The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Distance from spot shines = 12 m away
Height of man,h=2 m tall
Speed of man +1.6 m/s,
Distance from the building = 4 m
Let the height of shadow= y,
CD=x
Height of man=2 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
As the triangle ABD and ECD are similar. The property of the similarity is found as;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)
Differentiate the above question with respect to x;
\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)
From the given conditions the man is 4 m from the building the value of the remaining distance x is;
x=12-4
x=8 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
On putting all the values we get;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)
The speed of man when the length of his shadow on the building decreases when he is 4 m from the building;
\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)
Hence the value of the speed for the given conditions willl be 0.6 m/sec.
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an ideal carnot heat engine operates between 285 k and 460 k. what is its efficiency?
The efficiency of a Carnot heat engine is given by the formula: efficiency = (1 - T_cold/T_hot), where T_cold is the temperature of the cold reservoir and T_hot is the temperature of the hot reservoir.
In this case, the hot reservoir temperature is 460 K and the cold reservoir temperature is 285 K. So, the efficiency of the Carnot heat engine can be calculated as follows:
efficiency = (1 - 285/460) = 0.3804 or 38.04%
Therefore, the efficiency of the Carnot heat engine operating between 285 K and 460 K is 38.04%.
It is worth noting that the Carnot cycle is an idealized theoretical cycle and no real engine can achieve 100% efficiency. However, the Carnot cycle serves as a benchmark for the maximum theoretical efficiency that any heat engine can achieve.
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a thin film of water between individual soil grains acts to ___- the surface tension and ____ the shear strength.
A thin film of water between individual soil grains acts to reduce the surface tension and increase the shear strength.
The presence of water between soil grains helps to reduce the surface tension at the grain-water interface. Surface tension is the cohesive force between liquid molecules that tends to minimize the surface area.
When water is present in the form of a thin film between soil grains, it reduces the surface tension, making it easier for water to wet the soil particles and allowing for better water infiltration.
Additionally, the presence of water between soil grains increases the shear strength of the soil. Shear strength refers to the ability of a soil mass to resist deformation under applied shear stress.
The water-filled voids between soil grains act as lubrication, reducing the intergranular friction and allowing for smoother movement or sliding of grains against each other. This can increase the overall shear strength of the soil.
Overall, the thin film of water between soil grains decreases the surface tension, making it easier for water to interact with the soil particles, and increases the shear strength by reducing the intergranular friction.
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how long did it take the flag to rotate once in a full circle
Answer:
360 degrees is one full rotation starting at zero
it take 2 s to the flag to rotate once in a full circle with 3 rad/s of angular velocity.
What is Angular velocity and acceleration ?Angular velocity is "rate of change of angular displacement with respect to time". i.e. ω= dθ/dt. it is also defined as angular displacement over time. i.e. ω = angular displacement/Time.
Angular velocity shows how much angle can be covered in unit time. It's SI unit rad/s.
Angular acceleration is rate of change of Angular velocity with respect to time.
i.e. α = dω/dt if an object changes its angular velocity in short time, we can say that it has greater angular acceleration. It is expressed in rad/s².
In this problem we have to calculate time, but the angular velocity id not given.
Consider the angular velocity is 3 rad/s.
Given,
Angular displacement θ = 2π
angular velocity ω = 3 rad/s
Time t = ?
Time = θ/ω
Time = 2π/3 rad/s = 2 s
Hence the answer is 2s.
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En el proceso de diseño de ingeniería, ¿qué limitaciones deben tenerse en cuenta al utilizar un modelo / prototipo?
Answer:
Las limitaciones de un modelo o prototipo son;
1) Los parámetros ambientales (donde se opera el modelo, prototipo o producto) son diferentes y, por lo tanto, pueden producir relaciones y factores ambientales que serán diferentes de los factores ambientales y las relaciones del objeto real.
2) El análisis del problema puede ser inadecuado
3) La posibilidad de falta de satisfacción del cliente con un modelo, preferencia por la demostración real del producto.
