A soccer ball player bounces the ball off her head, changing the velocity of the ball. She changes the x-component of the velocity of the ball from vix = 7.9 m/s to vfx = 5.9 m/s and the y-component from viy = −3.4 m/s to vfy = 4.5 m/s.

If the ball has a mass of 0.40 kg and is in contact with the player's head for 7.1 ms, determine the direction of the impulse (in degrees counterclockwise from the +x-axis) delivered to the ball.

The evidence that  lead to the development of the principle of mass energy equivalence are radioactivity, atomic spectra and photoelectric effect.

The Einstein energy equation or the mass defect and binding energy are related by Albert Einstein's formula is given as;

E = mc²

where;

The evidence that  lead to the development of the principle of mass energy equivalence are listed below:

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

The force exerted by the wood on the bullet is 399.01 N

Explanation:

Given;

mass of bullet, m = 0.0021 kg

initial velocity of the bullet, u = 497 m/s

final velocity of the bullet, v = 0

distance traveled by the bullet, S = 0.65 m

Determine the acceleration of the bullet which is the deceleration.

Apply kinematic equation;

V² = U² + 2aS

0 = 497² - (2 x 0.65)a

0 = 247009 - 1.3a

1.3a = 247009

a = 247009 / 1.3

a = 190006.92 m/s²

Finally, apply Newton's second law of motion to determine the force exerted by the wood on the bullet;

F = ma

F = 0.0021 x 190006.92

F = 399.01 N

Therefore, the force exerted by the wood on the bullet is 399.01 N

1.21 x 10^26  photons with a wavelength = 12 cm, must be absorbed to raise the temperature of your eye by 3.0 C. Assume the mass of the eye is 11 g and its specific heat is 4.0 J/g K.

λ = 12 cm = 0.12 m

T=3 C degrees.

m = 11 g, or 0.011 kg, and c = 4 J/g K, or 4000 J/kg K.

Suppose there are n photons.

One photon's energy is equal to hc/.

h is the Planck constant, and let c represent the speed of light.

n photons' energy, E = n h c /

Since this energy is used to increase the eye's warmth, n h c / = m c. Δ T\sn = m c T = (0.011 x 4000 x 3 x 0.12)/(6.63 x 10-34 x 3 x 108), where n = 1.21 x 1026.

The number of photons is 1.21 x 1026.

The term "photon" refers to an elementary particle that is a quantum of the electromagnetic field, which includes electromagnetic radiation like light and radio waves, as well as the force carrier for the electromagnetic force. The word "photon" is derived from the Ancient Greek "phôs, phtós," which means "light." The speed of light in a vacuum, which is 299792458 m/s (or 186,282 mi/s), is the only speed at which photons can travel because they have no mass[a]. The boson class includes the photon.

The behavior of photons exhibits wave-particle duality, exhibiting characteristics of both waves and particles. Like other elementary particles, photons are best understood by quantum mechanics.  The contemporary photon theory was developed by Albert Einstein in the first two decades of the 20th century, building on the work of Max Planck.

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The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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Answer:

In physics, power is the amount of energy transferred or converted per unit time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

SI unit: watt (W)

Derivations from other quantities: P = E/t; P = F·v; P = V·I; P = τ·ω

In SI base units: kg⋅m2⋅s−3

Answer:

As a student, what are your insights about this lesson? Write an essay on your

toughts about the types of drugs/subtance of abuse, discussing its description and

effects

Answer:

192.6N

Explanation:

Let's consider the forces acting on the beam:

Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.

Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.

Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.

Let's break down the forces acting on the beam:

Vertical forces:

W (weight of the beam) - T (vertical component of tension) = 0

T = W

Horizontal forces:

F_link (horizontal component of the force exerted by the link) = ?

To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.

Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:

F_link = W * sin(θ)

Let's substitute the given values:

W = 39.4 kg * 9.8 m/s^2

θ = 33.1 degrees

F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)

Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.

The  wavelength at which the object emits the most radiation is 1.12 micrometers.

We use  Wien's displacement law in order to find the wavelength at which the object emits the maximum radiation.

The temperature of the item has an inverse relationship with the peak wavelength of the radiation it emits according to Wien's displacement law,

The formula of  Wien's displacement law,  is given as

λ_max = b/T

where λ_max =e peak wavelength of emitted radiation,

T = temperature of the object in Kelvin, and

b = Wien's displacement constant 2.898 × 10^-3 mK.

T = 2310°C + 273.15 = 2583.15 K

λ_max = (2.898 × 10^-3 mK) / 2583.15 K

λ_max = 1.12 × 10^-6 m = 1.12 μm

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The momentum of the gold ball that represents the force exerted on the ball at the three moments described is vector B.

