a student starts with 1.157 g of copper chloride. after reacting with aluminum, he recovers 0.523 g of copper. what is the percent chlorine in the copper chloride? give the answer to correct significant figures.

The grams of the mercury, Hg can be produced to from 3.55 moles of  Hg is 712 g.

The reaction is given below as :

2HgO  --->   2Hg + O₂

Given that :

The moles of HgO = 3.55 moles

2 moles of the HgO produces the 2 moles of Hg, Therefore the molar ratio is same : HgO : Hg = 2 : 2.

The number of moles of Hg = 3.55 mol

The number of moles = mass / molar mass

3.55 mol = mass / 200.59 g /mol

Mass = 712 g.

Thus , the mass of the Hg produces is 712 g.

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In a concentration cell, the movement of electrons from the anode to the cathode is driven by the difference in concentration of the electrolyte solution between the two electrodes.

The electrode with the higher concentration of ions will have a higher tendency to lose electrons and become the anode, while the electrode with the lower concentration of ions will have a higher tendency to gain electrons and become the cathode. This movement of electrons creates an electric current that can be harnessed for various applications.
In a concentration cell, the movement of electrons from the anode to the cathode is driven by the difference in ion concentrations between the two half-cells. This concentration gradient leads to a potential difference, which provides the driving force for the electron flow.

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

The simple deposit multiplier is higher than the real-world money multiplier if households decide to keep some portion of each check they deposit in their possession as money.

For each unit of money a bank has in reserves, the deposit multiplier determines the most money that can be made. The portion of the deposit amount that can be lent out is represented by the deposit multiplier. The Federal Reserve's reserve requirement typically determines that proportion of real-world money multiplier.

The process by which banks lend money and the outcome is more money flowing in the economy is referred to as a "real-world money multiplier." That is, the amount of money is increased.

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Step 1

The reaction:

1 Sn(HCO3)2 + 1 Ag2Cr2O7 => 1 SnCr207 + 2 AgHCO3 (completed and balanced)

-----------------

Step 2

Information provided:

167 g of Tin (Il) hydrogen carbonate, Sn(HCO3)2 => the limiting reactant

The excess = Ag2Cr2O7

-----

Information needed:

The molar mass of Sn(HCO3)2 = 240.7 g/mol (use your periodic table please)

---------------

Step 3

By stoichiometry,

1 mol Sn(HCO3)2 = 240.7 g

Procedure:

1 Sn(HCO3)2 + 1 Ag2Cr2O7 => 1 SnCr207 + 2 AgHCO3

240.7 g Sn(HCO3)2 ---------- 2 x 1 mole AgHCO3

167 g Sn(HCO3)2 ---------- X

X = 167 g Sn(HCO3)2 x 2 x 1 mole AgHCO3/240.7 g Sn(HCO3)2

X = 1.39 moles

Answer: 1.39 moles AgHCO3 are produced

Answer:

\(MgCl_{2} O_{4}\)

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

15.3 % = 15.3g Mg, 44.5% = 44.5g Cl, 40.2% = 40.2g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

15.3/24.3 = .630 mol

44.5/35.5 = 1.25 mol

40.2/16.0 = 2.5 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subscripts) of the empirical formula.

.630 mol/.630mol = 1

1.25 mol/.630mol = 2

2.5 mol/.630mol = 4

So the empirical formula is

\(MgCl_{2} O_{4}\)

Answer:

Based on the observations described, we can classify the metal ions as follows:

Definitely present: The metal ions that formed precipitates with H2S under acidic conditions are definitely present. These metal ions include:

Pb2+ (lead)

Hg2+ (mercury)

Cu2+ (copper)

Bi3+ (bismuth)

Cd2+ (cadmium)

Definitely absent: The metal ions that did not form precipitates with H2S under both acidic and basic conditions are definitely absent. These metal ions include:

Na+ (sodium)

K+ (potassium)

Mg2+ (magnesium)

Ca2+ (calcium)

Al3+ (aluminum)

Fe3+ (iron III)

Possible presence: The metal ions that did not form precipitates with H2S under acidic conditions but formed precipitates under basic conditions are possibly present. These metal ions include:

Zn2+ (zinc)

Mn2+ (manganese)

Ni2+ (nickel)

Co2+ (cobalt)

However, we cannot definitively conclude that these metal ions were present in the original mixture, as their precipitation under basic conditions may have been due to other factors such as the formation of complex ions or the pH dependence of their solubility. Further tests would be needed to confirm their presence.

