A student determines that a sample has a mass of 157.2 g and a volume of 20 cm^3. Which
substance from the table is the student analyzing?

(a) ball velocity = - 2.47 m/s  

(b) block velocity = 1.236 m/s

Two items collide when they briefly come into touch with one another. To put it another way, a collision is a brief reciprocal encounter between two masses in which the momentum and energy of the masses change.

For ball as it is at initially at height of 70.0 cm = 0.7 m

so by energy conservation,

K.E.(i) P.E.(i) + K.E.(f)+P.E.(f)

0 + mg×(0.7)  = 1/2 mv² + 0

v = 3.71 m/s

now, collision b/w ball and block

as the block is in rest initially and there is no external force b/w them

so by momentum conservation,

m₁u₁+ m₂u₂ = m₁v₁+ m₂v₂

or, (0.5 x 3.71) + 0 = (0.5x v₁) + (2.5 x v₂)

3.71 = v₁ + 5v₂  .........(1)

as elastic collision so energy conservation

or, 1/2 m₁ u₁² + 1/2 m₂ u₂² = 1/2 m₁ v₁² + 1/2 m₂ v₂²

or, (1/2 x 0.5 x 3.712) + 0 = (1/2 x 0.5 x v₁²) + (1/2 x 2.5 x v₂²)

or, 3.433 = 0.25xv₁² + 1.25 v₂²      ...............(2)

from eq. 1 and eq. 2

or, 3.433 = 0.25 x (3.71 - 5 v₂)² + 1.25v₂²  

or, v² = 1.236 m/s

and v₁ = 3.71 - 5v₂

or, v₁ = - 2.47 m/s

so after collision

ball velocity = - 2.47 m/s       [(-)ve x direction]

block velocity = 1.236 m/s     [(+)ve x direction]

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Answer:

That is true.

Explanation:

When the input force is applied to the wheel, as it is with a doorknob, the axle turns over a shorter distance but with greater force, so the mechanical advantage is greater than 1.

To find:

What a wave is? and what does it do?

Explanation:

A wave is the di

Hi there!

We can use the work-energy theorem to solve.

Recall:

\(\large\boxed{E_i = E_f}}\)

Initial energy = final energy

The initial energy is purely potential (she starts from rest), and, if we assign the bottom of the slope as the 0 line, her energy at the bottom is purely kinetic.

PE = mgh

KE = 1/2mv²

We can begin by setting the two equal:

mgh = 1/2mv²

Cancel out the mass and rearrange to solve for velocity:

2gh = v²

v = √2gh

Plug in given values and use g ≈ 10 m/s²:

v = √2(10)(20) = 20 m/s

Answer:

Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product by the square of velocity. Divide the answer by 2.

Explanation:

Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product with the square of velocity. Divide the answer by 2.

Hope this answer helps you

An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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Answer:

a c e f

Explanation:

Start with the last year then the month. to eliminate wrong choices

A. The kinetic energy of the stone is 4500 J

B. The kinetic energy of the baseball is 180 J

C. The kinetic energy of the bullet is 900 J

KE = ½mv²

KE = ½ × 10 × 30²

KE = 5 × 900

KE = 4500 J

KE = ½mv²

KE = ½ × 0.1 × 60²

KE = 0.05 × 3600

KE = 180 J

KE = ½mv²

KE = ½ × 0.02 × 300²

KE = 0.01 × 90000

KE = 900 J

From the above, we see clearly that the stone has the highest kinetic energy followed by the bullet and then the baseball.

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Answer:

No, all supply curves do not look basically the same in terms of slope and shape. The slope and shape of a supply curve depend on the specific market conditions and the behavior of the suppliers. The supply curve can have different slopes, ranging from being perfectly elastic to perfectly inelastic. The slope of the supply curve reflects the responsiveness of the quantity supplied to changes in the price of the good or service.

In terms of shape, the supply curve can take on different forms such as being linear or curved. The shape of the supply curve depends on the behavior of the suppliers and their ability to adjust the quantity supplied to changes in the price of the good or service. For example, if suppliers can easily adjust their production levels in response to changes in price, then the supply curve may be flatter or more horizontal, indicating a more elastic supply. On the other hand, if suppliers face higher costs or constraints on their ability to increase production, the supply curve may be steeper or more vertical, indicating a less elastic supply.