Momentum is a vector quantity resulted from the mass of a particle and its velocity. Momentum represents the force acting on the particle. Momentum is the implication of Newton's Second Law. Momentum can be formulated as:

P = m.v

where:

P = momentum

m = mass

v = velocity

Following the three moments, we can identify the vector that represent the force exerted on each moment. Let's discuss them further.

Once the golf ball is hit by a club from its stationary position, the force exerted on the golf ball will be in the same direction to the club movement. We assume in this case that the club hits the ball from the left to right. The force will move the ball from its stationary position to the right.

Once the ball is at maximum compression, the force is also at its maximum point. The direction of the force remains as the previous moment.

Lastly, once the ball starts to expand, the force declines. The ball will come to its end position once the momentum of the force becomes zero (0). The momentum of the force will decline since the force direction changes to the left as resulted of the frictional force from the air.

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Complete Question:

A stationary golf ball is hit by a club. while the club is in contact with the ball, the ball compresses, the club exerts maximum force when the ball is at maximum compression, and then the ball expands. the momentum of the golf ball after contact with the club is represented by the vector above. which of the following groups of vectors could represent the force exerted on the ball at the three moments described?

(Please refer to the picture attached below)

Answer:

The answer is air

Explanation:

Answer:

a)  F = 1.26 10⁵ N, b)  F = 2.44 10³ N, c)   F_net = 1.82 10³ N  directed vertically upwards

Explanation:

For this exercise we must use the relationship between momentum and momentum

         I = Δp

         F t = p_f -p₀

a) It asks to find the force

as the man stops the final velocity is zero

         F = 0 - p₀ / t

the speed is directed downwards which is why it is negative, therefore the result is positive

         F = m v₀ / t

         F = 63.5 7.89 / 3.99 10⁻³

         F = 1.26 10⁵ N

b) in this case flex the knees giving a time of t = 0.205 s

          F = 63.5 7.89 / 0.205

          F = 2.44 10³ N

c) The net force is

         F_net = Sum F

         F_net = F - W

         F_net = F - mg

let's calculate

         F_net = 2.44 10³ - 63.5 9.8

         F_net = 1.82 10³ N

since it is positive it is directed vertically upwards

Answer:

5 newtons

Explanation:

Just divide them

AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:

Explanation:

Answer:

B

Explanation:

no reason for this answer

Answer:

I know theirs South American coast he was there a lot

Answer: the force will increase 16 times

Explanation:

as the equation of the force is written, it's denominator is the distance squared

\(f = G\frac{m_{1}.{m_{2}}}{r^{2} }\)

so the distance is reduced by a factor of 4 ,the equation becomes\(f = G\frac{m_{1}.{m_{2}} }{{[r/4]}^{2} }\)

now as the distance r is divided by 4 the complete equation is multiplied by 16.

Answer:

wha is this .....................? same confusion

As the crew is adding one mile to the road each day, so the length of the road after 27 days is 79 miles.

A collection of skilled workers, including a supervisor, a construction manager, a distinct maintenance staff, and a team of specialist labourers, make up an efficient construction crew. Employees must actively participate in the prevention of hazardous situations as they have a significant role to play.

A road construction crew assists with new road and sidewalk creation, repairs to or improvements to current roads, and the burying of wires underneath the local roads. They are also known as vehicle restraining operators and highway maintenance operators.

The question is incomplete, find the complete question here

A construction crew is lengthening a road that originally measured 52 miles. The crew is adding one mile to the road each day. The length, L (in miles), after d days of construction is given by the following function. L = 52 + d. what is the length of the road after 27 days?

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Answer:896000 J

Explanation: K.E = 1/2*m*v^2

Answer:

The car has Kinetic energy. 896000 Joules

Explanation:

Kinetic energy formula: 1/2 (mass)(speed)^2

First you multiply 1120 by 1/2 and get 560

Then you take the square root of 40 (\(40x^{2}\)) and get 1600

Finally to get the answer multiply 560 by 1600 and your final answer should be 896000 Joules

The work done on the boxes and the energy spent is 700J while the power required to lift 4 boxes per minute is 2.8kW

This work done on an object is the force required to move that object from point A to point B.

Data Given;

This is the work done to move the boxes from point A to point B.

