After the collision, the velocity of the small cart is 0.870 m/s. The speed of the large cart after the collision is 0.027 m/s.
We can find the velocity of the large cart after the collision by applying the law of conservation of momentum which states that the total momentum of an isolated system remains constant if no external force acts on it.
Before the collision, the total momentum of the system was:
300 g × 1.50 m/s = 0.45 kg m/s
The momentum after the collision will also be 0.45 kg m/s since there is no external force acting on the system. The total momentum of the system after the collision can be expressed as the sum of the momenta of the two carts. Therefore, we can use the following equation to find the velocity of the large cart: 0.45 kg m/s = 0.3 kg × 0.870 m/s + 5 kg × v v = 0.027 m/s
The speed of the large cart after the collision is 0.027 m/s.
Here we have been given mass and velocity of two carts. These carts collide with each other and after the collision, the small cart recoils. We have to find out the velocity of the large cart after the collision.
For that, we will use the law of conservation of momentum which states that the total momentum of an isolated system remains constant if no external force acts on it.
Mathematically it can be written as:
M₁v₁ + M₂v₂ = M₁u₁ + M₂u₂
Here, M₁ = 0.3 kg, v₁ = 1.5 m/s (velocity of the small cart before collision), M₂ = 5 kg, v₂ = 0 m/s (velocity of the large cart before collision), u₁ = 0.87 m/s (velocity of the small cart after collision), and we have to find out the velocity of the large cart after collision which is u₂.
Using the above formula, we can write:
0.3 × 1.5 + 5 × 0 = 0.3 × 0.87 + 5 × u₂u₂ = 0.027 m/s
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questions 1) calculation of g (include all steps) percent error from 980 cm/s2 (show work) 2) length of a 1.00 sec simple pendulum show your work, or provide an explanation for how the length was determined
The answer is 1) the value of g is\(9.8 m/s^2.\) and 2) the length of a simple pendulum with a period of 1.00 second is approximately 0.245 meters.
1)Here is the Calculation of g (increasing speed due to gravity):
1) Calculation of g (acceleration due to gravity):
To calculate the esteem of g, we will utilize the equation:
g =\((acceleration) / (time^2)\)
Given:
Acceleration = \(980 cm/s^2\)
Time = 1 s
Converting acceleration to\(m/s^2:\)
\(980 cm/s^2 = 9.8 m/s^2\)
Substituting the values into the formula:
\(g = 9.8 m/s^2 / (1 s)^2\\g = 9.8 m/s^2\)
Therefore, the value of g is\(9.8 m/s^2.\)
2) 2) Length of a 1.00-second basic pendulum:
The length of a basic pendulum can be decided utilizing the equation:
T = 2π\(\sqrt{(L/g)}\)
where:
T = period of the pendulum
L = length of the pendulum
g = acceleration due to gravity
Given:
T = 1.00 s
g =\(9.8 m/s^2\)
Rearranging the formula to solve for L:
L = \((T^2 * g) / (4\)π\(^2)\)
Substituting the given values:
L = \((1.00 s)^2 * 9.8 m/s^2 /\)(4π\(^2)\)
L = 0.245 m
Therefore, the length of a simple pendulum with a period of 1.00 second is approximately 0.245 meters.
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A wave pulse travels along a horizontal string. As the pulse passes a pint on the string, the point moves vertically up and then back down again. How does the vertical speed of the point compare to the speed of the wave?
• the speed of the point equals the speed multiplied by the wavelength and divided by the string's length.
• the wave speed equals the point speed multiplies by the wavelength and divided by the string's length.
• the speed of the point is 2 times greater than the wave speed.
• the speed of the point could be neglected compared to the wave speed.
• the wave speed could be neglected compared to the speed of the point.
• the speeds could not be uniquely compared, because there is no fixed relationship between them.
Answer:
The vertical speed of the point is not directly related to the wavelength, but rather to the amplitude of the wave. Therefore, none of the options given are correct.
However, we can say that the vertical speed of the point depends on the frequency of the wave and the amplitude of the wave. The higher the frequency and/or amplitude of the wave, the greater the vertical speed of the point.
