Answer:
the student will have 1080 nanograms of HDR template left to use for future work
Explanation:
Given that:
the total volume of DNA which is eluted after the PCR clean up = 20ul
PCR clean up is a procedure by which the PCR product is gotten rid of DNA polymerase enzyme, excess primers, excess dNTPs so that these does not interfere in further experiments such as transformation.
using 2 ul of the 20 ul stock to nanodrop the sample
Concentration of the DNA after the PCR clean up = 60ng/ul
No, Since 2ul is used in the nanodrop, thus total volume left for further experiment will be = 20 - 2 = 18ul
Now, the total amount of the HDR template the student have left to use for future work will be;
⇒ 18ul × 60 ng/ul
= 1080 ng
Therefore, the student will have 1080 nanograms of HDR template left to use for future work
sample of brown dye from a lolly is placed at the origin on a strip of a chromatography plate. The solvent front moves 15.0 cm from the origin. A blue component of the dye moves 5 cm and a red component 3 cm in the same time. Calculate the Rf values of the two components
The Rf value for the blue component is approximately 0.333, and the Rf value for the red component is 0.2.
The Rf value, or the retention factor, is a ratio used in chromatography to quantify the migration distance of a component relative to the migration distance of the solvent front. It is calculated using the formula:
Rf = (distance moved by the component) / (distance moved by the solvent front)
Given the information provided:
Distance moved by the blue component = 5 cm
Distance moved by the red component = 3 cm
Distance moved by the solvent front = 15 cm
Now we can calculate the Rf values for the blue and red components:
Rf_blue = (distance moved by the blue component) / (distance moved by the solvent front)
= 5 cm / 15 cm
= 1/3
≈ 0.333
Rf_red = (distance moved by the red component) / (distance moved by the solvent front)
= 3 cm / 15 cm
= 1/5
= 0.2
Therefore, the Rf value for the blue component is approximately 0.333, and the Rf value for the red component is 0.2.
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which is the graph of the function g(x) = f(-x)
To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.
What is a graph of the function g(x) = f(-x)?To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.
If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).
However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.
In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.
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Calculate the vapor pressure (in torr) at 298 K in a solution prepared by dissolving 46.8 g of the non-volatile non-electrolye glucose in 117 g of methanol. The vapor pressure of methanol at 298 K is 122.7 torr. Enter your answer to 2 decimal places.
Answer: The total partial pressure of the solution is 131.37 torr.
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\) ......(1)
For glucose:Given mass of glucose = 46.8 g
Molar mass of glucose = 180 g/mol
Plugging values in equation 1:
\(\text{Moles of glucose}=\frac{46.8g}{180g/mol}=0.26 mol\)
For methanol:Given mass of methanol = 117 g
Molar mass of methanol = 32 g/mol
Plugging values in equation 1:
\(\text{Moles of methanol}=\frac{117g}{32g/mol}=3.66 mol\)
Mole fraction is defined as the moles of a component present in the total moles of a solution. It is given by the equation:
\(\chi_A=\frac{n_A}{n_A+n_B}\) .....(2)
where n is the number of moles
Putting values in equation 2:
\(\chi_{methanol}=\frac{3.66}{0.26+3.66}=0.934\)
Raoult's law is the law used to calculate the partial pressure of the individual gases present in the mixture. The equation for Raoult's law follows:
\(p_A=\chi_A\times p_T\) .....(3)
where \(p_A\) is the partial pressure of component A in the mixture and \(p_T\) is the total partial pressure of the mixture
We are given:
\(p_{methanol}=122.7torr\\\chi_{methanol}=0.934\)
Putting values in equation 3, we get:
\(122.7torr=0.066\times p_T\\\\p_T=\frac{122.7torr}{0.934}=131.37torr\)
Hence, the total partial pressure of the solution is 131.37 torr.
Why does it mean by methane molecule is symmetrical?