Explanation:

The metal cations most likely present in the original mixture were iron (Fe2+), lead (Pb2+), and zinc (Zn2+).

The iron ions would definitely have been present since they reacted with both the dilute HCl and the H2S to form a precipitate both times. Lead and zinc ions were also likely present since they too reacted with H2S, forming a precipitate in the second trial.

The metal cations that were definitely not present in the original mixture were copper (Cu2+), silver (Ag+), and cadmium (Cd2+). Copper and silver do not react with H2S and therefore no precipitate was formed.

Cadmium does react with H2S, but did not form a precipitate in the second trial when the pH was raised to 8, likely because it was not present in the original solution.

It is possible that nickel (Ni2+) and chromium (Cr3+) were present in the original mixture since they do not react with either HCl or H2S. However, since they did not react with the sodium carbonate to form a precipitate, it is impossible to definitively conclude their presence.

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Answer:

n = 7.86 mol

Explanation:

This question can be solved using the ideal gas law of PV = nRT.

Temperature must be in K, so we will convert 22.5C to 295 K ( Kelvin = C + 273).

R is the ideal gas constant of 0.0821.

(2.24atm)(85.0L) = n(0.0821)(295K)

Isolate n to get:

n = (2.24atm)(85.0L)/(0.0821)(295K)

n = 7.86 mol

Answer:

C12h22o11 moles to grams

1 mole is equal to 1 moles C12H22O11, or 342.29648 grams.

hope this helps

Explanation:

Why does cold soda taste great but warm soda taste flat ?

Answer

When a carbonated drink is at room temperature, it is less fizzy and taste flat. Cool it down and it will taste better because the drink is designed to be drank at a lower temperature for optimal fizz and taste.

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Answer:

151.33 g/mol

Explanation:

TRUST ME -_-

Answer:  The correct answer is C. Yellow to orange.

When a base is added to a potassium dichromate (K2Cr2O7) solution, the color change occurs due to the reduction of the chromium(VI) ions (Cr2O7 2-) to chromium(III) ions (Cr3+). The original color of the potassium dichromate solution is yellow-orange.

As the base is added, the solution becomes more alkaline, and the chromium(VI) ions undergo reduction to form chromium(III) ions. This reduction reaction results in a color change from yellow to orange.

Therefore, the correct answer is C. Yellow to orange.

Explanation:

Answer:

volume= 3

Explanation:

D=m/v

2.7=8.1/v

2.7v=8.1

8.1/2.7= 3

8.1/3= 2.7 which is the density!

Answer:

3 mL

Explanation:

\(V = \frac{8.1 g}{3 mL} = 2.7 g/mL\)

Answer:

will you like work ot just the answers

Protonation of the carbonyl O atom, Nucleophilic attack by the alcohol, Deprotonation of the conjugate acid of the hemiacetal, Protonation and elimination of H2O, Second nucleophilic attack, Deprotonation of the conjugate acid of the acetal.

An acetal is a functional group in organic chemistry with connectivity R2C(OR')2. The R groups in this case can be either hydrogen or organic fragments (a carbon atom with any additional atoms connected to it), but the R' groups must be organic fragments. The two R' groups might or might not be equivalent to one another (a "symmetric acetal") (a "mixed acetal"). Acetals have the same oxidation state at the central carbon as similar carbonyl compounds and are generated from or convertible to aldehydes or ketones Nucleophilic attack. However, they exhibit significantly greater chemical stability and reactivity. Since the center carbon atom is bound by four bonds, it is saturated and has a tetrahedral geometry.

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When a solid is heated, its surface area expands due to a type of thermal expansion known as superficial expansion.

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Answer:

5 ms2

Explanation:

The acceleration of the ball is 5 ms2.