On the other hand, the speed of the wave is determined by the properties of the string, such as its tension and mass density. Therefore, the speeds of the point and the wave are not directly related, and cannot be compared in a fixed way.
A block glass of mass 187.5g is 5cm long t 2cm thick and 75cm high. calculate the density of the in kg/cm^3
Answer:.00025 or .25 x 10^-3
Explanation:weird units! Density=mass/volume=.1875 kg/(2x75x5).
A very myopic man has a far point of 32.3 cm. what power contact lens (when on the eye) will correct his distant vision?
p=3.0D contact lens is needed to correct his distant vision.
The person is suffering from myopia and hence need a concave lens to correct the defect. The lens should be such that an object at infinity must form its image at the far point.
Hence,f= -32.3cm
= -0.323m
we can define the power of the lens as the reciprocal of its focal length in metre.
The power of lens is the ability to converge and diverge rays of light.
The power of the lens can be obtained as:
p= 1/f
p=1/(-0.323)
p=3.0D
Thus,the power is 3.0D to correct his distant vision.
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Two vehicles are traveling when they enter an intersection and crash and stick together. Both have a mass of 1,650 kg and both are traveling at 15 m/s. If one is headed North and the other is headed East, after the collision they end up traveling NE together at what speed (in m/s)? Please input your answer as a positive number with two decimal places.
Answer:
10.61 m/s
Explanation:
To find the final speed, we will use the conservation of momentum in each direction, so we can write the following equations:
\(\begin{gathered} p_{ix}=p_{fx} \\ m_1v_{1x}+m_2v_{2x}=(m_1+m_2)v_{fx} \\ \text{and} \\ p_{iy}=p_{fy} \\ m_1v_{1y}+m_2v_{2y}=(m_1+m_2)v_{fy} \end{gathered}\)Where m1 and m2 are the mass of the vehicles, v1 and v2 are their respective velocities in each direction, and Vfx and Vfy are the final velocities in each direction.
If one of the vehicles is headed north, its horizontal velocity Vx = 0 m/s. In the same way if the other is headed east, its vertical velocity Vy = 0m/s
Therefore, we can replace the values and solve the first equation as:
\(\begin{gathered} 1650(0)+1650(15)=(1650+1650)v_{fx} \\ 24750=3300v_{fx} \\ \frac{24750}{3300}=v_{fx} \\ 7.5m/s=v_{fx} \end{gathered}\)In the same way, we can solve the second equation as:
\(\begin{gathered} 1650(15)+1650(0)=(1650+1650)v_{fy} \\ 24750=3300v_{fy} \\ \frac{24750}{3300}=v_{fy} \\ 7.5m/s=v_{fy} \end{gathered}\)Now, we know that the vertical and horizontal speed was 7.5 m/s. So, we can calculate the final speed using the Pythagorean theorem as:
\(\begin{gathered} v=\sqrt[]{(v_{fx})^2+(v_{fy})^2} \\ v=\sqrt[]{(7.5)^2+(7.5)^2} \\ v=\sqrt[]{56.25+56.25} \\ v=\sqrt[]{112.5}=10.61\text{ m/s} \end{gathered}\)So, the speed after the collision was 10.61 m/s
a 1.50 v battery supplies 0.450 w of power to a small flashlight for 20.0 min. (a) how much charge (in c) does it move?
The total number of charges moved to power up the light for 20 min is 3.75 x 10¹⁹
The voltage of the battery = 1.50 V
The power supplied by the battery = 0.45 W
The flashlight will glow for 20 min
The total number of charges moved during the flashing of the flashlight can be found using the formula,
I = P/V
where I is the current
P is the power
V is the voltage supplied
We also know that,
I = Q/t
Let us substitute this equation, with the above equation, and we get
Q = Pt/V
Now, let us substitute the known values in the above equation, we get
Q = 0.45 x 20 / 1.50
= 9 / 1.50
= 6 C
Then, the number of charges is
n = Q/e
where e is the charge of an electron
n = 6 / 1.6 x 10⁻¹⁹
= 3.75 x 10¹⁹
Therefore, the number of charges moved is 3.75 x 10¹⁹
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The open-loop transfer function of a unity feedback control system is given by G(s) = k / (s+2)(s+4)(s2+6s+25).
