A student in the front of a school bus tosses a ball to another student in the back of the bus while the bus is moving forward at constant velocity. The speed of the ball as seen by a stationary observer in the street:_________

a. is less than that observed inside the bus.
b. is the same as that observed inside the bus
c. may be either greater or smaller than that observed inside the bus.
d. may be either greater, smaller, or equal to that observed inside the bus.
e. is greator than that observed inside the bus

Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

The velocity of the ladder when the base of the ladder is 7, 15, and 24 feet from the wall is -0.875, -2.25, and -10.286 respectively.

Given, the length of the ladder= 25 ft

Let x be the distance between the wall and the ladder and h be the height of the ladder from the ground

x² + h² = (25)²

x² +h²= 625

h²= 625- x²

h= \((625- x^{2})^{1/2}\)

\(\frac{dh}{dx}\) = \(\frac{1}{2}\) \((625- x^2)^{-1/2} * (-2x)\)

\(\frac{dh}{dx}\) =  \(\frac{-x}{\sqrt{ (625-x^2)}}\)

We have dx/dt= 3 ft/sec

Therefore, by applying the chain rule, we can get the value of dh/dt as:

dh/dt= dh/dx *dx/dt

=\(\frac{-x}{\sqrt{ (625-x^2)}}*3\)

=\(\frac{-3x}{\sqrt{ (625-x^2)}}\)

Now substituting the different values of x in the acquired equation

When x= 7, dh/dt= \(\frac{-7}{8}\) ft/sec= -0.875 ft/sec

When x= 15, dh/dt= \(\frac{-9}{4}\) ft/sec= -2.25 ft/sec

When x= 24, dh/dt= \(\frac{72}{7}\) ft/sec= -10.286 ft/sec

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With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

Given data

voltage supplied Vs= 1.5 volts

resistance R1= 1000 ohms

resistance R2= 500 ohms

The total resistance is

Rt= 1000+ 500

Rt= 1500 ohms

In series connection the current is the same for all components while the voltage divides across all components,the voltages consumed by each individual resistance is equal to the source voltage.

Therefore, With a 9.0 voltage battery connected with two resistors, one is 10 ohms and the other resistor is at 20 ohms the voltage drop across the battery 1 volt. Thus, option A is correct.

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Answer:

0.159

Explanation:

the formula to find its is 1÷2*gt^2

Answer:

D

Explanation:

v= a t

 = 5.1 * .25 = 1.275 m/s

The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N

We'll begin by obtaining the mass of the rover vehicle. This is shown below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

Divide both sides by g

m = W /g

m = 37 / 3.72

m = 9.95 Kg

Now, we shall determin the weight of the rover vehicle on Earth. Details below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 9.95 × 10

Weight = 99.5 N

Thus, we can conclude that the weight on Erath is 99.5 N

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Answer:

The volume is  \(V =5.32 *10^{-5} \ m^3\)

Explanation:

From the question we are told that

    The power of the heating element is \(P = 2.0 kW = 2.0 *10^3 \ W\)

    The temperature of the water in the kettle is  \(T _w = 100^oC\)

     The time to convert water to steam is t = 1 minute = 60 sec

      The specific latent heat of vaporization is \(H_v = \ 2,257,000 J/kg\)

      The density of water is \(\rho_w = 1000\ kg/m^3\)

The power of the heating element is mathematically represented as

      \(P = \frac{E}{t}\)

Where E  Energy generated by the heating element in term of heat

      \(E = Pt\)

substituting values

      \(E = 2.0 *10^{3} * 60\)

      \(E = 120000 J\)

Now

 The latent heat of vaporization is mathematically represented as

         \(H_v = \frac{E}{m}\)

Where m is the mass of water converted to steam

 So

      \(m = \frac{E}{H_v}\)

substituting values

      \(m = \frac{120000}{2257000}\)

     \(m = 0.0532\ kg\)

The volume of water converted to steam is mathematically evaluated as

    \(V = \frac{m }{\rho_w}\)

substituting values

   \(V = \frac{0.0532}{1000}\)

    \(V =5.32 *10^{-5} \ m^3\)

Answer:

C_d = 0.942

Explanation:

Let's first calculate the angle of inclination.

Formula is;

tan θ = (%slope)

% Slope is given as 12%

Thus;

θ = tan^(-1) (12/100)

θ = 6.843°

Let's now calculate the force due to the weight of the rider and bike combined from;

F = mg sin θ

We are given; m = 100 kg.

Thus;

F = 100 × 9.81 × sin 6.843

F = 116.885 N

The drag force will also be the same as the force due to the weight of the body. Thus;

Drag force; F = C_d(½ρu²A)

Where;

C_d is drag coefficient

ρ is density

U is terminal speed

A is area

We are given;

A = 0.9 m²

U = 15 m/s

From online tables, density of air is approximately 1.225 kg/m³

Thus;

116.885 = C_d(½ × 1.225 × 15² × 0.9)

116.885 = 124.03125C_d

C_d = 116.885/124.03125

C_d = 0.942

Answer:

The heat needed to raise the temperature of 1 gallon of water from 68°F to 40°C is approximately 28,265 Joules.

