A star's mass determines the —
A) shape of a Star
B) location of a star
C) length of its lifecycle
D) galaxy it belongs to

Answer:

1.B

2.A

Explanation:

Answer:

Hit me with brainlist pls

Explanation:

A equals 6.8 and C is the final answer of the equation so you would subtract the answer from a which gives you 2.6 grams

To inflate the baggie with a volume of 836 milliliters using nitrogen gas at a pressure of 1.05 atm and a temperature of 301 K, we can apply the ideal gas law. Using the equation PV = nRT and rearranging it to solve for the number of moles (n), we find that n = PV / RT, which yields approximately 0.08757 moles of nitrogen gas. By multiplying this value by the molar mass of nitrogen (28.02 g/mol for N₂), we can determine the mass of nitrogen gas needed, which comes out to be approximately 2.453 grams. Thus, around 2.453 grams of nitrogen gas are required to inflate the baggie to the desired volume.

To determine the mass of nitrogen gas needed to inflate the baggie, we can use the ideal gas law equation:

PV = nRT

Where:

P = Pressure = 1.05 atm

V = Volume = 836 mL = 0.836 L (converted from milliliters to liters)

n = Number of moles of gas (what we want to find)

R = Ideal gas constant = 0.0821 L·atm/(mol·K)

T = Temperature = 301 K

Rearranging the equation, we can solve for the number of moles (n):

n = PV / RT

n = (1.05 atm * 0.836 L) / (0.0821 L·atm/(mol·K) * 301 K)

n = 0.08757 mol (rounded to 5 decimal places)

Now, we can calculate the mass of nitrogen gas using the molar mass of nitrogen (N₂):

Molar mass of N₂ = 2 * atomic mass of nitrogen (N)

Atomic mass of N = 14.01 g/mol

Molar mass of N₂ = 2 * 14.01 g/mol

Molar mass of N₂ = 28.02 g/mol

Finally, we can calculate the mass of nitrogen gas (m) using the number of moles (n) and the molar mass (M):

m = n * M

m = 0.08757 mol * 28.02 g/mol

m = 2.453 g (rounded to 3 decimal places)

Therefore, approximately 2.453 grams of nitrogen gas are needed to inflate the baggie.

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It takes 24 years for 16.0 ng of tritium to decay to the point where 2.0 ng remains.

Tritium has a half-life of 12 years, which means that in each 12-year period, half of the tritium atoms will decay. To calculate the time it takes for a specific amount of tritium to decay, we can use the concept of half-life.

Step 1:

In the first 12 years, half of the tritium will decay, leaving 8.0 ng remaining (16.0 ng / 2).

Step 2:

In the next 12 years (the second half-life), half of the remaining tritium will decay again, leaving 4.0 ng (8.0 ng / 2).

Step 3:

Continuing this pattern, after another 12 years (the third half-life), we have 2.0 ng remaining (4.0 ng / 2).

Therefore, it takes 24 years for 16.0 ng of tritium to decay to the point where 2.0 ng remains.

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The solubility of caco3 (formula weight 100.1) is 0.0095 g in 1800 ml, The ksp is  8.6x10-8

Ksp is the solubility product constant, which is the equilibrium constant for a saturated solution of an ionic compound at a given temperature. To calculate the Ksp, we need to know the molar solubility of the compound.  The molar solubility of caco3 can be calculated from the given solubility, which is 0.0095 g in 1800 ml. To calculate molar solubility, we need to convert the solubility of caco3 into moles. 0.0095 g of caco3 is equal to 0.00094 moles.   Now, we can use the equation for Ksp, which is Ksp = [Ca2+][CO32-]. Substituting the molar solubility of caco3, we get Ksp = 0.00094 x 0.00094 = 8.6x10-8.

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Answer:

Boron has different isotopes with different atomic masses. The relative atomic mass of boron, which is 9, is the average of the atomic masses of the isotopes

Explanation:

The relative atomic mass is indicated in terms of its heaviness compared to the parts of mass of carbon-12. The relative mass of boron is 9 means its mass relative to the mass of carbon -12 is 9 amu.

The relative atomic mass of an element is the mass relative to the mass of carbon-12 or it can be defined as the number which indicates how many times the mass of one atom of the element is heavier in comparison to (1/12)th part of the mass of one atom of carbon-12.

Usually the mass number of an atom is the sum of number of protons and number of neutrons. But the actual mass or average atomic  mass is not calculated in this way.

The actual mass is determined using mass spectroscopy. The relative atomic mass of every element is computed based on the mass of C-12 obtained from spectroscopic technique.

