a=2.1, b=7.2, c=7.5
Is this a right triangle?

Answer:

C. 4:00 PM

Step-by-step explanation:

If Tyson left at 10:00 A.M. 6 hours later it would be 4:00 P.M.

Answer:

There are 68,640 different ways the runners can finish first, second, and third in the race.

Concept of Permutations

The number of different ways the runners can finish first, second, and third in a race can be calculated using the concept of permutations.

Brief Overview

Since there are 42 runners competing for the top three positions, we have 42 choices for the first-place finisher. Once the first-place finisher is determined, there are 41 remaining runners to choose from for the second-place finisher. Similarly, once the first two positions are determined, there are 40 runners left to choose from for the third-place finisher.

Calculations

To calculate the total number of different ways, we multiply the number of choices for each position:

42 choices for the first-place finisher × 41 choices for the second-place finisher × 40 choices for the third-place finisher = 68,640 different ways.

Concluding Sentence

Therefore, there are 68,640 different ways the runners can finish first, second, and third in the race.

The probability of rolling anything but a 1 is 1, which means that rolling a 1 is impossible with this die.

what is probability?
Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain.

We are given that the die has the following properties:

Probability of rolling 6, 3, or 2 on any roll is 1/2.

Probability of rolling 2, 5, or 4 on any roll is 1/2.

Probability of rolling 2 on any roll is 3/8.

Let's use these properties to answer the given questions:

(a) To find the probability of rolling either a 6, a 3, or a 1, we need to first find the probability of rolling a 1. We know that the probability of rolling either a 6, a 3, or a 2 is 1/2, so the probability of not rolling any of these numbers on a given roll is also 1/2. Similarly, the probability of not rolling either a 2, a 5, or a 4 is also 1/2.

Therefore, the probability of rolling a 1 is:

P(rolling a 1) = 1 - P(not rolling any of 6, 3, 2) - P(not rolling any of 2, 5, 4)

= 1 - (1/2) - (1/2)

= 0

Since the probability of rolling a 1 is 0, the probability of rolling either a 6, a 3, or a 1 is the same as the probability of rolling either a 6 or a 3, which is 1/2. Therefore:

P(rolling either a 6, a 3, or a 1) = 1/2

(b) To find the probability of rolling anything but a 1, we can subtract the probability of rolling a 1 from 1. Since we already know that the probability of rolling a 1 is 0, the probability of rolling anything but a 1 is:

P(rolling anything but a 1) = 1 - P(rolling a 1)

= 1 - 0

= 1

Therefore, the probability of rolling anything but a 1 is 1, which means that rolling a 1 is impossible with this die.

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Answer:

Step-by-step explanation: only (2,2)

\The task is to calculate the probability of pulling seven consecutive consonants from a set of tiles, with replacement each time.

we have a set of tiles, and we want to find the probability of pulling seven consecutive consonants. Since we are replacing the tile after each draw, each pull is an independent event.

To calculate the probability, we need to determine the total number of consonants and the total number of tiles in the set. Let's assume that the set contains a total of n tiles, with c of them being consonants.

For the first draw, the probability of selecting a consonant is c/n, as there are c consonants out of n total tiles. Since we are replacing the tile each time, the probability of pulling a consonant remains the same for each subsequent draw. Therefore, the probability of pulling seven consecutive consonants is (c/n)^7, as we need to multiply the probabilities of each individual draw together.

By substituting the values of c and n into the formula, we can calculate the probability of pulling seven consecutive consonants with replacement from the given set of tiles.

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The variable X has a binomial distribution in the following distributions:

A. When the medicine is tried with two patients, X is the number of patients for whom the medicine worked.

C. When the medicine is tried with six patients, X is the number of patients for whom the medicine worked.

In a binomial probability distribution, the number of "Successes" in a series of n experiments is represented as either success/yes/true/one (probability p) or failure/no/false/zero (probability q = 1 p), depending on the outcome's boolean value.

In a binomial distribution, we have a fixed number of independent trials (in this case, the number of patients), and each trial has only two possible outcomes (success or failure). The probability of success remains the same for each trial (in this case, the probability of the medicine working is 30%).

