A tension of 1500N is applied to a 50kg wire that is 10 m long. The wavelength of the wave produced is 0.15m. a) what is the speed of the wave? b) what is the frequency of this wave ?​

Answers

Answer 1

They We'll find the speed and frequency of the Wavelength using the given tension, mass, length, and wavelength. a) To find the speed of the wave, first we need to determine the linear mass density (µ) of the wire.

The calculated using the formula µ = Mass / Length Plug in the values µ = 50 kg / 10 m = 5 kg/m Now, we can use the formula for wave speed (v): v = sqrt (Tension / µ) v = sqrt (1500 N / 5 kg/m) = sqrt (300 m²/s²) = 17.32 m/s So, the speed of the wave is 17.32 m/s. b) To find the frequency of the wave, we can use the formula that relates wave speed, frequency, and wavelength Wave speed (v) = Frequency (f) * Wavelength (λ) We know the wave speed and the wavelength, so we can solve for the frequency (f) = Wave speed (v) / Wavelength (λ) f = 17.32 m/s / 0.15 m = 115.47 Hz The frequency of the wave is 115.47 Hz.

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Related Questions

The three elements of emotion are?

Answers

Answer: Physical component- state of physiological arousal triggered by autonomic nervous system

Behavioral component- outward expression of emotion, including facial expression and behavior

Cognitive component- appraisal of the situation determine which emotion we are experiencing and why.

Explanation:

hope that helps :)

The three elements of emotions are a subjective experience, a physiological response, and a behavioral or expressive response.

What are emotions?

Emotions enable us to express our needs to others, such as when we are depressed and in need of assistance. They can also assist us in taking swift action when necessary.

For instance, panic causes you to jump back onto the curb when you're ready to cross the street, and you see a car approaching swiftly. Three components make up the “feeling” aspect of consciousness: a particular physical arousal, a particular conduct that communicates the feeling to others, and an internal awareness of the emotion.

Therefore, the elements of emotions are subjective experience, physiological response, and behavioral or expressive response.

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What's the free body diagram for:
Mr. Seifert needs to push a cardboard box down the hallway for Ms. Wang. The box has a mass of 40 kg and he is pushing it with an acceleration of 2 m/s/s. Because the cardboard does not slide easily, there is a friction force of 25 Newtons acting on the box to the LEFT. How much force is Mr. Seifert applying to the box to move it forward to the RIGHT?

Answers

(a) The free body diagram for representing all the forces acting on an object.

(b) The force Mr. Seifert is applying to the box to move it forward to the RIGHT is 105 N.

What is free body diagram?

A free body diagram is a graphical illustration of all the forces acting on an object.

The force applied by Mr Seifert is calculated by applying Newton's second law of motion as follows;

F - Ff = ma

where;

F is the applied forceFf is the force of frictionm is the mass of the cardboarda is the acceleration of the cardboard

The given parameters include;

mass of the cardboard = 40 kg

force of friction = 25 N

acceleration of the cardboard = 2 m/s²

The force applied by Mr Seifert is calculated as follows;

F = Ff + ma

F = 25 N  +    (40 kg x 2 m/s²)

F = 105 N

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1.What happens to the Angle of Refraction as the medium becomes denser? Explain why.

Answers

Answer:

Explanation:

If angle of incidence and angle of refraction be i   and r respectively ,

sini / sinr = μ ( refractive index )

sin r = sin i / μ

If angle of incidence i be constant and medium becomes denser that means μ becomes higher in value , the value of sin r will be low ( because of increase in value of denominator )

As sin r decreases , r also decreases also.

Hence when medium becomes denser , angle of refraction becomes less .

how does the internal energy of the ice and water mixture change if the temperature does not rise while the ice is melting?
a. It decreases, because you need to use energy to make freezer run; but ice melts spontaneously
b. no enough information to determine
c. it increases, because it takes more energy for water molecules to be disordered than to be ordered
d. it remains the same because both are at the same temperature

Answers

Option-d).  it remains the same because both are at the same temperature. If the temperature does not increase while the ice melts, the internal energy of the ice and water mixture changes.

A temperature is a unit of hotness or coldness that can be described in terms of a variety of arbitrary scales. It also indicates the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature). Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a considerably higher temperature than a burning match, but it has a far larger total heat energy than a match. As opposed to extensive qualities like mass or volume, which are reliant on the amount of stuff being studied, the temperature is an intensive attribute, just like pressure or density.

