a wheel has eight spokes and a radius of 29.5 $cm$. it is mounted on a fixed axle and is spinning at 2.15 $rev/s$. you want to shoot a 22.5 $cm$ long arrow through the wheel, parallel to this axle, without hitting any of the spokes. assume that the arrow and the spokes are very thin and evenly spaced. what minimum speed must the arrow have?

Answer:

A. Piccolo

B. The flute would usually have the highest pitch, but because the piccolo is half the size of a flute, it's higher pitched. The piccolo in C has a range from D5 – C8 which is pretty high pitched. This means that the piccolo's range is an octave above that of the flute.

C. The human ear naturally picks out higher notes, so when piccolos play extremely high, we can hear them more easily than the other instruments in a band or orchestra.

D. I'm sorry but I don't know this one.

Answer:

Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate. In this case, the constant acceleration due to gravity is written as g, and Newton's Second Law becomes F = mg.

Assume an individual has no sodium in their intestinal tract. if this were the case the asorption of   galactose   would be most affected.

Adult insects' gastrointestinal tract epithelium is where nutrients are absorbed because of the exoskeleton. The majority of physiological investigations have described the intestinal absorption of sugar as a diffusional mechanism, and no sugar transporter has been successfully cloned from an insect's digestive system to date. The current investigation makes a convincing case for the existence of a saturable galactose transport system in the gastric caeca of Locusta migratoria.

Galactose absorption is unaffected by changes in pH, the absence of K+, Cl, Mg2+, or Ca2+, either. However, facilitative transporter inhibitors like as phloretin, cytochalasin B, and theophylline reduce sugar uptake by about 50%. The presence of an mRNA coding for at least one equilibrative sugar transporter in the L. migratoria gastric caeca is further supported by the observation that Xenopus laevis oocytes microinjected with poly A+ RNA isolated from gastric caeca show sodium-independent galactose uptake that is three times higher than in non-injected oocytes.

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This statement is True, a gamma ray of wavelength 1.00 × 10–8 cm has enough energy to remove an electron from a hydrogen atom.

Gamma rays are produced in the disintegration of radioactive atomic nuclei and in the decay of sure subatomic particles. The normally ordinary definitions of the gamma-ray and X-ray regions of the electromagnetic spectrum encompass a few wavelength overlap, with gamma-ray radiation having wavelengths which can be usually shorter than a few tenths of an angstrom (10−10 metre) and gamma-ray photons having energies which are extra than tens of hundreds of electron volts (eV).

There's no theoretical top limit to the energies of gamma-ray photons and no decrease limit to gamma-ray wavelengths; located energies currently expand up to 3 trillion electron volts—those extraordinarily excessive-power photons are produced in astronomical sources via currently unidentified mechanisms.

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Answer:

The length of the load arm is 3 m

The length of the effort arm is 15 m

Spoons and scissors are class 1 levers

Explanation:

The data given in the force diagram of the lever (machine) are;

The length of the lever = 18 m = (Length of effort arm) + (Length of load arm)

The force applied at the effort = 100 N

The load lifted by the lever = 500 N

The mechanical advantage, MA is given as follows;

MA = Load/Effort = (Length of effort arm)/(Length of load arm)

∴ MA = 500 N/(100 N) = 5

Let 'x' represent the length of the effort arm, and let 'y', represent the length of the load arm, we have;

x + y = 18...(1) (given)

MA = 5 = x/y

∴ x = 5·y...(2)

Substituting the value of 'x' in equation (1) with x = 5·y gives;

x + y = 5·y + y = 6·y = 18

∴ y = 18/6 = 3

y = 3

The length of the load arm, y = 3 m

x = 5·y = 5 × 3 = 15

x = 15

The length of the effort arm, x = 15 m

When lifting food with a spoon, the fulcrum, which can be taken as the edge of the plate or the supporting finger, is in between bowl of the spoon and the point of application of the thumb towards the extremities of the spoon handle

Therefore a spoon is a class 1 lever

The pivot of a scissors is in between the item being cut (the load) and the holes where the finger applies an effort

Therefore, a scissors is a class 1 lever.

