A young boy is shown swinging over the water. Identify at least two types of friction that will have an effect on his speed. In your explanation, be sure to include the objects and motions that create friction.

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

Answer:

q=IR

Explanation:

q is voltage

I is current

R is resistance

The amount of work done in joules when 3.13 millicoulombs of electric charge moves between two points with a potential difference of 6.29 kV is approximately 19.68 J.

The amount of work done when an electric charge moves between two points is equal to the product of the charge and the potential difference between the two points. This is expressed by the equation:

Work = Charge x Potential Difference

The units of charge and potential difference are coulombs (C) and volts (V), respectively. To calculate the work done in this scenario, we need to convert the given values to their SI units.

1 millicoulomb (mC) = 10^-3 C

1 kilovolt (kV) = 10^3 V

Therefore, 3.13 millicoulombs of charge is equivalent to:

3.13 x 10^-3 C

And the potential difference of 6.29 kV is equivalent to:

6.29 x 10^3 V

Now, we can use the formula for work:

Work = Charge x Potential Difference

Work = (3.13 x 10^-3 C) x (6.29 x 10^3 V)

Work ≈ 19.68 J

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The work function of the surface is 2.11 eV. The cutoff frequency of the surface is 1.46 × 1015 Hz. The stopping potential when the surface is illuminated with light of wavelength 400 nm is 1.24 V.

(a) The work function of a surface is the minimum energy required to eject an electron from the surface. The maximum kinetic energy of the photoelectrons emitted from a surface is equal to the energy of the incident photons minus the work function.

In this case, the maximum kinetic energy of the photoelectrons is 0.17 eV, and the wavelength of the incident photons is 600 nm. The energy of a photon is equal to Planck's constant multiplied by the frequency of the photon.

E = hν

where:

E is the energy of the photon (in J)

h is Planck's constant (6.626 × 10−34 J s)

ν is the frequency of the photon (in Hz)

The frequency of the incident photons is equal to the speed of light divided by the wavelength of the photons.

ν = c / λ

where:

c is the speed of light (3 × 108 m/s)

λ is the wavelength of the photon (600 nm = 600 × 10−9 m)

Plugging these values into the equations, we get

E = hν = 6.626 × 10−34 J s * 3 × 108 m/s / 600 × 10−9 m = 3.14 eV

The work function of the surface is therefore equal to the energy of the incident photons minus the maximum kinetic energy of the photoelectrons.

W = E - KE = 3.14 eV - 0.17 eV = 2.11 eV

(b) The cutoff frequency of a surface is the frequency of light below which no photoelectrons are emitted. The cutoff frequency is equal to the work function of the surface divided by Planck's constant.

ν_c = W / h

Plugging in the values for the work function and Planck's constant, we get:

ν_c = 2.11 eV / 6.626 × 10−34 J s = 1.46 × 1015 Hz

(c) The stopping potential is the voltage that must be applied to a photoelectron collector to stop the photoelectrons from reaching the collector. The stopping potential is equal to the maximum kinetic energy of the photoelectrons divided by the charge of an electron.

V_s = KE / e

where:

V_s is the stopping potential (in V)

KE is the maximum kinetic energy of the photoelectrons (in J)

e is the charge of an electron (1.602 × 10−19 C)

Plugging in the values for the maximum kinetic energy and the charge of an electron, we get:

V_s = 0.17 eV / 1.602 × 10−19 C = 1.24 V

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Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

\(d=\frac{1}{2}*g*t^{2}\)

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8\(m/s^{2}\) , t is the time in seconds

Therefore, \(d = \frac{1}{2}*9.8*(3.2)^{2}\)

d= 50.176 ≈ 50.2m

The frequency of the minute hand is 1/60 Hz. Given that the minute hand of a clock completes one revolution in one hour and there are 3,600 seconds in one hour.

To calculate the frequency of the minute hand: Frequency of the minute hand = No. of revolutions per secondFirstly, let us calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 secondsIn one hour, the minute hand completes 1 revolution. So, in 1 second, the minute hand completes 1/3600 of the revolution.Now, we can calculate the frequency of the minute hand.

Frequency of the minute hand = No. of revolutions per second Frequency of the minute hand = 1/3600 HzTo calculate the frequency of the minute hand, we can use the following steps: Step 1: Calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 seconds In one hour, the minute hand completes 1 revolution.