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A copper rod of length L = 18.0 in. is to be twisted by torques T (see figure) until the angle of rotation between the ends of the rod is 3.0°. (a) If the allowable shear strain in the copper is 0.0006 rad, what is the maximum permissible diameter of the rod? (b) If the rod diameter is 0.5 in., what is the minimum permissible length of the rod?

Answers

The maximum permissible diameter of the rod is approximately 0.208 inches. The minimum permissible length of the rod is approximately 8333.33 inches.

To determine the maximum permissible diameter of the rod, we can use the formula for shear strain:

Shear Strain = Angle of rotation / Length

Given that the allowable shear strain is 0.0006 rad and the length of the rod is 18.0 in., we can rearrange the formula to solve for the maximum permissible diameter:

Diameter = 2 * sqrt(Shear Strain * Length)

Plugging in the values:

Diameter = 2 * sqrt(0.0006 rad * 18.0 in.)

Diameter ≈ 2 * sqrt(0.0108 rad * in.)

Diameter ≈ 2 * 0.104 in.

Diameter ≈ 0.208 in.

Therefore, the maximum permissible diameter of the rod is approximately 0.208 inches.

To determine the minimum permissible length of the rod, we can rearrange the formula for shear strain:

Length = Angle of rotation / Shear Strain

Given that the diameter of the rod is 0.5 in. and the allowable shear strain is 0.0006 rad, we can calculate the minimum permissible length:

Length = (Angle of rotation * Diameter) / Shear Strain

Length = (3.0° * 0.5 in.) / 0.0006 rad

Length ≈ 5.0 in. / 0.0006 rad

Length ≈ 8333.33 in.

Therefore, the minimum permissible length of the rod is approximately 8333.33 inches.

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Magnetic domains are _____. ablocks of materials bregions that may or may not be magnetized cregions of atoms that are magnetically aligned dclusters of atoms randomly aligned

Answers

Magnetic domains are regions of atoms that are magnetically aligned, forming clusters within a material. These domains can be either magnetized or not and are the reason for the magnetic properties of ferromagnetic materials.

Magnetic domains are regions of a material in which the atomic magnetic moments are aligned in a specific direction, resulting in a net magnetic moment. These regions can be considered as small magnets with a north and south pole. In a ferromagnetic material, such as iron or nickel, the magnetic domains are aligned in the same direction, creating a strong overall magnetic field. In a paramagnetic material, such as aluminium or platinum, the magnetic domains are randomly oriented and the material does not exhibit a net magnetic moment. In a diamagnetic material, such as copper or gold, the magnetic domains have a weak opposing orientation and the material exhibits a slight repulsion in the presence of a magnetic field.

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What is the speed of an object that moves from 70 m to 68 m in 14 s?

Answers

Speed = m/s
Velocity can be negative, but speed cannot.

70 - 68 = 2
2/14 = 0.143 m/s

What is a population of cells that can be maintained for years called?

Answers

Stem cells maybe I’m not 100% sure

Stem cells is a population of cells that can be maintained for years.

What are stem cells ?

Stem cells are undifferentiated cells that have the capacity to differentiate into a wide variety of body cells.

Here,

The only cells in your body that can differentiate into other cell types, including blood, bone, and muscle cells, are stem cells. They also fix tissue that has been harmed.

Stem cells are now important in the treatment of blood cancer and blood disorders. Stem cells may potentially be used to treat a wide range of other diseases, according to medical researchers.

Stem cells are highly valuable for ageing research since they are thought to be immortal in culture. Increased proteostasis, which regulates protein quality, governs this longevity.

An association between elevated proteostasis and the immortality of human embryonic stem cells was discovered by a study team.

Hence,

Stem cells is a population of cells that can be maintained for years.

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Brainliest if right.

Show your work: A wolf chasing an elk. The wolf has a mass of 100 kg and is running with a velocity of 16 m/s
to the right. What is the wolf's momentum?
The elk has a mass of 180 kg. What does the elk's speed have to be for it to have the same momentum as the
wolf?

Answers

Answer:

The momentum of the wolf is 1600 kg×m/s

the velocity of the elk is 80/9 m/s

Explanation:

I have provided an explanation on the photo attached.

