Answer:
The stone takes 2.55 sec to reach a maximum height of 31.89 m
Explanation:
Vertical Motion
When an object is thrown vertically up with a speed vo, it loses speed because of the effect of the gravity and gains height until the speed is eventually zero. The height attained at that time is called maximum height, and can be calculated as follows:
\(\displaystyle h_m=\frac{v_o^2}{2g}\)
Since vo=25 m/s
\(\displaystyle h_m=\frac{25^2}{2\cdot 9.8}=31.89\ m\)
Also, the time taken to reach the maximum height is calculated by:
\(\displaystyle t_m=\frac{v_o}{g}\)
\(\displaystyle t_m=\frac{25}{9.8}=2.55\ s\)
The stone takes 2.55 sec to reach a maximum height of 31.89 m
\(Question: $x_{1}=\frac{5}{2}[\sin (2 \pi t)+\cos (2 \pi t)], x_{2}=5\left[\sin \left(2 \pi t+\frac{\pi}{4}\right)\right]$\)
Find the ratio of the amplitude of the given motion?
Options:
\((a) $\sqrt{2}: 1$\\(b) $2: 1$\\(c) $1: \sqrt{2}$\\(d) $1: 2$\)
Condense x₁ to get
sin(2πt) + cos(2πt) = √2 • (sin(2πt) + cos(2πt))/√2
… = √2 (cos(2πt) cos(π/4) + sin(2πt) sin(π/4))
… = √2 cos(2πt - π/4)
So the amplitude of x₁ is (5/2) • √2 = 5/√2, while the amplitude of x₂ is 5. The ratio between them is then 5/√2 : 5, or equivalently 1/√2 : 1 or 1 : √2.
Average speed of a girl that runs 100m in 50 seconds
Answer:
2 m/sec
Explanation:
speed = distance/time so v = 100/50 m/sec = 2 m/sec.
-What is the potential energy at point A?
-What is the kinetic energy at point A?
-What is the kinetic energy at point B?
-What is the potential energy at point D?
-What is the kinetic energy at point D?
Answer:
1560520156Explanation:
Assuming there is no friction or other force involved, recall that energy is conserved in a system as long as no external force acts on the system.
Using the data from point C, we can find out that the total energy of the system is 156 because \(E = K+Pe\).
Since at point A the object doesn't move, it has Kinetic energy of 0, because \(K=\frac{1}{2} mv^2\), therefore \(0=\frac{1}{2} m0^2\). However at point A it has maximum Potential energy, because \(Pe=mgh\).
At point B, we can find the Kinetic energy by using \(E = K+Pe\). Substitute values:
\(156=104+K\\52=K\)
At point D, the object has maximum kinetic energy and no potential energy, therefore it's the opposite of point A.
What important change in the atmosphere occurred during the Proterozoic Eon?
A. Helium escaped into space and hydrogen was bound into water molecules
B. Nitrogen and carbon dioxide levels decreased, fueling bacteria growth
C. Carbon dioxide levels increased, causing glaciation that cooled the planet
D. Methane levels decreased and oxygen levels increased, promoting aerobic life forms
Answer:
THE IS ANSWER IS D
Explanation:
I GOT THIS CORRECT ON MY EXAM!
what are ionic charges
Answer:
Ionic charges refer to the electrical charges of ions, which are atoms or molecules that have gained or lost electrons. These charges result from the loss or gain of electrons during chemical reactions.
When an atom loses one or more electrons, it becomes a positively charged ion known as a cation. The cation carries a positive charge equal to the number of electrons lost.
Conversely, when an atom gains one or more electrons, it becomes a negatively charged ion known as an anion. The anion carries a negative charge equal to the number of electrons gained.
The magnitude of the ionic charge depends on the number of electrons gained or lost, which is determined by the element's position in the periodic table and its electron configuration. For example, sodium (Na) loses one electron to become a +1 charged cation (Na+), while chlorine (Cl) gains one electron to become a -1 charged anion (Cl-).
A ballerina begins a tour jeté (Fig. 11-20a) with angular speed w; and a rotational inertia consisting of two parts:
Ileg = 1.44 kg m² for her leg extended outward at angle
0 = 90.0° to her body and Itrunk = 0.660 kg m² for the rest of
her body (primarily her trunk). Near her maximum height
she holds both legs at angle 0 = 30.0° to her body and has angular speed wf (Fig. 11-20b). Assuming that trunk has not
changed, what is the ratio wf/w?
