A small town has two local high schools. High School A currently has 650
students and is projected to grow by 85 students each year. High School B
currently has 800 students and is projected to grow by 60 students each year.
Let A represent the number of students in High School A in t years, and let
B represent the number of students in High School B after t years. Write an
equation for each situation, in terms of t, and determine after how many
years, t, the number of students in both high schools would be the same.

Answer:

y = -2x -5

Step-by-step explanation:

Assuming that 6.8 means the area of the triangle, the height would be 1.94.

If this is incorrect, please, don't refrain to tell me. Thank you.

8 ounces for $1.47. It comes out to $0.07 per ounce compared to $0.12 per ounce.

Answer:Rite aid

Step-by-step explanation:

8 ounces for $1.47. It comes out to $0.07 per ounce compared to $0.12 per ounce.

The total cost of all the items mentioned can be expressed as

12.99 + 1.19 P = C

Given : Sara needs to purchase one notebook

Also it is given that pack of pencils is represented by P

Since a notebook costs = $ 12.99

And pack of pencils cost = $ 1.19

Thus the total cost can simply be represented by adding all the above mentioned items

this means it can be written as

12.99 + 1.19 P = C where C represents the total cost { given }

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Answer:

the answer is D

f ≥0

m≥0

f≤30

45m+30f≤30

Step-by-step explanation:

hope it help luvs

The constraints that represent the given situation in the question are; Option D;

f ≥ 0

m ≥ 0

f ≤ 30

45m + 30f ≤ 30

We are told that;

Thus; we can say that; m ≥ 0 and f ≥ 0

We are told that Mary doesn't want to deliver more than 30 French sessions in one week. Thus;

f ≤ 30

Combining all the inequalities, we can say that;

45m + 30f ≤ 30

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Answer:

12

Step-by-step explanation:

All the denominators are factors of 12.

There are 3 balanced strings in set T.

To count the number of balanced strings in the set T={0, 1, 2}, we can establish a bijection between the set of balanced strings and T itself. A balanced string is defined as a string in which the sum of its digits is a multiple of 3.

We can define a function f: T" -> T that maps each string in T" to T by preserving the balanced property. If a string in T" is already balanced, f returns the string itself. If the string is not balanced, f replaces the last digit with digit that makes the sum a multiple of 3.

By showing that this function is both injective (one-to-one) and surjective (onto), we establish a bijection. The bijection rule states that if two sets have a bijection between them, they have the same cardinality. Therefore, the number of balanced strings is equal to the number of elements in T, which is 3.

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Each side of cube is 100 cm.

In Maths or in Geometry, a Cube is a solid three-dimensional figure, which has 6 square faces, 8 vertices and 12 edges. It is also said to be a regular hexahedron.

Given that,

Volume of cube = 1 cubic meter

We know that,

1 m = 100 cm

Also  volume of cube = \(a^{3}\)

Then,

Volume of cube = 1000000 cm

                   \(a^{3}\)  = \(100^{3}\)

                   a = 100 cm

Hence, Each side of cube is 100 cm.

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The length and the width of the rectangle are 10x and 5x, respectively

Scale drawing involves enlarging or reducing the side length of a shape to create another shape by a constant scale factor, where the scale factor does not equal one.

The length and the width of the scale drawing is:

Length = 10 cm

Width = 5 cm

Let the scale ratio be

Ratio = 1 : x

So, the length and the width of the swimming pool are:

Length = 10 * x

Length = 10x

Width = 5 * x

Width = 5x

Hence, the length and the width of the rectangle are 10x and 5x, respectively

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Mr. Jackson had $7,625 before shopping.

We can calculate the total amount Mr. Jackson spent on presents for his grandchildren by multiplying the cost of each present ($225) by the number of grandchildren (17). This gives us a total of $3,825. Additionally, we know that Mr. Jackson placed $500 into his savings account after shopping.

To find out how much money he had before shopping, we can add the amount spent on presents and the amount placed into savings: $3,825 + $500 = $4,325.

Therefore, Mr. Jackson had $4,325 before shopping.

The calculation above assumes that the money spent on presents and the amount placed into savings were the only financial transactions. In reality, Mr. Jackson's total amount of money before shopping could have been different if there were other income or expenses that are not mentioned in the given information.

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The number of students in the telescope club by $x$ and the number of students in the math club by $y$.

$y=2x$Now, suppose there are $z$ students who are members of both clubs. Then the total number of students who are in the math club or the telescope club (or both) is given by:$x + y - z$ Substituting $y=2x$ in the above expression, we get:$x + 2x - z=3x - z$ Hence, the expression for the total number of students who are in the math club or the telescope club (or both) is $3x - z$.b)The number of students who are in the math club but not in the telescope club is given by:$y-z$ And the number of students who are in the telescope club but not in the math club is given by:$x-z$ Adding these two expressions, we get the total number of students who are in the math club or the telescope club but not both:$ y-z+x-z $.