\(w = F.s\\F = ma = mg = 200N\\w = 200 * 3.5\\w = 700J\)

The work done to move the object is 700J

This is used to calculated the energy used to carry the work done and the formula is given as

\(E = force * displacement\\E = F.s\\E = 200 * 3.5\\E = 700J\)

The energy transferred when he lifts one box is 700J

Power is the rate at which energy is used with respect to time

\(P = E/t\\\)

The energy required to lift 4 boxes in one minutes is

\(700 * 4 = 2800\)

Now we can calculate the power used

\(P = Energy / time\\P = 2800 / 1 \\P = 2800W = 2.8kW\)

The power required to move four boxes in 1 minutes is 2.8kW

From the calculations above, the following was gotten

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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Given

\(\vec F = (4xz+y^2)\,\vec\imath + 2xy\,\vec\jmath + 2x^2\,\vec k\)

its curl would be

\(\nabla\times\vec F = \left(\dfrac{\partial(2xy)}{\partial z} - \dfrac{\partial(2x^2)}{\partial y}\right)\,\vec\imath - \left(\dfrac{\partial(4xz+y^2)}{\partial z} - \dfrac{\partial(2x^2)}{\partial x}\right)\,\vec\jmath + \left(\dfrac{\partial(4xz+y^2)}{\partial y} - \dfrac{\partial(2xy)}{\partial x}\right)\,\vec k\)

which reduces to the zero vector. Since the curl is zero, and \(\vec F\) doesn't have any singularities, \(\vec F\) is indeed a gradient field.

To determine what it is a gradient of, we look for a scalar function f(x, y, z) such that \(\nabla f = \vec F\). This entails solving for f such that

\(\dfrac{\partial f}{\partial x} = 4xz+y^2 \\\\ \dfrac{\partial f}{\partial y} = 2xy \\\\ \dfrac{\partial f}{\partial z} = 2x^2\)

Integrate both sides of the first equation with respect to x, which gives

\(f(x,y,z) = 2x^2z+xy^2 + g(y,z)\)

Differentiate both sides of this with respect to y :

\(\dfrac{\partial f}{\partial y} = 2xy = 2xy+\dfrac{\partial g}{\partial y} \\\\ \implies \dfrac{\partial g}{\partial y} = 0 \implies g(y,z) = h(z)\)

Differentiate f with respect to z :

\(\dfrac{\partial f}{\partial z} = 2x^2 = 2x^2 + \dfrac{\mathrm dh}{\mathrm dz} \\\\ \implies \dfrac{\mathrm dh}{\mathrm dz} = 0\implies h(z) = C\)

So it turns out that \(\vec F\) is the gradient of

\(f(x,y,z) = 2x^2z+xy^2+C\)

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

Answer: The energy released as thermal energy is 6.5 J

Explanation:

Energy stored by the spider when it relaxes is given by:

\(E_o=\text{Resilience}\times \text{Work}\)

We are given:

Resilience = 0.35

Work done = 10.0 J

Putting values in above equation, we get:

\(E_o=0.35\times 10\\\\E_o=3.5J\)

Energy released at thermal energy is the difference between the work done and the energy it takes to relaxes, which is given by the equation:

\(E_T=\text{Work done}-E_o\)

Putting values in above equation, we get:

\(E_T=(10-3.5)=6.5J\)

Hence, the energy released as thermal energy is 6.5 J

The energy released as thermal energy when 10 J of work is done to stretch silk will be 6.5 J

Thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.

Energy stored by the spider when it relaxes is given by:

\(\rm E_o=Resilience \ \times Work\)

We are given:

Resilience = 0.35

Work done = 10.0 J

Putting values in above equation, we get:

\(\rm E_o=0.35\times 10\)

\(E_o=3.5\ J\)

Energy released at thermal energy is the difference between the work done and the energy it takes to relaxes, which is given by the equation:

\(E_T=\rm Work done -E_o\)

Putting values in above equation, we get:

\(E_T=(10-3.5)=6.5\ J\)

Hence, the energy released as thermal energy is 6.5 J

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Answer:

Coulomb's law is:

\(F = \frac{1}{4*pi*e0} *(q1*q2)/r^2\)

First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:

N = (1/{e0})*C^2/m^2

then we have:

{e0} = C^2/(m^2*N)

And we know that N = kg*m/s^2

then the dimensions of e0 are:

{e0} = C^2*s^2/(m^3)

(current square per time square over cubed distance)

And knowing that a Faraday is:

F = C^2*S^2/m^2

The units of e0 are:

{e0} = F/m.

If a third resistor is added in SERIES, what changes happens to the....

When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.

The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.

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The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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A - B = (10i - 2j - 4k) - (i + 7j - k)

A - B = 9i - 9j - 3k

|A - B| = √(9² + (-9)² + (-3)²) = √189 = 3√19