a threat to internal validity occurs only if a potential design confound varies _________with the independent variable. group of answer choices spontaneously especially systematically haphazardly

Answer:

15% because it's 15 out of 100

Sarah's company started out with a $350 value and is currently changing at a rate of $100 annually.

The annual fee is expressed as an equation in slope-intercept form:

y = 100x + 350.

y = mx + b, where m is the line's slope and b is its y-intercept, is the formula for a straight line.

Given details:

The table displays the prices that Sarah charged each client during the course of her business's first two years:

Year                            Annual Dog-walking Fee

2010                            $350

2014                            $750

A.

Sarah has so increased the cost by $400 over the past four years.

For Sarah's company, its rate of change called slope will be,

m = 750 - 350 / 4

m = 100

Therefore, Sarah is raising the cost by $100 yearly.

Due to the payment she received for the first year, the calculated values of a business is $350.

B. Define x as the period of time that has passed since she began her business in 2010.

Consequently, the annual fee equation can be expressed in slope-intercept form as,

y = mx + c

where y stands for the cost she must pay after x years.

Her company's baseline value is therefore $350, and its rate of change is $100 annually.

The annual fee is expressed as an equation in slope-intercept form.: y = 100x + 350.

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Answer:

f < 3/2

Step-by-step explanation:

8f - 2 < 6f + 1

8f < 6f + 3

2f < 3

f < 3/2

In accordance with the cited statement The right option is:

snobbishness (E)

According to the passage, a scholar who has extensively researched and written on Plato argues that rather than being anti-arts, Plato was merely "elitist," or snobbish.

the tendency to belittle those with lower social standing. Synonyms: snobbism and snobbery. types: exclusivity, exclusivity, and cliquishness. tendency to hang out with only a few people.

adjective. When you criticize someone for being snobby, you are saying that they are too arrogant about their social standing, intelligence, or taste. They disapproved of their intellectual and social inferiors with a snobby dislike. She was friendly and warm, contrary to what I had anticipated.

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The approximate error in the predicted price per bushel of soybeans is approximately -0.1 dollars per bushel.

To approximate the corresponding error in the predicted price per bushel of soybeans, we can use differentials. Given that the quantity demanded per year is x = 2.1 billion bushels and there is a possible error of 10% in the forecast, we need to determine the corresponding error in the predicted price per bushel.

First, let's calculate the predicted price per bushel based on the demand equation:

p = f(x) = 53/(2x^2) + 1

Substituting x = 2.1 billion bushels into the equation:

p = 53/(2(2.1)^2) + 1

Calculating the predicted price per bushel:

p ≈ 5.6746 dollars per bushel

Next, let's calculate the differential of the demand equation:

df(x) = f'(x) dx

Where f'(x) is the derivative of f(x) with respect to x, which we can find by differentiating the demand equation:

f(x) = 53/(2x^2) + 1

Taking the derivative:

f'(x) = -53/(x^3)

Now, we can calculate the error in the predicted price per bushel by considering the possible error in the quantity demanded:

dx = 0.1x

Substituting x = 2.1 billion bushels and dx = 0.1(2.1) billion bushels:

dx ≈ 0.21 billion bushels

Finally, we can use the differential to approximate the corresponding error in the predicted price per bushel:

dp ≈ f'(x) dx

dp ≈ (-53/(x^3)) (0.21)

Substituting x = 2.1 billion bushels:

dp ≈ (-53/(2.1^3)) (0.21)

Calculating the approximate error in the predicted price per bushel:

dp ≈ -0.1038 dollars per bushel

The conclusion of this topic is that by using differentials, we can approximate the corresponding error in the predicted price per bushel of soybeans based on the forecasted harvest quantity. In this case, the demand equation for soybeans, along with the forecasted harvest of 2.1 billion bushels with a possible error of 10%, allows us to calculate the approximate error in the predicted price.

