Answer:
1 x 10⁻¹¹moldm⁻³
Explanation:
Given parameters:
pH of the solution = 11
Unknown:
[H] = ?
Solution:
The hydrogen ion concentration is unknown.
From:
PH = - log[H⁺]
So;
11 = -log[H⁺]
[H⁺] = 1 x 10⁻¹¹moldm⁻³
how does the earth compare in the orbital speed to the other planets?
Complete the balanced dissociation equation for the compound below in aqueous solution. If the compound does not dissociate, write NR after the reaction arrow. NaBr(s)
Answer:
NaBr(s) → Na+ (aq) + Br– (aq)
Explanation:
Dissociation refers to the separation of an ionic compound or molecule into its constituent ions when dissolved in water. The ions with their respective charges make up the ionic compound, hence, an ionic compound is said to dissociate when the respective cations (+ charge) and anions (- charge) are released in an aqeous solution.
In this case, NaBr(s) or Sodium bromide is an ionic solid {signified by the (s) sign}. Upon dissolving in water, NaBr(s) breaks down into the ionic charges that makes it up i.e dissociates. The balanced ionic equation is as follows:
NaBr(s) → Na+ (aq) + Br– (aq)
Note: 1 mole of the solid ionic compound dissociates into one sodium ion (Na+) and one bromide ion (Br–).
The balanced dissociation equation for the compound, NaBr is:
NaBr(s) —> Na⁺(aq) + Br¯(aq)
A dissociation equation is an equation showing the ions that makes up a compound.NOTE:
Dissociation will only occurs when the compound is dissolved in water
The dissociation equation for NaBr can be written as follow:
NaBr(s) —> Na⁺(aq) + Br¯(aq)From the equation above, we can see that the ions that makes up NaBr are clearly seen. Hence, the above equation is the dissociation equation for NaBr.
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A Se ion has a mass number of 77 and a charge of −2
. Determine the number of neutrons, protons, and electrons in this ion.
number of neutrons:
number of protons:
number of electrons:
Answer:
neutrons = 71
protons = 6
electrons = 6
Explanation:
Hope this works :)
Which of these is a chemical property?
boiling point
odor
ability to rust
color
Answer:
ability to rust
Explanation:
i'm like 90% sure thats correct
What is the mass produced of Hydrogen gas (H2), when 0.500g Hydrochloric acid (HCl) completely reacts to the following reaction. Zn + 2HCl → ZnCl2 + H2
Answer:
Mass = 0.014 g
Explanation:
Given data:
Mass of HCl = 0.500 g
Mass of hydrogen gas produced = ?
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of mole of HCl :
Number of moles = mass/molar mass
Number of moles = 0.500 g / 36.5 g/mol
Number of moles = 0.014 mol
Now we will compare the moles of HCl with hydrogen.
HCl : H₂
2 : 1
0.014 : 1/2×0.014 = 0.007
Mass of hydrogen gas:
Mass = number of moles × molar mass
Mass = 0.007 mol × 2 g/mol
Mass = 0.014 g
Please help me out ASAP!
What is meant by concentration?
Answer:
concentration is the abundance of a constituent divided by the total volume of a mixture.
The whistle of a teakettle has a greater frequency than a drumbeat. True or false and why
Answer:
how was enacting the GI bill Like teaching someone how to fish
The oldest known flower lived 120, million years ago. Is that a measured or exact number?
Answer:
measured
Explanation:
no way can they pin point exactly when something lived when its in the millions
the name of the acid present in milk
Answer:
lactic acidThe real acidity of milk is due to lactic acid. This is never found in milk when it is first drawn from the udder. It is produced by the action of the lactic acid organisms on the milk sugar. The so-called apparent acidity of milk is what gives fresh milk its acid reaction.
80 POINTS
Someone pls help me out
2) The heat capacity of aluminum is 219.44 J/mol.°C.
3) a) the experimental ΔHs of ice is -0.154 kJ/mol.
b) too high
How to calculate heat capacity?Calculate the heat released by the aluminum:
q = mcΔT
where q = heat released, m = mass of aluminum, c = specific heat capacity of water and ΔT = change in temperature.
q = (24.7 g) (0.903 J/g°C) (100.0°C - 23.4°C)
q = 18643.26 J
Next, calculate the heat absorbed by the calorimeter:
q = mcΔT
q = (99.5 g + 24.7 g) (15.8 J/°C) (23.4°C - 19.5°C)
q = 4009.92 J
The heat released by the aluminum is equal to the heat absorbed by the calorimeter and water:
18643.26 J = 4009.92 J + q3
where q3 = heat absorbed by the water.
q3 = 14633.34 J
Calculate the molar heat capacity of aluminum:
Cp,m = q3 / (nΔT)
where Cp,m = molar heat capacity, n = number of moles of aluminum, and ΔT = change in temperature.
n = m / M
where m = mass of aluminum and M = molar mass of aluminum (26.98 g/mol).
n = 24.7 g / 26.98 g/mol
n = 0.916 mol
Cp,m = 14633.34 J / (0.916 mol * 76.6°C)
Cp,m = 219.44 J/mol.°C
Therefore, the heat capacity of aluminum is 219.44 J/mol.°C.