Therefore, the slope and shape of a supply curve can vary depending on the market conditions and the behavior of the suppliers, and cannot be generalized as being the same for all supply curves.

Answer:

Negative

Positive

Explanation:

When a positive charge balloon is brought near the neutral metal can, the positive charge in the ballon, delocalization and arrangement of like charges occurs. The positive charge then flow to the an end while the negative charges flows to the other end.

Thus, after being touched, the charge on the can is negative.

And, If not touched, the charge on the ballon remains positive.

After being touched, the charge on the can is negative and the charge on the balloon is positive.

When the two materials are rubbed each other, then the electric charged generated between them.

This charging of materials due to the rubbing or two materials against each other, is called the charging by friction.

This force of attraction or repulsion is identified by the sign of the particular charge. According to the property of interacting charges-

Here, the neutral metal can is mounted on a foam stand. A positively charged balloon is brought near. The can is touched on the opposite side.

The positive charge on the balloon, make it to lose the electron. By this, the balloon become positively charged.

The atom on the opposite side have an excess of electron. Thus, the can become negatively charged.

Hence, after being touched, the charge on the can is negative and the charge on the balloon is positive.

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Answer:

Newton's second law applies here

Explanation:

Newton's second law states that the force on an object is equal to its mass times its acceleration. It applies to this question because a bigger car has more mass, so it needs a larger engine for more acceleration.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

a) 8.3×1015 s

b) 1.52×1013 Solar Masses

Answer:

117.6 v

Explanation:

4 watts = V * 3.4 x 10^-2

  V = 117.6 V

Answer:

Because the force F is always at 90 degrees to the velocity of the particle.

Explanation:

The factors that determine the path of a particle in a uniform magnetic field depend on

The magnetic flux density

The charge on the particle

The speed of the particle

Why is the trajectory of the positively charged particle curving down, to the bottom of the screen, when moving in the magnetic field?

Because the force F is always at 90 degrees to the velocity of the particle.

This can be illustrated by the equation

F = BQVSINØ

The magnetic force is always acting perpendicular to the particle velocity and its direction can be found using the left hand rule.

Net forces in all above cases will be

A) F net = 0

B) F net = 1 N

C) F net = 5 N

D) F net = 5N

E) F net  = 5 N

F) F net = 5 N

G) F net = 9.9 N

H) F net = 9.9 N

A) net force = upward force - downward force

                   = 4 - 4 = 0

B) net force = rightward force - leftward force = 4 - 3 = 1 N  

C) net force  

using Pythagoras theorem

F net =  \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N

D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N

E) balancing horizontal forces

   rightward force - leftward force  = 5 - 2 = 3 N

   using  Pythagoras theorem

   F net =  \(\sqrt{4^{2} + 3^{2} }\) = 5 N

F) balancing vertical forces

   -5 + 2 = -3 N

    using  Pythagoras theorem

     \(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N

G) using  Pythagoras theorem

    F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N

H ) balancing horizontal forces

     10 - 3 = 7 N

     \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N

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Possible experimental errors with the motion lab are making a math error, incorrect measuring, cars not let go at right time, did not follow directions.

The difference between two measurements is called an error.

The error in measurement is a mathematical way to show the uncertainty in the measurement.

Thus, possible experimental errors with the motion lab are making a math error, incorrect measuring, cars not let go at right time, did not follow directions.

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Answer:

9.57m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 90m/s

Distance  = 423m

Unknown:

Acceleration of the race car  = ?

Solution:

To solve this problem, we should apply one of the appropriate motion equations;

      V²  = U²   + 2as

Where V is the final velocity

           U is the initial velocity

           a is the acceleration

           s is the distance

  90²  = 0²  + 2 x a x 423

  8100 = 846a

      a  = 9.57m/s²

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Answer:

Explanation:

In this experiment, a block and tackle system was created using two broomsticks, a rope, and two helpers. The rope was tied to one broomstick and wrapped around the other, creating a simple pulley system. When the free end of the rope was pulled, the helpers resisted and the broomsticks did not move.

Next, the rope was woven back over the first broomstick, creating a double pulley. Pulling on the free end of the rope resulted in the broomsticks moving closer together. This demonstrated the mechanical advantage of the block and tackle system.

By adding more loops of rope over the broomsticks, the mechanical advantage was increased further. The force applied to the rope was spread out over a greater distance, resulting in less force required to move the broomsticks.

