The solution contains the 0.0218 M of the first compound. Then the absorbance through the path of the length of the 1.00cm is the 0.640. The concentration of the second compound is 0.00599 M.
For the first compound, is as :
A₁ = 0.640
c₁ = 0.0218 M
l₁ = 1.00 cm
Where
A is absorbance,
ε is the molar absorptivity ,
c is the concentration,
l is the path length.
For the second compound, is as :
ε₂ = 15.2 cm⁻¹M⁻¹
l₂ = 1.00 cm
A₂ total = 0.455, this is the absorbance after the addition of the second compound.
A₂total = A₁ + A₂
0.455 = 0.640 + (15.2)(c₂)(1)
c₂ = (0.455 - 0.640) / 15.2
c₂ = 0.091 / 15.2
c₂ = 0.00599 M
The concentration of the second compound is 0.00599 M.
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This question is incomplete, the complete question is :
a solution contains 0.0218m of a first compound. the absorbance through a path length of 1.00cm is 0.640. a second compound with an extinction coefficient of 15.2cm−1m−1 is added to the solution, and the absorbance through the path length of 1.00 cm increases to 0.455. What is the concentration of the second compound in the solution?
alice, a 14-year-old adolescent has been diagnosed with anorexia nervosa. which of the following would you most likely find in your assessment of alice? group of answer choices dysmenorrhea tachycardia decreased body temperature heat intolerance
A 14-year-old adolescent girl, Alice, has been diagnosed with anorexia nervosa. In the assessment of Alice, the findings that are more commonly associated with anorexia nervosa are Dysmenorrhea, decreased body temperature, and Heat intolerance.
Dysmenorrhea: Anorexia nervosa can lead to hormonal imbalances and disruptions in the menstrual cycle, which can cause irregular or absent periods (amenorrhea) and sometimes dysmenorrhea (painful periods).
Decreased body temperature: Anorexia nervosa can lead to lower body weight and reduced body fat, which can result in a lower body temperature. This is a physiological response to conserve energy and maintain the body's functions.
Heat intolerance: Anorexia nervosa can affect the body's ability to regulate temperature properly, leading to increased sensitivity to heat or cold. Individuals with anorexia may feel more discomfort or intolerance in extreme temperatures.
Hence, the findings that are more commonly associated with anorexia nervosa are explained above.
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40. 0% carbon, 6. 7% hydrogen, and 53. 3% oxygen with a molecular mass of 60. 0 g/mol. What is the molecular formula of the unknown compound?
The molecular formula of the unknown compound is C2H2O2.
To determine the molecular formula of the unknown compound, we need to calculate the empirical formula first and then find the multiple of its subscripts to obtain the molecular formula.
Given:
Percentage of carbon = 40.0%
Percentage of hydrogen = 6.7%
Percentage of oxygen = 53.3%
Molecular mass = 60.0 g/mol
Step 1: Convert the percentages to grams.
Assuming we have 100 grams of the compound:
Mass of carbon = 40.0 g
Mass of hydrogen = 6.7 g
Mass of oxygen = 53.3 g
Step 2: Convert the masses to moles using the molar masses of the elements.
Molar mass of carbon = 12.01 g/mol
Molar mass of hydrogen = 1.008 g/mol
Molar mass of oxygen = 16.00 g/mol
Number of moles of carbon = Mass of carbon / Molar mass of carbon
= 40.0 g / 12.01 g/mol
= 3.332 mol
Number of moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen
= 6.7 g / 1.008 g/mol
= 6.648 mol
Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen
= 53.3 g / 16.00 g/mol
= 3.331 mol
Step 3: Determine the empirical formula by dividing the moles by the smallest value.
Dividing the moles of carbon, hydrogen, and oxygen by 3.331 gives approximately 1 for each element.
So, the empirical formula of the compound is CHO.
Step 4: Determine the multiple of the subscripts to obtain the molecular formula.
To find the multiple, we divide the molecular mass by the empirical formula mass.
Molecular mass = 60.0 g/mol
Empirical formula mass = (12.01 g/mol) + (1.008 g/mol) + (16.00 g/mol) = 29.018 g/mol
Multiple = Molecular mass / Empirical formula mass
= 60.0 g/mol / 29.018 g/mol
= 2.07
Rounding to the nearest whole number, we get 2.
Therefore, the molecular formula of the unknown compound is C2H2O2.
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What are the formal charges on each of the atoms in the BH4 ion? Hint: draw the Lewis dot structure of the ion. A. B = 0; H = -1 B. B = -1; H = 0 C. B = 0; H = 0 D. B = +3; H = -1 E. B = 0; H = -(1/4)
Answer:
The correct answer is D. B = +3; H = -1.
