A water main is to be constructed with a ​% grade in the north direction and a ​% grade in the east direction. Determine the angle required in the water main for the turn from north to east.

Answer:

K= 95.4 J

Explanation:

For this exercise we must use the conservation of mechanical energy.

We set a reference system on the floor.

Starting point. Higher

          Em₀ = U = m g h

Final point. Just before taking the floor

           Em_f = K = ½ m v²

energy is conserved because there is no friction

         Em₀ = Em_f

         mg h = K

The height is

                 h = 0- y₀

let's calculate

       K =  3.23 (-9.81)  (-3.01)          

       K= 95.4 J

The all-or-none law is the principle that states, once the threshold has been crossed, the action potential either fires or it does not. there is no half measure.

The all-or-none law: It is a principle which states that the strength of a response of a muscle fiber or nerve cell is not dependent on the  stimulus strength. If the stimulus is above the certain threshold, a muscle fiber or nerve  will fire.

Essentially, there will be either a full response or no response for an individual muscle fiber or neuron. Therefore action potential is essentially a full response.

There is no thing as a strong or weak action potential. Instead, it is always All-or-nothing process.

This will minimize the possibility of information that will be lost in the way.

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In dragging a table across a rough floor, the potential energy for friction depends on the coefficient of friction, normal force, and distance traveled by the table, hence option (a), (b), and (c) are correct.

In this case, the potential energy for friction would depend on the following quantities:

Coefficient of friction: The coefficient of friction between the table and the floor would determine how much force is required to move the table and hence, the potential energy for friction.

Normal force: The normal force acting on the table due to the weight of the table and any objects placed on it would also affect the potential energy for friction.

Distance moved: The distance the table is moved would determine the amount of work done against friction and hence, the potential energy for friction.

Surface area: The surface area in contact between the table and the floor could also affect the potential energy for friction.

Overall, the potential energy for friction depends on a combination of factors, including the properties of the surfaces in contact, the force required to move the object, and the distance moved.

Therefore correct options are (a), (b), and (c).

Suppose you were dragging a table across a rough floor. in this case, the potential energy for friction depends on which quantity or quantities? (choose all that apply)

a. The total distance the table travels.

c. The coefficient of friction between the table and the floor.

d. The normal force that the floor exerts on the table.

e. There is no potential energy for frictional forces.

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When a new path of lesser resistance is made for an existing circuit a(n) short circuit occurs.

An electrical circuit short circuit is when two nodes that are supposed to be connected at different voltages make an improper connection. This leads to an electric current that can damage circuits, cause overheating, fire, or explosions, and is only constrained by the network's remaining nodes' equivalent Thevenin resistance. While short circuits are typically the result of a failure, they can occasionally be brought on purpose, such as when voltage-sensing crowbar circuit protectors are being installed.

An electrical connection that requires two nodes to have the same voltage is known as a short circuit in circuit analysis. Since there is no resistance and hence no voltage drop across the link in a "perfect" short circuit, there is no short circuit.

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Answer:

the answer is A.) Wedge

A knife to cut a piece of bread is a A. Wedge

A simple machine, any of several devices with few or no moving parts that are used to modify motion and the magnitude of a force in order to perform work.

since , a wedge is a simple machine  with two inclined planes which when put together forms a sharped edge, which forms a triangular shaped tool which can be used to separate portion of  two objects .

hence , a knife to cut a piece of bread is a A. Wedge

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Answer:

W=Px∆T= 21000x12=252.000J

When viewed above the North Pole, the Earth rotates counterclockwise, from west to east. This is also called a prograde rotation.

The Earth rotates around the Sun-also counterclockwise viewed from above the North Pole, clockwise observe from the South Pole-to give us our years. The plane of the Earth's orbit is called the sphere where aureole happens. Because of this direction of rotation, we see the sun rising every day in the east and position in the west.

