A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 15 m/s at an angle θ = 31 ° below horizontal. The stone moves without air resistance; use a Cartesian coordinate system with the origin at the stone's initial position.

Required:
With what speed, vf in meters per second, does the stone strike the ground?

The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:

F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².

Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.

The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.

Therefore, we have:

m₁ = 50 kg

m₂ = 7 × 10²² kg

r = 380,000,000 m

G = 6.7 × 10⁻¹¹ N m²/kg²

Substituting these values into the formula, we get:

F = (G × m₁ × m₂) / r²

F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²

F = 1.15 N

Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

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Answer:

The maximum torque is  \(\tau_{max} = 1.139 *10^{-7} \ N \cdot m\)

Explanation:

From the question we are told that

   The length of the wire is  \(l = 26.0 \ cm = 0.26 \ m\)

     The current flowing through the wire is  \(I = 5.77mA = 5.77 *10^{-3} \ A\)

      The magnetic field is  \(B = 3.67 \ mT = 3.67 *10^{-3 } T\)

The maximum torque is mathematically evaluated as

        \(\tau_{max} = \mu B\)  

Where \(\mu\)  is the magnetic dipole moment which is mathematically represented as

        \(\mu = \frac{I l^2}{4 \pi n }\)

Where \(n\) is the number of turns which from the question is  1

    substituting values

       \(\mu = \frac{ 5.77 *10^{-3} * 0.26^2}{4 * 3.142* 1 }\)

     \(\mu = 3.10 4* 10^{-5} A m^2\)

Now  

      \(\tau_{max} = 3.104 *10^{-5} * 3.67 *10^{-3}\)  

      \(\tau_{max} = 1.139 *10^{-7} \ N \cdot m\)  

The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

voltage

Explanation:

the current in a circuit, the voltage can be increased.

According to Ohm's law, when all other physical parameters, including temperature, are held constant, the voltage across a conductor is directly proportional to the current flowing through it.

From ohm's law, we can state that voltage is directly proportional to current.

Looking at the following formula:

I = V/R

Where V is voltage,

I is current, and

R is resistance

In the above equation, Current and Voltage are in a direct relationship such that if I is increased, V is also increased, and vice versa.

Therefore, To increase the current, the voltage should be increased.

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The equivalent resistance for the entire circuit is equal to 1830 Ω.

In a series combination of resistors, the resistors are connected end-to-end. Assume two resistors, R₁ and R₂ which are connected with each other in a series then their effective resistance:

Total Resistance, R =  R₁ + R₂

In a parallel combination of resistors, the resistors are connected parallel to each other.

\(\displaystyle \frac{1}{R} =\frac{1}{R_1} +\frac{1}{R_2}\)

The resistance in parallel, R₁ = 60 Ω , R₂ = 60 Ω , R₃ = 30 Ω

The equivalent resistance for the entire circuit will be given by:

\(R_{eq} =R' + R_3\)

\(\displaystyle R_{eq} = \frac{R_1R_2}{R_1+R_2} + R_3\)

\(\displaystyle R_{eq} = \frac{60\times 60}{1+1} + 30\)

R = 3600/2 +30

R = 1800 +30

R = 1830 Ω ​

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The site from above in which its activities would definitely result in island arcs, volcanoes and mountains is plate 2.

The correct answer choice is option b.

A volcanic arc simply refers to plates of volcanoes which are produced directly above a subducting oceanic tectonic plate. This belt or plate of volcanic arc is ultimately arranged an arc shape. This goes to say that it is formed when two different plates in the site of action collide against each other.

That being said, when two different pieces of plates collide against each other or it's smashing of plates together. It results in the formation of tectonic plates which at the end of the activities forms a mountain.

In conclusion, it can be deduced from the explanation given above that the smashing of plates with one another leads to the formation of volcanic island arcs.

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An electric motor is used to convert electrical energy to mechanical energy; therefore, the answer is B.