Acceleration is the rate at which an object's velocity with respect to time changes. It is a vector quantity to accelerate (in that they have magnitude and direction). The direction of the net force acting on an object determines the direction of its acceleration.

The acceleration of the car in its present direction of motion is referred to as a linear acceleration (or tangential acceleration in circular motions), and the passengers on board feel a force pressing them back into their seats as a result.

The acceleration that is used to change direction is referred to as radial acceleration (or centripetal acceleration in circular travels), and the reaction that the passengers feel is a centrifugal force.

Therefore, The acceleration of the ball is 5 ms2.

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To calculate the numerical change in vapor pressure with a change in temperature using the Clausius-Clapeyron equation, you need the heat of vaporization and the gas constant, R.

The Clausius-Clapeyron equation is a useful tool for estimating the change in vapor pressure with temperature. It requires the following quantities: the heat of vaporization (ΔHvap), which represents the energy needed to convert a substance from liquid to vapor at a constant temperature, and the gas constant (R), which is a fundamental constant with a value of 8.314 J/mol·K. Assuming both the initial and final temperatures are known, the equation allows you to calculate the numerical change in vapor pressure. Therefore, the two quantities needed to calculate the change in vapor pressure with temperature using the Clausius-Clapeyron equation are the heat of vaporization and the gas constant, R.

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Answer:

Acetyldehyde

Explanation:

It's a functional group essential for making alcohol and other products

Methanol (CH₃OH) is used to manufacture formaldehyde.

Formaldehyde can be described as a naturally occurring organic compound with the formula CH₂O and structure H-CHO. Pure Formaldehyde is a pungent, colorless gas that polymerizes spontaneously into paraformaldehyde. Formaldehyde is the simplest of aldehydes (R-CHO).

Formaldehyde is a colorless gas with a pungent, irritating odor. This gas is stable at about 150 °C but it can polymerize when condensed to a liquid.

Formaldehyde can be produced industrially by the oxidation of methanol. The common catalysts are iron(III) oxide, silver metal, iron-molybdenum oxides, or vanadium oxides.

2 CH₃OH  +  O₂   →   2 CH₂O + 2 H₂O

The silver-based catalyst works at a temperature of about 650 °C. Two chemical reactions on it produce formaldehyde simultaneously:

CH₃OH   →  CH₂O   +  H₂

In principle, formaldehyde can be generated by the oxidation of methane, but it is not industrially viable as methanol is more easily oxidized than methane.

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Answer:

p=F/A.Explanation:

Answer: seawater at pH 8 has the greatest concentration of hydroxyl ions[OH-].Thus, option (c) is the correct answer.

Explanation:

When the pH value increases from 7 to 14,it represents increase in the OH- ion concentration.pH scale determines the acidity or basicity of the solution.The value below 7 represents that solution is acidic and above 7 represents that solutions is basic.

The pH of pure water at room temperature is 7.It means it is neither acidic nor basic,it is neutral.The pH value of Battery Acid is 0 which means it is highly acidic.The pH value of Liquid drain cleaner is 14 which means it is highly basic.

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Answer:

Organisms with a recessive trait can have a dominant allele for the trait.

Explanation:

hope this helps

Answer

D

Organisms can be bred for specific traits based on a pattern of inheritance.

Answer:

gas doesn't have a definite volume

Two answers. Pressure and they're not big enough.

Now, you see, in order for hydrogen to be metallic, the interiors of Uranus and Neptune would have to have more pressure.

Pressure can be defined as the exertion of force upon a surface by an object, fluid, etc., in contact with it.

The three states of matter on Earth are solid, liquid, and gas. An element's shape is determined by its temperature and pressure. On Earth, hydrogen is generally a gas, but it may be intentionally cooled and compressed to change its state into a liquid or a solid. Hydrogen is still a non-metal even in these states; since its atoms strongly cling on to their electrons, it has poor electrical and thermal conductivity. Contrarily, metals have good electrical and thermal conductivity due to the arrangement of their atoms, which forms a lattice that makes it simple for the outermost electrons of one atom to go to another.

