(a x 10^m)(b x 10^m )

Based on your question, you have a dataset with five observations for two variables and an Excel file named "data14-25.xlsx". You'd like to estimate the regression equation.

In this context, "observations" refer to the data points collected for each of the two variables, and "variables" represent the attributes being measured or analyzed. The estimated regression equation is a mathematical model that describes the relationship between these two variables.

Unfortunately, I cannot access the Excel file you mentioned. However, I can guide you on how to estimate the regression equation using Excel:

1. Open the "data14-25.xlsx" file in Excel.
2. Organize your data with one variable in column A and the other variable in column B.
3. Click on the "Data" tab, then click "Data Analysis."
4. Select "Regression" from the list and click "OK."
5. In the "Input Y Range" box, select the range for the dependent variable (typically the one you want to predict). In the "Input X Range" box, select the range for the independent variable (the predictor).
6. Choose an output range or create a new worksheet for the results.
7. Click "OK."

The output will display the estimated regression equation, represented by the formula ŷ = b0 + b1x, where ŷ is the predicted value of the dependent variable, b0 is the intercept, and b1 is the slope of the regression line.

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a) The probability histogram of pmf for the number of students who show up for a professor's office hour on a particular day is shown below.

b) The probability that at least two students show up = 0.55 and the probability that more than two students show up = 0.25

c) The probability that between one and three students show up = 0.7

d) The probability that the professor shows up = 0.20

First we write the number of students who show up for a professor's office hour on a particular day and their pmf in tabular form.

x        p(x)

0       0.20

1       0.25

2       0.30

3       0.15

4       0.10

The probability histogram of this data is shown below.

The probability that at least two students show up would be,

P(x ≥ 2) = p(2) + p(3) + p(4)

P(x ≥ 2) = 0.30 + 0.15 + 0.10

P(x ≥ 2) = 0.55

Now the probbability that more than two students show up:

P(x > 2) = p(3) + p(4)

P(x > 2) = 0.15 + 0.10

P(x > 2) = 0.25

The probability that between one and three students show up would be:

P(1 ≤ x ≤ 3) = p(1) + p(2) + p(3)

P(1 ≤ x ≤ 3) = 0.25 + 0.30 + 0.15

P(1 ≤ x ≤ 3) = 0.7

And the probability that the professor shows up would be: p = 0.20

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Answer:

x=  16 /20420505

Step-by-step explanation:

Let's solve your equation step-by-step.

5(215)x=16

Step 1: Simplify both sides of the equation.

20420505x=16

Step 2: Divide both sides by 20420505.

20420505x /20420505  =  16 /20420505

x=  16 /20420505

Answer:

up to 5 candy bars

Step-by-step explanation:

Answer:

60

Step-by-step explanation:

119-59 = 60

Answer:

? = h

Step-by-step explanation:

v = lwh

v / wh = lwh / wh

v / wh = l

Hopefully this helped!

Brainliest please?

l=V/w[h]

Hope this helps

The variable "h" belongs in the green box

Answer:

!!!

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

In order to find the number of distinguishable permutations of the group of letters A, A, G, E, E, E, M, we can use the following formula:

The number of permutations = n! / (n1! n2! ... nk!), where n is the total number of objects to be arranged, and n1, n2, ..., nk are the numbers of objects that are identical to one another.

For this problem, we have 7 letters with 2 A's, 3 E's, and 1 G and 1 M letter.

Using the formula above, we can find the number of distinguishable permutations: 7! / (2! 3! 1! 1!) = (7 × 6 × 5 × 4 × 3 × 2 × 1) / [(2 × 1) × (3 × 2 × 1) × (1 × 1) × (1 × 1)] = 2520

Therefore, there are 2520 distinguishable permutations of the group of letters A, A, G, E, E, E, M.

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Answer:

$102

Step-by-step explanation:

The word MODE is a statistical term that refers to the number in a given set of data that occurs the most.

In the above question, we are given the set of data:

$102, $97, $98, $102, $98, $104, $95 and $102

Rearranging, we have:

$95, $97, $98, $98, $102, $102, $102, $104.

The mode cost in the given data set above is the phone cost bill that occurred the most and this is $102.

$102 occurred 3 times in the data set.

Answer: -(x - 2)(x + 2)(y - x)(y + x)

Step-by-step explanation:

Factor the following polynomial completely.

-x2y2 + x4 + 4y2 - 4x2

I assume the polynomial is as follows:

-x^2y^2 + x^4 + 4y^2 - 4x^2

Therefore:

-(x - 2)(x + 2)(y - x)(y + x)

The best answer regarding the effects of carbon monoxide is option c, CO results in less oxygen loading hemoglobin but unloading is not changed.

Carbon monoxide binds up more tightly to the hemoglobin as compared to the oxygen molecules. This reduces the oxygen-carrying capacity of the blood and results in less oxygen loading onto hemoglobin.