Option B does not represent a binomial distribution since it counts the number of patients for whom the medicine does not work, which is the complement of success. Option D is not a binomial distribution as it counts the number of doses each patient needs to take, which is not a success/failure outcome.

So, the correct answers are:

A. When the medicine is tried with two patients, X is the number of patients for whom the medicine worked.

C. When the medicine is tried with six patients, X is the number of patients for whom the medicine worked.

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The second expression is given by: We will substitute the given values of x and y:Therefore, the value of the second expression when x=2 and y=3 is -5. Hence, the two expressions are equivalent.

The two expressions are  and . Randy correctly finds that both expressions have a value of 20 when 2 and 3 respectively, and he needs to find the value of the second expression when 2 and 3.Let's first evaluate the first expression when x=2 and y=3:Now, we can find the value of the second expression when x=2 and y=3:Therefore, the value of the second expression when , and the two expressions are equivalent is -5.

Randy is checking to determine if the expressions  and  are equivalent. When x=2 and y=3, he correctly finds that both expressions have a value of 20. When x=2 and y=3, he correctly evaluates the first expression to find that  .We need to find the value of the second expression when x=2 and y=3.

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In this case, the function f(x) is a constant function, and the derivative of a constant function is always 0. Hence, df/dx is equal to 0.

To find df/dx using the definition of the derivative, we start by applying the definition:

df/dx = lim(h→0) [(f(x + h) - f(x))/h]

For the given function f(x) = 3, we substitute the function into the derivative definition:

df/dx = lim(h→0) [(3 - 3)/h]

Simplifying the expression, we have:

df/dx = lim(h→0) [0/h]

As h approaches 0, the numerator remains 0, and dividing by 0 is undefined. Therefore, the derivative df/dx does not exist for the function f(x) = 3.

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There are 45 handshakes that can be made between 10 people.

According to the given question.

Number of people invited in a party = 10

As we know that

The formula for the number of handshake possible with n people is given by

Number of handshakes = n(n -1)/2

This is because each of the people can shake with n -1 (they would not shake their own hand), and the handshake between two people in not counted twice.

Therefore, the number of hands each person shook

= 10(10 -1)/2

= 10(9)/2

= 45

Hence, there are 45 handshakes that can be made between 10 people.

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Answer:

C) 2m + 12 > 24

Step-by-step explanation:

Diego already has 12 goldfish.

He is getting 2 fish each month.

He will have more than 24.

Go step by step that what helps me and that's why I got a 100 on the TFAR.

Answer:

it's answer is 66 : 9

= 22 : 3

hope it helps you

Answer:

11/4

Step-by-step explanation:

Answer:

2, 19, -3

Step-by-step explanation:

we can use the mean and standard deviation of this normal distribution to make inferences about p1-p2.a. X1 has a binomial distribution, and x2 has a binomial distribution.b. A. The sampling distribution of p1-p2 overbar is approximately normal for large samples.

In the following question, we will describe the distributions of x1 and x2 and explain why the Central Limit Theorem is important in finding an approximate distribution for p1-p2.

Consider making an inference about p1-p2, where there are x1 successes in n1 binomial trials and x2 successes in n2 binomial trials.a. Describe the distributions of x1 and x26

. Explain why the Central Limit Theorem is important in finding an approximate distribution for p1-p2.

a. Choose the correct distributions below.x1 has a (normal/poisson/binomial) distribution and x2 has a (binomial/normal/poisson) distribution.b. Choose the correct explanation below.A. The sampling distribution of p1-p2 overbar is approximately normal for large samples.B. The sampling distribution of p1-p2 overbar is skewed for large samples.C. The sampling distribution of p1-p2 overbar remains the same for large samples.The distributions of x1 and x2 are binomial. X1 is a binomial distribution with parameters n1 and p1. X2 is a binomial distribution with parameters n2 and p2. The Central Limit Theorem (CLT) is important in finding an approximate distribution for p1-p2 because it helps us determine the standard deviation of the sampling distribution of p1-p2. The CLT tells us that if the sample size is sufficiently large, the sampling distribution of p1-p2 is approximately normal.

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Answer:

The correct option is C

Step-by-step explanation:

I attached an image that forms the complete question.

