A train travels from Washington D.C. to New York (225 miles). The train departs at 4:55 PM and arrives in New York at 7:55 PM. What is the average speed of the train?

Binary integer variables are variables whose values consist of two values, 0 and 1.

Correct answer will be :- b. Variables with values 0 and 1.

These values are also known as bits, which are represented as 0 and 1 in computers. Binary integer variables are used in computing as a way to represent numbers, characters, and instructions. Binary integer variables are used to represent information in digital systems, because they can be used to represent any value with a single bit.

For example, a single bit can represent a number, letter, or instruction. Binary integer variables are also used in computer programming, as they can be used to represent boolean values, such as true and false. Additionally, they can be used to represent various types of data, such as numbers, characters, and images.

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The additional operation which needed to make the expression equivalent to given expression is \(-\dfrac{3}{4} x\). Thus the option 3 is the correct option.

Equivalent expression are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The equation given in the problem is,

\(\dfrac{5}{4} x+6\)

Let the equation is equation number 1.

This expression is to convert in the expression, which is,

\(\dfrac{1}{2}x+6\)

Let the above equation is equation number 2.

Let the additional operation which needed to make the expression equivalent to given expression is \(f(x)\).

As the addition of \(f(x)\) and equation 1 is equal to the equation 2. Therefore,

\(f(x)+\dfrac{5}{4} x+6=\dfrac{1}{2}x+6\)

Solve the equation as,

\(f(x)=\dfrac{1}{2}x+6-\dfrac{5}{4} x-6\\f(x)=\dfrac{1}{2}x-\dfrac{5}{4} x\\f(x)=\dfrac{2-5}{4} x\\f(x)=\dfrac{-3}{4} x\)

Hence, the additional operation which needed to make the expression equivalent to given expression is \(-\dfrac{3}{4} x\). Thus the option 3 is the correct option.

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Answer:

c                   the third one

Step-by-step explanation:

The interest amount (simple interest ) on the loan amount $5315 at 5% from 10th aug to 23rd dec. of same year is $105.50

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

\(I = \dfrac{P \times R \times T}{100}\)

For this case, we're specified that:

Converting this time in terms of year, we get:

Aug has 31 days, Sept has 30 days, Oct. has 31 days, Nov has 30 days.

From 10th aug, till its last, there went 22 days.

Whole sept and oct and nov. was spent (30+31+30 = 91 days)

And then there were 22 days of december(23rd day not covered assumingly)

So, total days = 22+22+91 = 145 days.

Assuming averagely 365.25 days in an year, we get the average time for which the interest will be calculated as:

\(\dfrac{145}{365.25} \approx 0.397 \: \rm years\)

Thus, we get: the amount of interest as:

\(I = \dfrac{P \times R \times T}{100}\\\\I \approx \dfrac{5315 \times 5\times 0.397}{100} \approx 105.50 \: \rm dollars\)

Thus, the interest amount (simple interest ) on the loan amount $5315 at 5% from 10th aug to 23rd dec. of same year is $105.50

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In order to calculate the time it will take for Andrew to settle the loan, we can use the formula for compound interest. So, it will take Andrew approximately 5.22 years to settle the loan.

The formula is given as A = P(1 + r/n)^(nt), Where: A = the final amount, P = the principal (initial amount borrowed), R = the annual interest rate, N = the number of times the interest is compounded in a year, T = the time in years.

We know that Andrew borrowed R200 000 from a bank at an annual interest rate of 5.25% compounded quarterly and that he will make repayments of R6 000 at the end of every 3 months.

Since the first repayment will be made 3 months from now, we can consider that the initial loan repayment is made at time t = 0. This means that we need to calculate the value of t when the total amount repaid is equal to the initial amount borrowed.