4) Reproducción inexacta del entorno del producto durante la prueba del modelo
5) El factor de costo del modelo
6) Mayor complejidad introducida por el modelo / prototipo al análisis de la solución
Explanation:
El modelo o prototipo es la presentación del diseño articulado, construido para demostrar el producto real con el propósito de encontrar la existencia de errores en el diseño que serían corregidos, antes de que se realice la producción real
In Millikan's experiment, an oil drop of radius 1.96 Um and density 0.854 g/cm is suspended in chamber C (see the figure) when a downward electric field of 2.36 x 105 N/C is applied. Find the charge on the drop, in terms of e.
Millikan's experiment measured the charge of an electron by suspending an oil drop in an electric field. The charge on the oil drop can be calculated using the equation q = 4πεor2 E, where εo is the permittivity of free space, r is the radius of the oil drop and E is the electric field.
Plugging in the values given, we get q = 1.49x10-19 C which is equivalent to 0.93 e.
1. The electric field (E) and the radius of the oil drop (r) are given.
2. The charge on the drop (q) can be calculated using the equation q = 4πεor2 E, where εo is the permittivity of free space.
3. Plugging in the values given, we get q = 4π(8.85x10-12) (1.96x10-6)2 (2.36x105) = 1.49x10-19 C.
4. As the charge on the drop is given in terms of e, the charge is equal to 1.49x10-19/1.6x10-19 = 0.93 e.
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what is wg , the work done on the block by the force of gravity as the block moves a distance l up the incline? express the work done by gravity in terms of the weight w and any other quantities given in the problem introduction.
Work done on the block by the force of gravity as the block moves a distance L up the incline is - m*g*l*sinФ.
To move an object, it should be first transferred to energy. Transferring energy may be in the method of force. The quantity of energy transferred by the force to move an object is known as work done.
To express mathematically, work is equal to the force times the distance W = fd.
If force is exerted at an angle θ to the displacement then the work done is given by W = fd cos θ
Given,
applied force=F
angle=Ф
We have to evaluate work done by the force due to gravity,
We know that g= 9.8 m/s^2
Work done= m*g* sinФ * l *cos 180° +m*g* l *cos 90°
w = -m*g* sinФ* l + m*g *cosФ* l *0
As we know, cos 180° = -1
and cos 90° = 0
w = - m*g*l*sinФ
Hence, the work done on the block by the force of gravity as the block moves a distance L up the incline= - m*g*l*sinФ
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What is the speed of a wave that has a frequency of 110 Hz and a wavelength
of 0.21 m?
OA. 23.1 m/s
OB. 0.04 m/s
O C. 523 m/s
OD. 0.002 m/s
The speed of the wave of wavelength 0.21 m is 23.1 m/s. And the correct answer is 0A. 23.1 m/s.
How to calculate the speed of a wave?The speed of a wave is calculated by multiplying the wavelength and the frequency of the wave.
To calculate the speed of the wave, we use the formula below.
Formula:
s = λf......................................Equation 1Where:
s = Speed of the waveλ = Wavelength of the wavef = Frequency of the waveFrom the question,
Given:
f = 110 Hzλ = 0.21 mSubstitute these values into equation 1
s = 110×0.21s = 23.1 m/sHence, the speed of the wave is 23.1 m/s.
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Maximize points by completing the tasks correctly on first attempt. Incorrect responses incur a 2 point penalty per attempt. Calculate the distance and luminosity of Dargo in the following units: Distance meters Luminosity watts L s
Calculate the luminosities, in L s
, of the other stars.
No, without additional information such as apparent magnitude or spectral type, it is not possible to accurately calculate the distance and luminosity of Dargo or the luminosities of other stars.
Can the distance and luminosity of Dargo be calculated without additional information?In order to calculate the distance and luminosity of Dargo, we need additional information such as the star's apparent magnitude, spectral type, or any other relevant data. Without this information, it is not possible to provide accurate calculations for the distance and luminosity of Dargo or the luminosities of other stars.
Distance in astronomy is typically measured using units such as parsecs (pc) or light-years (ly). Luminosity, on the other hand, is a measure of the total amount of energy emitted by a star per unit time and is usually expressed in units of watts (W) or solar luminosities (L☉).
To calculate the distance to a star, methods such as parallax measurements or spectroscopic parallax can be used. These methods rely on observations and measurements of the star's apparent position or characteristics to determine its distance from Earth.