Jupiter and Saturn are the two gas giants in our solar system. Based on their densities, both planets have a considerable amount of hydrogen in them. However, the hydrogen in these giants is heated and compressed to such high temperatures and pressures that it assumes a number of peculiar phases, including liquid metallic hydrogen. Hydrogen, as I previously stated, is a non-metal. However, in Jupiter and Saturn, the extreme temperatures and pressures cause hydrogen atoms to lose their electrons, resulting in a stew of free-floating hydrogen nuclei (protons) and electrons. The ability of the electrons to travel freely between the nuclei due to their unbound state is a characteristic of metals. This is metallic hydrogen, which has a metallic-like behavior. Metallic hydrogen is conductive and is thought to play a significant role in the dynamo that drives the magnetic fields of Jupiter and Saturn. (However, the dynamo on Earth is propelled by liquid iron, a real metal.)

The ice giants of our solar system, Uranus and Neptune, are too dense for hydrogen to make up a significant portion of their composition. In addition, because of how similar their masses are, planetary scientists presume that the innards of these two planets are comparable and that hydrogen makes up just around 15% of their masses. Although hydrogen is thought to form a liquid molecular shell deeper into Uranus and Neptune and is present in their atmospheres, it never experiences the pressures and temperatures necessary to transform into metallic hydrogen.

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To find the correct number significant digits, learn the concentration and initial rate.

What is concentration?

In chemistry and related fields, the idea of concentration is used frequently. It is a way to gauge how much of one substance is incorporated into another.

What is initial rate?

When a reaction first begins, or when t = 0, its initial rate is the rate that exists at that precise moment. At time zero (t), the slope of the reactant concentration versus the time curve is equal to the initial rate.

Rak=k(H₂) (NH₃) Rak law expression

1. reaction order w.r.t H₂ is ⇒2

2. reaction order w.r.t  NH₃ is⇒ 1.

3. overall order 2+1=3 ( bird order reaction)

4. k(H₂) (NH₃)= 0.740⇒ 1

H₂ is doubled ⇒ r₂=k(H₂) (NH₃)=4k(H₂) (NH₃)⇒2

(2)/(1) = r₂/r₁ = 4k(H₂) (NH₃)/k(H₂) (NH₃)=4

r₂= 4∝ r₁ = 4∝ 0.740=2.96m/s

5. r= 6.0∝ 10^⁴m/s, (H₂)= 0.98m, (NH₃)= 0.31m

r=k(H₂) (NH₃)

k=r/(H₂) (NH₃)= 6.0 ∝ 10^⁴/(0.98)^²(0.31)=201528.93m^⁻²s^⁻¹

K=2.0 ∝ 10^5m^⁻²s^⁻¹

Therefore, the significant digit is K=2.0 ∝ 10^5m^⁻²s^⁻¹

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For a volume of tissue, the Dose `D would be 1 × 10^6 [cm−2] × 0.0233 [cm2 g−1] × 1 [MeV] / 1.602 × 10^-13 [J MeV−1] × 1.0 [g] = 1.448 mGy]`. The condition that is necessary to make this calculation is to assume a tissue type because the value of the energy absorption coefficient varies with different tissue types.

A) Calculation of dose in mGy for a volume of tissue and fluence of 1 × 10^6 [cm−2] of an energy of 1 MeV

For this calculation, the required formula is:

`Dose = Fluence × Energy Absorption Coefficient`

The fluence given is:

1 × 10^6 [cm−2] of an energy of 1 MeV

The value of energy absorption coefficient varies according to the tissue. Therefore, we have to assume a tissue type.For example, for the tissue type of soft tissue, the value of the energy absorption coefficient is:

0.0233 [cm2 g−1]

Thus, Dose `D = 1 × 10^6 [cm−2] × 0.0233 [cm2 g−1] × 1 [MeV] / 1.602 × 10^-13 [J MeV−1] × 1.0 [g] = 1.448 mGy]`

B) Condition necessary to make this calculation and why?

The condition that is necessary to make this calculation is to assume a tissue type because the value of the energy absorption coefficient varies with different tissue types.

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