The term "moment of inertia" refers to the quantity that describes how a body resists angular acceleration. It is calculated by multiplying each particle's mass by its square of the distance from the axis of rotation.
A rigid body's moment of inertia—also referred to as its mass moment of inertia, angular mass, second moment of mass, or—most precisely—rotational inertia—determines the torque.
"I = L / W"
Let Ja be the moment of inertia of the legs.
When leg at 90 degrees,
Ja1 = 1.44 kgm² = m*1²...m = 1.44/1 = 1.44
When both legs at 26.5°
sin 26.5°= 0.45
Ja2 = 2*m*(sen26.5)² = 2.88*.45² = 0.58 kgm²
Jt1 = Ja1 + Jt = 1.44 + 0.76 = 2.15 kgm²
Jt2 = Ja2+Jt = 0.58+0.706 = 1.29 kgm²
wf/w = Jt1/Jt2 = 2.15/1.29 = 1.67
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If a 400-mm diameter pipe with a pipe roughness coefficient of 100 flows full of pressurized water with a head loss of 0.4 ft per 1,000 ft of pipeline, what is the flow rate? Use the Hazen-Williams method
Answer:
Q = 913.9 gpm
Explanation:
The Hazen Williams equation can be written as follows:
\(P = \frac{4.52\ Q^{1.85}}{C^{1.85}d^{4.87}}\)
where,
P = Friction Loss per foot of pipe = \(\frac{0.4}{1000\ ft}\) = 4 x 10⁻⁴
Q = Flow Rate in gallon/min (gpm) = ?
d = pipe diameter in inches = (400 mm)(0.0393701 in/1 mm) = 15.75 in
C = roughness coefficient = 100
Therefore,
\(4\ x \ 10^{-4} = \frac{4.52\ Q^{1.85}}{(100)^{1.85}(15.75)^{4.87}}\\\\Q^{1.85} = \frac{4\ x \ 10^{-4}}{1.33\ x\ 10^{-9}} \\\\Q = (300384.75)^\frac{1}{1.85}\)
Q = 913.9 gpm
A man applies a force of 315 N to push the block of 225 kg onto 10 m ramp. Calculate the efficiency of the person if the mass gains a height of 1.2 m.
Answer:
η = 0.84 = 84%
Explanation:
The efficiency of the man can be given by the following formula:
η = output/input
where,
η = efficiency of man = ?
output = potential energy gain of the block = mgh
input = work done by man = Fd
Therefore,
\(\eta = \frac{mgh}{Fd}\)
where,
m = mass of block = 225 kg
g = acceleration due to gravity = 9.81 m/s²
h = height gained by block = 1.2 m
F = force exerted by man = 315 N
d = distance covered by man = 10 m
Therefore,
\(\eta = \frac{(225\ kg)(9.81\ m/s^2)(1.2\ m)}{(315\ N)(10\ m)}\)
η = 0.84 = 84%
A bird has a mass of 0.8 kg. Calculate the weight of the bird.
Answer:
the mass and wieght means same
5. A Car of mass 1000kg is driven from it's initial
state with uniform acceleration and reaches a
Speed of 30km/h in 10 second find
1 ). Force exerted by the engine.
2). the power in killo watts (kw)
A little girl pushes a 5.0 kg toy baby stroller at constant speed 7.0 m across the floor. She pushes on the handle with a force of 40 N at an angle of 30o with the horizontal. All parts are 4 points each.
Complete Question
1 a A little girl pushes a 5.0 kg toy baby stroller at constant speed 7.0 m across the floor. She pushes on the handle with a force of 40 N at an angle of 30o with the horizontal. How much work is done by the girl on the wagon?
