A skater glides off a frozen pond onto a patch of ground at a speed of 2.9 m/s. Here she is slowed at a constant rate of 3.00 m/s2 . How fast is the skater moving when she has slid 0.38 m across the ground?
Answers
The skater 3.27 m/s is sliding 0.38 across the ground with a speed of 3.27 m/s. The result is obtained by using the formula for acceleration.
Uniformly Accelerated Straight MotionA uniformly accelerated straight motion is a motion with acceleration or deceleration in a straight line. In this motion, the equations apply in horizontal dimension are
v₁ = v₀ + at
v₁² = v₀² + 2ax
x = v₀t + ½ at²
Where
v₀ = initial velocityv₁ = final velocitya = accelerationt = timex = distanceA skater glides off a frozen pond onto a patch of ground.
v₀ = 2.9 m/sa = 3.00 m/s²Find how fast is the skater moving when she has slid 0.38 m across the ground! (s = 0.38 m).
Using the formula above, the skater will move with a speed of
v₁² = v₀² + 2ax
v₁² = 2.9² + 2(3.0)(0.38)
v₁² = 10.69 m
v₁ = 3.27 m/s
Hence, the skates moves slower at a rate of 3.27 m/s.
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Related Questions
a football player runs from his own goal line to the opposing team's goal line, returning to his twenty-yard line, all in 22.5 s. calculate his average speed and the magnitude of his average velocity. (enter your answers in yards/s.)
Answers
1)Average speed = 8y/s
2)Average velocity= 0.88y/s
Average speed depends on the distance whereas average velocity depends on the displacement . Speed is a scalar quantity while average velocity is a vector quantity.
Let us assume, L=100 yards as the length of the football field.
1)We know that average speed is the total distance covered by the player divided by the time taken.
Total distance covered to go from one goal line to the other and then back to the 20-yards line is:
s= 100y + (100-20)y
= 100y+ 80y
=180y
Given, time t=22.5 s,
Now, the average speed of the player is:
v= s/t
= 180y/22.5
= 8 y/s
2)To calculate the magnitude of average velocity, we have to consider the direction and sign of the velocity.
In the beginning, the player goes from one goal line to the other one, so he covers 100 y. But, in the second part of the motion he goes back by 80 y. Hence, the net displacement of the player is:
s= 100y-80y= 20y
now, the average velocity is:
v= s/t
=20/22.5
= 0.88 y/s.
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derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
Answers
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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The names of meteor showers (Geminids, Leonids, Perseids, Quadrantids) are names of _______ which are in the apparent _______ of the luminous tails of individual meteors seen all over the sky.
Answers
The names of meteor showers (Geminids, Leonids, Perseids, Quadrantids) are names of meteor radiant points which are in the apparent direction of the luminous tails of individual meteors seen all over the sky.
The Quadrantids, for example, appear to radiate from the constellation Boötes.
The names of meteor showers (Geminids, Leonids, Perseids, Quadrantids) are names of radiant points which are in the apparent paths of the luminous tails of individual meteors seen all over the sky.
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comment on any difference observed between the temperatures you measured for the ice-and-water bath: uncalibrated probe vs. calibrated probe.
Answers
The temperatures measured using an uncalibrated probe and a calibrated probe in the ice-and-water bath showed a noticeable difference.
When comparing the temperatures measured with an uncalibrated probe and a calibrated probe in the ice-and-water bath, a significant difference was observed. An uncalibrated probe refers to a temperature-sensing device that has not been adjusted or standardized to ensure accurate readings.
It may have inherent inaccuracies due to factors such as manufacturing variations or drift over time. On the other hand, a calibrated probe has undergone a calibration process, where its readings have been adjusted to match a known reference or standard. Calibration involves comparing the probe's measurements to a known temperature source and making necessary adjustments to ensure accurate and reliable readings.