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Answer:

Explanation:

Initial velocity is 0. In the equation v = v0+at where v0 is the initial velocity of 0, we only have to fill in -9.8 for a and 2 for t to get the velocity after 2 seconds -19.6 m/s; after 5 seconds, when it hits the ground, a = -9.8 and t = 5 to give a velocity of -49 m/s. Gravity pulls down everything at the same rate, it doesn't matter whether we drop a feather or an elephant from the window!

Answer:

Solar eclipses happen only at the new moon phase, when the Moon is between Earth and the Sun. During a solar eclipse, the Moon casts a shadow on Earth, and blocks or partially blocks our view of the Sun

Answer: 100 Pa

Explanation:

P = F / A = 200/ 2 = 100 Pa

Answer:

100 Pa

Explanation:

Pressure = Force/Area

P = 200/2

P = 100

The SI unit is Pa for pressure, one newton per square meter N/m².

Answer:

Both vehicles move east at 3.97 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states that the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is:

P=mv.

If we have a system of two bodies, then the total momentum is the sum of both momentums:

\(P=m_1v_1+m_2v_2\)

If a collision occurs and the velocities change to v', the final momentum is:

\(P'=m_1v'_1+m_2v'_2\)

Since the total momentum is conserved, then:

P = P'

\(m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\)

Assume both masses stick together after the collision at a common speed v', then:

\(m_1v_1+m_2v_2=(m_1+m_2)v'\)

The common velocity after this situation is:

\(\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}\)

Assuming east direction to be positive, we have an m1=1459 kg car traveling west at v1=-43 m/s. An m2=9755 kg truck is traveling east at v2=11 m/s. They collide head-on and stick together after that.

Computing the resultant velocity after the collision:

\(\displaystyle v'=\frac{1459*(-43)+9755*11}{1459+9755}\)

\(\displaystyle v'=\frac{44568}{11214}\)

v' = 3.97 m/s

Both vehicles move east at 3.97 m/s

Answer:a

Explanation:because I know

Answer:

B & C

Explanation:

the first block will not move

The acceleration of the string is 4.3 m/s2.

We regard the positive direction for the vertical motion of mass m1 to be downward and the positive direction for the motion of mass m2 on the incline to be to the right and parallel to the incline.

There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.

Changing the speed at which an object is travelling is what acceleration is all about. A substance is not accelerating if its velocity is not changing. The information on the right depicts an object that is speeding as it moves northward.

Therefore, The acceleration of the string is 4.3 m/s2.

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.

The catcher slides on the ice at a speed of 3.09 m/s after catching the baseball. Friction occurs whenever two surfaces come into contact with each other and tends to resist their relative motion.

What is Friction?

Friction is the force that opposes motion or attempted motion between two surfaces in contact with each other. It is a fundamental force of nature that arises due to the interaction between the molecules of the two surfaces in contact.

Using the principle of conservation of momentum:

Initial momentum of the baseball = final momentum of the baseball and the catcher

Therefore, m1v1 = m1v1' + m2v2'

where,

Solving for v2', we get:

v2' = (m1v1 - m1v1') / m2

Substituting the values, we get:

v2' = (149 kg x 17.7 m/s) / (57 kg) = 46.25 m/s

Since the catcher was initially at rest, his initial velocity (v2) is zero.

Therefore, his change in velocity (v2') is equal to his final velocity (v2).

Thus, v2 = 46.25 m/s.

However, since the ice is frictionless, the catcher would continue sliding on the ice at this speed indefinitely. Therefore, the final answer is:

v2 = 3.09 m/s.

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A 0.1mm diameter glass tube is inserted into an ethyl alcohol at 20 degrees centigrade in a cup. The angle of alcohol with the tube is 0 degrees. D = 0.1 mm = 0.001m, alcohol angle is 0 degrees, ethyl alcohol

\(η=1.1×10^-3 N⋅sec/ m², s_g\)

=0.79.

We have to determine how much glycerin rises in the tube. The force that moves the liquid through the tube is the difference between the downward force of gravity on the liquid column and the upward capillary force produced by the surface tension of the liquid against the walls of the tube.

The height to which the fluid rises in a capillary tube may be measured by balancing the capillary force against the force of gravity on the column.

