A uniform thin rod of length 0.17 m and mass 4.1 kg can rotate in a horizontal plane about a vertical axis through its center. The rod is at rest when a 4.9 g bullet traveling in the rotation plane is fired into one end of the rod. As viewed from above, the bullet's path makes angle 60 degrees with the rod. If the bullet lodges in the rod and the angular velocity of the rod is 11.0 rad/s immediately after the collision, what is the bullet's speed just before impact?

Constant couple moment with magnitude is 2.24rad/s.

Kinetic Energy and work:

Since the weight of the links is negligible and the crate and the platform undergo curvilinear translation, the kinetic energy of the system is

T = 1/2mv² = 1/(200/32.2)v²

T = 3.1056v²

Since the system is initially at the rest T₁ = 0. Bx, By, Dx, and Dy does no work while M does positive work and W does negative work. When θ =60, W displaces upward through a distance of h = 4sin60 ft = 3.464ft. Thus, the work done by M and W is

UM = mθ = 900(Π/3) = 300Π ft.lb

UW = - Wh = -200(3.464) = -692.82ft.lb

Principle of Work and Energy

T1 + Σ U1-2 = T2

0 + [300Π - 692.82] = 3.1056v²

v = 8.966ft/s

Thus,

wab = wcd = v/ρ = 8.966/4 = 2.24rad/s

Thus the moment with magnitude is 2.24rad/s.

Learn more about couple moment here:

https://brainly.com/question/2759397

#SPJ4

Answer:theory

Explanation:

The airspeed of the plane can be any positive value.

To solve this problem, let's assume the airspeed of the plane is denoted by V (in km/hr). We need to find the value of V.

When the plane flies from city A to city B, it is flying against a headwind. The effective ground speed of the plane is reduced by the speed of the headwind. Given that the headwind has a velocity of 65 km/hr, the ground speed of the plane from A to B is (V - 65) km/hr.

On the return trip from city B to city A, the wind velocity is unchanged. Since the plane is now flying with the wind, the effective ground speed of the plane is increased by the speed of the wind. Therefore, the ground speed of the plane from B to A is (V + 65) km/hr.

We are given that the trip from B to A takes less time than the trip from A to B. This means that the ground speed from B to A is greater than the ground speed from A to B. Mathematically, we can express this as:

(V + 65) > (V - 65)

Simplifying the inequality, we get:

V + 65 > V - 65

130 > 0

For more such questions on airspeed visit:

https://brainly.com/question/27093584

#SPJ8

When a body is positively charged, it implies that there is positive as well as negative charge in the body but the positive charge is more than negative charge.

Most of the materials that make up our world are composed of atoms, which are made up of a nucleus containing protons and neutrons surrounded by electrons. When an atom loses or gains electrons, it becomes positively or negatively charged, respectively. This is because the number of protons in an atom, which determines its atomic number and chemical properties, does not change.

When there are more protons than electrons, the atom becomes positively charged, and when there are more electrons than protons, it becomes negatively charged.Positive charge is the property of a material that has lost one or more electrons and therefore has more protons than electrons. Positive charges repel other positive charges, while negative charges attract positive charges.

To know more about neutrons visit:

https://brainly.com/question/31977312

#SPJ11

The term cell is incorrect because, the average voltage of a cell is 3.40 V and as already mentioned in question, the volt of source is 18 V, so cell couldn't be the appropriate word, actually the source is battery.

Now, the source is most likely related to cell because a battery which is the source here, is made up of a "group of cell".

Knowing the acceleration, distance and initial velocity of a body, its final velocity is 100 m/s.

The final velocity of a body with uniform acceleration can be calculated using the formula:
Vf² = Vi² + 2aΔx

Where Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and Δx is the change in distance.

Plugging in the given values:
Vf² = (60m/s)² + 2(10m/s²)(320m)
Vf² = 3600m²/s² + 6400m²/s²
Vf² = 10000m²/s²
Vf = √(10000m²/s²)
Vf = 100m/s

Therefore, the final velocity of the body is 100m/s.

See more about  final velocity at https://brainly.com/question/25905661.

#SPJ11

To calculate the amount of time the clock ran, we can use the formula

time = charge / current

where charge is measured in coulombs (C), current is measured in amperes (A), and time is measured in seconds (s).

Given that the clock moved 10,700 C of charge at a rate of 0.490 mA, we can plug these values into the formula

time = 10,700 C / (0.490 mA / 1000) A

We convert the current from mA to A by dividing by 1000, since 1 A = 1000 mA.

time = 10,700 C / 0.490 A = 21857.142857142857 s

So the clock ran for approximately 21857.14 seconds or around 6.1 hours.