1b A farmhand pushes 20 ㎏ bale of hay 4m across the floor of the barn if she exerts a horizontal force of 60 N on the hay, how much work is done? (5 pts)
All parts are 4 points each
Answer:
1a
\(W = 242.5 \ J\)
1b
\(W = 240 \ J\)
Explanation:
Considering question a
From the question we are told that
The mass of the toy baby stroller is \(m = 5.0 \ kg\)
The distance covered is \(d = 7.0\ m\)
The force the girl applies on the handle is \(F = 40 \ N\)
The angle at which this force is applied is \(\theta = 30^o\)
Generally the workdone is mathematically represented as
\(W = F_x * d\)
Here \(F_x\) is the force along the horizontal axis , this is mathematically represented as
\(F_x = F cos (\theta )\)
=> \(F_x = 40 * cos(30 )\)
=> \(F_x = 34.64 \ N\)
So
\(W = 34.64 * 7\)
=> \(W = 242.5 \ J\)
Considering question b
From the question we are told that
The mass of the toy baby stroller is \(m = 20 \ kg\)
The distance covered is \(d = 4 \ m\)
The force the girl applies on the handle is \(F = 60 \ N\)
Generally the workdone is mathematically represented as
\(W = F * d\)
=> \(W = 60 * 4\)
=> \(W = 240 \ J\)
You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogram-meter^3 and the density of silicon in other units: 2.33 gram-centimeter^3. You decide to convert the density of silicon into units of kilogram-meter^3 to perform the comparison.
By which combination of conversion factors will you multiply 2.33 gram-centimeter^3 to perform the unit conversion?
Answer:
Explanation:
To convert gram / centimeter³ to kg / m³
gram / centimeter³
= 10⁻³ kg / centimeter³
= 10⁻³ / (10⁻²)³ kg / m³
= 10⁻³ / 10⁻⁶ kg / m³
= 10⁻³⁺⁶ kg / m³
= 10³ kg / m³
So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³
2.33 gram / cm³
= 2.33 x 10³ kg / m³ .
Two identical cars (m-1350 kg) are traveling at the same speed of 35.7 m/s. They are moving in the directions shown in the drawing
What is the magnitude of the total momentum of the two cars?
Car 1 - 60°
Car 2 - 30°
The magnitude of the total momentum of the two cars is 68,245.5 kg m/s.
What is the magnitude of the car's total momentum?To calculate the total momentum of the two cars, we need to first calculate the momentum of each car and then add them together.
The momentum of an object is given by the product of its mass and velocity. So, the momentum of each car can be calculated as:
p = m x v
where;
p is momentum, m is mass, and v is velocity.Since both cars have the same mass, their momenta will be equal if they have the same velocity. In this case, both cars are traveling at the same speed of 35.7 m/s.
The momentum of car 1 can be calculated by resolving its velocity into horizontal and vertical components:
vx1 = v1 cos(60°) = 0.5 x 35.7 = 17.85 m/s
vy1 = v1 sin(60°) = 0.866 x 35.7 = 30.97 m/s
The momentum of car 1 is then:
p₁ = m x v₁ = 1350 x √(vx₁² + vy₁²)
p₁ = 1350 x √(17.85² + 30.97²)
p₁ = 48,256.85 kg m/s
Similarly, the momentum of car 2 can be calculated by resolving its velocity into horizontal and vertical components:
vx2 = v2 cos(30°) = 0.866 x 35.7 = 30.97 m/s
vy2 = v2 sin(30°) = 0.5 x 35.7 = 17.85 m/s
The momentum of car 2 is then:
p₂ = m x v₂ = 1350 x √(vx₂² + vy₂²)
p₂ = 1350 x √(30.97² + 17.85²)
p₂ = 48,256.85 kg m/s
The total momentum of the two cars is the vector sum of their momenta, which can be calculated using the Pythagorean theorem:
ptotal = √(p₁² + p₂²)
= √((48,256.85 )² + (48,256.85²) = 68,245.5 kg m/s
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A 20 kg sled is pulled up a 10m tall hill. What work is done against gravity?
Answer:
1962
Explanation:
w = f × d
= 20×9.81 × 10
= 1962
Traveling waves propagate with a fixed speed usually denoted as v (but sometimes c). The waves are called __________ if their waveform repeats every time interval T. Traveling waves propagate with a fixed speed usually denoted as (but sometimes ). The waves are called __________ if their waveform repeats every time interval . transverse longitudinal periodic sinusoidal
Answer:
Periodic.
Explanation:
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.
Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data.
Generally, a fixed speed is used for the propagation of traveling waves and this speed is usually denoted with the variable "v" or sometimes "c."
Furthermore, if the waveform of a traveling wave is repeated every time at specific intervals T, it is referred to as periodic wave.
Mathematically, the period of a traveling wave is given by the formula;
\( Period = \frac {1}{T} \)
Where;
T is the time measured in seconds.
