Abba grew 1 foot over the past year. He is now 5 feet tall. Part B: Use your model in Part A to write and solve a proportion to find the percent increase in Abba's height.

Answer:

C. \(3\)

Step-by-step explanation:

\(y=-2x^2 + 8x-5 \\ \\ =-2(x^2 -4x)-5 \\ \\ =-2(x^2-4x+4-4)-5 \\ \\ =-2((x-2)^2 -4)-5 \\ \\ =-2(x-2)^2 +8-5 \\ \\ =-2(x-2)^2 + 3\)

9514 1404 393

Answer:

  100

Step-by-step explanation:

The $10 difference in base cost will pay for $10.00/$0.10 = 100 text messages.

Answer:

Please post the full question.

Step-by-step explanation:

I am trying to help, but the question is missing some key info.

Please dont delete, as when he posts the full thing, I will reply to this answer with the answer and explanation.

Answer:

each teammate contributed 1.43 sorry but i do not know how many members they have because my head hurts

The probability that the student receives a grade above C is 0.75

The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible

Probability = number of desirable outcomes / total number of possible outcomes

The value of probability lies between 0 and 1

Given data ,

Let the probability that the student receives a grade above C be P ( C )

And , the equation will be

Let the probability you will get an A in this class is P ( A ) = 0.25

Let the probability you will get a B in this class is P ( B ) = 0.50

Now , the events P ( A ) and P ( B ) are mutually exclusive events

So , P ( A ∩ B ) = 0

And , P ( A ∪ B ) = P ( A ) + P ( B ) - P ( A ∩ B )

On simplifying the equation , we get

P ( A ∪ B ) = P ( C )

And , probability that the student receives a grade above C = P ( A ) + P ( B )

The probability that the student receives a grade above C = 0.25 + 0.50

The probability that the student receives a grade above C = 0.75

Hence , the probability is 0.75

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The recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.

Using the provided data on the highest discharge per year on the Bow River at Calgary, Canada, we can calculate the recurrence interval (R) for specific flood magnitudes and determine the probability of such floods occurring in the future. Additionally, we can examine the 100-year trend for floods on the Bow River, excluding major floods, to identify the general trend of peak discharges over time.

1) Calculating the Recurrence Interval for the Second Largest Flood (1,520 m3/s in 1932):

To calculate the recurrence interval (R) for the second largest flood, we need to determine the rank of that flood. Since there are 95 data points in total, the rank of the second largest flood would be 94 (as the largest flood, in 2013, is excluded). Applying the formula R = (n + 1) / r, we have:

R = (95 + 1) / 94 = 1.0106 years

Therefore, the recurrence interval for the second largest flood (1,520 m3/s in 1932) is approximately 1.0106 years.

2) Probability of a Flood of 1,520 m3/s Occurring Next Year:

The probability of a flood of 1,520 m3/s happening next year can be calculated by taking the reciprocal of the recurrence interval for that flood. Using the previously calculated recurrence interval of 1.0106 years, we can determine the probability:

Probability = 1 / R = 1 / 1.0106 = 0.9895 or 98.95%

Thus, the probability of a flood of 1,520 m3/s occurring next year is approximately 98.95%.

3) Examination of the 100-Year Trend for Floods on the Bow River:

To analyze the 100-year trend for floods on the Bow River while excluding major floods, we focus on the peak discharges over time. Without considering the labeled major floods, we can observe the general trend of peak discharges.

Unfortunately, without specific data on the peak discharges for each year, we cannot provide a detailed analysis of the 100-year trend. However, by excluding major floods, it is likely that the general trend of peak discharges over time would show fluctuations and variations but with a relatively stable pattern. This implies that while individual flood events may vary, there might be an underlying consistency in terms of typical peak discharges over the 100-year period.

In summary, the recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.

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Answer:

The answer is "(1, -12)"

Step-by-step explanation:

In the given question some information is missing, that is the attachment of the graph, which can be attached as follows:

In the attached figure file, the quadrilateral ABCD vertices are (-3, 4), (3,4),(1,-2), and (-5,-2)

To find the coordinates of the D' the translation of (x, y) = (x + 6, y-10)

where point D=(-5, -2),

\(\to x=x+6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=y-10\\\\\to x=-5+6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=-2-10 \\\\\to x=1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=-12\)

So, the coordinates of D' is (1,-12).

Answer:

Area: T = 18

a.  The triangle area using Heron's formula: T=  sqrt(s(s−a)(s−b)(s−c) )

​b. 2\(\sqrt{10}\)  

c. h = 5.69

d. T = 18

Step-by-step explanation:

a. T=  sqrt(s(s−a)(s−b)(s−c) )

T=sqrt( 11.16(11.16−10)(11.16−6)(11.16−6.32) )

​T=  sqrt(324 )

​T =18

b. We compute the base from coordinates using the Pythagorean theorem

c=  sqrt( ((−2−4)^2)+ ((1−3) ^2) )

c= sqrt(40) = 2sqrt(10)

c. Calculate the heights of the triangle from its area

​  

correct answer is option C, i.e. vertical shrink by a factor of 1/6.