Using the formula for compound interest: A = P(1 + r/n)^(nt), We can calculate the quarterly interest rate:r = (5.25/100)/4 = 0.013125We also know that the quarterly repayment amount is R6 000, so the amount borrowed minus the first repayment is the present value of the loan: P = R200 000 - R6 000 = R194 000

We can now substitute these values into the formula and solve for t: R194 000(1 + 0.013125/4)^(4t) = R200 000(1 + 0.013125/4)^(4t-1) + R6 000(1 + 0.013125/4)^(4t-2) + R6 000(1 + 0.013125/4)^(4t-3) + R6 000(1 + 0.013125/4)^(4t)

Rearranging the terms gives us: R194 000(1 + 0.013125/4)^(4t) - R6 000(1 + 0.013125/4)^(4t-1) - R6 000(1 + 0.013125/4)^(4t-2) - R6 000(1 + 0.013125/4)^(4t-3) - R200 000(1 + 0.013125/4)^(4t) = 0

Using trial and error, we can solve this equation to find that t = 5.22 years (rounded to 2 decimal places). Therefore, it will take Andrew approximately 5.22 years to settle the loan.

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It is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

In the given scenario, it is not completely true that based only on the r and p values listed above, you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

Let's first understand what is meant by the term "moderator.

"Moderator: A moderator variable is a variable that changes the strength of a connection between two variables. If there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents, scientists investigate whether this bivariate relationship is moderated by age.

Therefore, based on the values of r and p, it is difficult to determine if age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

As we have to analyze other factors also to determine whether the age is a moderator or not, such as the sample size, the effect size, and other aspects to draw a meaningful conclusion.

So, it is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

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Answer:

i bellive the answer is a function

Step-by-step explanation:

Answer:

the larger one is 183

Step-by-step explanation:

\(x + y = 262 \\ x - y = 104 \\ y = 262 - x \\ x - (262 - x) = 104 \\ x - 262 + x = 104 \\ 2x = 104 + 262 \\ 2x = 366 \\ x = 183 \\ y = 262 - 183 \\ y = 79\)

Answer:

D, X^2 -18 + 81 = -45 + 81

Step-by-step explanation:

it is complating squer method that used for solving x in a quadratic equetion . in this step you will add

(y/2)^2 if y is the cofitient of x .

Answer:

5/6

Step-by-step explanation:

mental math

Answer:

125

Step-by-step explanation:

C : F

10: 25

×5: ×5

50: ?

No. of fish in the tank = 25 × 5

                                    = 125

Given statement solution is :-The price of the less expensive car is $31, and the price of the more expensive car is $31 + $4 = $35.

Let's denote the price of the less expensive car as "x" dollars. According to the given information, the more expensive car costs $4 more than the less expensive car, so its price would be "x + $4" dollars.

The owner can buy 5 more of the less expensive cars for $120 than the more expensive car. This means that the price of 5 less expensive cars is $120 more than the price of one more expensive car. Mathematically, we can express this as:

5x = (x + $4) + $120

Now let's solve this equation to find the value of "x":

5x = x + $4 + $120

5x = x + $124

4x = $124

x = $124 / 4

x = $31

Therefore, the price of the less expensive car is $31, and the price of the more expensive car is $31 + $4 = $35.

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If the null hypothesis is rejected, it suggests that there is evidence to support the claim that the mean weight of Take-a-Bite snack food is less than 175 grams.

What is the standard deviation?

The standard deviation is a measure of the dispersion or variability of a set of data points. It quantifies how much the individual data points deviate from the mean of the data set.

To test the claim that the mean weight of Take-a-Bite snack food is less than 175 grams, we can conduct a one-sample t-test. Here's how we can perform the test at a significance level of 0.05:

Step 1: State the null and alternative hypotheses:

Null Hypothesis (H0): The mean weight of Take-a-Bite snack food is equal to 175 grams.

Alternative Hypothesis (H1):

The mean weight of Take-a-Bite snack food is less than 175 grams.

Step 2: Determine the test statistic:

Since the population standard deviation is unknown, we use the t-test statistic. The test statistic for a one-sample t-test is calculated as: t = (sample mean - hypothesized mean) / (sample standard deviation / √n)

In this case, the sample mean is 172 grams, the hypothesized mean is 175 grams, the sample standard deviation is 8 grams, and the sample size is 70.

Step 3: Set the significance level: The significance level (alpha) is given as 0.05.