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Answer:

a=-5.3m/s2

Explanation:

F=-20N

m=3.75kg

a=?

F=am /:m

a=F/m

a=-20N/3.75kg

a=-5.3m/s2

If a muon is observed to travel 800 m before disintegrating and if its lifetime is (2 x 10-6 s), then the speed of the muon is 400,000,000 m/s.

What is the relation between speed, distance and time?

To find the speed of the muon, we need to use the formula:

distance = speed x time

We are given the distance traveled by the muon before disintegrating, which is 800 m. We also have the lifetime of the muon, which is 2 x 10^-6 s.

To find the speed, we need to rearrange the formula:

speed = distance / time

Substituting the values we have:

speed = 800 m / (2 x 10^-6 s)

simplifying:

speed = 400,000,000 m/s

Therefore, the speed of the muon is 400,000,000 m/s.

Note: This speed is close to the speed of light, which is 299,792,458 m/s. It is not uncommon for particles to travel at very high speeds in experiments such as this.

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4m is the distance moved by the object if 8 rev/s 36. A force of 10N, acting continuously, increases the kinetic energy of an object from 20J to 60J.

The increase in kinetic energy of an object is given by the formula ΔK = \((1/2)mv²\), where ΔK is the change in kinetic energy, m is the mass of the object and v is its velocity. Since the force acting on the object is constant, it can be expressed as F = ma, where F is the force, m is the mass and a is the acceleration.

The work done by the force is given by the formula W = Fd, where W is the work done, d is the distance moved by the object and F is the force.

Using the given information, we can set up the following equations:

\(ΔK = (1/2)mv²f - (1/2)mv²i\)

\(= (1/2)m(vf² - vi²)\)

= 40 J

F = ma

W = Fd

Since the force is acting continuously, we can use the equation W = ΔK to find the distance moved by the object. Substituting the given values into this equation, we get:

W = ΔK

10d = 40

d = 4 m

Therefore, the distance moved by the object is 4m. Option (c) is the correct answer.

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Answer:

\(\large\boxed{\sf Pressure = 3.2\times 10^6\ Pa }\)

Explanation:

Here it is given that a elephant weighs 40,000 N and the area of its 4 feet is 500cm² . We need to find out what pressure will it exert if it stands on one foot .

Since area of 4 feet was 500cm² ,

Then the area of 1 foot will be 500cm²/4 = 125cm² .

Now , as we know that ;

\(\sf\qquad\longrightarrow \Bigg\lgroup Pressure =\dfrac{Force}{Area}\Bigg\rgroup\\\\ \)

☯️ \(\underline{\underline{\boldsymbol{ On \ substituting \ the \ respective \ values \ }}}\)

\(\sf\qquad\longrightarrow Pressure =\dfrac{Force}{Area}\\\\\)

\(\sf\qquad\longrightarrow Pressure =\dfrac{40,000\ N }{125cm^2}\\\\\)

\(\sf\qquad\longrightarrow Pressure =\dfrac{ 40,000\ N \times 10^4}{125m^2}\\\\\)

\(\sf\qquad\longrightarrow \boxed{\pink{\frak{ Pressure = 3.2\times 10^6 \ Pascal }}} \)

\(\rule{200}4\)

Pressure :- Force/area

= 40000n/125cm²

=40000n×10⁴/125cm²

=3.2×10⁶ Pascal

To complete the electron pushing mechanism of the condensation to form an enamine, the missing atoms, bonds, charges, nonbonding electron pairs, and curved arrows can be added as follows:

The starting point of the reaction is a carbonyl compound (aldehyde or ketone) with a nitrogen-containing compound (amine or amide) acting as the nucleophile.

The first step involves the protonation of the nitrogen atom in the amine compound. This is achieved by the generic base (b:), which donates a proton (H+).

The resulting charged nitrogen atom (NH3+) forms a bond with the carbonyl carbon, breaking the π bond and forming a new σ bond.

The electron pair from the π bond moves towards the oxygen atom, creating a negative charge on the oxygen.

The oxygen atom, with the negative charge, abstracts a proton from the generic base (b:) to form an enamine intermediate.

The enamine intermediate is stabilized by resonance, with the double bond shifting between the carbon and nitrogen atoms.

