A white precipitate forms when excess Amonium added

Answers

Answer 1
Question: A white precipitate forms when excess Amonium added

answer : true

Related Questions

In using the Haber process in the formation of ammonia, what mass of hydrogen is needed to produce 51.0 grams of ammonia? 3 H₂(g) + N2 (g) → 2 NH3(g).

Answers

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Determine whether each chemical substance would remain the same color or turn pink in the presence of phenolphthalein.

Answers

Answer:

See the answer below

Explanation:

The complete question can be seen in the attached image.

Phenolphthalein is an indicator that is often utilized in an acid-base reaction to indicate the endpoints of such reactions due to its ability to change color from pink/colorless to colorless/pink depending on if the final solution is acidic or basic.

Phenolphthalein is usually colorless in acidic solutions and appears pink in basic solutions. The more basic or alkaline a solution is, the stronger the pink color of phenolphthalein. Hence;

1. Ammonia with a pH of 11 is basic, phenolphthalein will turn pink.

2. Battery acid with a pH of 1 is acidic, it will remain colorless.

3. Lime juice with a pH of 2 is acidic, it will remain colorless.

4. Mashed avocado with a pH of 6.5 is acidic, it will remain colorless.

5. Seawater with a pH of 8.5 is basic, it will turn pink.

6. Tap water with a pH of 7 is neutral, it will remain colorless

Determine whether each chemical substance would remain the same color or turn pink in the presence of

Phenolphthalein is a chemical compound with the formula\(C_{20}H_{14}O_4\). Phenolphthalein is often used as an indicator in acid-base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions

Phenolphthalein works as in:-

Colorless in acidPink in base

According to the question, There are 5 solutions having different ph and the indication only turns basic solution to pink

The indicator only turn the basic solution pink and these solutions are as follows,

AmmoniaSea waterTap water.

Hence, these are the answer.

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True or False: When the force increases, the speed increases and the distance it travels also increases.

Answers

Answer:

As we increase the force on an object the acceleration increases proportionally. Since the mass does not change as the acceleration increases, we can say that force is equal to acceleration. Therefore, if you double the force you double the acceleration.

Answer:  true?

Explanation:

A 1-L sample of CO initially at STP is heated to 546 K, and its volume is increased to 2 L.

Answers

A 1 L sample of CO initially at STP is heated to 546 K, and its volume is increased to 2 L, the final pressure of CO is 1 atm.

We have,

Initial volume, V₁ = 1 L

Final volume, V₂ = 2 L

Initial temperature, T₁ = 273 K (standard temperature)

Final temperature, T₂ = 546 K

Initial pressure, P₁ = 1 atm

Final pressure, P₂ = ?

To calculate final pressure, we will use combined gas law.

Combined gas law is given as -

                                               P₁V₁ = P₂V₂

                                                 T₁        T₂

where,

P₁ = initial pressure

P₂ = final pressure

V₁ = initial volume

V₂ = final volume

T₁ = initial temperature

T₂ = final temperature

Substituting values in the gas law equation -

1 x 1 = P₂ x 2

273       546

P₂ = 546 x 1 x 1  atm

          273 x 2

P₂ = 1 atm

Therefore, the final pressure of sample of CO at STP is 1 atm.

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what is electron configuration​. dont use googlrl plz

Answers

Answer:

Electron configuration is the structural arrangement notation of electrons in the shells or energy levels of an atom.

Explanation:

\({ \sf{}}\)

Look at the attachment below.

Look at the attachment below.

Answers

Sally is wrong because copper is less electropositive than hydrogen, thus, can not displace hydrogen from dilute acids.

The reactions to prepare copper (ii) chloride are:

the chlo­ri­na­tion of cop­per sul­fide at a high tem­per­a­ture

reaction of copper (ii) oxide with dilute hydrochloric acid

The equations of the given reactions are as follows:CuS + Cl₂ ---> CuCl₂ + SCuO + 2HCl ----> CuCl₂ + H₂O

What are reactive metals?