The factor that can have a significant influence on a planet’s surface temperature is its atmosphere.

The atmosphere plays a fundamental role in the Earth planet's temperature because it allows the entry and out of certain types of radiation that may increase the temperature.

The role of the atmosphere in the Earth's temperature is well documented because our temperature is thick and it increases its homeostatic temperature balance.

In conclusion, the factor that alters a planet’s surface temperature is its atmosphere.

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Cis-2-butene can be prepared from propyne, an alkyl halide, and other reagents by carrying out several reactions.

First, the propyne is reacted with an alcohol and a base, such as NaOH, to form an alkyl bromide. Then, this alkyl bromide is heated in the presence of a strong acid such as H₂SO₄ to form cis-2-butene. Finally, the cis-2-butene is separated from the reaction mixture by distillation.

To begin, propyne is reacted with an alcohol and a base, such as NaOH, to form an alkyl bromide. This reaction is called alkylation, and it occurs when a hydrogen atom is replaced by a halide, in this case a bromide.

The alkyl bromide formed is then heated in the presence of a strong acid such as H₂SO₄ to form cis-2-butene. This reaction is known as an E2 reaction, which is a type of elimination reaction.

Finally, the cis-2-butene is separated from the reaction mixture by distillation, where the different components of the mixture are separated based on their different boiling points.

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Answer:

Vf = 11.04 m/s

Explanation:

First, we consider free fall motion with zero initial velocity. Using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height of bridge = ?

Vi = Initial  Speed  = 0 m/s

t = time taken = 4.5 s

g = 9.8 m/s²

Therefore,

h = (0 m/s)(4.5 s) + (1/2)(9.8 m/s²)(4.5 s)²

Therefore,

h = 99.225 m

Now, we consider the forced motion when the youth throws the ball with some negative initial energy:

Vi = - Vi

t = 3 s

h = 99.225 m

Therefore,

99.225 m = - Vi(3 s) + (1/2)(9.8 m/s²)(3 s)²

Vi = (- 99.225 m + 44.145 m)/3 s

Vi = - 18.36 m/s

Now, we use this in 1st equation of motion for final velocity:

Vf = Vi + gt

Vf = -18.36 m/s + (9.8 m/s²)(3 s)

Therefore,

Vf = 11.04 m/s

Answer:

Vector

Explanation:

Vector, in physics, a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude.

Answer:

A particle that has the same charge as lambda baryon is a neutron.

Explanation:

A lambda baryon is a subatomic particle that is made up of three quarks - uds (up, down and strange). It contains the same number of protons and neutrons, and an isotopic spin of 1. It is a family of hadrons just like mesons.

A quark is a fundamental or basic particle that make up a matter. It can combine with two or more to form composite particles (e.g neutron or proton). These basic particles are held by a very strong attractive force. The composite particles are the constituents of the nucleus of an atom.

The particle that has the same electric charge as the lambda baryon is neutron.

The lambda is known to be a baryon that  is composed of three quarks. They are:

The neutron is known to be a kind of subatomic particle that is often written as n or n⁰ . It is known to have a neutral charge and its composition is that of 1 up quark and 2 down quarks.

See full question below

The lambda baryon has the quark composition uds. Which particle has the same electric charge as the lambda baryon?

1. neutron

2 electron

3. proton

4 antimuon

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Answer:

A) weight is determined by the force of gravity.

Answer:

A weight

Explanation:

The answer is weight. That's why someone would weigh more on a different planet, because the planet would have a higher/lower force of gravity.

Answer:

7t

Explanation:

how many washers or paper clips can be picked up by each magnet. The one which picks up the most is the strongest.

-Slowly bring each magnet close to a magnetic material (such as an iron pin). The one which attracts the pin from the farthest distance is the strongest.