As we viewed above the earth revolves empty around the sun each year when viewed from above the north pole. We know that the Earth is viewed once in twenty-four hours.

So we can conclude that Earth when seen from the top of the north pole, will be seen revolve in anti-clockwise.

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The wavelength of the standing wave λ = 40cm

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in consecutive cycles.

Its length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

How to solve:

We know the distance between two successive nodes = λ / 2

From the figure distance between two successive nodes = 20 cm

i.e. λ / 2 = 20 cm

∴ The wavelength of the standing wave λ = 40cm

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Astronomers explain the energetic jets that come out of quasars and active galactic nuclei(AGN) in opposite directions in a way that the supermassive black holes' chaotic accretion discs "spit out" jets in directions perpendicular to the disc.

Quasar : A supermassive black hole with a mass between millions and tens of billions of solar masses that is fueled by an extraordinarily bright active galactic nucleus (AGN) and encircled by a gaseous accretion disc is known as a quasar.

An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum.

Hence, astronomers propose that the chaotic accretion discs of supermassive black holes "spit out" jets in directions perpendicular to the disc, explaining the intense jets that emerge from quasars and active galactic nuclei in different directions.

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The magnitude of the net force on the punching bag is 1714N

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For me: WASH OUR HANDS REGULARLY

Answer:

Increase the work being done or decrease the time in which the work is completed

Explanation:

I got it right on the quiz i just took :)

Answer:

a = 2.84 m/s²

Explanation:

Given that,

Net force, F = 2500 N

Mass of the car, m = 880 kg

We need to find the acceleration of the car. Net force is given by :

F = ma

\(a=\dfrac{F}{m}\\\\a=\dfrac{2500\ N}{880\ m/s^2}\\\\a=2.84\ m/s^2\)

So, the acceleration of the car is 2.84 m/s².

The magnitude of the impulse is 0.183 kg·m/s, and the force exerted on the ball by the floor is 1.525 N in the upward direction.

To determine the magnitude and direction of the impulse delivered to the ball by the floor, we can use the principle of conservation of momentum. The impulse is given by the change in momentum of the ball.

The initial momentum of the ball before it hits the floor is given by:

p_initial = m * v_initial

where:

m = mass of the ball = 0.300 kg

v_initial = initial velocity of the ball before it hits the floor

The final momentum of the ball after it rebounds from the floor is given by:

p_final = m * v_final

where:

v_final = final velocity of the ball after it rebounds from the floor

The impulse delivered to the ball by the floor is the change in momentum:

Impulse = p_final - p_initial

Now, let's calculate the magnitudes and directions.

First, let's find the initial velocity of the ball using the height it was dropped from:

h = 1/2 * g * t^2

where:

h = height = 1.75 m

g = acceleration due to gravity = 9.8 m/s^2

t = time of fall

Using the equation above, we can solve for t:

t = sqrt(2 * h / g)

t = sqrt(2 * 1.75 / 9.8) ≈ 0.596 s

The initial velocity is given by:

v_initial = g * t

v_initial = 9.8 * 0.596 ≈ 5.83 m/s

Next, let's find the final velocity of the ball using the rebound height:

Using the equation for potential energy:

m * g * h = 1/2 * m * v_final^2

v_final = sqrt(2 * g * h)

v_final = sqrt(2 * 9.8 * 1.50) ≈ 6.44 m/s

Now we can calculate the impulse:

Impulse = m * v_final - m * v_initial

Impulse = 0.300 * 6.44 - 0.300 * 5.83 ≈ 0.183 kg·m/s

The magnitude of the impulse delivered to the ball by the floor is approximately 0.183 kg·m/s.

To find the force exerted on the ball by the floor, we can use the equation:

Impulse = Force * time

Solving for Force:

Force = Impulse / time

Force = 0.183 / 0.120 ≈ 1.525 N

The force exerted on the ball by the floor is approximately 1.525 N.

