As given by the question
There are given that the triangle.
Now,
For finding the missing side, use the tangent and cosine function.
Hence, the tangent and cosine functions are to be used to find the sides.
Now,
For find the angle, use sine function:
\(\begin{gathered} \sin x=\frac{40}{42} \\ si\text{nx=}0.9 \\ x=\sin ^{-1}0.9 \end{gathered}\)Then,
\(\begin{gathered} x=\sin ^{-1}0.95 \\ x=71.80 \end{gathered}\)Hence, the angle of the given triangle is 71.8 degrees.
Y=2X squared -12 X +20 for quadratic formula
x = (12 ± √(-16)) / 4,The solutions would be complex numbers.
What is the quadratic formula?To solve quadratic equations of the form ax2 + bx + c = 0, use the quadratic formula. For this situation, your condition is as of now as a quadratic condition, with a = 2, b = - 12, and c = 20.
The quadratic formula is:
x = (-b ± √\((b^2 - 4ac)\)) / 2a
Plugging in the values for a, b, and c, we get:
x = (-(-12) ± √\(((-12)^2 - 4(2)(20)))\) / 2(2)
Simplifying the expression inside the square root:
x = (12 ± √\((144 - 160)\)) / 4
x = (12 ± √(-16)) / 4
Since the square foundation of a negative number is definitely not a genuine number, this condition has no genuine arrangements. Complex numbers would provide the answers.
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Prove:is tangent to circle C.
The tangent at any point of a circle is perpendicular to the radius through the point of contact by showing that line PQ coincides with the radius OP.
Let us assume that we have a circle with center O and radius r.
Let P be any point on the circle .
And let Q be the point of intersection of the tangent to the circle at P and the radius OP,
To prove that PQ is perpendicular to OP.
First, we observe that OP is a radius of the circle and therefore its length is r.
Since PQ is tangent to the circle at point P,
It is perpendicular to the radius drawn from the center of the circle to point P.
As the tangent to a circle is perpendicular to the radius drawn to the point of contact.
This implies, angle QOP is a right angle.
Next, triangle OPQ is a right triangle with right angle at Q.
By the Pythagorean Theorem, we have,
OP²= OQ² + PQ²
Substituting r for OP and noting that OQ = r since Q is on the radius. we have,
⇒ r² = r²+ PQ²
Subtracting r² from both sides, we get,
⇒ PQ² = 0
This implies that PQ = 0,
In other words, that point Q coincides with point P.
PQ is a line that coincides with the radius OP.
And since angle QOP is a right angle, we can conclude that PQ is perpendicular to OP.
Therefore, it is proved that the tangent at any point of a circle is perpendicular to the radius through the point of contact.
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The above question is incomplete, the complete question is:
Prove that the tangent at any point of a circle is perpendicular to the radius through the point of contact.
Savings ($)
200
160
120
80
40
O
5 10 15 20 25
Time (weeks)
Find the constant of proportionality and write an equation for the relationship
The constant of proportionality is
The equation for the relationship is
For the given graph related to savings on y-axis and time on x-axis, the constant of proportionality is equal to 4, and the equation representing the relationship between the savings and the time is given by y = 4x.
As given in the question,
From the graph,
y-axis represents the savings in dollars
x-axis represents the time in seconds
Let us consider savings represents by y and time represents by x.
Form the graph we can see that,
When x = 10 ⇒ y = 40
when x = 15 ⇒ y = 60
Graph represents the straight line so it is linear function.
y = 40
⇒ y= 4(10)
⇒ y= 4x
⇒y ∝ x
⇒Constant of proportionality 'k' = 4
Now, for the equation consider two coordinates on the graph,
(x₁ , y₁) = (10, 40)
(x₂ , y₂) = (15, 60)
( y-y₁)/ (x-x₁) = (y₂ -y₁) / (x₂ - x₁)
⇒( y- 40)/(x-10) = (60 -40)/ (15-10)
⇒ y-40 = 4(x-10)
⇒y = 4x
Therefore, for the given graph related to savings on y-axis and time on x-axis, the constant of proportionality is equal to 4, and the equation representing the relationship between the savings and the time is given by y = 4x.
