A trailer is most likely to jackknife when it is ... 1. loaded to full capacity2. overloaded3. empty
Answers
A trailer is most likely to jackknife when it is empty (option 3).
When a trailer is empty, its weight is mostly concentrated near the front, making it more prone to jackknifing during sudden braking or turning maneuvers.
Jackknifing is a dangerous situation that occurs when a trailer swings out to the side of the towing vehicle, forming an angle similar to that of a folding pocket knife. This can happen when the wheels of the trailer lock up during braking or when the trailer skids while turning. An empty trailer is more likely to jackknife because it has less weight to stabilize it and its weight is more concentrated towards the front, leading to less traction and control during sudden maneuvers. Therefore, it is important to take extra precautions when towing an empty trailer, such as reducing speed and avoiding sudden turns or stops.
Option 3 is answer.
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Related Questions
you genetically engineer a strain of yarrowia lipolytica to produce vitamin c. which of the following will be needed for the yeast to produce this vitamin?
Answers
The yeast will need a source of carbon, nitrogen, and oxygen in order to produce vitamin C.
Yarrowia lipolytica is a yeast that can be genetically engineered to produce vitamin C. In order for the yeast to produce this vitamin, it will need a source of carbon, nitrogen, and oxygen. Carbon is needed for the yeast to produce energy, nitrogen is needed for the yeast to synthesize proteins, and oxygen is needed for the yeast to respire and produce energy. Additionally, the yeast will need a source of vitamin C precursors, such as glucose, fructose, and sucrose, in order to produce the vitamin. Finally, the yeast will need a source of vitamins and minerals, such as magnesium, iron, and zinc, in order to produce the vitamin.
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2. Because she has a Victim mindset and having low grade in her Math class, Julianna believes
O a. her low grades are the fault of her unfair teacher.
O b. she needs to take an easier class.
O c. that working with a tutor is the only way for her to pass the class.
O d. she can improve her grades if she studies more.
Answers
Because she has a Victim mindset and having low grade in her Math class, Julianna believes: A. her low grades are the fault of her unfair teacher.
What is a Victim mindset?A Victim mindset is also referred to as victim mentality and it can be defined as an acquired personality trait in which an individual tends to recognize and believe that the negative and unfair actions of others towards him or her, is responsible for the bad and unpleasant things that happens.
This ultimately implies that, an individual with a Victim mindset is prejudiced and strongly believes that every other person is against him or her, and as such these people are responsible for their failures.
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Two forces each ION act on a on a body jone towards the north and the other towards the east. The magnitude and direction of the resultant forces are
Answers
First, we need to draw a diagram of the two forces. Let's call the force pointing north "F_N" and the force pointing east "F_E".
We can then use the Pythagorean theorem to find the magnitude of the resultant force:
|F_R| = sqrt(F_N^2 + F_E^2)
To find the direction of the resultant force, we can use trigonometry.
tan(theta) = F_E / F_N
where theta is the angle between the resultant force and the force pointing north.
We can then use inverse tangent to solve for theta:
theta = tan^-1(F_E / F_N)
Overall, the magnitude and direction of the resultant force will depend on the magnitudes of the two forces and the angle between them. Without numerical values for F_N and F_E, we cannot calculate the specific magnitude and direction of the resultant force.
( I wasn’t too sure on this one, but if it’s not what you were looking for, then please let me know so I can help again! )
What other ways could a wildfire be contained, extinguished, or slowed down?
Answers
An asbestos pad is square in cross section, measuring 5 cm on a side at its small end, increasing linearly to 10 cm on a side at the large end. The pad is 15 cm high. If the small end is held at 600 K and the large end at 300 K, what heat‐flow rate will be obtained if the four sides are insulated? Assume one‐dimensional heat conduction. The thermal conductivity of asbestos may be taken as 0.173 W/m⋅K.
Answers
technician a says that map sensors use a 5-volt reference voltage from the pcm. technician b says the map sensor voltage will be higher at idle at high altitudes compared to when the engine is operating at near sea level. which technician is correct?