Brainliest if right.Show your work: A wolf chasing an elk. The wolf has a mass of 100 kg and is running

At a certain point on a heated metal plate, the greatest rate of temperature increase, 5 degrees Celsius per meter, is toward the northeast. If an object at this point moves directly north, at what rate is the temperature increasing

Answers

If an object at a certain point on a heated metal plate moves directly north, the rate of temperature increase can be determined by considering the direction of the greatest rate of temperature increase, which is toward the northeast.

Given that the greatest rate of temperature increase at the point is 5 degrees Celsius per meter toward the northeast, we can determine the rate of temperature increase when the object moves directly north.

Since the object is moving directly north, it is not moving in the direction of the greatest rate of temperature increase. Therefore, we need to determine the component of the temperature increase that is in the north direction.

Assuming that the temperature increase is uniform in all directions, we can use trigonometry to calculate the rate of temperature increase in the north direction. The north direction is perpendicular to the northeast direction, which means it forms a right angle.

The rate of temperature increase in the north direction can be calculated by taking the component of the rate of temperature increase toward the northeast in the north direction. Since the two directions are at a right angle, we can use the cosine function to determine this component.

Rate of Temperature Increase in the North Direction = Rate of Temperature Increase toward the Northeast * cos(90°)

cos(90°) = 0

Therefore, the rate of temperature increase in the north direction is 0 degrees Celsius per meter.

When an object at a certain point on a heated metal plate moves directly north, the rate of temperature increase is 0 degrees Celsius per meter. This is because the direction of the greatest rate of temperature increase is toward the northeast, and moving directly north does not contribute to an increase in temperature in that direction.

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the 3.0-m-long, 100 kg rigid beam of figure ex12.31 is supported at each end. an 80 kg student stands 2.0 m from support 1. how much upward force does each support exert on the beam?

Answers

The amount of upward force each support exert on the beam is  751.33 N and 1012.67 N.

What is force?

Force can be defined as the product of mass and acceleration of a body.

To calculate the upward force exerted by the beam, we apply the principle of moment.

From the diagram attached,

Taking our moment about N₂,

Mgd₁+mgd₂ = N₂L............ Equation 1

Where:

M = Mass of the beam d₁ = mid point of the beamm = Mass of the studentd₂ = Distance of the student from N₂N₂ = Supporrt 2L = Length of the beamg = Acceleration due to gravity.

From the question,

M = 100 kgm = 80 kgd₁ = 1.5 md₂ = 1 mL = 3 mg = 9.8 m/s²

Substitute these values into equation 1 and solve for N₂

N₂×3 = (100×9.8×1.5)+(80×1×9.8)3N₂ = 1470+7843N₂ = 2254N₂ =  2254/3 N₂ = 751.33 N

To calculate the First support N₁, we use the formula below.

N₁ + N₂ = mg+MgN₁ = mg+Mg-N₂N₁ = (80×9.8)+(100×9.8)-751.33N₁ = 1764-751.33N₁ = 1012.67 N

Hence, the upward force from each support is 751.33 N and 1012.67 N respectively.

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the 3.0-m-long, 100 kg rigid beam of figure ex12.31 is supported at each end. an 80 kg student stands

4. What is the amplitude of the waves shown in the diagram below?

4. What is the amplitude of the waves shown in the diagram below?

Answers

Answer:

7.5 m

Explanation:

one of the strongest earthquakes for the year was a magnitude 7.2 in Southern Peru on the Richter scale. a) Based on the image describe the FOCUS and EPICENTER of the earthquake. b) Determine the amount of energy released in ergs, and c) Determine the amount of energy released in Joules. Mag 7.2 earthquake Southern Peru Thursday, 26 May 2022 12:02 (UTC) Data: USGS Your answer Depth: 217.8km M7.2 Thu, 26 May 12:02 30 points

Answers

The magnitude 7.2 earthquake that occurred in Southern Peru had a focus located approximately 217.8 kilometers deep underground. The epicenter of the earthquake was in close proximity to the focus, indicating that the seismic activity originated at that particular location.

An earthquake's focus refers to the point within the Earth's crust where the initial rupture or release of seismic energy occurs. In this case, the focus of the earthquake in Southern Peru was situated around 217.8 kilometers below the Earth's surface. The depth of the focus is an essential characteristic to consider when analyzing an earthquake's impact and potential damage, as it influences the distribution and intensity of seismic waves.

