A tourist purchases a car in England and ships it home to the United States. The car stickers advertised that the car's fuel consumption was the rate of 40 miles per gallon on the open road.
The tourist does not realize that the U.K. gallon differs from the U.S. gallon:
1 U.K. gallon =4.546 090 0 litres
1 U.S. gallon =3.785 411.8 litres
For a trip of 750 miles (in the United states), how many gallons of fuel does the mistaken tourist believe she needs ?

Answers

Answer 1

The actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.

What is  fuel ?

Fuel is a material that is burned or used to produce energy. It can come in many forms, including gasoline, diesel, propane, wood, coal, natural gas, and oil. Fuel can be used to power engines to move vehicles, generate electricity, and heat homes and buildings. It is a necessity of modern life, as it is required to power many of the machines, appliances, and systems that make our lives easier. Without fuel, transportation, communication, and many other essential services would be impossible. Fuel is often divided into two categories, renewable and non-renewable.

The tourist mistakenly believes that she needs 18.75 gallons of fuel for a trip of 750 miles. This is calculated as follows:

750 miles/40 miles per gallon = 18.75 gallons

However, since the tourist is using a U.K. gallon, which is larger than a U.S. gallon, the actual amount of fuel needed is less. To do the conversion, we need to convert the 18.75 gallons to litres and then back to U.S. gallons:

18.75 U.K. gallons x 4.546090 litres/U.K. gallon = 85.22 litres

85.22 litres/3.785411.8 litres/U.S. gallon = 22.54 U.S. gallons

Therefore, the actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.

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Related Questions

Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

Learn more about Photovoltaic detection

To determine the coefficient of static friction between two materials, an engineer places a small sample of one material on a horizontal disk whose surface is made of the other material and then rotates the disk from rest with a constant angular acceleration of 0.4 rad/s2. If she determines that the small sample slips on the disk after 9.903 s, what is the coefficient of friction

Answers

This question is incomplete, the missing image is uploaded along this answer.

Answer:

the coefficient of friction is 0.32

Explanation:

 Given the data in the question;

we make use of kinematic equation of motion;

ω = ω₀ + ∝t

we substitute

ω = ( 0 rad/s ) + ( 0.4 rad/s² )( 9.903 s )

ω = 3.9612 rad/s

The centripetal force acting on the sample is;

Fc = mrω²

from the image; r = 200 mm = 0.2 m

so we substitute

Fc = m(0.2 m ) ( 3.9612 rad/s )²

Fc = (3.13822 m/s²)m

we know that the frictional force between the two materials should be providing the necessary centripetal force to rotate the sample object;

f = Fc

μN = Fc

μmg = (3.13822 m/s²)m

μ = (3.13822 m/s²)m / mg

μ = (3.13822 m/s²) / g

acceleration due to gravity g = 9.8 m/s²

so

μ = (3.13822 m/s²) / 9.8 m/s²

μ = 0.32

Therefore, the coefficient of friction is 0.32

To determine the coefficient of static friction between two materials, an engineer places a small sample

Can someone please help me label this right

Can someone please help me label this right

Answers

The tension at the top of the horizontal circle is T = m (v²/r - g ).

The tension at the bottom of the horizontal circle is m (v²/r + g ).

What is the tension at the bottom and top of the rope?

The tension at the bottom and top of he rope is calculated by applying the following formula as shown below;

The tension at the top of the horizontal circle is calculated as;

T = ma - mg

T = mv²/r - mg

T = m (v²/r - g )

where;

v is the speedr is the radius of the circleg is acceleration due to gravity

The tension at the bottom of the horizontal circle is calculated as;

T = ma + mg

T = mv²/r + mg

T = m (v²/r + g )

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The complete question is below:

Find the expression for the tension at the bottom and top of the circle

A mass on a spring vibrates in simple harmonic motion at a frequency of 4.0 Hz and an amplitude of 8.0 cm. If the mass of the object is 0.20 kg, what is the spring constant

Answers

Answer:

The spring has a constant of 126.334 newtons per meter.