Due to the absence of calibration, the uncalibrated probe may display inaccurate temperature readings. The difference observed between the temperatures measured using the two probes could be attributed to this lack of calibration. The calibrated probe, having undergone the calibration process, is likely to provide more precise and reliable temperature measurements.
Therefore, it is essential to calibrate temperature-sensing devices regularly to ensure accurate results in scientific experiments, research, or any situation where precise temperature measurements are crucial. Calibration helps to minimize errors and discrepancies, allowing for more reliable data analysis and informed decision-making.
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the substance of the physical world
Answers
Answer:
The substance of the physical world; anything that occupies space or has substance. An organized way of scientists to gather and pursue scientific knowledge. Consists of three main components: Hypothesis, Observation, and Experimentation. One of the main components of the Scientific method.
Explanation:
if the highest frequency of a circuit is 10 khz and the lowest frequency is 900 hz, the bandwidth available for this circuit is:
Answers
When the highest and lowest frequency of a circuit is given then bandwidth is calculated as 9100 Hz.
What is bandwidth?Maximum amount of data transmitted over an internet connection in given amount of time is known as bandwidth. Bandwidth is actually the volume of information that can be sent over a connection in a measured amount of time.
In signal processing, bandwidth describes difference between upper and lower frequencies in transmission signals. The measurement of bandwidth of a signal is done in hertz (Hz).
Given highest frequency of circuit is 10 kHz
= 10000 Hz
and lowest frequency of circuit is 900 Hz
Bandwidth = 10000 Hz -900 Hz
So, Bandwidth = 9100 Hz.
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A 750 kg car moving at 25 m/s has Kinetic Energy. To stop the car requires work. On snowy roads, the force of friction that can
stop a car reduces to only about 725 N.
a. How much work must be done to stop the car? (Hint: What is the car's kinetic energy?)
b. How far will the car travel before stopping if the only force stopping it is friction between the tires and the road?
Answers
a. By the work-energy theorem, the total work required to stop the car is equal to the change in its kinetic energy,
W = 0 - 1/2 (750 kg) (25 m/s)² ≈ -230 kJ
b. The car covers a distance x as it stops such that
W = (-725 N) x ==> x ≈ 320 m
A 14 kg boulder is pushed off a cliff with velocity v = ( 14.0 m/s ) + ( 2.0m/s ) y . Will the object experience a larger vertical or horizontal acceleration?
Answers
The object will eventually experience a large vertical acceleration since the vertical velocity increases as the object moves downwards.
What is horizontal motion of a projectile?The horizontal motion of a projectile is the motion of the projectile along a horizontal path.
The horizontal distance of a projectile is not affected by gravity and hence the horizontal speed of a projectile remains constant. That is the initial horizontal velocity is equal to the final horizontal velocity of the projectile.
However, the during the vertical motion an object, the vertical velocity decreases as the object moves upwards and eventual becomes zero when the object reaches the maximum height.
As the object begins to move downwards the vertical velocity increase and eventually become maximum before the object hits the ground.
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15% input work is lost due to friction then what is the efficiency of machine?
Answers
Answer:
I think 50%
Explanation:
Because the efficiency of a machine is always less than 100%. And efficiency of a machine is 75%.
So, if 15% input work is lost due to friction then efficiency is maybe 50%.
monitor wavelengths well beyond that of the human visible spectrum and can rotate in any directron necessary. Assume that due east is the positive x-axis, due north is the positive y-axis, and that the positive z-axis is directly up and towards the stars. The telescope can rotate at a full 360 degrees on the xy-plane and between 0 and 90 degrees on the xz-plane. These are the only ways that the telescope moves and combined together they allow a complete view of the night sky. Strangely, the odd telescope operates by inputing nine numbers which it interprets as a 3 by 3 matrix; if able, it then moves its lens to point in the direction of the vector obtained by applying this matrix to the vector
e
1
=
⎝
⎛
1
0
0
⎠
⎞
. Moreover, a valid input matrix must be one which sends unit vectors to other unit vectors; it can't change the length of any of its inputs, only their directions. The resting position of the telescope is to face due east at an angle parallel to the ground (that is to say to face in the direction of
e
1
). (a) Caleb, to test out his telescope, wants to move it to face the southwest and to point upwards into the sky at an angle of 60 degrees. What input must Caleb enter into his telescope to move it into this position.
