A solid ball of inertia m rolls without slipping down a ramp that makes an angle θ with the horizontal. What frictional force is exerted on the ball?

Answer:

2450 J

Explanation:

Given that,

A 50Kg girl jumps off a 5-meter-high diving board.

We need to find the kinetic energy of the girl before she hits the water. At this point the kinetic energy becomes equal to the potential energy such that,

\(K=mgh\\\\K=50\times 9.8\times 5\\\\K=2450\ J\)

So, her kinetic energy right before she hits the water is equal to 2450 J.

The molar mass of a compound can be found by adding the molar masses of all of the atoms in the compound.

The molar mass of an atom can be found on the periodic table by looking at the atomic mass listed for that element.

For example, to find the molar mass of water (H2O), we would add the molar masses of two hydrogen atoms (2 x 1.01 g/mol) and one oxygen atom (16.00 g/mol) to get a total molar mass of 18.02 g/mol.

Another way is by finding the molecular formula of the compound, it can be done by analyzing the compound's chemical and physical properties and then using the mass spectrometer to determine the molecular weight.

In conclusion, the molar mass of a compound can be found by adding the molar masses of the atoms in the compound using the atomic masses listed on the periodic table, or by determining the molecular formula of the compound and using a mass spectrometer to find the molecular weight.

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Answer:hereeee for pointssss only

Explanation:

The acceleration of gravity on Ganymede will be \(g=0.35\ \frac{m}{s^2}\)

It is given that for a simple pendulum on Ganymede

Lenth= 1.00 m

the time period  T= 10.5 sec

The formula for a time period of simple pendulum will be

\(T=2\pi\sqrt{\dfrac{l}{g} }\)

By rearranging the formula

\(g=l\times (\dfrac{2\pi}{T} )^2\)

\(g=1\times (\dfrac{2\pi}{10.5} )^2=0.3577\frac{m}{s^2}\)

\(g=0.3577\ \frac{m}{s^2}\)

Thus the acceleration of gravity on Ganymede will be \(g=0.35\ \frac{m}{s^2}\)

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NC means North Carolina.

Answer:

The temperatures will increase.

Explanation:

What will happen is that the temperature will increase. This is because, in wind direction and weather forecasting, a wind that shifts from the south means that warmer air/temperatures are approaching whereas a wind shift from the north implies that cooler air/temperatures are approaching.

Answer:

The volume of a gas is dependent on pressure and temperature.

Explanation:

Pressure and temperature affect different gases differently giving varied conclusions to the exact volume of that gas.

:-befrank

A two-dimensional representation of a charged point object can be obtained by drawing a point object at the center of the two-dimensional plane, indicating the x-axis and y-axis, assuming that the charged point object has a positive charge, and drawing the radially directed outward electric field lines.

a. To draw a two-dimensional representation of a charged point object and specify a convenient x-y coordinate system to describe the electric field of the object in a plane, follow the below steps: Step 1: Draw a point object at the center of the two-dimensional plane, which represents the charged point object. Step 2: To describe the electric field of the object in a plane, it is necessary to establish a convenient x-y coordinate system. Therefore, choose an x-y coordinate system and indicate the x-axis and y-axis as horizontal and vertical lines respectively. Step 3: Assume that the charged point object has a positive charge. In this case, the electric field lines originate from the charged point object and extend to infinity. These electric field lines are radially directed outward from the charged point object. Step 4: By using the right-hand rule, the direction of the electric field vectors can be found. If the thumb represents the direction of the electric field, and the fingers represent the direction of the electric current, the fingers are curled in the direction that makes the thumb point in the direction of the electric field. Hence, the electric field vectors at every point on the x-y coordinate plane can be found. b. To make an electric field map by choosing an arbitrary position on your coordinate system, and draw the vector that represents the electric field at that point if the charged object were in space, follow the below steps: Step 1: Assume a point in the x-y coordinate plane. For instance, let us assume that the point is at (3,2) in the x-y coordinate plane. Step 2: Draw a straight line from the charged point object to the point (3,2).Step 3: The electric field vector should be drawn along this straight line that points away from the charged point object. This electric field vector is a segment of this line and is the direction of the electric field at the point (3,2).Step 4: By following the same method for multiple points on the x-y coordinate plane, an electric field map can be obtained.

