a uniform rope of weight 50 n hangs from a hook as shown above. a box of weight 100 n hangs from the rope. what is the tension in the rope?

Answer:

See below

Explanation:

At the rope end where Cliff is :

W = f x d  

    100 N * 18 = 1800 J   of work input

13.)    At the weight end

          work done = f x d

                             = 500 N * 3 m = 1500 J    of work output

Cliff  only got 1500 J of work OUTPUT with 1800 J of work INPUT

    1500 / 1800 = 83.33 efficiency

If the distance between two objects is 4.00 m and the distance is tripled, then the new distance will be 12.00 m.

To find out the new distance, you need to multiply the original distance by the factor by which it is tripled, which is 3.In other words, if the distance between two objects is "d", and it is tripled, then the new distance is 3d.

Using this formula, if the original distance is 4.00 m, then the new distance will be 3 x 4.00 m = 12.00 m.

The new distance is three times the original distance.

Therefore, the new distance between the two objects will be 12.00 meters if the original distance was 4.00 meters and it was tripled.

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The law of conservation of matter and the law of conservation of energy essentially state that neither type of energy can be created nor destroyed, only transformed. The process by which grapes ferment to produce wine is an illustration of the law of conservation of matter. The amount of matter in the reactants in the bottle doesn't change, but its chemical form does.

It is a fundamental tenet of classical physics that matter cannot be created or destroyed in an isolated system; rather, it can only be changed from one form to another. This means that despite the apparent changes that are seen, no matter is lost during any chemical or physical change that may occur with any substance.

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Answer:

thermal energy

Explanation:

A tennis ball is thrown vertically upwards at 29 m/sec from a height of 80 m above the ground  time cannot be negative, we discard t = 0 and conclude that it takes approximately 5.92 seconds for the tennis ball to hit the ground.

To determine the time it takes for the tennis ball to hit the ground, we can use the kinematic equation for vertical motion:

h = ut + (1/2)gt²

Where:

h is the initial height (80 m)

u is the initial velocity (29 m/s)

g is the acceleration due to gravity (-9.8 m/s²)

t is the time

We want to find the time it takes for the ball to hit the ground, which means the final height will be 0.

0 = (29)t + (1/2)(-9.8)t²

This equation represents a quadratic equation in terms of t. We can solve it by rearranging and factoring:

(1/2)(-9.8)t² + 29t = 0

Simplifying further:

-4.9t² + 29t = 0

Now, we can factor out t:

t(-4.9t + 29) = 0

This equation will be true when either t = 0 or -4.9t + 29 = 0.

From -4.9t + 29 = 0, we can solve for t:

-4.9t = -29

t = -29 / -4.9

t ≈ 5.92 s

Since time cannot be negative, we discard t = 0 and conclude that it takes approximately 5.92 seconds for the tennis ball to hit the ground.

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Answer:

The mass of the space probe on Ganymede is 126 kg, and its weight is 180.2808 N.

Explanation:

The force of gravity, g, on the earth is 9.8 m/\(s^{2}\).

The gravitational force on Ganymede = 0.146 × g

                                                               = 0.146 × 9.8

                                                               = 1.4308 m/\(s^{2}\)

The gravitational force on Ganymede is 1.4308 m/\(s^{2}\).

Mass of space probe on Earth is 126 kg.

Weight of the space probe on Earth = m × g

                                                = 126 × 9.8

                                                = 1234.8 kgm/\(s^{2}\)

Weight of the space probe on Earth is 1234.8 N.

Since mass is constant, the mass of the space probe on Ganymede is 126 kg.

Weight of the space probe on Ganymede = m × g

                                                     = 126 × 1.4308

                                                    = 180.2808 kgm/\(s^{2}\)

Weight of the space probe on Ganymede is 180.2808 N.

Answer:

126 kg

Explanation:

Mass is a constant for a body, and does not change with location.

Answer:

False

Explanation:

Larger pulse with more energy means that the wave has large amplitude. As in the given question, both the waves are travelling in the same medium, hence their speeds will remain same and therefore the larger pulse will not overtake the smaller pulse. Remember the amplitude of a wave does not affect the speed at which the wave travels

Answer:

False

Explanation:

The amplitude of a wave does not affect the speed at which the wave travels.  The speed of a wave is only altered by alterations in the properties of the medium through which it travels.

the correct answer would be from trough to crest

3.1 Two differences between distance and displacement are:

- Distance is a scalar quantity that refers to the total length traveled irrespective of direction, while displacement is a vector quantity that measures the change in position from the initial point to the final point, considering both distance and direction.

- Distance is always positive or zero, as it only considers the magnitude of the traveled path. Displacement can be positive, negative, or zero, depending on the direction of the movement relative to the reference point.

How to solve for the time

3.2 To determine the time it takes for ball B to reach the ground, we can use the equation of motion for free fall:

h = (1/2)gt²

Where:

h is the initial height (25 m)

g is the acceleration due to gravity (approximately 9.8 m/s^2)

t is the time

Rearranging the equation to solve for time:

t = √((2h)/g)

Substituting the given values:

t = √((2 * 25) / 9.8)

t ≈ 3.19 seconds

Therefore, it takes approximately 3.19 seconds for ball B to reach the ground.