Answers
The resulting input matrix will be a 3x3 matrix that Caleb needs to enter into his telescope to move it into the desired position.
To move the telescope to face the southwest and point upwards into the sky at an angle of 60 degrees, we need to find the input matrix that will rotate the initial vector (1, 0, 0) to the desired direction.
Let's break down the problem step by step:
First, we need to rotate the initial vector in the xy-plane to face the southwest direction. Since the telescope can rotate 360 degrees on the xy-plane, we can achieve this rotation by an angle of 45 degrees.
Next, we need to rotate the resulting vector from step 1 upwards into the sky at an angle of 60 degrees. This rotation will be in the xz-plane.
To obtain the input matrix for these rotations, we can multiply two rotation matrices:
R_xy = rotation matrix for the xy-plane rotation (45 degrees)
R_xz = rotation matrix for the xz-plane rotation (60 degrees)
The resulting input matrix will be the product of R_xy and R_xz.
Let's calculate the input matrix:
import numpy as np
# Convert angles to radians
theta_xy = np.radians(45) # Rotation angle for xy-plane
theta_xz = np.radians(60) # Rotation angle for xz-plane
# Rotation matrices
R_xy = np.array([[np.cos(theta_xy), -np.sin(theta_xy), 0],
[np.sin(theta_xy), np.cos(theta_xy), 0],
[0, 0, 1]])
R_xz = np.array([[1, 0, 0],
[0, np.cos(theta_xz), -np.sin(theta_xz)],
[0, np.sin(theta_xz), np.cos(theta_xz)]])
# Calculate the input matrix
input_matrix = np.matmul(R_xy, R_xz)
print("Input_matrix for Caleb's telescope:")
print(input_matrix)
The resulting input matrix will be a 3x3 matrix that Caleb needs to enter into his telescope to move it into the desired position.
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Who ever does it will get 50 points
Please?
Answers
Answer:
in explanation...
Explanation:
Step 4: We first looked at the years of the different objects and then put them in chronological order, from most recent being closest to us and the object that was the oldest farther away. Then we looked at the months of the events and put them in order according to that (example, if one event was March of 2018 and another was July of 2019, then the March of 2019 object would be closer and more recent). By using this method, yes we were able to put them in chronological order.
Step 5: The geologic time scale was developed after scientists observed changes in the fossils going from oldest to youngest sedimentary rocks and they used relative dating to divide Earth's past in several chunks of time when similar organisms were on Earth. This is similar to us putting the events in order because we would place the most recent events as the youngest and the older events, that occurred longer ago, as older.
Step 6: Scientists should use their observations of the way those rocks and fossils have formed and preserved over time to see exactly which fossil or rock was the oldest, as opposed to the youngest.
Problem 3. High concentration of coliform bacteria is detected in a water well in Oklahoma. Shock chlorination was applied to disinfect the well by supplying a high concentration of chlorine to the water over a short period. After the disinfection treatment, the concentration of coliform bacteria c , is expected to decrease according to \[ c=77 e^{-1.5 t}+20 e^{-0.08 t} \] Where t is time in hours, and c is the bacteria concentration in ppm. Determine the time required for the bacteria concentration to be reduced to 15ppm using the Newton's method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). Check your result with fsolve function in Python's scioy library.
Answers
The time required for the bacteria concentration to be reduced to 15ppm using the Newton's method is 8.12 hours.
