Answer:
.
Explanation:
F = kx so k = 800/((10-5)/100) = 16000 N/m
W = 1/2 kx^2 = 1/2 * 16000 * .05^2 = 20 J.
(sorry if it's wrong)
n unit-vector notation, what is the torque about the origin on a particle located at coordinates (0, −4.0 m, 3.0 m) if that torque is due to (a) force F1 with components F1x = 2.0 N, F1y = F1z = 0, and (b) force F2 with components F2x = 0, F2y = 2.0 N, F2z = 4.0 N?
n unit vector notation, -22j is the torque about the origin on a particle located at coordinate (o, -4.0m, 3.0m)
Torque is defined as the force that can cause an object to rotate along an axis is measured as torque. Estimate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin.
T=R (distance) x F (Force)
R=-4j+3k
F=2J
Hence, t= R x F vector product
=(-4j+3k)x2j
=-4x2x(y x J)
=+3x2y(k x r)
=-8x(-k)+6j
=(6j+8k) nm
b) F^2=2J+4K
Hence, t=r x f^2
=(-4j+3k)x(2j+4k)
=0-16( J x k)+6(K x J)+0
=-16j-6j
=-22j
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When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
Answer:
When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
A swimmer swims the length of a 50-meter pool, swims back to their starting point, and finally swims back to the opposite side again.
What is their overall displacement?
What total distance did they swim?
SHOW YOUR WORK or explain your answer.
The distance that is covered is 150 m
The displacement is 50 m.
What is the displacement?We have to know that the displacement has to do with the distance that is covered in a specific direction. We have to take note of the direction that we have there as that is what does make the difference between the distance and the displacement.
The distance does not involve the direction. It can then be safe to say that displacement is a vector and that distance is a scalar. Once again let us recall that these are so because the distance does not take cognizance of the direction while the displacement would always take cognizance of the direction of the motion.
Then we have;
Distance = 50 m + 50 m + 50 m = 150 m
For displacement calculation;
Moving towards the opposite side and back = 50 m - 50 m = 0 m
Moving again to the opposite side;
Displacement = + 50 m
Note that the backward motion of the swimmer would be taken as negative.
Therefore total displacement = 50 m
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A man attempts to move a truck by pushing it, but he can't move it. Describe the work done by the man.
If a man tried to move a truck by pushing it, but he is not able to move it, then the work done by the man will be equal to zero.
What is Work?In physics, the word "work" involves measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied with in the direction of the displacement. The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given question,
The man tries to move the truck, but he is not able to move. It means that the total displacement is zero, which means according to the formula of work done the work is also zero.
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A bicycle has a mass of 39.5 kg on earth. What would its weight be on the moon ( g Moon = 1.6 N/KG
So, if the object is on the Moon, its weight will be 63.2 N.
IntroductionHi ! This time I will help you to discuss the weight of objects. Weight is not mass, because weight is affected by the acceleration of gravity. As for the mass of an object, its value will never change, whether in one place, another place, another planet, or even in outer space. The relationship between weight, mass, and gravitational acceleration can be formulated in the equation:
\( \boxed{\sf{\bold{w = m \times g}}} \)
With the following condition :
w = weight of the object (N)m = mass of the object (kg)g = acceleration of the gravity (m/s² or N/kg)Problem SolvingWe know that :
m = mass of the object = 39.5 kgg = acceleration of the gravity = 1.6 N/kgWhat was asked :
w = weight of the object = ... NStep by step :
\( \sf{w = m \times g} \)
\( \sf{w = 39.5 \times 1.6} \)
\( \boxed{\sf{w = 63.2 \: N}} \)
ConclusionSo, if the object is on the Moon, its weight will be 63.2 N.
See MoreWhich statements about surface gravity are true? https://brainly.com/question/26403335Match each action with the object that is primarily responsible for causing that action https://brainly.com/question/26403275An object is dropped from an unknown height. If it falls for 12.0s, how far
does it fall? (g = -9.81 m/s²)
O-706 m/s²
O -706 m/s
O -706 m
O-706 s
Question 7
4.1 pts
Answer:
706 m
Explanation:
Since distance is measured in meters (Standard Issued Units) the answer would be 706 m and not any other value.
What does the top pressure gauge in (Figure 1) read? Express your answer using two significant figures.
Digital manometers can be used to measure liquids, gases, and air, depending on the device. If the instruments have an internal memory, it works quite well.