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Answer:

120 pounds

Step-by-step explanation:

65% of y= 78 pounds

\(\frac{65}{100}\) × y = 78 pounds

65y = 78  × 100=7800

y= 7800/65= 120 pounds

Answer:

3

Step-by-step explanation:

It would be multiplied by 4 to get 12

Hope this helps

423

To solve the above equation follow the BODMAS rule

That is,

Brackets of Division Multiplication Addition Subtraction

BODMAS rule states that mathematical expressions with multiple operations need to be solved from left to right in the order of BODMAS.

so,

first, calculate the value in the brackets

(144-4)*(12/4)+3 = (140)*(12/4)+3

=140*(3)+3

According to the rule, a division operation is to be performed but there is no division operation in the equation we skip this step and proceed to the next operation

so, multiply 140*3

=420+3

the next operation is the addition

=423

the next operation according to the rule is subtraction which is not required to be performed in the equation.

therefore,

(144-4)*(12/4)+3 = 423

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The value of k is 2 and the cumulative distribution function F(v) is given by F(v) = 1 - √(2/v).

To evaluate k, we need to use the fact that the total area under the density function must be equal to 1.

∫ f(y) dy = 1

Integrating the function over the given interval, we get:

∫ k/x^2 dy = ∫ kx^-2 dy from x=1 to x=2

= -kx^-1 from x=1 to x=2

= -k(1/2 - 1)

= k/2

So,

∫ f(y) dy = ∫ k/x^2 dy from x=1 to x=2 + ∫ 0 dy from y=2 to y=4

= k/2 + 0

= 1

Thus,

k/2 = 1

k = 2

So, the value of k is 2.

To find F(v), the cumulative distribution function, we need to integrate the density function over the interval (-∞,v]. Since the density function is zero for y less than or equal to zero, we have:

F(v) = ∫ f(y) dy from y = 0 to y = v

= ∫2/x^2 dy from x = √(2/v) to x = 2

= -2/x from x = √(2/v) to x = 2

= -2/2 + 2/√(2/v)

= 1 - √(2/v)

Thus, the cumulative distribution function F(v) is given by F(v) = 1 - √(2/v).

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The complete question is:
Consider the density function (10 points) f(y) ={k/x^2 < y < 4 0

d. Evaluate k.

e. Find F(v)

Answer. I think is A

Step-by-step explanation:

Answer:

First one 5n-40 what does n so n=  8

The last one I see is d+15=30 so the d=15

Step-by-step explanation:

1. 5x8-40 i think

2.15+15=30 this is right am 91.1% right about this one

Answer:

C)

Step-by-step explanation:

The correct answer is C: Tony did not use the property correctly because he did not multiply every term on both sides of the equals sign by 1/4.

To solve the equation 4x = 12x + 20, Tony used the multiplicative property of equality but made an error in the application. The correct approach would be to multiply every term on both sides of the equals sign by the reciprocal of the coefficient of x, which is 1/4 in this case.

However, Tony only multiplied one term on each side by 1/4, resulting in equation x = 3x + 20. This action is incorrect because it does not apply the property to every term containing x. To solve the equation correctly, Tony should have multiplied both sides by 1/4, resulting in x/4 = (3x + 20)/4.

Answer:

Step-by-step explanation:

Draw altitudes from A and D to get two 30°-60°-90° triangles.

The sides of a 30°-60°-90° triangle are in the ratio 1:√3:2.

BC = 3√3 + 16 + 9√3 = 16 + 12√3

Solution of the given differential equation is Y_p(x) = e^(-2x)((4/5)x² - (8/5)x), obtained using the method of exponential shift and expanding the resulting inverse differential operator into an infinite series.

To find a particular solution of the differential equation Y'' + 2y' + 5y = (8x² - 8x² + 4x + 4)e^(-2x).

