Answers
The time taken is √3 s and the velocity with he lands is 17.3 m/s.
What is the time taken?In this case, we have to use the equations of kinematics as it has to do with motion under gravity. We know that;
h = ut + 1/2gt^2
h = height
u = initial velocity
g = acceleration due to gravity
t = time taken
Given that u = 0 m/s because the object was dropped from a height.
h = 1/2gt^2
t = √2h/g
t = √2 * 15/10
t = √3 s
The velocity with which he falls is obtained from;
v = u + gt
v = gt
v = 10 m/s^2 * √3 s
v = 17.3 m/s
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Related Questions
If the breaking strength of the string is 120 N, what is the minimum angle the string can make with the horizontal
Answers
Complete Question
A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string, If the breaking strength of the string is 120 N, what's the minimum angle the string can make with the horizontal?
Answer:
The value is \(\theta = 4.41^o\)
Explanation:
From the question we are told that
The mass of the rock is \(m_r = 940 \ g = 0.94 \ kg\)
The length of the string is \(l = 1.30 \ m\)
The breaking strength(i.e the maximum tension) on the string is \(T = 120 \ N\)
Gnerally the vertical component of the tension experienced by the string is mathematically represented as
\(T_v = T sin(\theta)\)
Generally this vertical component of tension is equivalent to the weight of the rock
So
\(Tsin (\theta) = mg\)
=> \(\theta = sin^{-1} [\frac{mg}{ T} ]\)
=> \(\theta = sin^{-1} [\frac{0.940 *9.8 }{ 120} ]\)
=> \(\theta = 4.41^o\)
To understand the basic principles underlying interference.
One of the most important properties of waves is the principle of superposition. The principle of superposition for waves states that when two waves occupy the same point, their effect on the medium adds algebraically. So, if two waves would individually have the effect "+1" on a specific point in the medium, then when they are both at that point the effect on the medium is "+2." If a third wave with effect "-2" happens also to be at that point, then the total effect on the medium is zero. This idea of waves adding their effects, or canceling each other's effects, is the source of interference.
Part C
In talking about interference, particularly with light, you will most likely speak in terms of phase differences, as well as wavelength differences. In the mathematical description of a sine wave, the phase corresponds to the argument of the sine function. For example, in the function y=Asin(kx), the value of kx at a particular point is the phase of the wave at that point. Recall that in radians a full cycle (or a full circle) corresponds to 2? radians. How many radians would the shift of half a wavelength from the previous part correspond to?
Express your answer in terms of ?.
Answers
Shift of half a wavelength from the previous part correspond to π radian.
What is the principle of interference?Interference is a phenomenon in which two waves combine by adding displacement together at every single point in the space and time, to form a resultant wave of greater, lower, or same amplitude.
The superposition principle explains that when two or more waves overlap in space, then the resultant disturbance is equal to the algebraic sum of individual disturbances
Given, Wavelength= λ
We have to find the phase difference when wavelength is half of the initial wavelength.
So, the path difference= Δx = λ/2
As, phase difference= 2π/λ * Δx
So, phase difference= 2π/λ * λ/2
Thus, phase difference= π radian
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a) A bomb, initially at rest, explodes into several pieces. (a) Islinear momentum of the system conserved? (b) Is kinetic energy of the system conserved? Explain
Answers
(a) The linear momentum of the system is conserved due to the absence of external forces. (b) The kinetic energy of the system is generally not conserved in an explosion due to energy transfers and losses associated with the process.
(a) According to the principle of conservation of momentum, the total momentum of an isolated system remains constant if no external forces act upon it. In the given scenario, the bomb is initially at rest, which means the total momentum of the system is zero before the explosion. After the explosion, the bomb fragments move in different directions, but their individual momenta add up to zero. Thus, the total momentum of the system remains conserved.
(b) In an explosion, a significant amount of potential energy stored in the bomb is rapidly converted into kinetic energy of the fragments. As the bomb explodes, the fragments gain kinetic energy, resulting in an increase in the total kinetic energy of the system. Additionally, the explosion may cause the fragments to collide with other objects or experience air resistance, leading to energy losses in the form of heat, sound, or work done against external forces. These energy losses further prevent the conservation of kinetic energy.