Thus the relative atomic mass of boron is calculated in a similar way and it is 9 amu.

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Answer:

body energy

Explanation: because  you are running it is taking ur energy

The concentration of CO (g) in the equilibrium mixture is 0.020 M. In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.

The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.

Given that the concentration of H2O (g) is [H2O] = 0.500 M at 1000°C, and  the reaction is:

C(s) + H2O(g) ⇄ CO(g) + H2(g) KC = 0.2 at 1000°C

We need to determine the concentration of CO in an equilibrium mixture (in mol/L)

if a reaction mixture initially contains only reactants.

We can solve this problem using the ICE table method as follows:

Let x be the change in concentration of H2O (g) and CO (g) when they reach equilibrium.

Then the equilibrium concentrations of CO (g) and H2 (g) are equal to x. Hence, the equilibrium concentration of H2O (g) is (0.500 - x) M. Substitute these values in the expression for Kc and solve for x.

Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]

= 0.2[CO (g)] = Kc [H2O (g)] [C (s)] / [H2 (g)]

= 0.2 × (0.500 - x) / x

We can simplify this expression by cross-multiplication to get:

5x = 0.1 - 0.2xx = 0.02 M

Substituting x = 0.02 M in the expression for [CO (g)], we get:

[CO (g)] = 0.2 × (0.500 - 0.02) / 0.02 = 5.8 M (approx.)

Therefore, the concentration of CO (g) in an equilibrium mixture (in mol/L) is 5.8 M.                                                                                               The problem requires us to find the equilibrium concentration of CO (g) in a mixture that initially contains only reactants.

To solve this problem, we need to use the expression for the equilibrium constant Kc, which is given by:

Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]

We can also use the ICE table method to solve this problem. In this method, we start with the initial concentration of the reactants and calculate the change in concentration of each species as they reach equilibrium.

We then use the equilibrium concentrations to calculate the value of Kc and solve for the unknowns. Here is how we can set up the ICE table for this problem: Reaction:

C(s) + H2O(g) ⇄ CO(g) + H2(g)

Initial: [C] = [H2]

= 0 M,

[H2O] = 0.500 M

Equilibrium: [C] = [H2] = x,

[H2O] = 0.500 - x,

[CO] = [H2] = x

Change: +x +x -x -x

Substituting the equilibrium concentrations into the expression for Kc, we get:

Kc = [CO] [H2] / [H2O] [C]

= x² / (0.500 - x)

= 0.2

Solving for x, we get: x = 0.020 M

Substituting this value of x into the expression for [CO], we get:

[CO] = x = 0.020 M

Therefore, the concentration of CO (g) in the equilibrium mixture is 0.020 M.

In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.

The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.

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Answer:

Saturated alkyne

Explanation:

The hydrocarbons are known as the compounds which is made up of only carbon and hydrogen atoms. They may be saturated or unsaturated based on the number of bonds present. The molecule H-C≡C-H is an Unsaturated alkyne. The correct option is B.

The hydrocarbons in which the carbon and hydrogen atoms are connected through double or triple bonds are known as unsaturated hydrocarbons. Here ethyne is an unsaturated hydrocarbon.

Ethyne is an alkyne which have the C-C  and C-H atoms connected through triple and single bonds.

Thus ethyne is option B.

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Answer:

Isotopes.

Explanation:

Atoms of the same element that have different numbers of neutrons but the same number of protons are called Isotopes.

When 32.6 ml of 0.100 M barium hydroxide is mixed with 166.5 ml of 0.200 M hydrochloric acid, the reaction goes to completion. The pH of the solution is 0.8643

The given balanced chemical reaction can be represented as: Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

The mole of Ba(OH)₂ and HCl are calculated as follows:

Ba(OH)₂ = 0.0326 L × 0.100 M = 0.00326 mole

HCl = 0.1665 L × 0.200 M = 0.0333 mole

Ba(OH)₂ is the limiting reagent because of the lesser amount of its mole as compared to the mole of HCl. Therefore, the moles of Ba(OH)₂ left after the reaction are zero. And moles of HCl consumed are twice the mole of Ba(OH)₂ consumed = 2 × 0.00326 mole = 0.00652 mole

The initial concentration of HCl = 0.200 M.

Hence, the concentration of HCl after the reaction = {0.0333 - 0.00652} / 0.1991 = 0.1365 M

The concentration of H+ is equal to the concentration of HCl after the reaction because HCl completely ionizes to give H+ and Cl- in the reaction.

The pH is given as pH = -log[H+]= -log(0.1365)= 0.8643

Therefore, the pH of the solution is 0.8643.