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A radioactive substance decays at a continuous rate of 14.4 % per day. After 15 days, what amount of the substance will be left if you started with 140 mg? (a) First write the rate of decay in decimal form. r = (b) Now calculate the remaining amount of the substance. Round your answer to two decimal places.
Answer:(a) The rate of decay is 14.4% per day, which can be written as a decimal by dividing by 100: r = 0.144.
(b) The formula for continuous decay is given by:
A = A₀ * e^(-rt)
where A is the remaining amount of the substance after time t, A₀ is the initial amount, r is the rate of decay, and e is the mathematical constant approximately equal to 2.71828.
Plugging in the given values, we get:
A = 140 * e^(-0.144*15)
A = 140 * e^(-2.16)
A ≈ 47.23
Therefore, after 15 days, approximately 47.23 mg of the radioactive substance will be left, rounded to two decimal places.
Step-by-step explanation:
Find the perimeter of the figure to the nearest hundredth.
The perimeter of the circular figure is P = 36.85 feet
What is a Circle?A circle is a closed two-dimensional figure in which the set of all the points in the plane is equidistant from a given point called “center”. Every line that passes through the circle forms the line of reflection symmetry. Also, the circle has rotational symmetry around the center for every angle
The circumference of circle = 2πr
The area of the circle = πr²
where r is the radius of the circle
The standard form of a circle is
( x - h )² + ( y - k )² = r²,
where r is the radius of the circle and (h,k) is the center of the circle.
Given data ,
Let the perimeter of the figure be represented as P
Now , the perimeter of the figure P = perimeter of circle + perimeter of lengths of sides
The total lengths of sides = ( 3 + 3 + 3 + 3 + 3 + 3 ) feet
The total lengths of sides = 18 feet
And , the circumference of circle = 2πr
The diameter of the circle d = 12 feet - 6 feet
The diameter of the circle d = 6 feet
So , the radius of the circle r = d/2 = 3 feet
And , the circumference of circle = 2 x π x 3
The circumference of circle = 6π
So , perimeter of the figure P = ( 6π + 18 ) feet
Perimeter of the figure P = 36.849 feet
Hence , the perimeter of the figure is 36.85 feet
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Given m∠JSL = (4y − 10)° and bisects ∠JSL.
What is the value of y if m∠HSJ = (y + 43)°?
The value of y is 48.
To find the value of y in this scenario, we need to use the fact that the angle bisector of ∠JSL splits it into two congruent angles.
Let's denote one of these congruent angles as ∠HSL and the other as ∠LSJ. Since ∠JSL is bisected, we have:
m∠JSL = m∠HSL + m∠LSJ
Given that m∠JSL = (4y - 10)° and m∠HSL = m∠LSJ = ∠HSJ = (y + 43)°, we can substitute these values into the equation:
4y - 10 = (y + 43) + (y + 43)
Simplifying the equation:
4y - 10 = 2y + 86
Subtracting 2y from both sides:
2y - 10 = 86
Adding 10 to both sides:
2y = 96
Dividing both sides by 2:
y = 48
Therefore, the value of y is 48.
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help plsss
rotate tuv 90 degrees clockwise around the origin
Answer: T'=(-1,-1), U'=(-3,-1), V'=(-1,-4)
Step-by-step explanation:
Which r value suggests a weak positive correlation?
r=0.17454
r= -0.17454
r=0.98264
r= -098264
Answer:
\(\boxed {\boxed {\sf A.\ r=0.17454}}\)
Step-by-step explanation:
The correlation coefficient helps us understand the relationship between variables.
A positive correlation is a positive number. A negative correlation is a negative number.
We can automatically eliminate choices B and D because they are negative, but we are looking for a positive correlation.
A number closer to 1 indicates a strong correlation. If the number is closer to 0, it's weak.
The two choices left are:
A. r=0.17454 C. r= 0.98264C is very close to 1, so it's a strong correlation.
We want to find the weak one, which must be A because it is closer to 0.
Consider five circles with radii of 1, 2, 4, 8, and 16 inches.
a. Complete the table.
b. Compare the areas and circumferences. What happens to the circumference of a circle when you double the radius? What happens to the area?
c. What happens when you triple the radius?
Please answer all questions or just the table, because I need help. Thanx!