Answers
Technician A is correct in stating that MAP (manifold absolute pressure) sensors use a 5-volt reference voltage from the PCM (powertrain control module) to measure engine load.
This voltage is used to determine the amount of air entering the engine and adjust the fuel injection accordingly. Technician B is also correct in stating that the MAP sensor voltage will be higher at idle at high altitudes compared to when the engine is operating at near sea level. This is because at higher altitudes, there is less air pressure, which affects the pressure in the engine. This change in pressure affects the voltage output of the MAP sensor. In summary, both technicians are correct in their statements.
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If = (4,0,3) =(−2,1,5). Find ||, and the vectors (+),(−) ,3 (2+5)
Answers
The vectors are magnitude of vector v is 5. The sum of vectors v1 and v2 is (+) = (2, 1, 8). The difference between vectors v1 and v2 is (-) = (6, -1, -2). The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).
To find the magnitude (||) of a vector, we can use the formula:
||v|| = sqrt(v1^2 + v2^2 + v3^2)
Given vector v = (4, 0, 3), we can calculate its magnitude as follows:
||v|| = sqrt(4^2 + 0^2 + 3^2)
= sqrt(16 + 0 + 9)
= sqrt(25)
= 5
Therefore, the magnitude of vector v is 5.
Now, let's find the sum (+) and difference (-) of the given vectors.
Given vectors v1 = (4, 0, 3) and v2 = (-2, 1, 5), the sum of these vectors is calculated by adding the corresponding components:
v1 + v2 = (4 + (-2), 0 + 1, 3 + 5)
= (2, 1, 8)
The difference between the vectors is found by subtracting the corresponding components:
v1 - v2 = (4 - (-2), 0 - 1, 3 - 5)
= (6, -1, -2)
Lastly, let's calculate the scalar multiple of vector v1:
3v1 = 3(4, 0, 3)
= (12, 0, 9)
Therefore, the vectors are as follows:
- The magnitude of vector v is 5.
- The sum of vectors v1 and v2 is (+) = (2, 1, 8).
- The difference between vectors v1 and v2 is (-) = (6, -1, -2).
- The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).
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Poems that focus on one image usually have what purpose? PLEASE HELP MEH!!
A. to make readers understand how one event leads to another
B. to make readers look at something in a new and different way
C. to make a point about how two or three things are alike
Answers
Answer:
A. to make readers understand how one event leads to another
Explanation:
Hope this helped have an amazing day!
Poems that focus on one image usually make readers understand how one event leads to another. The correct option is A.
What is poetry?Poetry is literature that uses words chosen and arranged for their meaning, sound, and rhythm to elicit a focused imaginative awareness of experience or a particular emotional response.
Narrative, dramatic, and lyrical poetry are the three basic categories. Sometimes it is difficult to distinguish between them.
For instance, lyrical poems can have narrative sections, just as epic poems can include lyrical passages.
Poetry is a genre of writing that is essential to life, art, and culture. Readers can typically comprehend how one occurrence leads to another in poems that concentrate on a single image.
Thus, the correct option is A.
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what happens to the recievng end voltage as the load on a transmission line is increased if the load has a lagging power facotr
Answers
Answer:
The receiving end Voltage ( VR ) will reduce significantly
Explanation:
Determine what happens to the receiving end voltage
Given that ; Load on transmission line is increased and Load has a lagging power factor
Increase in load = Increase in reactive/real power drawn from the transmission line and this will cause an increase in the current drawn as well.
Vs = VR + j XL I
Vs = sending end voltage
VR = receiving end voltage
jXL I = voltage drop across reactance
The rotating and shifting of Vs to a new power angle ( lagging power factor ) without a change in magnitude will cause the value of the VR receiving end voltage to drop significantly
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
A good place to get hints about how to answer a response question could be
a.
Your teacher
c.
Both of these
b.
The rest of the test
d.
