1 mole at S.T.P

Let x be the volume of the gas in Liters

Therefore, the volume of the gas in liters is 2.016 Liters

31.7 g of water formation in the given reaction releases 783.02 kJ of heat energy.

The change in heat in the given equation is -890.8 kJ/mol. This means that when one mole of CH4 reacts with 2 moles of O2, it produces one mole of CO2 and 2 moles of H2O while releasing 890.8 kJ of heat energy.Now, we have to find out how much heat energy will be released when 31.7 g of water is formed. To do this, we need to first calculate the number of moles of water formed from 31.7 g of H2O.Molar mass of H2O = 2 × 1.008 + 15.999 = 18.015 g/molNumber of moles of H2O = 31.7 g / 18.015 g/mol = 1.759 molNow we know that 2 moles of H2O are formed when 1 mole of CH4 reacts. Therefore, the number of moles of CH4 required to produce 1.759 mol of H2O will be:1 mole of CH4 : 2 moles of H2Ox moles of CH4 : 1.759 moles of H2Ox = 1.759/2 = 0.8795 molSo, 0.8795 moles of CH4 are required to produce 1.759 moles of H2O. And the heat released during the reaction of 0.8795 mol CH4 can be calculated using the given change in heat.ΔH = -890.8 kJ/molHeat released during the reaction of 0.8795 mol CH4= ΔH × number of moles= -890.8 kJ/mol × 0.8795 mol= -783.02 kJ.

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Answer:

+2.

Explanation:

Hello,

In this case, since chromium has six valence electrons in its outer shell, when it loses four electrons it remains with two of them, therefore it charge as chromium ion is +2, so it is written as Cr⁺² and named as chormium (II) or hypochromous ion.

Best regards.

a.  1.505 x 10²⁴

b.  4.37 x 10²⁴

c.  2.34 x 10²⁴

d.  8.127 x 10²³

Given

Number of moles of elements

Required

The number of particles

Solution

1 mol = 6.02 x 10²³ particles(molecules, ions, atoms)

Can be formulated :

N = n x No

No = Avogadro's number

n = mol

a. 2.5 mo Ca x 6.02 x 10²³ = 1.505 x 10²⁴

b. 7.26 mol Al x 6.02 x 10²³ = 4.37 x 10²⁴

c. 3.89 mol S x 6.02 x 10²³ = 2.34 x 10²⁴

d. 1.35 mol Pb x 6.02 x 10²³ = 8.127 x 10²³

Answer:

B) Germanium atoms have more electrons than titanium atoms

Explanation:

Trust me I did this but for those who are hesitant

---> Conductors : It is a type of substance which conduct electricity that means it allow the electrons to flow through them.

Example of conductors are, iron, aluminium, gold, etc.

Insulators : It is a type of substance which does not conduct electricity that means it does not allow the electrons to flow through them.

Examples of insulators are, glass, rubber, ceramics, etc.

Semiconductors : It is a type of substance which conduct electricity under certain conditions that means it allow the electrons to flow through them. The conductivity level of semiconductors lie between the conductors and the insulators.

The good examples of semiconductors are silicon, germanium, gallium, and  selenium.

In the given options, aluminium, gold are the metals which conduct electricity and concrete is an insulator which do not conduct electricity while the germanium is the good semiconductor.

Answer:

If n = 4, then the possible values of 1 and m depend on the equation or expression being used. Without more information, it is impossible to determine what the possible values of 1 and m might be. Can you please provide more context or information about the problem you are trying to solve?

The periodic table of elements has vertical groups that tell you the number of electrons and horizontal periods that tell you the number of valance shells. The chemical elements are arranged in the periodic table according to their atomic numbers, starting with hydrogen, which has the lowest atomic number, and moving up to uranium, which has the greatest atomic number.

Due to their comparable chemical behavior, the periodic table's vertical columns are referred to as groups or families. The number of valence electrons and chemical characteristics is the same for all members of a family of elements. Periods refer to the horizontal rows on the periodic table.

The contemporary periodic table has 18 vertical columns and 7 horizontal periods.

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Answer

CuSO₄ (aq) + Na₂CO₃ (aq) → CuCO₃ (s) + Na₂SO₄ (aq)

The reaction will occur.

Explanation

The given incomplete equation is: CuSO₄ + Na₂CO₃

The reaction will occur because Na will displace Cu from its salt because Na is more electropositive and higher in the activity series.

The complete equation for the reaction is:

CuSO₄ (aq) + Na₂CO₃ (aq) → CuCO₃ (s) + Na₂SO₄ (aq)

The reaction is a double replacement reaction.

The order of reaction is defined as the power to which the concentration of the reactants are raised in the rate equation of the reaction.

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These are 10 unique questions you can ask your fellow classmates about the things they have learned in your special ed classroom:

A special education classroom is a classroom designed to meet the needs of students with disabilities. These classrooms are staffed by specially trained teachers who are able to provide individualized instruction and support to students with a variety of disabilities.

These questions are designed to get your classmates thinking about the things they have learned in your special ed classroom and how those things have impacted them. The answers to these questions can be used to create a powerful and informative ad for your classroom.

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As per the given statement 0.297mol NO can be made when 75 moles of HNO3 are consumed

The inorganic substance with the formula HNO3 is nitric acid. It is a mineral acid that is quite corrosive. The substance is colourless, but older samples have a tendency to have a yellow cast because of breakdown into nitrogen oxides..