The epicenter, on the other hand, is the point on the Earth's surface directly above the focus. It is the location typically identified on maps and used to report the earthquake's location. Since the epicenter of the earthquake in Southern Peru was not specifically mentioned in the given information, we can assume that it was close to the focus, indicating that the seismic activity originated near that area.

To determine the amount of energy released by the earthquake, we can use the seismic moment magnitude (Mw) scale, which provides a measure of the total energy released during an earthquake. The Richter scale mentioned in the question is an outdated magnitude scale and is no longer widely used.

To calculate the energy released in ergs, we can use the following formula:

Energy (ergs) = \(10^(^1^1^.^8 ^+ ^1^.^5^ *^ M^w^)\)

Substituting the magnitude value of 7.2 into the formula, we can calculate the energy released in ergs.

To determine the amount of energy released in Joules, we need to convert ergs to Joules. One erg is equal to 1 x 10\(^(^-^7^)\) Joules. Therefore, we can convert the energy value obtained in ergs to Joules by multiplying it by  1 x 10\(^(^-^7^)\) Joules.

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How are the strong winds associated with the tornado in diagram C product

Answers

Answer:

there is no diagram, but i can try to help

Explanation:

strong winds bonding together (i.e hot and cold) help form the tornado, depending on the weather depends on how long it can go on, if more hot and cold are feeds into it, it will get faster and last longer. it is just like dust devils, it is wind and dirt mixing to make a tornado, the more wind and dirt the worst it will be

What is the speed of a wave that has a frequency of 110 Hz and a wavelength
of 0.21 m?
OA. 23.1 m/s
OB. 0.04 m/s
O C. 523 m/s
OD. 0.002 m/s

Answers

The speed of the wave of wavelength 0.21 m is 23.1 m/s. And the correct answer is 0A. 23.1 m/s.

How to calculate the speed of a wave?

The speed of a wave is calculated by multiplying the wavelength and the frequency of the wave.

To calculate the speed of the wave, we use the formula below.

Formula:

s = λf......................................Equation 1

Where:

s = Speed of the waveλ = Wavelength of the wavef = Frequency of the wave

From the question,

Given:

f = 110 Hzλ = 0.21 m

Substitute these values into equation 1

s = 110×0.21s = 23.1 m/s

Hence, the speed of the wave is 23.1 m/s.

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A steel railroad track has a length of 30.000m when the temperature is 0.0∘C, the ends of the rail are rigidly clamped at 0.0∘C so that expansion is prevented. The thermal stress set up in the rail if its temperature is raised to 40.0∘C is

Answers

The thermal stress set up in the rail when its temperature is raised to 40.0∘C can be calculated using the formula:
Thermal Stress = (Coefficient of Linear Expansion) * (Change in Temperature) * (Young's Modulus)


To calculate the thermal stress, we need to know the coefficient of linear expansion and Young's modulus of the steel rail. Let's assume the coefficient of linear expansion is α and Young's modulus is Y.
Given that the length of the rail is 30.000m and the temperature change is from 0.0∘C to 40.0∘C, the change in temperature is 40.0∘C - 0.0∘C = 40.0∘C.
Assuming we have the values for α and Y, we can substitute them into the formula to calculate the thermal stress.
Thermal Stress = α * (Change in Temperature) * Y
Please provide the values for the coefficient of linear expansion (α) and Young's modulus (Y) for the steel rail so that we can calculate the thermal stress accurately.

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A 0.045-kg golf ball is dropped from rest. Is dropped from a height of 1.3m and comes back up at a height of .7m

Answers

The  time to drop from 1.3m and velocity after height at 0.7 mis mathematically given as

t1 = 0.515 sec  

v0 = 3.7m/s

What is the time to drop from 1.3m and velocity after height at 0.7?

Question Parameters:

A 0.045-kg golf ball is dropped from rest.

Is dropped from a height of 1.3m and comes back up at a height of .7m

Generally, the equation for the time to drop from 1.3m   is mathematically given as

yf - yi = vi t + a t^2/ 2

Therefore

0 - 1.3 = 0 - 9.8 t^2 /2

t1 = 0.515 sec  

Hence, after its max height is 0.7 m,

vf^2 - vi^2 = 2 a (yf - yi)

0^2 - (v0)^2 = 2(-9.8)(0.7 - 0)

v0 = 3.7m/s

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Ratan took a thin, solid piece of material. When he put it in water, it rose and floated. He took it out of the water and cut out holes in it as shown below. When Ratan puts the material with holes back in the water, what will happen?