3) (a) To calculate the experimental ΔHs of ice, we first need to calculate the heat gained by the water and the heat lost by the ice during the process.
Heat gained by water = mass of water × specific heat capacity of water × change in temperature
= 100.0 g × 4.184 J/g·°C × (-20.1°C)
= -8,423.84 J
Heat lost by ice = mass of ice × heat of fusion of ice
= 25.6 g × 6.01 kJ/mol
= 154.496 J
Since the process is assumed to be adiabatic (no heat exchange with the surroundings), the heat gained by the water must be equal to the heat lost by the ice.
Thus, -8,423.84 J = 154.496 J = -8,269.344 J
The negative sign indicates that the process is exothermic. Therefore, the experimental ΔHs of ice is:
ΔHs = -154.496 J/mol = -0.154 kJ/mol
(b) If the student forgets to include the calorimeter term in the calculation, the calculated ΔHs of ice will be too high. This is because the heat absorbed by the calorimeter during the process is not accounted for, leading to an overestimation of the heat gained by the water and underestimation of the heat lost by the ice.
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what is the initial volume, in milliliters, needed to prepare each of the following diluted solution?350 mL of 3.0 %(m/v) HCl from 15.0 % (m/v) HCl Express your answer to two significant figures and include the appropriate units.
ANSWER
The initial volume of the solution is 70mL
EXPLANATION
Given that;
The initial concentration of the solution is 15.0% m/v
The final volume of the solution is 350mL
The final concentration of the solution is 3.0% m/v
Follow the steps below to find the initial volume of the solution.
Step 1; Apply the dilution formula
\(\text{ C1 V1 = C2 V2}\)Substitute the given data into the above formula
\(\begin{gathered} \text{ }\frac{15}{100}\text{ }\times\text{ V1 = }\frac{3}{100}\times\text{ 350} \\ \text{ 0.15 }\times\text{ V1 = 0.03 }\times\text{ 350} \\ \text{ 0.15 V1 = 10.5} \\ \text{ Divide both sides by 0.15} \\ \text{ V1 = }\frac{\text{ 10.5}}{\text{ 0.15}} \\ \text{ V1 = 70mL} \end{gathered}\)Therefore, the initial volume of the solution is 70mL
In a science demonstration, a teacher mixed zinc (Zn) with hydrogen chloride (HCl) in a flask and quickly attached a balloon over the mouth of the flask. Bubbles formed in the solution and the balloon inflated.
What most likely occurred during this demonstration?
a.The Zn and HCl both retained their identity.
b.Either Zn or HCl, but not both, retained its identity.
c.Evaporation of one of the substances occurred.
d.One or more new substances formed.
Answer:
a. The Zn and HCl both retained their identity.
2LiClO+KHSO - Li2SO4 + Cl2 + KOOH
1. How many moles of KOOH is produced, if you started the reaction with 5 moles of
LiCIO?
Answer:
2.5 moles of KOOH are produced.
Explanation:
1)Given data:
Number of moles of KOOH produced = ?
Number of moles of LiClO = 5 mol
Solution:
Chemical equation:
2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH
now we will compare the moles of KOOH and LiClO.
LiClO : KOOH
2 : 1
5 : 1/2×5 = 2.5
2.5 moles of KOOH are produced.
FORENSICS
Zara wants to learn more about spectrophotometry. Which of the following webinars should she attend?
A. Carrying Out Chemical Evaluations on Drugs
B. Identifying Drugs by Using Light
C. Understanding the Gas that Drugs Emit
D. Special Tools Every Forensic Scientist Needs
Zara should attend a webinar in identifying Drugs by Using Light (option A) if she wants to learn more about spectrophotometry.
What is spectrophotometry?Measuring concentrations present within solutions can be achieved by utilizing spectrophotometry - an approach that utilizes light as its primary mechanism. Its significance in identifying and measuring drugs located in samples continues to grow across numerous research areas due to its effectiveness.
Central to this method is recognizing how distinct substances absorb varying amounts of light dependent on their particular electronic structures on specific wavelengths.
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Why are atoms electrically neutral if they contain charged particles?
Answer:
Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged).