A methane molecule (CH4) is considered symmetrical because it possesses a symmetric structure and exhibits symmetry operations.
Symmetry refers to a balanced arrangement of elements that can be divided into equal parts by a plane, axis, or center. In the case of methane, it exhibits several symmetrical characteristics.
Firstly, methane has a tetrahedral molecular geometry, with the carbon atom at the center and four hydrogen atoms positioned around it. This geometry ensures that the molecule is symmetrical in terms of its spatial arrangement.
Each hydrogen atom is located at one of the vertices of the tetrahedron, forming equal angles and distances with respect to the central carbon atom. This symmetry is maintained regardless of the orientation of the molecule.
Additionally, methane possesses rotational symmetry. It can be rotated around any of the carbon-hydrogen bonds, and the molecule will retain its overall appearance.
The symmetry of methane arises from its molecular structure and the equal distribution of electron density around the central carbon atom. The four hydrogen atoms are bonded to the carbon through sigma bonds, which have a cylindrical symmetry. This balanced arrangement of the atoms contributes to the overall symmetry of the molecule.
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How many liters of carbon dioxide can be produced if 37.8 grams of carbon disulfide react with excess oxygen gas at 28.85 degrees Celsius and 1.02 atmospheres?
CS2(l) + 3O2(g) yields CO2(g) + 2SO2(g)
2.78 liters
5.95 liters
12.1 liters
11.9 liters
The volume of carbon dioxide produced is approximately (d) 11.9 liters.
To determine the amount of carbon dioxide (C\(O_2\)) produced when 37.8 grams of carbon disulfide (C\(S_2\)) reacts with excess oxygen gas (\(O_2\)), we need to use stoichiometry and the given balanced chemical equation:
C\(S_2\)(l) + 3\(O_2\)(g) → C\(O_2\)(g) + 2S\(O_2\)(g)
First, we calculate the number of moles of C\(S_2\) using its molar mass:
Molar mass of (C\(S_2\)) = 12.01 g/mol (C) + 32.07 g/mol (S) × 2 = 76.14 g/mol
Number of moles of (C\(S_2\)) = mass / molar mass = 37.8 g / 76.14 g/mol ≈ 0.496 mol
From the balanced equation, we can see that the stoichiometric ratio between (C\(S_2\)) and C\(O_2\) is 1:1. Therefore, the number of moles of C\(O_2\) produced will also be 0.496 mol.
Now we can use the ideal gas law to calculate the volume of C\(O_2\) at the given temperature and pressure. The ideal gas law equation is:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.
Converting the temperature from Celsius to Kelvin:
T(K) = 28.85°C + 273.15 = 302 K
Using the ideal gas law:
V = nRT / P = (0.496 mol) × (0.0821 L·atm/mol·K) × (302 K) / (1.02 atm) ≈ 11.9 L
The correct answer is 11.9 liters.
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A 54.2 g sample of polystyrene, which has a specific heat capacity of 1.880 J-gc, is put into a calorimeter (see sketch at
right) that contains 100.0 g of water. The temperature of the water starts off at 21.0 °C. When the temperature of the water stops
changing it's 34.3 °C. The pressure remains constant at 1 atm.
Calculate the initial temperature of the polystyrene sample. Be sure your answer is rounded to the correct number of significant
digits.
thermometer.
insulated
container
water
sample.
a calorimeter
Tthe initial temperature of the polystyrene sample is 39.4°C.