By applying Routh-Hurwitz criterion, determine (i) the range of k for which the closed-loop system will be stable and (ii) the values of k which will cause sustained oscillations in the closed-loop system. What are the corresponding oscillation frequencies?
The stability range for the parameter k is from 0 to infinity. Sustained oscillations happen when k ranges from 0 to 32, and the oscillation frequencies are ±4.
How to determine the stability of a control system
The Routh-Hurwitz criterion is a method used to determine the stability of a control system by analyzing the coefficients of the characteristic equation.
For a unity feedback control system with the given open-loop transfer function G(s), the characteristic equation is obtained by setting the denominator of G(s) equal to zero:
(s+2)(s+4)(s²+6s+25) = 0
By applying the Routh-Hurwitz criterion, we can determine the stability conditions:
(i) For the closed-loop system to be stable, all the coefficients in the first column of the Routh array must be positive. In this case, since the denominator has all positive coefficients, the range of k for stability is 0 < k < ∞.
(ii) To find the values of k that cause sustained oscillations, we need to identify when the first column of the Routh array contains a sign change. This occurs when the value of k causes the roots of the characteristic equation to have purely imaginary parts.
By solving the equation s²+6s+25 = 0, we find two complex conjugate roots: -3±4i. These roots correspond to sustained oscillations. By comparing the coefficients of the characteristic equation, we can determine that the range of k for sustained oscillations is 0 < k < 32.
The corresponding oscillation frequencies are given by the imaginary parts of the roots, which in this case are ±4.
Therefore, the range of k for stability is 0 < k < ∞, and sustained oscillations occur when 0 < k < 32 with corresponding oscillation frequencies of ±4.
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is boiling water in a kettle on a stove kinetic or potential energy?
Answer:
Boiling a kettle is an example of both thermal and kinetic energy. Thermal energy comes from a substance whose molecules and atoms are vibrating faster due to a rise in temperature. Heat energy is another name for thermal energy. Kinetic energy is the energy of a moving object.
it's kinetic!
in a following chapter we will be able to show, under certain assumptions, that the velocity v(t) of a falling raindrop at time t is v(t) = vt(1 − e−gt⁄vt)
The equation is given as v(t) = vt(1 − e^(-gt/vt)), where v(t) represents the terminal velocity of the raindrop, g is the acceleration due to gravity, and e is the base of the natural logarithm.
Under the assumptions made, we can establish the equation v(t) = vt(1 − e^(-gt/vt)) for the velocity of a falling raindrop at time t. This equation incorporates two key factors: the terminal velocity (v(t)) and the gravitational acceleration (g).
Terminal velocity is the maximum constant velocity achieved by an object falling through a fluid medium, such as air. It occurs when the drag force acting on the object equals the gravitational force pulling it downward.
The equation v(t) = vt(1 − e^(-gt/vt)) represents the variation of velocity with respect to time. As the raindrop falls, it accelerates due to the gravitational force. However, as it gains velocity, the air resistance opposing its motion increases until it reaches a point where the drag force matches the gravitational force.
At this point, the raindrop reaches its terminal velocity, denoted by v(t). The term (1 − e^(-gt/vt)) in the equation accounts for the decreasing effect of air resistance on the acceleration of the raindrop as it approaches terminal velocity.
Overall, this equation provides a mathematical representation of how the velocity of a falling raindrop changes over time, incorporating the effects of terminal velocity and gravitational acceleration.
It allows us to study and understand the behavior of raindrops as they descend through the atmosphere, considering the balance between gravity and air resistance.
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a. What are the defects of simple cell?
four negative charges of a magnitude of -6 nc each form a square, 12 cm on a side. find the magnitude of electric field at the center of the square.
If four negative charges of a magnitude of -6 nc each form a square, 12 cm on a side, the magnitude of electric field at the center of the square will be zero.
E = F / q
E = Electric field intensity
F = Force
q = Charge
They will all exert equal and opposite forces at the center of the square. So the diagonal forces will be equal in magnitude and opposite direction.
Let the four forces be Fa, Fb, Fc and Fd.