In summary, the block and tackle system increases mechanical advantage by spreading out the force applied over a greater distance. This is achieved through the use of pulleys and loops of rope, allowing a smaller force to move a larger load.

Answer:

Below

Explanation:

Equal and opposite 1500 N

Answer: Regardless of their weight, before opening their parachutes, the guys fell at the same velocity.

According to the data, the acceleration due to gravity is 9.8 m/s/s

Opening the parachutes provided air resistance and changed their velocity.

Explanation:

When in free fall, mass does not affect the speed of moving objects (only gravitational force is acting upon it).

If you take a look at the data, you can see that the velocity is increasing at a constant rate in intervals of 9.8. This is the acceleration which makes sense because acceleration is the change of velocity divided by time.

Think about it: parachutes slow down the object that is falling because it creates a barrier between the object falling and the gravitational force it encounters. The change in the effects of the gravitational force will alter the velocity.

I hope this was helpful. Have a nice day!

Answer:

The end of the ramp is 38.416 m high

Explanation:

Horizontal Motion

When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)

If the maximum horizontal distance is known, we can solve the above equation for h:

\(\displaystyle h=\frac {d^2g}{2v^2}\)

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

\(\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}\)

\(\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}\)

h= 38.416 m

The end of the ramp is 38.416 m high

Answer:

Explanation:

The charge must be negative so that force in a downward electric field will be upward so that its weight is balanced .

Let the charge be - q .

force on charge

= q x E where E is electric field

= q x 680

weight = 1.6 x 10⁻³ x 9.8

so

q x 680 = 1.6 x 10⁻³ x 9.8

q = 1.6 x 10⁻³ x 9.8 / 680

= 23 x 10⁻⁶ C

- 23 μ C .

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

\(\boxed {\boxed {\sf 2.2 \ m/s^2}}\)

Explanation:

We are asked to solve for the magnitude of the car's acceleration.

We are given the initial speed, final speed, and distance, so we will use the following kinematic equation.

\({v_f}^2={v_i}^2+2ad\)

The car is initially traveling at 15.0 meters per second and accelerates to 20.0 meters per second over a distance of 40.0 meters. Therefore,

Substitute the values into the formula.

\((20.0 \ m/s)^2= (15.0 \ m/s)^2 + 2 a (40.0 \ m)\)

Solve the exponents.

\(400.0 \ m^2/s^2 = 225.0 \ m^2/s^2 + 2 a(40.0 \ m)\)

Subtract 225.0 m²/s² from both sides of the equation.

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 225.0 \ m^2/s^2 -225 \ m^2/s^2 +2a(40.0 \ m)\)

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 2a(40.0 \ m)\)

\(175 \ m^2/s^2 = 2a(40.0 \ m)\)

Multiply on the right side of the equation.

\(175 \ m^2/s^2 =80.0 \ m *a\)

Divide both sides by 80.0 meters to isolate the variable a.

\(\frac {175 \ m^2/s^2}{80.0 \ m}= \frac{80.0 \ m *a}{80.0 \ m}\)

\(\frac {175 \ m^2/s^2}{80.0 \ m}=a\)

\(2.1875 \ m/s^2 =a\)

Round to the tenths place. The 8 in the hundredth place tells us to round the 1 up to a 2.

\(2.2 \ m/s^2=a\)

The magnitude of the car's acceleration is 2.2 meters per second squared.

Answer: 22.1

Explanation:

Answer:

Explanation:

Given that,

The current in the light bulb, I = 0.5 A

(a) We know that,

Electric current = charge/time

or

Q = It

Put t = 2 hours = 7200 s

So,

Q = 0.5 × 7200

Q = 3600 C

(b) Charge on one electron, \(Q=1.6\times 10^{-19}\ C\)

Let there are n electrons flow through the bulb in 2 hours.

I = Q/t

Since, Q = ne

So,

I = ne/t

\(n=\dfrac{I\times t}{e}\\\\n=\dfrac{0.5\times 7200}{1.6\times 10^{-19}}\\\\n=2.25\times 10^{22}\)

Hence, this is the required solution.

Answer:

The difference between AC and DC lies in the direction in which the electrons flow. In DC, the electrons flow steadily in a single direction, or "forward." In AC, electrons keep switching directions, sometimes going "forward" and then going "backward."