Explanation:

Given that mass-spring system experiment a simple harmonic motion, the angular frequency of the system as a function of frequency is:

\(\omega = 2\pi \cdot f\)

Where:

\(\omega\) - Angular frequency, measured in radians per second.

\(f\) - Frequency, measured in hertz.

Given that \(f = 4\,hz\), the angular frequency of the system is:

\(\omega = 2\pi \cdot (4\,hz)\)

\(\omega \approx 25.133\,\frac{rad}{s}\)

Now, the angular frequency can be obtained in terms of spring constant and mass. That is:

\(\omega = \sqrt{\frac{k}{m} }\)

Where:

\(k\) - Spring constant, measured in newtons per meter.

\(m\) - Mass, measured in kilograms.

The spring constant is now cleared:

\(k = \omega^{2}\cdot m\)

If \(\omega = 25.133\,\frac{rad}{s}\) and \(m = 0.20\,kg\), the spring constant is:

\(k = \left(25.133\,\frac{rad}{s} \right)^{2}\cdot (0.20\,kg)\)

\(k = 126.334\,\frac{N}{m}\)

The spring has a constant of 126.334 newtons per meter.

an electric kettle takes 2kw at 240v. Calculate the current and the resistance of the heating element

Answers

The power output is given 2000 watt and voltage is 240 v. Then the current through the heating element is 8.3 A and the resistance is 29 ohms.

What is power ?

The power used by an object is the rate of its work done or energy. It is the energy divided by time. The power output in a circuit is the product of the potential difference V and current I.

P = I V

Given,

P = 2 kw = 2000 W

v = 240 V.

Then I = P/v

I = 2000 w/240 v = 8.3 A.

According to Ohm's law, voltage v is the product of the current and resistance through the material.

hence,

V = I R

then, R = V/I

R = 240 V/8.33 A

  = 29 Ω.

Therefore, the current and resistance through the heating element are 8.3 A and 29 ohms respectively.

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What is the wavelength of a wave with a frequency of 466 Hz and a speed of 343 m/s?

Answers

Explanation:

The formula to calculate wavelength is: wavelength = speed / frequency.

Using the values you provided, we can calculate the wavelength as follows:

wavelength = 343 m/s / 466 Hz = 0.737 meters (rounded to three decimal places).

Therefore, the wavelength of the wave is approximately 0.737 meters.

Eclipses of the sun and moon are best explained by which of the following?

The irregular shape of the orbits of Earth and the moon


The rotation of Earth and the moon on their axis


The revolution of Earth and the moon around the sun

The different chemical compositions of the sun and the moon

Answers

Answer:

Eclipses of the Sun and Moon are best explained by the revolution of Earth and the Moon around the Sun.

Explanation:

An eclipse is the covering of a star by another celestial body.  In everyday language, an eclipse usually means a solar or lunar eclipse.

When the sun, moon and earth are aligned (in this order), the sun is covered by the moon when viewed from a place on earth. The sunlight will then no longer reach the earth. In other words, part of the earth has been eclipsed by the moon. This is referred to as a solar eclipse.

If the earth is between the sun and the moon, and thereby prevents sunlight from reaching the moon, then there is a lunar eclipse. After all, seen from the moon, the earth covers the sun. The moon is then eclipsed by the earth.

HELPP

im not exactly sure what to put

HELPPim not exactly sure what to put

Answers

Explanation:

between 0 and 2 hours the relationship between time and distance traveled is a linear one.

that means that the velocity (= distance/time like in km/s) is constant (and not increasing).

and because between the hours 2 and 3 there is no increase in distance, this means the car stood still during that time. so, no, it was not always in motion during the voyage.

therefore,

option 2 is correct (as described, no change in distance means no motion or zero velocity).

and option 3 is correct, because also between hours 3 and 5 the function is linear and the speed ratio is therefore constant.