What does the top pressure gauge indicate?Pressure Gauge in Psig Pressure as a percentage of the surrounding atmospheric pressure. The gauge pressure for this kind of pressure includes the pressure from the weight of the atmosphere because it is zero-referenced against atmospheric pressure.
These gauges typically have a measurement range of 0… 1 mbar to 0… 600 mbar and an accuracy class of 0.1 to 2.5. Although pressure gauges typically require very minimal upkeep, problems can happen.
Therefore, This tool can be used to measure pressure in a variety of locations. Measurements of negative pressure, overpressure, and differential pressure are all possible.
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What is likely to occur after a lava flow has destroyed all life in a natural community?
A:growth of opportunist species
B:climax community
C:primary succession
D:secondary succession
Answer:
C: primary succession
Explanation:
I took the test :)
Identify the different types of costs that must be identified and quantified to do aggregate planning. (Check all that apply.) -Inventory holding cost
- Subcontracting cost
- Regular production cost
- Hiring cost
- Backorder/lost sales cost
- Overtime cost
- Firing/layoff cost
The four relevant costs related to the aggregate production planning involves:
inventory holding costs,Regular production costOvertime costBackorder/lost sales cost.What is aggregate planning?Aggregate planning is a method for creating a comprehensive manufacturing plan that ensures continuous production at a facility. Aggregate production planning is typically applied over a three to eighteen-month period. It is the activity of matching output supply with demand over a medium time span using information derived from inventory levels.
This ultimately implies that aggregate planning is a strategic technique used by organizations to make an aggregate plan for their manufacturing (production) process ahead of time, in order to have an idea of the level of goods to be produced and what resources are required so that the total cost of production is kept to a bare minimum.
Production and inventory costs are the two major cost categories required as inputs for aggregate planning. Production costs include regular and overtime labor costs, costs of subcontracting production, costs of changing capacity by hiring or laying off workers, and costs of increasing or decreasing machine capacity.
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A frictionless plane is 10.0 m long and inclined at 36.0°. A sled starts at the bottom with an initial speed of 6.00 m/s up the incline. When the sled reaches the point at which it momentarily stops, a second sled is released from the top of the incline with an initial speed Vi. Both sleds reach the bottom of the incline at the same moment.
(a) Determine the distance that the first sled traveled up the incline. m
(b) Determine the initial speed of the second sled. m/s
Use the equation for the position of the second sled as a function of time to find the speed that makes it reach the bottom of the slope in the same time that the first sled takes to slide back down.
If a frictionless plane is 10.0 m long and inclined at 36.0°.
The sled traveled 8.17 m up the incline.The initial speed of the second sled is about 5.68 m/sHow to find the initial speed?We can use conservation of energy to find the distance that the first sled travels up the incline. The potential energy of the sled at the bottom of the incline is zero, and its kinetic energy is:
KE = (1/2)mv^2
where m is the mass of the sled and v is its speed. At the point where the sled stops, all of its kinetic energy has been converted into potential energy, so we can write:
mgh = (1/2)mv^2
where h is the height that the sled has traveled up the incline. Solving for h, we get:
h = (v^2)/(2g)
where g is the acceleration due to gravity. Using the given values, we have:
h = (6.00 m/s)^2 / (2 * 9.81 m/s^2) = 1.83 m
So the first sled travels a distance of 10.0 m - 1.83 m = 8.17 m up the incline.
b. To find the initial speed of the second sled, we can use conservation of energy again. At the top of the incline, the sled has potential energy:
PE = mgh
where h is the height of the incline. As the sled slides down the incline, its potential energy is converted into kinetic energy:
KE = (1/2)mv^2
where v is the speed of the sled at the bottom of the incline. We can equate these two expressions and solve for v:
mgh = (1/2)mv^2
v = sqrt(2gh)
Using the given values, we have:
v = sqrt(2 * 9.81 m/s^2 * 10.0 m * sin(36.0°)) = 12.2 m/s
So the second sled must be released from the top of the incline with an initial speed of 12.2 m/s.
