To maximize the reliability of the data collected, the student should ensure that the experiment is carried out under consistent conditions each time.
This can include using the same materials and equipment, following the same procedure, and conducting the experiment in the same environment. Additionally, the student should take careful and accurate measurements during each trial to ensure the most precise results. By doing so, the student can increase the validity of the experiment and minimize any potential sources of error that may affect the data collected. Ultimately, this will help to ensure that the average of the three results is a more accurate representation of the law of conservation of mass.
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A spring has a spring constant of 120 N/m. How much energy is stored in the spring as it is stretched a distance of 0.20 meter?
Answer:
2.4J
Explanation:
Given parameters:
Spring constant = 120N/m
Extension = 0.2m
Unknown:
Amount of energy = ?
Solution:
The energy stored in this stretched spring is called the elastic potential energy.
It can be derived using the expression below:
Elastic Potential energy = \(\frac{1}{2}\) ke²
k is the elastic constant
e is the extension
Insert the parameters;
Elastic potential energy = \(\frac{1}{2}\) x 120 x 0.2² = 2.4J
an object is dropped from the top of a 100ft bilding at what time will the object be 50 ft from the ground
Answer: 1.245
Explanation: It takes an object 2.49 seconds to fall completely from a 100 foot drop, divide that by 2 and you get 1.245..
If 30.943g of liquid occupies a space of 35.0mL, what is the density of the liquid in g/cm
Explanation:
Density = Mass ÷ Volume
∴ the density of the liquid = 30.943 g ÷ 35.0 mL
= 0.884 g/mL
NEED HELP PLEASE 50 POINTS
K12 Online school
Take the "Healthy Lifestyle Questionnaire" on page 413 in your PE textbook. Share the following information. What was your score and how you feel about your score?
(Answer in 2-4 complete sentences for full credit)
Answer:
I'm sorry, but as an AI language model, I don't have a PE textbook to access the "Healthy Lifestyle Questionnaire" on page 413. However, I can tell you that the questionnaire is a self-assessment tool designed to help individuals evaluate their current lifestyle habits and identify areas for improvement. It covers topics such as physical activity, nutrition, stress management, and sleep. The score obtained from the questionnaire can provide insight into one's overall health and well-being. If you have access to the questionnaire, I encourage you to take it and reflect on your score to identify areas where you can make positive changes to improve your health and well-being.
The questionnaire on healthy lifestyle will be used to assess an individual's lifestyle habits such as including exercise, nutrition, sleep, stress and substance use.
What can a healthy lifestyle questionnaire reveal?This questionnaire can reveal information about people lifestyle habits because its provids insight into areas where changes need to be made to improve overall health and well-being.
When a respondent answers question about issues like exercise, nutrition, the researchers can gain understanding of their current habits and identify areas where they may need to make changes.
Therefore, the information derived therein can then be used to develop a personalized plan for improving health and achieving wellness goals.
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Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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What is the main evidence for the existence of dark matter?.
Radio astronomical observations of spiral galaxies are the main source of evidence for dark matter. Large collecting telescopes are used in radio astronomy to gather radio frequency radiation from space.
The information will next be analyzed to reveal evidence for extra matter that cannot be explained by the luminous stuff that has been discovered.There is convincing proof that dark matter exists, at the very least. Even though scientists still don't fully understand dark matter, there is ample proof that it—or something similar—exists. Nothing we can immediately observe bridges the gap between the whole mass of the cosmos and what we can directly observe.To know more about dark matter
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how long will it take a 2000- w w motor to lift a 370- kg k g piano to a sixth-story window 17.0 m m above?
It will take approximately 31.11 seconds for a 2000-watt motor to lift a 370-kg piano to a sixth-story window 17.0 meters above the ground.
A 2000-watt motor is used to lift a 370-kg piano to a sixth-story window 17.0 meters above the ground. To calculate the time it takes, we first need to find the work done and then divide it by the power of the motor.
Work done (W) can be calculated using the formula W = m * g * h, where m is the mass (370 kg), g is the gravitational acceleration (approximately 9.8 m/s²), and h is the height (17.0 m). So, W = 370 kg * 9.8 m/s² * 17.0 m = 62,218 J (joules).
Now we have the work done and the power of the motor, which is 2000 watts (W). Time (t) can be calculated using the formula t = W / P, where P is the power. So, t = 62,218 J / 2000 W = 31.11 seconds.
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Which of the following lines could be used to describe an object that is accelerating in the positive direction on this Position vs. Time graph? (remember your lessons and resources)
The line which could be used to describe an object that is accelerating in the positive direction on this Position vs. Time graph is line a.
What is a position vs time graph?A position vs time graph can be defined as a type of graph that is used to graphically represent the distance traveled (covered) by an object from its starting position with respect to the time when it is started moving.