3.3 To calculate the initial velocity of ball A, we can use the equation of motion for vertical projectile motion:

\(v^2 = u^2 - 2gs\)

Where:

v is the final velocity (which is zero as the ball reaches its maximum height)

u is the initial velocity (which we need to find)

g is the acceleration due to gravity (approximately 9.8 m/s^2)

s is the displacement (which is the change in height, -20 m)

Rearranging the equation to solve for initial velocity:

\(u^2 = v^2 + 2gs\)

u = √(v² + 2gs)

Substituting the given values:

u = √(0² + 2 * 9.8 * (-20))

u = √(0 + (-392))

u ≈ -19.80 m/s

Therefore, the initial velocity of ball A is approximately -19.80 m/s (negative sign indicates upward projection).

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The average velocity of the car in m/s for the first leg is 36.2 m/s and the average velocity (in m/s) for the total trip is 7 m/s

Speed is the distance travelled per time taken. The S.I unit is m/s. The average speed is the ratio of the total distance travelled to the to time taken. While velocity is the distance travelled in a specific direction per time taken

Given that a race car traveling northward on a straight, level track at a constant speed travels 0.760 km in 21.0 s. The return trip over the same track is made in 26.0 s.

(a) The average velocity of the car in m/s for the first leg of the run will be

Velocity = (0.760 x 1000)/ 21

Velocity = 760 / 21

Velocity = 36.2 m/s

(b) The average velocity (in m/s) for the total trip will be

36.2 - (0.760 x 1000)/ 26

36.2 - (760) / 26

36.2 - 29.2

7 m/s

Therefore, the average velocity of the car in m/s for the first leg is 36.2 m/s and the average velocity (in m/s) for the total trip is 7 m/s

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The law of conservation of energy states that energy is neither created nor destroyed but is transformed from one form to another.

The law of conservation of energy is the law that states that energy is neither created nor destroyed but is transformed from one form to another.

Examples of activities of everyday life that shows the conservation of energy include the following:

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An example of the law of conservation of energy is a roller coaster.

The law of conservation of energy states that energy cannot be created or destroyed, only transferred or transformed from one form to another. This means that the total amount of energy in a closed system remains constant over time.

A roller coaster car gains kinetic energy as it moves down the track, but it also loses potential energy. At the bottom of the track, the car has the most kinetic energy and the least potential energy, while at the top of the track, it has the most potential energy and the least kinetic energy. However, the total amount of energy in the system remains constant.

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The equation mentioned in the manual is:

m = (n2/n1) * (cos(theta1)/cos(theta2))

n1 = 2.42

The equation mentioned in the manual is:

m = (n2/n1) * (cos(theta1)/cos(theta2))

where m is the slope obtained from the graph of sin(theta1) vs. sin(theta2), n1 and n2 are the refractive indices of the two materials, and theta1 and theta2 are the angles of incidence and refraction, respectively.

In this problem, we have n2 = 1.0003 (since the second material is air). We also know that sin(theta1) = sin(theta2), since the graph is of sin(theta1) vs. sin(theta2). Therefore, cos(theta1) = sqrt(1-sin^2(theta1)) = sqrt(1-sin^2(theta2)) = cos(theta2).

Substituting these values into the equation above, we get:

0.413 = (1.0003/n1) * 1

Simplifying this expression, we get:

n1 = 1.0003/0.413 = 2.42

Therefore, the correct answer is n1 = 2.42.

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Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 7.26 \times {2}^{2} \\ = 2 \times 7.26\)

We have the final answer as

Hope this helps you

Explanation:

Specific heat of a substance is defined as the amount of heat that is required to raise the temperature of one mole or mass of a substance by 1°C.

The total amount of heat of a substance is the amount of heat required to raise the temperature of the given mass of the substance by 1°C.

Specific heat is an intensive property and does not depend on the amount of matter that is present within a substance.

Total amount of heat is an extensive property of matter and it is predicated on the amount of matter present.

Answer:

The acceleration of the car is 4.10 m/s².

Explanation:

The acceleration of the car can be found using the following equation:

\( F = ma \)    (1)

Where:

F is the force

m is the mass

a is the acceleration

The force is:

\(F = F_{p} - F_{f}\)   (2)

Where:

F(p) is the parallel force = 560 N

F(f) is the force of friction = 45 N

By entering equation (2) into (1) we have:

\(F_{p} - F_{f} = (m_{c} + m_{p}*2)a\)

\( 560 N - 45 N = (2000 kg + 55*2 kg)a \)

\( a = \frac{2000 kg + 55*2 kg}{515 N} = 4.10 m/s^{2} \)

Therefore, the acceleration of the car is 4.10 m/s².

I hope it helps you!

As the spaceship approaches and passes through the center of the asteroid ring, the gravitational force on the ship increases due to the reduced distance between them.