To draw the Lewis dot structure of the BH4 ion, we first determine the total number of valence electrons:
B: 3 valence electrons
H: 1 valence electron x 4 = 4 valence electrons
Total: 3 + 4 = 7 valence electrons
The single B atom is the central atom, and the four H atoms are attached to it. Each H atom forms a single bond with the B atom, which uses up 4 valence electrons:
H H
| |
H-B-H
|
H
We have 3 valence electrons left, which we place around the central B atom as lone pairs:
H H
| |
H-B-H
| |
H--
Each H atom has a full valence shell (2 electrons), and the B atom has an octet (8 electrons). However, the B atom now has 5 valence electrons, which gives it a formal charge of +3. Each H atom now has only 1 valence electron, which gives it a formal charge of -1. The sum of the formal charges in the BH4 ion is 0, as it should be for a neutral molecule/ion.
please help in all 3 questionnn
Answer:
Explanation:
a) photosynthesis
b) Substances used: water, sun, gas and nutrients. Products: glucose and flowers
c) there will be no sunlight or no open environment
5. The solubility of sugar in water at room temperature is about 180g/100ml. A solution had 2.625 Kg of sugar dissolved in 1.5 L of water. Answer the following questions:
What is the concentration of the solution? Show your calculation.
Is the solution unsaturated, saturated or supersaturated? Why?
Is the solution concentrated or dilute? Why?
How could you create a supersaturated solution from this mixture?
The concentration of the solution is 1.75 g/ml of solubility of sugar.
Solubility explained.
To find the concentration of the solution, we need to use the formula:
Concentration = mass of solute (sugar) / volume of solution
We are given that the solution has 2.625 kg of sugar dissolved in 1.5 L of water. To convert the mass of sugar to grams, we multiply by 1000:
Mass of sugar = 2.625 kg x 1000 = 2625 g
The volume of the solution in milliliters is:
1.5 L x 1000 ml/L = 1500 ml
The concentration of the solution is then:
Concentration = 2625 g / 1500 ml = 1.75 g/ml
The solution is supersaturated, because it has more sugar dissolved in it than what would be expected for a saturated solution at room temperature (180 g/100 ml).
The solution is also concentrated because it has a relatively high concentration of sugar, 1.75 g/ml.
To create a supersaturated solution from this mixture, one could heat the solution to dissolve more sugar, and then cool the solution slowly and carefully without disturbing it, so that the excess sugar remains in solution.
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50 point answer
A 25.0 g piece of brass at 325 °C
was placed into a sample of water.
The final temperature of the water and brass was 42.0 °C.
What is the heat, q, of the brass?
The heat of the brass is approximately -2702.75 J.
To calculate the heat (q) of the brass, we can use the equation:
q = m × c × ΔT
where q is the heat, m is the mass of the brass, c is the specific heat capacity of brass, and ΔT is the change in temperature.
First, we need to determine the specific heat capacity of brass. The specific heat capacity of brass varies depending on the composition of the brass, but we can use an approximate value of 0.38 J/g°C.
Given:
Mass of brass (m) = 25.0 g
Change in temperature (ΔT) = 42.0 °C - 325 °C = -283 °C
Now we can calculate the heat of the brass:
q = (25.0 g) × (0.38 J/g°C) × (-283 °C)
q = -2702.75 J
The negative sign indicates that heat is being transferred from the brass to the surroundings (water in this case). Therefore, the heat of the brass is approximately -2702.75 J.
It's important to note that the negative sign does not change the magnitude of the heat, it simply indicates the direction of heat flow. In this case, the brass is losing heat to the water, resulting in a decrease in its temperature and a corresponding increase in the temperature of the water.
So, the heat of the brass is -2702.75 J.
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Answer: -2688.5. I urge you to see what I have to say below, however, as it is very easy to understand how to do this once you get the simple equation down.
Explanation:
An easy way to get these answers down yourself without having to reach out for help is to do this equation:
Mass of the metal * Specific heat of the metal * (Final Temperature - Initial Temperature). Doing that got me the answer.
In this case, 25*0.380*(42-325) will get you the answer, 25 being the mass, 0.380 being the specific heat of the brass, and 42-325 being the final temperature of 42 degrees celsius minus the initial temperature of 325 degrees celsius. Hope this helped so you can do your best in the future.
How would you measure the specific latent heat of vaporisation of a liquid?
Answer:
Ramsey and Marshall method.