Therefore, the magnitude of the impulse is 0.183 kg·m/s, and the force exerted on the ball by the floor is 1.525 N in the upward direction.

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Based on the given data, (a)  the acceleration of the first block is 1.45 m/s² ; (b) the tension in the cord is 5.15 N

To calculate the acceleration of the first block, we know that the tension in the string is same throughout.

Let, T be the tension in the string and a be the acceleration of the system.

Then, 3.55a = T... (i) and, 2.78g - T = 2.78a... (ii)

Multiplying equation (i) by 2.78 and adding to equation (ii),

2.78g - 2.78T + 3.55a * 2.78 = 2.78a + 2.78T5.32a = 2.78g... (iii)

=> a = 2.78g/5.32 = 1.45 m/s²

Therefore, the acceleration of the first block is 1.45 m/s².

To calculate the tension in the cord, putting a = 1.45 in equation (i),

T = 3.55a= 3.55 * 1.45= 5.15 N

Therefore, the tension in the cord is 5.15 N.

Thus, the correct answers are : (a) 1.45 m/s² ; (b) 5.15 N.

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The symbol V in the given equation is explained by the quantity theory of money. Here, V denotes the velocity of money circulation.

The quantity theory of money helps to explain the relationship between the good's price and the money supply. This relationship is explained by the Fisher equation as M×V=P×Y. Here, the total amount of the money or money supply is denoted by M, the velocity of money circulation is denoted by V, the price level is denoted by P, and the real output or real income is denoted by Y.

This theory helps to determine the value of money. This also helps to stop inflation.

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The value of the shunt resistance Rs is calculated to be approximately (1.02 Ω).To convert a galvanometer into an ammeter with a maximum reading value of 500 mA, a shunt resistance (Rs) needs to be added.

The value of the shunt resistance can be calculated using the formula Rs = (RG * IMax) / (IMax - Max), where RG is the internal resistance of the galvanometer, IMax is the maximum deflection current of the galvanometer (15 mA), and Max is the desired maximum current reading of the ammeter (500 mA).

To convert a galvanometer into an ammeter, a shunt resistance is connected in parallel with the galvanometer.

The shunt resistance diverts a portion of the current, allowing the remaining current to flow through the galvanometer.

By choosing an appropriate value for the shunt resistance, the ammeter can be calibrated to measure higher currents.

In this case, the shunt resistance value (Rs) can be determined using the formula Rs = (RG * IMax) / (IMax - Max), where RG is the internal resistance of the galvanometer, IMax is the maximum deflection current of the galvanometer (15 mA), and Max is the desired maximum current reading of the ammeter (500 mA).

Substituting the given values,

we have Rs = (RG * 15 mA) / (15 mA - 500 mA). Simplifying further, Rs = (RG * 15 mA) / (-485 mA).

Rearranging the equation,

we get Rs = - RG * (15 mA / 485 mA). Since RG is given as (RG-59), we substitute it into the equation to obtain Rs = - (RG-59) * (15 mA / 485 mA).

The result of this calculation gives us the value of the shunt resistance Rs, which is approximately 1.02 Ω. Therefore, a shunt resistance of approximately 1.02 Ω should be added in parallel with the galvanometer to convert it into an ammeter with a maximum reading value of 500 mA.

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Answer:

D

Explanation: Given that a student leaves their history classroom and walks 20 meters north to a drinking fountain. Then the student turns and walks 50 meters south to their art classroom.

The distance is a scalar quantity.

The distance = 50 + 20

distance = 70 metres

Therefore, the magnitude of the total distance traveled by the student is 70 metres. Which is option D

In order to convert a temperature from Kelvin to degrees Celsius, we must deduct 273.15 from it, and in order to transfer a temperature from degrees Celsius to Kelvin, we must add 273.15 to it.