Luminosity can be calculated using various methods, including the star's temperature, radius, and the Stefan-Boltzmann law, which relates the luminosity of a star to its temperature and radius.
Without specific data or parameters for Dargo or other stars, it is not possible to provide accurate calculations for their distances or luminosities.
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A student is creating a model of a concave lens. The diagram shows her incomplete model.
Which action would best complete her model?
A
The student should draw the light moving into the lens and then exiting in converging lines.
B
The student should draw the rays of light moving into the lens and then exiting at right angles.
C
The student should draw the rays of light moving into the lens and then exiting in a straight path.
D
The student should draw the light moving into the lens and then exiting in lines that are spreading out.
Answer:
D
Explanation:
I’m pretty sure it’s correct but I don’t really know. Just trying to pass science
Answer:
The correct answer is D trust me I did the test
When the concave lens moves in it exit by spreading out like water
The force that the left team pulls with is 1000 N. If the right team's total mass is 300 kg and they accelerate by 1.2 m/s2, what is the force of resistance on the right team
Answer:
the force of resistance on the right team is 360 N
Explanation:
Given;
force of the left team, = 1000 N
total mass of the right team, m = 300 kg
acceleration of the right team, a = 1.2 m/s²
The force of resistance of the right team is calculated as;
Force = mass x acceleration
Force, F = 300 x 1.2
Force = 360 N
Therefore, the force of resistance on the right team is 360 N
a 1,200 kg car can accelerate with a force of 3,000n. if the car is stopped at a red light and then accelerates for 15 s after the light turns green, how far (in m) will the car be from the light?
Acceleration: the rate at which the speed and direction of a moving object vary over time.A point or object going straight ahead is accelerated when it accelerates or decelerates.
Find the Acceleration ?Three different accelerated motion types exist: average acceleration, non-uniform acceleration, and uniform acceleration.
a = F / m
1 N = 1 kg•m/s²
F = ma; where F = force in newtons (N), m = mass in kg, and a = acceleration in m/s².
Known and Unknown
F = 3000 N = 3000kg•m/s²
m = 1200 kg
a = F/m
a = (3000 kg•m/s²)/(1200 kg)
Kilograms cancel.a = 2.5m/s²
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Describe 2 potential problems or limitations of ratio
analysis.
A ball is thrown horizontally at a speed of 24 meters per second from the top of a cliff. If the ball hits the ground 4.0 seconds later, approximately how high is the cliff? I NEED HELP FOR THIS QUIZ LOL
Answer:
78.4m
Explanation:
In these situations, vertical and horizontal components need to be considered separately;
So, horizontal speed is irrelevant since we are talking about vertical height, i.e. the height of the cliff;
But, the fact that the speed is horizontal is relevant because this means the vertical speed initially is 0m/s;
The downwards movement of the ball is due to gravity, which is 9.8m/s²;
The time is given as 4.0s from the top of the cliff to the bottom;
We know the acceleration, time and initial speed so we can use this kinematic equation to solve for distance:
s = ut + ¹/₂at²
s = displacement (/distance)
u = initial vertical velocity = 0
t = time (time taken for the ball to fall) = 4
a = acceleration (downwards) = 9.8
Substitute these values into the equation to get the distance:
s = 0(4) + ¹/₂(9.8)(4)²
s = 78.4m
The ratio of the magnitude of the frictional force to the magnitude of the force
holding two surfaces together is called the and its UNIT is
Answer: the coefficient of friction
Explanation:
The coefficient of friction (μ (mu)) has no unit because it is a ratio of forces so the units of N (newtons, which are the units of force) cancel out.The magnitude of frictional force is \(\mu\)N and the magnitude of the force is N. So if we take the ratio of it we will get \(\mu\) In result.
What is the Coefficient of friction?The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them. Typically, the Greek letter is used to symbolize it, i.e., \(\mu\). In mathematical terms, is equal to F/N, where F represents frictional force and N represents normal force. Since both F and N are measured in units of force, the coefficient of friction is a dimensional less quantity (such as newtons or pounds).
For both static and kinetic friction, the coefficient of friction has a range of values. When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. In kinetic friction, the frictional force resists the motion of the object.