Answers

Answer:

The material will still remain afloat.

Explanation:

The fact that the material floated on water as a solid piece means that the material is less dense than water. When a material is less dense than another liquid material, the material floats in the denser material. Cutting holes in the material will not reduce the buoyancy of the material. If the material had not floated as a single solid piece, then it will be said to be denser than the liquid material, and in such a case, if a strategic hole is cut on it to reduce its weight while maintaining its immediate volume, then it can be made to float. This is the principle behind metal floating ships.

True/False: The span of any finite nonempty subset of R n contains the zero vector.

Answers

The statement that says "The span of any finite nonempty subset of Rn contains the zero vector" is true.

A span of a set of vectors S in Rn is the set of all linear combinations of vectors in S.

In other words, it is the collection of all possible linear combinations of the vectors in the subset S. The zero vector is found in all of the possible linear combinations because the zero vector multiplied by any scalar will still produce the zero vector.

In simpler terms, any linear combination of a subset of Rn can be created by multiplying each vector in the subset by its corresponding scalar coefficient and adding them up.

The span of any finite nonempty subset of Rn contains the zero vector because all linear combinations in this span must have a combination of the subset's vectors, and also since the subset is finite, it will always contain at least one zero vector.

Thus, this statement is true because, in any non-empty subset of Rn, the span of the subset will always include the zero vector.

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Under the current law on nutrition labeling, the Nutrition Facts
panel must include
a. total calories from trans fat
b. grams of monounsaturated fat
c. grams of total fat
d. total calories from satura

Answers

The Nutrition Facts panel must include the grams of monounsaturated fat, grams of total fat, and total calories from saturated fat.

a. The total calories from trans fat are not required to be included in the Nutrition Facts panel. Trans fat is listed separately under "Total Fat" and does not have its own specific calorie value.

b. The grams of monounsaturated fat are required to be included in the Nutrition Facts panel. Monounsaturated fat is a type of fat that is beneficial for health, and its quantity is provided to help consumers make informed choices.

c. The grams of total fat are required to be included in the Nutrition Facts panel. Total fat represents the sum of all types of fats present in the food product.

d. The total calories from saturated fat are required to be included in the Nutrition Facts panel. Saturated fat is a type of fat that is associated with an increased risk of certain health conditions, and providing the calorie value helps consumers monitor their intake.

Therefore, the Nutrition Facts panel must include b. grams of monounsaturated fat, c. grams of total fat, and d. total calories from saturated fat.

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When using the lens equation, a negative value as the solution for di indicates that the image is real. Virtual. Upright. Inverted.

Answers

Option B is correct. A negative value as the solution indicates that the image is Virtual.

What is the lens equation?

The Lens formula describes the relationship between the distance of an image (v), the distance of an object (u), and the focal length (f) of the lens in optics.

The lens equation is given below;

\(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)

When light beams from the same spot on an item reflect off a mirror and diverge or spread apart, virtual pictures are formed.

Hence option B is correct. A negative value as the solution indicates that the image is Virtual.

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Answer:

B. Virtual

Explanation:

Edge 2023

A rocket is shot out of a navy battleship to test a new rocket. It takes 16 seconds for the rocket
to reach its destination after leaving the barrel. If its final velocity was found to be 200 m/s,
then what was the rocket's acceleration?

Answers

the acceleration was 200 m/s or 69420

a horizontal spring with stiffness 0.5 n/m has a relaxed length of 15 cm. a mass of 20 g is attached and you stretch the spring to a total length of 25 cm. the mass is then released from rest and moves with little friction. what is the speed of the mass at the moment when the spring returns to its relaxed length of 15 cm?

Answers

The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.

1. First, we need to find the spring constant (k) and the mass (m). We are given k = 0.5 N/m and m = 20 g (which we need to convert to kg): m = 20/1000 = 0.02 kg.

2. Next, we need to determine the elongation (x) of the spring. We are given the initial length (25 cm) and the relaxed length (15 cm):

x = 25 cm - 15 cm = 10 cm (which we need to convert to meters):

x = 10/100 = 0.1 m.