Given: Mass of polystyrene sample = 54.2 gSpecific heat of polystyrene = 1.880 J-g°CWater mass = 100.0 g Initial water temperature = 21.0°CWater final temperature = 34.3°CPressure remains constant at 1 atmFormula used:Heat gained by water = heat lost by polystyreneHence,Heat lost by polystyrene = Heat gained by water=> mcΔT = mcΔTwhere,m = mass of polystyrene or waterc = specific heat capacityΔT = change in temperatureThe temperature change is ΔT = 34.3°C - 21.0°C = 13.3°CNow we can use this temperature change to calculate the initial temperature of the polystyrene.Taking the water's specific heat capacity, c = 4.184 J/g°CHeat gained by water = (100.0 g)(4.184 J/g°C)(13.3°C) = 5574 JHeat lost by polystyrene = 5574 JTaking the polystyrene's specific heat capacity, c = 1.880 J/g° ) = 13.3°C Now let's calculate the mass of polystyrene using the specific heat capacity formula.5574 J = (54.2 g)(1.880 J/g°C)(13.3°C - Ti)Ti = 39.4°C
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Calculate the maximum amount of product that can be formed and the amount of unreacted excess reagent when 3.1 mol of SO2 reacts with 2.7 mol of O2 according to the equation: 2SO2(g) + O2(g)->2SO3(g)
I found out that the maximum amount of product that can be produced is 248 g SO3, how can I find the mass of the excess reagent?
the maximum amount of product that can be formed is 124.39 g SO₃, and there will be 36.8 g of excess O₂ left over.
To find the amount of excess reagent, you need to first determine which reactant is limiting and which is in excess.
Determine the limiting reagent:
Use stoichiometry to determine how much product can be formed from each reactant:
mol SO2:
2 SO₂ + O₂ -> 2 SO₃
2 mol SO₃/2 mol SO₂ = 1 mol SO₃/mol SO₂
1 mol SO₃ = 80.06 g SO₍₃₎
From 2.7 mol O₂
2 SO₂ + O₂ -> 2 SO₃
1 mol SO₃/1 mol O₂ = 1 mol SO₃/mol O₂
1 mol SO₃ = 80.06 g SO₃
2.7 mol O₂ x (1 mol SO₂/1 mol O₂) x (80.06 g SO₂/mol SO₂) = 216.45 g SO₂
Since the amount of SO₂ produced from 3.1 mol of SO₂ is less than the amount produced from 2.7 mol of O₂, SO₂ is the limiting reagent.
Calculate the amount of excess reagent:
To find the amount of excess O₂, use the balanced equation to determine how much O₂ is required to react with all of the SO₂:
2 SO₂ + O₂ -> 2 SO
3.1 mol SO2 x (1 mol O₂/2 mol SO2) = 1.55 mol O₂
Subtract the amount of O₂ used from the initial amount of O₂:
2.7 mol O₂ - 1.55 mol O2 = 1.15 mol O₂
Finally, convert the excess O₂ to mass:
1.15 mol O₂ x 32.00 g/mol = 36.8 g O₂
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PLS HELP ME FOR BOTH QUESTIONS
Answer:
IF the match is stuck on the side it could chach burning hot.
2) the burn peices looks like its burned and it becomes black since of it.
Explanation:
The periodic table of the elements lists the elements in order of increasing atomic number. Each element has its own unique square in the periodic table. Numbers in an element's square are used to tell how many protons, neutrons and electrons a typical atom of each element has.

Based on the information shown, which of the following is true about magnesium atoms?
A.
They all have 12 protons.
B.
Some have 24 protons and others do not.
C.
They all have 24 protons.
D.
Some have 12 protons and others do not.
Answer:
A) They all have 12 protons.
Explanation:
Magnesium has an atomic number of 12 which means it has 12 protons. All Magnesium atoms have 12 protons, the neutrons however may differ which produces things called isotopes where the atoms have same protons but neutrons change.
Keep in mind the atomic number is unique to each element, so 12 atomic number will always be Magnesium, 1 will always be Hydrogen and so on.....
Small pieces of broken rock, sand, and shells are called _______________.
a. Dirt
b. Sediment
c. Dust
d. Sedimentary Rock
Answer:
b- sediment
Explanation:
the remains of plants and animals are known as sediments. It can be as small as a grain of sand or as large as a boulder. Sediment moves from one place to another through the process of erosion.
pls mark me as the brainliest
If d represents the density of a gas and k is a constant. The relationship between the rate of diffusion r, and d is ____?