However, once oxygen is already bound to hemoglobin, CO does not significantly affect its release or unloading. Therefore, option c is the most accurate statement among the given choices.

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Answer:

\( - 7y(2x + 3y)\)

Step-by-step explanation:

\( - 14xy - 21 {y}^{2} \)

\( = - 7y(2x + 3y)\)

hope this helps

brainliest appreciated

good luck! have a nice day!

The number  \(log_2^3\) is an irrational number.

For given question,

We need to prove \(log_2^3\) is an irrational number.

An irrational number is a real number x that cannot be written as the ratio of two integers.

Assume that \(log_2^3\) is rational.

⇒ \(log_2^3\) = a/b

where a and b are positive integers with no factor in common.

Then  3 = \(2^{(\frac{a}{b} )}\)

or

\(3^b=2^a\)

which is impossible since 3^(b) is odd and 2^(a) is even.

Hence \(log_2^3\) cannot be rational, that is it is irrational.

Therefore,  \(log_2^3\) is an irrational number.

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Answer:

9 years

Step-by-step explanation:

Losing 15 % means 85% remains

  so multiply each year's value by .85 to find the current value

       after 'n'  years it will be  24300 * .85^n

when will it be 5600 ?

    5600 = 24300 * .85^n

     5600/24300  = .85^n  

             now you need to take the log of both sides and solve for 'n'  years

  log ( 5600/24300) / log(.85) = n = 9.031 = ~~ 9 years

It would take the automated car wash 20 hours to wash 120 cars.

What is rate ?

In general, a rate is a measure of how much of something happens within a certain period of time. It can be thought of as a ratio that compares two different units of measurement.

In the context of the problem, the rate at which the automated car wash can wash cars is the number of cars that it can wash per unit of time.

The rate at which the automated car wash can wash cars is 30 cars per 5 hours. To find out how long it would take to wash 120 cars, we can use the formula:

Time = (Number of cars / Rate)

Time = (120 cars / 30 cars per 5 hours)

Time = (120/30) * 5 hours

Time = 20 hours

So it would take the automated car wash 20 hours to wash 120 cars.

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The rate at which the automated car wash can wash cars is 30 cars per 5 hours. To find out how long it would take to wash 120 cars, we can use the formula:

Time = (Number of cars / Rate)

Time = (120 cars / 30 cars per 5 hours)

Time = (120/30) * 5 hours

Time = 20 hours

So it would take the automated car wash 20 hours to wash 120 cars.

Answer:

The time will be 1:00pm(13 hours) at which the degree Celsius will drop down to 8degrees Celsius since the temperature at 12noon was 10 degree Celsius and it is dropping at the rate of 2 degree Celsius.

Answer:

72

2s+3l

Step-by-step explanation:

for first answer,

15×2+ 14× 3 = 30+ 42=72

for second answer,

2 ×s + 3×l

= 2s+3l

The probability that it takes three rolls until the player rolls doubles is 25/216.

The probability of rolling doubles with one roll of two fair six-sided dice is 1/6.

The probability of an event is nothing but a number between 0 and 1, where zero shows the impossibility, and one shows the certainty.

First, determine the probability of rolls to obtain doubles in each roll.

Fails in the first roll:

P = 1 - 1/6 = 5/6

Fails in the second roll:

P = 1 - 1/6 = 5/6

In the third roll, the player rolls doubles, that is,

p = 1/6

Now, the probability of requiring 3 rolls until getting doubles will be:

= 5/6 × 5/6 × 1/6

= 25/216

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Answer: $3.50

Step-by-step explanation:28/8=3.5

=3.50

Answer: h=3.50

Step-by-step explanation:28/8=h. This is the equation because in order to find the answer you must find the unit rate. In order to do so you grab the total cost and than the amount of something and divide them in order to find the answer.

The unknown variables in parallelograms above include the following:

x = 8 units.

y = 27 units.

x = 20°

x = 9°

In Mathematics, a parallelogram simply refers to a geometrical figure (shape) and it can be defined as a type of quadrilateral and two-dimensional geometrical figure that has two (2) equal and parallel opposite sides.

In this context, we have:

2x - 5 = 11

2x = 11 + 5

2x = 16

x = 8 units.

y + 1 = 28

y = 28 -1

y = 27 units.