None of these
Please select the best answer from the choices provided
A
B
C
D
Answers
Answer:
I think its A
Explanation:
...............................
Evaluate the intensity of solar radiation for 6 September 2021 , given solar constant ( Isc ) = 1800 W / m2
Answers
Answer:
The answer is "\(1802.1978 \ \frac{w}{m^2}\)"
Explanation:
The Solar radiation reaches the earth surfaces is given by
\(I=Isc(1+0.033 \cos \frac{360.(n)}{365.25})\)
where n is number of days in years
n for 6 September 2021:
\(\to n= 31+28+31+30+31+30+31+31+6\\\\\to n= 249\)
\(\to I=Isc(1+0.033 \cos \frac{360 \alpha 249}{365.25})\\\\\to I=1800(1+0.033(+0.037))\\\\\to I =1800(1.001221)\\\\\to I=1802.1978 \ \frac{w}{m^2}\)
2..Three formations, each 25 m thick, overlie one another. If a constant-velocity vertical flow field is set up across the set of formations with h = 120 m at the top and h = 100 m at the bottom, calculate h at the two internal boundaries. The hydraulic conductivity of the top formation is 0.0001 m/s, the middle formation 0.0005 m/s, and the bottom formation 0.0010 m/s.
Answers
The values of h at the two internal boundaries are :
h₁ = 104.625 m h₂ = 101.55 mGiven data :
Z₁ = Z₂ = Z₃ = 25 m
h top = 120 m
h bottom = 100 m
K₁ = 0.0001 m/s
K₂ = 0.0005 m/s
K₃ = 0.0010 m/s
First step : Calculate the value of Keqwe will apply the formula below since flow is perpendicular to the bedding plane
Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\) ----- ( 1 )
Insert values given above into equation 1
Therefore ; Keq = 2.307 * 10⁻⁴ m/s
Next step : determine the hydraulic gradientHydraulic gradient ( Ieq ) = head loss / length
= ( 120 - 100 ) / 3 * 25
Ieq = 0.266
Given that the flow is perpendicular to bedding plane
q1 = q2 = q3
V₁ = V₂ = V₃ = V
K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq
Hence :
V = Keq* Ieq
= 2.307 * 10⁻⁴ * 0.266
= 6.15 * 10⁻⁵ m/s .
Also;
K₁i₁ = Keq * ieq = K₂i₂ = K₃i₃
therefore :
i₁ = 0.615
i₂ = 0.123
i₃ = 0.0615
Final step : determine the value of h at the two internal boundariesPressure at point 1 ( i.e. pressure between first two formations )
h₁ = h top - i₁L₁
= 120 - 0.615 * 25
= 104.625 m
Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )
h₂ = h₁ - i₂L₂
= 104.625 - 0.123 * 25
= 101.55 m
Therefore we can conclude that The values of h at the two internal boundaries are : h₁ = 104.625 m , h₂ = 101.55 m
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several project managers at area 51 are impressed with your recent efforts that successfully characterized the static stability and trim characteristics of the blackstar configuration. your understanding of the fundamentals related to static concepts are clearly quite strong. as such, you are being now tasked on a new project to assist with dynamic concepts of another next-generation aircraft.
Answers
If a first order system's characteristic value, 8, is smaller than zero, we may say that it is dynamically stable. Rolling convergence is the term used to describe the motion, which is a damped roll rate.
Explain the aircraft dynamic modes ?Two parameters can be used to define oscillating motions: the duration of one full oscillation and the duration needed to damp to half-amplitude, or the duration needed to double the amplitude for a dynamically unstable motion. A long-period oscillation known as a phugoid mode and a short-period oscillation known as the short-period mode make up the two different oscillations that make up the longitudinal motion.The "phugoid mode," which has a longer period, is characterised by large amplitude variations in air speed, pitch angle, and altitude but almost no variations in angle of attack.As the aircraft tries to return to the equilibrium level-flight condition from which it had been disturbed, the phugoid oscillation is a slow exchange of kinetic energy (velocity) and potential energy (height) around some equilibrium energy level.Find the attachment answer
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The scale of the blueprint tells us the
of drawing to real space?