Answer:
a) 2. 4pi (in) , 4pi
3. 8pi , 16pi
4. 16pi, 64pi
5. 32 pi , 256pi
Step-by-step explanation:
b) when radius increase , the areas and circumferences increase to
circumference = 2 pi * radius ; so if you double the radius , circumference will be double
area = pi * radius * radius ; if you double the radius , area will be 2^2 or 4 times
c) circumference will be triple and
area will be 3^2 or 9 times
Type the correct answer in the box.
Winston is creating a rectangular piece of 8-bit art using squares that are x pixels wide. The length of the rectangular piece, in pixels, is represented by the function l(x) = x + 24, and the width of the rectangular piece is represented by w(x) = x + 16.
Write the standard form of the function which describes the total area of the rectangular piece, a(x), in terms of x, the side length of each square pixel.
Area=l×w
Function:-
\(\\ \sf\longmapsto (l*w)(x)\)
\(\\ \sf\longmapsto l(x)*w(x)\)
\(\\ \sf\longmapsto (x+24)(x+16)\)
\(\\ \sf\longmapsto x^2+40x+384\)
81 of 360 students at Jefferson Elementary are taking Spanish. What percent of students are taking Spanish
Answer:
Step-by-step explanation:
81: 360*100 =
(81*100): 360 =
8100: 360 = 22.5
By using graphical method, find optimal solution of the problem max z = 3x + y s.t 2x - y ≤ 5 -x + 3y ≤ 6 x ≥ 0, y ≥ 0
By analyzing the graph and evaluating the objective function at each vertex of the feasible region, we can find the optimal solution, which is the vertex that maximizes the objective function z = 3x + y.
To find the optimal solution of the given problem using the graphical method, we need to plot the feasible region determined by the given constraints and then identify the point within that region that maximizes the objective function.
Let's start by graphing the constraints:
1. Plot the line 2x - y = 5. To do this, find two points on the line by setting x = 0 and solving for y, and setting y = 0 and solving for x. Connect the two points to draw the line.
2. Plot the line -x + 3y = 6 using a similar process.
3. The x-axis and y-axis represent the constraints x ≥ 0 and y ≥ 0, respectively.
Next, identify the feasible region, which is the region where all the constraints are satisfied. This region will be the intersection of the shaded regions determined by each constraint.
Finally, we need to identify the point within the feasible region that maximizes the objective function z = 3x + y. The optimal solution will be the vertex of the feasible region that gives the highest value for the objective function. This can be determined by evaluating the objective function at each vertex and comparing the values.
Note: Without a specific graph or additional information, it is not possible to provide the precise coordinates of the optimal solution in this case.
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Question 10 of 25 What is the recursive formula for this geometric sequence? -2,-16, -128, -1024,... A. ○ B. C. (a, D. 3₁ = :-2 an = 2n-1 = = -2 an = an-1.8 • a₁ = 8 an = an-1• (-2) (a₁ = -8 30 = 20-1.2 SUBMIT
Answer:
\(a_{n}\) = 8\(a_{n-1}\) ; a₁ = - 2
Step-by-step explanation:
a recursive formula in a geometric sequence allows a term to be found by multiplying the preceding term by the common ratio r
here r = \(\frac{a_{2} }{a_{1} }\) = \(\frac{-16}{-2}\) = 8 , then
\(a_{n}\) = 8\(a_{n-1}\) ; a₁ = - 2
I need help please help me out .
Given
mZQPS is a straight angle
mZQPR = 72 – 4°
mZRPS = 9x - 40°
Find mZQPR:
P
9514 1404 393
Answer:
m∠QPR = 94°
Step-by-step explanation:
Given:
m∠QPS = 180°
m∠QPR = 7x -4°
m∠RPS = 9x -40°
Find:
m∠QPR
Solution:
m∠QPR + m∠QPR = 180°
(7x -4°) +(9x -40°) = 180°
16x = 224° . . . . . . . . . . . . . add 44°
x = 14° . . . . . . . . . . . . . divide by 16
m∠QPR = 7x -4° = 7(14°) -4°
m∠QPR = 94°
what are the steps to solve this
Answer:
The equation of this line is y = -4.