Explanation:
The specific latent heat of vapourization of a liquid is measured by a modification of the method of Ramsey and Marshall in the year 1896.
how many moles of water, h2o, are present in 985 g of epsom salt, which has the empirical formula of mgso4.7h2o?
If all the water molecules are present, there are 3.98 moles of water in 985 g of epsom salt. which has the empirical formula of mgso4.7h2o
We must first get the molecular formula of epsom salt by dividing the empirical formula by its molar mass in order to determine how many moles of water there are in 985 g of epsom salt. Mgso4 has a molar mass of 120.4 g/mol, while 7h2o has a molar mass of 126.1 g/mol. Epsom salt's molar mass is 246.5 g/mol, and its molecular formula is mgso4.7h2o. We must first deduct the mass of the mgso4 from the overall mass of epsom salt in order to determine how many moles of water there are, and then divide the result by the molar mass of 7h2o. In 985 g of epsom salt, this results in 3.98 moles of water.
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An experiment was conducted to estimate the effect of smoking on the blood pressure of a group of 37 cigarette smokers. The difference for each participant was obtained by taking the difference in the blood pressure readings at the beginning of the experiment and again five years later. The sample mean increase, measured in millimetres of mercury, was x = 9.1. The sample standard deviation was s = 5.5. Estimate the mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment. Find the 95% margin of error. (Round your answer to two decimal places
The 95% margin of error for the mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment is ±1.98 (rounded off to two decimal places).
The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment can be estimated by using the formula;μ = x ± z(\(a^{2}\)) * σ/√n
Where;μ is the population mean increase.x is the sample mean increase.z(\(a^{2}\)) is the z-scoreα is the level of significanceσ is the population standard deviationn is the sample size.
Substituting the given values into the formula;μ = 9.1 ± 1.96 * 5.5/√37= 9.1 ± 1.98
The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment lies between 7.12 to 11.08.
Hence, the estimated mean increase is between 7.12 to 11.08 millimeters of mercury.
The 95% margin of error can be calculated using the formula;
Margin of error (E) = z(\(a^{2}\)) * σ/√n
Margin of error (E) = 1.96 * 5.5/√37
Margin of error (E) = 1.98 (approximated to two decimal places).
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Identify the parts of the periodic table square somehow would be greatly appreciated
According to the given picture:
A represents the atomic number.
B represents the chemical symbol.
C represents the atomic mass.
D represents the name of the element.
Imagine you are calling out to your friend as they are walking towards you. How is your friend able to hear the sound you create?
Crests and troughs are created to carry sound waves through air molecules.
Compression and rarefactions carry sound waves through air molecules.
Crests and troughs are created to carry sound waves through moisture in the air (water molecules).
Compressions and rarefactions carry sound waves by bouncing off of solid structures between you and your friend.
Answer:
Compression and rarefactions carry sound waves through air molecules.
Explanation:
How many moles are there in 135g of aluminum ?
Answer:
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Aluminium, or 26.981538 grams.
n physical changes, substances might change in ________ but not in ________.
Answer: Physical properties, but not in its identity
Explanation:
Physical changes only change the substances physical properties, not the substance’s identity
Rolf prepares four solutions using different solutes as shown in the table below.
Which solution is unsaturated?
Solution A
Solution B
Solution C
Solution D
Answer:
Solution A
Explanation:
Correct on Edge Cumulative Review Exam 2021
Have a blessed day
The unsaturated solution is the one where, the amount solute is lower than the solubility at a specific temperature. Hence, the solution A will form an unsaturated solution.
What is unsaturated solution?Unsaturated solutions are those having the lower concentration of solute than the saturation point of the solvent. Whereas, a saturated solution will completely dissolve the solute in its maximum amount and beyond a point the solute cannot be dissolved.
At a specific temperature gradient, if the dissolved solute is equal to the solvent's saturation point it will form a saturated solution. From the given table it is clear that except solution A all solutions have higher amount of solute than the saturation point.
As the solute concentration is higher, the solvent will try to dissolve maximum amount of the solute. Hence, in solution A have only 20 g of solute added but its saturation point is 37 g/100g. THus, the solution forms an unsaturated solution.
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What happens to your hypotheses as new information is gained
A mixture of amino acids (written as M) was tested against five known amino acids (written as 1 to 5) and the chromatogram was made. Which amino acids are found in the mixture M?
I can’t see the picture
Explanation:
density ________ as temperature ________ because the molecules lose energy and slow down, so the same number of molecules occupy less space.
This increased energy causes the molecules to move more rapidly, which in turn increases the volume of the substance. As the volume of the substance increases, its density decreases because the same amount of matter is spread out over a larger volume.