A plane is flying to Minnesota with a velocity of 277.73 km/h, N. The plane
encounters a crosswind with a velocity of 71.97 km/h, W. What is the magnitude of
the resultant velocity of the plane? (Answer in km/h)

Answers

Answer:

466 km/h

255°

measured anticlockwise from the east direction

Explanation:

find the resultant velocity of a plane after a crosswind affects its motion. take the positive

x -direction as east, and the positive y -direction as north. The components of the plane's velocity (without wind) are

upx = 0upy =  450 Km/ h

And for the wind.

uwx = - 120 Km/huwy = 0

The components for the resultant velocity of the plane are given by

ux =upx + uwx = 0 - 120 Km/h =  - 120 Km/huy = upy + uwy  = - 450 Km/h +0 = - 450 Km/h

The magnitude of the resultant velocity is

\(\sqrt{(vx)^2+(vy)^2} =\sqrt{(-120lkm/h^2+(-450lkm/h)^2}\)

= 466 km/h

Hope this helps u : )

The side of a cube of metal is measured to be (1.00±0.06) cm and its mass is measured to be (41.0±0.4) g. Determine the uncertainty in the density of the solid in kilograms per cubic meter.

Answers

The density of the solid is (4.10 ± 0.78) × 10^3 kg/m^3.

To calculate the density of the cube below formula can be used:

ρ = m/V

where ρ is density, m is mass, and V is volume. For a cube, the volume is given by:

V = (side)^3

Therefore, the uncertainty in density can be calculated using the formula:

δρ/ρ = sqrt[(δm/m)^2 + 3(δs/s)^2]

where δρ is the uncertainty in density, δm is the uncertainty in mass, δs is the uncertainty in side, and s is the value of the side.

Now, putting in the given values:

s = (1.00 ± 0.06) cm = 0.01 ± 0.0006 m

m = (41.0 ± 0.4) g = 0.0410 ± 0.0004 kg

Volume, V = (0.01 m)^3

                  = 1.0 × 10^-6 m^3

Therefore, the density is:

ρ = m/V

  = 0.0410 kg/1.0 × 10^-6 m^3

  = 4.10 × 10^4 kg/m^3

Now substituting the values and calculating the uncertainty in density:

δρ/ρ = sqrt[(δm/m)^2 + 3(δs/s)^2]

δρ/ρ = sqrt[(0.0004/0.0410)^2 + 3(0.0006/0.01)^2]

δρ/ρ = 0.019

Therefore, the uncertainty in density is:

δρ = (0.019)(4.10 × 10^4 kg/m^3)

     = 779 kg/m^3

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how does cool roofs help the co2?

Answers

Answer:

These cool down not only the house but even helps with the potential of canceling the heating effect of up to two years of worldwide carbon dioxide emissions. Which would over help the co2 rates.

A spring with constant 200 N/m is stretch 2 m. How much EPE does it have?

Answers

The displacement of a 1.5 kg mass is then determined using the formula x = F/k.  stretching a spring 2 cm from its equilibrium position need twice as much effort as stretching it a distance of x

W = 1/2kx2 = 1.96 Joules.

Does stretching a spring 2 cm from its equilibrium position need twice as much effort as stretching it 1 cm from equilibrium position?

Actually, it requires more than twice as much labour since, as the spring extends, more power is needed to do so.

The shear strength and shear modulus of a compression spring formed of music wire with a 2mm diameter are 800 MPa and 80 GPa, respectively.

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Introduction to Simple Machines
This activity will help you meet this educational goal:
You will compare and contrast information from a video with information from a text.

Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write a brief evaluation of your work.
Activity
Watch this video and then answer the following questions based on what you learned.

Part A
How does a bicycle make work easier?





Part B
Which two examples of levers are mentioned in the video?








The picture shows a bicycle’s pedals. Look at the shaft that the pedals are attached to. Do you think the shaft is a lever? Why or why not?

Answers

Answer:

word for word answers!

Explanation:

1) Part A: By pedaling a bicycle lightly, the rider can go a long way

2) Part B: The two examples mentioned in the video are the handlebars and the brakes

3) Yes, it’s a type of lever because the two pedals rotate around a fixed point

Light from red, green and blue spotlights shine on asheet of paper. The paper contains cyan and magentapigments. Which of the three primary light colors will bereflected by the pigments?1.Red and Green2.Red3.Red and Blue4.Blue and Green5.Green6.Blue

Answers

Given:

Light from red, green and blue spotlights shine on a sheet of paper.

