a solution of mno42- is electrolytically reduced to mn3 . a current of 8.64 amp is passed through the solution for 15.0 minutes. what is the number of moles mn3 produced in this process?

Answer: 0.002 m³

Explanation:

We can use our unit conversions to find the volume in m³.

\(2L*\frac{1m^3}{1000L} =0.002m^3\)

Answer:

B) Conduction requires two objects to be in physical contact.

Explanation:

Conduction is when two objects are directly touching each other. So, the objects must come in physical contact with each other.

The volume of the person's lungs if the temperature rises from 36°C to 39°C is 3.53L and will likely not explode.

The volume of a substance can be calculated using the following formula:

V1/T1 = V2/T2

Where;

3.5/309 = V2/312

309V2 = 1092

V2 = 1092 ÷ 309

V2 = 3.53L

Therefore, the volume of the person's lungs if the temperature rises from 36°C to 39°C is 3.53L and will not explode.

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Answer: You could put the frozen block of ice on the stove and let it melt and eventually boil out leaving the salt behind

Explanation:

The balanced chemical equations for the given reactions are:

16Ag + S₈  →  8Ag₂S

2 Al + 3 Br₂  →  2 AlBr₃

2 KClO₃  →  2KCl  + 3 O₂

CH₄  + O₂  →  CO₂   + 2 H₂O

2Al  + 3 O₂  → Al₂O₃

2 H₂O₂  → 2 H₂O   + 2 O₂

A balanced equation can be defined as an equation in which the number of atoms of every element involved in the reaction is equal on either side of the chemical equation.

The law of conservation of matter has to be obeyed by a balancing of a chemical equation.

By following the law of conservation of matter, the total mass of the elements of reactants will be equal to the total mass of products in a balanced chemical equation.

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The mass of the go-cart in kilograms : 20 kg

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object  

\(\large {\boxed {\bold {a = \frac {\sum F} {m}}}\)

F = force, N  

m = mass = kg  

a = acceleration due to gravity, m / s²  

Maybe the student's data are shown in the attachment

So,  the mass of the go-cart :

\(\tt m=\dfrac{10}{0.5}=\dfrac{20}{1}=\dfrac{30}{1.5}=\dfrac{40}{2}=20~kg\)

Answer:

The volume of a gas is determined by the volume of the container it is in. Gases take the shape of their container and the volume of the container....

Explanation:

What happens to the volume or size of a balloon as it rises in the air?

When a balloon goes up higher in the air, its size will increase. Since there's less air in the upper atmosphere, there's less stuff pushing back on the balloon, and hence the pressure is lower, which allows the balloon to expand.

Is pressure inside a balloon greater?

The pressure inside the balloon is higher than the pressure on the outside. ... And the direction of airflow is always from higher to lower pressure. If the pressure was same then there would be no airflow and if the pressure outside was higher , air will flow from outside to the inside of the balloon.

What is the relationship between volume and pressure?

Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when temperature is held constant. Therefore, when the volume is halved, the pressure is doubled; and if the volume is doubled, the pressure is halved.

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requires 10 hours of contact time; anything less than 10 hours is disinfection, not sterilization.

The difference between any two stationary state energy is the right response.

In atoms, the orbits of electrons are quantized. Electrons can travel to a higher orbit by absorbing some energy and can move to a lower orbit by releasing energy. Each orbit has distinct energy. Discrete spectra result from the quantization of the orbits, which also quantizes the energy received or emitted. One of the most common ways to introduce and remove energy from atoms is by photon absorption or emission, and the energy involved is equivalent to the change in electron energy as it moves from one orbit to another.

What is atomic quantization?

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Answer: 143.48 moles of copper will be produced.