Answers
Answer:
yes
Explanation:
blueprint of the construction is a prediction of project its is slightly auto cad
Torque is expressed in pounds per foot (lbs.-ft).
Group of answer choices
True
False
Answers
In a pipe of diameter 350 mm and length 75m water is flowing at a velocity of 2.8 m/s. Find the head lost due to friction by using Darcy Weisbach equation?
Answers
Answer:
1.71 m
Explanation:
The attachment shows the equation and values used in it. The Moody Friction Factor is not specified in this problem statement, so we have used the value provided by the calculator web site (0.02). The head loss is proportional to that factor, so it is not difficult to find the loss if your factor is different.
Thin cuts called Sipes allow the tread pattern blocks to flex during stops and starts? Group of answer choices True False
Answers
Answer:
I think its True
it should be True
An inventor claims to have developed a device requiring no work or heat transfer input yet able to produce hot and cold air streams at steady state.
a. True
b. False
Answers
Answer:
a. True
Explanation:
Apply the principle of conservation of mass.
and also the expression for the steady flow energy equation.
kinetic and potential energy effects can be neglected.
The given statement by the inventor who is claiming the development of a device that requires no work or heat transfer input yet is able to produce hot and cold air streams at a steady state is definitely false.
What is heat transfer?Heat transfer may be characterized as a type of process which involves the migration of heat from one object or component to another by numerous mechanisms like conduction, convection, and/or radiation.
The process of heat transfer may occur where there is a temperature difference between two objects exist. It significantly utilizes the mechanism of exchanging thermal energy between two or more physical systems.
According to the concept of physics, no object or thing has the ability to perform its function without the utilization of any source of heat or energy. Then, how it is possible for that device to produce hot and cold air streams at a steady state.
Therefore, the given statement by the inventor is absolutely false.
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1.Write an equation that shows the equivalency between meters and Gigameters.
Answers
Answer:
Explanation:
A gigameter is 1,000,000,000 meters
so, let us say m is the number of meters, g is the number of gigameters
the equation then is
\(g*10^9=m\)
If a project required a nonbearing exterior wall to minimize solar heat gain while transmitting some light, which of the following materials would be appropriate?
A. Glass block
B. Face brick
C. Modular brick
D. Grade MW brick
Answers
The appropriate material for a nonbearing exterior wall that minimizes solar heat gain while transmitting some light would be A. Glass block.
Glass block, also known as glass bricks, is a type of material that is commonly used in construction for nonbearing exterior walls. It is an excellent material for minimizing solar heat gain while still allowing some light to pass through. Glass block is also a good choice for nonbearing exterior walls because it is strong and durable, and can withstand the elements without deteriorating.
In contrast, face brick, modular brick, and grade MW brick are not as effective at minimizing solar heat gain or transmitting light. These types of materials are typically used for structural or decorative purposes, and are not designed to minimize solar heat gain or transmit light.
Therefore, the correct answer to this question is A. Glass block.
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reductants cannot have a positive charge. reductants cannot have a positive charge. true false
Answers
False. Reductants cannot have a positive charge.
Are reductants capable of carrying a positive charge?Contrary to the statement, reductants can indeed have a positive charge. Reductants are substances that have the ability to donate electrons, thereby reducing another substance. They play a crucial role in various chemical reactions, particularly in redox reactions, where one species is oxidized and another is reduced.
While it is true that many reductants are negatively charged or neutral, there are instances where reductants can carry a positive charge. For example, metal cations like iron(II) and copper(I) can act as reductants by donating electrons. So, the statement that reductants cannot have a positive charge is false.
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W.Q. 1: Albireo, a star in the constellation Cygnus, is a visual binary system whose two components can be seen easily with even a small amateur telescope. Viewers describe the brighter star as "golden" and the fainter one as "sapphire blue." a. What does this description tell you about the relative temperatures of the two stars? Explain. b. What does it tell you about their respective sizes? Explain.