The position of the sled as a function of time is given by:
y = -0.5gt^2 + Vi*t + h
where y is the vertical position of the sled, t is the time, Vi is the initial speed of the sled, and h is the height of the incline. At the bottom of the incline, y = 0, so we can solve for the time it takes for the second sled to reach the bottom:
0 = -0.5gt^2 + Vi*t + h
t = (Vi ± sqrt(Vi^2 - 2gh)) / g
Since we want both sleds to reach the bottom at the same time, we set the time for the first sled to slide down the incline equal to this expression for t and solve for Vi:
t = sqrt(2h/g) = sqrt(2 * 1.83 m / 9.81 m/s^2) = 0.619 s
0 = -0.5gt^2 + Vi*t + h
Vi = (h - 0.5gt^2) / t
Vi = (1.83 m - 0.5 * 9.81 m/s^2 * (0.619 s)^2) / 0.619 s
Vi = 5.68 m/s
So the initial speed of the second sled is about 5.68 m/s
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Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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In our solar system, which celestial object is known as the dwarf planet?
Answer:
unfournatletly
Explanation:
i have no clue sorry to waste ur time ill rather not say a answer that will be incorrect.
Answer:
Pluto
Explanation:
Pluto was part of our solar system till 2006In 2006 international scientific committee removed it from planets listIt's known as dwarf planet now6. What is the mass of a boy who is standing on top of a 1.5 meter high
wall and has 735 J of gravitational potential energy?
Answer:
m = 50 [kg]
Explanation:
The potential energy can be calculated by means of the following equation.
\(E_{p}=m*g*h\)
where:
Ep = potential energy = 735 [J]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1.5 [m]
Now replacing:
\(735=m*9.81*1.5\\m = 50 [kg]\)
A solid block is attached to a spring scale. When the block is suspended in air, the scale reads 20.1 N; when it is completely immersed in water, the scale reads 15.3 N.
A) What is the volume of the block?
B) What is the density of the block?
Answer:
A) \(V = 4.92 \cdot 10^{-4} m^{3} = 492 cm^{3}\)
B) \( d = 4181.49 kg/m^{3} = 4.18 g/cm^{3} \)
Explanation:
A) Using the Archimedes' force we can find the weight of water displaced:
\( W_{d} = W_{a} - W_{w} \)
Where:
\(W_{a}\): is the weight of the block in the air = 20.1 N
\(W_{w}\): is the weight of the block in the water = 15.3 N
\( W_{d} = W_{a} - W_{w} = 20.1 N - 15.3 N = 4.8 N \)
Now, the mass of the water displaced is:
\( m = \frac{W_{d}}{g} = \frac{4.8 N}{9.81 m/s^{2}} = 0.49 kg \)
The volume of the block can be found using the mass of water displaced and the density of the water:
\(V = \frac{m}{d} = \frac{0.49 kg}{997 kg/m^{3}} = 4.92 \cdot 10^{-4} m^{3} = 492 cm^{3}\)
B) The density of the block can be found as follows:
\( d = \frac{W_{a}}{g*V} = \frac{20.1 N}{9.81 m/s^{2}*4.92 \cdot 10^{-4} m^{3}} = 4181.49 kg/m^{3} = 4.18 g/cm^{3} \)
I hope it helps you!
A runner starts from rest and achieves a maximum speed of 8.85 m/s.
If her acceleration is 9.67 m/s2, how long does it take her to reach that speed?
Answer:
The appropriate answer is "0.9152 seconds".
Explanation:
The given values are:
Maximum speed,
v = 8.85 m/s
Acceleration,
u = 9.67 m/s²
Now,
⇒ \(v = u+at\)
By putting the values, we get
⇒ \(8.85=0+9.67t\)
⇒ \(t=\frac{8.85}{9.67}\)
⇒ \(=0.9152 \ second\)
Which best describes friction?
Answer:
It is the force that opposes motion between two surfaces touching each other. ( OR ) The force between two surfaces that are sliding or trying to slide across each other.
Explanation:
Answer:
a constant force that acts on objects that rub together
Explanation:
a constant force that acts on objects that rub together
Drag each label to the correct location on the image.
Match the government activities to the different fiscal policies.
government is spending
less than what it earns
budget indicates a surplus
budget indicates a deficit
government is spending
more than what it earns
Contractionary Fiscal Policy
government is spending more
on infrastructure development
Expansionary Fiscal Policy
Matching the government activities to the different fiscal policies.