Given:

Two graphs are given, one is of f(x) = x^4 and other is of b(x)=6x^4.

Find:

we have to find the correct option.

Explanation:

when we transformed the graph

The height of the building is 71 meters.

We can solve this problem using the similar triangles. The height of the building can be determined by setting up the following proportion:

(the height of pole) / (length of pole's shadow) = (height of building) / (length of building's shadow)

Substituting the given values:

2.8 / 1.49 = (height of building) / 37.5

To find the height of the building, we can cross-multiply and solve for it:

(2.8 * 37.5) / 1.49 = height of building

Calculating the expression on the right side:

(2.8 * 37.5) / 1.49 ≈ 70.7013

Rounding to the nearest meter, the height of the building is approximately 71 meters.

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Answer:

11.-1x

Step-by-step explanation:

then continue like that

Answer:

-1

Step-by-step explanation:

just multiply

Using a graphing calculator, we obtain the following regression model.

Thus, the regression model is:

For part b, find the value of x by subtracting 2025 by 2010. Thus, the value of t is 15. Substitute 15 for t in the obtained equation in part a and then solve for P(t).

Thus, there is approximately 41.4 million people on 2025.

For part c, substitute 40 for P(t) in the obtained equation in part a and then solve for t.

Add the obtained value of t to 2010. Thus, the population will reach 40 million in 2020.

The maximum number of intersection points of a parabola and ellipse is 4.

A parabola and an ellipse can have a maximum 4 number of intersections.

A regular oval form produced when a cone is cut by an oblique plane that does not intersect the base, or when a point moves in a plane so that the sum of its distances from two other points remains constant.

In another word, an ellipse is a curve that becomes by a point moving in such a way that the sum of its distances from two fixed points is a closed planar curve produced.

We can make an ellipse and a parabola such that there is a maximum of four points of intersection as shown in the image.

It can be possible if the major axis is very large as compared to the minor axis.

Hence "A parabola and an ellipse can have a maximum 4 number of intersections".

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Answer:

Solution : Graph 4

Step-by-step explanation:

Let's break down this function,

{ y = 5 if x ≤ - 2, y = 0 if x = 3, y = - 1 if x > 3 }

As you can see, graph 4 is the only one that represents this.

• When y = 5, x  ≤ - 2. This is represented by a ray with a colored hole, indicating that x = - 2. At the same time this ray extends infinitely in the negative direction, indicating that x < - 2.

• When y = 0, x = 3. This is represented as the point ( 3, 0 ).

• And when y = - 1, x > 3. At y = - 1 another respective ray, that has a non - filled hole, indicates that x ≠ 3. The ray extends infinitely in the positive direction, meeting the criteria that x > 3.

Using the fundamental theorem of calculus, part 2, we have evaluated the integral ∫1−1(t3−t2)dt to be -1/6.

To use the fundamental theorem of calculus, part 2 to evaluate the integral ∫1−1(t3−t2)dt, we first need to find the antiderivative of the integrand. To do this, we can apply the power rule of calculus, which states that the antiderivative of x^n is (x^(n+1))/(n+1) + C, where C is the constant of integration. Using this rule, we can find the antiderivative of t^3 - t^2 as follows:
∫(t^3 - t^2)dt = ∫t^3 dt - ∫t^2 dt
= (t^4/4) - (t^3/3) + C
Now that we have found the antiderivative, we can use the fundamental theorem of calculus, part 2, which states that if F(x) is an antiderivative of f(x), then ∫a^b f(x)dx = F(b) - F(a). Applying this theorem to the integral ∫1−1(t3−t2)dt, we get:
∫1−1(t3−t2)dt = (1^4/4) - (1^3/3) - ((-1)^4/4) + ((-1)^3/3)
= (1/4) - (1/3) - (1/4) - (-1/3)
= -1/6
Therefore, using the fundamental theorem of calculus, part 2, we have evaluated the integral ∫1−1(t3−t2)dt to be -1/6.

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Step-by-step explanation:

come on, now, this is one of the (if not THE) most important formula you need to remember for the rest of your life :

a² + b² = c²

with c being the Hypotenuse (the side opposite of the 90° angle), a and b are the legs.

so, in our case, we have then

x² = 5² + 12² = 25 + 144 = 169

x = sqrt(169) = 13

Answer:

19.6349540849

Step-by-step explanation:

π × 2.5^2 = 19.6349540849

Answer:

No

Why he is not correct is because the y-intercept is the coordinate of the point where the graph meets or crosses the y-axis, which is equivalent to a point on the graph where the x-coordinate value reduces to zero, or to put it in a mathematical form x = 0

Step-by-step explanation:

From the given data, we have;

x     \({}\)       y

2     \({}\)      -2

4     \({}\)       0

6      \({}\)      2

8      \({}\)      6

The given data is linear because it has a constant first (common) difference of 2

The general form of the straight line equation is y = m·x + c

Where;

m = The slope

c = The y-intercept

\(Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

The slope of the graph of the data from any two points, (x₁, y₁) = (4, 0) and (x₂, y₂) = (4, 0)) is m = (2 - 0)/(6 - 4) = 1

The equation representing the data in point and slope form is therefore;

y - 4 = 1 × (x - 0)

Which gives;

y = x + 4

Therefore, the y-intercept = 4.