Answers
The description of Albireo's two stars as "golden" and "sapphire blue" indicates that they have different temperatures. The color of a star can also provide insight into their respective sizes.
Golden stars are typically cooler, with a temperature range of 3,500 to 5,000 Kelvin, while sapphire blue stars are hotter, with a temperature range of 10,000 to 50,000 Kelvin. Cooler stars emit more red and yellow light, making them appear golden, while hotter stars emit more blue light, making them appear blue or sapphire. Therefore, the brighter "golden" star is cooler than the fainter "sapphire blue" star.
Generally, larger stars have higher temperatures, and smaller stars have lower temperatures. Since we already determined that the sapphire blue star has a higher temperature, we can infer that it is likely to be larger than the golden star, which has a cooler temperature. This means that the sapphire blue star has a larger size compared to the golden star in the Albireo binary system.
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John has just graduated from State University. He owes $35,000 in college loans, but he does not have a job yet. The college loan company has agreed to give John a break on a deferred-payment plan that works as follows. John will not have to repay his loan for 5 years. During this “grace period” the loan obligation will compound at 4% per year. For the next 5 years, a monthly payment will be required, and the interest rate will be 0.5% per month. What will be John’s monthly payment over the 60-month repayment period?
Answers
Answer:
The correct response is "821.88". A further explanation is given below.
Explanation:
According to the question,
The largest amount unresolved after five years would have been:
= \(35000\times (\frac{F}{P}, 4 \ percent,5 )\)
= \(35000\times 1.216 7\)
= \(42584.50\)
Now,
time (t) will be:
= \(5\times 12\)
= \(60 \ monthly \ payments\)
So, monthly payment will be:
= \(42582.85\times (\frac{A}{P}, 0.5 \ percent,60 )\)
= \(42584.50\times 0.0193\)
= \(821.88\)
Average setup time on a certain production machine is 5.0 hr. Average batch size is 52 parts, and average operation cycle time is 4.2 min. The reliability of this machine is characterized by mean time between failures of 37 hr and a mean time to repair of 55 min.
(a) If availability is ignored, what is the average hourly production rate of the machine.
(b) Taking into account the availability of the machine, determine its average hourly production rate.
(c) Suppose that availability only applied during the actual run time of the machine and not the setup time. Determine the average hourly production rate of the machine under this scenario.
Answers
(a) The machine's average hourly production rate without considering availability is 6.02 parts/hr.
(b) The machine's average hourly production rate, taking into account availability, is 6.17 parts/hr.
(c) The machine's average hourly production rate when only available during run time is 5.71 parts/hr.
How to solve calculations on a production machine?(a) To calculate the average hourly production rate of the machine without considering availability, we need to first calculate the total time it takes to produce a batch of 52 parts.
Total time = (setup time) + (operation time per part x batch size)
Total time = 5.0 hr + (4.2 min/part x 52 parts)/60 min/hr
Total time = 5.0 hr + 3.64 hr
Total time = 8.64 hr
Average hourly production rate = Batch size / Total time
Average hourly production rate = 52 parts / 8.64 hr
Average hourly production rate = 6.02 parts/hr
Therefore, the average hourly production rate of the machine without considering availability is 6.02 parts/hr.
(b) To calculate the average hourly production rate of the machine taking into account availability, we need to first calculate the machine's availability using the mean time between failures (MTBF) and mean time to repair (MTTR) values.
Availability = MTBF / (MTBF + MTTR)
Availability = 37 hr / (37 hr + 0.92 hr)
Availability = 0.975 or 97.5%
Now we can calculate the total time that the machine is available for production:
Available time = Total time x Availability
Available time = 8.64 hr x 0.975
Available time = 8.42 hr
Average hourly production rate = Batch size / Available time
Average hourly production rate = 52 parts / 8.42 hr
Average hourly production rate = 6.17 parts/hr
Therefore, the average hourly production rate of the machine taking into account availability is 6.17 parts/hr.