'3 Cu + 8HNO3      3 Cu(NO3)2 + 2 NO + 4H₂O

Element  Molar Mass

Hydrogen 1

Nitrogen 14

Copper 63.5

Oxygen 16

Referring  the above table we get  no of moles in HNO3

1(1.0) + 1(14) + 3(16) = 1 + 14 + 48 = 63 g/mol

75g HNO3 x 1 mol HNO3/63 g HNO3 = 1.190 mol HNO3

The coefficient of HNO3 is 8, and NO is 2

1.190 mol HNO3 x 2 mol NO/8 mol HNO3 = 0.297mol NO

Hence, 0.297mol NO can be made when 75 moles of HNO3 are consumed.

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Answer:

584.2 g

Explanation:

Hello there!

In this case, since we know the 20% of the atoms correspond to sodium, we can compute the total atoms as shown below:

\(\frac{1.204 x10^{24}}{0.2}=6.02x10^{24}atoms\)

Which are also equal to 1 mol and the Avogadro's number of sodium chloride with a molar mass of 58.44 g/mol; thus, the grams of salt turn out to be:

\(6.02x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{58.44g}{1mol}\\\\=584.2g\)

Best regards!

Este problema indica el volumen deseado de una solución (250 cm³) cuya concentration es de 5 g/L y pregunta la cantidad de sal que se debe disolver.

De este modo, dado que el volumen y la concentración están en distintas unidades, debemos convertir una de ellas a la de la otra, en este caso los cm³ a L como se muestra a continuación:

\(250cm^3*\frac{1L}{1000cm^3}= 0.250L\)

Seguidamente, multiplicamos el volumen previamente obtenido por la concentración con el fin the encontrar los gramos de sal:

\(0.250L*5\frac{g}{L} \\\\=1.25 g\)

Así, esto indica que se deben disolver 1.25 gramos de sal para este requerimiento.

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The energy in joules of one mole of photons of visible light having a wavelength of 4.11×10^2 nm? can be expressed as 2.9*10^5 J

From the question we were told to find the energy and the parameters that is needed to calculate these are;

c=3*10^8

h= 6.626 * 10^-34 J.s

1 mol photons = 6.023x10^23 photon

λ = 4.11×10^2 nm  = 4.11 × 10-7 meters

The parameters can be input  as Energy of one mole photon (E) = ( 6.023x10^23 * 6.626 * 10^-34 * 3*10^8)/ (4.11 × 10^-7)

=291302

=2.9*10^5 J

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The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is

A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.

15.0 °C = 288 K

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L

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Taking into account the definition of pH and pOH, the concentration of hydrogen ions and hydroxide ions is 7.94×10⁻¹³ M and 0.0126 M respectively.

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

Being pH= 12.1, the [H₃O⁺] is calculated as:

12.1= - log [H₃O⁺]

Solving:

[H₃O⁺]= 10⁻¹² ¹

[H₃O⁺]= 7.94×10⁻¹³ M

The concentration [H₃O⁺] is 7.94×10⁻¹³ M

Being pH= 12.1, pOH is calculated as:

pOH + 12.1= 14

pOH= 14 - 12.1

pOH= 1.9

Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

- log [OH⁻]= 1.9

Solving

[OH⁻]= 10⁻¹ ⁹

[OH⁻]= 0.0126 M

In summary, the [OH⁻] is 0.0126 M.

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The non-metal elements in Group 7 – known as the halogens – get less reactive as you go down the group

Answer & Explanation:

The reactivity of elements in Group VII, also known as Group 17, decreases with increasing atomic radius. This is because halogens have high electronegativities and a proclivity to gain electrons in noble gas configurations. Myths are traditional stories or beliefs that explain cultural or societal beliefs, customs, or natural phenomena. They can be passed down through generations and can be based on true or fictitious events. Mythology, on the other hand, is the collection of myths associated with a specific culture or religion. Mythology can be amplified through retelling, incorporation into religious practices; association with significant events or figures, and adaptation into other media forms such as literature, film, or art.

Answer:  2.73 g PbSO4

Explanation:

1) solvefor moles Pb(no3)2

0.10 M X 0.09 L =0.009 moles Pb(NO3)2

2) stoichiometry from balanced chemical equation

___Pb(NO3)2 + ___H2SO4--->   PbSO4 +  ___2 HNO3

0.009 moles Pb(NO3)2 X (1 mole PbSO4 / 1 mole Pb(NO3)2) X (303.2516 g PBSO4/ 1mole PbSO4) = 2.73 g PbSO4

Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

Fossil fuels are essential part of the power generation in the world. They are easily combustible and more reliable and cheaper. However, the burning of fossil fuels releases toxic gases  to the environment.

Fossil fuels are fuel generated from the decomposition materials. Petroleum, coal, natural gas  etc. are fossil fuels which are excavating from the earth.

Fossil fuels are non-renewable sources of energy. Hence, as the existing fossil sources are exhausted no more fossil fuel can be made. It is cheaper, reliable and easy to use.

However, the toxic hydrocarbon gases released from the burning of fossil fuels make the environment polluted. Therefore, overuse of fossil fuel definitely rise the atmospheric pollution.

Its use over the next 50 years, will increase the global warming and more of it will be exhausted.

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