A two-dimensional representation of a charged point object can be obtained by drawing a point object at the center of the two-dimensional plane, indicating the x-axis and y-axis, assuming that the charged point object has a positive charge, and drawing the radially directed outward electric field lines. To make an electric field map, an arbitrary point is selected in the x-y coordinate plane, a straight line is drawn from the charged point object to the selected point, and the electric field vector is drawn along this line that points away from the charged point object. By repeating this process for multiple points on the x-y coordinate plane, an electric field map can be obtained.

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The angular velocity depends on the length of the orbit and the orbital

speed of the telescope.

Response:

First question:

Second question:

Third question:

The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun

The orbital velocity of the telescope = The Earth's orbital velocity

First question:

\(Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}\)

The orbital velocity of the Earth = 29.8 km/s

The distance between the Earth and the Sun = 148.27 million km

The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77

Radius of the orbit, r = 149.77 million kilometer from the Sun

The length of the orbit of the James Webb telescope = 2 × π × r

Which gives;

r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers

Therefore;

\(Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199\)

Second question:

Centrifugal force force, \(F_{\omega}\) = m·ω²·r

Which gives;

\(F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m\)

\(Gravitational \ force, F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}\)

Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Mass of the Sun = 1.989 × 10³⁰ kg

Which gives;

\(F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx 0.00592 \cdot m\)

Which gives;

\(F_{\omega}\) < \(F_G\), therefore, the James Webb telescope has to accelerate away from the Sun

F = \(\mathbf{F_{\omega}}\) - \(\mathbf{F_G}\)

The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ 0.0005·m (away from the Sun)

Third part:

Other forces include;

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Answer:

A simple cell can be made by connecting two different metals in contact with an electrolyte

Answer:

520 n is the final momentum of the car and is also the final speed of the car

Explanation:

The final momentum is 250 newton.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.

On the other hand, a particle's momentum represents the length of time needed for a consistent force to bring it to rest.

Therefore, The final momentum is 250 newton.

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Light intensity can be estimated using either the total wave output, luminosity, or brightness.

Thus,  It is a measurement of the amount of power either emitted or reflected by a source. Intensity and luminosity work together to determine brightness.

Luminosity is the most widely used unit to measure light intensity because scientists typically find that examining the entire output spectrum is the most beneficial.

The intensity of light formula becomes eqI = fracLA/eq when luminosity L is substituted. The surface area of a sphere must be used as the denominator in the calculation to appropriately measure light intensity because light waves propagate in all directions.

Thus, Light intensity can be estimated using either the total wave output, luminosity, or brightness.

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The theoretical efficiency is greater than that of the actual efficiency of the engine. This is because heat engine always produces some waste heat.

The Second Law of Thermodynamics states that a heat engine cannot be 100% efficient. In practice, a heat engine is only 100% efficient when it is operating at about 30-50% efficiency.

If we were to multiply this by 100, we would get the efficiency as a percent: 49%. This is the theoretical maximum efficiency. If we were to actually build an engine, it would be less efficient than the theoretical engine. The theoretical engine that can achieve this theoretical maximum efficiency is called the Carnot Engine.

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Answer:

The SI unit of electric charge is the coulomb and is represented by the symbol C.

\( \large\sf \leadsto\pmb{ Symbol \: Unit \: For \: Electric \: Charge}\)

\( \sf \blue {The \: SI \: unit \: of \: electric \: charge \: is \: coulomb \: which \: is \: also \: represented \: as \: C!}\)

The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.