The gravitational force between two objects is dependent on their masses and the distance between them. When the spaceship is far away from the ring of asteroids, the gravitational force exerted by the ring on the ship is relatively weak due to the large distance between them. However, as the spaceship approaches the center of the ring, the distance between the ship and the asteroids in the ring decreases, resulting in an increase in the gravitational force. This increase in gravitational force is proportional to the decrease in distance between the two objects. As the spaceship continues to move towards the center of the ring, the gravitational force exerted by the ring on the ship will continue to increase until it reaches its maximum when the ship is at the center of the ring.

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Answer:

a

Explanation:

Answer:

A) real image that appears to be on the right of the mirror.

Explanation:

The complete equations are:

The difference that might exist between any two points. The amount of work required to move a unit positive charge along any path from one point to another without accelerating is referred to as the electric field.

The external effort required to move a charge in an electric field from one position to another is known as an electric potential difference or voltage.

Therefore, the formula are:

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The joints that connect the four fingers (excluding the thumb) with the carpal bones are called metacarpophalangeal joints (MCP joints).

The metacarpophalangeal joints are located at the base of each finger, where the metacarpal bones of the hand articulate with the proximal phalanges of the fingers. These joints allow for flexion (bending) and extension (straightening) of the fingers and also provide some degree of rotational movement.

There are five metacarpophalangeal joints in total, one for each finger. They are commonly referred to as the knuckles.

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The magnitude of the acceleration of the elevator is approximately 3.51 \(m/s^2\).

(a) The scale reading when the elevator is at rest gives the normal force acting on the person, which is equal in magnitude to the person's weight. Thus, the weight of the person is 598 N when the elevator is at rest.

(b) The weight of an object is given by the product of its mass and the acceleration due to gravity.

weight = mass x acceleration due to gravity

598 N = mass x 9.81 \(m/s^2\)

mass = 60.9 kg

Therefore, the person's mass is approximately 60.9 kg.

(c) We can use Newton's second law (F = ma) to find the acceleration of the elevator. The net force acting on the person is given by:

net force = final force - initial force

net force = 384 N - 598 N

net force = -214 N

net force = mass x acceleration

-214 N = 60.9 kg x acceleration

acceleration = -3.51 \(m/s^2\)

Therefore, the magnitude of the acceleration of the elevator is approximately 3.51 \(m/s^2\).

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Answer:

I believe that it's C

Explanation:

The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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By using internal energy, the heat transferred to the air until its volume doubles is 5570.69 joule.

We need to know about internal energy to solve this problem. For a closed system, with matter transfer excluded, the changes in internal energy are due to heat transfer and due to thermodynamic work done by the system on its surroundings. It can be determined as

ΔU = Q - W

where ΔU is the change in internal energy, Q is heat transferred and W is work done.

From the question above, we know that

m = 6 kg

P1 = 200 kPa

T1 = 298 K

P2 = 400 KPa

The internal energy should be

ΔU = Q - W

m(U2 - U1) = Q2 - W2

at the second state the work is zero

m(U2 - U1) = Q2

Assume constant specific heats

Q2 = m . Cv (T2 - T1)

Using the ideal gas

P1/T1 = P2/T2

200/298 = 400/T2

T2 = 596 K

Q2 = m . C . (T2-T1)

Q2 = 6 . 3.1156 . (596-298)

Q2 = 5570.69 joule

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When the distance between the two charged particles is increased by a factor of 3, the force between them is decreased by a factor of 9.

Option B.

The electric force between two charged particles is determined by applying Coulomb's law.

Coulomb's law states that the force of attraction or repulsion between two charged particles is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

F = kq²/r²

where;

From the formula above, we can see that when the distance between two charged particles increases by a factor of 3, the force between them decreases by a factor of 9.

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Answer:

v = 1.63 m/s

Explanation:

Given that,

The mass of a car, m = 1500 kg

The kinetic energy of a car, K = 2004 m/s

We need to find the speed of a car. The formula for the speed of a car is given by :

\(K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 2004}{1500}} \\\\v=1.63\ m/s\)

So, the speed of the car is equal to 1.63 m/s.

Answer:taking my points !

Explanation:

Answer:

repeat using same variables

Explanation:

have peer repeat using same variables

Answer:

W 1920 N

Explanation:

200kg at a location where g=9.6m/s^2

The  height of an AM radio station's antenna should be 86.21 meters tall for a station broadcasting at a frequency of 870 kHz.

To determine the height of an AM radio station's antenna broadcasting at a frequency of 870 kHz, you need to follow these steps:
1. Convert the frequency from kHz to Hz: 870 kHz = 870,000 Hz.

2. Calculate the wavelength (lambda) using the speed of light (c = 3 x 10^8 m/s) and the frequency (f) with the formula: lambda = c / f.
3. Divide the wavelength by 4 to get the antenna's height.

Now, let's calculate the height of the antenna:

1. The frequency is 870,000 Hz.
2. lambda = (3 x 10^8 m/s) / (870,000 Hz) = 344.83 meters.
3. Antenna height = lambda / 4 = 344.83 meters / 4 = 86.21 meters.

So, the antenna should be 86.21 meters tall for a station broadcasting at a frequency of 870 kHz.

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