Explanation:

We are given:

Number of particles of copper (I) sulfate = \(4.32\times 10^{25}\)

According to the mole concept:

\(6.022\times 10^{23}\) number of particles is contained in 1 mole of a compound

So, \(4.32\times 10^{25}\) number of particles will be contained in = \(\frac{1}{6.022\times 10^{23}}\times 4.32\times 10^{25}=71.74mol\) of copper (I) sulfate

The given chemical equation follows:

\(Fe+Cu_2SO_4\rightarrow FeSO_4+2Cu\)

By the stoichiometry of the reaction:

If 1 mole of copper (I) sulfate produces 2 moles of Cu

So, 71.74 moles of copper (I) sulfate will produce = \(\frac{2}{1}\times 71.74=143.48mol\) of Cu

Hence, 143.48 moles of copper will be produced.

Stretch Blow Molding is a variation of injection blow molding in which blowing rod stretches the soft parison for a more favorable stressing of polymer than conventional blow molding.

Blow molding is the technique used for manufacturing hole, usually plastic elements. Some examples of blow molded merchandise are small custom plastic bottles and containers for consumer products like water, shampoo, or milk.

High-Density Polyethylene (HDPE) acceptable physical properties—such as chemical resistance, temperature resistance, and a high energy-to-density ratio—make it one of the most popular blow molding substances.

In popular, blow molding is used to make singular, hollow products like bottles and beakers. Injection molding makes solid parts, like plates and discs, or is used to provide stable parts or portions for plastic merchandise.

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Stretch Blow Molding is a variation of injection blow molding in which the blowing rod stretches the soft parison for a more favorable stressing of polymer than conventional blow molding.

A polymer is a substance together with very large molecules referred to as macromolecules, composed of many repeating subunits. Due to their vast spectrum of homes, both synthetic and natural polymers play vital and ubiquitous roles in regular lifestyles.

Products made from polymers are all around us: garb made from synthetic fibers, polyethylene cups, fiberglass, nylon bearings, plastic bags, polymer-primarily based paints, epoxy glue, polyurethane foam cushion, silicone heart valves, and Teflon-covered cookware.

A number of the beneficial houses of diverse engineering polymers are excessive electricity or modulus-to-weight ratios, toughness, resilience, resistance to corrosion, lack of conductivity, color, transparency, processing, and coffee price.

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The answer is that regions of the polymer that are very ordered are called crystalline regions, whereas regions of the polymer that are very disordered are called amorphous regions.

Polymers are long chains of repeating units called monomers. The degree of order in the polymer chains can vary depending on factors such as the type of monomers used and the processing conditions during polymerization. When the polymer chains are arranged in a regular, repeating pattern, they form crystalline regions, which have a high degree of order.

These regions tend to be more rigid and have higher melting points compared to the amorphous regions. On the other hand, when the polymer chains are arranged in a random, disordered pattern, they form amorphous regions, which have a low degree of order. These regions tend to be more flexible and have lower melting points compared to the crystalline regions. The balance between crystalline and amorphous regions in a polymer can affect its mechanical properties, such as strength and flexibility.

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The empirical formula for given values is C₃H₅0₄ for the given compound containing water carbon di oxide .

The empirical fοrmula οf a chemical cοmpοund in chemistry is the simplest whοle number ratiο οf atοms present in the substance. As an example, the empirical fοrmula οf Sulphur mοnοxide, οr SO, is simply SO, as is the empirical fοrmula οf disulfur diοxide.

Thus, sulphur mοnοxide and disulfur diοxide, bοth sulphur and οxygen cοmpοunds, have the same empirical fοrmula. Their mοlecular fοrmulae, which express the number οf atοms in each mοlecule οf a chemical cοmpοund, are, hοwever, nοt identical.

The arrangement οr number οf atοms are nοt mentiοned in an empirical fοrmula. Many iοnic cοmpοunds, such as calcium chlοride and macrοmοlecules, such as silicοn diοxide, use it.

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The number of hamburgers sold on Wednesday is 275.

Let's assume the number of hamburgers sold is x.

