A toy car rolls down a ramp, even absence of non-conservative forces, it's
not possible for all of it's potential energy to convert into kinetic energy.
What is moving, within the car-system itself, that is also gaining energy
in order for this part of the car to move? How is this responsible for
consuming some of the mechanical energy?

Answer:

Explanation:

L₁ =80 dB

S₁ = 2 m

S₂ = 40 m

__________

L₂ - ?

The intensity of the site is nearby:

ΔL = 10·lg(S₂/S₁)²

ΔL = 10·lg(40/2)² = 10·2·lg(20) = 20·1.3 = 26 dB

L₂ = L₁ - ΔL = 80 - 26 = 54 dB

The distance travelled by the train when it is accelerating for another 16 seconds with the same acceleration is 256 meters.

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 6.0 m/s. Once free of this area, it speeds up to 11 m/s in 8.0 s.

At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed.

Here, we have to find the acceleration of the train.

To solve this problem, we will use the kinematic equation of motion:

v = u + at

Where,v = Final velocity (11 m/s)u = Initial velocity (6 m/s)t = Time taken (8 s)a = Acceleration

We know the value of initial velocity, final velocity, and time taken to reach the final velocity, thus we will substitute the values in the above formula:

11 m/s = 6 m/s + a (8 s)11 m/s - 6 m/s = 8 a5 m/s = 8 a  a = 5/8 m/s²

This is the acceleration of the train when it speeds up to 11 m/s in 8 seconds.

Now, we need to find the distance travelled by the train in 16 seconds when it is accelerating with the same acceleration.

We will use the kinematic equation of motion:

s = ut + (1/2) at²

Where,s = Distance travelled u = Initial velocity (11 m/s)t = Time taken (16 s)a = Acceleration

We know the value of initial velocity, time taken, and acceleration, thus we will substitute the values in the above formula:s = (11 m/s)(16 s) + (1/2) (5/8 m/s²)(16 s)²s = 176 m + 80 m  s = 256 m.

Therefore, the distance travelled by the train when it is accelerating for another 16 seconds with the same acceleration is 256 meters.

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Answer:

Average speed \(= 2.5\) meter per second

Explanation:

Given

The total distance walked \(= 2250\) meters

The total time taken to walk \(2250\) meters is \(15\) minutes

In one minute there are \(60\) seconds

As we know Average speed is equal to total distance travelled divided by total time taken

Hence,

Average speed

\(\frac{2250}{15*60} \\2.5\)meter per second

Answer:

I KNOW THE ANSWER IT WILL COST 30$

Explanation:

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

0.1 m/s (or 100 cm/s)

Explanation:

At the first point on the graph’s faded grid, the object has traveled 1 meter in 10 seconds. At the next point, the object traveled 2 meters in 20 seconds. This is a 1 to 10 ratio, or 1/10, which is 0.1 in decimal format.

(a) The normal force of the wooden box of mass 25 kg is 245 N (b) The friction force of the wooden box of mass 25 kg is 49 N.

The normal force is an everyday force that is felt when a surface pushes against an object that is placed on that surface.

To find the normal force of the wooden box, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

(b) Similarly, to calculate the friction force, we use the formula below.

Fromula:

Where:

From the question,

Given:

Substitute into equation 2

Hence, (a) The normal force is 245 N (b) The friction force is 49 N.

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4764 joule is potential energy associated with the spring-nugget system

Potential energy ,P =mgh

mass= 286 kg

g=9.8 m/s^2

h= 1.70 m

P =mgh

P=×286 kg×9.8×1.70

P=4764 joule

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or extended, its potential energy increases. If a steel ball is lifted above the ground as opposed to falling to the ground, it has higher potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has greater potential energy as they get further apart.

Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.

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The scale will read a weight of 463.5 N during the elevator's acceleration.

To calculate the weight that the scale reads during the elevator's acceleration, we need to consider the forces acting on the child.

Weight is a force caused by the gravitational pull of the Earth on an object. It is given by the formula:

Weight = mass × gravitational acceleration

The mass of the child is given as 45.0 kg. The gravitational acceleration is approximately 9.8 m/s² on the surface of the Earth.

However, during the elevator's acceleration, there will be an additional force acting on the child due to the acceleration. This force is given by Newton's second law:

Force = mass × acceleration

In this case, the acceleration is the difference in velocity divided by the time taken, which is (3.0 m/s - 1.0 m/s) / 4.00 s = 0.5 m/s².

So, the additional force acting on the child during the acceleration is:

Additional Force = mass × acceleration = 45.0 kg × 0.5 m/s² = 22.5 N

Now, we can calculate the total force acting on the child, which includes both the weight and the additional force:

Total Force = Weight + Additional Force

Since the weight is equal to mass × gravitational acceleration, we can rewrite the equation as:

Total Force = mass × gravitational acceleration + Additional Force

Total Force = (45.0 kg × 9.8 m/s²) + 22.5 N

Total Force = 441 N + 22.5 N

Total Force = 463.5 N

Therefore, the scale will read a weight of 463.5 N during the elevator's acceleration.