The density decreases as the temperature increases because the molecules lose energy and slow down, so the same number of molecules occupy less space. This happens because the increase in temperature causes the molecules to move more rapidly, increasing the space between them. The density of a substance is defined as its mass per unit volume. The density of a substance depends on its temperature, as well as its pressure and composition. As the temperature of a substance increases, the kinetic energy of its molecules also increases. This increased energy causes the molecules to move more rapidly, which in turn increases the volume of the substance. As the volume of the substance increases, its density decreases because the same amount of matter is spread out over a larger volume.
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Explain what is going on at the molecular level as your liquid sample cools down and
solidifies.
Answer:
Freezing. When a liquid is cooled, the average energy of the molecules decreases. At some point, the amount of heat removed is great enough that the attractive forces between molecules draw the molecules close together, and the liquid freezes to a solid.
Note how temperature effects the motion of the atoms or molecules in a liquid. As the temperature of a solid, liquid or gas increases, the particles move more rapidly. As the temperature falls, the particles slow down. If a liquid is cooled sufficiently, it forms a solid.
I hope it helps you:)Consider a biochemical reaction that is taking place in a 0. 1 M buffer. The initial pH is 7. 4, and the pKa of the buffer is 7. 2. If, in a final reaction volume of 1. 0 mL, 10 micromol of protons are generated, what would be the final pH of the solution?
The final pH of the solution would be 2.2
The final pH of the solution can be calculated using the Henderson-Hasselbalch equation, which states that the pH of a buffer solution is equal to the pKa of the buffer plus the logarithm (base 10) of the ratio of the concentration of the buffer's conjugate base to the concentration of its acid.
In this case,
The buffer is 0.1 M The pKa of the buffer is 7.2.The initial pH of the solution is 7.4, which means that the buffer is in its protonated form (the acid) at the start of the reaction.
When 10 micro mols of protons are generated, the buffer will lose protons and become the conjugate base. Therefore, the concentration of the conjugate base will increase and the concentration of the acid will decrease.
To calculate the final pH, we use the Henderson-Hasselbalch equation:
pH = pKa + log([conjugate base]/[acid])
We know that the pKa = 7.2, so the final pH will be equal to 7.2 + log([conjugate base]/0.1 - [conjugate base]).
To find the [conjugate base], we can use the stoichiometry of the reaction. We know that the reaction generates 10 micro mols of protons. We also know that the buffer has a 1:1 stoichiometry (1 acid: 1 conjugate base)
So [conjugate base] = 1010^-6 mol / 1 = 1010^-6 M
Therefore, the final pH = 7.2 + log(10*10^-6/0.1)
= 7.2 + log(10^-5) = 7.2 - 5 = 2.2
So the final pH of the solution would be 2.2
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pless answer thisss!!
the process by which the atoms of one or more substances are rearranged to form different substances is called a
Answer:
Chemical reaction
Explanation:
This process is called a chemical reaction. A chemical reaction is where atoms are rearranged to create various compounds, so the atoms can either be formed or broken.
For example, in this equation for the formation of water:
2H2(g) + O2(g) → 2H2O(l)
Here hydrogen and oxygen both combine to form water. This new compound, water, that has formed is what makes it a chemical reaction.
In this equation for the decomposition of calcium carbonate:
CaCO3(s) → CaO(s)+ CO2(g)
Here, CaCO3 has been broken down into CaO and CO2, which takes place as a chemical reaction.
Tea contains various acidic organic molecules called tannins. Given that, why is it helpful to us na2co3 in this experiment?.
Tannins are acidic organic molecules found in tea. In the experiment, Na2CO3 is helpful to us. When Na2CO3 is added to the tannin-containing tea, the tannins react with it and precipitate out. The process is known as the tannin test.Tea is made up of various components, including caffeine, tannins, and other substances.
Tannins are one of the most significant components of tea. Tannins are acidic organic molecules found in tea. The tannin test is used to detect these tannins. Sodium carbonate (Na2CO3) is used to perform the tannin test. When Na2CO3 is added to the tannin-containing tea, the tannins react with it and precipitate out. The precipitated tannins can then be used to determine the tannin concentration in the tea. The presence of tannins in tea has both good and harmful effects on human health.
The tannin test is a helpful tool for determining the tannin concentration in tea. When Na2CO3 is added to the tea, it reacts with the tannins and causes them to precipitate out. The precipitated tannins can then be collected and measured to determine the tannin concentration in the tea. Tannins are present in varying quantities in different types of tea. Green tea, for example, contains fewer tannins than black tea. The tannin concentration in tea has a significant impact on its taste. Tea with a higher tannin concentration tends to have a more bitter taste. Tannins can also cause tea to darken when it is brewed for too long..