The relationship between the rate of diffusion r, and d is r ∝ 1/√d.
The relationship between the rate of diffusion (r) and the density of a gas (d) can be explained using Graham's law of diffusion. According to this law, the rate of diffusion of a gas is inversely proportional to the square root of its density. Mathematically, it can be expressed as:
r ∝ 1/√d
where the symbol '∝' represents 'proportional to'. The constant of proportionality (k) can be introduced to this equation as:
r = k/√d
This equation shows that as the density of a gas increases, its rate of diffusion decreases. This is because denser gases have more molecules per unit volume and thus, they experience greater intermolecular collisions that hinder their movement. Therefore, it requires more energy for them to diffuse through a medium compared to less dense gases.
The relationship between the rate of diffusion and density is particularly important in understanding the behavior of gases in different environments. For instance, in a gas chromatography column, the rate of diffusion of a gas determines how quickly it moves through the column and separates from other components. Similarly, in the Earth's atmosphere, the rate of diffusion of greenhouse gases such as carbon dioxide affects their concentration and hence, their impact on climate change.
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Draw the organic and inorganic products of the reaction, describe the type of bond cleavage, and classify the reaction.
Answer:
See explanation and images attached
Explanation:
The complete question his shown in the image attached to this answer.
This reaction is a substitution reaction. We identify it as a substitution reaction because one specie replaced another in the substrate.
The organic product and inorganic products were also shown in the image. The bond was breakage is a hetereolytic fission since the two electrons of the bond reside on only one of the species.
how many carbon atoms are in it
Belching (burping) cows give off much of the methane, a greenhouse gas, from raising farm animals. Now researchers are investigating a way to reduce the greenhouse gas that is burped by cows.
In one study, scientists fed a group of dairy calves (which are cows that produce milk) a methane-blocker chemical. Sensors at feeding stations measured methane in the cows’ gas while the animals were nearby. That allowed the team of researchers to estimate the methane being belched (burped) out each day.
Over their first year of life, the treated cows, which received the methane-blocker chemical, released about ten percent less methane than the group of cows not given the chemical.
What can you infer or conclude based on the evidence from the passage?
*Your response should include the evidence to support your conclusion.
Cows and other ruminants are significant producers of the greenhouse gas methane—contributing 37 percent of the methane emissions resulting from human activity.
What is greenhouse gas?Greenhouse gases (also known as GHGs) are gases in the earth's atmosphere that trap heat. During the day, the sun shines through the atmosphere, warming the earth's surface. At night, earth's surface cools, releasing heat back into the air. But some of the heat is trapped by the greenhouse gases in the atmosphere.
While carbon dioxide is typically painted as the bad boy of greenhouse gases, methane is roughly 30 times more potent as a heat-trapping gas. As temperatures rise, the relative increase of methane emissions will outpace that of carbon dioxide from these sources, the researchers report.
The cow's ramen is like a large fermentation vat. More than 200 different bacteria and 20 types of protozoa help the cow to utilize fibrous feed stuffs and non-protein nitrogen sources. Bacteria adhere to the feed and gradually digest the fermentable material.“You can probably reduce methane by about 20-25% by altering diet,” he says.
One study by researchers at the University of California, Davis, estimated it might be possible to reduce global methane emissions from cows by 15% by changing their diet.
Thus, this evidence support the passage.
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Select the correct answer.
Which of the following does the Sun orbit?
A.
The center of the Milky Way
B.
The Earth
C.
The Moon
D.
The stars
The concentration of the water and alcohol solution is 25% alcohol by volume calculate the volume of the alcohol would be in 200 mL of the solution
The volume of the alcohol would be in 200 mL of the solution is equal to 50 ml.