According to the given information, the number of cheeseburgers sold is 70 more than the number of hamburgers. So, the number of cheeseburgers sold can be expressed as x + 70.

The total number of hamburgers and cheeseburgers sold is given as 620, so we can set up the following equation:

x + (x + 70) = 620

Combining like terms, we get:

2x + 70 = 620

Subtracting 70 from both sides of the equation:

2x = 550

Dividing both sides by 2:

x = 275

Therefore, the number of hamburgers sold on Wednesday is 275.

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To increase the rate of reaction the chemist could increase the temperature, surface area of NaOH or the concentration of HCl.

The chemist could crush the NaOH pellets into a finer powder. A greater surface area allows more NaOH particles to come into contact with HCl particles at the same time, leading to a faster rate of reaction.
The chemist could use a higher concentration of HCl solution, which would provide more HCl molecules to react with the NaOH, resulting in a faster reaction rate.
By increasing the temperature, the kinetic energy of the particles increases, leading to more frequent and energetic collisions between NaOH and HCl molecules. This will result in a faster rate of reaction.

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Answer:

B

Explanation:

They go into a state of dormancy like hibernation .

In this stage they do

The molar solubility of \(Al(OH)_3\) in 0.2 M \(Al(NO_3)_3\) is approximately \(2.68 * 10^-^1^1 M.\)

To determine the molar solubility of \(Al(OH)_3\) in 0.2 M \(Al(NO_3)_3\) , we must take into account the normal ion effect. The presence of \(Al^3^+\) ions from \(Al(NO_3)_3\) will affect the solubility of \(Al(OH)_3\).

The balanced equation for the dissolution of \(Al(OH)_3\) in water is:

\(Al(OH)_3(s)\)⇌ \(Al^3^+(aq) + 3OH^-(aq)\)

The solubility product expression for \(Al(OH)_3\) is

\(K_s_p\) = \([Al^3^+]. [OH^-]^3\)

The molar solubility can be established using an equilibrium table, the \(K_s_p\) of \(Al(OH)_3\) is \(2.0 * 10^-^3^2\)

So,

[\(Al^3^+\)] = 0 (from 0.2 M \(Al(NO_3)_3\))

[\(OH^-\)] = 0

At equilibrium:

\([Al^3^+]\) = x (change due to dissolution of \(Al(OH)_3\))

\([OH^-]\)= 3x (since the stoichiometric coefficient is 3 in the balanced equation)

Using the \(K_s_p\)expression:

\(K_s_p = [Al^3^+][OH^-]^3\)

\(2.0 * 10^-^3^2 = x * (3x)^3\\2.0 * 10^-^3^2 = 27x^4\)

\(x = \sqrt[3]{2.0 * 10^-32 / 27} \\x = 2.68 * 10^-^1^1\)

Therefore, the molar solubility of \(Al(OH)_3\) in 0.2 M \(Al(NO_3)_3\) is approximately \(2.68 * 10^-^1^1 M.\)

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Answer:

Barium, beryllium, and Strontium

Explanation:

These 3 elements are located in the same group, which determines the number of valence electrons.

The valence electrons determine how reactive an element will be.    

A. →barium

B. silicon

C. aluminum

D. →strontium

E.osmium

F. →beryllium

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This is correct because each piece of wood has the same composition.

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Answer:

\({ \rm{2H {}^{ + } _{(aq)} + CO {}^{2 - } _{3(aq)} \: \: \: {}^{ { \huge{\dashrightarrow} }} _{ \huge{ \dashleftarrow}} }} \: \: { \rm{H _{2} CO _{3(aq)} }}\)

Answer:

Heat is something you can't control

Explanation:

Plastic is something you could control like moving it around

The reaction takes place in third order. The rate constant of the reaction for the given rate and concentrations is 1.23 × 10³ mol⁻² L² /s.

The rate of a reaction is the rate of increase in the concentration of products or rate of decrease in the concentration of the reactants.