We have to find the acceleration using;

v = u - at

v = final velocity = 0 m/s

u = initial velocity = 35.6m/s

a = acceleration = ?

t = time = 0.35 s

u = at

a = u/t = 35.6m/s / 0.35 s

a = 101.7 ms-2

The force on the driver =  75kg ×  101.7 ms-2 = 7629 N

Using the principle of conservation of momentum;

Momentum before collision = momentum after collision

m1u1 +m2u2 = m1v1 + m2v2

Hence

(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2

13.12 = 4.8 + 2.3v2

13.12 - 4.8 = 2.3v2

v2 = 13.12 - 4.8/2.3

v2 = 3.6 m/s

Using the principle of conservation of linear momentum;

m1u1 + m2u2 = m1v1 + m2v2

(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v

v = 79.98 + 55.1/10.1

v = 13.37 m/s

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We believe that the shape of the universe is geometrically flat based on critical density of the CMB.

New measurements of the cosmic microwave background by the Atacama Cosmology Telescope find that the universe is flat, with a density matching the critical density. There is no evidence of deviation from flatness. According to ACT scientists, the interpretation that the deviation seen by Planck is a statistical fluctuation.”

The CMB is useful to scientists because it helps us learn how the early universe was formed. It is at a uniform temperature with only small fluctuations visible with precise telescopes. By studying these fluctuations, cosmologists can learn about the origin of galaxies and large-scale structures of galaxies and they can measure the basic parameters of the Big Bang theory.

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Answer:

i think answer is c

Explanation:

as formation water from steam condensed release heat

else all need heat

One cyclist is cycling at a speed of 17 km/hr while the other is cycling at a speed of 23 km/hr.

Let's denote the rate of the slower cyclist as "r" km/h. Then the rate of the faster cyclist is "r+6" km/h.

When they are cycling toward each other, their relative speed is the sum of their speeds. Therefore, we can set up the equation:

\(120 \ km = (r + r+6) \ km/h \times 3\) hours  (since together they both travel a total distance of 120 km)

Simplifying this equation:

\(120 \ km = (2r + 6)\  km/h \times 3 \ hours\)

\(40 \ km = (2r + 6) \ km/h\)

\(2r + 6 = 40 \ km/h\)

\(2r = 34 \ km/h\)

\(r = 17 \ km/h\)

So the slower cyclist is cycling at 17 km/h and the faster cyclist is cycling at 17+6=23 km/h.

Therefore, the speeds of cyclists are 17 km/h and 23 km/h.

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Answer:

Explanation:

a )

the value Vy at the top of the bullet's trajectory will be zero . At the top , only the horizontal component Vx will exist .

b )

At the top Vy = 0

initial velocity will have vertical component = 260 sin30 = 130 m /s

acceleration = - g = - 9.8

v = u - gt

o = 130 - 9.8 t

t = 13.26 s .

c )

Total time = Time of ascent + time of descent

= 13.26 + 13.26 = 26.52 s

d )

Range R = u² sin2Ф / g , where u is initial velocity , Ф is angle of throw , g is acceleration due to gravity .

R = 260² sin 2 x 30 / 9.8

= 5973.8 m .

The horizontal velocity was constant, so:

\(s = vt\)

\(s = 10\cdot9\)

\(s = 90\)

it traveled 90meters

Explanation:

Named Valles Marineris, the grand valley extends over 3,000 kilometers long, spans as much as 600 kilometers across, and delves as much as 8 kilometers deep. By comparison, the Earth's Grand Canyon in Arizona, USA is 800 kilometers long, 30 kilometers across, and 1.8 kilometers deep.

Answer:

60 seconds

Explanation:

bxdnfjrjrjjrjrjrj

Answer:

C. Photosynthesis

Explanation:

Photosynthesis is a process by which plants and photosynthetic bacteria obtain their food in presence of sunlight from water and carbon dioxide. They produce glucose as the food and oxygen is emitted as the byproduct. The equation for photosynthesis is - 6H2O+6CO2 → C6H12O6 + 6O2

Thus, the correct answer is 'C.Photosynthesis.'

The minimum voltage required to hoist the mass is approximately 0.024 V.

The force required to lift the 100 g mass is equal to its weight, which is given by:

F = m * g = 0.1 kg * 9.8 m/s^2 = 0.98 N

The force exerted by the motor is given by the torque it produces divided by the radius of the spool:

F = T / r

where F is the force, T is the torque, and r is the radius of the spool.

