A typical running track is an oval with 74-m-diameter half circles at each end. A runner going once around the track covers a distance of 400 m. Suppose a runner, moving at a constant speed, goes once around the track in 1 min 40 s.

Answers

Answer 1

The centripetal acceleration is 0.432 m/s at the turn at each end of the track.

One round's total distance is 400 meters.

Duration of one round, T = 1 minute and 40 seconds = 100 seconds

Speed of runner , V = D/T = 400/100 = 4m/s

Now centripetal acceleration is given by

ac = \(V^{2}\)/R

where

V =  4m/s

Radius = D/2 = 74/2 = 37m

ac = 16/37 = 0.432m/\(s^{2}\)

When compared to displacement and velocity, acceleration is like the ferocious dragon of motion variables, breathing fire. It may be violent, some people may be afraid of it, and if it's large, it compels you to pay attention. You can feel yourself accelerating when you're in a car or go kart turning a bend at a fast speed, or when you're seated in a plane during takeoff or slamming on the brakes in a plane.

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Related Questions

The three point charges of the figure below are colinear. The charge in the middle is Q = -5.2 nC. If the resultant force on charge q 2 is zero, what is the value of 1? 9. 92 10 cm 10 cm O 10 nC O 21 nc O 5.2 nc 42 nc

Answers

The correct option is B. The value of Q1 is 21nc.

Q1= \(\frac{4680}{2.25*10^11} columbs\)

   = 2080× \(10^(11)c\)

   = 20.8nc = 21nc

The resultant force is the net force that results from the combination of all the individual forces acting on an object. It is the vector sum of all the forces acting on an object, taking into account both their magnitude and direction.

When two or more forces act on an object, they can either work in the same direction or opposite directions. In the former case, the resultant force is the sum of the magnitudes of the individual forces, while in the latter case, the resultant force is the difference between the magnitudes of the individual forces.

The resultant force is an important concept in physics, particularly in the study of motion and mechanics. Understanding resultant force is crucial for predicting the motion of objects under different conditions and for designing structures and machines that can withstand various forces.

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Complete Question:

The three-point charges of the figure below are colinear. The charge in the middle is Q = -5.2 nC. If the resultant force on charge q 2 is zero, what is the value of Q1

a). 10 nC

b). 21 nc

c). 5.2 nc

d). 42 nc

The three point charges of the figure below are colinear. The charge in the middle is Q = -5.2 nC. If

You and your friend see a ball rolling across the floor to the right. Your friend says
that because it is moving to the right, it must have a net force on it pushing it to
the right. Do you agree with her? Why or why not?
Your answer

Answers

Answer:

unforturnitly

Explanation:

step unstepable

What is the relation between the weight of a body and acceleraton due to gravity?​

Answers

Answer:

All objects on Earth, regardless of their mass, accelerate due to gravity at the same rate - that is, 9.8 m/sec2. The weight of an object can be calculated using the formula for force - F = m * a - where F equals the weight of the object and now the acceleration (a) is the acceleration of gravity (g).

Given the resistivities below, which matedal is best described as an insulator?
O A. 4.5 Ω•m
O B. 2.8 x 10-8 Ω•m
O c. 3.2 x 108 Ω•m
O D. 1.7 x 10-8 Ω•m​

Answers

Answer:

C. 3.2 x 10^8 Ω•m

Explanation:

An insulator is a material that resists the flow of electricity.

In the given data the material with the highest resistivity is the best insulator

3.2 x 10^8 Ω•m

a large box of mass m is moving on a horizontal surface at speed v0. a small box of mass m sits on top of the large box. the coefficients of static and kinetic friction between the two boxes are μs and μk, respectively.

Answers

When the large box moves at speed v0, the small box on top experiences static or kinetic friction. Static friction prevents sliding, while kinetic friction occurs when sliding starts.