E = [ Fa + ( - Fb ) + Fc + ( - Fd ) ] / q
I Fa I = I Fb I = I Fc I = I Fd I
E = 0
Therefore, the magnitude of electric field at the center of the square will be zero.
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Which is one use of lasers
A. reproducing images to make them clearer
B. Producing a magnified image of the moon
C. Cutting an iron bar into two pieces
D. Making a leaf appear larger so it’s veins are visible
Answer:
c
Explanation:
because what else can the laser be used for
What is the electric field 6.44 m from the centre of the terminal of a Van de Graaff with a 9.82 m charge, noting that the field is equivalent to that of a 3.811C charge at the centre of the terminal?
The electric field at 6.44 m from the center of the terminal of a Van de Graaff generator with a 9.82 mC charge is 1530 N/C.
Electric field is a measure of the force that an electric charge experiences when it is placed in an electric field. The electric field at a point in space is proportional to the charge at that point and inversely proportional to the square of the distance from the point to the source of the field.
In this case, the electric field at 6.44 m from the center of the terminal of the Van de Graaff generator is equivalent to the field produced by a 3.811 C charge at the center of the terminal.
Using the formula for electric field, E = kQ / r^2, where E is electric field, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), Q is the source charge (3.811 C), and r is the distance from the source (6.44 m), we can calculate the electric field to be 1530 N/C.
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is your interest equal to zero, meaning the line passes through the origin? if not then did we miss something when we said f in equation 5 was only due to spring force
When the angle between the force and the displacement is more than 90 degrees, work might be negative. It can also be zero; if = 90, this will occur.
The spring force, which defines the force applied to an object by the end of an ideal spring, is the most well-known illustration of a force whose value varies on position. An ideal spring will exert a force on the object attached to one end that is proportionate to how much it is stretched, and a force that is proportional to how much it is compressed on the object linked to the other end.
The force must function in order to accomplish its mission have a component that is parallel to the motion's direction or the opposite.
We must compute an integral (a sum) to determine the work done if the force acting on the object is not constant while it is moving.
Assume that an external force with the x component Fx(x) is acting on the object, causing it to travel in a straight line (let's say along the x axis, from xi to xf). (Or, we understand the force Fx to be a function of x.)
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How much work is done on a pumpkin with a force of 24 newtons when you lift it 15 meters? *
Answer:
I'm not that busy solving but I'll tell you the formula that Force x distance is equal to work done
The work is done on a pumpkin when we lift it by 15 m with 24 N is 360 J
What is Work ?Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J).
i.e. Work(W) is force(F) times displacement(s).
W=F× s
When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.
Writing for it's dimension,
W=F× s
Force has dimension [L¹ M¹ T²]
Displacement has dimension [L¹]
multiplying both the dimensions Force and Displacement
we get,
dimension of Work [L² M¹ T²]
According to newton's second law of motion,
Force(F) is mass(M) times acceleration(a).
i.e. F=ma
Given,
Force = 24 N
Displacement = 15 m
W=F.s= 24*15 = 360 J
Hence work done on pumpkin is 360 J
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A physics professor uses an air-track cart of mass m to compress a spring of constant k by an amount x from its equilibrium length. The air-track has negligible friction. When she lets go, the spring launches the cart. What cart velocity should she expect after it is launched by the spring
Answer:
v = √k/m x
Explanation:
We can solve this exercise using the energy conservation relationships
starting point. Fully compressed spring
Em₀ = \(K_{e}\) = ½ k x²
final point. Cart after leaving the spring
\(Em_{f}\) = K = ½ m v²
Em₀ = Em_{f}
½ k x² = ½ m v²
v = √k/m x
which term describes a lens with a surface that curves outward like the exterior of a sphere?
Answer:
Convex lens
hope that helps you
A 20 kg rock is on the edge of a 100 meter cliff. What is the
potential energy of the rock and if the rock falls off the cliff,
what is its kinetic energy just before striking the ground?
a 361. 4 kJ
b 1kJ. 1 kJ
C 19. 6 kJ, 19. 6 kJ
d 10 kl. 5. 5 ku
Answer:
Explanation:substitute the values for equation PE=m/vg×
In an aqueous solution where the H+ concentration is 1 x 10-6 M, the OH concentration must be:
A. 14 x 10-6 M
B. 1 x 10-6 M
C. 1 x 10-7 M
D. 1x 10-8 M
E. 14 x 10-8 M
Answer:
D. 1×10⁻⁸ M
Explanation:
[H⁺] [OH⁻] = 10⁻¹⁴
(1×10⁻⁶) [OH⁻] = 10⁻¹⁴
[OH⁻] = 1×10⁻⁸
The concentration of hydroxyl ion will be \(10^{-8}\)M.