Answer:

B is correct

Explanation:

Maximum Kinetic energy= Work done.

Now, Work done=mgh=mg(L−Lcosθ)=mgL(1−cosθ)

Option B is thus correct.

Answer:

- 0.33 m/s

Explanation:

An illustration is shown above,

In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,

m1u1 - m2u2 = (m1 + m2)v

Where,

m1 = mass of the first object

u1 = initial velocity of the first object

v1 = final velocity of the first object

m2 = mass of the second object

u2 = initial velocity of the second object

v2 = final velocity of the second object

Therefore,

(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v

12 - 16 = 12v

-4 = 12v

Divide both sides by 12,

-4 / 12 = 12v / 12

-1 / 3 = v

v = -0.33 m/s

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The force exerted between the charges q1 and q3 is   -5.25 × 10⁻⁶ N and that between q2 and q3 is -2.93   × 10⁻⁶ N. Hence the net force is - 8.18  × 10⁻⁶ N .

According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:

Fc = Ke q1 q2 /r²

where Ke = 8.9 × 10⁹ Nm²/C²

Given the charge of  q1 = 3.97  × 10⁻⁹ C

charge of q3  = -5.95 × 10⁻⁹ C

distance r = 0.200 m

then Fc =  8.9 × 10⁹ Nm²/C²  ( 3.97  × 10⁻⁹ C) (-5.95 × 10⁻⁹ C)/(0.200 m)² = -5.25 × 10⁻⁶ N

Similarly, the force on q3  by the charge q2 is calculated as follows:

distance to q2 = 0.30 m

charge of q2 = 4.99 × 10⁻⁹ C.

Then Fc =   8.9 × 10⁹ Nm²/C²  (4.99 × 10⁻⁹ C ) (-5.95× 10⁻⁹ C)/(0.30 m)² = - -2.93 × 10⁻⁶ N

The net electric force acting on A =  3.9 × 10⁻⁵ N - (-1.9 × 10⁻⁵ N) = 5.8 × 10⁻⁵ N.

Therefore, the net electric force acting on q3 is  8.18  × 10⁻⁶ N.

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Your question is incomplete. But your complete question probably was:

Two point charges are placed on the x-axis as follows: charge  3.97 nC is located at 0.200 m (q1) and charge 4.99 nC (q3) is at -0.304 m .What is the magnitude of the total force exerted by these two charges on a negative point charge q3

= -5.95 nc that is placed at the origin?

The mass will be moving at 14.3 m/s when it reaches the equilibrium position.

To determine the speed of the mass when it reaches the equilibrium position, we need to consider the conservation of mechanical energy, which includes both the spring potential energy and the gravitational potential energy.

The total mechanical energy (E) of the system is the sum of the potential energy and the kinetic energy:

E = PE (potential energy) + KE (kinetic energy)

At the equilibrium position, all the potential energy is converted into kinetic energy, so the total mechanical energy is entirely in the form of kinetic energy.

The potential energy stored in the spring (PE_spring) is given by Hooke's Law:

PE_spring = (1/2) * k * \(x^{2}\)

Where k is the spring constant (250 N/m) and x is the displacement from the equilibrium position (0.32 m).

PE_spring = (1/2) * 250 N/m *\((0.32 m)^2\)

PE_spring = 12.8 J

The change in gravitational potential energy (ΔPE_gravity) is given by:

ΔPE_gravity = m * g * h

Where m is the mass (0.125 kg), g is the acceleration due to gravity (9.8 m/\(s^2\)), and h is the change in height (which is zero in this case since the height doesn't change).