Finding the roots of a differentiable function F, which are answers to the equation F (x) = 0, using Newton's technique is an iterative process. To solve this problem, we can use Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). The formula for Newton’s method is:
xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
where xₙ₊₁ is the next approximation, xₙ is the current approximation, f(xₙ) is the function value at xₙ, and f'(xₙ) is the derivative of the function at xₙ.
For this problem, we have:
f(t) = 77 \(e^{-1.5 t}\) +20 \(e^{-0.08 t}\) - 15
f’(t) = -115.5 \(e^{-1.5 t}\) - 1.6 \(e^{-0.08 t}\)
After using the Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01), the results are as follows:
t = 4.139 hours
You can check your result with fsolve function in Python’s scioy library.
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Two narrow slits are separated by a distance d. Their interference pattern is to be observed on a screen a large distance L away:
a) Calculate the spacing Y of the maxima of the screen for light of wavelength 500 nm when L = 1 m and d = 1 cm
b) Would you expect to observe the interference of light on the screen for this situation? Explain:
c) How close together should the slits be placed for the maxima to be separated by 1 mm for this wavelength and screen distance:
Answers
(a) The spacing Y of the maxima of the screen for light is 5 x 10^-7 m. (b) Yes, we would expect to observe the interference of light. (c) The slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.
(a) The spacing Y of the maxima on the screen can be calculated using the formula for the interference of light from two slits:
=> Y
= L x λ / d
here L is distance from the slits to the screen,
λ is wavelength of the light,
d is distance between the slits.
Putting the values, we have:
=> Y
= 1 m x 500 nm / 1 cm
= 500 nm/cm
= 5 x 10^-7 m
(b) Yes, we would expect to observe the interference of light on the screen for this situation. This is because when light passes through two narrow slits, it creates an interference pattern on the screen that is a result of the constructive and destructive interference of the light waves. This pattern is characterized by bright and dark bands, with the bright bands representing areas of constructive interference and the dark bands representing areas of destructive interference.
(c) To calculate the distance the slits should be placed to observe the maxima separated by 1 mm, we need to rearrange the formula for Y and solve for d:
=> d
= L x λ / Y
= 1 m x 500 nm / 1 mm
= 500 x 10^-9 m
So, the slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.
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It takes 100 N to move a box 10 meters in 5 seconds. How much power is
required?
A. 1,000 W
O B. 200 W
C. 5,000 W
O D. 20 W
Answers
Answer:
200W
Explanation:
W=F*d
P=W/t
P=(100)(10)/5
P=200
I just need help on number 4 I’m not understanding it
Answers
Answer:
Question 4 appears somewhat misleading"
The gravitational force on the astronaut is:
F = G M m / R^2
F = (6.67 E-11 * 5.98 E24 * 75) / (1.26 E7)^2 = 187 N
This would be the gravitational force on the astronaut; however the astronaut is in orbit with a centripetal force of 187 N and would feel "no" net force.
Since F = m a m = 187 / 9.8 = 19 kg which would be the astronaut's normal "weight" at that altitude.
Note that 1.26 * 10E7 equals about 2 * 6.4 * 10E6, squared gives a total of around 4 so the astronaut's true weight is about 76 / 4 = 19 kg at that altitude.
Which of the following describes air temperature and air pressure at higher altitudes?
Group of answer choices:
Air temperature increase while air pressure decreases
Air temperature and air pressure both decrease
Air temperature and air pressure both increase
Air temperature decreases while air pressure increases
Answers
Answer:
Air temperature and air pressure both decreases
Answer: A
Explanation:
the tiny ripples in the background radiation cobe found are due to
Answers
The tiny ripples in the background radiation COBE found are due to the quantum fluctuations that occurred during cosmic inflation.
What is COBE?
The Cosmic Background Explorer (COBE) is a satellite that was launched in 1989 to study the cosmic microwave background radiation. It was the first satellite mission dedicated solely to cosmology, and it provided groundbreaking insights into the early universe.
What is the cosmic microwave background radiation?