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b) By what factor does the fundamental frequency change when the mass per unit length of a guitar string increases by a factor of 3.50?
Answers
The fundamental frequency change when the mass per unit length of a guitar string increases by a factor of 3.50 is, 3.5ⁿ
What is frequency ?Frequency definition states that it is the number of complete cycles of waves passing a point in unit time, the SI unit of frequency is Hertz(Hz),
The frequency of a sinusoidal wave as the number of complete oscillations made by any wave element per unit of time.
The frequency of vibration of a string depends on the length L between the nodes,
the tension F in the string and its mass per unit length m.
Frequency,
f ∝ [Lᵃ] ... (1)
f ∝ [Fᵇ] ...(2)
f ∝ [Mⁿ] ...(3)
Combining equation (1) (2) and (3) we can say:
f₀ = k[Lᵃ x Fᵇ x Mⁿ]
So, when the mass per unit length increases by a factor of 3.50
Then, the new frequency is,
f = k[Lᵃ x Fᵇ x( 3.5M)ⁿ]
= 3.5ⁿ x k[Lᵃ x Fᵇ x Mⁿ]
f = 3.5ⁿ f₀
Hence, the frequency will increase by a factor of 3.5ⁿ
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You are sitting at your dinner table and notice three peas have fallen off of your plate as shown. Each pea has a mass of 0.22g and d=3.6cm. A. Find the magnitude and direction (CCW from the +axis) of the net gravitational force on the pea labeled M1 B. Find the direction (CCW from the +axis) of the net gravitational force on the pea labeled m1
Answers
Answer:
force = 2.73 x 10^ -15 N
angle = 153.435
Explanation:
Let us redraw the diagram
Let us call
F13 = force on m1 due to m3
F12 = force on m1 due to m2
Now along the x-axis, we have
\(F_x=F_{13}\sin \theta\; \hat{i}\)and along the y-axis, we have
\(F_y=F_{13}\cos \theta+F_{12}\; \hat{j}\)Now,
\(F_{13}=G\frac{m_1m_3}{d^2+(2d)^2}\)and
\(F_{12}=G\frac{m_1m_2}{d^2}\)Therefore, the force along the x-axis becomes
\(\begin{gathered} F_x=F_{13}\sin \theta\; \hat{i} \\ \Rightarrow F_x=G\frac{m_1m_3}{d^2+(2d)^2}\sin \theta\; \hat{i} \end{gathered}\)and the force along the y-axis becomes
\(\begin{gathered} F_y=F_{13}\cos \theta+F_{12}\; \hat{j} \\ \Rightarrow F_y=G\frac{m_1m_3}{d^2+(2d)^2}\cos \theta+G\frac{m_1m_2}{d^2}\hat{\; j} \end{gathered}\)Since
\(\sin \theta=\frac{2d}{\sqrt[]{d^2+(2d)^2}}=\frac{2d}{d\sqrt[]{5}}=\frac{2}{\sqrt[]{5}}\)and
\(\cos \theta=\frac{d}{\sqrt[]{d^2+(2d)^2}}=\frac{d}{d\sqrt[]{5}}=\frac{1}{\sqrt[]{5}}\)The above equations become
\(F_x=G\frac{m_1m_3}{d^2+(2d)^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}\)\(\Rightarrow\boxed{F_x=G\frac{m_1m_3}{5d^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}}\)and
\(\boxed{F_y=G\frac{m_1m_3}{5d^2}\times\frac{1}{\sqrt[]{5}}+G\frac{m_1m_2}{d^2}\hat{j}}\)To find the numerical value, we now put
G = 6.67 x 10^-11
m_1 = m_2 = m_3 = 2.2 x 10^-4 kg
d = 0.036 m
into the above equations and get
\(F_x=(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{5(0.036)^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}\)\(\boxed{F_x=4.46\times20^{-16}\; \; \hat{i}}\)and
\(F_y=(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{5(0.036)^2}\times\frac{1}{\sqrt[]{5}}+(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{(0.036)^2}\hat{j}\)\(\Rightarrow\boxed{F_y=2.7\times10^{-15}\; \hat{j}}\)Therefore, the net gravitational force is
\(F_{\text{tot}}=4.46\times20^{-16}\; \; \hat{i}+2.7\times10^{-15}\; \hat{j}\)the magnitude of this net force is
\(|F_{\text{tot}}|=\sqrt[]{(4.46\times20^{-16})^2+(2.7\times10^{-15})^2}\)\(\boxed{|F_{\text{tot}}|=2.73\times10^{-15}}\)Finally, we need to find the direction of this force.