ΔPE_gravity = 0 J

Therefore, the total mechanical energy (E) is equal to the potential energy stored in the spring:

E = PE_spring

E = 12.8 J

Since the total mechanical energy is entirely in the form of kinetic energy at the equilibrium position, we can calculate the speed (v) using the equation:

E = (1/2) * m * \(v^2\)

Rearranging the equation, we get:

\(v^2\) = (2 * E) / m

\(v^2\) = (2 * 12.8 J) / 0.125 kg

\(v^2\) = 204.8 \(m^2\)/\(s^2\)

Taking the square root of both sides:

v = √ 204.8 \(m^2\)/\(s^2\)

v ≈ 14.3 m/s

Therefore, the mass will be moving at approximately 14.3 m/s when it reaches the equilibrium position.

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The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The fraction of a wavelength represented by the first harmonic is 1/2.

The higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

1. The first harmonic of a standing wave on a string with a loose end occurs when there is a node near the driver end and an antinode at the loose end. To measure the frequency of the first harmonic, we need to determine the fraction of a wavelength represented by this standing wave.

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The first harmonic of a standing wave on a string with a loose end consists of a node near the driver end and an antinode at the loose end. This configuration creates the simplest standing wave pattern.

In a standing wave, a node is a point where the amplitude of the wave is always zero, representing a point of minimum displacement. An antinode, on the other hand, is a point of maximum displacement, where the amplitude is at its highest.

Since the loose end does not invert the phase of the wave upon reflection, the reflected wave and the original wave constructively interfere at the loose end, resulting in an antinode.

In the first harmonic, there is exactly half a wavelength between the node near the driver end and the antinode at the loose end.

Therefore, the fraction of a wavelength represented by the first harmonic is 1/2.

2. To predict the frequencies of higher harmonics, we can use the relationship that the frequency of each harmonic is a multiple of the frequency of the first harmonic. The higher harmonics can be calculated as follows:

Second Harmonic: The second harmonic consists of two nodes and one additional antinode compared to the first harmonic. The fraction of a wavelength for the second harmonic is 1/2 * 2 = 1. Thus, the second harmonic has a frequency that is twice that of the first harmonic.

Third Harmonic: The third harmonic consists of three nodes and two additional antinodes compared to the first harmonic. The fraction of a wavelength for the third harmonic is 1/2 * 3 = 1.5. Thus, the third harmonic has a frequency that is three times that of the first harmonic.

Fourth Harmonic: The fourth harmonic consists of four nodes and three additional antinodes compared to the first harmonic. The fraction of a wavelength for the fourth harmonic is 1/2 * 4 = 2. Thus, the fourth harmonic has a frequency that is four times that of the first harmonic.

In general, the higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

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Objective observations do not include bias or opinions.

Observations can capture a child's strengths and weaknesses

This refers to the types of observation that is done through the senses through what we see, touch, feel, hear, smell, and taste.

Hence, we can see that objective observation is important because they provide insight into the strengths and needs of a child.

One of the ways you can capture your observations is through note-taking.

The federal law which ensures that all children and family education information is confidential is called The Family Educational Rights and Privacy Act (FERPA)

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Answer:

Explanation:

To find the speed of the clock at the lowest point in its swing, we can use the formula:

Speed = (distance) / (time)

In this case, the distance is the length of the clock (0.993 m) multiplied by the sine of the maximum angle of the swing (4.57°).

Speed = (0.993 m) x (sin 4.57°)

But we need to keep in mind that the angle needs to be converted to radians before we can use it in the sin function, since the trigonometric functions operate in radians.

So, the first step is to convert the angle from degrees to radians:

4.57° * (π/180) = 0.0799 radians

Now we can plug that angle in the formula,

Speed = (0.993 m) x (sin 0.0799 radians)

This will give us the speed of the clock at the lowest point of its swing.

The pendulum on grandfather clock is 0.993 m long, and swings to maximum 4.57° angle. It is moving at 0.248 m/s, the lowest point in its swing.

A pendulum is a weight suspended from pivot such that it can swing freely. When the pendulum is displaced sideways from its resting position, equilibrium position, then it is subject to a restoring force due to gravity that will accelerate it back towards equilibrium position.