Learn more about :  clock battery
https://brainly.com/question/30189382

The maximum allowable current through the three resistors is approximately 2.47 Amperes.

To determine the maximum allowable current through each resistor, we can use the formula:

I = sqrt(P / R)

where I is the current, P is the power, and R is the resistance.

Given:

r1 = 5 ohms

r2 = 3 ohms

r3 = 6 ohms

p(1n) = 20 watts

p(2n) = 27 watts

p(3n) = 24 watts

For resistor 1 (r1):

I1 = sqrt(p(1n) / r1) = sqrt(20 / 5) = sqrt(4) = 2 Amperes

For resistor 2 (r2):

I2 = sqrt(p(2n) / r2) = sqrt(27 / 3) = sqrt(9) = 3 Amperes

For resistor 3 (r3):

I3 = sqrt(p(3n) / r3) = sqrt(24 / 6) = sqrt(4) = 2 Amperes

Therefore, the maximum allowable current through each resistor is 2 Amperes for r1 and r3, and 3 Amperes for r2.

The maximum allowable current through the resistors is 2 Amperes for r1 and r3, and 3 Amperes for r2 based on the given power and resistance values. It is important to ensure that the actual current through the resistors does not exceed these values to prevent damage to the resistors or the circuit.

To know more about current, visit:

https://brainly.com/question/1100341

#SPJ11

The pressure exerted by the reflected wave is \(1.25 * 10^-^9 Pa\).

To calculate the pressure exerted by the reflected wave, we can use the formula P = (2I)/c, where P is pressure, I is the intensity of the wave, and c is the speed of light.

The intensity can be found using the equation I = (1/2)ε_0c\(E^2\), where ε_0 is the electric constant, c is the speed of light, and E is the electric field amplitude.

Since the wave is linearly polarized, we know that the electric field amplitude is equal to the magnetic field amplitude, so E = Bc.

Plugging in the values given in the question, we find that I = \(6.25 * 10^-^1^5 W/m^2\), and therefore P = \(1.25 * 10^-^9\) Pa.

For more such questions on pressure, click on:

https://brainly.com/question/28012687

#SPJ11

The magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

The magnetic field strength is found as;

\(B = \frac{\mu_0I}{2r} \\\\ \mu_0 = 4 \PI \times 10^{-7}\)

In the formula,I denote current, and r denotes the distance between the point and the current carrying wire and magnetic field due to current in the bottom wire.

At point 1, the net magnetic field is found as the sum of magnetic field due to current in the top wire.

\(\rm B_{net} = B1_+(-B_2)\)

\(B = \frac{ 4 \PI \times 10^{-7}I}{2r} \\\\ \rm B_{net} = B_1_+(-B_2)\\\\ \rm B_{net} = \frac{4 \times \pi \times 10^{-7} \times 10}{2 \times \pi \times 0.02} -\frac{4 \times \pi \times 10^{-7} \times 10 }{2 \times \pi \times 0.06} \\\\\ \rm B_{net} = 6.67 \times 10^{-5} T\)

Hence, the magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.

To learn more about the strength of induced magnetic field, refer:

https://brainly.com/question/2248956

#SPJ4

Answer:

0.466 (3 sig. fig.)

Explanation:

Frictional force acting on the box = 5.00×10^2xsin25

Normal force acting on the box = 5.00×10^2xcos25

coefficient of friction = 0.466 (3 sig. fig.)

The Kelvin scale is also called absolute zero scale

Explanation:

true

The wave that is the largest in the electrocardiogram is the R wave.

In electrocardiography, R wave is the most substantial upward deflection in the QRS complex, which is the primary waveform complex that shows ventricular depolarization on an electrocardiogram (ECG). The R wave represents the earliest phase of ventricular depolarization in the cardiac cycle. Furthermore, the amplitude of the R wave varies depending on the individual's heart size, age, and sex, as well as the ECG machine's gain settings. The R wave's normal amplitude varies between 5 and 30 millimeters in a standard ECG recording.