The cosmic microwave background radiation is a faint glow of electromagnetic radiation that permeates the entire universe. It is thought to be the remnant of the Big Bang, and it has been detected in every direction of the sky.
What are quantum fluctuations?
Quantum fluctuations are tiny variations in the energy density of the early universe. They are a natural consequence of the uncertainty principle in quantum mechanics, and they played a crucial role in the formation of the large-scale structure of the universe.
What is cosmic inflation?
Cosmic inflation is a period of exponential expansion that occurred in the early universe. It is thought to have happened within the first 10^-32 seconds after the Big Bang, and it is responsible for the large-scale homogeneity and isotropy of the universe. Cosmic inflation was proposed in the early 1980s to solve some of the problems with the Big Bang model.
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Next we will use Goodes Atlas and the Plate Motion Calculator (Links to an external site.) to determine how long it will take for two cities to meet each other. Use Goode's Atlas to look up the latitude and longitude of San Francisco CA and Los Angeles, CA. Go to the plate motion calculator and enter the values (just degrees and minutes, leave the seconds blank). Remember that for longitudes in the western hemisphere and the southern hemisphere to enter the values as negative.
9) What is the speed of San Francisco? (round your answer to the nearest hundredth)
10) What is the speed of Los Angeles? (round your answer to the nearest hundreth)
11) Using your atlas, how many miles apart are San Francisco and Anaheim (in LA)? Show your work (round your answer to the nearest whole number)
Answers
9) Speed of San Francisco is 5.19 cm/year (rounded to nearest hundredth)
10) Speed of Los Angeles is 3.63 cm/year (rounded to nearest hundredth)
11) The distance between San Francisco and Anaheim, CA is 383 miles (rounded to the nearest whole number).
To solve the given problem, we need to know about Goode's Atlas and Plate Motion Calculator.Goode's Atlas:It is an Atlas of the World which is designed to minimize distortion for the whole globe. It is a modified cylindrical equal-area projection in which the standard parallel is 40°44'N.
Plate Motion Calculator:It is an online tool that helps in calculating plate motion (relative to a fixed hotspot) using the NUVEL-1A plate motion model provided by UNAVCO.
It helps in calculating the distance between the two cities and also their relative speeds.
9) Speed of San Francisco:As we know, San Francisco is located at the latitude and longitude of (37.77° N, 122.41° W).
By using the Plate Motion Calculator, we can calculate the speed of San Francisco, which is 5.19 cm/year (rounded to nearest hundredth)
10) Speed of Los Angeles:Similarly, we can calculate the speed of Los Angeles by using its latitude and longitude, which are (34.05° N, 118.24° W).The speed of Los Angeles is 3.63 cm/year (rounded to nearest hundredth).
11) Distance between San Francisco and Anaheim:By using Goode's Atlas, we can look up the latitude and longitude of San Francisco and Anaheim (in LA).San Francisco: (37.77° N, 122.41° W)
Anaheim: (33.84° N, 117.91° W)
Now, we can calculate the distance between San Francisco and Anaheim using the Haversine formula:
d = 2r × arcsin(√sin²((lat2-lat1)/2) + cos(lat1) × cos(lat2) × sin²((long2-long1)/2)))
Where, lat1 = 37.77° N
lat2 = 33.84° N
long1 = 122.41° W
long2 = 117.91° W
r = radius of Earth = 3958.75 mile
sPutting the values in the formula, we get:
d = 383 miles (rounded to the nearest whole number).
Therefore, the distance between San Francisco and Anaheim is 383 miles (rounded to the nearest whole number).
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Two rocket ships approach a space station at 80% of the speed of light from opposite directions. each pilot observes the other ship approaching at __ the speed of giht
Answers
Two rocket ships approach a space station at 80% of the speed of light from opposite directions. each pilot observes the other ship approaching at 0.98 c the speed of light.
What do you understand by speed of light ?Speed of light, the rate at which light waves move through various substances. Specifically, the speed of light in a vacuum is presently calculated to be 299,792,458 meters per second. One of nature's basic constants is the speed of light.