(c) If availability only applies during the actual run time of the machine and not the setup time, we need to adjust the available time calculation:
Available time = (operation time per part x batch size) / 60 min/hr x Availability
Available time = (4.2 min/part x 52 parts) / 60 min/hr x 0.975
Available time = 4.11 hr
Total time = Available time + setup time
Total time = 4.11 hr + 5.0 hr
Total time = 9.11 hr
Average hourly production rate = Batch size / Total time
Average hourly production rate = 52 parts / 9.11 hr
Average hourly production rate = 5.71 parts/hr
Therefore, the average hourly production rate of the machine taking into account availability only during run time is 5.71 parts/hr.
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2. Prove the correctness of RSA. You can refer to the content on pages 178 and 179. Basically, you need to consider two cases, ged (x, n) = 1 and gcd (x,n) is not equal to 1. For the 2 case, you need to use x = s.q for proof (The textbook uses x=r.p) (30 points)
Answers
To prove the correctness of RSA, we need to show that the decryption of the ciphertext using the private key gives us the original plaintext. We can do this by considering two cases:
Case 1: gcd(x,n) = 1
In this case, we have that x and n are coprime, which means that there exists an integer y such that xy mod n = 1 (by Bezout's identity). Now, let's encrypt a plaintext m by raising it to the power of the public key exponent e and taking the remainder modulo n: c = m^e mod n. To decrypt c, we raise it to the power of the private key exponent d and take the remainder modulo n: m' = c^d mod n.
Using the properties of modular arithmetic, we can show that m' = m^(ed) mod n = m^(xy) mod n = (m^x)^y mod n = (c^y) mod n = (m^e)^y mod n = m^(ey) mod n = m mod n.
Thus, in the case where gcd(x,n) = 1, RSA is correct.
Case 2: gcd(x,n) is not equal to 1
In this case, we have that x and n share a common factor. Let's write x = s.q, where s and q are coprime and q is a factor of n. Then, if we encrypt a plaintext m using RSA, we get c = m^e mod n. To decrypt c, we raise it to the power of the private key exponent d and take the remainder modulo n: m' = c^d mod n.
Using the Chinese Remainder Theorem, we can split the problem into two parts: first, we compute m1 = c^d mod q, and then we compute m2 = c^d mod (n/q). Then, we can use the extended Euclidean algorithm to find integers u and v such that us + vq = 1. Since q is a factor of n, we have that n = q(n/q), and thus we can compute m' = (m1(v(n/q)) + m2(uq)) mod n.
Again using the properties of modular arithmetic, we can show that m' = m mod n.
Thus, in both cases, RSA is correct.
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.Write a program that uses a void function void miles_to_km() to generate a kilometer
conversion table for all even kilometers from 2 miles to 62 miles. Use two decimal
places for kilometers.
Answers
Explanation:
rational
Step-by-step explanation:
The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax
2
+bx+c=0 is:
\boxed{\mathrm{d =} \ b^2 - 4ac}
d= b
2
−4ac
.
If:
• d > 0, then there are two real solutions
• d = 0, then there is a repeated real solution
• d < 0, then there is no real solution.
In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x
2
+4x−2=0 . Therefore, the discriminant of the equation is:
b² - 4ac = (4)² - 4(3)(-2)
= 16 - (-24)rational
Step-by-step explanation:
The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax
2
+bx+c=0 is:
\boxed{\mathrm{d =} \ b^2 - 4ac}
d= b
2
−4ac
.
If:
• d > 0, then there are two real solutions
• d = 0, then there is a repeated real solution
• d < 0, then there is no real solution.
In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x
2
+4x−2=0 . Therefore, the discriminant of the equation is:
b² - 4ac = (4)² - 4(3)(-2)
= 16 - (-24)
= 40
Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.
= 40
Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.