The converse Pythagorean theorem states that, "If the square of the longest side of a triangle is equal to the square of the other two sides, then the triangle is a right triangle."

That is if c is the longest side of a triangle and then a and b are the other sides, then if,

c² = a² + b², the triangle is a right triangle.

Looking at all the options, option C fits the theorem well. Because

3² + 4² = 5² implies the triangle is a right triangle and the converse theorem is established.

The option D also looks close, but it's not correct because you can just draw any two sides and put the right angle in between them. The longest is always the part of the triangle that is opposite to the right angle, 90°. If for instance, you draw 3 and 5 then put the right angle in between them, 4 will take the position of the longest side which is wrong.

Therefore, the correct option is c.

Answer:

c

Step-by-step explanation:

Answer: 47/4

Step-by-step explanation:

Convert the words into math:

The number = x

( 13 + x ) * 3 = 7 * x - 9

Expand:

39 + 3x = 7x - 9

Subtract 3x from both sides:

38 = 4x - 9

Add 9 to both sides:

47 = 4x

x = 47/4

Answer:

c

Step-by-step explanation:

ive never been wrong

Answer: C

Step-by-step explanation:

Edge 1945

Answer:

B) (2,5)

Step-by-step explanation:

First of all, your question should be: Factor completely 2xy – 6mn – 3my + 4nx, and not Factorize completely 2xy – 6mn – 3m + 4nx. This noted, we proceed to the solution, which is:

2xy – 6mn – 3my + 4nx

→ y(2x – 3m) + 2n(–3m + 2x)

→ (2x – 3m) (y + 2n)

.: Final answer: (2x – 3m) (y + 2n)

(2x – 3m) (y + 2n) is the factorized form of  2xy -6mn - 3m + 4nx

Two or more expressions with an Equal sign is called as Equation.

Factorization or factoring consists of writing a number or another mathematical object as a product of several factors, usually smaller or simpler objects of the same kind.

The given expression is 2xy – 6mn – 3my + 4nx

Two times of xy minus six times of mn minus three times of m y plus four times of nx

2xy – 6mn – 3my + 4nx

By using commutative property arrange the terms

2xy –3my– 6mn+ 4nx

Take y as common from first two terms and 2n as common in last two terms

y(2x – 3m) + 2n(–3m + 2x)

(2x – 3m) (y + 2n)

Hence, (2x – 3m) (y + 2n) is the factorized form of  2xy -6mn - 3m + 4nx

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\(\text{Given that ,}\\\\\text{Length,}~ l = (2y+5)~\text{units.}\\\\\text{Width, } w= 3~\text{units.}\\\\\\\text{Area} = lw = (2y+5)(3) = (6y+15) ~~ \text{units}^2.\\\\\\\text{Perimeter} =2(l+w) = 2(2y+5 +3) = 2(2y+8) = (4y+16)~~ \text{units}.\)

1   Y is distributed as N(aμ + b, a^2σ^2), as desired.

2  We have shown that under these conditions, E[XY] = E[X]E[Y].

To prove that Y is distributed as N(aμ + b, a^2σ^2), we need to show that the mean and variance of Y match those of a normal distribution with parameters aμ + b and a^2σ^2, respectively.

First, let's find the mean of Y:

E(Y) = E(aX + b) = aE(X) + b = aμ + b

Next, let's find the variance of Y:

Var(Y) = Var(aX + b) = a^2Var(X) = a^2σ^2

Therefore, Y is distributed as N(aμ + b, a^2σ^2), as desired.

We can use the definition of covariance to prove that E[XY] = E[X]E[Y]. By the properties of expected value, we know that:

E[XY] = ∫∫ xy f(x,y) dxdy

where f(x,y) is the joint probability density function of X and Y.

Then, we can use the fact that X and Y are independent to simplify the expression:

E[XY] = ∫∫ xy f(x) f(y) dxdy

= ∫ x f(x) dx ∫ y f(y) dy

= E[X]E[Y]

where f(x) and f(y) are the marginal probability density functions of X and Y, respectively.

Therefore, we have shown that under these conditions, E[XY] = E[X]E[Y].