Explanation:

Explanation:

395.53 N

The force of attraction between a student of mass 53 kg and Earth is calculated using the equation F = G*m1*m2/r^2, where G is the gravitational constant (7.51 N/kg), m1 is the mass of the student (53 kg), m2 is the mass of Earth, and r is the distance between them (the altitude of the space shuttle). Plugging in these values, we get F = 7.51*53*5.97e24/((6.37e6 + 6.37e6)^2) = 395.53 N.

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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Answer:

person is accelerating downwards

Explanation:

We are told that the force of the person standing on the elevator is 800 N acting downwards.

We are also told that the upward force of the elevator on the person is 600 Newtons.

This means that Upward force is lesser than downward force and thus the person is accelerating downwards

Sheena's speed with respect to the starting point on the bank is 2.07 mi/h.

To solve this problem, we can break Sheena's velocity into its horizontal and vertical components. The horizontal component of Sheena's velocity should be equal to the rate at which she crosses the river, while the vertical component of her velocity should be equal to the rate at which she is carried downstream by the current. The resulting velocity with respect to the starting point on the bank can be found using the Pythagorean theorem.

Let's first find the rate at which Sheena crosses the river. We can use the sine function to find this value, as follows:

sin(25°) = opposite/hypotenuse

opposite = sin(25°) x hypotenuse

opposite = sin(25°) x 2.20 mi/h

opposite = 0.9437 x 2.20 mi/h

opposite = 2.07 mi/h

So Sheena's horizontal velocity is 2.07 mi/h.

Now let's find the rate at which Sheena is carried downstream by the current. We can use the cosine function to find this value, as follows:

cos(25°) = adjacent/hypotenuse

adjacent = cos(25°) x hypotenuse

adjacent = cos(25°) x 1.90 mi/h

adjacent = 1.6987 mi/h

So Sheena's vertical velocity is 1.6987 mi/h.

Finally, we can use the Pythagorean theorem to find her speed with respect to the starting point on the bank:

velocity^2 = (horizontal velocity)^2 + (vertical velocity)^2

velocity^2 = (2.07 mi/h)^2 + (1.6987 mi/h)^2

velocity^2 = 4.29 mi^2/h^2

velocity = sqrt(4.29) mi/h

velocity = 2.07 mi/h

Therefore, Sheena's speed with respect to the starting point on the bank is 2.07 mi/h.

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Answer:

His gravitational potential energy will increase as well.

Explanation:

Let gpe represent gravitational potential energy.

gpe = mass × gravitational field strength × height

From the formula above, we can conclude that as the mass of a body increases, it's gpe increases too.

Answer:

C

Explanation:

C

Answer:

3.33m

Explanation:

Given parameters:

Force applied  =500N

Elastic constant  = 150N/m

Unknown:

Amount of stretch or extension  = ?

Solution:

To solve this problem use the expression below:

    F  = k e

F is the force applied

k is the elastic constant

e is the extension

  So;

           500  = 150 x e

             e  = \(\frac{500}{150}\)    = 3.33m

A. After the collision, the Kauaion has a velocity of 75,000 m/s.

B. After the collision, the Waimeaon has a velocity of 25,000 m/s.

The velocity of the Kauaion and the Waimeaon after the collision is calculated by applying the principle of conservation of linear momentum as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

Let the mass of the Waimeaon = m

3m(50000) + m(100000) = 3mv₁  + mv₂

m(150,000) + m(100000) = m(3v₁  + v₂)

150,000 + 100000 = 3v₁  + v₂

250,000 = 3v₁  + v₂

v₂ = 250,000 - 3v₁  --------(1)

u₁ + v₁ = u₂ + v₂

v₂ = u₁ + v₁  - u₂

v₂ = 50000 + v₁ - 100000

v₂ = v₁ - 50000 ----(2)

Solve (1) and (2) together

v₁ - 50000 = 250,000 - 3v₁

4v₁ = 300,000

v₁  = 300,000/4

v₁  = 75,000 m/s

v₂ = v₁ - 50000

v₂ = 75,000 - 50,000

v₂ = 25,000 m/s

Thus, after the collision, the Kauaion has a velocity of 75,000 m/s.

After the collision, the Waimeaon has a velocity of 25,000 m/s.

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The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².

Acceleration is change of velocity with respect to time (can include deceleration or changing direction).

The acceleration of a body can be calculated by using the following expression;

a = F/m

Where;

According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:

a = 4N ÷ 2.55kg

a = 1.57m/s²

Therefore, 1.57m/s² is the acceleration of the object.

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Energy conservation is the principle that energy is neither created nor destroyed, but can only be converted or transferred. It involves using energy-efficient appliances and transitioning to renewable energy sources to reduce consumption and environmental impact.

Energy conservation refers to the principle that energy cannot be created or destroyed; it can only be converted from one form to another or transferred between systems. This principle is based on the law of conservation of energy, also known as the first law of thermodynamics. In other words, the total amount of energy in a closed system remains constant over time.