To specify, the direction, we need to find the angle this force makes counterclockwise with respect the x-axis.
The angle is given by
\(\cos \theta=\frac{1}{\sqrt[]{5}}\)\(\Rightarrow\theta=63.435^o\)adding additional 90 degrees gives the angle with respect to the positive x-axis.
\(\theta+90^o=153.435^o\)Hence, the force is directed at about 153 degrees counterclockwise with respect to the x-axis.
Find Density of a cylinder with diameter of 5.0 cm and height of 12.0cm and mass of 600.0g
Answers
Answer: 2.55 g/cm^3
Explanation:
density is defined as:
Density = mass/volume
Now, the mass of the cylinder is 600g
and the volume of a cylinder is:
V = pi*r^2*h
where r is the radius (half of the diameter), here r = (5/2)cm and h is the height, here 12 cm
So the volume is:
V = 3.14*(2.5cm)^2*12cm = 235.5cm^3
then the density is:
D = 600g/235.5cm^3 = 2.55 g/cm^3
A ball thrown with an initial velocity of u(10i+15j)m/s when it reaches the top of it trajectly neglucating air resistance what is avelocity & acceleration ?
Answers
At the apex of the trajectory, the ball's velocity and acceleration are u (10i+15j) m/s and zero
The initial velocity of the ball is u (10i+15j) m/s.
Velocity at the top of the trajectory: Since the ball is thrown with an initial velocity, it will reach the top of its trajectory with the same velocity, since there is no air resistance. Therefore, the velocity of the ball at the top of the trajectory is u (10i+15j) m/s.
Acceleration: The acceleration of the ball at the top of the trajectory is zero, since the ball is not accelerating (there is no acceleration due to air resistance).
Therefore, the velocity and acceleration of the ball at the top of the trajectory are u (10i+15j) m/s and zero, respectively.
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a javelin is thrown at 28.5m/s from flat ground at a 43.2 degree angle. How long does it take to reach its maximum height? IN SECONDS
Answers
The time taken for the javelin thrown at 28.5 m/s from flat ground at a 43.2 degree angle to reach the maximum height is 2.0 s
How do I determine the time taken to reach the maximum height?From projectile motion, we understand that the time taken to reach maximum height is given as:
t = uSineθ / g
Where
t is the time to reach maximum heightu is the initial velocity θ is the angle of projectiong is acceleration due to gravityNow, using the above formua, we can obtain the time taken for the javelin to reach the maximum height as follow:
Initial velocity (u) = 28.5 m/s
Angle of projection (θ) = 43.2 degrees
Acceleration due to gravity (g) = 9.8 m/s²
Time taken to reach the peak (t) = ?
t = uSineθ / g
t = (28.5 × Sine 43.2) / 9.8
t = 2.0 s
Thus, the time taken to reach maximum height is 2.0 s
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What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Answers
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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Need help Electric Forces
Answers
The net electric force on charge q2 is 28.7 N.
What is the net electric force on q2?The net electric force on charge q2 is calculated by applying Coulomb's law of electrostatic force.
F(net) = F(12) + F(23)
The force on q2 due to charge 1 is calculated as;
F(12) = -(9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.1²)
F(12) = 25.2 N
The force on q2 due to charge 3 is calculated as;
F(23) = (9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.15²)
F(23) = 3.5 N
The net force on q2 is calculated as;
F(net) = 25.2 N + 3.5 N = 28.7 N
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A pilot wants to fly due north a distance of 125 km. The wind is blowing out of the west at a constant 35 km/h. If the plane can travel at 175km/h, how long will the trip take?
Answers
The time taken for the trip is determined as 0.73 hrs.
What is the time taken for the trip?The time taken for the trip is calculated by applying the following formula as follows;
time taken for the trip = ( total displacement ) / (average velocity)
To determine the total displacement of the pilot we will use Pythagoras theorem as follows;
(175 t)² = (35t)² + 125²
where;
t is the time of motion30625t² = 1225t² + 15625
Simplify the equation further and solve for t;
30625t² - 1225t² = 15625
29400t² = 15625
t² = 15625/29,400
t² = 0.53
t = √0.53
t = 0.73 hrs
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What is the vibrating source that creates sound waves?