We can rearrange this equation to solve for the torque required to lift the mass:

T = F * r = 0.98 N * 0.01 m = 0.0098 N-m

To hoist the mass, the motor must produce at least this much torque. We are given that the motor has a stall torque of 20 mN-m at 6 V. The stall torque is the maximum torque the motor can produce when it is not rotating, so we can assume that it will produce less torque at higher speeds.

We can use the motor's torque-speed characteristics to determine the minimum voltage required to hoist the mass. Let's assume that the motor produces a torque proportional to the applied voltage, and that it reaches its maximum speed at the rated voltage. At this speed, the torque produced by the motor is zero, so we can write:

T = T_s * (V / V_r)

where T_s is the stall torque, V is the applied voltage, and V_r is the rated voltage.

Solving for the minimum voltage required to produce the torque required to lift the mass, we get:

V = (T / T_s) * V_r = (0.0098 N-m / 20 mN-m) * 6 V = 0.0039 * 6 V ≈ 0.024 V

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The maximum mass of a polar bear can sit on the floor before sinking is 3075 kg.

The mass of an object is constant and does not change with location, unlike weight which does change depending on the gravitational pull of the planet.

Mass can be determined by measuring the gravitational force on an object using a device called a balance or scale. The International System of Units (SI) unit of mass is the kilogram (kg)

The maximum mass of a polar bear that can sit on the ice floe before it sinks is determined by the buoyancy force. The buoyancy force is equal to the weight of the water that the ice floe displaces, which is equal to the volume of the ice floe multiplied by the density of seawater.

The volume of the ice floe is 3m2 * 1m = 3 m3.

The buoyancy force is 3m3 * 1025 kg/m3 = 3075 kg.

The mass of the polar bear that can sit on the ice floe before it sinks is equal to the buoyancy force. So the maximum mass of a polar bear that can sit on the ice floe before sinking is 3075 kg.

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τnet = (TL ‐ TR)R is the needed net torque just on pulley about the axle.

A flexible line, cord, rope, chain, or belt is fastened to the rim of a wheel termed as a pulley. To transport motion and energy, pulleys may be employed singly or in combination.

If TL and TR are really the stresses pulling there at left and the sides of the pulleys, respectively, the net torque here on pulley would then be defined as net = (TL - TR)R, in which R represents the radius of pulley (see Fig. 1). It is believed that positive torque moves in a clockwise direction.

This means that  τnet = (TL ‐ TR)R is the necessary formula for net torque.

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The correct realistic problem for the given equation is problem 1 in which the electric field strength of the disc is half its value at the center of the disk.

We know that,

Electric field of a charged disc at a distance along its axis is given by,

E = σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) )

Electric field at the centre of a charged disc is given by,

\(E_{c}\) = σ / 2 ε ( Since at centre, x = 0 )

Distance along the axis of a charged disk, where electric field strength's value is half its value at the center of the disk.

\(E_{x}\) = \(E_{c}\) / 2

σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) =  ( σ / 2 ε ) / 2

x / √ ( \(x^{2}\) + \(r^{2}\) ) = 1 / 2

4 \(x^{2}\) = \(x^{2}\) + \(r^{2}\)

3 \(x^{2}\) = \(r^{2}\)

x = r / √ 3 ,which is the correct distance, when magnitude is half its value from centre.

Electric field is a field that surrounds electrically charged particles that exerts force on other charged particles in the field.

Therefore, the given equation is suitable for Electric field of a charged disc at a distance along its axis where electric field strength's value is half its value at the center of the disk.

The given question is incomplete. The completed question is

You are given the following equation to solve a problem:

σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) = \(E_{c}\) = σ / 2 ε

Choose the most realistic problem for which this could be the correct equation.

1 ) At what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? Give your answer in terms of the disk's radius R.

2 ) At what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? Give your answer in terms of the disk's radius R.

3 ) At what distance along the axis of a charged square is the electric field strength double its value at the center of the square? Give your answer in terms of the square's side R.

4 ) At what distance along the axis of a charged square is the electric field strength half its value at the center of the square? Give your answer in terms of the square's side R.

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