Contractionary Fiscal Policy:
budget indicates a surplus
government is spending less than what it earns
Expansionary Fiscal Policy:
government is spending more on infrastructure development
budget indicates a deficit
government is spending more than what it earns
When the government is spending less than what it earns, it has a budget surplus. This indicates that the government is collecting more revenue than it is spending. This is an example of a contractionary fiscal policy because it reduces the amount of money circulating in the economy, which can help control inflation.
When the government is spending more than what it earns, it has a budget deficit. This indicates that the government is spending more money than it is collecting in revenue. This is an example of an expansionary fiscal policy because it injects more money into the economy, which can stimulate economic growth.
When the government is spending more on infrastructure development, it is an example of an expansionary fiscal policy because it increases government spending and stimulates economic growth.
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A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. What is the beaver’s mass?
A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the kinetic energy (KE) of an object that is KE = (1/2) ×m × \(v^2\).
KE = (1/2) ×m × \(v^2\).
where m= mass of the object, v=its velocity.
The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation
45 J = (1/2) ×m × \((2.0 m/s)^2\)
Simplifying this equation:
45 J = (1/2) × m × 4.0\(m^2/s^2\)
45 J = 2 m × 2 \(m^2/s^2\)
45 J = 4 \(m^3/s^2\)
\(m^3\) = 45 J / 4 \(s^2\)
\(m^3\) = 11.25 kg×\(m^2/s^2\)
Taking the cube root of both sides to solve for mass,
m = (11.25 kg×\(m^2/s^2)^(^1^/^3^)\)
m = 1.74 kg (rounded to two decimal places)
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Please help, I keep trying a bunch of things but keep getting them wrong. I don't know where I am going wrong here.
1. Boyle's Law states the volume and pressure of a gas are inversely proportional.
Name the three units of the constant of proportionality between pressure and volume in alphabetical order. (**I have the first two)
2. The ideal gas law can be written as (PV/nT=R). Name the units for R.
The units of the constant of proportionality between pressure and volume in alphabetical order are
1. Celsius (°C)
2. Fahrenheit (°F)
3. Kelvin (K)
The units for R, that is, the ideal gas constant are
1. J K⁻¹ mol⁻¹
2. L atm K⁻¹ mol⁻¹
We will start by completing the Boyle's Law stated
Boyle's Law states the volume and pressure of a gas are inversely proportional, provided that the temperature remains constant.
This means temperature is the constant of proportionality.
Now, we will name the three units of the constant of proportionality, that is, temperature. The units are
1. Degree Celsius (°C)
2. Degree Fahrenheit (°F)
3. Kelvin (K)
2. In the ideal gas equation (PV/nT=R), R represents the ideal gas constant.
The units for R, that is, the ideal gas constant are
1. J K⁻¹ mol⁻¹
2. L atm K⁻¹ mol⁻¹
Hence,
The units of the constant of proportionality between pressure and volume in alphabetical order are
1. Celsius (°C)
2. Fahrenheit (°F)
3. Kelvin (K)
The units for R, that is, the ideal gas constant are
1. J K⁻¹ mol⁻¹
2. L atm K⁻¹ mol⁻¹
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How large is the tension in a rope that is being used to accelerate a 100 kg box upward at 2m/s2?
\(\\ \sf\Rrightarrow T=F\)
\(\\ \sf\Rrightarrow T=ma\)
\(\\ \sf\Rrightarrow T=100(2)\)
\(\\ \sf\Rrightarrow T=200N\)
What is the world ? B
Answer:
World B. FreeAmerican professional basketball player
World B. Free is a retired American professional basketball player who played in the National Basketball Association from 1975 to 1988. Free was known as the "Prince of Mid-Air", "Brownsville Bomber", and most often as "All-World".Explanation:
sana makatulong ^^ (hope it helps)
The anomalous expansion characteristics of liquid water are crucial to many biological systems. Rather than an approximately constant value for the coefficient of volume expansion, the value for water changes drastically, as illustrated in the figure.
Below what temperature T
does water shrink when heated?
If the temperature of water at 30 ∘C
is raised by 1 ∘C
, the water will expand. At approximately what initial temperature T
will water expand by twice as much when raised by 1 ∘C
?
(A) The water will shrink when is heated above 4°C. (B).water at an initial temperature of 33.3°C will be expand by twice as much when it is raised by 1°C compared to water at 30°C.
The anomalous expansion of water refers to the fact that its volume increases upon cooling from 4°C to 0°C, and then contracts upon further cooling to 0°C, and continues to contract upon further cooling. Similarly, when water is heated, its volume first contracts until it reaches 4°C, and then expands upon further heating.
