A student walks 3 north and 4 m west. The magnitude of the resultant displacement for the student is

In the game motorized catapult catch, two players throw a ball to one another while moving towards each other. The game is played such that if the ball is missed, it will travel some distance before it comes to a stop. The aim of the game is to see which player can throw the ball to the other before it comes to a stop. The problem above is stated as follows:

If you and your friend are playing motorized catapult catch, where you move towards each other while throwing a ball back and forth. If you are moving at 1.5 m/s, your friend is moving at 4.5 m/s and you can throw the ball at 25 m/s, how far will the ball have traveled if you start 200.0 m apart Solution Given the scenario, we can say that we have two players who are moving towards each other with speeds of 1.5 m/s and 4.5 m/s respectively.

Let's assume that the two players meet at a point, x. At this point, we can say that the ball is thrown at a speed of 25 m/s towards the other player. At this point, we can calculate the time it takes for the ball to reach the other player. Using the formula time = distance/speed, we can find the time it takes for the ball to reach the other player. The distance covered by the ball is given by: distance covered by ball

= 200 - x + 200 - x = 400 - 2xLet's call the time it takes for the ball to travel from one player to the other t. Thus:25t = 400 - 2xt = (400 - 2x)/25Now that we have found the time it takes for the ball to travel, we can now use the formula distance = speed × time to find the distance covered by the ball. Therefore, we can write: distance = 25t= 25(400 - 2x)/25= 400 - 2xHence, the distance covered by the ball is given by 400 - 2x. Answer: 400 - 2x.

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The net force on an object is determined by the sum of all the external forces acting on it, while the acceleration is determined by the net force divided by the mass of the object.

When the acceleration of a system is zero, it means that the system is either at rest or moving at a constant velocity. In such cases, the net force on the system must be zero according to Newton's second law, which states that the net force is equal to the product of mass and acceleration.

However, the internal forces within the system can still exist and exert forces on each other. These internal forces can cancel each other out, resulting in a zero net force on the system. For example, in a balanced tug-of-war between two teams, the net force on the rope is zero even though the teams are applying forces in opposite directions.

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Power = 6.00 V * 0 A = 0 W, Energy = 0.5 * 4.50 H * (final current)^2,

Power (dissipated) = (final current)^2 * 8.00 Ω, Power (battery) = Power (dissipated) + Power (stored).

The circuit is completed, the rate at which the battery supplies electrical energy to the circuit can be determined by calculating the power delivered by the battery. The power is given by the formula:

Power = Voltage * Current

Since the inductor is just connected to the battery, the initial current is zero (I = 0) because the inductor resists changes in current. Therefore, the initial rate at which the battery supplies electrical energy is:

Power = 6.00 V * 0 A = 0 W

So, just after the circuit is completed, the battery is not supplying any electrical energy to the circuit.

When the current reaches its final steady-state value, the energy stored in the inductor can be calculated using the formula:

Energy = 0.5 * L * I^2

where L is the inductance and I is the current.

Plugging in the values, we have:

Energy = 0.5 * 4.50 H * (final current)^2

The rate at which electrical energy is being dissipated in the resistance of the inductor can be calculated using the formula:

Power (dissipated) = I^2 * R

where I is the current and R is the resistance.

Plugging in the values, we have:

Power (dissipated) = (final current)^2 * 8.00 Ω

The rate at which the battery supplies electrical energy to the circuit is equal to the sum of the power dissipated in the resistance and the rate at which energy is stored in the inductor:

Power (battery) = Power (dissipated) + Power (stored)

Substituting the appropriate formulas and values, we can determine the rate at which the battery supplies electrical energy to the circuit.

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Answer:

I'm not sure but I think it is electric currents in the outer core

Answer:

The __law__ conservation

of state that either energy may produced nor destroyed

Answer:

how long it will take a shell fired from a cliff at an initiaia velocity 800m/s at an angel of 30° below the horizontal to reach the ground 150m?

A resistor in series means that it has a direct connection to the battery, basically components that are connected one after another

In this series, the resistors that are in series are A and D since B and C are in parallel.

Therefore the answer is option C

Answer:

Destructive interference

Answer: I believe his brother, Mike, who is 6'2, will have the longer shadow.

This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2 Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

Here's the solution to the given problem: Let the origin of our coordinate system be located at the center of the platform. We can assume that there is no friction between the platform and the ground. If v  Rw, the woman will collide with the center of the platform after the platform stops moving because it is not able to move with the required speed to reach the center of the platform before it stops. The net torque about the origin, assuming that the angular momentum is conserved, is Iα = τ, or, assuming that the angular momentum is conserved,T2−T1=IwoR2wR2+mr2αT2 = Mg/2 + Mv/RT1 = (M + m)g/2Let a be the speed of the platform just after the woman reaches the center, which is given by a = v + αr. This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

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Both low energy explosives and high energy explosives react slower than the speed of sound. The statement is false.

