A straight long wire carries an electric current to the right. The current is placed in a uniform magnetic field directed into the page. What is the direction of the magnetic force on the current

Answer:

A bird flies 75m in 15s.Calculate its speed

Answer:

A 220 N

Explanation:

it’s the only one not marked out on the photo. Hope this helps!

if our sun were twenty-four times as massive as it is, 4.4721Vο  times faster or slower should the earth move in order to remain in the same orbit.

Given m= 20 m

Vо = √GM/R

     =√20Vo

      =4.47214 Vo

Depending on how far away from the Sun a planet is, its orbital speed varies. A planet's gravitational attraction is stronger and it moves more quickly the closer it is to the Sun. If the Sun's mass doubled without pushing or pulling on the Earth, the Earth's orbit would change to an ellipse, bringing it out to our current radius but spending most of the time closer to the Sun. The farther it is from the Sun, the weaker the Sun's gravitational pull is, and the slower it moves in its orbit. When our orbit brings us closer to the sun, the tides would likely get considerably greater. The sun's gravity controls the orbital distance and speed.

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The hypotenuse is the initial velocity of the cannonball (56.0m/s). The opposite side is the vertical component of the velocity and the adjacent side is the horizontal component of the velocity.

To determine the unknowns, we need to use trigonometry. Let's use theta to represent the angle at which the cannonball was launched. The vertical component of the initial velocity can be found using the equation:
Vsin(theta) = opposite side
Vsin(theta) = (56.0m/s)sin(theta)
The horizontal component of the velocity can be found using the equation:
Vcos(theta) = adjacent side
Vcos(theta) = (56.0m/s)cos(theta)
We can use these equations to solve for the unknowns. For example, if we wanted to find the angle at which the cannonball was launched, we could set the two equations equal to each other and solve for theta:
Vsin(theta) = Vcos(theta)
tan(theta) = opposite side/adjacent side
tan(theta) = (56.0m/s)sin(theta)/(56.0m/s)cos(theta)
tan(theta) = sin(theta)/cos(theta)
theta = tan^-1(sin(theta)/cos(theta))
Using a calculator, we find that theta is approximately 51.3 degrees. Therefore, the cannonball was launched at an angle of 51.3 degrees.  While the ultimate velocity of an object thrown upward will be zero, the final velocity of an object thrown downward will be twice as fast as the initial velocity. Due to the forces of gravity, when an object is thrown both upward and downward with the same initial velocity, the ultimate velocities will differ. The object thrown upward will have a negative ultimate velocity, while the thing thrown downhill will have a positive end velocity.

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Answer:

Explanation:

Answer:

A

Explanation:

turning on a stove to heat dinner because it undergoes a chemical reaction to transform into other substance

Growing up a tree is a conversion from light energy to chemical energy.

Energy can neither be created nor be destroyed , it gets only transferred from one form to another.

Thus, Growing up a tree is a conversion from light energy to chemical energy.

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The net momentum of the system before the collision is given by the expression: Momentum before = m1v1 + m2v2where m1 and v1 are the mass and velocity of the cue ball respectively and m2 and v2 are the mass and velocity of the eight ball respectively.

Substituting in the given values, we have:Momentum before = (0.6 kg) (3.0 m/s) + (0.55 kg) (2.0 m/s) = 1.80 kg m/s + 1.10 kg m/s = 2.90 kg m/s. The net momentum of the system after the collision is given by the expression:Momentum after = m1v1' + m2v2'where v1' and v2' are the velocities of the cue ball and eight ball respectively after the collision.

Substituting in the given values, we have: Momentum after = (0.6 kg) (2.0 m/s cos 40°) + (0.55 kg) (v2')Momentum after = 1.20 cos 40° kg m/s + (0.55 kg) (v2')Momentum after = 0.92 kg m/s + 0.55 kg v2'Conservation of momentum principle states that the total momentum before the collision must equal the total momentum after the collision: Momentum before = Momentum after2.90 kg m/s = 0.92 kg m/s + 0.55 kg v2'Solving for v2', we get:v2' = (2.90 kg m/s - 0.92 kg m/s) / 0.55 kgv2' = 4.71 m/s.