One example of energy conservation is the use of energy-efficient appliances in households. By using appliances that are designed to minimize energy waste, such as energy-saving light bulbs, efficient refrigerators, or insulated windows, individuals can reduce their energy consumption and lower their electricity bills. These appliances are designed to convert electrical energy into useful forms, such as light or heat, with minimal energy losses.

Additionally, energy conservation plays a crucial role in sustainable practices and environmental preservation. For instance, reducing reliance on non-renewable energy sources like fossil fuels and transitioning to renewable energy sources such as solar or wind power helps conserve natural resources and reduces greenhouse gas emissions.

In summary, energy conservation is the principle that states energy cannot be created or destroyed but can only be converted or transferred between different forms. By adopting energy-efficient practices and utilizing renewable energy sources, individuals and society can contribute to conserving energy and mitigating environmental impact.

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The question probable may be:

Explain the concept of energy conservation and provide an example of how it applies in real-life situations.

The sentence that best describes the motion is "the motion is a circular motion and has completed one revolution".

Question: "If a car moved one full circular track of 15 Km, which sentence describes its motion?​"

An object moves in a circle at a constant speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is spinning continuously, is moving uniformly in circles.

There are two types of circular motion: uniform and non-uniform.

Circular motion can be seen in the orbit of a satellite, ice skaters moving at a constant speed in a circle, and vehicles traveling in a circle.

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Answer:

\(W_m=183.495N\)

Explanation:

From the question we are told that:

Weight \(W=248Ibs\)

Mass of Weight  \(m= 248*0.453\)

                          \(m=112.344kg\)

Generally the acceleration due to gravity on the Moon is one-sixth that on Earth.

Therefore

The equation for Weight on Moon is given as

 \(W_m=m*g/6\)

 \(W_m=122.344*\frac{9.8}{6}\)

 \(W_m=183.495N\)

Answer:

F ’= 40.9 lb

Explanation:

The weight of a body is the attraction of the Earth on the body

          F = \(G \frac{m M_e}{R_e^2}\)

          F = mg

          m = F / g

          m = 248/32

         m = 7.75 slug

The weight of the body on the moon is the attraction of the body for the satellite

         F ’= \(G \frac{mM}{R^2}\)

from the tables the mass and radius of the moon are M = 7.34 10²² kg and R = 1.74 10⁶ m

let's reduce the mass to the SI system

         m = 7.75 slug (14.59 kg / 1 slug) = 113 kg

         F ’= 6.67 10⁻¹¹ 113 7.34 10²² / (1.74 10⁶) ²

         F ’= 1.82 10² N

         F ’= 1.82 10² N (0.2248 lb / 1 N)

         F ’= 40.9 lb

Answer:

earth is not the center of the universe

Explanation:

i just took the test

Kepler's laws allow us to find that the correct answer, the basis is these is

 d) Earth is not the center of the universe.

Kepler made extensive measurements and created a mathematical model of the movement of the planets around the sun, these analyzes are written in the form of three laws

                \(T^2 = ( \frac{4\pi ^2}{G M_s} ) \ a^3\)

Where T is the period, a the major axis, G the universal gravitational constant and \(M_s\) the most of the sun.

When analyzing these Kepler's laws in all the sun is the center of movement.

Let's analyze the different claims;

a) False. The laws are not on a specific planet

b) False. Gravity is not in Kepler's laws

c) False. A ratio of the masses between planets and the sun is not established

d) True. In the laws the sun is the center of movement, therefore the earth is not the center of the universe.

In conclusion using Kepler's laws we can find that the correct answer for the bases of these is:

 d) Earth is not the center of the universe.

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Answer: 2.7 x10^-4 N

Explanation: 6.674 ×10^-11 × 1000 x 1000 divided by 0.5 squared.

Given

The voltage of the battery, V=20.0 V

The resistance of the two resistors are 40 ohm each.

The two resistance are connected in parallel

To find

The current through the circuit.

Explanation

The resistors are connected in parallel

Thus the equivalent resistance is

By Ohm's law,

where I is the current through the battery

Putting the values

Conclusion

The current through the battery is 1.00 A

A group of people pulling up on by pulley is way easier than by pulling directly because a pulley system is a freight lift system that allows objects to be hoisted to higher floors with less force. The pulley mechanism is used for Wells to hoist the bucket out of the well. In order to operate, certain forms of gym equipment use pulleys. In order to lift and position heavy goods, building pulleys are used.

A wheel on an axle or shaft known as a pulley is used to transfer power from the shaft to the cable or belt or to sustain movement and direction change of a taut cable or belt. The supporting shell is known as a block, and the pulley may also be referred to as a sheave or a pulley wheel when it is supported by a frame or shell but does not transmit power to a shaft. For the purpose of locating the cable or belt, a pulley may include a groove or grooves between flanges around its circle. A rope, cable, belt, or chain may serve as the drive component of a pulley system. It is example of  simple machines.

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