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Which statement describes how chemical formulas, such as H20, represent compounds?
Answer:
They show the elements that make up a compound.
They show the three-dimensional shape of a molecule.
They show the types of atoms that make up a molecule.
They show the number of each type of atom in a molecule.
Explanation:
❣️(◍Jess bregoli◍)❣️#keep learning!!
Explain why we draw straight lines to show rays of light.
Suppose of electrons must be transported from one side of an electrochemical cell to another in minutes. Calculate the size of electric current that must flow.
1605 amperes of electric current would need to flow to transport 1 mole of electrons in 1 minute.
To calculate the size of electric current that must flow to transport a given number of electrons, we need to use Faraday's law of electrolysis, which states that the amount of charge (Q) needed to transport a given number of electrons is proportional to the number of electrons (n) and the charge on a single electron (e):
Q = n * e
We can rearrange this equation to solve for the number of electrons:
n = Q / e
To determine the electric current required to transport a given number of electrons in a certain amount of time, we need to use the equation:
I = Q / t
where I is the electric current, Q is the amount of charge, and t is the time.
Using Faraday's law, we can calculate the amount of charge required to transport 1 mole of electrons:
Q = n * e = (6.02 × \(10^{23\)) * (1.6 × \(10^{-19}\)) ≈ 9.63 × \(10^4\) coulombs
Using the equation for electric current, we can calculate the size of the current required to transport this amount of charge in 1 minute:
I = Q / t = (9.63 × \(10^4\)) / 60 ≈ 1605 amperes.
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A man pushes a box across a floor. as he increases the force he applies horizontally to the box
a) the kinetic friction decreases
b) the kinetic friction may increase or decrease depending on the velocity of the box
c) the kinetic friction remains the same
d) the kinetic friction increases
When a man pushes a box across a floor, as he increases the force he applies horizontally to the box, then the kinetic friction remains the same.
To find the answer, we need to know about friction.
What is friction?Whenever a body moves, over the surface of another body, a force comes into play which acts parallel to the surface of contact and opposes the relative motion. This opposing force is called friction.There are two frictions acting on a surface.Static friction: It come into play between two bodies before when it starts moving. Self-adjusting force and the max value of it is called limiting static friction.Kinetic friction: It come into play between two bodies when it starts moving. It is not a self-adjusting force.As we increase applied force, kinetic friction will remain same.Thus, we can conclude that, kinetic friction remains the same when we increase the applied force.
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As a guy pushes a box across a floor, the kinetic friction stays constant no matter how much force is applied on the box horizontally.
We must understand friction if we are to find the solution.
Describe friction?A force that works parallel to the surface of contact and opposes the relative motion is always present whenever a body moves over the surface of another body. Friction is the name for this opposing force.On a surface, there are two frictions operating.Static friction: It occurs between two bodies before motion is initiated. Limiting static friction is the term used to describe the maximum amount of self-adjusting force.As soon as two bodies begin to move, kinetic friction is triggered. It is not a force that adjusts itself.The amount of kinetic friction will not change when we apply more force.We can therefore draw the conclusion that kinetic friction does not change as the applied force is increased.
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A hiker tries to prepare a hard-boiled egg on the high slopes of Mount Everest. The base camp is located 5,300 meters above sea level. The hiker observes that the water begins to boil at 82⁰C, much lower than the 100⁰C needed to cook the raw egg. He hopes that just leaving the egg in the boiling water longer will let the egg cook. Will he have hard-boiled eggs for breakfast?
Answer: :’)
Explanation:
A mass of 4.5 kg is attached to a spring with spring constant 0.5 N/m. The mass-spring system is hooked to a machine that applies a driving force to the mass that is equal to f(t)=5sin3t Newtons. The displacement of the mass-spring system from the spring equilibrium is measured to be 0.4 m, the mass having no initial velocity. Assume that there is no air resistance. Find the position of the mass as a function of time.
The position of the mass as a function of time is given by x(t) = 0.4sin(3t + φ), where φ is the phase constant.
In this mass-spring system, the driving force applied to the mass is given by f(t) = 5sin(3t) N. The equation of motion for a mass-spring system without air resistance is given by the second-order linear differential equation:
\(m * d^2x/dt^2 + k * x = f(t)\)
where m is the mass (4.5 kg), k is the spring constant (0.5 N/m), and x(t) represents the displacement of the mass from the equilibrium position.