In a position vs time graph, the position of a physical object (body) is always plotted on the y-coordinate (y-axis) while time is always plotted on the x-coordinate (x-axis).
Generally speaking, there are different types of motion that are described by a position vs time graph and these include a motion in the positive direction and accelerating or speeding up in the positive direction as depicted by line a, which simply means that the speed of the physical is increasing.
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Asky wave is incident on the ionosphere at an angle of 60°. The electron density of this ionosphere layer is N = 24.536 × 10¹¹ electrons/m³
a. For the point of reflection, determine the refractive index of the ionospheric layer. (3 Marks)
b. Identify the critical frequency for the communication link. (2 Marks)
c. Determine the maximum usable frequency (2 Marks)
d. Give reasons why the transmissions would fail the following frequencies if the frequencies were 10 MHz and 30 MHz respectively. (4 Marks)
e. The lonosphere bends high frequency radio waves towards Earth. Discuss this bending phenomenon.
We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)
(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.
The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.
Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).
(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).
(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.
(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.
(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.
As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.
This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.
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Somebody help!?
13. The graph below represents the speed of a car vs. time. Circle the letter(s) with the lowest acceleration.
What is the acceleration? How do you know?
Answer:
acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
Explanation:
Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .
calculate the rotational inertia of the entire rotating arm plus sliding masses (at a distance of 15 cm from the axis of rotation). what shape and corresponding formula did you use for the two masses? what shape did you use to model the rotating arm?
The rotational inertia of an object depends on its mass distribution and shape relative to the axis of rotation. To calculate the rotational inertia of the system, we would need to know the shapes and masses of the rotating arm and sliding masses.
Rotational inertia depends on the object's mass distribution and the axis of rotation. The greater the object's mass is concentrated away from the axis of rotation, the greater the rotational inertia. The moment of inertia of a rigid body is defined as the sum of the products of the mass of each particle in the body and the square of its distance from the axis of rotation.
Rotational inertia plays a crucial role in many physical phenomena involving rotation, such as the behavior of rotating machines, the motion of planets and stars, and the stability of objects in motion. Understanding rotational inertia is essential for designing efficient and effective machines and for predicting the behavior of rotating systems.
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QUESTION 11 What is the phase of the moon when the moon is on the opposite side of the earth from the sun? a. The full moon. b. The new moon The crescent moon d. The gibbous moon. e. The quarter moon.
The phase of the moon when the moon is on the opposite side of the earth from the sun is the full moon. This happens when the sun, earth, and moon are aligned, with the earth in the middle.
The full moon appears when the sun’s light reflects off the entire surface of the moon, making it appear completely illuminated from our perspective on earth.Therefore, option A is the correct answer: The full moon.
When the moon is on the opposite side of the Earth from the sun, it is in the full moon phase. During this phase, the sun illuminates the entire side of the moon facing the Earth, making it appear fully lit and round. This occurs because the sun, Earth, and moon are aligned in a straight line, with the Earth in the middle. The full moon phase is characterized by a bright, round shape and is often considered the most visually striking lunar phase. It occurs approximately once every 29.5 days as the moon orbits around the Earth.
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3. Find the density of 35 g of a substance that occupies 25 mL.
Answer:
1400g/L
Explanation:
Change 25ml into litres.
Use the formula d=m/v
Devide 35g by 0.025L
A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) What was the photon's energy (in eV)? _________eV (b) Later, the atom returns to the ground state, emitting one or more photons in the process. Which of the following energies describes photons that might be emitted thus? (Select all that apply.) O 1.89 ev O 12.1 eV O 10.2 ev O 13.6 ev
A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.
To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:
E = -13.6 eV / n^2
where E is the energy of the electron in the atom, and n is the principal quantum number.
(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:
ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)
Calculating the value of ΔE:
ΔE = -13.6 eV / 9 + 13.6 eV
= -1.51 eV
Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).
(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.
ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV
ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV
ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV
ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV
ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV
ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV
ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV
Comparing the calculated energy differences with the given options:
(A) 1.89 eV: This energy difference does not match any of the calculated values.
(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.
(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.
(D) 13.6 eV: This energy difference does not match any of the calculated values.
Therefore option B and C are correct.
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I have no questions.
Answer: happy Ramadan
Explanation: thanks
an nmos transistor having vt = 1v is operated in the triode region with vds small. with vgs = 1.5v, it is found to have a resistance rds of 1kω. what value of vgs is required to obtain rds = 200ω?
The value of Vgs required to obtain Rds = 200Ω in an NMOS transistor operated in the triode region with small Vds is approximately 0.9V.
To calculate the required Vgs, we can use the equation that relates Rds to the transistor parameters. In this case, we assume the electron mobility (μn), oxide capacitance per unit area (Cox), and the width-to-length ratio (W/L) of the transistor to be constant.