What is the concentration?The concentration of the given solution can be explained in the terms of molarity, molality, and Normality. We can easily calculate the molar concentration of a substance in a solution.
In chemistry, concentration can be defined as the abundance of components divided by the total volume of a mixture.
The percent by volume of a solution can be calculated as the ratio volume of alcohol and the total volume of the solution.
The percent by volume = volume of alcohol / Total volume of solution
Given the total volume of the solution, = 200 ml
The percent by volume = 25 %
25 % = volume of alcohol / 200
The volume of alcohol = (25/100) × 200
Volume of alcohol = 50 ml
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Which best describes the relationship between population size, carrying capacity, and limiting factors?
O The size of a population usually stays high due to its carrying capacity and limiting factors.
The size of a population usually stays near its limiting factors due to carrying capacity.
The size of a population usually stays near its carrying capacity due to limiting factors. O
The size of a population usually stays low due to its carrying capacity and limiting factors.
The best description of the relationship between population size, carrying capacity, and limiting factors is: "The size of a population usually stays near its carrying capacity due to limiting factors."
Carrying capacity refers to the maximum number of individuals that a particular environment can sustainably support. It represents the limit to which a population can grow given the available resources, such as food, water, and habitat. Limiting factors, on the other hand, are the factors that restrict population growth by reducing birth rates, increasing death rates, or limiting access to resources.As a population approaches its carrying capacity, limiting factors come into play and regulate the population size. These limiting factors can include competition for resources, predation, disease, availability of suitable habitat, and other environmental factors. They act as checks on population growth, preventing it from exceeding the carrying capacity of the ecosystem.
Therefore, the size of a population usually stays near its carrying capacity because the limiting factors ensure that the population does not exceed the available resources and ecological limits of the environment. If the population surpasses the carrying capacity, the limiting factors will intensify, causing a decline in resources and an increase in mortality rates, which ultimately brings the population back towards the carrying capacity.It's important to note that the relationship between population size, carrying capacity, and limiting factors is dynamic and can vary depending on various ecological and environmental factors.
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How much heat energy is required to raise the temperature of 50g of bromine from 25°C to 30°C? [Specific heat capacity of bromine = 0.226 J/(g °C]
Answer:
56.5J
Explanation:
To find the heat energy required use the formula for the specific heat capacity which is
c=quantity of heat/mass×change in temperature
in this question c is 0.226j/g,the mass is 50g and the change in temperature is 30-25=5
therefore
0.226=Q/50×5
Q=0.226×250
=56.5J
I hope this helps
What is the IUPAC name of the following substance?
The International Union of Pure and Applied Chemistry (IUPAC) provides a standard system for naming organic compounds.
It is essential to learn this nomenclature system to communicate correctly about the chemical structures of compounds and how they relate to each other. Here is the IUPAC name of the following substance.Below is the structure of the given compound: In the given compound, there are four carbon atoms that are connected with single bonds. Carbon atoms are also attached to hydrogen atoms. Since it has four carbons in the main chain, the root name will be "but-". The functional group present in the molecule is the carboxylic acid group (-COOH), which gives the suffix "-oic acid." Therefore, the IUPAC name of the given substance is Butanoic acid.Thus, the IUPAC name of the given compound is Butanoic acid. It is essential to know the IUPAC naming of organic compounds to communicate correctly about the chemical structures of the compounds.
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What is the mass number of an atom with 17 protons, 17 electrons,and 18 nuetrons?
Answer:
35
Explanation:
the formula is: mass number = protons + neutrons
so 17+18=35
2ca + o2 - 2cao identify the oxidizing and reducing agents
Answer:
Ca is a reducing agent and O is the oxidizing agent.
Explanation:
calcium is the reducing agent as it reduces oxygen while it oxidize itself and oxygen is an oxidising agent because it oxidized others and reduces itself. in this equation oxygen is reducing and Calcium is oxidising. and as it is stated in the definition that oxidizing agent is the agent which oxidises others and reduces itself and it is also stated that reducing agent reduces others and oxidize itself. so based on this statement calcium is reducing agent and O is a oxidizing agent.