As, m⋅ g⋅ sin(θ)=mv²/(R⋅sinθ)

So, v² = gr sin²Ф

= 9.8 * 0.993 * sin (4.57)

Hence, v= 0.248 m/s

It is moving at 0.248 m/s the lowest point in its swing.

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Answer:

Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.

Answer:

Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.

Explanation:

Answer:

Crawling, bc you are using ur arms and legs and core and lungs while running you are just using your legs and lungs.

Brainliest?

i think

Answer:

physics. The ______ is a systematic way to observe, experiment, and analyze the world. scientific method. The valid digits in a measurement are called the. significant digits.

Explanation:

truth'

Answer: When a disrupted part of the ecosystem is left alone so that nature can help restore itself what people are counting on happening is secondary succession

Explanation:

The current flowing through the 30.0 Ω resistor is 2.0 A, which corresponds to option C.

To find the current flowing through the 30 Ω resistor, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R).

Given that the voltage across the circuit is 120.0 V, we can calculate the current flowing through each resistor.

For the 10.0 Ω resistor, using Ohm's Law: I = V/R = 120.0 V / 10.0 Ω = 12.0 A.

For the 20.0 Ω resistor, again using Ohm's Law: I = V/R = 120.0 V / 20.0 Ω = 6.0 A.

Now, let's find the total resistance in the circuit. Since the three resistors are connected in series, we can add them up: R_total = 10.0 Ω + 20.0 Ω + 30.0 Ω = 60.0 Ω.

Next, we can find the current flowing through the 60.0 Ω equivalent resistance. Again, using Ohm's Law: I = V/R = 120.0 V / 60.0 Ω = 2.0 A.

Finally, to find the current flowing through the 30.0 Ω resistor, we can apply Ohm's Law once more: I = V/R = 2.0 A.

Therefore, the current flowing through the 30.0 Ω resistor is 2.0 A, which corresponds to option C.

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Answer:

increasing the positive charge of the positively charged object and increasing the negative charge of the negatively

charged object

Explanation:

Got it right on edge

Initially rolling inside a horizontal circle five meters above the ground at a speed of two meters per second, the ball breaks the string as it approaches true North. Though it is falling, it is still heading in the direction

The lower string, however, is the one that snaps if it is forcefully yanked. The prevailing theory holds that the mass's inertia prevents it from moving and, as a result, from pulling on the top string.

If both strings are equally strong, the top string will break sooner. However, a change in tension from the lower string takes a moment to transfer because of the inertia of a hanging object.

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The force that will balance the two forces is 6.4 N

The resultant force, F can be obtained as follow:

F = √(F₁² + F₂²)

F = √(4² + 5²)

F = √(16 + 25)

F = √41

F = 6.4 N

Thus, the force that will balance the two forces is 6.4 N

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The force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.

The Resultant of the two forces 4.0 N and %.0 N acting perpendicular to each other is calculated using the formula:

R² = A² + B²

where A and B are the two forces acting perpendicular to each other.

R² = 4² + 5²

R² = 41

R = 6.4 N

Therefore, the force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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ANSWER: About 9.832 m/s raised to a power 2

Explanation:

In combination , the equational bulge and the effects of the surface centrifugal force due to rotation that means sea level gravity increases from about 9.780 m/s raised to a power 2 at the equator to about 9.832m/s raised to a power 2 at the poles , so an object will weigh approximately 0.5% more at the poles than the equator

Answer:

umm of which subject ?? science ?? physics?? chemistry?? biology??ooook

To find the kinetic energy at position B, we need to know the height or the velocity at position B. Without this information, we cannot calculate the exact value of the kinetic energy.

To determine the kinetic energy of the ball at position B, we need to consider the m conservation of Mechanical energy. Since the ball is released from position A, we can assume that there is no initial kinetic energy (velocity is zero), and the total mechanical energy at position A is equal to the potential energy.