By rearranging the equation and substituting the given values, we find that Vgs - Vt is inversely proportional to Rds. Since we know the initial value of Vgs (1.5V) and Rds (1kΩ), we can calculate the new value of Vgs using the proportionality.
By solving the equation, we find that Vgs ≈ 0.9V is required to achieve Rds = 200Ω in the given NMOS transistor.
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within most of the temperature range that we find liquid water on earth, what happens to the density of that water as its temperature decreases?
The maximum density occurs at 4 degrees Celsius, and beyond this point, the density starts to decrease due to the unique structure of water molecules.
Within most of the temperature range where we find liquid water on Earth, the density of water increases as its temperature decreases. This occurs because water molecules move closer together and form more hydrogen bonds when the temperature drops.
As the temperature of water decreases, the kinetic energy of its molecules also decreases, which causes them to slow down and occupy less space. This results in an increased density of water. However, this trend only continues until the water reaches its maximum density at approximately 4 degrees Celsius (39.2 degrees Fahrenheit).
Beyond this point, the density of water starts to decrease again as it approaches its freezing point at 0 degrees Celsius (32 degrees Fahrenheit). This anomaly occurs because the hydrogen bonds in water form a hexagonal structure when the temperature is close to the freezing point. This unique structure creates open spaces within the water, causing it to expand and become less dense as it turns into ice. Within most of the temperature range of liquid water found on Earth, its density increases as the temperature decreases.
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A crossbow (5.0kg) is sitting loaded with a bolt (m = 0.10kg) on a friction free table. The crossbow is triggered and the bolt (also called an arrow) is launched to the right with a speed of 25 m/s. The velocity of the crossbow as it recoils is _m/s
Answer:
The velocity of the crossbow as it recoils is 5 m/s. This can be calculated using the conservation of momentum. The momentum of the system before the bow was triggered is 0 (since the bow is stationary). After launching the bolt, the momentum of the system is (0.10 kg * 25 m/s), so in order for the momentum of the system to remain constant, the crossbow must recoil with a momentum of (5.0 kg * -5 m/s).
The Fastest Moving Planet In A Solar System Is:? A. The Smallest Planet. B. Any Planet, Because They All Move At The Same Speed. C. The Planet Nearest The Sun. D. The Planet Farthest From The Sun.
The planet that moves the fastest in a solar system is the planet nearest the Sun.
The correct option is C. The Planet Nearest The Sun.
What is a Solar System?
A solar system is a collection of planets, moons, comets, asteroids, and other objects that revolve around a single star. The sun is the center of our solar system, and it includes all of the matter and energy that orbits around it, including Earth and all the other planets.
Sun, the star around which Earth and the other planets of the solar system revolve, has a huge gravitational field. Planets move around the sun in a fixed orbit at varying speeds, depending on their distance from the sun. Because planets are closer to the sun, their gravitational pull is greater, resulting in a faster orbital speed for them.
The planet nearest the sun in the solar system is Mercury. Due to its proximity to the sun, it orbits at a speed of around 48 km/s, making it the fastest planet in the solar system, with an orbital period of 88 Earth days.
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Multiple choice
There is a positive correlation between one's level of
A. cognitive anxiety and somatic anxiety
B. trait anxiety and state anxiety
C. arousal and stress
D. a and c
E. b and c
There is posetive correlation between one's level of cognitive anxiety and somatic anxiety.
What is correlation?Correlation is a statistical of the measure that is expresses the extent to the which two variables are the linearly related (meaning they change together at its constant rate). It's a common tool for describing simple relationships without making a statement about cause and effect.
An individual with higher of the trait anxiety score tends to the higher state anxiety score. Scores of state anxiety are rated high in the circumstances where an individual feels the situation to be threatening irrespective of the objective danger.
It means the higher the level of the somatic or cognitive anxiety experience by the athletes, the lower sport to performance. The relationship between somatic and cognitive anxiety was explained best in Multidimensional Anxiety Theory. This theory explains by that both cognitive and somatic anxiety effect performance.
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What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100 g of the substance increases in temperature from 10 degrees Celsius to 70 degrees Celsius?
Answer:
I'm sorry to inform that I couldn't find an answer to this question. Socratic can help! This learning app, powered by Google AI, helps you understand your school work at a high school and university level. Ask Socratic a question and the app will find the best online resources for you to learn the concepts.
Explanation:
A Grasshopper Jumps At A 63. 0° Angle With An Initial Velocity Of 4. 22 M/S. How Far Away Does It Land?
The grasshopper lands approximately 0.689 meters away horizontally from its initial position.
To find the horizontal distance the grasshopper lands, we need to consider the horizontal and vertical components of its motion.