The formula T (K) = T (°C) + 273.15 can be used to convert between Celsius and Kelvin. These two temperature units are extremely dissimilar to one another. The temperature is expressed in °C on the Celsius scale, which was created by Anders Celsius. Lord Kelvin created the Kelvin scale, and K stands for the Kelvin unit of temperature.

The unit of measurement for temperature on a Celsius scale or a centigrade scale is Celsius. It is expressed as °C and can represent a range of temperatures or the difference between two temperatures.

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The correct statement regarding potential energy is that "potential energy is the energy that an object has based on its position."

This means that an object has the potential to do work based on its position in relation to other objects or forces. For example, a ball at the top of a hill has potential energy due to its position at the top of the hill, and this potential energy can be converted into kinetic energy as the ball rolls down the hill.

The other statements about potential energy are not true.

Potential energy can be stored and is not immediately converted to kinetic energy.

The potential energy of an object can be determined using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

And finally, an object in motion can still have potential energy, such as a pendulum swinging back and forth.

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The given transformer is a step-down transformer since the primary coil has more loops than the secondary coil. The power of the primary coil is 2,912 W, and assuming no losses, the power of the secondary coil is also 2,912 W.

a.) It is a step-down transformer because the primary has more loops than the secondary.

The primary coil has 497,119 loops, which is greater than the 2,721 loops of the secondary coil. In a step-down transformer, the primary coil has more loops than the secondary coil, resulting in a decrease in voltage from the primary to the secondary.

b.) To determine the power of the primary coil, we can use the formula P = VI, where P is power, V is voltage, and I is current. Given that the primary current is 52 A and the primary voltage is 56 V:

Power of the primary coil (P) = 56 V * 52 A = 2,912 W.

c.) Assuming no losses, the power of the secondary coil is equal to the power of the primary coil. Therefore, the power of the secondary coil is also 2,912 W.

d.) The voltage in the secondary coil can be calculated using the turns ratio of the transformer. The turns ratio is given by the equation: Turns ratio = Number of turns in the secondary coil / Number of turns in the primary coil. In this case:

Turns ratio = 2,721 / 497,119 ≈ 0.00548.

Therefore, the voltage in the secondary coil is:

Voltage in the secondary coil = Turns ratio * Primary voltage = 0.00548 * 56 V ≈ 0.307 V.

e.) To calculate the current in the secondary coil, we can use the equation I = P / V, where I is current, P is power, and V is voltage. Assuming no losses, the power of the secondary coil is 2,912 W, and the voltage is 0.307 V:

Current in the secondary coil (I) = 2,912 W / 0.307 V ≈ 9,481 A.

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The initial horizontal velocity of the projectile is 22.1 m/s.

The given parameters;

The time of motion of the object is calculated as follows;

h = ut + ¹/₂gt²

where;

h = ¹/₂gt²

\(t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 25}{9.8} } \\\\t = 2.26 \ s\)

The initial horizontal velocity of the projectile is calculated as follows;

R = vₓt

\(v_x = \frac{R}{t} \\\\v_x = \frac{50}{2.26} \\\\v_x = 22.1 \ m/s\)

Thus, the initial horizontal velocity of the projectile is 22.1 m/s.

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The body's response to a cold involves various immune cells and processes. Here is a simplified flow chart depicting the step-by-step response:

This flow chart demonstrates the coordinated response of B cells, helper T cells, macrophages, mucus production, lymph, cytokines, receptor proteins, antibodies, memory cells, and plasma cells in combating a cold virus and eventually eliminating it from the body.

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A 2.0-kilogram cart traveling at a constant speed in a horizontal circle of radius 3.0 meters. The magnitude of the centripetal force of the cart is 24 newtons. The speed of the car is 6 m/s. Thus, Option A is the correct answer.

To find the speed, the given values are,

Mass m = 2 Kg

Radius r =3 meters

Centripetal force = 24 Newtons.

A centripetal force is the force which is made up of two Latin words centrum which means center and peterum which means to seek.