Reactive metals are metals that readily give up their electrons to form positive ions.

Reactive metals displace hydrogen from dilute acids. They are found in group 1A and 2A of the periodic table. Copper is not a reactive metal and will not displace hydrogen from acids.

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Sally is wrong because copper chloride is not made from the reaction of copper and dilute hydrochloric acid.

2. Copper (ii) chloride can be prepared as follows:

reacting copper (ii) oxide with dilute hydrochloric acidsingle replacement reaction of cop­per sul­fide and chlorine gas at a high tem­per­a­ture

3. the equations of the reaction are:

CuO + 2HCl ----> CuCl₂ + H₂OCuS + Cl₂ ---> CuCl₂ + S

What are single replacement reactions?

Single replacement reactions are reactions in which a more reactive atom replaces another atom in a compound.

An example of a single replacement reaction is the reaction of chlorine gas with copper sulfide at high temperatures to form copper chloride.

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Marine science table 20-2

Marine science table 20-2

Answers

The distance between two consecutive crests or troughs of a wave, particularly in the case of electromagnetic or sound waves, is known as its wavelength.

The wavelength (in nanometers) or frequency of light is used to quantify it (in Hertz). Like with radio waves, they can also be as long as centimetres or metres. It is represented by and inversely proportional to wave frequency.

What distinguishes frequency from wavelength?

Frequency and wavelength are intimately related, particularly in the context of light. Frequency is determined by the number of waves that pass through a single place over a particular period of time, whereas wavelength is the distance between two successive troughs or crests.

The crest of a wave is the part of transverse waves that are above the mean level. The wave's trough is the region of transverse waves that lies below the mean level. The distance between two succeeding crests or troughs is known as the wavelength.

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7. What is the volume of the
composite
solid?
4 in.
3 in.
3 in.

7. What is the volume of thecompositesolid?4 in.3 in.3 in.

Answers

Answer:

The volume of Component 1 is 36 cubic inches.

Explanation:

To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.

In this case, the composite solid consists of multiple components with the following dimensions:

Component 1:

Length: 4 inches

Width: 3 inches

Height: 3 inches

To find the volume of Component 1, we multiply the length, width, and height together:

Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches

Therefore, the volume of Component 1 is 36 cubic inches.

Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.

Assuming a 4.00 litre of a sample gas at 1.00 atm compressed to 0.800 litre at constant temperature. Calculate the final presure of the gas.

Answers

At constant temperature, the final pressure of the compressed gas is 5.0atm.

Given the data in the question;

Initial volume of the gas; \(V_1 = 4L\)Initial Pressure; \(P_1 = 1.0atm\)Final volume; \(V_2 = 0.800L\)

Final pressure; \(P_2 = \ ?\)

Boyle's law

Boyle's law states that the volume V of a given quantity of gas is inversely proportional to its pressure P at constant temperature.

It is expressed as;

\(P_1V_1 = P_2V_2\)

Where \(P_1\) is Initial Pressure, \(V_1\) Initial volume, \(P_2\) is Final Pressure and \(V_2\) is Final volume.

To determine the final pressure of the gas, we substitute our given values into the expression above.

\(P_1V_1 = P_2V_2\\\\P_2 = \frac{P_1V_1}{V_2} \\\\P_2 = \frac{1.0atm \ *\ 4L}{0.800L}\\ \\P_2 = \frac{1.0atm \ *\ 4}{0.800}\\\\P_2 = \frac{4.0atm}{0.800}\\\\P_2 = 5.0atm\)

Therefore, at constant temperature, the final pressure of the compressed gas is 5.0atm

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In one to two sentences, explain how this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.

In one to two sentences, explain how this reaction demonstrates that matter is neither created nor destroyed

Answers

Since the number of atoms which are reacting are equal to the number of to the number of atoms in the product, this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.

What is the principle of matter conservation?