3. Now, we can calculate the potential energy (PE) stored in the spring when it's stretched: PE = (1/2) * k * x^2 = (1/2) * 0.5 N/m * (0.1 m)^2 = 0.0025 J.

4. When the spring returns to its relaxed length, the potential energy will be converted into kinetic energy (KE): KE = (1/2) * m * v^2.

5. Since PE = KE, we can solve for the velocity (v) of the mass: 0.0025 J = (1/2) * 0.02 kg * v^2.

6. Solve for v: v^2 = (0.0025 J * 2) / 0.02 kg

v^2 = 0.25

v = √0.25 = 0.5 m/s.

The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.

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A go cart engine applies a force of 888N and moves the cart forward 22m.
a) How much work is done?
b) We put on a bigger engine (1111N) but the cart still moves forward 22m. How much work is done now?
c) Why would you put on a bigger engine if you are still moving 22m?

Answers

Answer:

Explanation:

a) work=Force times distance. given force is 888N and distance travelled is 22M

work= 888 x 22 = 19536J or 1.954x10^5J

b) work = 1111 x 22= 24442J or 2.444x10^5J

c) putting on a larger engine means that there are gonna be more force applied to the go cart. therefore the cart will travel the same distance faster

a. The amount of work done by the go cart engine is 19,536 Nm.

b. The amount of work done when a bigger engine is used is 24,442 Nm.

c. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

Given the following data:

Force A = 888 NewtonDistance = 22 meterForce B = 1111 Newton

a. To determine the amount of work done by the go cart engine:

Mathematically, the work done by an object is given by the formula;

\(Work\;done = Force \times distance\)

Substituting the given parameters into the formula, we have;

\(Work\;done = 888 \times 22\)

Work done = 19,536 Nm.

b. To determine the amount of work done when a bigger engine is used:

\(Work\;done = Force \times distance\)

\(Work\;done = 1111 \times 22\)

Work done = 24,442 Nm.

c. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

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what type of reaction occurs when a cadle is burned

Answers

Answer:

Exothermic Reaction.

Explanation:

An exothermic reaction is a chemical reaction that releases energy in the form of light or heat. The burning of the candle is an exothermic reaction. Endothermic reactions - Heat is absorbed, like the Photosynthesis process.

HF Radio Blackouts The Empirical HIDIVE model suggests that the HF blackout intensity varies as a function of f-1.24, where fis frequency and COS0.⁹(0), where is solar zenith angle. If a radio blackout occurs at a maximum of 15 MHz at 10 AM Eastern Daylight Time over Laurel, Maryland on September 10th, then what is the maximum frequency affected by the blackout and at what location? [An approximate answer within 0.1 MHz and 1° lat/lon will be accepted.

Answers

The maximum frequency affected by the blackout is approximately 7.943 MHz, and the location of the blackout is Laurel, Maryland, which is located at approximately 39.09°N, 76.85°W.

HF radio blackouts are a phenomenon that impacts High Frequency (HF) radio waves by causing them to become inaudible or distorted. The severity of an HF radio blackout is determined by a number of factors, including the frequency of the radio waves, the time of day, and the solar zenith angle.

Let us calculate the maximum frequency affected by the blackout: According to the model, the frequency of the radio wave is inversely proportional to the power of 1.24. So we can write:f∝(P)-1.24, Where f is the frequency of the radio wave, and P is the power of the blackout. So if a blackout occurs at 15 MHz, then we can find the power of the blackout:P=15^(1.24)P=26.98

So the power of the blackout is approximately 26.98.Next, we need to calculate the maximum frequency affected by the blackout. We can do this by using the formula: f∝(P)-1.24, where f is the frequency of the radio wave, and P is the power of the blackout. So if the power of the blackout is 26.98, then we can find the frequency of the radio wave:f=26.98^(-1/1.24)f=7.943MHz

So the maximum frequency affected by the blackout is approximately 7.943 MHz. Now let us find the location of the blackout: According to the question, the blackout occurred at 10 AM Eastern Daylight Time over Laurel, Maryland on September 10th. So the location of the blackout is Laurel, Maryland, which is located at approximately 39.09°N, 76.85°W.

Therefore, the maximum frequency affected by the blackout is approximately 7.943 MHz, and the location of the blackout is Laurel, Maryland, which is located at approximately 39.09°N, 76.85°W.