First, let's find the time it takes for the grasshopper to reach the highest point of its jump. We can use the vertical component of its initial velocity and the acceleration due to gravity.
Vertical component of initial velocity:
V_y = V_initial * sin(angle)
V_y = 4.22 m/s * sin(63.0°)
V_y ≈ 3.689 m/s
Acceleration due to gravity:
g = 9.8 m/s^2
Using the kinematic equation for vertical motion:
V_y = V_initial_y + (g * t)
3.689 m/s = 0 + (9.8 m/s^2 * t)
Solving for time (t):
t = 3.689 m/s / 9.8 m/s^2
t ≈ 0.376 s
Now, let's find the horizontal distance traveled during this time. We can use the horizontal component of the initial velocity and the time.
Horizontal component of initial velocity:
V_x = V_initial * cos(angle)
V_x = 4.22 m/s * cos(63.0°)
V_x ≈ 1.834 m/s
Using the equation for distance traveled horizontally:
distance = V_x * t
distance = 1.834 m/s * 0.376 s
distance ≈ 0.689 m
Therefore, the grasshopper lands approximately 0.689 meters away horizontally from its initial position.
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How much must you raise the
temperature of 1.00 m^3 of water
so that its volume expands by
0.00100 m^3?
Water
B = 207-10-6 0-1
(Unit = C)
Answer:
4.83 °C
Explanation:
001 = λ*ΔT
ΔT = 10^-3*10^6/207 = 4.83°C
Answer:
4.83
Explanation:
Ask Your Teacher An electric utility company supplies a customer's house from the main power lines (120 V) with two copper wires, each of which is 34.0 m long and has a resistance of 0.109 Ω per 300 m. (a) Find the potential difference at the customer's house for a load current of 116 A.
Answer:
The potential difference at the customer's house is 117.1 V.
Explanation:
a) The potential difference at the customer's house can be calculated as follows:
\( \Delta V_{h} = \Delta V_{p} - \Delta V_{l} \)
Where:
\(V_{h}\): is the potential difference at the customer's house
\(V_{p}\): is the potential difference from the main power lines = 120 V
\(V_{l}\): is the potential difference from the lines
\( \Delta V_{h} = \Delta V_{p} - IR \)
The resistance, R, is:
\(\frac{0.109 \Omega}{300 m}*2*34.0 m = 0.025 \Omega\)
Now, the potential difference at the customer's house is:
\(\Delta V_{h} = 120 V - 116A*0.025 \Omega = 117.1 V\)
Therefore, the potential difference at the customer's house is 117.1 V.
I hope it helps you!
Find the surface area of the solid shape below ( please help !!!!!!)))))))
Which of these objects has kinetic energy?
Answer:
A ball moving through the air.
Explanation:
The ball has momentum which is a form of kinetic energy.
I don't know if that is correct, but I hope it helps!!!!
If the ball rolls out of bounds on the sideline in soccer, what is the result?
a.Free Kick
b.Goal Kick
c.Throw-In
d.Corner Kick
What is leptin released by and how would you predict the levels of leptin to be in nicole when compared to a healthy, female adult of similar age and weight?.
Leptin is released by adipocytes, and I predict that the levels of leptin would be decreased in Nicole when compared to a healthy, female adult of similar age and weight.
The body regulates itself in two ways, neural signals and hormones. Hormones are chemical messengers released by endocrine glands into the blood stream that carry out a particular function in the body. The hormone that regulates appetite and body weight is leptin.
Leptin is released by fat storing cells in the body called adipocytes. The word 'leptin' comes from a Greek word 'leptos' meaning 'fat controller', perfectly fitting its function. Since leptin is stored in the fat tissues, a person's weight has a direct effect on the levels of leptin in a person. When we lose weight, the amount of leptin circulating in the body decreases, leading to more appetite and weight gain.
A lack of leptin in the body, arising from genetic diseases results in uncontrolled appetite and obesity. Generally, female adults also produce less leptin than male adults
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What is the acceleration of a car with the mass of 1’980 kg if it experiences a net horizontal force of 1’000 N
Answer:
See below
Explanation:
For the, just remember the equation
F = m a
1000 N = 1980 kg * a
1000/1980 = a = .505 m/s^2
Please help guyss!!!
You leave your house walk 2 miles north to go to the store, then 3 miles south to go to a friend's house. What is your total DISPLACEMENT and DISTANCE traveled?
Explanation:
The distance traveled north ward = 2 miles
distance traveled south ward = 3miles
Displacement is the distance traveled in a specific direction. So, it depend on the start and finish point.
The displacement = 3 miles - 2miles = 1mile southward
Distance is the total length of path;
Distance = 3 miles + 2 miles = 5miles