Any system that is closed to all exchanges of matter and energy is subject to the law of conservation of matter, which is a general law of physics and chemistry. This law states that regardless of how the components rearrange themselves, the mass of an object or group of things remains constant over time.

A chemical reaction is what?

A chemical reaction is a procedure that causes one group of chemical components to change chemically into another. Chemical reactions, which can frequently be described by a chemical equation, traditionally include changes that solely affect the locations of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei.

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Q- 30. The number of grams of solute
30:dissolved in 100 grams of solution
is called:30.09
سولیوٹ کی گرامز :
مقدار جو سلوشن کے 100 گرامز د حل
ہو، یہ پرسینٹیج کہلاتا ہے
ماس /ماس Mass
/
Mass
ماس / واليم Mass
/
Volume
والیم /ماس Volume
/
Mass
والیم و البم Volume
/
Volumne​

Answers

Answer:

Mass by mass

Explanation:

Because it's telling only about mass in grams

Put these elements in order of decreasing electronegativity, with the highest electronegative element as number 1.
a. tin (Sn, Group 14, Period 5)
b. rubidium (Rb, Group 1, Period 5)
c. bromine (Br, Group 17, Period 4)
d. lithium (Li, Group 1, Period 2)
e. cadmium (Cd, Group 12, Period 5)

Answers

Answer:the answer is a c and e

Explanation:

4- Calculate the mol fraction of ethanol and water in
a sample of rectified spirit which contains 95% of
ethanol by mass.​

Answers

Answer:

math si hard

Explanation:

The mole fration of ethanol and water in a sample of rectified spirit which contains 95% of ethanol by mass is 0.8 and 0.11.

How do we calculate mole fraction?

Mole fraction of any substance will be calculated by dividing the moles of that substance from the total moles of the solution.

Moles (n) will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given that 95% of ethanol by mass is present in the sample, so 95g of ethanol is present in 100g of solution.

Mass of solvent (water) = 100 - 95 = 5g

Moles of water = 5g / 18g/mol = 0.27mol

Moles of ethanol = 95g / 46g/mol = 2.06mol

Mole fraction of water  = 0.27 / (0.27+2.06) = 0.11

Mole fraction of ethanol = 2.06 / (0.27+2.06) = 0.8

Hence required mole fraction of water & ethanol is 00.11 and 0.8 respectively.

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What mass of sucrose is needed to make 300.0 mL of a 0.5 M solution? (molar mass=
342.34 g/mol)

Answers

i need points i’m sorry but yea lol good luck


Physical and chemical changes occur all around you every day. Read the story below and use the movable
highlighter pieces to highlight the physical changes in PURPLE and the chemical changes in ORANGE.

Physical and chemical changes occur all around you every day. Read the story below and use the movablehighlighter

Answers

The physical changes are:

"blend up a banana smoothie instead"."cut a piece of bread in half"."I cracked two eggs and whipped them with a fork"."water had evaporated"."glass breaking"."Steam was rolling out"."broke off a piece"."the chocolate melted".

The chemical changes are:

"the milk had soured"."was covered in brown spots"."it was completely tarnished"."plants were dying"."toast must be burning"."rusted bicycle".

Changes of matter

Matter can undergo 2 kinds of changes:

Physical changes: matter changes form but not its identity.Chemical changes: matter changes its identity due to a chemical reaction.

Let's consider the following text.

When my alarm went off at 70'clock, I hit snooze" a few times then finally got out of bed with excitement for my morning bowl of cereal. I poured the cereal and milk into my bowl. But before I even drank it, I could tell from the smell that the milk had soured! So, I decided to blend up a banana smoothie instead. I took some ice out of the freezer and grabbed the only banana that we had in the kitchen, which was covered in brown spots. My grumbling stomach needed to be satisfied before school so I didn't really care.

Just as I was sitting down to drink my smoothie my little brother came bounding into the kitchen and asked, Would you make some eggs and toast for me for breakfast?