Answers
Answer:
Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.
how is voltage related to electric potential energy?
Answers
Answer:
Explanation:
Electric potential energy is energy possessed by a charged body by virtue of its location. Voltage which is also known as electric potential difference is the external work required to bring a charge from a given location in an electric field to another location
What is the Potential Energy of a roller coaster if it has a velocity of 35 m/s and a mass of 2000 kg and is at a height of 200 m? Please answer fast
A.) 137,200,000 J
B.) 12,005,000 J
C.) 3,920,000 J
D.) 1,400,000 J
Answers
Answer:
C
Explanation:
It cant be A or D, meaning your left with B and C. there cant be an answer in the 1000's place eather
If you double the mass, what happen to the acceleration?
Answers
Answer: The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.
Explanation:
A canister filled with 3.5 mol of single-atom helium gas has a temperature of
300 K. What is the approximate total internal energy of the gas? (Recall that the equation for kinetic energy due to translation in a gas is: 3/2 nRT; the
equation for kinetic energy due to rotation of a molecule in a gas is: nRT, and R= 8.31 J/(mol.K).)
R= 8.31 J/(mol-K).)
A. 13,100 J
B. 5800 J
C. 15,400 J
D. 8200 J
Answers
The answer is C
Please dont get mad at me if this is not right im pretty sure it is
hope this helps!
What are some good experiment ideas for quantum physics (stuff like the double slit experiment)
Answers
Some good experiment ideas for quantum physics is magic wavelength magnetometry of ultra-cold atoms.
What is an Experiment?This is referred to as a procedure which is carried out to support or refute a hypothesis. It is usually performed in the laboratory under controlled conditions and to achieve a purpose.
Quantum physics on the other hand is the study of matter and energy at the most fundamental level and also explains the properties and behaviors of very small objects, such as electrons, photons etc.
Magic wavelength magnetometry of ultra-cold atoms is characterized by the use of perturbations in the ambient magnetic field on particles such as electrons which are caused by contrasts in magnetic susceptibility and it helps in the study of quantum physics.
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A ray of light makes an angle of 35 with a plane mirror ,what is the reflection
Answers
When a ray of light strikes a plane mirror, the angle of reflection is equal to the angle of incidence.
In this case, the ray of light makes an angle of 35 degrees with the plane mirror. Therefore, the angle of reflection will also be 35 degrees. To understand why this happens, we need to consider the properties of reflection. When light interacts with a smooth surface like a mirror, it follows the law of reflection.
According to this law, the incident ray, the reflected ray, and the normal (a line perpendicular to the mirror's surface) all lie in the same plane. The angle of incidence is the angle between the incident ray and the normal, measured on the side of the normal where the light is coming from. In this case, the angle of incidence is 35 degrees.
According to the law of reflection, the angle of reflection is the angle between the reflected ray and the normal, also measured on the side of the normal where the light is coming from. Since the incident and reflected rays are on opposite sides of the normal, the angle of reflection is also 35 degrees.
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34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again.
Answers
Answer and Explaination:
To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.
1. Gravitational force:
The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.
2. Force exerted by the spring:
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Given:
Mass (m) = 5.0 kg
Compression of the spring (x) = 20.0 cm = 0.20 m
Angle of the inclined plane (θ) = 30°
First, let's find the force exerted by the spring (F_spring):
F_spring = -kx
To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.
Next, let's calculate the gravitational force components:
Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ
Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ
Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.
At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).
Therefore, we have:
F_perpendicular = F_spring
mg * cosθ = -kx
Now, let's substitute the known values and solve for k:
(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m
49.0 N * 0.866 = -k * 0.20 m
42.426 N = -0.20 k
k = -42.426 N / (-0.20 m)
k = 212.13 N/m
Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:
PE_spring = (1/2) * k * x^2
PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2
PE_spring = 4.243 J
The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.
KE_max = PE_spring = 4.243 J
Next, we can calculate the height (h) the mass reaches on the inclined plane:
KE_max = m * g * h
4.243 J = 5.0 kg * 9.8 m/s^2 * h
h = 4.243 J / (5.0 kg * 9.8 m/s^2)
h = 0.086 m
The height the mass reaches on the inclined plane is 0.086 m.