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Answer:1/2 (1 over 2)

Step-by-step explanation:

Answer:

get it from some else pllease

Step-by-step explanation:

type this in

The graph shows a scuba diver's ascent over time. Use the graph to write an equation in slope-intercept form that represents the diver's depth over time.

Answer:

x^2

Step-by-step explanation:

ax^2 + bx + c is quadratic standard form

Answer:

Option c

Step-by-step explanation:

They represent the factors of the constant variable -20

x = 147 / 0.5446 ≈ 270.2 ft

To find the length of the guy wire for a radio transmission tower, trigonometry concepts are applied. Given a tower height of 160 feet, with the wire attached 13 feet from the top and making an angle of 29° with the ground, we can solve for the length of the guy wire, represented by x.

Using the Pythagorean theorem and considering the right triangle formed by the tower height, the wire attachment point, and the ground, we can set up the equation:

x = √((160 - 13)² + x²)

Next, we apply the tangent function to the given angle:

tan(29°) = (160 - 13) / x

Simplifying, we have:

0.5446 = 147 / x

To solve for x, we rearrange the equation:

x = 147 / 0.5446 ≈ 270.2 ft

Rounding to the nearest tenth of a foot, the length of the guy wire required is approximately 270.2 feet. This wire is attached 13 feet from the top of the tower and makes a 29° angle with the ground.

Trigonometry plays a crucial role in solving real-world problems involving angles and distances. It provides a mathematical framework for calculating unknown values based on known information, enabling accurate measurements and constructions.

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There are 16 bit strings of length eight that contain either three consecutive 0s or four consecutive 1s.

To count the number of bit strings of length eight that contain either three consecutive 0s or four consecutive 1s, we can use the principle of inclusion-exclusion.

Step 1: Count the total number of bit strings of length eight.

Each bit in the string can have two possible values (0 or 1), so the total number of bit strings of length eight is 2^8 = 256.

Step 2: Count the number of bit strings with three consecutive 0s.

We can treat the three consecutive 0s as a single block and consider the remaining five bits. The block of three 0s can start from the first position to the sixth position, so we have 6 choices for its starting position. The remaining five bits can have two possible values (0 or 1), so there are 2^5 = 32 choices for the remaining bits. Therefore, the number of bit strings with three consecutive 0s is 6 * 32 = 192.

Step 3: Count the number of bit strings with four consecutive 1s.

Similar to Step 2, we treat the four consecutive 1s as a single block and consider the remaining four bits. The block of four 1s can start from the first position to the fifth position, so we have 5 choices for its starting position. The remaining four bits can have two possible values (0 or 1), so there are 2^4 = 16 choices for the remaining bits. Therefore, the number of bit strings with four consecutive 1s is 5 * 16 = 80.

Step 4: Subtract the overlaps.

In Step 2 and Step 3, we have counted some bit strings twice. Specifically, there are bit strings that contain both three consecutive 0s and four consecutive 1s. To correct for this, we need to subtract the number of bit strings that have both patterns.

To have both patterns, we consider the starting position of the block of three 0s and the block of four 1s. The block of three 0s can start from the first position to the fourth position (leaving three positions for the block of four 1s). So, we have 4 choices for the starting position of the block of three 0s. The remaining three positions can have two possible values (0 or 1), so there are 2^3 = 8 choices for the remaining bits. Therefore, the number of bit strings with both patterns is 4 * 8 = 32.

Step 5: Calculate the final count.

To obtain the number of bit strings that contain either three consecutive 0s or four consecutive 1s, we subtract the overlaps from the total count:

Total count - Overlaps = 256 - 192 - 80 + 32 = 16.

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Answer: To find the point P that divides a segment AB into a particular ratio, determine the ratio k by writing the numerator over the sum of the numerator and the denominator of the given ratio. Next, find the rise and the run (slope) of the line. Finally, add (k. the run) to the x-coordinate of A and add (k.

Step-by-step explanation: Hope this helps :)

Question

Which algebraic expression has like terms?

\(9n^3 - 2n + 3 - 4n^2\)

\(7n^3 + 3n - 3 - 6n^2\)

\(7n^3 + 4n - 3n^3 - 5n^2\)

\(6n^3 - 4n^4 + 6n - 5n^2\)

Answer:

A. \(9n^3 - 2n + 3 - 4n^2\)

B. \(7n^3 + 3n - 3 - 6n^2\)

Step-by-step explanation:

Given:

The above expressions

Required:

Expressions with like terms

Algebraic expressions are said to have like terms if and only if the have the equivalent exponents;

Like terms are dependent on the exponents and are independent on the sign of each terms.