"Ugh, sure," I said. I cut a piece of bread in half and put it in the toaster, then I cracked two eggs and whipped them with a fork. I reached for one of my mother's copper cooking pans in the cabinet and saw that it was completely tarnished! I didn't want to be blamed for this, so I ran to tell my mother right away. As I ran out of the kitchen slipped on that banana peel and it smeared all over the floor. As I lay on the floor with the wind knocked from me, I noticed that our family's plants were dying and that some water had evaporated from our fish tank. I made a mental note to take care of these things after school.

Just as I regained my breath and stood up, I heard glass breaking upstairs and my mother shrieking. I ran up the stairs, breathing heavily now. Steam was rolling out from the open bathroom door. When the steam cleared, saw why my mother had been screaming. Before me was my older sister standing in the bathroom with purple hair. I inferred from the scene that my mother had dropped a glass when she first saw her look what your sister did to her hair my mother yelled furiously I decided that I needed to get out of the house immediately, this morning was a crazy one!

A distinct smell was waiting up the stairway and I realized that my brother's toast must be burning! When reached the kitchen, my brother was happily spreading butter on his very browned toast. "I like my toast really crispy!" he said.

"Good I can't handle any more chaos this morning! I exclaimed. I grabbed my backpack headed out into the foggy morning air, and hopped on my slightly rusted bicycle to ride to school. A few minutes into my ride, my stomach grumbled and I realized that I never got a chance to drink my banana smoothie. Luckily, I had stashed a chocolate bar in my backpack yesterday. "Yes! I thought as I stopped pedaling, grabbed the chocolate and broke off a piece. As the chocolate melted in my mouth, I knew that my day was bound to get better!

The physical changes are:

"blend up a banana smoothie instead"."cut a piece of bread in half"."I cracked two eggs and whipped them with a fork"."water had evaporated"."glass breaking"."Steam was rolling out"."broke off a piece"."the chocolate melted".

The chemical changes are:

"the milk had soured"."was covered in brown spots"."it was completely tarnished"."plants were dying"."toast must be burning"."rusted bicycle".

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Please need help ASAP

Please need help ASAP

Answers

The effect of table salt and sugar on bubbles is that sugar makes it easier to blow and stronger whereas salt makes it difficult to blow bubbles.

(i) The combination in cup 2 made blowing bubbles simpler since the bubbles lasted longer; nevertheless, when the bubbles struck something, they popped just as easily as the ones in cup 1.

(ii) However, compared to cup 1, the combination in cup 3 made blowing bubbles more challenging.

(iii) Compared to salt, which did not mix well together with liquid dish detergent and made it more difficult to blow huge, forceful bubbles, sugar was an excellent ingredient to mix with liquid dish detergent.

(iv) If we were to carry out this experiment further, we may experiment with other materials in the cups to discover which ones the liquid dish detergent reacted best with. Using cups 4 and 5 for flour and brown sugar and cup 6 for pepper, respectively. Then, we would contrast these combinations with the cups that we had already examined.

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a. Anna's chemistry class is going to be experimenting with AgNO3 today, which
can stain hands and clothes. Anna is concerned about her jewelry, so as she
gets ready for school, she removes her gold (Au) ring andreplaces it with a
cheaper nickel (Ni) ring. Is this a good idea? Explain your answer. (3 points)

Answers

Answer:

No. While gold would not react with a silver nitrate solution, nickel would.

Explanation:

Refer to the metal reactivity series.

Reactivity: \(\text{Gold} < \text{Silver} < \text{Nickel}\).

Gold is positioned after silver in the reactivity series, meaning that gold is typically less reactive than silver. Thus, gold would not react with a solution of silver ions to produce silver metal.

However, since nickel is positioned before silver in the reactivity series, it is expected that nickel would react with silver ions in this solution to produce silver metal.

Thus, if the silver nitrate solution comes into contact with the two rings, the nickel ring would likely react with the solution, the gold ring would not.