The speed at which explosives react can vary depending on their energy content. Low energy explosives typically have a slower reaction rate than the speed of sound, meaning that the reaction propagates through the material at a speed slower than sound waves travel through that medium. This slower reaction rate is due to the lower energy content and characteristics of the explosive material. On the other hand, high energy explosives can indeed react faster than the speed of sound. These explosives release a significant amount of energy in a short period, causing a rapid and explosive reaction. The reaction front can travel through the material faster than the speed of sound in that medium, resulting in a shockwave that moves faster than sound.

It's important to note that the specific reaction speed can depend on various factors, including the type of explosive, its composition, and the conditions in which it is detonated. However, as a general trend, low energy explosives react slower than the speed of sound, while high energy explosives can react faster, creating shockwaves that move faster than sound.

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(1) The voltage drop in the second resistor is 10 V.

(2) The voltage drop across each resistor will all double to match change in resistance.

The given parameters:

The total voltage in a series circuit is given as;

\(V_T = IR_1 + IR_2\\\\V_T = V_1 + V_2\)

The voltage drop in the second resistor is calculated as follows;

\(V_2 = V_T - V_1\\\\V_2 = 15 - 5\\\\V_2 = 10 \ V\)

(2)

The resistance of the circuit:

\(R = \frac{V}{I} = \frac{10}{2} = 5 \ ohms\)

When the total resistance is doubled;

In series circuit, the current in each resistor is constant, the voltage drop is calculated as;

\(V = IR\\\\V = 2 (5+5)\\\\V = 20 \ V\)

Thus, we can conclude that the voltage drop across each resistor will all double to match change in resistance.

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When a meter stick is placed on a support, such as a pivot or fulcrum, it will balance if the center of mass of the meter stick is directly above the support. This is because the center of mass is the point where the weight of the meter stick can be considered to be concentrated, and if this point is directly above the support, the weight will be balanced.

If the center of mass of the meter stick is not directly above the support, the meter stick will not be balanced and will tip over. This is because there will be a net torque acting on the meter stick, which is the product of the weight force and the distance between the center of mass and the support. If the torque is non-zero, the meter stick will rotate until the torque is balanced.

Therefore, to ensure that the meter stick is balanced on the support, the center of mass must be located at the support position. If the center of mass is not at the support position, the meter stick will not balance and will either tip over or rotate until it reaches a balanced position.

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The correct answer is B. 50 feet.

Liquefaction is a phenomenon that occurs when water-saturated soil loses its strength and behaves like a liquid.

This can happen during an earthquake, when the shaking causes the soil particles to lose contact with each other. Liquefaction can also be caused by other factors, such as heavy rains or flooding. The depth of groundwater is an important factor in determining whether or not liquefaction will occur. If the groundwater is close to the surface, the soil is more likely to liquefy. This is because the water provides a pathway for the soil particles to move around, and it also reduces the friction between the particles. Most code documents state that liquefaction is no longer a concern once the historic high groundwater is deeper than 50 feet from the surface. This is because the soil at this depth is typically not saturated with water, and it is therefore less likely to liquefy. However, it is important to note that liquefaction can still occur at depths greater than 50 feet, especially if the soil is very loose or if there is a lot of groundwater.

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For 1/4 value of r is the potential energy equal to the total energy.

Potential energy is the form of energy that a object gain.

first want to find the value of our, what value of R is the potential energy equal to the total energy? So you are is equal to negative 1/4 pi epsilon naught E squared over R. Which is the potential energy. And E. This is a total energy. So we just set these two values equal to each other. So negative 1/4 pi epsilon naught E squared over R. Is equal to negative M. E. To the fourth divided by eight E squared and squared each squared and R is equal to two. So we can go ahead and solve this. We get R. Is equal to two. Absolutely not H squared divided by pi M. R. E squared. And actually this is just two times A. So the radius is to a. Now part B. We want to find the probability of electron being found in this classically forbidden forbidden region are greater than the classical turning point. So we need, so first of all let's look at the ground state wave function which is one over squared pi a cubed times E. To the negative are over A. This is what will be needed to integrate to find the probability. So the probability goes from R. is equal to two way to sigh.

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During waxing gibbous phase of the Moon, the Moon appears to be more than half illuminated but less than fully illuminated. At this phase, the Moon is positioned between first quarter and full moon phases.

The position of the Moon and the Earth during a waxing gibbous phase can be described as follows:

The Moon is located on the opposite side of the Earth from the Sun, and it is moving towards the full moon phase.

The Earth is located between the Moon and the Sun, with the Sun's light illuminating the near side of the Moon.