What is concentration?The amount of a chemical substance in a mixture is expressed by the substance's concentration.
Calculation of concentration.
Given data:
Concentration of H+ = 1 x \(10^{-6}\) M.
It is known that,
[\(H^{+}\)][\(OH^{-}\)] = \(10^{-14}\)M
Now, put the value of concentration of [\(H^{+}\)] in above equation.
[1× \(10^{-6}\)][\(OH^{-}\)] = \(10^{-14}\)M
[\(OH^{-}\)] = \(10^{-14}\) / [1× \(10^{-6}\)]M
[\(OH^{-}\)] = \(10^{-8}\)M
Therefore, the concentration of hydroxyl ion will be \(10^{-8}\)M.
Hence, the correct answer will be an option (D).
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A car has a weight of 10 000 N. A man takes 10 seconds to push the car 5 m using a force of 1000 N. calculate the work done
At a particular instant, a proton moves toward the east in a uniform magnetic field that is directed straight downward. The magnetic force that acts on it is
When a proton moves toward the east in a downward-directed magnetic field, the magnetic force acts perpendicular to both the velocity and the magnetic field. According to the right-hand rule, the force will be directed toward the south.
When a charged particle, such as a proton, moves through a magnetic field, it experiences a magnetic force. The direction of this force is determined by the right-hand rule, which states that if you point your thumb in the direction of the particle's velocity and your fingers in the direction of the magnetic field, then the force is directed perpendicular to both, according to the direction your palm faces.
In this scenario, the proton is moving toward the east, while the magnetic field is directed straight downward. When you apply the right-hand rule, you will find that the magnetic force on the proton is directed toward the south. Therefore, the correct answer is c) Toward the south. The force acts perpendicular to the velocity and the magnetic field, causing the proton to experience a sideways deflection toward the south.
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Complete question is:
At a particular instant, a proton moves toward the east in a uniform magnetic field that is directed straight downward. The magnetic force that acts on it is Group of answer choices
a) Upward.
b) Downward.
c) Toward the south
d) Toward the north.
e) Zero.
Can a apple fall from a tree and not break open?
Well as you've seen before most likely, an apple can fall right off a tree, and stay perfectly fine. its all dependent on the variables. What angle is the apple falling at? Whats the speed, height, even the size of the apple? We must take into aware anything can happen, but its all behind the variables.
Brainliest if helpful
P.S Fact Check with the second person who just answered
Answer:
yes
Explanation:
i had an apple tree and it happens all the time most often they don't break open.
Which table best describes the parts of the atom? A 3 column table with 3 rows. The first column is labeled particle with entries proton, electron, neutron. The second column is labeled charge with entries positive, 0, negative. The last column is labeled location with entries outside nucleus, outside nucleus, inside nucleus. A 3 column table with 3 rows. The first column is labeled particle with entries proton, electron, neutron. The second column is labeled charge with entries negative, 0, negative. The last column is labeled location with entries inside nucleus, outside nucleus, inside nucleus. A 3 column table with 3 rows. The first column is labeled particle with entries proton, electron, neutron. The second column is labeled charge with entries 0, negative, positive. The last column is labeled location with entries outside nucleus, inside nucleus, inside nucleus. A 3 column table with 3 rows. The first column is labeled particle with entries proton, electron, neutron. The second column is labeled charge with entries positive, negative, 0. The last column is labeled location with entries inside nucleus, outside nucleus, inside nucleus.
The table describes the basic components of atoms, which are protons, electrons, and neutrons.