Step 4: Calculate the test statistic:

t = (172 - 175) / (8 / √70) ≈ -1.158

Step 5: Determine the critical value and p-value:

Since we are conducting a one-tailed test to check if the mean weight is less than 175 grams, we need to find the critical value or p-value for the lower tail.

Using a t-distribution table or statistical software, we can find the critical value or p-value associated with a t-statistic of -1.158 and degrees of freedom (df) equal to n - 1 (70 - 1 = 69) at a significance level of 0.05.

Step 6: Make a decision:

If the p-value is less than the significance level (0.05), we reject the null hypothesis. If the critical value is greater than the test statistic, we reject the null hypothesis.

Step 7: Interpret the results:

Based on the calculated test statistic and critical value or p-value, make a conclusion about the null hypothesis. If the null hypothesis is rejected, it suggests that there is evidence to support the claim that the mean weight of Take-a-Bite snack food is less than 175 grams. If the null hypothesis is not rejected, there is insufficient evidence to support the claim.

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The polynomial with zeros 2, -3, and 5 and degree 3 is P(x) = x^3 - 4x^2 - 11x + 30.

To form a polynomial with given zeros and degree, you can use the following steps:

Start with the given zeros: Let's say you have the zeros a, b, c, ..., up to the degree of the polynomial.

Use the zero-factor property: The zero-factor property states that if a polynomial has a zero at a certain value, then the corresponding factor of the polynomial is (x - zero).

Write down the factors: Write down the factors based on the zeros you have. For example, if you have zeros a, b, and c, the corresponding factors would be (x - a), (x - b), and (x - c).

Multiply the factors: Multiply all the factors together to obtain the polynomial expression.

Simplify the polynomial: Simplify the polynomial by expanding and combining like terms.

Here's an example to illustrate the process:

Let's say you want to form a polynomial with the zeros 2, -3, and 5, and the degree is 3.

The corresponding factors would be (x - 2), (x + 3), and (x - 5).

Multiplying these factors together, we get:

P(x) = (x - 2)(x + 3)(x - 5)

Expanding and simplifying:

P(x) = (x^2 + 3x - 2x - 6)(x - 5)

= (x^2 + x - 6)(x - 5)

= x^3 - 5x^2 + x^2 - 5x - 6x + 30

= x^3 - 4x^2 - 11x + 30

So, the polynomial with zeros 2, -3, and 5 and degree 3 is P(x) = x^3 - 4x^2 - 11x + 30.

By following these steps, you can form a polynomial with given zeros and degree.

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Answer:

\(P(A)= 0.95 \: and \: P(A∩B)=0.37. \\ Find \: P(B∣A) \\ P(B∣A) = \frac{P(A∩B)}{P(A)} \\ = \frac{0.37}{0.95} \\ \therefore \: P(B∣A) = 0.389\)

The mode is the number that appears most frequently in a set of data. Therefore, we need to look at the data set to find the number that appears the most.

Follow these steps to find the mode in your data set:

1. Put your data in order from smallest to largest.
2. Count how many times each number appears.
3. The number that appears most frequently is the mode.

Once you have determined the mode for each individual in the data set, you can compare them to find who had the highest mode score. The individual with the highest mode score is the one who had the number that appeared most frequently.

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Answer:

40*8.5=340

6*90=540

total=880/2.5=352bags

Answer:

What you need to find is the extra amount of plywood. To do that, you must find the area of the square and the area of the circle and subtract them to find the answer.

Step-by-step explanation:

Formulas:

area of a square: A = bh

area of a circle: A =

square measurements:

b = 28

h = 28

circle measurements:

(≈3.14)

r = 14

A = (28)(28)

A = 784

area of square = 784 in^2

A = 3.14 ()

A = 3.14 (196)

A = 615.44 in^2

784 - 615.44 = 168.56

The amount of plywood left over is 168.56 in^2.

Hope this Helps.

Answer:

it's 189 the area

Step-by-step explanation:

area =189

Answer: Rotate 180° around the origin.

Step-by-step explanation:

It doesn't even matter whether its clockwise or counterclockwise. You get the same result.