For the given reaction, the rate law is written as:

rate = k[A][B]²

[A] = 0.023

[B] = 0.054

rate = 8.31 ×10⁻² M/s

Rate constant k = rate/[A] [B]²

K = 8.31 ×10⁻² M/s/(0.023 × 0.054²)

  = 1.23 × 10³ mol⁻² L² /s

Therefore, the rate constant for the reaction is 1.23 × 10³ mol⁻² L² /s.

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Your question is incomplete. But your complete question probably was:

The rate of a reaction is, Rate = k[A][B]2.when the concentration of a and b were 0.023 m and 0.054 m, the reaction rate was 8.31x10-2 m/sec, calculate the value for k (with units).

Answer:

C6H6

Explanation:

The empirical formula, CH, has a unit mass of 13 (12+1).  78/13 = 6

There are 6 units of CH in the intact compound.  The molecular formula must be C6H6.

C:  6 * 12 = 72

H:  6 * 1 =     6

Total     =    78

The both can be separated by adding water to the mixture.

Diamonds and sugar are two very different substances, and it is relatively easy to separate them from each other using physical and chemical methods.

One common method to separate diamonds from sugar is by using their different physical properties. Diamonds have a much higher density than sugar, so if you mix a sample of both substances in water, the diamonds will sink to the bottom while the sugar will float on top and dissolve in the water. This is known as gravity separation.

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Explanation:

Refer to pic.............

For I₂ under the harmonic oscillator approximation at 300 K, the ratio of molecules in the first excited state (n=1) to the ground state (n=0) can be calculated using the Boltzmann distribution equation. The vibrational energy levels are assumed to be equally spaced, and the proportion of molecules in the first excited state compared to the ground state can be determined.

Additionally, the temperature at which the population in the first excited state is half of that in the ground state can be found by setting up an equation based on the Boltzmann distribution.

The ratio of molecules in the first excited state to the ground state for I₂ at 300 K using the harmonic oscillator approximation, we can use the Boltzmann distribution equation. The energy levels of a harmonic oscillator are given by E = (n + 1/2)hν, where n is the vibrational quantum number, h is Planck's constant, and ν is the vibrational frequency.

a) Ratio of molecules in the first excited state to the ground state:

Since the energy levels are equally spaced, the energy difference between adjacent levels is ΔE = hν. Using the formula ΔE = √(k/μ), where k is the force constant and μ is the reduced mass, we can calculate the vibrational frequency (ν) for I₂.

μ = m1 * m2 / (m1 + m2)  (reduced mass equation)

Plugging in the mass of iodine (I) as 126.9 amu and applying the reduced mass equation, we can find μ.

Once we have ν, we can calculate the energy difference (ΔE) and determine the ratio of molecules in the first excited state (n=1) to the ground state (n=0) using the Boltzmann distribution equation.

b) Temperature at which the population in the first excited state is half of that in the ground state:

To find this temperature, we can set up an equation where the ratio of molecules in the first excited state (n=1) to the ground state (n=0) is 1:2. We can solve for the temperature (T) using the Boltzmann distribution equation.

With the given force constant (k=170 N/m) and the calculated vibrational frequency (ν), we can determine the temperature at which the population in the first excited state will be half of that in the ground state.

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the condensed electron configuration for Cr³⁺ is [Ar] 3d³. Since there are three electrons in the 3d subshell, and each occupies a separate orbital, there are 3 unpaired electrons in Cr³⁺.

To determine the condensed electron configuration and the number of unpaired electrons for Cr³⁺, we need to first find the electron configuration for the neutral chromium atom (Cr) and then remove 3 electrons to account for the 3+ charge.

1. The electron configuration for the neutral chromium atom (Cr) is [Ar] 4s¹ 3d⁵.

2. To remove 3 electrons for Cr³⁺, we need to remove one electron from the 4s subshell and two electrons from the 3d subshell. This results in the electron configuration [Ar] 3d³.

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a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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