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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a true statement of
kinetic theory
Answer:
real kinetic theory means that kinetic energy
6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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Two streams merge to form a river. One stream has a width of 8.3 m, depth of 3.2 m, and current speed of 2.2 m/s. The other stream is 6.8 m wide and 3.2 m deep, and flows at 2.4 m/s. If the river has width 10.4 m and speed 2.8 m/s, what is its depth?
Answer:
The depth of the resulting stream is 3.8 meters.
Explanation:
Under the assumption that streams are formed by incompressible fluids, so that volume flow can observed conservation:
\(\dot V_{1} + \dot V_{2} = \dot V_{3}\) (1)
All volume flows are measured in cubic meters per second.
Dimensionally speaking, we can determine the depth of the resulting stream (\(h_{3}\)), in meters, by expanding (1) in this manner:
\(w_{1}\cdot h_{1}\cdot v_{1} + w_{2}\cdot h_{2}\cdot v_{2} = w_{3}\cdot h_{3}\cdot v_{3}\)
\(h_{3} = \frac{w_{1}\cdot h_{1}\cdot v_{1}+w_{2}\cdot h_{2}\cdot v_{2}}{w_{3}\cdot v_{3}}\) (2)
\(v_{1}, v_{2}\) - Speed of the merging streams, in meters per second.
\(h_{1}, h_{2}\) - Depth of the merging streams, in meters.
\(w_{1}, w_{2}\) - Width of the merging streams, in meters.
\(w_{3}\) - Width of the resulting stream, in meters.
\(v_{3}\) - Speed of the resulting stream, in meters per second.
If we know that \(w_{1} = 8.3\,m\), \(h_{1} = 3.2\,m\), \(v_{1} = 2.2\,\frac{m}{s}\), \(w_{2} = 6.8\,m\), \(h_{2} = 3.2\,m\), \(v_{2} = 2.4\,\frac{m}{s}\), \(w_{3} = 10.4\,m\) and \(v_{3} = 2.8\,\frac{m}{s}\), then the depth of the resulting stream is:
\(h_{3} = \frac{(8.3\,m)\cdot (3.2\,m)\cdot \left(2.2\,\frac{m}{s} \right) + (6.8\,m)\cdot (3.2\,m)\cdot \left(2.4\,\frac{m}{s} \right)}{(10.4\,m)\cdot \left(2.8\,\frac{m}{s} \right)}\)
\(h_{3} = 3.8\,m\)
The depth of the resulting stream is 3.8 meters.
David is driving a steady 25.0m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.60m/s2at the instant when David passes.
How far does Tina drive before passing David?
What is her speed as she passes him?
Tina's speed as she passes David is 25.0 m/s, which is the same as David's speed. To solve this problem, we can use the kinematic equations of motion:
Position as a kinematic equations of time: x = x0 + v0t + (1/2)at^2
Final velocity as a function of time: v = v0 + at
First, let's find out how long it takes for Tina to catch up to David. We can use the second equation above to find the time it takes for Tina to reach David's speed:
v = v0 + at
25.0 m/s = 0 + 2.60 m/s^2 * t
t = 9.62 s
Now we can use the first equation to find how far Tina travels during that time:
x = x0 + v0t + (1/2)at^2
x = 0 + 0 + (1/2)(2.60 m/s^2)(9.62 s)^2
x = 120.3 m
Therefore, Tina drives 120.3 meters before passing David. To find her speed as she passes David, we can use the second equation above:
v = v0 + at
v = 0 + 2.60 m/s^2 * 9.62 s
v = 25.0 m/s is the final velocity.
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A 2.6 mm -diameter sphere is charged to -4.5 nC . An electron fired directly at the sphere from far away comes to within 0.37 mm of the surface of the target before being reflected. Part A What was the electron's initial speed
Answer: \(1.96\times 10^{8}\ m/s\)
Explanation:
Given
Diameter of sphere is \(d=2.6\ mm\quad \quad[r=1.3 mm]\)
Charge on the sphere is \(Q=-4.5\ nC\)
Nearest distance electron can reach to sphere is \(d=0.37\ mm\)
Here, kinetic energy of electron is converted into electrostatic energy between the two i.e.