Now, we can calculate the distance traveled.
A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.
Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.For more questions on the spring constant
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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A student measures that 81,500 J of thermal energy were added to 0.5 kg of water. If the specific heat of water is 4,184 J/kg 0C, what was its change of temperature?
Answers
Answer:
\(\Delta T=38.95^{\circ} C\)
Explanation:
Given that,
Heat measured, Q = 81500 J
Mass of water, m = 0.5 kg
The specific heat of water is 4,184 J/kg °C
We need to find the change in temperature. The heat measured is given by :
\(Q=mc\Delta T\)
Where
\(\Delta T\) is the change in temperature
\(\Delat T=\dfrac{Q}{mc}\\\\\Delat T=\dfrac{81500}{0.5\times 4184 }\\\\\Delta T=38.95^{\circ} C\)
So, the change in temperature is \(38.95^{\circ} C\).
A sled on ice moves in the ways described below. Friction is so small that it can be ignored. A person wearing spiked shoes standing on the ice can apply a force to the sled and push it along the ice. Choose the one force (A through G) which would keep the sled moving as described in each statement below. You may use a choice more than once or not at all but choose only one answer for each blank. If you think that none are correct, answer choice J.A. The force is toward the right and is decreasing in strength (magnitude).B. The force is toward the right and is increasing in strength (magnitude).C. The force is toward the right and is of constant strength (magnitude).D. The force is toward the left and is decreasing in strength (magnitude).E. The force is toward the left and is increasing in strength (magnitude).F. The force is toward the left and is of constant strength (magnitude).G. No applied force is needed.
Answers
Answer:
G. No applied force is needed.
Explanation:
Force is any motion which changes or intends to change the position of an object. When a force is applied to an object it causes acceleration to increase and velocity changes. The sled is moving at a constant velocity, there is no acceleration in the force therefore force is not applied nor needed.
A system absorbs 1500J of heat energy from its surroundings. Determine the change in the internal energy of the system when: (i) system performs 2200J of work on the surroundings (ii) the surroundings perform 2200J of work on the system
Answers
(a) When the system does work on the surroundings, the change in the internal energy is - 700 J.
(b) When the surroundings performs work on the system, the change in the internal energy is 3,700 J.
What is the change in the internal energy of the system?
The change in the internal energy of the system is determined by applying the first law of thermodynamics as shown below.
Mathematically, the formula for first law of thermodynamics is given as;
ΔU = Q ± W
where;
ΔU is the change in the internal energy of the systemQ is the heat gain or loss of the systemW is the work done by or done on the systemWhen the system does work on the surroundings, the equation is given as;
ΔU = Q - W
ΔU = 1500 J - 2200 J
ΔU = -700 J
When the surroundings performs work on the system, the equation is given as;
ΔU = Q + W
ΔU = 1500 J + 2200 J
ΔU = 3,700 J
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A long glass rod A is initially at 22.0°C. A second rod B is identical to rod A and has the same mass and initial temperature as A. The same amount of heat is supplied to both rods and the two rods A and B reach final temperatures of 86.3°C and 190.0°C respectively. If the specific heat of glass is 0.2007 kcal/(kg· °C), what is the specific heat of the material from which rod B is made?
Answers
Answer:
\(c_B=0.0768\frac{kcal}{kg\cdot\°C}\)
Explanation:
In order to calculate the specific heat of the material B, you use the following formula for the change in the temperature of a substance, where an amount of heat Q is given to the substance:
\(Q=mc(T_2-T_1)\)
Q: amount oh heat
m: mass of the substance
T2: final temperature
T1: initial temperature
c: specific heat of the substance.
If QA and QB are the heat of material A and B, you have:
\(Q_A=m_Ac_A(T_{2A}-T_{1A})\\\\Q_B=m_Bc_B(T_{2B}-T_{1B})\)
both materials have the same mass, mA = mB
cA: specific heat of A = 0.2007 kcal/(kg.°C)
cB: specific heat of B = ?