-Construct a device such as in class (place a tongue depressor between two plastic cups, place each magnet on top of the tongue depressor, and then suspend a paperclip beneath it to see how many washers each magnet can hold

Answer:

no we can send rovers into space to explore i am reading the martian but this is my opinion it depends on what nasa decides

Explanation:

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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Concave mirrors can create both actual and virtual pictures. Mirrors can be enlarged, shrunk, or the exact size as the item. They can just be upright (if online) or reversed (unless real); front of the glass (unless real); or behind the glass (if virtual).

Convex mirrors are not utilized to focus light since they diverge light rays by reflecting light outward. Virtual, upright, and initially smaller than the item, the image grows to a maximum size equal to the thing as it approaches the mirror. Diverging mirrors are another name for such mirrors.

Spherical mirrors include both concave and convex mirrors.

Property 1: The incoming ray that is perpendicular to the main axis travels through the concave mirror's focus.

Property 2: The incident light will be reflected parallel toward the major axis if it passes through the focus.

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The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

Where:

make v the subject of the equation.

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

Substitute these values into equation 2

Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

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a concentric ring model in which social groupings are spatially organised in a hierarchy of rings. The upper class resides further away from the center, while the lower class is located closer to it.

The concentric ring model operates on the presumption that cultural content results from the incorporation of original ideas into the creation and/or presentation of music, text, and picture, and that these concepts originate in the fundamental artistic creativity spheres. Burgess' concentric ring model concept envisions growth occurring in a series of concentric rings surrounding the concentric ring model . According to Hoyt's sector model, economic expansion follows transportation corridors.

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Answer:

Explanation:

answer: 4 velocity.

if nominal gdp is 1800 and the money supply is 450, then what is velocity?

4 velocity.

If the nominal GDP is 1800 and the money supply is 450, then the velocity of money would be 4.

The total value of goods and services generated in an economy during a given time period, usually a year, is referred to as nominal GDP and is not adjusted for inflation. It depicts what products and services are now selling on the market.

Given:

Nominal GDP, PQ = 1800

Money supply, M = 450

From equation of exchange:

MV = PQ

V = (PQ) ÷ M

V = (1800) ÷ (450)

V = 4

Hence, if the nominal GDP is 1800 and the money supply is 450, then the velocity of money would be 4.

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Answer:

4.5 because just do the math and its 4.5

Answer: the volleyball

Explanation:

The volleyball, in contrast, is full of air, which contains fewer, more widely spaced particles of matter. In other words, the matter inside the bowling ball is denser than the matter inside the volleyball. A bowling ball is denser than a volleyball.

The value that represents the mass of block C that would keep crate D in equilibrium is 196.2 kg (Option D).

To determine of value that represents the mass of block C that would keep crate D in equilibrium, ee can begin by determining the tension in the ropes. Since the crate is held in a certain location by two blocks, the tension in the ropes should be equal. We can use this fact to calculate the tension in the ropes by assuming that they have the same magnitude.

In this case, let T be the tension in each rope segment. The forces acting on the system can be represented in the following free-body diagram:

For the x-direction: T sin 30° = T sin 60° + µg = 0

where µ is the coefficient of friction and g is the acceleration due to gravity. Since the pulleys are frictionless, µ = 0. Therefore, we can simplify the equation as follows:

T sin 30° = T sin 60°

Dividing both sides by T:

sin 30° = sin 60°/2

This gives us: T = (2/√3) mg where m is the total mass of the system and g is the acceleration due to gravity.

Substituting the given values, we obtain:

T = (2/√3) × 150 × 9.81 ≈ 1962 N

Next, we can use the law of the lever to calculate the mass of block C required to keep the crate in equilibrium. According to this law, the sum of the moments acting on the system must be zero. We can choose the point where the ring is attached to the rope as the pivot. This gives us the following equation:

(135 kg)(9.81 m/s²)(3 m) + (mC)(9.81 m/s²)(6 m) - (150 kg)(9.81 m/s²)(4.5 m) - (1962 N)(3 m) = 0

Simplifying: (135)(3) + (6mC) - (150)(4.5) - (1962)(3) = 0

Rearranging: 6mC = 150(4.5) + 1962 - 135(3)

6mC = 2127

mC ≈ 196.2 kg

Therefore, the value that represents the mass of block C required to keep crate D in equilibrium is approximately 196.2 kg. Thus, the correct option is D.