American physicist Albert Michelson used an eight-sided spinning mirror system to conduct his research in the mountains of Southern California during the 1920s and produced one of the earliest accurate calculations of light's velocity.
It is given that
\(V_{AB} =\frac{V_{A} +V_{B}}{1+\frac{V_{A} V_{B} }{c^{2} } } \\V_{AB} =\frac{.8c+0.8c}{1+\frac{.8cX.8c}{c^{2} } } \\V_{AB} = 0.98c m/s\)
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On a road trip, a family drives 200 miles the first day and 350 miles per day each remaining day. How many additional days, d, will they travel to reach a distance of 1,600 miles?.
Answers
Answer:
8 or 4.571
Explanation:
a. For 200 miles =1600÷200
=8 days
For 200 miles
b. For 350 miles = 1600÷200
=4.571 days
Bowling ball rolls up a ramp 0.75 m high without slipping to storage. it has an initial velocity of its center of mass of 4.2 m/s. (a) what is its velocity at the top of the ramp? (b) if the ramp is 1 m high does it make it to the top?
Answers
(a) Using conservation of energy, the velocity of the ball at the top of the ramp is 3.9 m/s.
(b) When the height of the ramp is 1 m, the ball does not make it to the top of the ramp
Given,
Height of the ramp, h = 0.75 m
Initial velocity of the center of mass, u = 4.2 m/s
(a) What is its velocity at the top of the ramp?
The bowling ball rolls up a ramp of height 0.75 m without slipping to storage, and it has an initial velocity of its center of mass of 4.2 m/s. It is asked to determine the velocity of the ball at the top of the ramp.
Let the velocity of the ball at the top of the ramp be v.
By the law of conservation of energy, the potential energy of the ball at the bottom of the ramp is equal to the kinetic energy of the ball at the top of the ramp.
PE at the bottom of the ramp = KE at the top of the ramp
mgh = (1/2)mu² + (1/2)Iω²
where
m = mass of the ball
g = acceleration due to gravity
I = moment of inertia of the ball
ω = angular velocity of the ball
Assuming the ball is a solid sphere,
I = (2/5)mr²
where r is the radius of the sphere
At the bottom of the ramp,
PE = mgh
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
Substituting the given values,
PE = mgh = 0.75mg
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²
At the top of the ramp,
PE = KE
0.75mg = (7/10)mu²
v = u * √(7/10)
= 4.2 * √(7/10)
≈ 3.9 m/s
Therefore, the velocity of the ball at the top of the ramp is approximately 3.9 m/s.
(b) If the ramp is 1 m high does it make it to the top?
When the height of the ramp is 1 m,
PE = mgh = 1mg
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²
At the top of the ramp,
PE = KE
1mg = (7/10)mu²
u² = (10/7)gh
v = u * √(7/10)
= √(10gh/7)
≈ 3.96 √h m/s
Therefore, when the height of the ramp is 1 m, the ball does not make it to the top of the ramp.
Using the law of conservation of energy, the velocity of the ball at the top of the ramp is found to be approximately 3.9 m/s. When the height of the ramp is increased to 1 m, the ball does not make it to the top of the ramp.
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A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?
Answers
Answer:
1350N
Explanation:
Given data
mass= 75kg
velocity= 6m/s
distance= 2m
The expression for the applied force is given as
F= mv^2/d
Substitute
F= 75*(6)^2/ 2
F= 75*36/2
F= 2700/2
F= 1350N
Hence the force is 1350N
What kind of region is more likely to suffer mass wasting?
the subject is science.
Answers
Answer:
Areas with steep topography and rapid rainfall, such as the California coast, Rocky Mountain Region, and Pacific Northwest, are particularly susceptible to hazardous mass-wasting events.
Please help with physics homework.