The north component (y-component) of the momentum of the cue ball after collision is given by the expression:py = m1v1' sin θSubstituting the given values, we have:py = (0.6 kg) (2.0 m/s sin 40°)py = 0.78 kg m/sTherefore, the final velocity of the eight ball is 4.71 m/s.

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The new gravitational force between the two heavenly bodies is six times the original gravitational force.

The gravitational force between two heavenly bodies can be calculated using Newton's law of universal gravitation;

F1 = G × (m1 × m2) / r²...eq (1)

gravitational constant = G

mass 1 = m1

mass 2 = m2

radius = r

distance between them constant,

we can calculate the new gravitational force F2 using the formula:

F2 = G × (m1 × m2) / r²; where

gravitational constant = G

mass 1 = 2m1 (doubled)

mass 2 = 3m2 (tripled)

radius = r

on substitution,

F2 = G × (2m1 × 3m2) / r²

= G × (6m1m2) / r²

= 6 × G × (m1m2) / r²

⇒ (G × (m1 × m2) / r² = F1 )...from eq. (1)

= 6 × F1

⇒ F2 = 6F1

Therefore, the new gravitational force will be six times the original gravitational force when one mass is doubled and the other mass is tripled.

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If one of the masses in a gravitational system is doubled and the other mass is tripled while keeping the distance between the bodies constant, then the new gravitational force will increase by a multiple of:

6 (2 x 3 = 6)

We know from Newton's Law of Gravitation that the gravitational force between two objects is:

F = G * (m1 * m2) / r^2

Where:

F = Gravitational force

G = Universal gravitational constant

m1 = Mass of first object

m2 = Mass of second object

r = Distance between the objects

Since the distance (r) between the two bodies remains constant in the given scenario, it drops out when calculating the change in force.

We are only concerned with how the change in masses affects the force.

Based on the equation, we can see that the gravitational force is directly proportional to the product of the two masses (m1 * m2).

If one mass doubles and the other mass triples, their product will increase by a multiple of 2 x 3 = 6.

Therefore, the new gravitational force between the two heavenly bodies will increase by a factor of 6, compared to the original gravitational force when only one mass was doubled and the other mass tripled, while keeping the distance constant between them.

Answer:

It is an educated guess

Explanation:

let me know if the bottom ones need to be answered too.

The specific heat capacity of water is 1 calorie per gram per degree Celsius. This means that 1 gram of water will absorb 1 calorie of heat for every 1 degree Celsius increase in temperature.

In this case, we have 32.0 grams of water that is heated from 25.0 degrees Celsius to 80.0 degrees Celsius. The change in temperature is therefore 80.0 - 25.0 = 55.0 degrees Celsius.

The amount of heat absorbed by the water is therefore 32.0 x 55.0 = 1760 calories.

To convert calories to joules, we can use the following conversion factor:

1 calorie = 4.184 joules

Therefore, the amount of heat absorbed by the water in joules is 1760 x 4.184 = 7374 joules.

Therefore, the answer to your question is that 32.0 grams of water absorbs 7374 joules of heat when it is heated from 25.0 degrees Celsius to 80.0 degrees Celsius.

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Explanation:

Uranus is the outermost planets of the solar system. Uranus rotates from east to west and has a highly tilted rotational axis. As a result, in its orbital motion it appears to roll on its side. because the axis of uranus is very tilted, therefore, it appears to roll on it's side

Answer:25

Explanation:

Formula(77°F − 32) × 5/9 = 25°C

Answer: The answer is C. 298 K

Explanation:

The work performed by Sean is 32.14 J.

Work can be defined as the product of force and distance. The S.I unit of work is Joules (J)

To calculate the amount of work performed by Sean, we use the formula below.

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The work performed by Sean is 32.14 J.

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The current in the wire is 3.0 A.

The current in the wire can be calculated using the formula I = Q/t where I is current, Q is the charge, and t is the time. In this case, the wire delivers 12.0 c of charge in 4.0 s. Plugging these values into the formula,

we get I = 12.0 c / 4.0 s = 3.0 A.

Thus, the current flowing through the wire is 3.0 Amperes (A). This indicates the rate at which the charge is passing through the wire during the 4.0 seconds interval. Current is a fundamental electrical quantity, and its value is essential in understanding and analyzing electrical circuits and devices.