The right response is that 18 people covered 18 kilometers in total.

observe the instructions provided.

Try to form the following in light of the given circumstances: 6 + 7 + 5

Determine the difference or total for: 13 + 5.

Add up or subtract 18 and find the result.

Response: 18

How else do you determine the overall distance travelled?

As soon as a direction changes, note it. Determine the distance covered among each direction change in step two. Step 3: Total the distances from steps 2 and 3 to determine the total distance traveled.

To get the separation between any two points, use the Pythagorean theorem with the formula d=(((x 2-x 1)2+(y 2-y 1)2).

The length of the segment of the line connecting the two points is the distance between them. The shortest line segment between the point and the line will determine the distance between the two.

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                                      "complete question"

In training for a distance running event, Millicent runs 7 miles to a park. Then, she runs 5 miles to the beach before running 6 miles from the beach back to her house.

The first four nonzero terms of the Taylor series for f(x) centered at a = 2 are: 3, (x-2), 0, 0.

To find the first four nonzero terms of the Taylor series for f(x) centered at a = 2, we can use the definition of the Taylor series expansion:

f(x) = f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + f'''(a)(x-a)^3/3! + ...

First, let's find the values of f(a), f'(a), f''(a), and f'''(a) at a = 2:

f(2) = 1 + 2 = 3

f'(2) = 1

f''(2) = 0

f'''(2) = 0

Now, we can substitute these values into the Taylor series expansion:

f(x) = 3 + 1(x-2)/1! + 0(x-2)^2/2! + 0(x-2)^3/3!

Simplifying, we get:

f(x) = 3 + (x-2) + 0 + 0

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Answer:

it's 75

0/0

Step-by-step explanation:

it's 75

cc. vh.

Answer:

320

Step-by-step explanation:

distance=speed*time= 8 *40.

Answer:

This time I was told the answer is 14

Answer:

t = 98 kilometers

Step-by-step explanation:

Answer:

Step-by-step explanation:

I think the question is missing something. There is no x in the equation for h(x) so for this h(x)=0 always.

The main difference between a binomial and multinomial experiment lies in the number of possible outcomes for each trial.

In a binomial experiment, there are two possible outcomes (success or failure), denoted by k = 2. On the other hand, a multinomial experiment involves multiple possible outcomes, with k representing the number of distinct outcomes.

In a binomial experiment, each trial has two possible outcomes, typically labeled as success (S) and failure (F). The number of successful outcomes is of interest, and the probability of success remains constant for each trial. The binomial distribution is characterized by parameters such as the number of trials, the probability of success, and the number of successful outcomes.

In contrast, a multinomial experiment involves multiple possible outcomes, with each outcome occurring with a certain probability. The number of possible outcomes is denoted by k, and each outcome can be categorized or labeled differently. The multinomial distribution considers the probabilities associated with each outcome and their respective frequencies.

In summary, the difference between a binomial and multinomial experiment lies in the number of possible outcomes for each trial. A binomial experiment has two outcomes (success or failure), while a multinomial experiment involves multiple distinct outcomes, with the number of possible outcomes denoted by k.

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Highest possible whole number is 3.

A triangle has three sides, three angles, and three vertices, which are its characteristics. A triangle's total internal angles are always equal to 180 degrees. This is referred to as the triangle's angle sum property. Any two triangle sides can add up to a length that is longer than the third side.

Given Data

Sum of length of any two sides of a triangle is always equal to the third side.

For sides a, b and c

We must have, a + b > c

Sides of triangle are x, x +3 and 10cm

So,

x + x+ 3 > 10

2x > 10 - 3

2x> 7

x > \(\frac{7}{2}\)

Possible values of x are 3.5, 3, and so on.

Highest possible whole number is 3.

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Using equations we know that approximately 8 liters of water must be added in order to produce a 30% acid solution.

So, we know that:

Liters of water: x

25% of solution: 0.25 × 50

30% of solution: 0.30 (50 + x)

Now, form equations and calculate as follows:

0.25 × 50 = 0.30 (50 + x)

12.5 = 15 + 0.30x

15 + 0.30x = 12.5

15 + 0.30x - 15 = 12.5 -15

0.30x = -2.5

.030x/.30 = -2.5/.30

x = - 8.33

Since we can't add water in negative, hence it will be +.

Rounding off: 8 liters

Therefore, using equations we know that approximately 8 liters of water must be added in order to produce a 30% acid solution.

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