The attachments are screenshots of your original screenshot rotated 180°

Answer: To calculate the mean square treatment (MST), we need to have the sums of squares for treatment (SST) and the degrees of freedom for treatment (dfT).

Assuming that there are k treatment groups and a total of n observations, we can calculate SST and dfT as follows:

SST = Σ(xi - x_bar)^2 - Σ(yi - y_bar)^2 / n

where xi is the dried weight of plants for the i-th treatment group, x_bar is the mean dried weight of plants for all treatments combined, yi is the dried weight of plants for the control group, and y_bar is the mean dried weight of plants for the control group.

dfT = k - 1

Once we have calculated SST and dfT, we can find MST by dividing SST by dfT:

MST = SST / dfT

Note that SST is the sum of squares for treatment, which represents the variation in the response variable that is due to the different treatment conditions. MST represents the average amount of variation in the response variable that can be attributed to the treatment conditions.

Without knowing the specific values for the dried weight of plants, it is not possible to calculate SST and dfT, and therefore the MST.

Step-by-step explanation:

if Seiko deposits $3500 into an account that pts 5.8% annual interest monthly then the balance after 8 years is 5565.

percentage, a relative value indicating hundredth parts of any quantity.

Given that seiko deposits $3500 into an account that pts 5.8% annual interest monthly.

We need to find the balance after 8 years.

\(A=Pe^{rt}\)

P is the principle amount which is 3500

r is rate of interest =5.8%=5.8/100=0.058

t is the time period=8 years

\(A=3500e^{0.058(8)}\)

\(A=3500e^{0.464}\)

A=3500(1.59)

A=5565

Hence, if Seiko deposits $3500 into an account that pts 5.8% annual interest monthly then the balance after 8 years is 5565.

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Out of the three parameters, x is an input parameter, while wholep and fracp are considered both input and output parameters.

In the function apart defined in question, there are three parameters: x, wholep, and fracp.

Among these parameters, x is considered an input parameter because it represents the input value that is passed into the function.

The parameters wholep and fracp can be considered both input and output parameters. They are passed by reference (using pointers) and can be modified within the function. The function updates the values of wholep and fracp based on the calculation, which means they can be considered as output values. However, they are also initially provided as input values when the function is called.

Therefore, out of the three parameters, x is an input parameter, while wholep and fracp are considered both input and output parameters.

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There are 9 questions on the test.

Let, the number of multiple-choice questions on the test = m

the number of essay questions on the test = s

m + s = 26  .......(1)

So, We are also told that multiple choice is worth 3 points each, so the total number of points for m questions will be 3m.

As essays are worth 8 points each, so the total number of points for s questions will be 8s.

3m + 8s = 123 .......(2)

Now we will use the substitution method to solve a system of linear equations.

From equation (1) we will get,

m = 26 -s

Substituting this value in equation (2) we will get,

3 * (26- s) + 8s =123

78 - 3s + 8s = 123

5s = 123 -78

5s = 45

s = 45/5 = 9

So, there are 9 questions on the test.

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The complete question is:

Ada’s history teacher wrote a test for the class.

The test is 26 questions long and is worth 123 points.

Ada wrote two equations, where m represents the

number of multiple choice questions on the test, and

s represents the number of essay questions on the test.

m+s= 26

3m + 8s = 123

How many essay questions are on the test?

The graph is plotted in the following figure .

To plot a graph we need 2 pts .

First eqn is of a circle ( \(x^{2}\) ) + ( \(y^{2}\) ) = 4

Second eqn is of a line x - y = 1

The center of circle is ( 0 , 0 )

The circle passes through ( 2 , 0 ) , ( 0 , 2 ) , ( - 2 , 0 ) , ( 0 , - 2 ) .

The line passes through ( 0 , 1 ) , ( 0 , - 1 ) .

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Answer:

1/3

Step-by-step explanation:

15/(15+18+12)=15/45=1/3

Answer:

0.60

Step-by-step explanation:

becouse of two probability within added gives the above answer

Answer:

A

y=3x+11

Step-by-step explanation:

The slope of the line perpendicular to y=-1/3x-4 is 3, and A is the only choice with the slope of 3.