We can use the method of exponential shift by introducing an exponential factor to the right-hand side of the equation and expanding it into an infinite series. Let's apply the method of exponential shift to find a particular solution of the given differential equation. We start by assuming a particular solution of the form Y_p(x) = e^(-2x)U(x), where U(x) is an unknown function to be determined. We then differentiate Y_p(x) twice to find Y_p''(x) and Y_p'(x). Next, we substitute Y_p(x), Y_p'(x), and Y_p''(x) into the original differential equation, yielding e^(-2x)U'' + 2e^(-2x)U' + 5e^(-2x)U = (8x² - 8x² + 4x + 4)e^(-2x). Simplifying, we have e^(-2x)U'' + 2e^(-2x)U' + 5e^(-2x)U = 4x + 4.

Now, we can multiply the entire equation by e^(2x) to remove the exponential factor. This leads to U'' + 2U' + 5U = 4xe^(2x) + 4e^(2x). To solve this equation, we use the method of undetermined coefficients. We assume a particular solution of the form U_p(x) = (Ax^2 + Bx + C)e^(2x), where A, B, and C are constants to be determined. We differentiate U_p(x) to find U_p'(x) and U_p''(x). Substituting U_p(x), U_p'(x), and U_p''(x) back into the equation, we obtain the following equation: (2A + 2B + 5(Ax^2 + Bx + C))e^(2x) = 4xe^(2x) + 4e^(2x).

By comparing coefficients, we can determine the values of A, B, and C. Equating the coefficients of like terms, we get 2A + 2B + 5C = 0 for the exponential terms, and 5A = 4 for the constant term. Solving these equations, we find A = 4/5, B = -2A = -8/5, and C = 0. Therefore, a particular solution of the given differential equation is Y_p(x) = e^(-2x)((4/5)x² - (8/5)x), obtained using the method of exponential shift and expanding the resulting inverse differential operator into an infinite series.

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Answer:

yw

Step-by-step explanation:

Answer:

10

please mark brainiest

Answer:

C

Step-by-step explanation:

1/18 x³y + 7/18 xy²

1/18 xy (x² + 7y)

The value of the expression  a+b = 45+8 = 53

To write (3x)² (5x⁶) in the form of ax^b, we need to simplify the expressions and multiply the coefficients and the variables separately:

(3x)² (5x⁶) = 9x² × 5x⁶ = 45x^(2+6) = 45x^8

So, the expression (3x)² (5x⁶) can be written as 45x^8 in the form of ax^b, where a=45 and b=8.

Therefore, a+b = 45+8 = 53

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The values of 65 euros is 76.70 US dollars.

To convert 65 euros to dollars, you need to know the current exchange rate between the two currencies. As of September 2021, the exchange rate is 1 euro = 1.18 US dollars.

To calculate the conversion, you can simply multiply the amount of euros by the exchange rate.

65 euros x 1.18 US dollars = 76.70 US dollars

Therefore, 65 euros is equivalent to 76.70 US dollars.

It's important to note that exchange rates can fluctuate, so the conversion may not be the same in the future. It's always best to check the current exchange rate before making a conversion.

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Therefore, the values of x in the interval 0° <= θ <= 360° that satisfy the equation sin^2(x) + 3sin(x) + 2 = 0 are x = -90° and x = 270°.

To solve the equation sin^2(x) + 3sin(x) + 2 = 0 in the interval 0° <= θ <= 360°, we can treat it as a quadratic equation in terms of sin(x). Let's solve it step by step:

sin^2(x) + 3sin(x) + 2 = 0

We can rewrite sin^2(x) as (sin(x))^2:

(sin(x))^2 + 3sin(x) + 2 = 0

Now, let's substitute sin(x) with a variable, say u:

u^2 + 3u + 2 = 0

We can factor this quadratic equation:

(u + 1)(u + 2) = 0

Setting each factor to zero:

u + 1 = 0 or u + 2 = 0

Solving for u in each case:

u = -1 or u = -2

Now, let's substitute u back with sin(x):

sin(x) = -1 or sin(x) = -2

However, the range of values for sin(x) is -1 to 1. Therefore, sin(x) cannot be equal to -2. Thus, the only solution is when sin(x) equals -1.

sin(x) = -1

We know that the sine function is equal to -1 at two angles: -π/2 and 3π/2.