When the large box, with a mass of 'm,' moves horizontally at a speed of 'v0,' the small box, also with a mass of 'm,' positioned on top of it, experiences either static or kinetic friction depending on its state. The coefficient of static friction between the two boxes is denoted by 'μs,' while 'μk' represents the coefficient of kinetic friction.

If the small box remains at rest relative to the large box, the static friction prevents it from sliding off. The maximum static friction force, 'fs,' is given by fs ≤ μs * (mass of small box + mass of large box) * g, where 'g' is the acceleration due to gravity.

However, if the large box accelerates to a speed that overcomes the static friction force, the small box starts sliding. At this point, the kinetic friction between the two boxes comes into effect. The magnitude of the kinetic friction force, 'sk,' is given by sk = μk * (mass of small box + mass of large box) * g.

It's important to note that the frictional force always acts in the direction opposite to the motion or the tendency to motion.

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A race car rounds a curve at 54 m/s. The radius of the curve is 441 m, and the car’s mass is 610 kg. (Assume that the car’s speed remains constant. Take the radially inward direction to be positive) The car’s acceleration is 6.61 m/s2. What is it in g’s? What is the centripetal force acting on the car?

Answers

The car’s acceleration in g’s is equal to 0.67 m/s² and the centripetal force acting on is equal to 4033.47 Newton.

How to calculate the car’s acceleration in g’s?

Since the car’s acceleration is given as 6.61 m/s², we would simply divide it by the acceleration due to gravity (9.8 m/s²) to calculate the car’s acceleration in g’s as follows:

Acceleration, g = 6.61/9.8

Acceleration, g = 0.67 m/s².

What is the centripetal force acting on the car?

Mathematically, the centripetal force acting on this car can be calculated by using this formula:

Fc = mv²/r

Fc = (610 × 54²)/441

Fc = 1778760/441

Fc = 4033.47 Newton.

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awnser thiss i need awnsers​

awnser thiss i need awnsers

Answers

Answer:

B

Explanation:

Density = mass / volume

Less dense objects float to the surface so if the liquid becomes 1000 kg/m3 then it is the densest thing in the mixture, except for Q which has a density = to that of the water so it will stay in place around the middle, since the other two are more dense they will go to the bottom of the container.

The answer to this question is b

what did the electronic synthesizer allow composers to create for the first time?

Answers

The electronic synthesizer allowed composers to create and manipulate sounds electronically for the first time.

The electronic synthesizer revolutionized the field of music composition by introducing the capability to generate and shape sounds using electronic means. Before the advent of synthesizers, composers primarily relied on acoustic instruments and traditional methods of sound production.

With the electronic synthesizer, composers gained the ability to generate sounds from scratch, modify existing sounds, and explore a wide range of sonic possibilities. Synthesizers use electronic oscillators, filters, and amplifiers to produce and manipulate sounds through voltage control and signal processing techniques.

By adjusting various parameters such as waveform shape, pitch, duration, amplitude, and timbre, composers could create entirely new sounds that were not possible with traditional acoustic instruments alone. The synthesizer offered control over fundamental sound elements, enabling composers to experiment with novel textures, complex harmonies, layered tones, and other sonic characteristics.

Moreover, the synthesizer allowed for the exploration of electronic effects, such as modulation, delay, and reverb, which further expanded the creative possibilities for composers. This technology opened up new avenues for musical expression, enabling composers to break free from the constraints of traditional instruments and explore uncharted sonic territories.

The electronic synthesizer allowed composers to create and manipulate sounds electronically, offering them unprecedented control and freedom in shaping and designing new sounds. This breakthrough technology played a significant role in transforming music composition and paved the way for the development of electronic music as a distinct genre.

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4. In a long distance race, the athletes were expected to take four rounds of the track such that the line of finish was same as the line of start. Suppose the length of the track was 200m. What is the total distance to be covered by the athletes? What is the displacement of the athletics when they touch the finish line?

Answers

Answer:

The total distance to be covered by the athletes is 800 m

The displacement of the athletes when they touch the finish line is zero.

Explanation:

Given;

Length of the track, L = 200m

the Length of the track for a single round = 200 m

(a) Distance is a scalar quantity which has only magnitude;

If the athletes were expected to take four rounds of the track, then the total distance = 4 x 200 m = 800 m

(b) Also, if  the line of finish was same as the line of start, then displacement of the athletes when they touch the finish line is zero (0 meters). This is because displacement has both magnitude and direction. Once the athlete returns to his starting point, his displacement at that point is zero.

Town Q is 20km due north at P, the bearing of town R from Q is 140. If R is 8km from Q. calculate a) The bearing of R from P to the nearest degree. b) How far north of P from R. leave your answer in 2 S.F.​

Answers

A) The bearing of R from P is 140 degrees (measured clockwise from the north).

B) R is about 5.15 km north of P.

a) To find the bearing of R from P, we need to first determine the angle between the north-south line (i.e., the line joining P and Q) and the line joining P and R. Let's call this angle x.

Since the bearing of R from Q is 140 degrees, we know that the angle between the line joining Q and R and the north-south line is 180 - 140 = 40 degrees.

Now, in triangle PQR, we have two angles: x and 40 degrees. We can find the third angle by noting that the sum of the angles in any triangle is 180 degrees. Therefore,

x + 40 + 90 = 180

Solving for x, we get x = 50 degrees.

So the bearing of R from P is 90 + 50 = 140 degrees (measured clockwise from the north).

b) To find how far north of P R is, we need to use trigonometry. Let's call the distance we're looking for y.

In triangle PQR, the angle opposite side QR (i.e., angle QPR) is 180 - 90 - 50 = 40 degrees. We also know that QR = 8 km.

Using the sine function, we can write:

sin 40 = y/QR

Rearranging, we get:

y = QR * sin 40 = 8 * sin 40 ≈ 5.15 km (rounded to 2 decimal places)

Therefore, R is about 5.15 km north of P.

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If a roller-coaster car has 40,000 J of gravitational potential energy when at rest on the top of a hill, how much kinetic energy does it have when it is ½ of the way down the hill?

Answers

Answer:   20,000 J

=============================================

Work Shown:

PE = potential energy

KE = kinetic energy

m = mass

g = acceleration of gravity

h = height of the object

PE = m*g*h = 40,000 joules

---------

If the car is halfway down the hill, then that means the height of the car is h/2 instead of h

We can then say:

m*g*(h/2) = (m*g*h)/2 = (40,000)/2 = 20,000 J

is the amount of potential energy at this location. The amount of kinetic energy must be the remaining amount that adds to this, to get 40,000 J again.

Put another way: The 40,000 J of PE to start off with, when KE = 0, means we have a total energy of 40,000 J

---------

So,

PE+KE = total energy

PE+KE = 40,000 J

20,000 J + KE = 40,000 J

KE = (40,000 J) - (20,000 J)

KE = 20,000 J when the car is halfway down the hill.

a handy piece of equipment that can be used to spread open thimbles, tighten lags, and help wrap dead-end grips onto the cable is a

Answers

A handy piece of equipment that can be used for spreading open thimbles, tightening lags, and assisting in wrapping dead-end grips onto a cable is a cable grip puller.

A cable grip puller is a specialized tool designed to provide a firm grip and leverage when working with cables. It typically consists of a handle or grip portion and a set of jaws or clamps that can be adjusted to accommodate different sizes of thimbles or lags. The puller allows for the spreading open of thimbles, which are metal sleeves used to protect and reinforce the cable ends.

Additionally, the grip puller's adjustable jaws or clamps can be used to tighten lags, which are screws or bolts used to secure cable fittings or fixtures. The tool provides a secure grip and the necessary torque for tightening the lags effectively.

Furthermore, a cable grip puller can assist in wrapping dead-end grips onto the cable. Dead-end grips are devices used to secure the cable ends to support structures or equipment. The puller aids in applying the necessary tension and ensuring a proper and secure grip on the cable.

Overall, the cable grip puller is a versatile and practical tool that facilitates various tasks involved in cable installation, maintenance, and securing cable ends. Its design and functionality make it a valuable asset for professionals working with cables in various industries.

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Two runners are racing around a cicular track. The first runner is in the inside lane. The second runner is in the outside lane. If the first runner wants to stay side-by-side with the second runner, what does her angular velocity need to be?.

Answers

The angular velocity needs to exactly the same as they would then cover equal angular distance for a period of time. An equal angular distance means that would always be side to side.

A pseudovector used in physics to represent how quickly an object's angular position or orientation changes over time is called an angular velocity, rotational velocity, or angular frequency vector. Angular velocity is defined as follows: The vector representation of rotation rate, or how quickly an object rotates or revolves in relation to another point, is called angular velocity. The time rate at which an object rotates or revolves around an axis is known as its angular velocity. The rotational axis is the direction in which the angular velocity is moving. The angular velocity of an object rotating counterclockwise is along the axis of rotation, away from you. The angular velocity of an object rotating counterclockwise points in your direction along the axis of rotation.

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A soccer ball accelerates at a rate of 22 m/s²

forward when kicked by a player. The soccer ball

has a mass of 0.5 kg. How much force was applied

to the ball?

Answers

The force applied to the ball is 11 Newtons.

What is Newton's second law of motion?

To solve this problem, we need to use Newton's second law of motion, which states that the force applied to an object is equal to its mass times its acceleration:

F = m * a

Here, we are given the acceleration of the soccer ball when it is kicked by a player. The acceleration is 22 m/s² forward. We are also given the mass of the ball, which is 0.5 kg.

To find the force applied to the ball, we simply need to plug these values into the equation:

F = m * a

F = 0.5 kg * 22 m/s²

F = 11 N

Therefore, the force applied to the ball is 11 Newtons.

Note that the unit of force is Newtons (N), which is the SI unit of force. The Newton is defined as the amount of force required to give a mass of 1 kilogram an acceleration of 1 meter per second squared. In this case, the force applied to the soccer ball is 11 Newtons, which means that it is enough force to give the ball a mass of 0.5 kg an acceleration of 22 m/s² forward.

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The density of aluminum is 2700 kg/m^3. If transverse waves propagate at 38 m/s in a 4.6 mm diameter aluminum wire, what is the tension on the wire?
a 39 N b 65 N c 52 N d 78 N

Answers

The correct option is B: The tension on the aluminum wire is approximately 65 N.

How to calculate tension in aluminum wire?

To find the tension on the aluminum wire, we can use the formula for the speed of transverse waves in a string:

v = √(T/μ)

where:

v = speed of transverse waves

T = tension in the wire

μ = linear mass density (mass per unit length) = density * area

First, let's calculate the area of the aluminum wire:

Given diameter = 4.6 mm

Radius = diameter/2 = 4.6 mm / 2 = 2.3 mm = 2.3 x \(10^(^-^3^)\) m

Area = π * \(r^2\)

      = π * (2.3 x 10⁽⁻³⁾)²

      = π * (5.29 x 10⁽⁻⁶⁾)

      ≈ 1.658 x 10⁽⁻⁵⁾ m²

Now, let's calculate the linear mass density (μ):

Density of aluminum = 2700 kg/m³

Linear mass density (μ) = density * area

                       = 2700 kg/m³ * 1.658 x 10⁽⁻⁵⁾ m²

                       ≈ 0.0447 kg/m

Now, we can rearrange the formula for the speed of transverse waves to solve for tension (T):

T = μ * v²

Given v = 38 m/s and μ = 0.0447 kg/m, we can calculate T:

T = 0.0447 kg/m * (38 m/s)²

 ≈ 63.9906 N

Rounding to the nearest whole number, the tension on the wire is approximately 64 N.

Therefore, the closest option from the given choices is: b) 65 N

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The force of gravity between two students is 3.5E-8 Newtons. If
the first students mass is 71.0 kg and the second students mass is
67.0 kg, how far apart must the students be from each other?

Answers

Answer:

I put both in an image so there is no plagiarizing.

Explanation:

Hope it helps!

The force of gravity between two students is 3.5E-8 Newtons. Ifthe first students mass is 71.0 kg and
The force of gravity between two students is 3.5E-8 Newtons. Ifthe first students mass is 71.0 kg and

The air in a tire pump has a volume of 1.5 L at a temperature of 5 ℃. If the temperature is increased to 25 ℃ and the pressure remains constant, what is the new volume of the tire pump

Answers

Answer:

Explanation:

5 C = 278 K

25 C = 298 K

V1 / T1 = V2 / T2

1.5L / 278 K = V2 / 298 K

V2 = (1.5L * 298) / 278

V2 = 1.61 L

For a uniformly accelerated motion the graph of displacement versus time would be​

Answers

Explanation:

hope this may help you

have a nice day

For a uniformly accelerated motion the graph of displacement versus time would be

A bookhelf i 2m long, with upport at it end(P and Q). Don't conider the weight of the bookhelf when you are anwering quetion

The book i moved o that it i 50cm from Q. Ue moment to calculate the frce at P and Q

Answers

A bookshelf is 2m long, with support at it end (P and Q). Don't consider the weight of the bookshelf. The book is moved to that it is 50cm from Q. The force at P is W/3 and Q is 2W/3.

The force at points P and Q using the concept of moments, you need to know the weight of the bookshelf and the location of the book on the shelf. The moment of a force about a point is equal to the force multiplied by the distance from the point to the line of action of the force. The line of action of a force is the straight line through which the force acts. In this case, let's assume that the weight of the bookshelf is W and the location of the book is x meters from Q. The forces at points P and Q can be found using the following equations:

Moment at P = (W - F) x x

Moment at Q = F x (2 - x)

Where F is the force exerted by the book on the shelf.

Solving these equations for F and substituting the given values gives:

= F = W x (2 - x) / (2 - x + x)

= W x 2 / 3

The force at point P is equal to the weight of the bookshelf minus the force exerted by the book, which is:

= F at P = W - F

= W - W x 2 / 3

= W / 3

The force at point Q is equal to the force exerted by the book, which is:

= F at Q = F

= W x 2 / 3

So, if the weight of the bookshelf is W and the book is 50 cm from Q (which is equal to 0.5 meters), the force at point P is W / 3 and the force at point Q is 2W / 3.

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For a particular transformer, the voltage E in the circuits is related to the number of windings W of wire around the core by the equation E = 40W. How many windings will produce a voltage of 760 V?

Answers

ANSWER

\(19\text{ windings}\)

EXPLANATION

The voltage, E, is related to the number of windings, W, by the equation:

\(E=40W\)

To find the number of windings that will produce 760 V, we have to solve for W when E is 760 V. That is:

\(\begin{gathered} 760=40W \\ \Rightarrow W=\frac{760}{40} \\ W=19\text{ windings} \end{gathered}\)

That is the answer.

do you agree or disagree that folk dance forms can be outside their original formmeaningful s

Answers

I disagree that folk dance forms can be outside their original meaningful form in this scenario.

What is Folk dance?

This is the type of dance which is unique to a particular set of people and helps celebrate their culture.

This dance is a ritualistic entertainment which is done in different type of gatherings such as ceremonies etc which is why it isn't outside their original meaningful form.

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.The speed of light through a clear solid is 2.05 x 10 m/s. Is the solid A) zircon where n-1.92, B) diamond where n=2.42, or C) quartz where n-1.46? Provide mathematical proof of your answer. (2 Marks)

Answers

Given, speed of light through a clear solid is 2.05 × 108 m/s. We need to find whether the given solid isA) zircon where n = 1.92, B) diamond where n = 2.42, or C) quartz where n = 1.46. Let us use Snell’s law of refraction to find out whether the given solid is zircon, diamond or quartz.

Snells law states that:n1 sin θ1 = n2 sin θ2,where n1 = refractive index of the medium in which the incident ray is travelling,n2 = refractive index of the medium in which the refracted ray is travelling,θ1 = angle of incidence, andθ2 = angle of refraction. The refractive index n is given by:n = c/vwhere c is the speed of light in vacuum and v is the speed of light in the given medium. Let the given medium be denoted by x. The speed of light through a clear solid, x is given as 2.05 × 108 m/s. The refractive index of the medium can be calculated as:n = c/v = 3 × 108/2.05 × 108 = 1.46≈ 1.46Now, we can calculate the critical angle for the given medium using the formula:θc = sin−1 (n2/n1),where n1 = refractive index of the medium in which the incident ray is travelling,n2 = refractive index of the medium in which the refracted ray is travelling.

Using the given options and their refractive indices, we get the following values for critical angles for zircon, diamond and quartz:Zircon:θc = sin−1 (1/1.92) = 30.27°Diamond:θc = sin−1 (1/2.42) = 24.41°Quartz:θc = sin−1 (1/1.46) = 41.81°Now, we can calculate the critical angle for the given medium using the formula:θc = sin−1 (n2/n1),where n1 = refractive index of the medium in which the incident ray is travelling,n2 = refractive index of the medium in which the refracted ray is travelling.Let the given medium be denoted by x and its refractive index be denoted by nx. Since the given medium is a clear solid, we can assume that the angle of incidence is zero (i.e. the incident ray is perpendicular to the surface of the solid).θ1 = 0°Hence, we get the following expression for the angle of refraction:θ2 = sin−1 (n1/n2 × sin θ1) = sin−1 (n1/n2 × 0) = 0°Therefore, the incident ray will not be refracted when it enters the given solid. Since no refraction occurs, we can conclude that the critical angle for the given solid is zero.

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HW 08-03 1 1 point A 3.3 kg block is sitting on a ramp inclined at an angle = 37. There are coefficients of friction μg = 0.44 and uk = 0.30 between the block and the ramp. What is the minimum force Fmin (in N) that must be applied horizontally in order to move the block up the ramp? Round your answer to one (1) decimal place. If there is no solution or if the solution cannot be found with the information provided, give your answer as: -1000 Type your answer... ch --00 Submit

Answers

The minimum force (Fmin) required to move the block up the ramp is 12.7 N.

Mass of the block (m) = 3.3 kg

Angle of the ramp (θ) = 37°

Coefficient of friction between the block and the ramp (μg) = 0.44

Coefficient of kinetic friction between the block and the ramp (uk) = 0.30

Step 1: Resolve the forces acting on the block.

The weight of the block (mg) can be resolved into two components:

- The force acting parallel to the incline (mg*sinθ)

- The force acting perpendicular to the incline (mg*cosθ)

Step 2: Calculate the force of friction.

The force of friction can be calculated using the equation:

Force of friction (Ff) = μg * (mg*cosθ)

Step 3: Determine the minimum force required.

To move the block up the ramp, the applied force (Fapplied) must overcome the force of friction.

Thus, the minimum force required (Fmin) is given by:

Fmin = Ff + Fapplied

Step 4: Substitute the given values and calculate.

Ff = μg * (mg*cosθ)

Fmin = Ff + Fapplied

Now, let's calculate the values:

Ff = 0.44 * (3.3 kg * 9.8 m/s² * cos(37°))

Ff ≈ 12.717 N

Fmin = 12.717 N + Fapplied

Therefore, the minimum force (Fmin) required to move the block up the ramp is approximately 12.7 N.

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a cylinder weighs 29.2 grams what is its density? and will it float in water?

Answers

In order to determine the density of a cylinder, we need to know its mass and volume. The mass of the cylinder is given as 29.2 grams, but the volume is not provided. Without the volume, it is impossible to calculate the density of the cylinder.

As for whether or not the cylinder will float in water, that also depends on its density. If the density of the cylinder is less than the density of water (1), then it will float. However, without knowing the density of the cylinder, it is impossible to determine whether or not it will float in water.

A car goes forward along a level road with a certain acceleration, a. The additional force needed to bring the car into equilibrium is.

Answers

The additional force needed to bring the car into equilibrium is equal to the mass of the car times the acceleration of the car, or F = ma.

What is equilibrium?

Equilibrium is a state of balance and stability between opposing forces or actions. In economics, it refers to the point where the supply and demand for a given product or service are equal, and the market price of the product or service is stable. In physics and chemistry, equilibrium is a state in which different competing forces are balanced, so that no net change is observed. In biology, it is the ability of an organism to maintain a stable internal environment despite changes in external conditions. Ultimately, equilibrium is a state of balance, stability, and homeostasis.


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Projectile motion describes objects projected outward near the surface of the earth objects orbiting the earth objects leaving the earth's gravitational field resistance due to friction The resultant displacement is the same as distance travelled (discussed in Ch 2) is always equal to the length of the path along which an object travels is the shortest distance from the starting point directly to the ending point is measured in units of distance divided by time Question 3 (0.5 points) When adding vectors, which of the following is NOT true the order in which the vectors are added is important drawing a diagram may be useful for solving the problem the tip-to-tail method of adding vectors is useful the arrow drawn from the tail of the first vector to the tip of the last vector represents the sum of the vectors The parallelogram method is used for adding vectors used for determining Kindergarden aptitude the same as the Pi method used for resolving a vector into its components The trigonometric function sin( theta) is equal to length of the side opposite the angle theta divided by the length of the hypotenuse (o/h) length of the side adjacent the angle theta divided by the length of the hypotenuse (a/h) length of the side opposite the angle theta divided by the length of the side adjacent the angle theta length of the side adjacent the angle theta divided by the length of the side opposite the angle theta The following are all examples of objects that experience projectile motion near the surface of the earth EXCEPT a thrown baseball a basket ball thrown toward the basket a speeding bullet a clock pendulum Projectile motion near the surface of the earth makes a path in the shape of a parabola triangle straight line trapezoid One yellow tennis ball is projected horizontally while at the same time a red tennis ball is dropped vertically from the same point near the earth's surface. The yellow tennis ball will reach the ground before the red tennis ball reach the ground after the red tennis ball reach the ground at the same time as the red tennis ball enter a lunar orbit You are hanging in a tree 3 meters off the ground. A friend on a nearby 3 meter high hill aims a tennis ball launcher horizontally directly at you. What will happen if you let go of the tree and fall directly to the ground at the same time the gun is fired? (neglecting air resistance) You will hit the ground and be in position to catch the ball as it arrives at the same spot at the same time you do. The tennis ball will pass through the spot where you were hanging. while you will have dropped down below. You will reach the ground before the tennis ball, which will arrive at the same spot after you reach the ground The tennis ball will pass over your head, but below the spot where you were hanging Question 10 (0.5 points) Two vectors can be added accurately by adding their components along chosen axes with the aid of trigonometric functions maximum and minumum magnitudes along each axis in a chosen coordinate system areas formed within right-angle triangles where the vectors form the hypotenuse of each triangle magnitudes, without taking into consideration their directions Projectile motion describes objects projected outward near the surface of the earth objects orbiting the earth objects leaving the earth's gravitational field resistance due to friction Question 2 (0.5 points) The resultant displacement is the same as distance travelled (discussed in Ch 2) is always equal to the length of the path along which an object travels is the shortest distance from the starting point directly to the ending point is measured in units of distance divided by time Question 3 (0.5 points) When adding vectors, which of the following is NOT true the order in which the vectors are added is important drawing a diagram may be useful for solving the problem the tip-to-tail method of adding vectors is useful the arrow drawn from the tail of the first vector to the tip of the last vector represents the sum of the vectors The parallelogram method is used for adding vectors used for determining Kindergarden aptitude the same as the Pi method used for resolving a vector into its components

Answers

For Question 3, the statement that is NOT true when adding vectors is the same as the Pi method used for resolving a vector into its components.

When adding vectors, the Pi method is not used for resolving a vector into its components. The Pi method, also known as the method of trigonometric components, is used to break down a single vector into its horizontal and vertical components. It involves using trigonometric functions (such as sine and cosine) to determine the magnitudes of the components.

On the other hand, when adding vectors, the tip-to-tail method is commonly used. It involves placing the vectors head-to-tail and drawing an arrow from the tail of the first vector to the tip of the last vector. The resulting arrow represents the sum or resultant of the vectors. The parallelogram method can also be used, which involves constructing a parallelogram using the vectors and drawing the resultant vector from the common point of the parallelogram.

Therefore, the statement that is NOT true when adding vectors is that the Pi method is used for resolving a vector into its components.

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Which type of comb would be best to use in the winter, a plastic comb or a glass comb? Explain using the Triboelectric series.

Answers

Answer:

I'm not sure how to use it using the Series, but it would be the plastic comb

Explanation:

In the winter, it's likely to be cold and the glass would absorb that energy, also making it cold. in order to be able to hold it, you would need something warm, thus making the plastic one the better option as it is less likely to absorb the cold energy

A person weighing 823 n is standing on a scale in an elevator that is accelerating upward at 4 m/s2. what does the scale read

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A person weighing 823 N is standing on a scale in an elevator is accelerating upward. The scale will read 1159 N.

What is acceleration?

Acceleration is the time rate of change of velocity.

Person weighs 823 N, elevator's acceleration is 4 m/s² and the acceleration due to gravity is 9.8 m/s².

The Net upward force = (823 / 9.8 ) x 4 = 336 N

The force pushing person downward will add up to the weight of person to give the scale reading.

F = 823 N + 336 N

F = 1159 N

Thus, the scale will read 1159 N.

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HELP ASAP PLEASEEE

Question 3 of 10
Which action must you take before starting to make an electromagnet out of
connecting wires, a battery, an ammeter, and a magnetic core wrapped in
wire?
A. Cover the ammeter with the same insulation that is on the wires.
B. Remove the wire that is wrapped around the magnetic core
material.
C. Wrap the battery with insulated wire.
D. Remove the insulation from the ends of the connecting wires.
SUBMIT

Answers

Answer:

The answer should be

D. Remove the insulation from the ends of the connecting wires.

Explanation:

The exact letter may not be D for everyone but the answer is

Remove the insulation from the ends of the connecting wires.

The action that you must take before starting to make an electromagnet out of connecting wires, a battery, an ammeter, and a magnetic core wrapped in wire is to "remove the insulation from the ends of the connecting wires". Hence, Option D is the correct answer.

What is an electromagnet?

Electromagnet, can be described as the device which  consists of a core of magnetic material surrounded by a coil through  and it allows the  electric current to pass so as  to magnetize the core.

It should be noted that the  electromagnet  can be made to function in a case where there is controllable magnets are required,  which can be  contrivances in which the magnetic flux is to be varied, hence in the case above  Removal of  the insulation from the ends of the connecting wires will be the best action since the you are making an electromagnet out of connecting wires,  as well as  battery, an ammeter.

Therefore, option D is the correct answer.

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on the celestial sphere, which of the following terms are specific to the observer (that is, they are unique for unique observers)? (choose all that apply.) select one or more: a. celestial equator b. north celestial pole c. nadir d. meridian e. horizon f. zenith g. ecliptic

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The terms specific to the observer are e, f, and g. The ecliptic is the path that the Sun appears to follow across the sky throughout the year as viewed from Earth.

The horizon is an imaginary line that marks the point where the sky and the Earth's surface seem to meet. The zenith is an imaginary point directly overhead from the observer's location.

The celestial equator is an imaginary line that runs around the celestial sphere, dividing it into two hemispheres. The north celestial pole is the point directly above the observer's north horizon. The nadir is an imaginary point directly below the observer's location.

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