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a bicycle wheel has a diameter of 74.6 cm and a mass of 0.758 kg. the bicycle is placed on a stationary stand on rollers and a resistive force of 95.7 n is applied to the rim of the tire. assume all the mass of the wheel is concentrated on the outside radius. in order to give the wheel an acceleration of 2.6 rad/s 2 , what force must be applied by a chain passing over a sprocket with diameter 8.38 cm? answer in units of n.

Answers

Force applied by a chain passing over a) is 854 N and force is required if the chain shifts to a 8.38 cm is 869N.

A) The expression for force is product of force and distance of force from the axis of rotation,

τ = r x F

Here sum of clock wise moments are negative and sum of anticlockwise moments are positive,

τ = r x Fa

τnet = r x Fa - R x F

Torque is product of inertia and angular acceleration,

I∝ = r x Fa - R x F

\(F_a = \frac{I\alpha + R*F_r_e_s}{r}\)

Moment of inertia of wheel is,

I = MR²

= (0.758)(0.746)

= 0.565 kg.m³

Fa = 854 N

B) using the equation,

\(F_a = \frac{I\alpha + R*F_r_e_s}{r}\)

= \(\frac{(0.565) (2.6) + (95.7)(0.746) }{0.0838}\)

= 869N

Newton's alternate law establishes that the net necklace acting on a body equals the product of the body's moment of indolence and its angular acceleration,

The moment of indolence serves as a measure of the body's resistance to a change in its rotational state of stir.

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Witch TWO types of rock are formed as particles get pushed closer together A. Intrusive igneous B. Extrusive igneous C. Sedimentary D. Metamorphosis

Answers

Answer:

C

Explanation:

Sedimentary rocks are the product of

1) weathering of preexisting rocks,

2) transport of the weathering products,

3) deposition of the material

4) compaction (two rocks pushed together)

5) cementation of the sediment to form a rock.

Rock A is thrown horizontally off of a cliff with a velocity of 20m/s. The rock lands 60m from the base of the cliff.
According to the information and diagram above, what is the height of the cliff?

А. 10.1m

B. 44.1m

С. 60.0m

D. 210m

Answers

Answer:

B. 44.1

Explanation:

We can use the equation y=1/2gt^2 to find the distance in the vertical direction, where y= distance in the vertical direction, g=acceleration due to gravity, and t=time

we only know acceleration due to gravity(9.8m/s^2),

plug in known variables,

y=1/2*9.8*t^2

we still need to plug in the time variable.

In order to do that, we an use the s=d/t equation and re arrange that formula to get: t=d/s, where t=time, d=distance, and s=speed.

plug in known variables,

t=60/20

t=3

now that we know the time, we can plug that into our original equation

y=1/2*9.8*3^2

simplify,

y=4.9*3^2

y=4.9*9

y=44.1m

Thus, B is your answer

The driver of a car slams on the brakes, causing the car to slow down at a rate of 24.0ft/s? as the car skids 253ft to a stop.
How long does the car take to stop?
What was the car's initial speed?

Answers

It takes approximately 4.59 seconds for the car to come to a stop. the car's initial speed was approximately 110.2 ft/s,

To determine the time it takes for the car to stop and the car's initial speed, we can use the kinematic equation:

v² = u² + 2as

where:

v is the final velocity (0 ft/s, since the car comes to a stop),

u is the initial velocity (unknown),

a is the acceleration (-24.0 ft/s², as the car slows down),

and s is the distance traveled (253 ft).

Plugging in the known values into the equation, we can solve for u:

0² = u² + 2(-24.0 ft/s²)(253 ft)

0 = u² - 48.0 ft/s² * 253 ft

48.0 ft/s² * 253 ft = u²

u² = 12144 ft²/s²

Taking the square root of both sides:

u = √12144 ft/s

u ≈ 110.2 ft/s

So, the car's initial speed was approximately 110.2 ft/s.

Now, to find the time it takes for the car to stop, we can use the equation:

v = u + at

0 = 110.2 ft/s + (-24.0 ft/s²) * t

24.0 ft/s² * t = 110.2 ft/s

t = 110.2 ft/s / 24.0 ft/s²

t ≈ 4.59 s

Therefore, it takes approximately 4.59 seconds for the car to come to a stop.

In summary, the car's initial speed was approximately 110.2 ft/s, and it took approximately 4.59 seconds for the car to come to a stop while skidding a distance of 253 ft.

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