Answer:
y=-4
Step-by-step explanation:
zero slope m=0
y-y1=m(x-x1)
y-(-4)=0(x-(-9))
y+4=0
y=-4
What is the value of the expression 2z ÷ [z – (z – 4)] when z = 8?
2z ÷ [z – (z – 4)]
Sub z=8 into the expression
2(8) ÷ [8 – (8 – 4)] = 16 ÷ 4
= 4
Write rules for the composition of translations.
Answer: gurl you think i know
Step-by-step explanation:
Two forces of 560 N and 222 N act at a point. The resultant force is 634 N. Find the angle between the forces.
The angle between the two forces of 560 N and 222 N is 80.96°
What is the resultant of two vectors?The resultant of two vectors P and Q refer to the magnitudes of the vectors and it can be expressed by the formula \(\mathbf{R = \sqrt{P^2 +Q^2 +2PQ cos \theta }}\)
Now, using the above equation, we can easily determine the angle between the forces of the two vectors as follows:
\(\mathbf{634 = \sqrt{560^2 +222^2 + 2(560 \times 222) \ Cos \theta }}\)
\(\mathbf{401956 =313600 +49284 + 248640 \ Cos \theta }}\)
\(\mathbf{401956 -313600 -49284 = 248640 \ Cos \theta }}\)
\(\mathbf{39072= 248640 \ Cos \theta }}\)
\(\mathbf{ Cos \theta = \dfrac{39072}{248640}}}\)
\(\mathbf{Cos \theta =0.1571}\)
\(\mathbf{ \theta =80.96^0}\)
Therefore, we can conclude that the angle between the forces is 80.96°
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3x + (2 + x) + 5 ∙ 3
help will give brainliest
Answer:
20+2=22
Step-by-step explanation:
When you go down by 2, then use the Inverse Operation to add it up.
Candace is designing a rectangular tile that has a width of 3/5 meter and an area of 9/10 meter what is the length of the tile Candace is designing
The length of the tile Candace is designing is 3 /2 meters.
The rectangular tiles he is designing has the following dimension:
width = 3/5 meters
area = 9/10 meters
The length of the tiles Candace is designing can be calculated below:
area of a rectangle = lw
where
l = length
w = width
Therefore,
9/10 = 3/5 l
cross multiply
9 × 5 = 3 × 10l
45 = 30l
divide both sides by 30
45 / 30 = l
l = 9 / 6 = 3 / 2 meters
length = 3 / 2 meters
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A company uses the graph to show how many packages each truck driver delivers .How many packages will one truck driver deliver in a 7-hour day?
The truck driver would deliver 105 packages in a 7 hours day
What is an equation?An equation is an expression that shows how numbers and variables are related to each other using mathematical operators.
Let y represent the number of packages delivered by the truck driver in x hours. Using the point (1, 15) and (4, 60). Hence, the equation is:
y - 15 = [(60-15)/(4-1)](x - 1)
y = 15x
For a 7 hour day (x = 7):
y = 15(7) = 105
The driver would deliver 105 packages in 7 hours
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in how many ways can the letters of MCHNLRN be arranged
Answer:
2520
Step-by-step explanation:
There are 7 letters in MCHNLRN and they can be arranged into 7 ways:
7! = 5040 ways in total
However, the letter 'N' is repeated so we have to divide it by 2.
5040 ÷ 2 = 2520 ways
Answer:
2,520 ways
Step-by-step explanation:
MCHNLRN has 7 letters with one repetition.
therefore, =7!/2!
=2,520 ways
Two identical gardens are to be weeded, each by a two-person team. Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h. Team B includes two gardeners, either of whom could weed the garden in 3 h. Which team will finish first? Explain.
Step-by-step explanation:
Team A time is 1 garden / ( 1 garden/ 2 hr + 1 garden/4 hr) = 1 1/3 hr
Team B = 1 / ( 1/3 + 1/3) = 1 1/2 hr
Team A wins !
Please help
21. What are the missing coordinates of point Q?
P(0, c)
A.
B.
C.
D.
Session 2-Calculator Allowed
(-2a, 0)
(2a, 0)
(-2a, c)
(2a, c)
Q(?, ?) O
N(2a, 0)
"The correct answer is option A." The missing coordinates of point Q are (a, c/2).We are given the coordinates of points P and N as (0, c) and (2a, 0), respectively. We are also given that point Q lies on the same line as points P, Q, and N. We need to find the missing coordinates of point Q.