The paper contains cyan and magenta pigments.

To find:

The reflected pigments

Explanation:

We know, magenta is a mixture of red and blue colour and cyan is a mixture of blue and green colour.

Magenta will reflect the red and blue while cyan will reflect the blue and the green colours.

But the blue colour is common among the two colours so, neither magenta nor the cyan will absorb the blue colour.

Hence, the reflected pigment is blue only.

An adjustable tennis ball launcher launches tennis balls into the air from level ground and that return to level ground. The tennis balls are first launched with an initial velocity (vi) of 8.0 meters per second at an angle of 50° above the horizontal. The ball has an initial horizontal velocity of 5.1 meters per second. [Neglect friction.]
Calculate the vertical component of the ball’s initial velocity.
Calculate the maximum height reached by the ball.
Calculate the time elapsed to reach its maximum height.
Calculate the total horizontal distance travelled during its flight.

Answers

Answer:

Explanation:

I just need points

Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?

Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 areopen, i leads e by 30.

Answers

Based on the information, it should be noted that the resistance R is 0.5 Ω.

How to calculate the resistance

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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A particle moves in a straight line with an initial velocity of 37 m/s and a constant acceleration of 20 m/s2. If at t = 0, x = 0, what is the particle's position (in m) at t = 6 s?

A particle moves in a straight line with an initial velocity of 37 m/s and a constant acceleration of

Answers

Answer:

582 m

Explanation:

Given:

v₀ = 37 m/s

a = 20 m/s²

t = 6 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (37 m/s) (6 s) + ½ (20 m/s²) (6 s)²

Δx = 582 m

A 0.05 kg bullet strikes a 1.3 kg box and displaces it by a height of 4.5 m. After hitting
the box, the bullet becomes embedded and remains inside the box. Find the velocity of the bullet-block system after it's hit.
(a) 6.76 m/s
(b) 5 m/s
(c) 9.39 m/s
(d) 7.67 m/s

Now use the above velocity (of the bullet-block system) to find the bullet's velocity before it hit the box.
(e) 196.76 m/s
(f) 100.07 m/s
(g) 209.39 m/s
(h) 253.53 m/s

Answers

Answer:

Explanation:

The answer is **(c) 9.39 m/s** for the velocity of the bullet-block system after it's hit, and **(g) 209.39 m/s** for the bullet's velocity before it hit the box.

The velocity of the bullet-block system after it's hit can be found using the conservation of energy. The potential energy of the box before it was hit is mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height that the box was displaced. After the bullet hits the box, the potential energy of the box is zero, but the kinetic energy of the bullet-block system is mv^2/2, where m is the total mass of the bullet-block system and v is the velocity of the bullet-block system. Setting these two expressions equal to each other, we get:

```

mgh = mv^2/2

```

Solving for v, we get:

```

v = sqrt(2mgh)

```

In this case, we have:

* m = 0.05 kg + 1.3 kg = 1.35 kg

* g = 9.8 m/s^2

* h = 4.5 m

So, the velocity of the bullet-block system after it's hit is:

```

v = sqrt(2 * 1.35 kg * 9.8 m/s^2 * 4.5 m) = 9.39 m/s

```

The velocity of the bullet before it hit the box can be found using the conservation of momentum. The momentum of the bullet before it hit the box is mv, where m is the mass of the bullet and v is the velocity of the bullet. After the bullet hits the box, the momentum of the bullet-block system is (m + M)v, where M is the mass of the box and v is the velocity of the bullet-block system. Setting these two expressions equal to each other, we get:

```

mv = (m + M)v

```

Solving for v, we get:

```

v = mv/(m + M)

```

In this case, we have:

* m = 0.05 kg

* M = 1.3 kg

* v = 9.39 m/s

So, the velocity of the bullet before it hit the box is:

```

v = 0.05 kg * 9.39 m/s / (0.05 kg + 1.3 kg) = 209.39 m/s

```

The velocity of the bullet-block system after the collision is approximately a) 6.76 m/s, and the bullet's velocity before it hit the box is approximately e) 196.76 m/s.