Explanation:
1. Write the IUPAC names for the following 1.1 1.2 N 1.3 O NO2 x Y ·0 OH 5
1. The IUPAC name of N is nitrogen.
2. Nitrogen dioxide
3.The IUPAC name of O is oxygen
4.The IUPAC name of OH is hydroxyl.
The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.
IUPAC names for the given compounds are:1.1. N: Nitrogen
The IUPAC name of N is nitrogen.
It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide
Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.
The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen
Explanation: The IUPAC name of O is oxygen.
It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.
X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.
Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.
It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.
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Note: The complete question is given below
Provide the IUPAC names for the following compounds:
\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)
C6H5CH(CH3)2
H2NCH2CH2CH2CH2CH2NH2
CH3CH2CH2CH2CH2OH
CH3CH2CH2CHOHCH3
A mixture of krypton and argon gas is expanded from a volume of 88.0L to a volume of 100.0L, while the pressure is held constant at 27.0atm. Calculate the work done on the gas mixture. Round your answer to 3 significant digits, and be sure it has the correct sign (positive or negative).
Answer:
-3.28 × 10⁴ J
Explanation:
Step 1: Given data
Pressure exerted (P): 27.0 atmInitial volume (Vi): 88.0 LFinal volume (Vf): 100.0 LStep 2: Calculate the work (w) done by the gaseous mixture
We will use the following expression.
w = -P × ΔV = -P × (Vf - Vi)
w = -27.0 atm × (100.0 L - 88.0 L)
w = -324 atm.L
Step 3: Convert w to Joule (SI unit)
We will use the conversion factor 1 atm.L = 101.325 J.
-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J
Solid tin is combined with hydrofluoric acid (hydrogen fluoride) to produce Tin (II) fluoride and hydrogen gas
How many grams of Tin (II) fluoride are produced from the reaction of 30.00g of hydrogen fluoride with Tin?
The concept balanced equation is used here to determine the amount of Tin (II) fluoride produced from 30.00g of hydrogen fluoride. The mass of SnF₂ is 117.5 g.
What is a balanced equation?A chemical equation which obeys the law of conservation of mass in which the mass of the reactants is equal to the mass of the products on either side of the reaction is known as the balanced equation.
The balanced equation for the given reaction is:
Sn + 2HF → SnF₂ + H₂
Here 1 mole of SnF₂ is produced from 2 mole of HF. The molar mass of SnF₂ is 156.71 g and that of HF is 20 g.
30 g HF × 1 mol HF / 20 g HF × 1 mol SnF₂ / 2 mol HF × 156.71 g SnF₂ / 1 mol SnF₂ = 117.5 g SnF₂
Thus the mass of Tin (II) fluoride is 117.5 g .
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What does =173 degrees celsius
feel like?
173 degrees Celsius is extremely hot and would feel scorching and painful. It is well above the boiling point of water (100 degrees Celsius), so any contact with surfaces at this temperature would cause severe burns.
In more detail, at 173 degrees Celsius, the air would be unbearably hot, making it difficult to breathe. Your skin would feel a burning sensation immediately upon contact with any object or surface heated to this temperature. It would be similar to touching a hot stove or a blazing fire. The intense heat would quickly penetrate your skin, causing deep burns and potentially permanent damage. Extreme caution and protective measures are necessary to avoid such high temperatures, as they pose a significant risk to health and safety. It is important to stay away from such extreme temperatures to prevent serious harm.
In summary, 173 degrees Celsius would feel extremely hot and would cause severe burns upon contact with objects or surfaces at this temperature. The air would be scorching and difficult to breathe, making it essential to avoid exposure to such extreme heat for the sake of personal safety.
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Sound waves with a large distance between A and B would be sound waves that have a large
es
and produce loud sounds.
Answer:
Wavelength
Explanation:
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If 4.44 mol of C,H₁2 reacts with excess O₂, how many moles of CO₂ will be produced by the following combustion reaction?
C₂H2 +80₂6H₂O +5C0₂
moles of CO₂:
mol
A combustion reaction is a type of chemical reaction that involves the rapid combination of fuel (typically a hydrocarbon) with oxygen, resulting in the release of energy in the form of heat and light.
Combustion reactions are often characterized by the presence of a flame and the production of carbon dioxide (CO₂) and water (H₂O) as products.
In the given balanced combustion reaction:
C₂H₂ + 5O₂ → 4H₂O + 2CO₂
The stoichiometric ratio indicates that 1 mole of C₂H₂ reacts with 2 moles of CO₂ produced. Therefore, if 4.44 moles of C₂H₂ react, we can calculate the moles of CO₂ produced using the ratio:
Moles of CO₂ = (4.44 mol C₂H₂) × (2 mol CO₂ / 1 mol C₂H₂)
Moles of CO₂ = 8.88 mol
Therefore, 8.88 moles of CO₂ will be produced in the combustion reaction.