To find the values of x, we convert these angles to degrees:

-π/2 radians = -π/2 * (180/π) degrees = -90 degrees

3π/2 radians = 3π/2 * (180/π) degrees = 270 degrees

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Quick sort will be guaranteed to run in O(n log n) time when the pivot element is chosen in a way that partitions the array into approximately equal halves.

Quick sort is a sorting algorithm that uses divide-and-conquer to sort an array or list of elements. The algorithm works by partitioning the array into two subarrays, one containing all elements smaller than a chosen pivot element, and the other containing all elements larger than the pivot.

The pivot element is then placed between the two subarrays and the process is repeated recursively on each subarray until the entire array is sorted.

Quick sort is generally considered to have an average case time complexity of O(n log n), which means that the algorithm will take proportional to n log n time to sort an array of n elements on average. However, in the worst case, the time complexity of quick sort can be O(n^2), which can occur when the pivot is consistently chosen as the smallest or largest element in the array, leading to an unbalanced partitioning of the array.

To guarantee that quick sort will run in O(n log n) time, it is important to choose a good pivot element that is representative of the entire array and leads to a balanced partitioning of the elements. This can be done by using a randomized pivot selection or by choosing a median-of-three pivot selection that takes the median of the first, middle, and last elements of the array as the pivot. Additionally, choosing a good partitioning scheme that minimizes the number of comparisons and swaps required can also improve the time complexity of the algorithm.

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It will take them 3 days to paint the building if they work together on it except for 1 day when the painter is ill and the apprentice works alone is the answer.

Given that a painter can paint a building in 4 days and his apprentice can do it in 6 days, the following steps can be taken to find out the time taken to paint the building when they work together on it except for 1 day when the painter is ill and the apprentice works alone.

Step 1: Let's find the painter's work efficiency.

The painter can paint a building in 4 days. It means, in 1 day, the painter can complete 1/4 of the work.(1/4) × (4 days) = 1 work done

Therefore, the painter can complete 1 work in 1 day.

Step 2: Let's find the apprentice's work efficiency.

The apprentice can paint a building in 6 days. It means, in 1 day, the apprentice can complete 1/6 of the work. (1/6) × (6 days) = 1 work done

Therefore, the apprentice can complete 1 work in 1 day.

Step 3: Let's find out their combined work efficiency.

In 1 day, the painter can complete 1 work and the apprentice can complete 1 work.

So, in 1 day, their combined work efficiency = 1 + 1 = 2 works done.

Step 4: Let's find out the time taken to complete the work if they work together on it except for 1 day when the painter is ill and the apprentice works alone. If they work together for x days (except for 1 day when the painter is ill and the apprentice works alone), then, the following equation can be formed: Painter's work done in x days + Apprentice's work done in x days = Total work to be done.

Painter's work done in x days = (1/4) × (x - 1) = (x - 1)/4.

Apprentice's work done in x days = (1/6) × x = x/6.

Total work to be done = 1.

So, the equation becomes:(x - 1)/4 + x/6 = 1.

⇒ 3(x - 1)/12 + 2x/12 = 1.

⇒ (3x - 3 + 2x)/12 = 1.

⇒ 5x - 3 = 12.

⇒ 5x = 15.

⇒ x = 3.

Therefore, it will take them 3 days to paint the building if they work together on it except for 1 day when the painter is ill and the apprentice works alone.

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The cut separates the variables from their negations, each clause will have at least one true literal, satisfying the 3SAT instance.

To show that MAX-CUT is NP-complete, we need to demonstrate two things: First, that MAX-CUT is in the NP complexity class, meaning that a proposed solution can be verified in polynomial time. Second, we need to reduce a known NP-complete problem to MAX-CUT, showing that MAX-CUT is at least as hard as the known NP-complete problem.