The correct table is:
Particle Charge Location
Proton Positive Inside nucleus
Electron Negative Outside nucleus
Neutron 0 Inside nucleus
This table best describes the parts of the atom. The proton has a positive charge and is located inside the nucleus of the atom. The electron has a negative charge and is located outside the nucleus, in the electron cloud. The neutron has no charge, or a charge of 0, and is located inside the nucleus along with the protons. This table provides a clear and concise summary of the basic properties and locations of the three fundamental particles that make up an atom.
Protons are positively charged particles found inside the nucleus, while electrons are negatively charged particles found outside the nucleus. Neutrons have no charge and are also located inside the nucleus.
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what could you do to increase the final momentum of a golf ball?
Answer:
I would hit it as hard as you can with the club.
Explanation:
well one thing that I like to do is hit the golf ball as hard as possible with the club.
This is because for me, when I do that, I can normally get more momentum which means I also get a farther hit.
Obtain the theoretical values of nodal voltages for the analysis circuit using Kirchhoff's Laws.
(V1,V2,V3,V4,V12,V23,V24,V34)
The theoretical values of nodal voltages using Kirchhoff's Laws can be used in the analysis of an electrocardiogram (ECG) to identify potential cardiac abnormalities and diagnose specific heart conditions by providing important information about the electrical activity of the heart.
The ECG measures the electrical activity of the heart by detecting the changes in voltage that occur during each heartbeat. The electrical activity of the heart can be modeled using Kirchhoff's Laws, which describe how current and voltage behave in an electrical circuit. Abnormalities in the electrical activity of the heart can be detected by analyzing the ECG waveform and comparing it to the theoretical values of nodal voltages.
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--The complete Question is, How can the theoretical values of nodal voltages using Kirchhoff's Laws be used in the analysis of an electrocardiogram (ECG) to identify potential cardiac abnormalities and diagnose specific heart conditions? --
How long does it take a plane, traveling at a constant speed of 200 m/s, to fly once around a circle whose radius is 2750 m
Answer:
2000 and 156300
jade it jawaban nya
If I see the star Sirius in the constellation of Canis Major rise at 8 pm tonight, what time will it rise one week from now
Viewed from the same place, it will lag by about 4 minutes per day.
7 days later puts it at roughly 8:28 PM.
Which direction will thermal energy flow if you pick up a snowball with your bare hand? Thermal energy will flow from the snowball to your hand. Thermal energy will flow from your hand to the snowball. Thermal energy will not flow between your hand and the snowball.
Answer:
b. Thermal energy will flow from your hand to the snowball.
Explanation:
Answer:
B
Explanation:
A three-wheeled car moving along a straight section of road starts from rest, accelerating at 2.00 m/s
2
until it reaches a speed of 34.0 m/s. Then the vehicle moves for 57.05 at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the three-wheeled car in motion (in s)? 5 (b) What is the average velocity of the three-wheeled car for the motion described? (Enter the magnitude in m/s.) m/s
The three-wheeled car is in motion for approximately 17.00 seconds, and its average velocity for the motion described is approximately 20.36 m/s.
Part 1: Acceleration
Initial velocity, u = 0 m/s (starting from rest)
Acceleration, a = 2.00 m/s²
Final velocity, v = 34.0 m/s
Using the equation v² = u² + 2as, we can find the displacement (s) during the acceleration phase:
s = (v² - u²) / (2a)
s = (34.0² - 0²) / (2 * 2.00)
s ≈ 289 m
Part 2: Constant Speed
The car moves for a distance of 57.05 m at a constant speed.
Total distance covered:
Total distance = displacement during acceleration + distance at constant speed
Total distance = 289 m + 57.05 m
Total distance ≈ 346.05 m
Total time in motion:
Time = time during acceleration + time at constant speed + time to stop
Time = (v - u) / a + distance at constant speed / v + time to stop
Time = (34.0 - 0) / 2.00 + 57.05 / 34.0 + 5.00
Time ≈ 17.00 s
Average velocity:
Average velocity = Total distance / Total time
Average velocity = 346.05 m / 17.00 s
Average velocity ≈ 20.36 m/s
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Tom rides his motorcycle at a speed of 15 meters/second for an hour.
So, how far did he ride? Hint:1 hour is equal to the 60 minutes. 60 min =3600 seconds?
Answer:
1 hour to ride his motorcycle