T2A: final temperature of A = 86.3°C
T1A: initial temperature of A = 22.0°C
T2B: final temperature of B = 190.0°C
T1B: initial temperature of B = 22.0°C
In this case you have that both material A and B receive the same amount of heat Q. Then, you equal QA with QB and solve for cB:
\(m_Ac_A(T_{2A}-T_{1A})=m_Bc_B(T_{2B}-T_{1B})\\\\c_B=\frac{c_A(T_{2A}-T_{1A})}{(T_{2B}-T_{1B})}\\\\c_B=\frac{(0.2007kcal/(kg.\°C))(86.3\°C-22.0\°C)}{190.0\°C-22.0\°C}\\\\c_B=0.0768\frac{kcal}{kg\cdot\°C}\)
hence, the specific heat of the second rod B is 0.0768kcal/(kg°C)
Integrated Concepts A lightning bolt strikes a tree, moving 20.0 C of charge through a potential difference of 1.00×102 MV . (a) What energy was dissipated? (b) What mass of water could be raised from 15ºC to the boiling point and then boiled by this energy? (c) Discuss the damage that could be caused to the tree by the expansion of the boiling steam.
Answers
Answer:
a) 2*10^9 J
b) 764.8 kg
Explanation:
Given that
Energy of charge, q = 20 C
Potential difference, ΔV = 1*10^2 MV = 1*10^2 * 10^6 V = 1*10^8 V
a)
To find the energy dissipated, we use the formula
ΔU = qΔV
ΔU = 20 * 1*10^8
ΔU = 2*10^9 J
b)
Change in temperature, ΔT = 100 - 15°
ΔT = 85° C
Change in energy, ΔU = 2*10^9 J
Specific heat of water, C = 4180 j./Kg.K
Latent heat of vaporization, L(v) = 2.26*10^6 J/Kg
Q1 = mcΔT
Q2 = mL(v)
Net energy needed, U = Q1 + Q2
U = mcΔT + mL(v)
U = m (cΔT + L(v))
m = U /[cΔT + L(v)]
Being that we have all the values, we then substitute
m = 2*10^9 / [(4180 * 85) + 2.26*10^6]
m = 2*10^9 / (3.553*10^5 + 2.26*10^6]
m = 2*10^9 / 2.615*10^6
m = 764.8 kg
c)
Having 765 kg of steam at the temperature would have extreme effect on the tree, damaging it permanently. Possibly even blowing it to pieces
The fundamental cause of a variable star's change in luminosity is that the star's _____ is changing.
Answers
Tonya is modeling the discovery of electromagnetic induction. Which procedure should she use? moving a magnet into a coil of wire in a closed circuit moving a magnet into a coil of wire in an open circuit bringing a compass near a wire that has no electric current bringing a compass near a wire that has an electric current
Answers
To model the discovery of electromagnetic induction, Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.
Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.
Electromagnetic induction refers to the phenomenon of generating an electric current in a conductor by varying the magnetic field passing through it. This concept was discovered by Michael Faraday in the early 19th century. To model this discovery, Tonya needs to recreate the conditions that led to this breakthrough.
In Faraday's experiment, he observed that when a magnet is moved into or out of a coil of wire, it induces an electric current in the wire. This occurs when the magnetic field passing through the coil changes. Therefore, Tonya should use a similar setup to replicate this process.
Out of the given options, the most appropriate procedure for Tonya would be to move a magnet into a coil of wire in a closed circuit. By having a closed circuit, it means that the ends of the wire are connected to form a complete loop. When the magnet is moved into the coil, the changing magnetic field induces an electric current to flow through the wire.
This procedure demonstrates the principle of electromagnetic induction and shows how a changing magnetic field can produce an electric current. It allows Tonya to visually observe the effects of the induced current, which is essential in modeling the discovery of electromagnetic induction.
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A sphere of radius =0.280 m and uniform charge density 151 nC/m^3 lies at the center of a spherical, conducting shell of inner and outer radii 3.50 and 4.00, respectively. If the conducting shell carries a total charge of =−11.9 nC, find the magnitude of the electric field at the given radial distances from the center of the charge distribution.
Answers
The magnitude of the electric field at the given radial distances from the center of the charge distribution is, For the first case electric field=E₁= 1211.37N/C, For the second case electric field =E₂=762.82 N/C, For the third case electric field= E₃= 3276.7 N/C, For the fourth case electric field=E₄=555.04N/C
What is electric field?Electric field is defined in a way that a field is present in a frame. There is two electric source is present that associated with each other and make the field electrified and source of electric. It can be shown in electric per unit area.