To solve this problem, we can apply the principle of conservation of momentum and the principle of conservation of mechanical energy.

First, let's calculate the velocity of the bullet-block system after the collision. We can use the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Let m1 be the mass of the bullet (0.05 kg) and m2 be the mass of the box (1.3 kg). Let v1 be the velocity of the bullet before the collision (which we need to find) and v2 be the velocity of the bullet-block system after the collision.

Using the conservation of momentum:

m1 * v1 = (m1 + m2) * v2

0.05 kg * v1 = (0.05 kg + 1.3 kg) * v2

0.05 kg * v1 = 1.35 kg * v2

Now, let's calculate the velocity of the bullet-block system (v2). Since the system goes up by a height of 4.5 m, we can use the principle of conservation of mechanical energy.

m1 * v1^2 = (m1 + m2) * v2^2 + m2 * g * h

0.05 kg * v1^2 = 1.35 kg * v2^2 + 1.3 kg * 9.8 m/s^2 * 4.5 m

Now, we can substitute the value of v2 from the momentum equation into the energy equation and solve for v1.

By solving these equations, we find that v1 is approximately 196.76 m/s.

Therefore, the bullet's velocity before it hit the box is approximately 196.76 m/s. (e) 196.76 m/s

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Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of
strength-training
is Laasya performing?

Answers

Laasya is performing resistance training by lifting a table and moving it to another room to expand the space in her room. The correct option to this question is D.

Strength training By putting your muscles up against resistance, resistance training builds muscle strength. Free weights, weight machines, resistance bands, and your own body weight are all used in various types of resistance training. To get the most out of their training, beginners should go two or three times per week.Resistance training is founded on the idea that, when called upon, the body's muscles will struggle to overcome a resisting force. Resistance exercise has both advantages and disadvantages.Resistance exercises include planks, sit-ups, squats, push-ups, leg raises, and leg extensions. You and a small amount of room are all that are needed for these strength training exercises.

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Complete question : Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of strength-training is Laasya performing?

a. Endurance

b. Isometric

c. Isotonic

d. Resistance

Calculate the size of the magnetic field 20 m below a high voltage power line. The line carries 450 MW at a voltage of 300,000 V. Group of answer choices 0.237 T 0.0237 T 0.474 T 2.37 T 0.237 J

Answers

Answer:

\(1.5 \times 10^{-5} \mathrm{~T}\).

Explanation:

Power carried by the line \(=P=450 \mathrm{MW}=450 \times 10^{6} \mathrm{~W}\)

Voltage across the line Volts

Current flowing in the line =i

Size of magnetic field =B

Distance from the line

Formula Used:

Current flowing is given as

\(i=\frac{P}{\Delta V}\)

Magnetic field by the current carrying wire is given as

\(B=\left(\frac{\mu}{4 \pi}\right)\left(\frac{2 i}{r}\right)\)

Inserting the values

 \(B=\left(10^{-7}\right)\left(\frac{2(1500)}{(20)}\right) \\ B=1.5 \times 10^{-5} \mathrm{~T}\)

Conclusion:

Thus, the magnetic field comes out to be \(1.5 \times 10^{-5} \mathrm{~T}\).