From the perspective of an observer on Earth, the Moon appears to be getting larger and brighter as it moves towards the full moon phase. The waxing gibbous phase is an important period for lunar observations, as the illuminated portion of the Moon provides ample opportunity to observe its surface features with a telescope.

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Answer:

f=1.92 cm

If ans is correct reply for explanation.

The typical focal length formula looks as follows: 1/Focal length = 1/Image distance + 1/Object distance , where: Image distance and Object distance are given in mm.

1/f = 1/u + 1/v

1/f = 1/133 + 1/22.5

    = 0.007 + 0.044

    = 0.0514 mm

"The focal length of an optical system is a measure of how strongly the system converges or diverges light; it is the inverse of the system's optical power. A positive focal length indicates that a system converges light, while a negative focal length indicates that the system diverges light."

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Answer:

Below

Explanation:

384 400 km / 300 000 km/s = 1.28 seconds

Answer:

a.2.5 m/s

b.2.27 m/s

c.2.385 m/s

Explanation:

velocity=displacement/time

a.50/20=2.5 m/s

b.50/22=2.27 m/s

c.average velocity=total velocity/2

=2.27+2.5/2

=4.77/2

=2.385 m/s

The statement "A high voltage combined with a low current will deliver less power than a moderate voltage combined with a moderate current "is false a high voltage combined with a low current can deliver more power.

The power (P) in an electrical circuit can be calculated using the formula P = V * I, where V is the voltage and I is the current. Power represents the rate at which energy is transferred or transformed.

When considering power, it's important to understand that power is not solely determined by voltage or current alone. It depends on their combination.

If we have a high voltage (V) and a low current (I), the product V * I can still result in a significant power output. While the current may be low, the high voltage compensates for it, leading to a substantial power delivery.

Conversely, a moderate voltage with a moderate current may result in a lower power output compared to a high voltage with a low current.

Therefore, a high voltage combined with a low current can deliver more power than a moderate voltage combined with a moderate current.

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Answer:

5 m/s²

Explanation:

Acceleration = change in speed/time taken

20-5=15

15/3= 5 m/s²

Explanation:

Which of the following solutions have a concentration of 0.11 g/mL?

Answer:

22 g of acetic acid in 200 mL of water

Explanation:

22g/200mL = 0.11 g/mL

Momentum of the 80 kg player is 240 kg⋅m/s (80 kg× 3 m/s).Momentum of the 60 kg player is 180 kg⋅m/s (60 kg×3 m/s).The velocity of the 60 kg player must be -3 m/s.

Momentum is an important concept in physics which describes the physical quantity of a moving body's inertia. It is a vector quantity, meaning it has both a magnitude and a direction. Momentum is equal to the product of mass and velocity, and is measured in kilograms-meters per second (kgm/s). Momentum is conserved in closed systems, meaning that the total momentum of a system will remain the same, regardless of any changes in mass or velocity. Momentum is a very useful tool for understanding the motion of objects, particularly in collisions and impacts.

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Answer:

Explanation:

A tunnel, dug from one side of the Earth to the other would be, on average, 12,742 km. ... If you jumped into the tunnel, you'd fall down towards the center of the Earth, accelerating constantly, thanks to gravity.

Answer:

43.3 m/s.

Explanation:

Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:

Total energy = Potential energy + Kinetic energy

Kinetic energy = Total energy - Potential energy

Kinetic energy = 300 J - 40 J = 260 J

However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:

Potential energy = mgh

40 J = m(9.81 m/s^2)(300 m)

m = 0.137 kg

Now we can use the kinetic energy to find the velocity:

Kinetic energy = (1/2)mv^2

260 J = (1/2)(0.137 kg)v^2

v^2 = (2*260 J) / 0.137 kg

v = 43.3 m/s (rounded to one decimal place)

Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.

Answer:

volume is the correct answer

Explanation:

When separated by 4 meters, the 20,000-kilogram truck and the 3,200-kg automobile are attracted to one other with a force of attraction of roughly 0.0000016748 N. The right response in this case is option A.

Newton's rule of universal gravitation, which says that the force between two things is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers, may be used to compute the force of attraction between two objects. The equation can be written mathematically as:

F = G * (m1 * m2) / r^2

Where:

F is the gravitational constant, while G is the force of attraction.

The two objects' masses are m1 and m2, and their separation from one another's centers is r.

In this instance, the truck weighs 20,000 kg, whereas the automobile weighs 3,200 kg. They are 4 meters apart from one another.

With these values entered into the formula, we obtain:

F = (6.674 × 10^-11 N(m/kg)^2) * (20,000 kg * 3,200 kg) / (4 m)^2

F = 1.6748 × 10^-6 N

Therefore, at a distance of 4 meters, the force of attraction between the 3,200-kilogram automobile and the 20,000-kg truck is roughly 0.0000016748 N.

Option A is therefore the one that comes the closest to this value, at 0.0003 N.

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