What is the mass of reactants in the following equation? N2 + 3H2 ----> 2NH3 Question 3 options: 34.05 amu 31.03 amu 30.02 amu 15.01 amu

Answers

Answer:

34.06amu

Explanation:

The reaction expression is given  as:

          N₂   +   3H₂   →    2NH₃  

We are to find the mass of reactants in the equation given;

  Here:

      Mass of reactants  = 2(atomic mass of N) + 3[ 2 x atomic mass of H]

 Atomic mass of N  = 14.0067amu

 Atomic mass of H = 1.008amu

      Mass of reactants  = 2(14.0067) + 3(2 x 1.008)  = 34.06amu

A platinum solid weighs 175 g. Look up its density and calculate the volume in dm3 this platinum solid occupies.

Answers

The volume of the platinum solid is determined as 8.16 cm³.

Volume of  platinum solid

The volume of the  platinum solid is calculated from its density and mass as shown below.

V = m/ρ

where;

V is the volume of the  platinum solidm is the mass of the  platinum solidρ is the density of the  platinum solid = 21.45 g/cm³

Volume of the platinum solid is calculated as follows;

V = 175 g / 21.45 g/cm³

V = 8.16 cm³

Thus, the volume of the platinum solid is determined as 8.16 cm³.

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Please help!!!
25 points!! I’ll give brainliest!
Task is in the picture.

Please help!!!25 points!! Ill give brainliest!Task is in the picture.

Answers

Answer:

Van't Hoff factor: 3.99

Degree of electrolytic dissociation: 1.995

Explanation:

ΔT = iKfm

Calculate the molality of the K2SO4 solution.

Since the solution is 20% K2SO4, we can assume that we have 20 grams of K2SO4 in 100 grams of solution.

The molar mass of K2SO4 is 174

So, 20 grams of K2SO4 is equal to:

20/ 174 = 0.115 moles of K2SO4

The mass of water in 100 grams of solution is:

100 g - 20 g = 80 g

The density of water is 1 g/mL, so 80 g of water is equal to 0.080 kg of water.

Therefore, the molality of the solution is:

m = 0.115 mol / 0.080 kg = 1.4375 mol/kg

Now, we need to determine the freezing point depression constant of water (Kf). The value of Kf for water is 1.86 °C/m.

ΔT = T°f - T°i = -10 °C - 0 °C = -10 °C

Substituting the given values in the formula for ΔT, we get:

-10 °C = i * 1.86 °C/m * 1.4375 mol/kg

Solving for i, we get:

i = -10 °C / (1.86 °C/m * 1.4375 mol/kg) = 3.99

Finally, we can calculate the degree of electrolytic dissociation (α) using the formula:

α = (i - 1) / (n - 1)

where n is the number of ions produced per formula unit of the solute.

For K2SO4, n = 3, since it dissociates into three ions.

Substituting the values, we get:

α = (3.99 - 1) / (3 - 1) = 1.995

Hence, it is 3.99 and 1.995

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For the K₂SO₄ solution, the Van't Hoff factor (i) is approximately 5. For the 20% K₂SO₄ solution, the degree of electrolytic dissociation (α) is approximately 0.833, or 83.3%.

How to calculate Van't Hoff factor and the degree of electrolytic dissociation?

To calculate the Van't Hoff factor and the degree of electrolytic dissociation, use the freezing point depression equation:

ΔT = Kf · m · i

where ΔT is the change in freezing point, Kf is the freezing point depression constant for the solvent (water), m is the molality of the solution, and i is the Van't Hoff factor.