The distance that is covered by the wave in one second is called
Answer:
The distance that is covered by the wave in one second is called frequency.
Explanation:
1.45g of naphthalene (C10H8) is dissolved in 21.6g of benzene. Calculate the freezing point of the solution given that the freezing point of pure benzene is 5.5°C, and the molal freezing point depression constant is 4.45°C/m
Therefore, the freezing point of the solution is 3.173°C.
What is freezing point?Freezing point is the temperature at which a liquid substance turns into a solid at a given pressure. At the freezing point, the solid and liquid states of the substance are in equilibrium, meaning that the rate of melting equals the rate of freezing. The freezing point of a pure substance is a characteristic physical property that depends on the substance's chemical composition and can be used to identify it. When a solute is dissolved in a solvent, the freezing point of the solvent is lowered, and the degree of lowering depends on the amount and identity of the solute.
Here,
To solve for the freezing point of the solution, we need to use the formula:
ΔTf = Kf x molality
where:
ΔTf = change in freezing point
Kf = molal freezing point depression constant
molality = moles of solute per kilogram of solvent
First, we need to calculate the molality of the solution:
Mass of naphthalene = 1.45 g
Molar mass of naphthalene = 128.17 g/mol
Number of moles of naphthalene = 1.45 g / 128.17 g/mol = 0.0113 mol
Mass of benzene = 21.6 g
Density of benzene = 0.879 g/mL
Volume of benzene = 21.6 g / 0.879 g/mL = 24.6 mL = 0.0246 L
Mass of benzene = volume x density = 0.0246 L x 0.879 g/mL = 0.0216 kg
molality = moles of solute / mass of solvent (in kg)
molality = 0.0113 mol / 0.0216 kg = 0.523 mol/kg
Now, we can substitute the given values into the formula to solve for ΔTf:
ΔTf = Kf x molality
ΔTf = 4.45°C/m x 0.523 mol/kg
ΔTf = 2.327°C
Finally, we can calculate the freezing point of the solution:
Freezing point of solution = freezing point of solvent - ΔTf
Freezing point of solution = 5.5°C - 2.327°C
Freezing point of solution = 3.173°C
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What size volumetric flask would you use to create a 0.50 M
solution using 10.00 g of CaBr2
Answer:
Explanation:
First convert the grams of Calcium Bromide to moles by using the atomic weight. Then use the formula for molarity, which is moles per liter.
CaBr2 = 199.9 g/mol
10/199.9 = 0.05 moles of CaBr2
\(0.5M=\frac{0.05mol}{x}\)
x = 0.1L or 100mL
if 9.00g grams of gas are enclosed in a 50.00 L vessel at 273.15K and 2.000 atmospheres of pressure , what is the molar mass of the gas? what gas is this?
Answer: 4.88 g/mol. and helium
Explanation:
To find the molar mass of the gas, we can use the ideal gas law equation which is PV=nRT where:
P = pressure = 2.000 atm
V = volume = 50.00 L
n = number of moles
R = gas constant = 0.08206 L·atm/K·mol
T = temperature = 273.15 K
First, we need to find the number of moles of the gas:
PV = nRT
n = PV/RT
n = (2.000 atm)(50.00 L)/(0.08206 L·atm/K·mol)(273.15 K)
n = 1.844 mol
Now, we can find the molar mass of the gas by dividing its mass by the number of moles:
molar mass = mass/number of moles
mass = 9.00 g
molar mass = 9.00 g/1.844 mol
molar mass = 4.88 g/mol
Therefore, the molar mass of the gas is 4.88 g/mol.
To determine what gas this is, we can compare the molar mass of the gas to the molar masses of known gases. The molar mass of 4.88 g/mol is closest to that of helium (4.00 g/mol). Therefore, this gas is most likely helium.