The presence of tannins in tea can have both good and harmful effects on human health. To determine the tannin concentration in tea, the tannin test is used. Na2CO3 is used to perform the test, causing the tannins to precipitate out. The tannin concentration in tea varies depending on the type of tea.
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what action is not necessary before lighting a bunsen burner?
Answer:
Even though you didn't include any option choices in your question, I've searched it up anyways, and every source I found says that the answer is "Leave the gas stop open for a few minutes before lighting to clear the line."
Explanation:
Hope this is what you were looking for :)
If not, then I'm sorry.
950 J of energy is used to heat an unknown mass of copper from 20.0° C to 95.0° C. The specific heat of copper = 0.39 J/(g·°C).
What is the mass of the copper?
Answer:
32g
Explanation:
I just took the test and got it right
The mass of the copper is approximately 32.5 grams.
To find the mass of the copper, we can use the formula for heat:
Q = m * c * ΔT
where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature.
In this case, we are given:
Q = 950 J (heat energy)
c = 0.39 J/(g·°C) (specific heat)
ΔT = 95.0°C - 20.0°C
= 75.0°C (change in temperature)
Substituting these values into the formula, we can solve for the mass (m):
950 J = m * 0.39 J/(g·°C) * 75.0°C
Dividing both sides of the equation by (0.39 J/(g·°C) * 75.0°C), we get:
m = 950 J / (0.39 J/(g·°C) * 75.0°C)
m ≈ 32.5 g
Therefore, the mass of the copper is approximately 32.5 grams.
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What’s the correct answer to this problem?
thermochemistry problem Could you please type everything because when it says tutor is working on equation I cant see it only when its typed.
Answer
84.8485 g
Explanation
Initial temperature, T₁ = 148 °C
Final temperature, T₂ = 20.4 °C
ΔT = T₂ - T₁
ΔT = 20.4 - 148
ΔT = -127.6 °C
Since heat is released, i.e heat loss, then Q = -324.8 calories
specific heat of the lead bar, c = 0.0300 cal/g°C
Using Q = mcΔT, we can find m as shown below
\(\begin{gathered} -324.8=m\times0.0300\times(-127.6) \\ -324.8=-3.828m \\ \text{Divide both sides by -3.828} \\ -\frac{324.8}{-3.828}=-\frac{3.828m}{-3.828} \\ \Rightarrow m=84.8485\text{ g} \end{gathered}\)The mass of the bar is 84.8485 g
g take a deep breath. breathe in deeply and exhale. and again. in the presence of oxygen, which product pyruvate is the end product of glycolysis; and in the absence of oxygen, which metabolite lactate is the primary product responsible for acidic buildup in muscle; and which product oxamate favored as the final electron acceptor to regenerate nad and which product nadh is the electron carrier?
The byproduct of glycolysis in the presence of oxygen is pyruvate. Lactate is the main substance that causes acidic accumulation in muscle when oxygen is not present.
Oxamate is favored as the final electron acceptor to regenerate NAD, and NADH is the electron carrier. Glycolysis is the process through which all bodily cells generate energy. Pyruvate is the end product of glycolysis under aerobic conditions, and lactate under anaerobic conditions. Pyruvate proceeds through fermentation in the cell's cytoplasm if oxygen is not present. Fermentation comes in two flavors: Alcoholic fermentation causes the conversion of pyruvate to ethanol and CO2. This is an irreversible reaction that takes place in the cells of plants and fungi (like yeast cells).
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3. Which half-reaction equation represents reduction?
Answer:
Which half-reaction equation represents reduction?
answer is 2
Answer:
B CU2+ +2e- -> Cu
Explanation:
reduction means something opposite of the word
reduction means an electron is GAINED in the part before the arrow
it's the " + 2e- " part of the equation before the arrow or "->" part
oxidation is the LOSING of an electron so it would show up to the right of arrow or "->" of the equation as "+2e-"
both reduction & oxidation reactions are called "redox"
in a battery
anode is oxidation
cathode is reduction
anode is positive
cathode is negative electrode
decomposing compounds is electrolysis.
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The valency of silver in silver sulphide (Ag₂S).
Answer:
Explanation:a
1. How many mL of copper (II) sulfate of a 2.5M stock solution is needed to make 250 mL of 0.2M solution?
Answer:
20ml
Explanation:
using the formula;C1V1=C2V2
2.5×V1=0.2×250
2.5V1= 50
V1=50/2.5
V1=20L