To determine at what temperature water shrinks when heated, we need to find the point at which the coefficient of volume expansion, β, becomes negative. The coefficient of volume expansion is defined as the fractional change in volume per degree Celsius change in temperature, i.e.,
β = (1/V) (dV/dT)
where V is the volume of the water and dV/dT is the rate of change of volume with respect to temperature.
At temperatures below 4°C, the coefficient of volume expansion is positive, indicating that water expands upon heating. However, at temperatures above 4°C, the coefficient of volume expansion becomes negative, indicating that water contracts upon heating.
Therefore, water will shrink when heated above 4°C.
To determine the initial temperature at which water will expand by twice as much when raised by 1°C, we can use the formula for the coefficient of volume expansion:
β = (1/V) (dV/dT)
We want to find the initial temperature T such that
(dV/dT)T = 2 (dV/dT)30
where (dV/dT)T is the rate of change of volume with respect to temperature at temperature T, and (dV/dT)30 is the rate of change of volume with respect to temperature at 30°C.
Using the coefficient of volume expansion for water, we have
β = 3α
where α is the coefficient of linear expansion, which is approximately constant for small temperature changes. Therefore, we can write
(dV/dT) = V × 3α
Substituting this into the equation above and simplifying, we get
T = 30 + 10/3 = 33.3°C
Therefore, water at an initial temperature of 33.3°C will expand by twice as much when raised by 1°C compared to water at 30°C.
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Sadly, the car crashed into a tree at a speed of 5 ms*'. It took 1.2 s for the car to come to a full stop. Calculate the force exerted on the tree. the car weighs 1600kg
Sadly, the car crashed into a tree at a speed of 5 ms*'. It took 1.2 s for the car to come to a full stop, then the force exerted on the tree would be 6666.67 N.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
By using the first equation of the motion,
v = u + at
0 = 5 + 1.2a
a = 5 / 1.2
a = 4.167 m / s²
The force exerted on the tree = 1600 × 4.167
= 6666.67 N
Thus, the force exerted on the tree would be 6666.67 N.
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Gold forms a solid solution with silver. Since the densities of pure gold and silver are 19.32 g/cm³ and 10.49 g/cm³, respectively, calculate the number of gold atoms per cubic centimeter for a silver-gold alloy containing 10% Au and 90% Ag by weight.
There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.
The density of a binary alloy can be calculated using the following equation:
ρ = w1ρ1 + w2ρ2
where,
ρ = density of the alloy
w1 and w2 = weight fractions of the two components (in this case, gold and silver)
ρ1 and ρ2 = densities of the pure components.
We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:
\(w_{Au}\) = 0.10
\(w_{Ag}\) = 0.90
We are also given the densities of pure gold and silver as:
ρ_Au = 19.32 g/\(cm^{3}\)
ρ_Ag = 10.49 g/\(cm^{3}\)
Now we can substitute these values into the density equation to find the density of the alloy:
ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag
ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))
ρ = 11.08 g/\(cm^{3}\)
Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.
To do this, we can use Avogadro's number and the atomic weights of gold and silver:
\(N_A\) = 6.022 × \(10^{23}\) atoms/mol
Aum = 196.97 g/mol
Agm = 107.87 g/mol
The number of gold atoms:
\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)
Substituting the values, we get:
\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol
\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)
Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.
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An electric motor is used to hoist building supplies from the ground to the roof of a building. How high can it lift a 131 kg bundle of shingles in that time?
The electric motor will lift the 131 kg bundle of shingles at a height of 14 m.
What is gravitational potential energy?Gravitational potential energy is the energy exhibited by an object because of a change in its position in the presence gravitational field.
The gravitational potential energy of an object at height h from the surface of the earth is given by:
\(U = mgh,\) where m is the mass of the object.
Given, the power of the electric motor, P = 1.5 KW, and time, t - 12 s
Power = Work/ time
Work = Power × time
Work = 1500 ×12 = 18000 J
Given, the mass of the object, m= 131 Kg
The gravitational potential energy, U = 18000J
The height of the bundle of shingles can be determined as:
18000 = 131 ×9.8 ×H
H = 14 m
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Your question was incomplete most probably complete question was,
An electric motor is used to hoist building supplies from the ground to the roof of a building. How much work can the motor do in 12 seconds if its power output is 1.5 kW. How high can it lift a 131 kg bundle of shingles in that time?
what is the statement of objectives in newton's second law using word to investigate, to plot,to compare, to measure
by changing the force and observing the impact on an object's acceleration, one can examine the link between force and acceleration.