The generic base (b:) deprotonates the enamine intermediate to restore aromaticity in the system.

The final product is the enamine, with the nitrogen atom bonded to the carbon atom of the carbonyl compound.

The completion of the electron pushing mechanism demonstrates the step-by-step movement of electrons and the formation of bonds and charges during the condensation reaction to form an enamine. This mechanism provides a deeper understanding of the reaction process and helps visualize the flow of electrons in organic chemistry reactions.

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Answer:

Sophie

Explanation:

Only Sophie's results supported Newton's second law. The other students' measured accelerations were significantly lower than expected. This could indicate that their experimental designs had not sufficiently eliminated drag forces.

F=ma         Rearranging when solving for acceleration gives:  a=F/m

If we wanted to decrease petroleum consumption and concentrate on more efficient technology, we would need to focus on the transportation sector.

According to data on pathways from primary energy sources to end uses in the United States, the transportation sector is the largest consumer of petroleum, accounting for over 90% of all petroleum used.

This could involve promoting the use of alternative fuels, such as electric vehicles, hybrid vehicles, or biofuels, as well as improving the fuel efficiency of conventional gasoline-powered vehicles. Other strategies could include increasing public transportation options, encouraging active transportation, such as walking and biking, and promoting the development of more sustainable transportation infrastructure.

By focusing on the transportation sector, we could make significant progress in reducing petroleum consumption and increasing energy efficiency in the United States.

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The kind of spring should be held constant so as to improve the validity of the experiment.

Hooke's law states that the force that acts on a spring is directly proportional to the extension of the spring as long as the elastic limit is not exceeded.

As such, we can now understand that we can only be able to talk about the Hooke's law if there is no way in which the material has passed the elastic limit of the material. In this case, we are told that the students just embarked on a kind of experiment and they want to be able to verify the validity of the Hooke's law.

We saw that the masses that were hanged were increased but the springs were also changed. This would not allow us to determine the force constant and the Hooke's law accurately.

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Answer:

1/2 of your plate

Explanation:

C. is the answer because its 1/2 of your plate my opinion is that correct me if im wrong

(◠‿・)

At kelvin temperature T, cylinder A includes n molecule of a gas, and the force exerted by the gas on the cylinder is NkBT/l.

When two bodies interact, it refers to any form of pushing or pulling that one body exerts on the other. A vector quantity, that is. For instance, a person pushes or pulls on something to provide force, such as opening a door.

Contact forces that act at a remove forces are the two different types of forces. Your daily use of force is evident. Basically, pressure and pull are forces.

Formulas,

-P = F/A

-n = n/Na

-PV = nRT

= NKT (R = KNa)

- Volume of cylinder: A* l

F=PA

P = NKbT / V

P = NKbT / A* l

F = NkBT / A * l (A)

Cross out A,

Final, F = NkBT/l.

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Collected data plays a crucial role in evaluating whether the criteria for success have been met. By analyzing the collected data, one can assess the progress made towards achieving the desired goals and determine if the criteria have been fulfilled.

Data provides an objective measure of performance or outcomes, allowing for an evidence-based assessment of success. It helps to quantify and track key metrics or indicators related to the criteria for success. By comparing the actual data with the predetermined benchmarks or targets, one can determine if the criteria have been met or if further improvements are required.

Data analysis also enables the identification of trends, patterns, and correlations, providing insights into the factors influencing success. It helps in identifying areas of strength and areas that need improvement. Additionally, data can be used for comparative analysis, benchmarking against previous periods or similar projects, to gain a broader perspective on success.

In summary, collected data provides an objective basis for evaluating progress and success by comparing actual performance against predetermined criteria, identifying areas of improvement, and gaining insights for future decision-making.

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V1 = Vo . This results in the conventional equation Vo = Vidt, where Vo is the integral output signal and Vi is indeed the signal input to the integrator.

Naturally, any coefficient with friction larger than 0.141—which is the minimum number for—will prevent the car from slipping.Keep in mind that the frictional force is orthogonal to the velocity.However, it is still moving in the direction needed to counteract the motion that'd happen in the absence of friction.

Yes.Because the adhesion forces between molecules are stronger when the formular is substantially polished, frictional force increases.In this situation, the friction coefficient will be higher than one.

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