First, calculate the molality of the solution:

molality (m) = moles of solute / mass of solvent (in kg)

Assuming there is 1 kg of solvent, the mass of solute (K₂SO₄) in 20% solution would be:

mass of solute = 0.2 × 1000 g = 200 g

The molar mass of K₂SO₄ is 174.26 g/mol, so the number of moles of K₂SO₄ in 200 g is:

moles of K2SO4 = 200 g / 174.26 g/mol = 1.148 mol

Therefore, the molality of the solution is:

m = 1.148 mol / 1 kg = 1.148 mol/kg

Next, calculate the change in freezing point (ΔT). Since we know that the solution freezes at -10°C instead of 0°C (the freezing point of pure water):

ΔT = 0°C - (-10°C) = 10°C

The freezing point depression constant (Kf) for water is 1.86 °C/m. Substituting the values into the equation:

10°C = 1.86 °C/m · 1.148 mol/kg · i

Solving for i:

i = ΔT / (Kf · m) = 10°C / (1.86 °C/m · 1.148 mol/kg) = 4.99

Therefore, the Van't Hoff factor (i) for the K2SO4 solution is approximately 5.

The degree of electrolytic dissociation (α) can be calculated using the formula:

α = i / (1 + i)

Substituting the value of i:

α = 5 / (1 + 5) = 0.833

Therefore, the degree of electrolytic dissociation (α) for the 20% K₂SO₄ solution is approximately 0.833 or 83.3%.

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Calculate the number of CO2
molecules ( NCO2
) in 0.0734 mol
of CO2

Answers

Answer:

4.42 x 10^22 molecules

Explanation:

1 mole of CO2 has 6.022 x 10^23 molecules

=> 0.0734 x 6.022 x 10^23 = 4.420148 x 10^22 or 4.42 x 10^22

Calculate the number of moles of ethanol burned.

Calculate the number of moles of ethanol burned.

Answers

The number of mole of ethanol burned, given the various data from the question is 0.17 mole

How do I determine the number of mole?

First, we shall obtain the mass of ethanol burned. This is shown below:

Mass of ethanol before burning = 70.3 gMass of ethanol after burning = 62.5 gMass of ethanol burned =?

Mass of ethanol burned = (Mass of ethanol before burning) - (Mass of ethanol after burning)

Mass of ethanol burned = 70.3 - 62.5

Mass of ethanol burned = 7.8 g

Finally, we shall determin the number of mole of ethanol burned. Details below:

Mass of ethanol burned = 7.8 gMolar mass of ethanol = 46 g/mol Number of mole of ethanol burned =?

Mole = mass / molar mass

Number of mole of ethanol burned = 7.8 / 46

Number of mole of ethanol burned = 0.17 mole

Thus, the number of mole is 0.17 mole

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More accurate dates of the reigns of ancient Egyptian pharaohs have been determined recently using plants
that were preserved in their tombs. Samples of seeds and plant matter from King Tutankhamun’s tomb have
a C-14 decay rate of 9.07 disintegrations/min/g of C. How long ago did King Tut’s reign come to an end?

Please show how to achieve the answer. I do not know how to get the answer of 3350 years. Please explain what equations

Answers

King Tut's reign came to an end at 3350 years ago

Further explanation

Carbon-14 is a radioactive isotope that can decay. This isotope can be used to determine how long ago an organism died by knowing the ratio from 12C to 14C

Can be formulated

\(\tt Nt=No\dfrac{1}{2}^{t/t1/2}\)

Or we can use :

\(t=-\frac{1}{\lambda }\text{ln}\left(\frac{{N}_{t}}{{N}_{0}}\right)\longrightarrow t=-\frac{1}{\lambda }\text{ln}\left(\frac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)\)

The half-life of C-14, 5730 years, so the decay constant :

\(\tt \lambda =\dfrac{\text{ln 2}}{{t}_{1\text{/}2}}=\dfrac{0.693}{\text{5730 y}}=1.21\times {10}^{-4}}\)

Assume the initial C-14 activity was 13.6  disintegrations/min/g of C

\(\tt t=-\dfrac{1}{\lambda }\text{ln}\left(\dfrac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)=-\dfrac{1}{1.21\times {10}^{-4}}\text{ln}\left(\dfrac{9.07}{13.6}\right)=\text{3348}\approx 3350~y\)

the number of moles of solute in a bottle containing 225 mL of 0.220 mol/l sodium sulfide solution is?