The potential energy at position A can be calculated using the formula:

Potential energy at A = mass * gravitational acceleration * height

Potential energy at A = 20 kg * 9.8 m/s² * height

Now, at position B, all the potential energy is converted into kinetic energy. The kinetic energy at position B is given by the formula:

Kinetic energy at B = 1/2 * mass * velocity²

Since the ball is released from rest, the velocity at position B can be determined using the conservation of mechanical energy:

Potential energy at A = Kinetic energy at B

20 kg * 9.8 m/s² * height = 1/2 * 20 kg * velocity²

Simplifying the equation, we get:

9.8 m/s² * height = 1/2 * velocity²

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Answer:

The acceleration of the ball is  \(a_y = - 0.3672 \ m/s^2\)

Explanation:

From the question we are told that

       The maximum height the ball reachs is \(H_{max} = 42.24 \ m\)

       The horizontal component of the initial velocity of the ball is \(v_{ix} = 5.57 \ m/s\)

       The vertical component of the initial velocity of the ball is \(v_{iy} = = 16.18 m/s\)

The vertically motion of the ball can be mathematically represented as

       \(v_{fy}^2 = v_{iy} ^2 + 2 a_{y} H_{max}\)

Here the final velocity at the maximum height is zero so \(v_{fy} = 0 \ m/s\)

Making the acceleration \(a_y\) the subject we have

        \(a_y = \frac{v_{iy} ^2}{2H_{max}}\)

substituting values

      \(a_y = - \frac{5.57^2}{2* 42.24}\)

      \(a_y = - 0.3672 \ m/s^2\)

The negative sign shows that the direction of the acceleration is in the negative y-axis

Use the kinematics formula: \(v = v_0+at\)

Your initial velocity is 10 m/s. Your acceleration is 4 m/s². The time elapsed is 4 s. And so,

\(v=10+4(4) \\v= 26 \text{ m/s}.\)

T = 2π√(L/g)

For earth , g ~ 10

18.9 = 2×3.14 √(L/g)

9 = L/g

L = 90 metres

Answer:

88m

Explanation:

T=2π*\(\sqrt{L/g}\)-->Τ/2π=\(\sqrt{L/g}\)-->18.9/2π=\(\sqrt{L/g}\)-->3=\(\sqrt{L/g}\)-->3^2=L/g-->9=L/9.8

so L=9*9.8-->L≈88m

The two molecules that best complete the reactants' side of the equation\(CO_2\) + 2\(H_2O\) are \(O_2\) and CO.

The correct answer would be \(O_2\) and CO.

Based on the partial chemical equation provided, \(CO_2\) + 2\(H_2O\), we need to select two molecules that complete the reactants' side of the equation while also considering the conservation of mass. Let's evaluate the given options:

1. \(NaCl_3\): This compound, sodium trichloride, does not contain carbon (C) or oxygen (O) atoms, which are required to balance the equation. Therefore, \(NaCl_3\) is not a suitable choice.

2. \(HS_4\): This compound, hydrogen tetrasulfide, also does not contain carbon (C) or oxygen (O) atoms necessary to balance the equation. Hence, \(HS_4\) is not the correct choice.

3. \(CH_4\): This molecule, methane, consists of one carbon atom (C) and four hydrogen atoms (H). It contains carbon but lacks oxygen atoms required for balancing the equation. Thus, \(CH_4\) does not complete the reactants' side.

4. \(O_2\): Oxygen gas (diatomic oxygen) is represented by\(O_2\). It contains two oxygen atoms, which helps balance the equation since there are two oxygen atoms on the product side (2\(H_2O\)). \(O_2\) is a valid choice for completing the reactants' side.

Considering the conservation of mass, we still need a molecule that contains carbon. Among the given options, CO is the only molecule that consists of one carbon atom (C) and one oxygen atom (O). By adding CO to the reactants' side, we balance both carbon and oxygen atoms in the equation.

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