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A) The rover’s coordinates and its distance from the lander at t = 2.0 s are; (1, 4) and 4.1 m

B) The rover’s displacement and average velocity vector during the interval are; s = (-1, 4) and v = (-0.5, 2) m/s

C) The magnitude and direction of the instantaneous velocity are; 2.24 m/s and 117°

The rover's x and y coordinates are given as;

x = 2.0m − (0.25 m/s²)t²

y = (1.0m/s)t + (0.25 m/s³)t³

A) At t = 2 s, the rovers coordinates are;

x = 2.0m − (0.25 m/s²)2²

x = 1 m

y = (1.0m/s)2 + (0.25 m/s³)2³

y = 4 m

Distance from the lander is;

s = √[(1 - 2)² + 4²]

s = 4.1 m

B) Let us first find the distance coordinates for the interval t = 0.0 s to t = 2.0s. Thus;

s = r - r₀

s = (1 - 2), (4 - 0)

s = (-1, 4)

Thus, average velocity vector is;

v = ¹/₂s

v =  ¹/₂(-1, 4)

v = (-0.5, 2) m/s

C) A general expression for the instantaneous velocity components is;

v_x = -0.5t

v_y = 1 - 0.75t²

Thus, v(2) is;

v_x = -0.5(2) = -1

v_y = 1 - 0.75(2)²

v_y = -2

Instantaneous velocity vector is; v = (-1, -2)

Magnitude of instantaneous Velocity = √(-1² + -2²) = 2.24 m/s

Direction = 180° - tan⁻¹(-2/-1) ≈ 117°

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The inverse of the mass is referred to as acceleration. The acceleration will be slower the more mass there is.

Acceleration is the rate of change in an object's velocity over time in mechanics. One of the vector quantities is speed. The direction of the net force exerted on an object is what determines its acceleration. The change in velocity rate is referred to as acceleration. Usually, but not always, acceleration implies a change in velocity.

A circular object moving at a constant velocity is still accelerating because its velocity is changing in the opposite direction. In physics, acceleration is the rate of change in an object's velocity over time.  According to Newton's second law, the sum of all forces acting on an object determines its acceleration. Meters per second (ms²) is the SI unit for acceleration.

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Answer:

the powar produced is 0.7 watts

To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

b)

We know that the impulse is related to the momentum as:

and to the force by:

which means that:

But we know that the collision is elastic which means that the velocity after the colision has the same magnitude than before the collison but with opposite sign, hence:

Plugging the values given we have that:

Therefore, the velocity right after the rebound is 11.177 m/s

c)

To determine how high in meters the ball will travel after the rebound we need to remember that the force acting on the ball is that of its weight which means that its acceleration is the acceleration of gravity and hence, the motion is an uniformly accelerated motion. Since we know the initial velocity, the acceleration and the final velocity (which will be zero at the highest point) we can use:

To find the height; plugging the values we have that:

Therefore, the ball will reach a height of 6.374 m

\(P_{allow}\) = π²/ \(l_{eff^{2} }\) x E\(I_{min}\)

\(\frac{P}{N}\) = (π²/ 10²) x 29000 x \(\frac{1}{12}\) x 0.8 x 0.2³

\(\frac{P}{2}\) = 1.52649

P = 3.05299 kip

Buckling is defined as the sudden failure of a structural member under high compressive stress, where the actual compressive stress at the point of failure is less than the ultimate compressive stresses that the material can withstand.

The maximum load, also known as the critical load, causes the column to be in an unstable equilibrium, which means that even the slightest lateral force will cause the column to fail by buckling. The maximum axial load that a long, slender, ideal column can support without buckling is given by Euler's formula.

In architecture and structural engineering, a column or pillar is a structural element that transmits the weight of the structure above to other structural elements below through compression. A perfect column is one that is straight, homogeneous, and free of initial stress.

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Answer:

Explanation:

An electric dipole is formed by two point charges +q and −q connected by a vector a. The electric dipole moment is defined as p = qa

Answer:

B. For a gas in a closed container at a constant temperature, the product of the pressure and the volume remains constant.

Explanation:

The rest are societal laws, as they are telling you something you should avoid or follow.

Hope this helps :)

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Answer: Steeper slopes mean lower speeds.

Explanation:

Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

Answer:

They both have the same total K.E at the bottom

Explanation:

This Is because If assuming no work is done by non conservative forces, total mechanical energy must be conserved

So

K1 + U1 = K2 + U2

But If both hoops start from rest, and and at the bottom of the incline the level for gravitational potential energy is zero for reference

thus

K1 = 0 , U2 = 0

ΔK = ΔU = m g. h

But if the two inclines have the same height, and both hoops have the same mass m,

So difference in kinetic energy, must be the same for both hoops.

The time that was taken for the movement of the item is observed as 3 seconds.

The equations of motion describe the motion of objects in terms of their position, velocity, acceleration, and time.

For the equation;

v = u + at

This equation relates the final velocity (v) of an object to its initial velocity (u), acceleration (a), and time (t). If three of these variables are known, the equation can be rearranged to solve for the unknown variable.

We know that;

v = u - gt

We know that the object would come to rest after being thrown.

0 = 30 - 10t

-30 = - 10t

t = 3 seconds

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Explanation:

5.4 m = 1s2

? = 784 s2

(5.4 * 784)/1

= 4,233.6 m/s2

Answer:

Height of the ramp

Explanation:

The independent variable is always what the person doing the experiment can change or modify.  So if the question is about whether the height of the ramp with  effect the car, that is indeed what they are changing or modifying in the experiment.

Answer

.0003

Explanation:

Answer:

Weather is the conditions (temperature, wind etc.) at a given time, like on that day. Climate, which is what his data would show, is the conditions over an extended period of time like the 3 months he collected data

Answer:

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