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If a 5.00% citric acid solution contains 5.00 grams of citric acid in every 100.0 mL of the solution, how many grams of citric acid are present in 375 mL of the 5.00% (w/v) solution? show your work using dimensional analysis and report your answer with the correct number of significant figures
Answer:
18.8 g Citric acid
Explanation:
We have a 5.00% (w/v) citric acid solution, that is, there are 5.00 grams of citric acid every 100.0 mL of the solution. We can use dimensional analysis to calculate the grams of citric acid in 375 mL of the 5.00% (w/v) solution.
375 mL Solution × (5.00 g Citric acid/100.0 mL Solution) = 18.8 g Citric acid
can someone help me with this
Answer:
I think cold front if not than its c
A logical conclusion based on observations is called an inference.
Question 2 options:
True
False
Answer:
True
Explanation:
Because the definition of inference is a conclusion reached on the basis of evidence and reasoning.
how does fire relate to science
Answer: A fire itself is the result of a chemical reaction known as combustion, where fuel and oxygen react with one another and atoms rearrange themselves irreversibly. For this to occur, fuel must reach its ignition temperature, and combustion will continue if there is enough fuel, heat and oxygen
solid substance A has a melting point of 100C. Liquid substance B has a freezing point of 110C. For each substance, identify it's state of matter and describe the motion of it's particles when the substance is at 115C
State of matter of both substance will be liquid at 115C.
A substance-A substance's melting point is 100 degrees Celsius. Thus, liquid material A will arise from temperatures over 100 degrees. Since material A is liquid at 115 degrees Celsius, the particles are free to migrate and glide over one another.
B Substance-It has a freezing point of 110 degrees Celsius. This signifies that substance B will exist in a liquid condition at any temperature greater than 110 °C. In a liquid condition, the components of solution B will also be sufficiently mobile to travel past one another.
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The pressure inside the cabin of an airplane decreases to 12.5 psi during a high altitude flight. Convert this pressure value to units of …. (1 psi= 0.068 atm: This is another common pressure)
a. ... millimeters of mercury (mm Hg):
b. Submit
c. ... atmospheres (atm):
d. Submit
e. ... kilopascals (kPa):
The new helium gas cylinders have just arrived at the loading dock of a local party store. In the cool January air, the 20.0-L cylinders have a pressure of 55.7 atm. Once brought into the store, the cylinder’s temperatures increases to 31.9°C and the pressure adjusts to 61.3 atm. What is the outdoor temperature in °C? (Assume a constant volume.)
A sample of oxygen gas at 68.5°C and 3.88 atm is heated until its pressure has increased to 6.10 atm. What is the new temperature (in °C)?
Will B. Sellabraten purchases a set of Helium balloons at the local card shop. Each balloon occupies a volume of 15.8 liters when in the store; but when taken outside, they are observed to shrink. If the indoor temperature is 26.6°C and the outside air temperature is -2.4°C, then what is the new volume of the balloons when taken outside?
A sample of helium gas at 61.8°C has a volume of 342 mL. What is the volume of this gas at -71.7°C?
are air, sea water, and sugar water all homogenous mixtures??
Answer:
yes
Explanation:
convert 5.0 mol Si to grams
140g/mol
Explanations:
The mass of silicon is expressed according to the formula:
\(Mass\text{ of Silicon}=moles\times molar\text{ mass}\)Given the following parameters
• Moles of silicon = 5.0moles
,• Molar mass of silicon = 28g/mol
Substitute the given parameters into the formula
\(\begin{gathered} Mass\text{ of silicon}=5.0moles\times\frac{28g}{mol} \\ Mass\text{ of silicon}=140g\text{/}mol \end{gathered}\)Hence the mass of silicon is 140g/mol
Be sure to answer all parts. How many moles of water contain each of the following number of molecules?
Report your answer using appropriate number of significant figures.
a. 9.52 x 1026 molecules
_____ mol
b. 7.81 x 1022 molecules
_____mol
c. 2.5 % 1023 molecules
_____ mol
Answer:
1.520
1.333
15.899
Explanation:
its very easy
N = n x No
No = avogadro's number = 6.02 x 10²³
n = mol
a. 9.52 x 10²⁶ : 6.02 x 10²³ = 1.58 x 10³ (3 sig figs)
b. 7.81 x 10²² : 6.02 x 10²³ = 1.30 x 10⁻¹ = 0.130 (3 sig figs)
c. 2.5 x 10²³ : 6.02 x 10²³ = 0.42 (2 sig figs)