Two optically flat glass plates, 16.0 cm long, are in contact at one end and separated by 0.0200 mm at the other end. The space between the plates is occupied by oil with index of refraction 1.45. The index of refraction of the glass plates is 1.55. The plates are illuminated at normal incidence with monochromatic light, and fringes are observed. If the dark fringes are spaced 2.00 mm apart, what is the wavelength of the monochromatic lig

Answers

Answer:

The wavelength of monochromatic light is - 725nm

Explanation:

Lets calculate -

Given - The dark fringes are  2.0mm wide and the glass plate is 16.0cm

 Thus , the number of fringes is - \(n=\frac{16cm}{0.2mm}\)

                                  Here , converting the units into metre

                                                 = \(\frac{16m}{0.2\times10^-^3m}\)

                                                   = 80

Now , the expression used here is - \(2nt=m\pi\)

        Putting the given values,

                    \(2\times (1.45)\times(2.0\times10^-^3)=80\pi\)

                     \(\pi =\frac{2\times1.45\times2.0\times10^-^3}{80}\)

                     \(\pi =7.25\times10^-^7m\)

                      \(=725\times10^-^9m\)

                       =725nm

Therefore , the answer is 725nm .                            

The wavelength of the monochromatic is mathematically given as

\(\pi =725nm\)

Wavelength of the monochromatic

Question Parameters:

Two optically flat glass plates, 16.0 cm long,

The space between the plates is occupied by oil with index of refraction 1.45.

The index of refraction of the glass plates is 1.55.

Generally the equation for the    number of fringes is is mathematically

given as

\(n=\frac{16}{0.2}\)  convert to m

n=80

Therefore

\(2* (1.45)*(2.0*10^-^3)=80\pi\\\\ \pi =7.25*10^-^7m\)

\(\pi =725nm\)

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A dead body was found at 10pm. The internal boy temperature was 68 OF. What was the time of death?

Answers

I think the answer would be 13 hours

does the mass of a parachute affect terminal velocity?

Answers

Answer:

The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.

In 2001, the moose population in a park was measured to be 4,850. By 2009, the population was measured again and was found to be 5,890. Assume the population continues to change linearly.
(a) Find a formula for the moose population, P, since 2001. (Let t represent the number of years since 2001.)

b) What does your model predict the moose population to be in 2017?
moose

Answers

Answer:

Explanation:

Letting 2001 equate to t=0 for our starting point

We started at (0, 4840) and 8 years later we are at (8, 6200)

4840 + 8t = 6200    The population went from 4840 to 6200 over 8 years.

Subtract 4840 from both sides

8t = 6200 - 4840

8t = 1360

divide both sides by 8 to isolate t

t = 1360/8

t = 170

The population rises by 170 moose per year

P(t) = 170t + 4840

b)  In 2020... t = 2020 - 2001 = 19 years

   P(t) = 170t + 4840

   P(t) = 170(19) + 4840

   P(t) = 8070

By our linear model there should be approximately 8070 moose by 2020.

******************************************

You could also take the two initial points (0, 4840), (8, 6200)

and find the slope m to set up the equation in

slope intercept form  y = mt + b

where m is the slope and the point (0,b) = (0, 4840) is y-intercept.

m = (rise/run) = (6200-4840)/(8-0) = 170

y(t) = mt + b = 170t + 4840

There is another, probably easier, way to find the "245" for this

problem.  We have two points (0, 4240) and (8, 6200)

We can use that to find the slope of our equation to set up the

equation in slope intercept form of  y = mx + b... or, in this case

y = mt + b   since y is a function of t

m = slope of the line, and the point (0,b) is the y-intercept = (0, 4240)

m = (change in y)/(change in t)  = (6200-4240)/(8-0) = 1960/8 = 245

We can then set up our equation y = mt + b

using 245 for m, and 4240 for b

y = 245t + 4240

fred (mass 60 kg ) is running with the football at a speed of 5.9 m/s when he is met head-on by brutus (mass 130 kg ), who is moving at 4.3 m/s . brutus grabs fred in a tight grip, and they fall to the ground.

Answers

They slide up to 0.0756 meters to the opposite direction.

What is Velocity ?

Velocity is a vector quantity that describes the rate of change of an object's position. It is equal to the displacement of an object divided by the time interval over which the displacement occurred. Velocity has both magnitude and direction, and its units are typically meters per second (m/s).

The velocity of an object can change over time due to acceleration, and if an object is moving in a circular path, it also has a component of velocity perpendicular to its direction of motion, known as centripetal velocity.