How can I calculate the electric field?The conducting shell carries a total charge of=Q=−11.9 nC=11.9*10⁻⁹C
A sphere of radius=R =0.280m
A uniform charge density of a sphere=ρ₁= 151 nC/m³= 151×10⁻⁹C/m³
A uniform charge density of a spheric shell,
ρ₂=Q/(4/3)π[(4.00R)³−(3.50R)³]
Or,ρ₂=3Q/4πR³[(4.00)³−(3.50)³]
Or,ρ₂=3*11.9*10⁻⁹/4π(0.280)³[(4.00)³−(3.50)³]
Or,ρ₂=6.15*10⁻⁹ C/m³
We know the law of electric field,
E=(1/4πϵ₀)*(q/r²)
(a) r₁=0.76R
The electric field, in this case, can be given as:
E₁=(1/4πϵ₀)*(q₁/r₁²)
Or, E₁=(1/4πϵ₀)*(ρ₁*{(4/3)πr₁³}/r₁²)
Or, E₁=(1/4πϵ₀)*(ρ₁*(4/3)πr₁)
Or, E₁=9*10⁹*( 151×10⁻⁹*(4/3)π*0.76*0.280)
Or, E₁= 1211.37N/C
According to the calculation, The electric field for this case is, E₁= 1211.37N/C
(b) r₂=3.65R
The electric field, in this case, can be given as:
E₂=(1/4πϵ₀)*(q₂/r₂²)
Here, q₂=Q+(4/3)π[(4.00)³−(3.50)³]
Or, q₂=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]
Or, q₂=88.488*10⁻⁹C
Now, E₂=(1/4πϵ₀)*(q₂/r₂²)
Or, E₂=(1/4πϵ₀)*(88.488*10⁻⁹/(3.65*0.280)²)
Or, E₂=762.82 N/C
According to the calculation, The electric field for this case is, E₂=762.82 N/C
(c) r₃=2.30R
The electric field, in this case, can be given as:
E₃=(1/4πϵ₀)*(q₃/r₃²)
In this case, electric charge enclosed by the Gaussian surface is given by: q₃=151×10⁻⁹C/m³
Now, E₃=(1/4πϵ₀)*(q₃/r₃²)
Or, E₃=(1/4πϵ₀)*(151×10⁻⁹/(2.30*0.280)²)
Or, E₃= 3276.7 N/C
According to the calculation, The electric field for this case is, E₃= 3276.7 N/C
(d) r₄=4.50R
Here, q₄=Q+(4/3)π[(4.00)³−(3.50)³]
Or, q₄=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]
Or, q₄=88.488*10⁻⁹C
Now, E₄=(1/4πϵ₀)*(q₄/r₄²)
Or, E₄=(1/4πϵ₀)*(88.488*10⁻⁹/(4.50*0.280)²)
Or, E₄=555.04N/C
According to the calculation, The electric field for this case is, E₄=555.04N/C
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Which statement describes a switch in an electrical circuit?
Answers
Answer:
An electrical component that can disconnect or connect the conducting path in an electrical circuit.
What is the strength of the electric field at the position indicated by the dot in (Figure 1)?
What is the direction of the electric field at the position indicated by the dot in (Figure 1)? Specify the direction as an angle measured clockwise from the positive x
axis.
Answers
At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.
Assuming that the two charges are of equal magnitude and opposite sign and that the distance between them is d, the electric field at the point indicated by the dot can be found using Coulomb's law:
\(E = kq/r^2\)
where k is Coulomb's constant (\(8.99 *10^9 N m^2/C^2\)), q is the magnitude of the charge, and r is the distance between the charges.
Since the charges are of equal magnitude, the net charge at the point indicated by the dot is zero, so we only need to consider the electric field due to one of the charges. Let's assume that we want to find the electric field due to the positive charge.
The distance between the positive charge and the point indicated by the dot is r = d/2. Therefore, the electric field at that point is:
\(E = kq/(d/2)^2 = 4kq/d^2\)
The direction of the electric field is radial, pointing away from the positive charge and toward the negative charge. At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.
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