What is the mass, in grams, of 9.45×1024 molecules of methanol (CH3OH)?
The mass of 9.45 × 1024 molecules of methanol (CH3OH) is 4.10 × 1026 grams.
A 25 ml solution of 0.5 M NaOH is titrated until neutralized into a 50 ml sample of HCl?
The concentration of the acid is \(0.25 M\).
Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a standardized solution of known concentration.
The titration formula can be given by,
(Volume of the Base) \(\times\) (Normality of the Base) = (Volume of the Acid) \(\times\) (Normality of the Acid)
\(\Rightarrow V_1N_1=V_2N_2\)
Given, the volume of the base (\(NaOH\)), \(V_1 =25 ml\).
The concentration of the base (\(NaOH\)), \(M_1=0.5 M\).
The equivalence of the base (\(NaOH\)) is \(1\).
Hence, the normality of the base (\(NaOH\)), \(N_1=\frac{0.5}{1}N=0.5N\).
Given, the volume of the acid (\(HCl\)), \(V_2 =50 ml\).
Let us assume that the normality of the acid (\(HCl\)) \(N_2\).
Substitute the values in the given formula of titration.
\((25\times0.5)=(50 \times N_2)\\\Rightarrow 12.5=50N_2\\\Rightarrow N_2=\frac{12.5}{50} N\\\Rightarrow N_2=0.25 N\)
Hence, the normality of the acid (\(HCl\)), \(N_2=0.25 N\).
The equivalence of the acid (\(HCl\)) is \(1\).
Therefore, the concentration of the acid, \(M_1=\frac{0.25}{1}=0.25 M\).
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Predict the product, write the balanced chemical reaction, include states of matter, Aluminum hydroxide -->
Answer
Explanation
Required: The decomposition of Aluminum hydroxide.
Solution:
\(3HCl_{(l)}\text{ + }Al(OH)_{3(s)}\rightarrow\text{ AlCl}_{3(s)}\text{ + 3H}_2O_{(l)}\)A reaction that is used to make ClO2 is:HCl + NaOCl +2NaClO2 2ClO2 + 2NaCl + NaOHa) Which element is oxidized? b) Which element is reduced? c) Which substance is the oxidizing agent and which is the reducing agent?
Given the following reaction:
\(\text{HCl + NaOCl + 2NaClO}_2\text{ }\rightarrow2ClO_2\text{ + 2NaCl + NaOH}\)We want to know the element oxidized, the element reduced and the substance that is the oxidizing agent and a reducing agent.
Answer:
a) Element Oxidized = Na
b) Element reduced = Cl
c) NaClO is an oxidizing agent and HCl is a reducing agent.
Calculate the solubility of copper(II) hydroxide, Cu(OH)2, in g/L
Answer:
Ksp = [ Cu+² ] [ OH-] ²
molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol
Ksp = [ Cu+² ] [ OH-] ²
Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰
|__________|___Cu+² __|_2OH-____|
|Initial concentration(M)|___0__|_0______|
|Change in concentration(M)|_+S |__+2S__|
|Equilibrium concentration(M)|_S _|2S___|
Ksp = [ Cu+² ] [ OH-] ²
2.2 ×10-²⁰ = (S)(2S)²= 4S³
\(s = \sqrt[3]{ \frac{2.2 \times {10}^{ - 20} }{4} } = 1.8 \times {10}^{ - 7} \)
S = 1.8 × 10-⁷ M
The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M
Solubility of Cu (OH)2 =
\(Cu (OH)2 = \frac{1.8 \times {10}^{ - 7} mol \:Cu (OH)2 }{1L} \times \frac{97.546 \: g \: Cu (OH)2}{1 \: mol \: Cu (OH)2} \\ = 1.75428 \times 10 ^{ - 5} \)
Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L
I hope I helped you^_^