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Explanation:

\(net \: force \: = gravitation \: force - resistance \\ 10000 = F - 9000 \\ F = 19000\)

According to the information provided, the area showing abnormally high sea level is area C.

To identify the area of the sea with the highest level, we must take as a reference the colors of each region and to what parameters each one corresponds.

In this case we have a map with areas painted in blue, yellow, red and gray, that is, there are areas with the following characteristics.

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Answer:c

Explanation:test

Answer:

The mass of the reactants will always equal the mass of the products.

Explanation:

If an equation is provided choose the one that has the same number of atoms on each side.

The work required by the process is _____ kJ/kg.

The work required to compress water isentropically from 10°C and 81.4 percent quality to 3 MPa can be determined using steam tables. The first step is to locate the initial state of water at 10°C and 81.4 percent quality in the steam tables. From the tables, we find the specific enthalpy (h1) and specific entropy (s1) values for the given state.

Next, we find the specific enthalpy (h2) at the final state of 3 MPa from the steam tables.

Using the isentropic compression process, we assume that the entropy remains constant (s2 = s1).

The work required (W) can be calculated using the equation:

W = h1 - h2

Substituting the values obtained from the steam tables, we can find the work required per kilogram in kJ.

Steam tables provide a comprehensive set of data for water and steam properties, including enthalpy, entropy, and other thermodynamic parameters. These tables are essential for engineers and scientists working with steam and thermal systems. By utilizing steam tables, it becomes possible to accurately calculate various processes involving water and steam, such as compression, expansion, and phase changes. They are widely used in fields like power generation, HVAC systems, and industrial processes. Understanding and effectively utilizing steam tables are crucial skills for professionals in these domains.

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Water at 10°C and 81.4 percent quality, when compressed isentropically in a closed system to 3 MPa, requires a work of _______ kJ/kg.

The work required for this process can be determined by considering the initial and final states of the water percent quality and applying the principles of thermodynamics. At the given initial condition of 10°C and 81.4 percent quality, we can use steam tables to find the specific enthalpy and entropy values.

By applying the isentropic compression process, we can determine the final state of the water at a pressure o f 3 MPa. The difference in specific enthalpy between the initial and final states givesus the work required per unit mass.To calculate the specific enthalpy at te initial state, we use the steam tables to find the enthalpy of water at 10°C, which is h1. Similarly, the specific entropy at the initial state is obtained from the steam tables as s1.

By assuming an isentropic process, the specific entropy at the final state, s2, remains the same as s1. Using the final pressure of 3 MPa, we find the specific enthalpy of water at this state, h2, from the steam tables.

The work required per unit mass (w) cn be calculated using the equation:

w = h2 - h

Substituting the values obtained from the steam tables, we can determine the work required for this process in kJ/kg.

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Therefore, option (b) is the correct answer. It is important to note that increasing the speed of the ball will also increase its kinetic energy and potential energy, as well as the tension in the string.

The force on the string holding the ball swinging in a circle is related to the speed and mass of the ball. When the ball is moved twice as fast, the force on the string will increase. This increase in force can be calculated using the equation F = mv²/r, where F is the force on the string, m is the mass of the ball, v is the velocity of the ball, and r is the radius of the circle. As the velocity of the ball is doubled, the force on the string will be four times as great. This is because velocity is squared in the equation.

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Answer:

The mass of platinum iridium rod whose diameter and height are equal an kept at international bureau of weight and measurement in Paris of France is called as one standard kg.

a) The isocost curve equation is G = (20000 - 100C)/500. b) The isocost curve equation is G = (30000 - 100c)/500. c) The isocost curve equation is G = (20000 - 100C)/375. d)  The isocost curve equation is G = (20000 - 120C)/500.

To draw the isocost curve showing the different combinations of gas and coal, we need to use the cost per unit values for coal and gas, as well as the given expenditure (TC) and the changes in expenditure or prices.

Let's denote the quantity of coal as C and the quantity of gas as G. The cost per unit of coal is 100, and the cost per unit of gas is 500.