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The required number of children and adults for sitting in the theater are 300 and 50 respectively.

A equation is supposed to be linear equation in two factors in the event that it is written as hatchet + by + c=0, where a, b and c are genuine numbers and the coefficients of x and y, i.e an a and b separately, are not equivalent to nothing. For instance, 10x+4y = 3 and - x+5y = 2 are straight equation in two factors.

Let be consider number of children be x and that of adults is y.

We have,

x + y = 350-------(1)

y = 350 - x

And 5x + 10y = 2000------------------(2)

Put value of y in equation (2)

5x + 10( 350 - x) = 2000

5x + 3500 - 10x = 2000

-5x = -1500

x = 300

Then

y = 350 - x = 350 - 300 = 50

Thus, There will be 300 children and 50 adults in the  theater .

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Answer: 1/y18

Step-by-step explanation:

Answer:

\(\frac{1}{y18}\)

Answer:

A)

\(P=2x+2\pi r\)

B)

\(x=\frac{1}{2}(P-2\pi r)\)

C)

\(x\approx173\text{ feet}\)

Step-by-step explanation:

So, the track is composed of a rectangle and two semicircles.

The side length of the rectangle is x, and the radius of the semicircles is r.

Part A)

The perimeter is simply the length around the figure.

We can see that the perimeter will be equivalent to two times x plus two times the circumference of the semi-circles.

So, let's figure out the circumference of the semi-circles. The circumference of a normal circle is:

\(C_{\text{normal}}=2\pi r\)

A semi-circle is half of that. So, we will divide by 2:

\(C_{\text{ semi}}=\pi r\)

We are excluding the diameter from this.

So, our perimeter will be two times x and two times the circumference of a semi-circle (since there are two semi-circles). In other words:

\(P=2(x)+2(\pi r)\)

Simplify:

\(P=2x+2\pi r\)

Part B)

So we acquired the formula:

\(P=2x+2\pi r\)

To solve for x, first, subtract 2πr from both sides. So:

\((P)-2\pi r=(2x+2\pi r)-2\pi r\)

The right side cancels. So:

\(P-2\pi r=2x\)

Multiply both sides by 1/2:

\(\frac{1}{2}(P-2\pi r)=\frac{1}{2}(2x)\)

The right side cancels. So:

\(\frac{1}{2}(P-2\pi r)=x\)

Flip:

\(x=\frac{1}{2}(P-2\pi r)\)

Part C)

So we want to find x when the perimeter is 660 and r is 50 feet. So, substitute them into our formula. We have:

\(x=\frac{1}{2}(P-2\pi r)\)

Substitute 660 for P and 50 for r:

\(x=\frac{1}{2}(660-2\pi (50))\)

Multiply:

\(x=\frac{1}{2}(660-100\pi )\)

Distribute:

\(x=330-50\pi\)

Use a calculator. So:

\(x\approx173\text{ feet}\)

And we're done!

Answer:

A.

have a good day or night

Answer: C. rationalizing the denominator

Rationalizing the denominator is a useful step to simplify expressions where there are square roots in the denominator. It doesn't apply to actually solving a quadratic. On the other hand, the quadratic formula can solve quadratics. The same applies for choices B and D as well.

Answer: x= by/d

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

3.2/0.4=8

8×2=16

16×0.4=6.4

6.4÷0.1=64

Let

S = 1 + 2 + 3 + … + (n - 2) + (n - 1) + n

Reversing the order of terms, we have

S = n + (n - 1) + (n - 2) + … + 3 + 2 + 1

and we observe that terms in the same position on the right side add up to n + 1.

2S = (1 + n) + (2 + (n - 1)) + (3 + (n - 2)) + … + (n + 1)

There are n terms in the sum, so each the right side is simply n copies of n + 1, and

2S = n (n + 1)

S = n (n + 1)/2

Now,

17 + 18 + 19 + … + 41 + 42 + 43

= (1 + 2 + 3 + … + 41 + 42 + 43) - (1 + 2 + 3 + … + 14 + 15 + 16)

= (S with 43 terms) - (S with 16 terms)

= 43 (43 + 1)/2 - 16 (16 + 1)/2

= 810