\(\Rightarrow \dfrac{1}{2}mv^2=\dfrac{kQq}{d}\\\\\Rightarrow \dfrac{1}{2}\times 9.1\times 10^{-31}\times v^2=\dfrac{9\times 10^9\times 4.5\times 10^{-9}\times 1.6\times 10^{-19}}{(3.7\times 10^{-4})}\\\\\Rightarrow v^2=3.8491\times 10^{16}\\\Rightarrow v=1.96\times 10^{8}\ m/s\)
Thus, the initial speed of electron is \(1.96\times 10^{8}\ m/s\).
2 kq kg of ice at -4 degress Celsius is heated at Water at room temperature of 25 degrees Celsius .how much heat is absorbed
Answer:
893.8 [kJ].
Explanation:
1) the total heat can be calculated as
E=Q₁+Q₂+Q₃, where Q₁ - energy to heat the ice from -4 to 0; Q₂ - energy to melt the ice; Q₃ - to heat the water at 0 °C to 25 °C;
2) Q₁=λ*m*Δt₁, ⇒ Q₁=2100*2*4=16800 [J];
3) Q₂=c₂*m; ⇒ Q₂=333500*2=667000 [J];
3) Q₃=c₃*m*Δt₂; ⇒ Q₃=4200*2*25=210000 [j];
4) finally, the required heat is
E=16800+667000+210000=893800 [J]=893.8 [kJ].
How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.
The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.
What is hydrostatic pressure?Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.
The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:
P = ρgh + Po
where:
P is the absolute pressure at the given depth
ρ is the density of the water
g is the acceleration due to gravity (assumed to be 9.81 m/s²)
h is the depth of the ocean
Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)
Substituting the given values, we get:
P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa
P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa
P = 1.002 x 10^8 Pa.
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Lola Is making breakfast. she makes toast, scrambles eggs, butters, the toast, fries bacon and squeezes oranges for orange juice. Of the tasks Lola completes, which ones were physical changes, Lola is making breakfast. She makes toast, scrambles eggs, butters the toast, fries bacon, and and how do you know? A- Answer the question: P- Provide evidence: E- Explain and expand:
A- When preparing breakfast, Lola undergoes the following physical changes: Butter the bread and fries the bacon. oranges are squeezed for orange juice
A- Answer the question: P- Provide evidence:Butter the toast: The heat of the toast causes the butter to gently melt when Lola spreads it on the bread. This is a physical modification because it only modifies the butter's and toast's physical characteristics, not their chemical makeup.
Fry bacon: When Lola fries the bacon, the heat melts the fat and denatures and coagulates the proteins, giving the bacon a crispy quality. This is likewise a physical modification because it only modifies the bacon's physical characteristics, not its chemical makeup.
Oranges are squeezed to produce orange juice. The juice is drawn from the orange cells and separated from the pulp when Lola squeezes oranges.
A- Answer the question: E- Explain and expand:A physical alteration is one in which just the substance's physical characteristics, such as shape, size, colour, or state, are altered. The substance's chemical makeup remains unchanged. The butter, bacon, and orange are all enduring physical modifications in the activities that Lola completes because they simply alter their physical characteristics without altering their chemical makeup. For instance, altering the physical qualities of things without altering their chemical makeup includes melting butter and bacon and extracting the juice from an orange.
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Sir Isaac newton's book on laws of motion and gravity is considered of what significance 
The greatest single contribution in the history of science
A steppingstone to becoming a brilliant politician and a member of parliament
A brilliant work on the principles of calculus
Finest math Mattix text book for the 17th century
Answer:
B)
Explanation:
a brilliant work on all the principles it open up a whole new world and change the world algebraicly
question answered finish
question answered finish
What are the reasons Flat Earther's use to prove their claim?
Answer:
The ground we walk on is flat, not round. Gravity doesn't exist. Objects don't fall down, the flat earth(disk) goes up with a force called dark energy. There is a 45 ft tall ice wall to prevent people from falling off the Earth.
Explanation:
If velocity of the car is given as v(t)= 10+3t+512. Determine the acceleration at t=2s.
Given data
*The given velocity of the car is v(t)= 10 + 3t + 512
The acceleration of the car is calculated as
\(\begin{gathered} a(t)=\frac{d}{dt}(v(t)) \\ =\frac{d}{dt}(10+3t+512) \\ =3m/s^2 \end{gathered}\)Thus, the acceleration of the car at t = 2 s is 3 m/s^2
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