Conservation of momentum:

        60x6 -120x4 =180.v

              v = 120/180 = 2/3 m/s

After falling,

            Kinetic energy = work done against friction

             K=  0.5x180x(2/3)2 = 40 J

Work done against friction,

                       W = f.S = μ.(M +m)g.S = 0.3 x 180x9.8 x S

                            = 529.2 x S

Equating W = K and solving,

                      S = 40/529 = 0.0756 m= 7.56 cm

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What is the moment of inertia of the wheel?

What is the moment of inertia of the wheel?

Answers

The moment of inertia of the wheel is calculated as 0.0125 kg m².

What is moment of inertia?

Moment of inertia is a measure of any object's resistance to the rotational motion, similar to how mass is a measure of object's resistance to linear motion. Moment of inertia depends on the distribution of mass in the object and axis of rotation.

Moment of inertia of a solid cylinder rotating about its central axis is: I = (1/2) * M * R²

M is mass of the wheel and R is its radius.

So I = (1/2) * 1.41 * (0.130 )²

I = 0.0125 kg m²

Therefore,  moment of inertia of the wheel is 0.0125 kg m².

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A ball is dropped from the top of a 82-m-high building. What speed does the ball have in falling 3.6 s?

Answers

The speed of the ball have in falling 3.6 s is 35.5 m/s.

What is the speed of the ball?

The speed of the ball is calculated using the equation of a body falling under the influence of gravity or velocity of free fall.

The equation of the motion of the body is given as follows:

v = u - gt

where;

u is the initial velocity

g = acceleration due to gravity

t = time

v = final velocity

Assuming u = 0 m/s, g = 9.8 m/s², t = 3.6 s

v = 0 - 9.8 * 3.6

v = 35.5 m/s

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Which statements correctly describe the effect of distance in determining the gravitational force and the electrical
force? Check all that apply.
The gravitational force has an infinite reach.
The electrical force has an infinite reach.
The gravitational force is inversely proportional to the distance.
U The electrical force is inversely proportional to the distance.
O The gravitational force is inversely proportional to the square of the distance.
O The electrical force is inversely proportional to the square of the distance.

Answers

The statements 1,4 and 5 accurately describe the influence of distance on gravitational and electrical forces.

What is Newton's law of gravity?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Decreasing the distance would increase the gravity of the planet.

The following statements accurately describe the influence of distance on gravitational and electrical forces.

1. The gravitational force has an infinite reach.

4. The gravitational force is inversely proportional to the square of the distance.

5. The electrical force is inversely proportional to the square of the distance.

Hence, options 1,4 and 5 are correct.

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After an initial test run Mike determines that his pump does 240 J of work (W1). Calculate the amount of work (W2) in J that Mike would expect his pump to do if its volume were 3.5 times greater.

Answers

The Pump has a 240 J of work in normal condition. The change in volume of work will decrease the work performance of pump,

Since water discharge is equal to volume: \(Q=\frac{V}{t}\)

And Power is equal to Work: \(P=\frac{J}{s}\)

Then if the volume were 3.5 greater, than the Work of Pump will be 3.5 less than before, around 68.75 J

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In a baseball game, Joseph hits a ball to the outfield. When does the ball have the most potential energy?

A. when the ball is caught
B. when the bat hits the ball
C. when the ball reaches its greatest velocity
D. when the ball reaches its highest point

Answers

It has the greatest Potential energy when the ball reaches its highest point.The correct option is D

What is potential energy?

Potential energy is the energy that an object possesses due to its position or state, which can be converted into work or kinetic energy when acted upon by a force.

There are three types of Potential Energy such as :

Elastic Potential Energy: Anything that can act like a spring or a rubber band can have elastic potential energyGravitational Potential Energy: There is a constant attractive force between the Earth and everything surrounding it, due to gravityChemical Potential Energy.

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Answer:

1) PE=mgh

2)when the ball reaches its highest point

3)21,599,200 J

4) The object’s mass, gravity, and height determine its potential energy.

5)Members of a team work together to create a plan, and then members choose different tasks to carry out the plan.

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