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About the nuclear chemistry unit test. The test typically covers topics like radioactive decay, nuclear reactions, half-life, and uses of radioisotopes in various applications.

To excel in the test, ensure you understand these concepts, practice relevant problems, and review class notes or textbook material. However, providing specific answers is not appropriate, as learning and comprehending the subject is crucial for academic growth.

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A particular reaction is expected to yield 125 g of calcium, the actual amount of calcium obtained is equal to 105 g, the percentage yield for the reaction is 84%.

The actual yield is calculated as the theoretical yield divided by the theoretical yield multiplied by 100. It can cause a chemical reactions actual yield to be lower than its theoretical yield.

Utilizing the formula percent yield = actual yield/theoretical yield x 100, we can determine the yield percentage.

Expected yield = 125grams

Obtained yield = 105grams

% yield = (Obtained yield /Expected yield  ) × 100

% yield  = (105/125) X 100 = 84%.

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The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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To neutralize all the phosphoric acid, you would need to weigh out a certain amount of sodium carbonate. The balanced equation for the reaction between phosphoric acid (H₃PO₄) and sodium carbonate (Na₂CO₃) is:

2 H₃PO₄ + 3 Na₂CO₃ → 6 H₂O + Na₃PO₄ + 3 CO₂

To determine the amount of sodium carbonate needed, we need to consider the weight percentage of H₃PO₄ and the stoichiometric ratio between H₃PO₄ and Na₂CO₃.

To calculate the amount of sodium carbonate needed to neutralize all the phosphoric acid

1. Calculate the amount of H₃PO₄: If the phosphoric acid is 85% H₃PO₄ by weight, this means that 85 grams of every 100 grams of the acid is H₃PO₄. Therefore, if we have a certain mass of phosphoric acid, we can determine the mass of H₃PO₄ by multiplying it by 0.85.

2. Convert the mass of H₃PO₄ to moles: To determine the stoichiometric ratio between H₃PO₄ and Na₂CO₃, we need to convert the mass of H₃PO₄ to moles. This is done by dividing the mass of H₃PO₄ by its molar mass, which can be calculated by adding the atomic masses of hydrogen (H), phosphorus (P), and oxygen (O) in H₃PO₄.

3. Use the stoichiometric ratio: From the balanced equation, we can see that 2 moles of H₃PO₄ react with 3 moles of Na₂CO₃. This means that the stoichiometric ratio between H₃PO₄ and Na₂CO₃ is 2:3.

4. Calculate the amount of Na₂CO₃: Multiply the moles of H₃PO₄ by the stoichiometric ratio. This will give us the moles of Na₂CO₃ needed to neutralize the given amount of H₃PO₄.

5. Convert moles to grams: Finally, multiply the moles of Na₂CO₃ by its molar mass to calculate the mass of Na₂CO₃ needed.

By following these steps, we can determine the amount of sodium carbonate (Na₂CO₃) that should be weighed out to neutralize all the phosphoric acid.

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Answer:

an element os3a material that consists of a single type of atom each type contains the same number of protons.

Answer:

.2 M

Explanation:

grams/molar mass=ans./volume(L)=molarity

5.6/56=ans./.500=.2 M

- Hope that helps! Please let me know if you need further explanation.

This statement is partially correct. The CO2 volume in an open can of soda depends on various factors such as the initial carbonation level of the soda, the temperature, and the atmospheric pressure.

When a can of soda is opened, the pressure inside the can is no longer confined, and the CO2 gas escapes from the liquid to the atmosphere until equilibrium is reached. The amount of CO2 that escapes depends on the initial carbonation level of the soda, which varies depending on the brand and type of soda.

Moreover, temperature plays a crucial role in determining the amount of CO2 gas that remains dissolved in the liquid. At higher temperatures, the solubility of CO2 in liquids decreases, leading to a decrease in the CO2 volume.

Lastly, the atmospheric pressure also affects the amount of CO2 gas that remains in the soda. At lower atmospheric pressures, such as at higher elevations, the solubility of CO2 in liquids decreases, which can result in a decrease in CO2 volume.

Therefore, the statement that an open can of soda at 25 ∘C will have a CO2 volume of approximately 0.04 y is an oversimplification, and the actual CO2 volume will depend on various factors.

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Answer: The second one

Explanation: Color works by specific light wavelengths reflecting off surfaces and reaching our eyes. If the red light is absorbed it can't reach our eye cones and we won't be able to see it.