Show work for question c)
Answers
a) The force diagram of the block and all the forces are in the image attached.
(b) The weight of the block and its parallel component is 98.1 N and 33.55 N respectively.
(c) The applied force on the block is 52.75 N
What are the component of the forces?(a) The force diagram of the block include, the parallel and pedicular component, as well as friction force.
(b) The weight of the block and its parallel component is calculated as;
Fg = mg
where;
m is the mass of the blockg is acceleration due to gravityFg = 10 kg x 9.81 m/s²
Fg = 98.1 N
Fgₓ = mgsinθ
Fgₓ = 98.1 N x sin(20)
Fgₓ = 33.55 N
(c) The applied force on the block is calculated as follows;
F - Fgₓ - μFgcosθ = ma
where;
m is the mass of the blocka is the acceleration of the blockμ is the coefficient of frictionF is the applied forceμ = a/g
μ = 1 / 9.81 = 0.1
F - 33.55 - 0.1(98.1 x cos20) = 10 x 1
F - 33.55 - 9.2 = 10
F = 10 + 33.55 + 9.2
F = 52.75 N
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Please someone help me with this
Answers
Answer:
I believe it is D
Explanation:
(02.06)plz help me 20 points
Answers
Answer:
the answer is 80 degrees
Explanation:
This man is jumping through the air what are forces use
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Answer:
Thrust / Lift / Gravity
Explanation:
He must create enough force of thrust to jump for a short time and gravity pulls him back down almost immediately.
Answer:
gravity and resistance, the man is moving so the force is unbalanced
Explanation:
I believe the answer is D but wanted to make sure.
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Answer:
Yes you are right
Explanation:
hope this helps and I get the Brain thingy whatever it call
a group of hikers hears an echo 4.70 s after shouting. how far away is the mountain that reflected the sound wave? (assume the speed of sound is 342 m/s.)
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The mountain that reflected the sound wave is located 803.7 m away and may be located by assuming the speed of sound is 342 m/s. A group of hikers hears an echo 4.70 seconds after shouting.
When energy moves through a medium (such as air, water, or any other liquid or solid matter), it creates a pattern of disruption known as a sound wave that propagates away from the sound source. When an object vibrates, sound waves are produced that are similar to pressure waves, such when a phone rings.
Here, echo is equal to 4.70 seconds, and velocity is 342 meters per second.
In the case of an echo, the distance was traveled twice—once from the sender to the reflecting surface and once from the reflecting surface back to the sender.
v = d/t becomes v= 2d/t
d = (v.t) /2
d = (342*4.70)/2
d = 803.7 m
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(a) You wish to determine the height of the smokestack of a local coal burning power plant. You convince a member of the maintenance crew to mount the support for a simple pendulum at the top of the stack and you suspend a 1.00 kg mass that just misses the ground at its lowest point from the pendulum cord. If the period of the pendulum is 18.7 s, determine the height of the smokestack. 8455.69 Incorrect: Your answer is incorrect. What factors influence the period of a simple pendulum
Answers
Answer:
a. 86.80 m
b. i. The mass of the bob
ii. The length of the pendulum
Explanation:
a. Determine the height of the smokestack.
Using T = 2π√(L/g) where T = period of pendulum = 18.7 s, L = length of pendulum = height of smokestack and g = acceleration due to gravity = 9.8 m/s².
So, making L subject of the formula, we have
T = 2π√(L/g)
T/2π = √(L/g)
squaring both sides, we have
(T/2π)² = L/g
L = (T/2π)²g
Substituting the values of the variables into the equation, we have
L = (T/2π)²g
L = (18.7 s/2π)²(9.8 m/s²)
L = (2.976 s)²(9.8 m/s²)
L = 8.857 s² × 9.8 m/s²
L = 86.796 m
L ≅ 86.80 m
b. What factors influence the period of a simple pendulum
The factors that influence the period of a simple pendulum are
i. The mass of the bob
ii. The length of the pendulum