Design a decimal arithmetic unit with two selection variables, V1, and Vo, and two BCD digits, A and B. The unit should have four arithmetic operations which depend on the values of the selection variables as shown below. V1=0011, V0=0101 and output functions are as follows;
1- A+9's complement of B
2- A+B
3- A+10's complement of B
4- A+1 (add 1 to A)
(You can see question number 3 in the attached file)
Answers
A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print: 1. The printer's electronic circuits must be energized. 2. Paper must be loaded and ready to advance. 3. The printer must be "on line" with the microprocessor. As each of the above conditions is satisfied, a HIGH is generated and applied to a 3-input logic gate. When all three conditions are met, the logic gate produces a HIGH output indicating readiness to print. The basic logic gate used in this circuit would be an): A) NOR gate. B) NOT gate. C) OR gate. D) AND gate.
Answers
Answer:
D) AND gate.
Explanation:
Given that:
A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print
These conditions are:
1. The printer's electronic circuits must be energized.
2. Paper must be loaded and ready to advance.
3. The printer must be "on line" with the microprocessor.
Now; if these conditions are met the logic gate produces a HIGH output indicating readiness to print.
The objective here is to determine the basic logic gate used in this circuit.
Now;
For NOR gate;
NOR gate gives HIGH only when all the inputs are low. but the question states it that "a HIGH is generated and applied to a 3-input logic gate". This already falsify NOR gate to be the right answer.
For NOT gate.
NOT gate operates with only one input and one output device but here; we are dealing with 3-input logic gate.
Similarly, OR gate gives output as a high if any one of the input signals is high but we need "a HIGH that is generated and applied to a 3-input logic gate".
Finally, AND gate output is HIGH only when all the input signal is HIGH and vice versa, i.e AND gate output is LOW only when all the input signal is LOW. So AND gate satisfies the given criteria that; all the three conditions must be true for the final signal to be HIGH.
Integer dataSize is read from input. Then, strings and integers are read and stored into string vector colorList and integer vector quantityList, respectively. Lastly, string colorAsked is read from input.
Find the sum of the elements in quantityList where the corresponding element in colorList is equal to colorAsked.
For each element in colorList that is equal to colorAsked, output "Index " followed by the element's index. End with a newline.
Ex: If the input is:
3
lavender 25 lavender 22 gray 161
lavender
Then the output is:
Index 0
Index 1
Total: 47
#include
#include
using namespace std;
int main() {
int numElements;
string colorAsked;
int sumQuantity;
unsigned int i;
cin >> numElements;
vector colorList(numElements);
vector quantityList(numElements);
for (i = 0; i < colorList.size(); ++i) {
cin >> colorList.at(i);
cin >> quantityList.at(i);
}
cin >> colorAsked;
/*answer here*/
cout << "Total: " << sumQuantity << endl;
return 0;
}
Answers
Where the above condition is given, here's the solution:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main() {
int numElements, sumQuantity = 0;
string colorAsked;
unsigned int i;
cin >> numElements;
vector<string> colorList(numElements);
vector<int> quantityList(numElements);
for (i = 0; i < colorList.size(); ++i) {
cin >> colorList.at(i);
cin >> quantityList.at(i);
}
cin >> colorAsked;
for (i = 0; i < colorList.size(); ++i) {
if (colorList.at(i) == colorAsked) {
cout << "Index " << i << endl;
sumQuantity += quantityList.at(i);
}
}
cout << "Total: " << sumQuantity << endl;
return 0;
What is the explanation of the above code?
First, we declare an integer variable sumQuantity to keep track of the sum of quantities of elements in quantityList where the corresponding element in colorList is equal to colorAsked.We read the integer numElements from input.We declare two vectors colorList and quantityList with numElements elements each.We use a loop to read each string and integer from input and store them in colorList and quantityList, respectively.We read the string colorAsked from input.We use another loop to iterate through colorList and check if each element is equal to colorAsked. If it is, we output "Index " followed by the element's index and add the corresponding quantity from quantityList to sumQuantity.Finally, we output the total sum of quantities in sumQuantity.
Learn more about vectors on:
https://brainly.com/question/13322477
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