It is defined a force which make a body to follow a curved path. The direction of this force is always orthogonal to the body's motion and it is always towards the fixed point which is instantaneous center of the path's curvature.

Centripetal force is expressed according to the formula;

F = mv²/r

m is the mass of the body

v is the speed of the cart

r is the radius

Substituting the values into the formula and get v,

24 = 2v²/3

24×3 = 2v²

72 = 2v²

v² = 72/2

v² = 36

v =√36

v = 6m/s

Hence, the speed of the cart is 6m/s. Thus, Option A is the correct answer.

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The correct option is d. -2.738 V.

We know that, E°cell = E°cathode – E°anodeIn this question, we need to calculate the potential of an aluminum electrode immersed in 0.05 M KOH solution saturated with Al(OH)3. Let us consider the half-reactions occurring at the cathode and anode.2Al(OH)3(s) + 6OH-(aq) ⇌ 2[Al(OH)6]3-(aq) (cathode)Al(s) + 3OH-(aq) ⇌ [Al(OH)3]-(aq) + 3e- (anode). On balancing the above reactions we get:2Al(OH)3(s) ⇌ Al(s) + 3[Al(OH)4]- (aq) + 3OH-(aq). By applying the Nernst equation, we get: For cathode: E°cathode = 0V (Since it is given that Al(OH)6 is saturated). For anode: E°anode = - (0.0592/3) log10{([Al(OH)4]-]^3/[Al][OH^-]^3)}E°anode = - (0.0592/3) log10{([Al(OH)4]-]^3/[OH^-]^3}E°anode = - (0.0592/3) log10(1.8 × 10^-12)E°anode = 1.076V. On substituting the values of E°cathode and E°anode in the formula of E°cell, we get E°cell = E°cathode – E°anodeE°cell = 0 - 1.076 VE°cell = -1.076 V. We know that the potential of the electrode is equal to the standard potential of the electrode plus the electrode potential calculated from the Nernst equation. potential of the aluminum electrode = -1.662 + (-1.076) = -2.738 V. Therefore, the correct option is d. -2.738 V.

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Answer:

The distance traveled by the man during the acceleration is 1186.32 meters

Explanation:

The initial velocity of the man = 40 m/s

The added acceleration rate of the man to outrun = 2.5 m/s²

The time of acceleration = 12 seconds

The relevant kinematic equation of motion is given as follows;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the car the man is driving = 40 m/s

t = The time of travel during acceleration of the car the man is driving = 12 seconds

a = The acceleration by the man to outrun the cops = 2.5 m/s²

s = The distance traveled by the man during the acceleration

Substituting, gives;

s = 40 × 12 + 1/2 × 9.81 × 12² =  1186.32

The distance traveled by the man during the acceleration = s = 1186.32 m.

Answer:

20

Explanation:

W = F*d

400 = 20*d

d = 20

The current in each loop of the solenoid is 6.25 A. current is placed inside the solenoid, we can assume that the current passing through each loop is the same.

The solenoid is 17 cm long and has 800 loops of wire. Since the wire carrying the 5.0 A current is placed inside the solenoid, we can assume that the current passing through each loop is the same.

To find the current in each loop, we can use the formula:

I_solenoid = N * I_wire

Where:

I_solenoid is the current in the solenoid,

N is the number of loops,

I_wire is the current in the wire.

Plugging in the values, we have:

I_solenoid = 800 * I_wire

5.0 A = 800 * I_wire

Solving for I_wire, we get:

I_wire = 5.0 A / 800 = 0.00625 A

Therefore, the current in each loop of the solenoid is 6.25 A.

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The tangental acceleration of the flywheel of  radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².

This is the rate of change of tangental velocity of an object in circular motion.

To calculate the tangental acceleration, we use the formula below.

Formula:

Where:

From the question,

Given:

Subsitute these values into equation 1

Hence, The tangental acceleration of the flywheel of  radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².

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