Generally speaking, the opposite angles of a parallelogram are always congruent or equal and as such, we have the following:

(7x - 1)° = 139°

7x = 139° + 1°

7x = 140°

x = 140/7

x = 20°

For parallelogram b, we have:

(7x - 10)° = (6x - 1)°

7x - 6x = -1 + 10

x = 9°

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Answer:

Step-by-step explanation:

The expressions for the lengths of the segments obtained using vectors notation are;

a. i. \(\overrightarrow{LA}\) = q - (1/2)·p  ii. \(\overrightarrow{AN}\) = (2/7)·(p - q)

b. The expressions for \(\overrightarrow{MN}\), \(\overrightarrow{LA}\), and \(\overrightarrow{AN}\) indicates;

\(\overrightarrow{MN}\) = (1/84)·(46·q - 11·p)

A vector is a quantity that has magnitude and direction and are expressed using a letter aving an arrow in the form, \(\vec{v}\)

a. i. \(\overrightarrow{LA}\) = \(\overrightarrow{BA}\) - \(\overrightarrow{LB}\) =  \(\overrightarrow{BA}\) - (1/2) × \(\overrightarrow{CB}\)

\(\overrightarrow{BA}\) - (1/2) × \(\overrightarrow{CB}\) = q - (1/2)·p

\(\overrightarrow{LA}\) = q - (1/2)·p

ii. \(\overrightarrow{AC}\) = \(\overrightarrow{BC}\) - \(\overrightarrow{BA}\)

\(\overrightarrow{AN}\) = (2/7) × \(\overrightarrow{AC}\)

\(\overrightarrow{AN}\) = (2/7) × \(\overrightarrow{BC}\) - \(\overrightarrow{BA}\)

\(\overrightarrow{AN}\) = (2/7) × (p - q)

b. \(\overrightarrow{MN}\) = \(\overrightarrow{MA}\) + \(\overrightarrow{AN}\)

\(\overrightarrow{MA}\) = (5/6) × \(\overrightarrow{LA}\)

\(\overrightarrow{LA}\) = q - (1/2)·p

\(\overrightarrow{AN}\) = (2/7) × (p - q)

Therefore;

\(\overrightarrow{MN}\) = (5/6) × ( q - (1/2)·p) + (2/7) × (p - q)

\(\overrightarrow{MN}\) = (1/84) × ( 70·q - 35·p + 24·p - 24·q) = (1/84)(46·q - 11·p)

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a) 2.7% of mayflies live at least 26.8 hours.

b) 85% of the mayflies die after approximately 26.2 hours.

a) We can begin by standardizing the value of 26.8 hours:

\(z = \frac{26.8 - 23.7}{1.6} = 1.9375\)

Using a standard normal table or a calculator, we can find that the probability of a standard normal random variable being greater than 1.9375 is approximately 0.027, or 2.7%. Therefore, about 2.7% of mayflies live at least 26.8 hours.

b) We want to find the value of x such that 85% of the mayflies have a lifespan less than x. To do this, we need to find the z-score corresponding to the 85th percentile of the standard normal distribution:

\(z = \text{invNorm}(0.85) \approx 1.04\)

Then we can solve for x:

\(x = \mu + z\sigma = 23.7 + 1.04(1.6) \approx 26.2\)

Therefore, 85% of the mayflies die after approximately 26.2 hours.

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The additional information that could be used to prove that ΔXYZ ≅ ΔFEG by ASA or AAS are:

∠Z ≅ ∠G and XZ ≅ FG

∠Z ≅ ∠G and XY ≅ FE .

The AAS is a theorem that states that we can prove that two triangles are congruent if they have two pairs of congruent angles and a pair of non-included sides.

The SAS is also another theorem that states that we can prove that two triangles are congruent if they have two pairs of congruent sides and a pair of included congruent angles.

From the image attached below, we are only given one pair of congruent angles, which is ∠X ≅ ∠F.

Therefore, for both triangles to be congruent by AAS or SAS, the additional information needed are:

∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE .

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The value of the expression below when x=5x=5?

8x+9 is equal to \(7^{2}\) (or) 49.

Substitute \(\left \{ {{x=5x} \atop {5x=5}} \right. into (8x+9)\)

The expression,

y = 8x + 9

If the domain of the function is x = 5, hence the range of the function is gotten by substituting x = 5 into the given function as shown:

So, we can substitute x = 5,

Then, y = 8 * 5 + 9

Calculate the product or quotient,

y = 40 + 9

Calculate the sum or difference,

y = 49

We can write alternative form,

y = \(7^{2}\)

Therefore,

Hence the value of the expressions if x = 5 is \(7^{2}\) (or) 49.

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The volume of the rectangular package is the amount of space in the package

Let the dimension of the package be x and y.

So, the perimeter (P) and the volume (V) are

P = 4x + y

V = x²y

The maximum perimeter of the box is P.

So, the inequality is:

4x + y ≤ P

Recall that:

P = 4x + y

The perimeter becomes

4x + y = 108

Make y the subject

y = 108 - 4x

Substitute y = 108 - 4x in V = x²y

V = x²(108 - 4x)

Expand

V = 108x² - 432x

Differentiate

V' = 216x - 432

Set to 0

216x - 432 = 0

Add 432 to both sides

216x = 432

Divide by 216

x = 2

Substitute x = 2 in y = 108 - 4x

y = 108 - 4 * 2

Evaluate

y = 100

So, the inequalities are:

x ≤ 2 and y ≤ 100

Using the above inequality, three possible dimensions are: 2 by 100,1 by 104 and 1.5 by 102

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