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Answer:

Favorable sites include the tops of smooth, rounded hills; open plains and water; and mountain gaps that funnel and intensify wind. Wind resources are generally more favorable for electricity generation at higher elevations above the earth's surface

Answer: Ionic bonds usually occur between metal and nonmetal ions.

Explanation:

Answer:

796110

Explanation:

(4.81)(1000)+7.913(105)

=4810+7.913(105)

=4810+(7.913)(100000)

=4810+791300

=796110

The resistance of the wire is  3.8 × 10⁻² Ω.

option B.

The resistance of the wire is calculated as follows;

R = ρL/A

Where;

The resistivity of copper at 20°C = 1.77 x 10⁻⁸ Ω·m.

The resistance of the wire is calculated as;

R = (1.77 x 10⁻⁸ Ω·m) x (6.50 m) / (3.0 x 10⁻⁶ m²)

R = 3.8 × 10⁻² Ω

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To find the eigenvalues and eigenfunctions of the operator R, we start by writing out the matrix representation of R in the basis of the states

|1>, |2>, ..., |6>:

markdown:

 R =  |0   1   0   0   0   1 |

      |1   0   1   0   0   0 |

      |0   1   0   1   0   0 |

      |0   0   1   0   1   0 |

      |0   0   0   1   0   1 |

      |1   0   0   0   1   0 |

where we have used the shorthand notation IФn> = |n>.

To find the eigenvalues and eigenfunctions, we solve the eigenvalue equation:

 R|ψ> = λ|ψ>

where λ is the eigenvalue and |ψ> is the corresponding eigenvector.

Let's start by looking for eigenvectors of the form:

 |ψ> = a|1> + b|2> + c|3> + d|4> + e|5> + f|6>

where a, b, c, d, e, and f are complex numbers. Substituting this into the eigenvalue equation, we get:

 |2> = λ|1> + f|6>

 |3> = λ|2> + e|5>

 |4> = λ|3> + d|4>

 |5> = λ|4> + c|3>

 |6> = λ|5> + b|2>

 |1> = λ|6> + a|1>

Solving this system of equations, we find that the eigenvalues are:

 λ = ±1, ±i

and the corresponding eigenvectors are:

 |ψ1> = (1/√6) (|1> + |2> + |3> + |4> + |5> + |6>)

 |ψ2> = (1/√2) (|1> - |4>)

 |ψ3> = (1/√2) (|2> - |5>)

 |ψ4> = (1/√2) (|3> - |6>)

where we have normalized the eigenvectors to have unit length.

Note that the eigenvectors are orthogonal, which means that they form a complete set of basis vectors for the six-dimensional space of states. Any state can be written as a linear combination of these eigenvectors:

 |ψ> = c1|ψ1> + c2|ψ2> + c3|ψ3> + c4|ψ4>

where c1, c2, c3, and c4 are complex coefficients. Therefore, the eigenfunctions of the operator R span the space of the states.

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Answer:

The answer is C. The electromagnetic waves transfer energy.

The electromagnetic waves cause a disturbance in the electric and magnetic field as the electromagnetic waves transfer energy. Thus, the correct option is C.

The electromagnetic radiation (EMR) consists of waves of the electromagnetic (EM) field. These waves propagate through space and carry momentum and electromagnetic radiant energy as well. It includes radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. All of these waves form together different parts of the electromagnetic spectrum.

Electromagnetic waves or the EM waves are waves which are created as a result of vibrations between an electric field and a magnetic field. Electromagnetic waves are composed of oscillating magnetic and electric field lines and transmit energy.

Therefore, the correct option is C.

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Cause it's Corona Time

Answer: D

Explanation: