A transmission line strung 7.0 m above the ground carries a current of 500 A. What is the magnetic field on the ground directly below the wire

Answers

Answer 1

Answer:

Approximately \(143\; {\rm T}\) assuming that this transmission line is straight and infinitely long.

Explanation:

Lookup the permeability of free space: \(\mu_{0} = 4\, \pi\; {\rm T \cdot m \cdot A^{-1}\).

Consider an infinitely-long straight wire in empty space carrying a current of \(I\). At a distance of \(r\) from this wire, the magnitude of the magnetic field from the wire would be:

\(\begin{aligned} B &= \frac{\mu_{0}\, I}{2\, \pi\, R}\end{aligned}\).

In this question, it is given that \(I = 500\; {\rm A}\). At a distance of \(R = 7.0\; {\rm m}\) from this wire, the magnitude of the magnetic field from this cable would be:

\(\begin{aligned} B &= \frac{\mu_{0}\, I}{2\, \pi\, R} \\ &= \frac{(4\, \pi \; {\rm T \cdot m \cdot A^{-1}}) \, (500\; {\rm A})}{(2\, \pi)\, (7.0\; {\rm m})} \\ &\approx 143\; {\rm T}\end{aligned}\).


Related Questions

You are now the owner of a sailboat with a 35 -foot mast. You are only comfortable sailing when you have at least one foot of clearance between the top of your mast and the object you are sailing under. There is a bridge you want to sail under in this harbor that has a 32-foot clearance at mean high water (MHW). Assume the difference from MLLW which was used as the reference point in this data and MHW is 3.8 feet. You know there are many days and times you cannot sail under the bridge due to improper clearance. Answer the following questions to help you determine when it is safe to sail under the bridge. 13. How tall is your mast (the answer is in the prompt above)? 14. Using the information in the prompt above, how much clearance do you need to feel comfortable sailing under the bridge (i.e., how much space between the water level and bridge do you need)? 15. What is the bridge clearance in feet at MHW (the answer is in the prompt above)? 16. What is the bridge clearance in feet at MLLW? 17. How low must the water height be relative to MLLW for you to clear the bridge? 18. On which days in the window from February 3-7 could you plan to sail under the bridge? 19. If you miss your window, what it the next day you can leave?

Answers

(13)The height of the mast is given as 35 feet.(14) Need at least 1 foot of clearance between the top of your mast and the object you are sailing under.(15)Mean high water (MHW) is given as 32 feet.(16)Bridge clearance at MLLW = 28.2 feet.(17) The water height must be lower than the bridge clearance at MLLW, which is 28.2 feet.(18)Based on the water heights, you can determine if there are days with a low enough water level for you to clear the bridge.(19) Look for a day when the water height relative to MLLW is low enough for you to sail under the bridge with the required clearance.

Let's address each question one by one:

(13)The height of the mast is given as 35 feet.

(14)You need at least 1 foot of clearance between the top of your mast and the object you are sailing under.

(15)The bridge clearance at mean high water (MHW) is given as 32 feet.

(16)To find the bridge clearance at mean low low water (MLLW), we need to subtract the difference between MLLW and MHW from the MHW bridge clearance.

Bridge clearance at MLLW = Bridge clearance at MHW - Difference (MLLW - MHW)

Given: Difference (MLLW - MHW) = 3.8 feet

Bridge clearance at MLLW = 32 feet -3.8 feet

Bridge clearance at MLLW = 28.2 feet

(17)To clear the bridge, the water height must be lower than the bridge clearance at MLLW, which is 28.2 feet.

(18)To determine which days you can plan to sail under the bridge, we need the tidal information for those days. Unfortunately, I don't have access to real-time tidal data. You would need to consult a local tide chart or a reliable online source to determine the water heights relative to MLLW during that specific time period. Based on the water heights, you can determine if there are days with a low enough water level for you to clear the bridge.

(19)To determine the next day you can leave, you would need to check the tidal information for the days following the February 3-7 window. Look for a day when the water height relative to MLLW is low enough for you to sail under the bridge with the required clearance.

Remember to consult reliable and up-to-date tidal information to ensure the accuracy of the water heights and plan your sailing accordingly.

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Here is a revised version with appropriate paragraph breaks and mathematical breaks for better readability:

1. The mast height of the sailboat is 35 feet.

Paragraph breaks refer to separating distinct ideas or concepts into separate paragraphs for better organization and readability. Each paragraph focuses on a specific topic or point, allowing the reader to easily follow the flow of information.

Mathematical breaks, on the other hand, refer to breaking down mathematical equations or expressions into separate lines or steps to make them easier to understand and follow. It involves presenting mathematical calculations in a clear and structured manner, often using line breaks or indentation to separate each step or component of the equation.

2. The owner is only comfortable sailing under the bridge when there is at least one foot of clearance between the top of the mast and the object it is sailing under.

3. The bridge clearance at mean high water (MHW) is 32 feet.

4. The difference between MHW and mean low water (MLLW) is 3.8 feet, so the bridge clearance at MLLW would be 32 - 3.8 = 28.2 feet.

5. The owner would need to have the water height at least 36 feet below MHW (32 feet + 1 foot clearance + 3 feet difference between MHW and MLLW) to clear the bridge.

6. From the tide chart given below, we can see that the lowest tide during the window from February 3-7 occurs on February 5 at 2:48 AM, with a height of 0.1 feet below MLLW. Since the owner needs the water height to be at least 36 feet below MHW to clear the bridge, they would not be able to sail under the bridge on any of these days.

7. The next day the owner could leave would be February 8.

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A gas at 110kPa and 30 degrees celsius fills a flexible container to a volume of 2L. If the temperature was raised to 80 degrees celsius and the pressure to 440kPa, what is the new volume

Answers

To determine the new volume of the gas when the temperature and pressure change, we can use the combined gas law equation, which relates the initial and final states of a gas:

(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)

Given:

Initial pressure (P₁) = 110 kPa

Initial temperature (T₁) = 30 °C = 30 + 273.15 K

Initial volume (V₁) = 2 L

Final pressure (P₂) = 440 kPa

Final temperature (T₂) = 80 °C = 80 + 273.15 K

New volume (V₂) = ?

Substituting the given values into the combined gas law equation, we have:

(110 * 2) / (30 + 273.15) = (440 * V₂) / (80 + 273.15)

Simplifying the equation further, we can solve for V₂:

(220 / 303.15) = (440 * V₂) / (353.15)

Now, we can calculate the new volume by rearranging the equation:

V₂ = (220 / 303.15) * (353.15 / 440)

By performing the calculations, we can find the value of V₂, which represents the new volume of the gas after the change in temperature and pressure.

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Completion Status: A Click Submit to complete this assessment. estion 4 A 12 in diameter rod is subjected to an axial tensile load of 60 kips. Compute. a. The normal stress developed on an inclined plane at an angle of 25 with the cross section of the rod. b. The maximum normal stress developed in the rod.

Answers

The normal stress on an inclined plane at 25 degrees can be calculated using σ = F / A * cos²θ, while the maximum normal stress is σ_max = F / A_max.

a. To calculate the normal stress developed on an inclined plane, we use the formula: σ = F / A * cos²θ. Given that the diameter of the rod is 12 inches, the radius (r) is half of the diameter, which is 6 inches or 0.5 feet. The cross-sectional area of the rod (A) can be calculated using the formula for the area of a circle: A = π * r². Substituting the values, we get A = π * (0.5)^2 = π * 0.25 = 0.7854 square feet.

Now, we can calculate the normal stress using the given axial tensile load (F) of 60 kips and the angle (θ) of 25 degrees. Since the load is given in kips (1 kip = 1000 pounds), we convert it to pounds by multiplying by 1000: F = 60 * 1000 = 60000 pounds.

Using the formula σ = F / A * cos²θ, we substitute the values and calculate the normal stress:

σ = 60000 / 0.7854 * cos²25 ≈ 95317.91 psi (pounds per square inch).

b. The maximum normal stress in the rod occurs when the inclined plane is aligned with the maximum cross-sectional area. In this case, the maximum cross-sectional area (A_max) is the same as the cross-sectional area of a circle, which is π * r². Substituting the radius value, we get A_max = π * (0.5)^2 = π * 0.25 = 0.7854 square feet.

To calculate the maximum normal stress (σ_max), we use the formula σ_max = F / A_max. Substituting the given axial tensile load (F) of 60 kips and the maximum cross-sectional area (A_max), we calculate the maximum normal stress:

σ_max = 60000 / 0.7854 ≈ 76448.44 psi (pounds per square inch).

Therefore, the normal stress developed on an inclined plane at an angle of 25 degrees with the cross section of the rod is approximately 95317.91 psi, and the maximum normal stress developed in the rod is approximately 76448.44 psi.

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If two objects are repelling each other, that means they have _________ electrical charges.

Answers

Answer:

the same

Explanation:

if that is what you are asking

The diffusion of inanimate forms of energy was vital to the accelerated development of the modern world. The industry is completely dependent on the techniques of extracting energy from nature. The development of energy sources or the lack of them determined the fate of countries. Those that were able to develop and exploit them led the industrialization process, those that did not invest in the energy sector became technologically lagging countries.

Discuss about:

a) the evolution of the main energy matrices after the industrial revolution (main sources of energy);

b) The social and environmental consequences of these energy sources;

c) relate energy development and degree of industrial development.

Answers

The evolution of energy matrices, the social and environmental consequences of energy sources, and the relationship between energy development and industrial development are critical aspects of understanding the interplay between energy and the modern world. Balancing the need for energy with sustainability and minimizing environmental impacts is a key challenge for societies today.

a) The evolution of the main energy matrices after the industrial revolution:

The industrial revolution marked a significant shift in the sources of energy used to power the growing industries and societies. Prior to the industrial revolution, human and animal labor, along with limited use of water and wind power, were the primary sources of energy. However, with the advent of steam engines and mechanization, there was a need for more abundant and efficient sources of energy.

Coal: Coal became the dominant energy source during the early stages of the industrial revolution. It provided the necessary fuel for steam engines and played a crucial role in powering factories, railways, and steamships.

Oil: The discovery and commercialization of oil in the late 19th century revolutionized the energy landscape. Oil became a major source of energy for transportation, as it fueled the internal combustion engines of automobiles, trucks, and airplanes.

Natural Gas: With the expansion of oil drilling, natural gas also emerged as an important energy source. It is used for heating, electricity generation, and as a feedstock for various industrial processes.

Nuclear Energy: The development of nuclear power in the mid-20th century introduced a new source of energy. Nuclear reactors harness the energy released from nuclear fission reactions to generate electricity.

Renewable Energy: In recent decades, there has been a growing emphasis on renewable energy sources such as solar, wind, hydroelectric, and geothermal power. These sources offer sustainable alternatives to fossil fuels, with lower environmental impact and the potential for long-term energy security.

b) The social and environmental consequences of these energy sources:

Each energy source has its own social and environmental consequences:

Fossil Fuels: The burning of fossil fuels, such as coal, oil, and natural gas, releases greenhouse gases and contributes to climate change. Extraction of fossil fuels can lead to habitat destruction, water pollution, and health hazards for workers and nearby communities.

Nuclear Energy: While nuclear energy does not produce greenhouse gas emissions during operation, it presents risks associated with accidents, radioactive waste disposal, and potential weaponization of nuclear materials. Public safety concerns and environmental risks have led to debates over the use of nuclear power.

Renewable Energy: Renewable energy sources offer benefits in terms of reduced greenhouse gas emissions and environmental sustainability. However, their deployment may require land use changes, and some technologies (e.g., large-scale hydroelectric dams) can cause ecological disruptions and displacement of communities.

c) The relationship between energy development and degree of industrial development:

Energy development and industrial development are closely intertwined. The availability of affordable and reliable energy sources is crucial for driving industrialization and economic growth. Access to abundant energy resources enables countries to power their industries, expand transportation networks, and improve living standards.

Countries that have invested in the development and exploitation of energy sources have typically experienced accelerated industrialization and technological advancement. The ability to secure and utilize energy resources efficiently has been a determining factor in a country's competitiveness and economic prosperity.

Conversely, countries that lack access to energy sources or fail to invest in their energy sectors may face challenges in industrial development. Limited energy availability can constrain production capacities, limit access to modern technologies, and hinder economic progress.

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.What is the mass of an object if it accelerates at 3 m/s2 and has a force of 1 N?

Answers

Answer:

1/3 kg

Explanation:

\(a = \frac{f}{m} = \frac{1}{3 }kg\)

Which force is there between an ice skate and the ice​

Answers

The answer is friction
friction

At the same time, if there were no friction at all on ice, skating would be impossible, because it is the friction between the skate and the ice when a skater pushes off that starts the motion to begin with. And friction is also what allows a skater to ever come to a stop.

What is the index of refraction of a refractive medium if the angle of incidence in air is 30 degrees and the angle of refraction is 20 degrees?

Answers

The index of refraction of a medium is a ratio of the speed of light in a vacuum to the speed of light in that medium.

It is denoted by the symbol "n". The relationship between the angles of incidence and refraction and the index of refraction of a medium is given by Snell's law, which states that:n1 sinθ1 = n2 sinθ2where n1 and n2 are the indices of refraction of the two media, and θ1 and θ2 are the angles of incidence and refraction, respectively.In this case, the incident medium is air, which has an index of refraction of approximately 1.00. The angle of incidence is 30 degrees, and the angle of refraction is 20 degrees. Therefore, we can use Snell's law to solve for the index of refraction of the refractive medium

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mosquito buzzing has an intensity level of 40dB, calculate the intensity of this buzzing sound

Answers

The intensity of the buzzing sound of the mosquito will be 10⁻⁸ W/m².

What is the intensity of sound?

The intensity of a sound is the power of the sound in the unit of Watts divided by the area which the sound covers in square meters. The loudness of a sound is related to the intensity of any given sound to the intensity at the threshold of hearing capacity. Intensity is measured in decibels (dB).

Intensity level = β = 40 dB

The intensity of this mosquito buzzing sound (I).

The formula to find intensity level is

β = 10 log₁₀ (I/I₁₀)

Here, we have to put the values of β and I₀ (10⁻¹² W/m²)

40 = 10 log₁₀ (I/ 10⁻¹²)

I = 10⁻¹²antilog₁₀(4)

I = 10⁻¹²× 10⁴

I = 10⁻⁸ W/m²

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The gravitational field strength on Earth is 10 N/kg. What is the gravitational potential energy of a 5 kg mass raised to a height of 3m?
PLEASE HELPP

Answers

Answer:

The gravitational potential energy is 150J

Explanation:

P. E=mgh

=5*10*3

When the car comes to a sudden stop, the passenger ________ in motion

Answers

Answer:

If the car comes to a sudden stop, your body tends to keep moving forward.

Explanation:

true or false
the faster an object moves, the greater its potential energy?

Answers

Answer:

true

Explanation:

Because the more mass you have, the faster the speed and the greater its potential energy, which is a storage energy.

A boy is pulling his two sisters on a sled.
If one sister weigh 30.0 kg, the other
weights 40.0 kg, and the coefficient of
kinetic friction is 0.120, how much force
is required to pull the sled?
[?] N

Answers

Answer:

Explanation:

The oly way we can figure this out is if the boy is pulling the sled at a constant velocity. If not, we need a value for acceleration, and you don't have that here. If the boy is pulling the sled at a constant velocity, then the value for acceleration is 0, making this a really simple problem. I'm going with that, since there is no way to answer you otherwise. If velocity is not constant, please either repost the question or put it in the notes section under the question as it stands. If acceleration is 0, then

F - f = ma becomes

F - f = m(0) which is

F - f = 0 and

F = f which says that the applied force is the same as the frictional force. We need then to find the frictional force, which has an equation of

f = μ\(F_n\) where normal force is the same as the weight of the 2 girls. We will find that, then:

Each girl's mass is different so the normal force/weight equation is

w = (30.0)(9.8) + (40.0)(9.8) to get

w = 290 + 390 and

w = 680. Plug that into the frictional force equation:

f = (.120)(680) so

f = 82N

project: weather forcasting
Instructions
Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your file(s) and are ready to upload your assignment, click the Add Files button below and select each file from your desktop or network folder. Upload each file separately.

Answers

B that is the correct answer

3. What are the two types of mixtures?

Answers

Answer:

heterogeneous and homogeneous

Explanation:

Hetero you can separate whilst homo is combined and cant be separated

a car starts from rest and travels for 3.4s with a uniform acceleration of 17.0 m/s. what is the final velocity of the car

Answers

Answer:

Explanation:

57.8 m/s

Refer to the photo taken.
a car starts from rest and travels for 3.4s with a uniform acceleration of 17.0 m/s. what is the final

What is the effect of gravity on a falling object?​

Answers

Answer:

When objects fall to the ground, gravity causes them to accelerate.

Madison applied a force of 150 N in a horizontal direction to a sleigh. Meanwhile the sleigh slid 30.0 m across a level surface of snow. The work done on the sleigh by Madison is _________ J.

Answers

Answer:

4500 joules

Explanation:

since work(joules) = force(newtons) x distance(meters),

150N x 30M = 4500 Joules

Answer:

4500 joules

Explanation:

150 N x 30 M = 4500 joules

(a) Draw a Velocity - Time graph for an Object with Constant Acceleration.
(b) Draw a Velocity - Time graph for an Object with Constant velocity.
(c) In the given graph, compare the acceleration the body undergoes in region A and C.​

Answers

Explanation:

answers to 1 and 2 above/below respectively but can't do 3 because I don't know what graph you're talking about

(a) Draw a Velocity - Time graph for an Object with Constant Acceleration. (b) Draw a Velocity - Time
(a) Draw a Velocity - Time graph for an Object with Constant Acceleration. (b) Draw a Velocity - Time

Information about conservation of energy

Answers

Explanation:

Energy conservation is the effort made to reduce the consumption of energy by using less of an energy service. This can be achieved either by using energy more efficiently (using less energy for a constant service) or by reducing the amount of service used (for example, by driving less). Energy conservation is a part of the concept of Eco-sufficiency. Energy conservation reduces the need for energy services and can result in increased environmental quality, national security, personal financial security and higher savings.It is at the top of the sustainable energy hierarchy. It also lowers energy costs by preventing future resource depletion.

Energy can be conserved by reducing wastage and losses, improving efficiency through technological upgrades and improved operation and maintenance. On a global level energy use can also be reduced by the stabilization of population growth.

Energy can only be transformed from one form to other, such as heat energy to motive power in cars, or kinetic energy of water flow to electricity in hydroelectric power plants. However machines are required to transform energy from one form to other. The wear and friction of the components of these machine while running cause losses of very high amounts of energy and very high related costs. It is possible to minimize these losses by adopting green engineering practices to improve life cycle of the components.

Hope this helps u ......Explanation:

Two teams are playing tug of war. Team A pulls to the right with a force of 450 N. Team B pulls to the left with a force of 415 N. What is the net force on the rope, and what is its direction? 35 N to the right 35 N to the left 865 N to the right 865 N to the left

Answers

A). 35 N to the right is the correct answer

The two force acting on the rope are opposite in direction hence, they cancel in magnitude and the resultant force will be the subtracted value. Hence, the net force on the rope is 35 N to the right.

What is force?

Force is an external agent by which the state of an object can be changed or it can be deformed. Force is a vector quantity having both magnitude and direction.

If two force acting on object are from the same direction then, the net force will be sum of the two forces in magnitude. If they are acting in opposite direction, the net force will be the substracted value with a direction in which the largest force acts.

Here, a force of 450 N acts on the rope in right direction and 415 N to the left. Therefore,the net force will be 450 - 415 = 35 N. The direction of net force is to the right direction.

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Does this equation show that transmutation has taken place during decay?
Why or why not?
Ni – S.Ni+y
A. No, because there is conservation of the number of atoms as well
as the number of nucleons.
B. No, because high-energy electromagnetic waves are emitted.
C. Yes, because the numbers of nucleons and atoms are conserved.
D. Yes, because nickel atoms remain nickel atoms with the same
number of neutrons.

Answers

Answer:

Maybe A is the correct answer

A PM DC electric motor will be selected for an arm mechanism which has a length of 0.3 meters. This arm is aimed to lift 2 kg of load attached to its free end while rotating with 60 rpm at maximum power. There will be a gearbox with 3:1 ratio (speed reducer) and 80% efficiency attached between the motor and the arm. a) State the stall torque, maximum speed and power requirements for the desired motor at maximum loading, b) If input voltage is required to be 24 V and armature resistance of all possible motors is 1.5 ohm, state electrical constant and torque constant of the desired motor.

Answers

On the PM DC electric motor:

a) Stall torque is 5.88 Nm. Maximum speed is 20 rpm. Power requirements are approximately 12.29 W.b) Electrical constant is 1.2 V/(rad/s). Torque constant is approximately 3.92 Nm/A.

How to solve for the DC electric motor?

a) To determine the stall torque, maximum speed, and power requirements for the desired motor:

Stall torque (Ts):

The stall torque is the maximum torque generated by the motor when it is not rotating (at 0 rpm). It can be calculated using the equation:

Ts = (Load mass) x (Acceleration due to gravity) x (Length of the arm)

Given:

Load mass = 2 kg

Acceleration due to gravity = 9.8 m/s²

Length of the arm = 0.3 meters

Ts = 2 kg x 9.8 m/s² x 0.3 meters

Ts = 5.88 Nm

Therefore, the stall torque of the desired motor is 5.88 Nm.

Maximum speed (Nmax):

The maximum speed is given as 60 rpm. However, considering the speed reduction by the gearbox, calculate the maximum speed at the motor shaft. The maximum speed at the motor shaft (Nmotor) can be calculated as:

Nmotor = (Nmax) / (Gearbox ratio)

Given:

Nmax = 60 rpm

Gearbox ratio = 3:1

Nmotor = (60 rpm) / (3)

Nmotor = 20 rpm

Therefore, the maximum speed at the motor shaft is 20 rpm.

Power requirements (P):

The power requirements at maximum loading can be calculated using the equation:

P = (Stall torque) x (Maximum speed) / (9.55)

Given:

Stall torque = 5.88 Nm

Maximum speed = 20 rpm

P = (5.88 Nm) x (20 rpm) / (9.55)

P ≈ 12.29 W

Therefore, the power requirements of the desired motor at maximum loading are approximately 12.29 W.

b) To find the electrical constant (Ke) and torque constant (Kt) of the desired motor:

Electrical constant (Ke):

The electrical constant relates the back electromotive force (EMF) of the motor to its angular velocity. It can be calculated as the ratio of the voltage across the motor terminals to the maximum speed at the motor shaft:

Ke = (Input voltage) / (Nmotor)

Given:

Input voltage = 24 V

Nmotor = 20 rpm

Ke = (24 V) / (20 rpm)

Ke ≈ 1.2 V/(rad/s)

Therefore, the electrical constant of the desired motor is approximately 1.2 V/(rad/s).

Torque constant (Kt):

The torque constant relates the torque output of the motor to the current flowing through its armature. It can be calculated as the ratio of the stall torque to the current:

Kt = (Stall torque) / (Armature current)

Given:

Stall torque = 5.88 Nm

Armature resistance = 1.5 ohm

Kt = (5.88 Nm) / (1.5 ohm)

Kt ≈ 3.92 Nm/A

Therefore, the torque constant of the desired motor is approximately 3.92 Nm/A.

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If a dog ran at 5 m/s how far would it run in 45 s

Answers

Answer:

225 m//s

Explanation:

It ran 5m/s so 5x45=225

Answer:

225 meters

Explanation:

If it is running 5 meters per seconds, and it ran 45 seconds, you would need to multiple the seconds it ran by the speed per second: 5 • 45

5 • 45 = 225

An athlete is running a race. The athlete’s body needs energy. Which type of organelle in the athlete’s cells supplies the energy for cellular function?.

Answers

Mitochondria. It would make the most sense.

An athlete is running a race, and he needs energy, then mitochondria are the organelle that will supply the energy for cellular function.

What are mitochondria?

The principal purpose of the mitochondrion, a membrane-bound organelle found in the nucleus of nearly all eukaryotic cells (organisms with clearly defined nuclei), is to produce lots of energy in the shape of adenosine triphosphate (ATP). The normal shape and size of mitochondria are circular to oval and range from 0.5 to 10 m.

In addition to generating energy, mitochondria also produce heat and regulate cell development and death. They also store calcium for use in cell signaling functions.

Human erythrocytes don't contain any mitochondrial, whereas liver and muscle cells may have hundreds or even thousands of mitochondria. This is because the amount of mitochondria per cell varies greatly.

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Heat flows into a gas in a piston and work is performed on the gas by its surroundings. The amount of work done is equal to the heat added. In this situation,

Answers

Answer:

The Internal energy of the gas did not change

Explanation:

In this situation the Internal energy of the gas did not change and this is because according the the first law of thermodynamics

Δ U = Q - W  ------ ( 1 )

Δ U  = change in internal energy

Q = heat added

W = work done

since Q = W.  the value of ΔU  will be = zero   i.e. No change

1. A rocket traveling at 400 m/s fires its booster rockets until the craft reaches 550 m/s. If
the boosters fire for 30 seconds, what was the acceleration of the rocket?

Answers

Answer:

Your answer is 5 m/s

Explanation:

what would happened if there is no invented of machine?​

Answers

if there were no invention of machines then life would have been more difficult and simple works could be hard to do. Even now we are using our phones, sitting in a AC room interacting to eachother from different places. without the invention of machines simple things like transportation would have been difficult. There would be horses and donkey for the transportation. There would be no electricity,no internet, no transportation, not even c computers or mobile etc. The market for business will be smaller, the knowledge and news about world would be less.

so the problem would have been bigger than we can imagine. But one thing is that nature could survive lot more compared to what we have done till now by destroying nature.

What are sport skills sometimes referred to as?
a skill-related fitness
b. performance skills
c. health-related fitness
d. physical fitness

Answers

B) performance skills

Describe two vectors a andb such that vector a+ vector b= vector c and a+b=c
(b) vector a + vector b= vector a - vector b
(c) vector a + vector b + vector c and a2 +b2=c2
can you show me how to do this problem and show all work myprofessor didn't go over any of this and i dont have a clue.

Answers

Answer:

a + b = c      where a and b and c are vector quantities

Since c is the result of adding vector b to vector a (to add two vectors the vectors are connected head to tail)

a^2 + b^2 - 2 ab cos θ = c^2 is an expression of such a relationship

Note that a^2 + b^2 = c^2 if a and b are at right angles to one another

Another way to express this is:

a x + b x = c x    where a and b are the x-components of a and b

a y + b y = c y      describes the y -components of a and b

The above two equations will provide the x and y components of vector c

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