Listing out the exponents of each options;

A. \(9n^3 - 2n + 3 - 4n^2\)

The exponents of n are 3 1 0 2

Rearrange: 0 1 2 3

B. \(7n^3 + 3n - 3 - 6n^2\)

The exponents of n are 3 1 0 2

Rearrange: 0 1 2 3

C. \(7n^3 + 4n - 3n^3 - 5n^2\)

The exponents of n are 3 1 3 2

Rearrange: 1 2 3 3

D. \(6n^3 - 4n^4 + 6n - 5n^2\)

The exponents of n are 3 4 1 2

Rearrange: 1 2 3 4

From the list of exponents above, only A and B are equal;

Hence, the following expressions have the like terms

A. \(9n^3 - 2n + 3 - 4n^2\) and B. \(7n^3 + 3n - 3 - 6n^2\)

Step-by-step explanation:

put the point on -2 and make the line go left

It will take the town 21 years 4 months to reach 4600 in population

a rate is a ratio that compares two different quantities which have different units. For example, if we say John types 50 words in a minute, then his rate of typing is 50 words per minute. The word "per" gives a clue that we are dealing with a rate.

initial population = 3000

population increase every year = 2.5% of 3000

which is 2.5/100 x 3000 = 75

let the time taken to reach 4600 be d

increment for d number of years = 75d

Total population after d years is 75d + 3000

so 75d + 3000 = 4600

75d = 4600  - 3000

75d = 1600

d = 1600/75

d = 21.33 years which is 21 years 4 months

In conclusion 21 years 4 months is the time taken for the ton tto get tto 4600

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Explanation:

1) C = 5/9 f + 32

The start value is the constant = 32.

The start value = 32

Growth value = rate of change

Growth value = 5/9

2) y = 4000 - 250x

The start value is the constant = 4000

The start value = 4000

Answer:

28%

Step-by-step explanation:

i took the review and i got that one right pls make brainiest

Option C represents a modified Hardy-Weinberg equation that incorporates the effects of natural selection on a population. The equation is given as:

$(p-3s)^2 + 2(p-s)q + q^2 = 1$

In this equation, various terms are included to express the impact of natural selection. Let's break down the equation and understand its components.

$p$ represents the frequency of the dominant allele in the population, while $q$ represents the frequency of the recessive allele. These frequencies are determined based on the initial allele frequencies in the population.

The term $(p-3s)^2$ represents the expected frequency of the homozygous dominant genotype in the next generation. The factor $3s$ denotes the selection coefficient, where $s$ represents the frequency of homozygous recessive individuals who do not survive due to natural selection. By subtracting $3s$ from $p$, we account for the reduction in the frequency of the dominant allele due to selection.

The term $2(p-s)q$ represents the expected frequency of the heterozygous genotype in the next generation. This term incorporates both the initial frequency of the heterozygous individuals, represented by $(p-s)$, as well as the transmission of alleles through reproduction, given by $q$. The factor of 2 accounts for the two possible combinations of alleles in the heterozygous genotype.

Finally, $q^2$ represents the expected frequency of the homozygous recessive genotype in the next generation. This term considers the transmission of the recessive allele, represented by $q$, and its squared value accounts for the homozygous recessive genotype.

The equation is set equal to 1, as the frequencies of all genotypes should sum to 1 in a population.

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Answer:

x = 3

Step-by-step explanation:

4(x + 10) = 52

distributive property

4x + 40 = 52

4x = 12

x = 3

Answer:

x=3

Step-by-step explanation:

4(x+10)=52

simplify by distributing 4

4x+40=52

subtract 40 from both sides

4x=12

divide 4 from both sides

x=3

You have to show the picture of what your talking about. Please do so if you want someone to answer your question.

Answer:

x = 29.5

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos x = adj side/ hypotenuse

cos x = 67/77

Taking the inverse cos of each side

cos^-1( cos x) = cos^-1 (67/77)

x = 29.52626525

To the nearest tenth

x = 29.5

the probability that the next customer will pay with something other than a credit card as a decimal to the nearest hundredth is 0.93.

To calculate the probability that the next customer will pay with something other than a credit card, we need to know the total number of customers who paid cash or used a debit card.

The total number of customers who paid cash or used a debit card is the sum of the customers who paid cash and those who used a debit card:

Total customers who paid cash or used a debit card = customers who paid cash + customers who used a debit card = 76 + 10 = 86

Therefore, the probability that the next customer will pay with something other than a credit card is:

P = Total customers who paid cash or used a debit card / Total number of customers

P = 86 / (76 + 10 + 1) (adding 1 to account for the next customer)

P = 0.93

So the probability that the next customer will pay with something other than a credit card as a decimal to the nearest hundredth is 0.93.

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