(a) Initial expenditure (TC) of 20000:

To find the combinations of gas and coal that can be purchased with an initial expenditure of 20000, we can use the following isocost equation

TC = 100C + 500G

We can rearrange the equation to solve for G in terms of C

G = (TC - 100C) / 500

Now we can plot the isocost curve with TC = 20000 using the equation above.

(b) Expenditure (TC) increases by 50%

If the expenditure increases by 50%, the new expenditure (TC_new) becomes 1.5 × TC = 1.5 × 20000 = 30000.

We can use the same isocost equation as before, but with the new expenditure value:

TC_new = 100C + 500G

Rearranging the equation to solve for G

G = (TC_new - 100C) / 500

Now we can plot the isocost curve with TC_new = 30000.

(c) Gas price reduced by 25%:

If the gas price is reduced by 25%, the new cost per unit of gas (Gas_new) becomes 0.75 × 500 = 375.

We can use the original isocost equation, but with the new cost per unit value:

TC = 100C + 375G

Rearranging the equation to solve for G

G = (TC - 100C) / 375

Now we can plot the isocost curve with the reduced gas price.

(d) Coal price rises by 20%

If the coal price rises by 20%, the new cost per unit of coal (Coal_new) becomes 1.2 × 100 = 120.

We can use the original isocost equation, but with the new cost per unit value:

TC = 120C + 500G

Rearranging the equation to solve for G:

G = (TC - 120C) / 500

Now we can plot the isocost curve with the increased coal price.

By plotting these isocost curves on a graph with G on the y-axis and C on the x-axis, we can visualize the different combinations of gas and coal that can be purchased at the given expenditures or price changes.

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The measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

Option C.

The median is the middle point in a dataset—half of the data points are smaller than the median and half of the data points are larger.

To find the median: Arrange the data points from smallest to largest. If the number of data points is odd, the median is the middle data point in the list.

So from the given data of the 100 meter dash, the measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

The median will help to separate half of the data points that are smaller than the cutoff time and half of the data points are larger than the cutoff time.

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Explanation:

First, we need to calculate the gravitational field strength g on Planet Y. So, we will use the following e

The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.

The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

The force on particle q2 due to q1 will be:

F1 = k * (q1 * q2) / (0.980m)^2

The force on particle q2 due to q3 will be:

F2 = k * (q2 * q3) / (0.750m)^2

The net force acting on q2 will be the vector sum of F1 and F2.

Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.

Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.

Answer:

Measurement scales are used to categorize and/or quantify variables. This lesson describes the four scales of measurement that are commonly used in statistical analysis: nominal, ordinal, interval, and ratio scales.

Hope I helped let me know if I didn't

Answer:

i) 180m ii) 6sec ii)180m

Explanation:

i) Hmax = U²/2g

= 60²/20

= 3600/20= 180m

ii). Tmax= U/g

= 60/10= 6sec

iii). X= ut²+ 1/2gt²

since U is 0,then ut=0

X=0+ 1/2×10×6²

X=5×36= 180m

hope its clear??

The Mach number for the plane is approximately 3.51.

To find the speed of the plane, we can use the equation:

Speed of sound = Speed of the plane / Time taken

Given: Speed of sound (v) = 344 m/s

Time taken (t) = 3.51 seconds

Let's calculate the speed of the plane:

Speed of plane = Speed of sound × Time taken

Speed of plane =\(344 m/s * 3.51 s\)

Speed of plane ≈ 1206.44 m/s

Rounded to 2 decimal places, the speed of the plane is approximately 1206.44 m/s.

To find the Mach number of the plane, we need to divide the speed of the plane by the speed of sound:

Mach number = Speed of plane / Speed of sound

Mach number ≈ \(1206.44 m/s / 344 m/s\)

Mach number ≈ 3.51

Rounded to 2 decimal places, the Mach number for the plane is approximately 3.51.

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Operators must have unobstructed access to a ladder for escape from a trench within a distance of 25 feet.
According to OSHA regulations, operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet.

According to OSHA Occupational Safety and Health Administration, employers must provide ladders, steps, ramps, or other safe means of egress for workers working in trench excavations 4 feet 1.22 meters or deeper1. The means of egress must be located so as not to require workers to travel more than 25 feet 7.62 meters laterally within the trench1. Therefore, the answer is c 25 feet. Operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet

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