Answers

In order to find the answer for this question we will use the Molarity formula, which is:

M = n/v

where

M = molar concentration or molarity in mol/L

n = number of mols

v = volume in Liters

Now using the values given in the question we will have:

0.220 = n/0.225

n = 0.0495 moles of solute

The distances from large bodies of water will affect the average rainfall of an area. (Example: Florida has more rain than Nevada) *10 points
A. True
B. False

Answers

Answer:

A

Explanation:

Use the PhET simulation to identify what happens to the concentrations of a dilute Drink mix mixture or a pure Drink mix solution for the following scenarios. A pure Drink mix solution can be obtained by draining all the mixture, then adding Drink mix to the container as a Solution (radio button in the upper right area of the simulation). Note that the Concentration meter can be placed toward the bottom of the container or in the stream of the Drink mix. Drag the appropriate items to their respective bins.

Answers

Hello user, you did not add a picture of an attachment to enable me help you solve this problem. Please check the attachment I added i believe it is the question that needs to be solved.

Explanation:

1. In the first column

INCREASE CONCENTRATION: these are the items that needs to be placed in this bin

a. Add drink mix solid to a diluted mixture of drink mix in pure water

b. Add drink mix solution to a diluted mixture of drink mix in pure water

c. Add drink mix solid to pure drink mix solution

d Evaporate water from a diluted mixture of drink mix in pure water

e Evaporate water from pure drink mix solution

2. The items below are what should be placed in this bin,DECREASE CONCENTRATION:

a. Add water to a diluted mixture of drink mix in pure water

b. Add water to pure drink mix solution

3. These items here should be placed here. DOES NOT AFFECT CONCENTRATION:

a. Add pure drink mix solution to pure drink mix solution

b. Drain the pure drink mix solution

c. Drain the diluted mixture

Use the PhET simulation to identify what happens to the concentrations of a dilute Drink mix mixture

A student goes through seven class periods in school. Each period lasts 61
minutes. How many hours does he spend in class per week?

Answers

Answer:

35 1/2 hours

Explanation:

61 x 7 = 427, 427 x 5 = 2135

2135 / 60 = 35.58333333333333333

moles of Zn(NO3)2 in 143.50 g of this substance
Express your answer in moles to four significant figures.

Answers

Answer:

0.76 moles

Explanation:

mole = mass ÷ molar mass

mass = 143.50

molar mass = 189.36

189.36÷143.50 = 0.757 = 0.76

The moles of Zn(NO3)2 in 143.50 g of this substance is 0.7578.

What is molar mass?

The molar mass of a substance is defined as the mass of one mole of that substance expressed in grams per mole, which is equal to the mass of 6.022 10 23 atoms, molecules, or formula units.

Molar mass is generally defined as the mass of an Avogadro number of atoms, molecules, or compounds, whereas molecular mass is defined as the sum of all the atomic masses present in the given molecule or compound.

Molecular mass is also referred to as molecular weight. Because the mass is relative to carbon-12, the term "relative molecular mass" is more appropriate.

Molar mass is a related term that refers to the mass of one mole of a sample.

Here, it is given that 143.50 g is the mass of substance.

Mole = mass ÷ molar mass

Mass = 143.50gm

Molar mass = 189.36gm

Mole = 143.50/189.36

Mole = 0.7578

Thus, the answer is 0.7578.

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Hi I hope can make a better deal for you and this is a wonderful

Hi I hope can make a better deal for you and this is a wonderful

Answers

To answer this question we have to find the value of ka, to do it, we can use the value of kb. The product of the kb of a base and the ka of its conjugated base is kw(1x10^-14):

\(\begin{gathered} k_a\cdot k_b=k_w \\ k_a=\frac{k_w}{k_b} \\ k_a=\frac{1\times10^{-14}}{4.38\times10^{-5}} \\ k_a=2.88\times10^{-10} \end{gathered}\)

Now, we have to use the equation of Hendersson and Hasselbach:

\(\)

how do you balance this equation
2h2s+3o2+so2

Answers

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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