To solve the equation, we assume the solution to be of the form x(t) = A * sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase constant. Substituting this solution into the equation of motion and comparing the coefficients of sin(ωt) on both sides, we can determine the values of A and φ.
Given that the displacement of the mass is 0.4 m, we can deduce that A = 0.4. The angular frequency ω is determined by ω = sqrt(k / m).
Plugging in the given values of k and m, we get ω = sqrt(0.5 / 4.5). With these values, we can now express the position of the mass as a function of time:
x(t) = 0.4sin(ωt + φ)
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8. An object has a force applied. The object has a mass of 36 Kg and accelerates at 3.4 m/sec2. What is the force acting on the object? *
a. 120.6 N
b. 126.9 N
c. 122.4 N
d. 118.3 N
Answer:
122.4
Explanation:
Can we track the movement of energy in nature
Your 1000-m-long starship has warning lights at each end that, to you, flash simultaneously every minute. You are moving directly away from the planet Zerkon at 0.70c.
To a Zerkonian, do the lights flash simultaneously? If not, which flashes first-the light at the front of your ship or the trailing one?
Answer Choices:
A. The lights flash simultaneously.
B. The front light flashes first.
C. The trailing light flashes first.
D. Not enough information given to answer the question.
To a Zerkonian observer, the lights on your starship do not flash simultaneously. The trailing light flashes first.
This is due to the phenomenon of time dilation, predicted by Einstein's theory of relativity. As you, the observer on the starship, are moving away from the planet Zerkon at a high velocity of 0.70c (70% of the speed of light), time appears to be passing slower for you relative to the stationary frame of reference on Zerkon. As a result, the time interval between the flashes of the warning lights, which is one minute in your frame of reference, will be dilated or stretched from the perspective of the Zerkonian observer. The light at the front of your starship, which is moving away from Zerkon, takes longer to reach the observer compared to the light at the trailing end. Therefore, the trailing light will be observed to flash first by the Zerkonian observer. Hence, the correct answer is C. The trailing light flashes first.
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Problem 1 Line Broadening II Which cause for line broadening is dominant in the following cases? (a) Starlight moves through a cloud of hydrogen atoms of particle density n = 105/m³ and temper- ature T 10 K. Is the natural line width AwN, the Doppler width Awp or the collision width Awc the dominant cause for the broadening of the hyperfine transition and the Lyman a-line? The decay time for the hyperfine transition 1¹S1/2 (F= 0 F = 1) at λ = 21 cm is to = 109 s and the collision cross section to 10-9 s and o= 10-15 cm². = 10-22 cm², whereas for the Lyman a-line A = 121.6 nm, 5 (3+2) points (b) A laser beam of wavelength λ = 3.39 µm and a beam diameter of 1 cm is sent through a methane cell, in which CH4-molecules at T = 300 K absorb on the transition ik (tok = 20 ms). Is the natural line width Awy, the Doppler width Awp, or the flight time width AwFT the largest?
In the case of starlight passing through a cloud of hydrogen atoms, the dominant cause for line broadening is ________.
In the case of a laser beam passing through a methane cell, the largest line broadening effect is due to ________.
In the case of starlight passing through a cloud of hydrogen atoms, the dominant cause for line broadening depends on the given parameters. The natural line width (AwN) is primarily determined by the lifetime of the excited state, which is given as to. The Doppler width (Awp) is influenced by the temperature (T) and the mass of the particles. The collision width (Awc) is influenced by the collision cross section and the particle density (n). To determine the dominant cause, we need to compare these factors and assess which one contributes the most significantly to the line broadening.
In the case of a laser beam passing through a methane cell, the line broadening is affected by different factors. The natural line width (AwN) is related to the energy-level structure and transition probabilities of the absorbing molecules. The Doppler width (Awp) is influenced by the temperature (T) and the velocity distribution of the molecules. The flight time width (AwFT) is determined by the transit time of the molecules across the laser beam. To identify the largest contributor to line broadening, we need to evaluate these effects and determine which one has the most substantial impact on the broadening of the spectral line.
the dominant cause of line broadening in starlight passing through a cloud of hydrogen atoms and in a laser beam passing through a methane cell depends on various factors such as temperature, particle density, collision cross section, and energy-level structure. To determine the dominant cause and the largest contributor, a thorough analysis of these factors is required.