Apart from the R wave, the Q wave and S wave are also part of the QRS complex, which represents ventricular depolarization. The Q wave, which is the first downward deflection after the P wave, is typically small and narrow. The S wave, which is the second downward deflection in the QRS complex, is also typically small and narrow.

learn more about electrocardiogram  here

https://brainly.com/question/11431788

#SPJ11

True

The helium-neon lasers most commonly used in student physics laboratories have average power outputs of 0. 250 mw

Intensity of laser beam is 72.3W/m²

Given:

average power output = 0. 250 mw

To Find: intensity of laser beam

First of all, we need to find the area of the circular spot, which is given by:

A = πr^2

where r is the radius of the spot, which is half the diameter, therefore

r = d/2 = 2.10mm/2 = 1.05mm = 1.05 x 10^-3m

So, the area of the spot is

A = π(1.05 10^-3m)^2 = 3.46 10^-6m²

We know that the power output of the laser is

P = 0.250mW = 2.5.10^-4W

So the intensity of the laser beam is

I = P/A = 2.5^-10 W/3.46-10^-6m^2 = 72.3W/m²

So, intensity of laser beam is 72.3W/m²

To learn more about intensity visit:

https://brainly.com/question/17583145

#SPJ4

Answer:

the answer is 2,3,1 then 4 my bio teacher said this was correct

Explanation:

The eardrum is the thin piece of tissue which is present between the outer and middle ear. This is responsible for the hearing capacity of an individual.

The eardrum, middle ear, cochlea, and pinna are important parts of the Ear. The eardrum is a thin piece of tissue which separates the outer and middle ear. Damage to this eardrum may harm hearing capacity. Mastoiditis is an infection of the bony air cells which are present in the mastoid bone, that is located just behind the ear.

Middle ear has three tiny bones including the malleus, incus and stapes.  These bones transfer sound vibrations from eardrum to the inner ear.

The cochlea is a hollow, spiral-shaped bone which is found in the inner ear that plays a key role in the sense of hearing and it also participates in the process of auditory transduction. Sound waves are transduced into electrical impulses which the brain can interpret as individual frequencies of sound.

The auricle or pinna is the visible portion of the outer ear. It is responsible for collecting the sound waves and channels them into the ear canal, where the sound is amplified.

Learn more about Ear here:

https://brainly.com/question/29255597

#SPJ1

Using ohms law

\(\\ \sf\longmapsto \dfrac{V}{I}=R\)

\(\\ \sf\longmapsto R=\dfrac{1.8}{0.5}\)

\(\\ \sf\longmapsto R=3.6\Omega\)

Let us find first the forces at 1, 2 & 3 points.

We know that ke= 8.99 * 109N.m2 / C2

The forces are: -

F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2

F1 = 359.6 N

F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2

F2 = 29.96 N

F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2

F3 = 269.7 N

Now,

The net force on q1 is F1 – F2,

i.e. F1 + F2 = 359.6 + 29.96

F(q1) = 389.56 N to the left

To learn more about Coulomb’s Law:

https://brainly.com/question/66110

#SPJ1

1. If the plug is moved from one position to another, the frequency of the standing wave remains constant.

2. If the plug is moved to a position where the distance between nodes or antinodes decreases, the wavelength of the standing wave will decrease.

3. The wave speed of the standing wave will remain constant regardless of the position of the plug.

As the plug is moved from one position to another in a system where a standing wave is formed, several changes occur in the standing wave frequency, wavelength, and wave speed:

1. Standing wave frequency: The frequency of a standing wave is determined by the vibration frequency of the source that creates the wave. Therefore, if the plug is moved from one position to another, the frequency of the standing wave remains constant as long as the source frequency remains the same. The movement of the plug does not directly affect the frequency of the standing wave.

2. Standing wave wavelength: The wavelength of a standing wave is determined by the distance between two consecutive nodes or antinodes. When the plug is moved, the position of nodes and antinodes may change, affecting the wavelength of the standing wave. If the plug is moved to a position where the distance between nodes or antinodes increases, the wavelength of the standing wave will also increase. Conversely, if the plug is moved to a position where the distance between nodes or antinodes decreases, the wavelength of the standing wave will decrease.

3. Wave speed: In a medium, the wave speed is determined by the properties of the medium, such as its density and elasticity. The movement of the plug does not directly change the properties of the medium, so it does not affect the wave speed. As long as the medium remains the same, the wave speed of the standing wave will remain constant regardless of the position of the plug.

It's important to note that the specific changes in the standing wave frequency, wavelength, and wave speed will depend on the details of the system and the nature of the wave being generated.

To know more about frequency here

https://brainly.com/question/22982188

#SPJ4

Answer:

With a vector, however, the sign simply tells you about the direction of the vector. If you're travelling with a velocity of 20 km/hr east, it means you're travelling east, and your speed is 20 km/hr.