Since point Q lies on the same line as P, Q, and N, its x-coordinate must be halfway between the x-coordinates of points P and N. That is, the x-coordinate of Q is:
x-coordinate of Q = (x-coordinate of P + x-coordinate of N) / 2
x-coordinate of Q = (0 + 2a) / 2 = a
So, we know that the x-coordinate of point Q is a.
To find the y-coordinate of point Q, we can use the fact that point Q lies on the same line as point P, which has coordinates (0, c). The equation of the line passing through P and N is:
y - c = (0 - c) / (2a - 0) * (x - 0)
Simplifying this equation gives:
y - c = -c/2a * xy = -c/2a * x + c
Substituting x = a in this equation gives:
y = -c/2a * a + cy = -c/2 + cy = c/2
So, we know that the y-coordinate of point Q is c/2.
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Solve for x -2(2x-4)=4x
Answer:
1
Hope this helps sorry I'm not really good at explaining math, cause when I do nobody understands.
in order to compare the means of two populations, independent random samples of 457 observations are selected from each population, with the following
On solving the provided question, we can say that - 95 confidence interval Z alpha 2 = 1.96, CI = (4.1 , 53.9)
What is the 95 confidence interval Z alpha 2?The z critical value is 1.96 for a test with a 95% confidence level (e.g. = 0.05). The z critical value is 5.576 for a test with a 99% confidence level (for instance, with = 0.01).
Why is Z alpha 2 significant?The two red tails represent the alpha level split by two. Finding the z-score for an alpha level for a two-tailed test is what is meant when a question asks you to determine z alpha/2. The confidence interval may be subtracted from 100% to calculate alpha, which is connected to confidence levels.
for 95% confidence,
\(Z_{\frac{\alpha }{2} }\) = 1.96
CI = (5279 - 5250) ± 1.96\(\sqrt{\frac{140^2}{395} + \frac{210^2}{395} } \\\)
CI = (4.1 , 53.9)
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the square of a number is equal to 6 minus the number find all such numbers
The solutions to the equation \($x^2 = 6 - x$\) are \($x = -3$\) and \(x = 2$.\)
What is square of a number?
The square of a number is the result of multiplying the number by itself. In mathematical notation, the square of a number "\(x\)" is written as "\(x^2\)".
Let's call the number we are looking for "x".
According to the problem statement, we have:
\($$x^2 = 6 - x$$\)
We can rearrange this equation to get:
\($$x^2 + x - 6 = 0$$\)
Now, we can factor the left-hand side of this equation:
\($$(x + 3)(x - 2) = 0$$\)
So, either \($x + 3 = 0$\) or \(x - 2 = 0$.\) Solving for x in each case gives us:
\($$x = -3 \text{ or } x = 2$$\)
Therefore, the solutions to the equation \($x^2 = 6 - x$\) are \($x = -3$\) and \(x = 2$.\)
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g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standar deviation will be needed to achieve a process capability index
Complete Question
A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?
Answer:
The value required is \(\sigma = 0.0133\)
Step-by-step explanation:
From the question we are told that
The upper specification is \(USL = 1.68 \ mm\)
The lower specification is \(LSL = 1.52 \ mm\)
The sample mean is \(\mu = 1.6 \ mm\)
The standard deviation is \(\sigma = 0.03 \ mm\)
Generally the capability index in mathematically represented as
\(Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]\)
Now what min means is that the value of CPk is the minimum between the value is the bracket
substituting value given in the question
\(Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]\)
=> \(Cpk = min[ 0.88 , 0.88 ]\)
So
\(Cpk = 0.88\)
Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2
Now let assuming that
\(\frac{\mu - LSL }{ 3 * \sigma } = 2\)
So
\(\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2\)
=> \(0.08 = 6 \sigma\)
=> \(\sigma = 0.0133\)
So
\(\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }\)
=> \(2\)
Hence
\(Cpk = min[ 2, 2 ]\)
So
\(Cpk = 2\)
So \(\sigma = 0.0133\) is the value of standard deviation required