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what is achieved when competition forces producers to minimize the per-unit cost of the output they produce
Competition is an essential component of the market economy that forces producers to minimize the per-unit cost of their output. This leads to cost efficiency and optimization in the production process, increased accessibility of goods and services to consumers, and economic growth.
When competition forces producers to minimize the per-unit cost of the output they produce, it leads to the achievement of cost efficiency and optimization in the production process. Competition is an essential aspect of the market economy, which leads to the production of goods and services at the lowest possible cost. The more producers compete, the more they are likely to minimize the per-unit cost of their output. This is because they are forced to be more innovative and efficient in their production processes to maintain their market share and stay competitive in the market. As such, the competition forces producers to find ways of reducing costs and increasing efficiency through, for instance, adopting new technologies, implementing better production techniques, improving the supply chain, and reducing waste. The benefits of competition in minimizing the per-unit cost of the output produced are numerous. When the production costs are lower, producers can sell their goods and services at lower prices, making them more accessible to consumers. In addition, the lower prices may stimulate demand, which, in turn, increases output, reduces unemployment, and stimulates economic growth. Moreover, when the per-unit cost of production is low, it increases the profit margin for the producer, making the business more competitive and attractive to investors.For more questions on the economy
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"True or False": Because action and reaction forces are equal in magnitude, they will produce the same acceleration in both objects involved.
True. Forces that are equal in magnitude always result in the same acceleration.
True. The same acceleration will result because the two objects are acting on each other.
False. Acceleration is dependent on the mass of the object that is accelerated.
False. Even though both objects experience an equal force, only one will accelerate.
True im not 100% sure but I tried.
a teacher wants to demonstrate that the radioactive source emits alpha beta and gamma radiation.
describe a method the teacher can use
It is possible to distinguish between these types of radiation by the use of an electrostatic field.
What is a radioactive source?A radioactive source is a source that emits radiation such as alpha, beta and gamma radiation. We can be able to distinguish between these types of radiation by the use of an electrostatic field.
The gamma rays is undeflated by the field, the alpha ray is deflated to the negative part of the field while the beta rays is deflated by the positive part of the field.
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What affects the gravitational potential energy of an object?.
The factors that affect an object’s gravitational potential energy are its height with respect to some reference point, mass of the object, and the intensity of the gravitational field it is in.
Gravitational energy is the potential energy linked with the force due to gravitation, as work is required to displaces the objects against Earth’s gravity in upward direction. The potential energy due to displacement in positions is called gravitational potential energy, and the best example where gravitational potential energy can be seen is by water in an elevated reservoir or stored behind a dam. If an object falls from a point to another point inside a gravitational field, the force due to gravity will do some work in the positive direction on the object, and the gravitational potential energy will starts to decrease by the same amount.
If we consider a book placed on top of a table. We can observe that some external force works against the gravity, while the book in on the table. The potential energy stored by the book goes to accelerate the mass of the book and is converted into kinetic energy, if the book falls off the table. When the book hits the floor, this kinetic energy is converted into heat and sound by the impact with floor.
As we know that at any height from the ground the potential energy of the mass is given by
U = mgh
so potential energy depends on
1) mass of object (m)
2) acceleration due to gravity (g)
3) height from the earth surface (h)
Hence, height with respect to some reference point of the object, mass of the object, and the intensity of the gravitational field affects the gravitational potential energy of an object.
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A jet airplane travelling at the speed of 500 km / hr ejects its products of combustion at the speed of 1500 km / hr relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?
\(v{j} = 500\)
\(vpj = - 1500\)
solution:\(vpj = vp - vj\)
\( - 1500 = vp - 500\)
\(vp = - 1000\)
= 1000 km/h
Speed of ejection of combustion products observed from ground is 1000km/h in direction opposite to the direction of motion of the jet airplane.
TRUE/FALSE. all galaxies beyond those local to the milky way appear to be receding from us.