MAX-CUT is in NP:

To verify a proposed solution for MAX-CUT, we can simply check if the cut separates the vertices into two disjoint subsets S and T, and count the number of edges that cross the cut. If the number of crossing edges is equal to or larger than k, we can accept the solution. This verification process can be done in polynomial time, making MAX-CUT a member of the NP complexity class.

Reduction from a known NP-complete problem:

We will reduce the known NP-complete problem, 3SAT, to MAX-CUT. The 3SAT problem involves determining if a given Boolean formula in conjunctive normal form (CNF) is satisfiable, where each clause contains exactly three literals.

Given an instance of 3SAT with n variables and m clauses, we construct a graph G for MAX-CUT as follows:

Create a vertex for each variable and its negation, resulting in 2n vertices.

For each clause (a ∨ b ∨ c), introduce three additional vertices and connect them in a triangle. Label one vertex as a, another as b, and the third as c.

Connect the variable vertices with the corresponding clause vertices. For example, if the variable is x and it appears in the clause (a ∨ b ∨ c), create edges between x and a, x (negation of x) and b, and x and c.

Now, we claim that there exists a cut in G of size k or more if and only if the 3SAT instance is satisfiable.

If the 3SAT instance is satisfiable, we can assign truth values to the variables such that each clause evaluates to true. We can then define the cut by placing all true variables and their negations in one subset S, and the remaining variables and their negations in the other subset T. The number of crossing edges in the cut will be at least k, as each clause triangle will have at least one edge crossing the cut.

If there exists a cut in G of size k or more, we can use it to derive a satisfying assignment for the 3SAT instance. Assign true to all variables in subset S and false to those in subset T.

Therefore, we have successfully reduced 3SAT to MAX-CUT, showing that MAX-CUT is NP-complete. This conclusion is based on the assumption that 3SAT is already a known NP-complete problem, as stated in Problem 7.26.

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Answer:

To plot (1,5), start at the origin (0,0) and move right 1 unit and up 5 units.

(1,5)

To plot (4,−1) , start at the origin (0,0) and move right 4 units and down 1

units.

(4,−1)

List the points below:

(1,5),(4,−1)

Step-by-step explanation:

Rotation, dilation, reflection and translation are all a type of transformation.

The transformation, i.e., f: X X, is a function, f, that maps to itself. Following the transformation, the pre-image X changes into the image X. Any operation, including translation, rotation, reflection, and dilation, may be used to create this transformation.

A rectangular array of numbers is called a matrix, and different operations are provided for it. The components are arranged in vertical columns and horizontal rows.

Rotation, dilation, reflection and translation are all a type of transformation.

A rectangular array of numbers or other objects arranged in a grid position system is called a matrix.

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Step-by-step explanation:

the initial Equation :

50 + 20X = 150

it could be changed to :

20X + 50 = 150

=>

20X = 150-50

20X = 100

x = 100/20

x = 5 hours

the correct answer is option A

Answer:

T = 3.5m

T is trash in pounds

m is members of family

Step-by-step explanation:

The required expression for `f(x + h)` is `f(x + h) = x² + 2xh + h² + 3x + 3h + 1`.

Given that the function is,  `f(x) = x² + 3x + 1`.

We need to find the expression for `f(x + h)`.

To simplify the expression of `f(x + h)`, we need to substitute `x + h` in place of `x` in the given function `f(x)`.i.e., we need to replace each occurrence of `x` in the function with `(x + h)`.

Therefore, `f(x + h) = (x + h)² + 3(x + h) + 1`

Here, we need to use the formula of `(a + b)² = a² + 2ab + b²`

To expand the above expression of `f(x + h)`, we get; `f(x + h) = x² + 2xh + h² + 3x + 3h + 1`

Thus, `f(x + h) = x² + 2xh + h² + 3x + 3h + 1`.

Therefore, the required expression for `f(x + h)` is `f(x + h) = x² + 2xh + h² + 3x + 3h + 1`.

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