If the resistance remains constant and the voltage doubles, the power will increase by a factor of 4 (option E)

The following data were obtained from the question:

P = V² / R

Resistance is constant, we have

V₁² / P₁ = V₂² / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

From the above, we can conclude that the power will increase by a factor of 4 (option E)

Learn more about electrical power:

https://brainly.com/question/23850602

#SPJ1

I = present t = time One electron has a charge of e = 1.602 1019 C. If the current fed to the screen is constant, the total quantity of charges passing a cross-section will amass on a television in 5.0 seconds.

Electric Power where V = Current difference, R = Resistance, and I = current, electrical power is the rate wherein electric power is converted into other types of energy. 1.136 x 10 18 electrons pass through the electric lightbulb in one second.

2.25 1022 electrons would travel via the wire, to give the operative response. (b) Disburse the cathode and anode products employing Ag electrodes to electrolyze an AgNO₃ solution.

To know more about Electric Power visit :

https://brainly.com/question/29199566

#SPJ1

Answer:

Saltaions :)

Explanation:

TELL ME IF I AM WRONG

The moment of inertia about the b-b' axis is 24.6E6 mm^4.

To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.

We are given that the moment of inertia of the shaded area about the A-A' axis is

and that the area of the shaded region is

We are also given the distances

which correspond to the distances of the two particles in the shaded region from the B-B' axis.

The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.

Learn more about Moment of Inertia here:

https://brainly.com/question/14460640

#SPJ4

Complete Question:

If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?

Given: A6E3 mm², ds-50 mm, d₂-10 mm

a. none of these answers

B. 21.2E6 mm^4

C  25.2E6 mm^4

D. 26.3E6 mm^4

E. 24.6E6 mm^4

The focal length is negative, the lens is a diverging lens.

The magnification formula for a thin lens is given by:

magnification = -image distance / object distance

where negative sign indicates that the image is inverted.

For a projector, the image distance is equal to the distance between the lens and the screen, which is 8.65 m. The magnification is given as 6, so we have:

6 = -8.65 / object distance

Solving for the object distance, we get:

object distance = -8.65 / 6 = -1.442 m

Since the object is located in front of the lens, the object distance is negative.

The lens equation is given by:

1/focal length = 1/object distance + 1/image distance

We know the image distance (8.65 m) and the object distance (-1.442 m), so we can solve for the focal length:

1/focal length = 1/(-1.442) + 1/8.65

1/focal length = -0.691

focal length = -1.447 m

Since the focal length is negative, the lens is a diverging lens.

Learn more about lens here:

https://brainly.com/question/29834071

#SPJ11

Answer:

¨ Occluded fronts¨

Explanation:

¨usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.¨.

The potential energy of the system is 0.2352 joules.

The system is released from rest, this potential energy is converted into other forms of energy, such as kinetic energy and possibly some amount of energy dissipated as heat or sound due to friction or air resistance. The potential energy of the system is 0.2352 joules.

To address the scenario you described, we have a system consisting of two paint buckets connected by a lightweight rope. The system is initially at rest, with one bucket above the other. The mass of the bucket that is higher is 12.0 kg, and it is 2.00 m above the floor.

Based on this information, we can calculate the potential energy of the higher bucket using the formula:

Potential Energy (PE) = mass * acceleration due to gravity * height

PE = 12.0 kg * 9.8 m/s² * 2.00 m

PE = 235.2 joules

The potential energy represents the energy stored in the system due to its position. In this case, it is the energy associated with the higher bucket being above the floor.

As the system is released from rest, this potential energy is converted into other forms of energy, such as kinetic energy and possibly some amount of energy dissipated as heat or sound due to friction or air resistance.

Therefore, the potential energy of the system is 0.2352 joules.

learn more about potential energy on

https://brainly.com/question/9349250

#SPJ11

Complete question is here

A system of two paint buckets connected by a lightweight rope is released from rest with 12.0 kg bucket 2.00 m above the floor. Use the principle of conservation of energy to find the speed with which this bucket strikes the floor. You can ignore friction and mass of the pulley.

Answer:

Subscribe my Gaming channel Sameer Duos

Explanation:

Generally, a seismograph consists of a mass attached to a fixed base. During an earthquake, the base moves and the mass does not. The motion of the base with respect to the mass is commonly transformed into an electrical voltage. The electrical voltage is recorded on paper, magnetic tape, or another recording medium.