Answer:

8.15 L I2

Explanation:

So, I have the balanced equation of:  2CuBr2 +4KI  →  2CuI   +   4KBr   + I2

Now, we do:  

241.6g  /  1 mol KI  /  1 mol I2  /  22.4 L

---------------------------------------------------------  =   8.15 L I2

           /  166g KI  /   4 mol KI  /   1 mol I2

Hope this helps! ^u^

Metallic elements exist in a solid-state and they are opaque, have a shiny surface, good conductors of electricity and heat, malleable and ductile, and are dense. The structure of metals is formed by atoms that are held together by metallic bonds. These atoms have loosely bound valence electrons that can be shared between the neighboring atoms.

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Answer:

String a piece of twine between the cups. Use a long piece of string to help the sound travel farther. Tie a knot in the end of the string to keep it in the cup. Decorate the cups if desired. One person can hold the phone up to their ear and the other person can talk into the other cup. Keep the string tight or the sound waves won’t travel.

Explanation:

Answer:

nitric acid anhydride

OR

Dinitrogen pentaoxide

The name of N4O10 is Tetranitrogen decaoxide.

In order to name this compound, we have to consider the number of atoms of each element in the compound.

Looking at the compound, we can see that there are four nitrogen and ten oxygen atoms. Nitrogen is an element in group 15 of the periodic table and has five valence electrons. Oxygen is an element in group 16 of the periodic table and has six valence electrons. These two elements combine to give tetranitrogen decaoxide (N4O10).

Hence, the accurate name of the compound is tetranitrogen decaoxide.

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Answer:

1.993 × 10^(24) moles

Explanation:

From avogadro's number, we have that;

1 mole of atoms contain 6.022 × 10^(23) atoms

Therefore, 1.2 x 10^(48) atoms of copper will contain;

(1.2 x 10^(48) × 1)/(6.022 × 10^(23)) = 1.993 × 10^(24) moles

Answer:The empirical formula is

C

4

H

11

O

2

.

Explanation:First, we calculate the masses of

C

and

H

from the masses of their oxides (

CO

2

and

H

2

O

).

Mass of C

=

1.900

g CO

2

×

12.01 g C

44.01

g CO

2

=

0.5185 g C

Mass of H

=

1.070

g H

2

O

×

2.016 g H

18.02

g H

2

O

=

0.1197 g H

Mass of C + Mass of H

=

0.5185 g + 0.1197 g

=

0.6382 g

This is less than the mass of the sample.

The missing mass must be caused by

O

.

Mass of O = 0.9827 g - 0.6382 g = 0.3445 g

Explanation:

They allow the bonds between oxygen and hydrogen to be single. They increase the partial positive charge on the oxygen atom. They counter the uneven pull on electrons between the atoms.

The claim that the atomic model should not be continually changed is based on the principle of scientific stability and coherence. Continually changing the atomic model can undermine the stability of scientific understanding and impede the development of robust theories.

The claim that the atomic model should not be continually changed is based on the principle of scientific stability and coherence. Continually changing the atomic model can undermine the stability of scientific understanding and impede the development of robust theories. The current atomic model, based on quantum mechanics and the understanding of subatomic particles, has provided a consistent framework that has successfully explained and predicted numerous phenomena. This model has undergone rigorous testing, verification, and refinement over the years. While scientific progress and new discoveries are essential, it is important to maintain a balance between incorporating new evidence and maintaining a stable foundation. Frequent changes to the atomic model can lead to confusion and make it difficult to build upon existing knowledge. It is preferable to refine and expand upon the current model as new evidence emerges, rather than discarding it entirely. This approach ensures continuity and progress in scientific understanding while maintaining a coherent framework for further exploration.

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The Kc of the reaction is obtained as 0.013.

We know that the Kc can be obtained form the formula;

a = √Kc/C

Where;

a = the percent dissociation

Kc = dissociation constant

C = concentration

The number of moles of the nitrosyl chloride =  1.50 g/65 g/mol

= 0.023 moles

Concentration of the nitrosyl chloride = 0.023 moles/1.00 liter

= 0.023 M

Then we would have

Kc = Ca^2

Kc = 0.023 * 0.572

Kc = 0.013

The percent dissociation of the compound would be seen to be 0.013.

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To find the number of moles in 4.50g of Zn, we need to use the molar mass of Zn which is 65.38 g/mol.

First, we can calculate the number of moles using the formula:

moles = mass / molar mass

Substituting the given values, we get:

moles = 4.50 g / 65.38 g/mol

moles = 0.0689 mol

Therefore, there are 0.0689 moles in 4.50g of Zn.