What aims does Newton's second law of motion have?In conclusion, Newton's second law gives an explanation for how objects whose forces are out of balance behave. According to the law, when there are imbalanced forces acting on an item, the object will accelerate with an acceleration that is inversely proportional to the mass and directly proportional to the net force.
What is Newton's law supposed to achieve?The student should be able to relate the magnitudes of the various forces acting on an object to its state of motion, particularly the direction of acceleration. The pupil ought to be able to connect the net force.
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An elevator accelerates upward at 1.2 m/s
2
.
The acceleration of gravity is 9.8 m/s
2
.
What is the upward force exerted by the
floor of the elevator on a(n) 92 kg passenger?
Answer in units of N
Answer:
1012 N
Explanation:
There are two forces acting on the passenger.
Normal force N pushing up and weight force mg pulling down.
Apply Newton's Second Law:
∑F = ma
N − mg = ma
N − (92 kg) (9.8 m/s²) = (92 kg) (1.2 m/s²)
N = 1012 N
1. The resistance of an electric device is 40,000 microhms. Convert that measurement to ohms
2. When an electric soldering iron is used in a 110 V circuit, the current flowing through the iron is
2 A. What is the resistance of the iron?
3. A current of 0.2 A flows through an electric bell having a resistance of 65 ohms. What must be
the applied voltage in the circuit?
Answer:
(1) 0.04 ohms (2) 55 ohms (3) 13 volt
Explanation:
(1) The resistance of an electric device is 40,000 microhms.
We need to convert it into ohms.
\(1\ \mu \Omega =10^{-6}\ \Omega\)
To covert 40,000 microhms to ohms, multiply 40,000 and 10⁻⁶ as follows :
\(40000 \ \mu \Omega =40000 \times 10^{-6}\ \Omega\\\\=0.04\ \Omega\)
(2) Voltage used, V = 110 V
Current, I = 2 A
We need to find the resistance of the iron. Using Ohms law to find it as follows :
V = IR, where R is resistance
\(R=\dfrac{V}{I}\\\\R=\dfrac{110}{2}\\\\R=55\ \Omega\)
(3) Current, I = 0.2 A
Resistance, R = 65 ohms
We need to find the applied voltage in the circuit. Using Ohms law to find it as follows :
V=IR
V = 0.2 × 65
V = 13 volt
Answer:
1. 0.04 Ohms
2. 55 Ohms
3. 13 Volts
Explanation:
Penn Foster
A car accelerates from rest at a rate of 8.1 m/s2. How much time does it take the car to travel a distance of 65 meters?
Answer:
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Explanation:
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A 2.5kg rock is thrown off the top of a 18m tall building with a speed of 14m/s. How fast is it going the instant it hits the ground?
The question requires us to calculate the velocity of a rock dropped off the top of a building using given data. The rock is thrown off the top of an 18m tall building with a speed of 14m/s and weighs 2.5kg. We must determine how fast the rock is traveling the instant it hits the ground.
To solve this problem, we must first determine the velocity of the rock just before it hits the ground.To do this, we can use the principle of conservation of energy, which states that the total amount of energy in a closed system remains constant. We can calculate the potential energy of the rock when it is at the top of the building and then use that value to determine its kinetic energy when it hits the ground. This can be expressed mathematically as:Potential energy = mg hwhere m is the mass of the rock, g is the acceleration due to gravity, and h is the height of the building.Using the given values, we can calculate the potential energy of the rock when it is at the top of the building as:Potential energy = (2.5kg)(9.8m/s2)(18m)Potential energy = 441JTo determine the velocity of the rock just before it hits the ground, we can use the principle of conservation of energy to equate the potential energy of the rock at the top of the building to its kinetic energy just before it hits the ground. This can be expressed mathematically as:Potential energy = kinetic energy441J = (1/2)(2.5kg)v2where v is the velocity of the rock just before it hits the ground.Simplifying the equation, we get:v2 = (2)(441J) / (2.5kg)v2 = 352v = √(352)v = 18.7m/sTherefore, the rock is going 18.7m/s the instant it hits the ground.For such more question on velocity
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