A simple pendulum is made of a small blob of mass m=7.000 kg attached to the end of an inextensible wire. The angular amplitude of oscillation is θ=5.730°. Consider that the gravitational acceleration is g=9.807 m/\(s^{2}\). What is the magnitude of the tension in the wire when the blob is directly below its point of support?

The length of the rod under the surface of the water can be calculated using Archimedes’ principle. The principle states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.

The buoyant force is given by the formula:

Buoyant force = Density of fluid x Volume of fluid displaced x Gravity

Since the rod is floating, the buoyant force is equal to the weight of the rod. We can use this to calculate the volume of fluid displaced by the rod.

Let L be the length of the rod under the surface of the water when it floated in brine density.

The weight of the rod is given by:

Weight of rod = Density of rod x Volume of rod x Gravity

Since the rod is floating, the weight of the rod is equal to the buoyant force.

Buoyant force = Weight of rod = Density of rod x Volume of rod x Gravity

The volume of fluid displaced by the rod is given by:

Volume of fluid displaced = Volume of rod = Length of rod x Cross-sectional area of rod

Since the cross-sectional area of the rod is constant, we can write:

Buoyant force = Density of fluid x Volume of fluid displaced x Gravity Density of rod x Volume of rod x Gravity = Density of fluid x Length of rod x Cross-sectional area of rod x Gravity

Solving for L, we get:

L = (Density of rod / Density of fluid) x Length of rod

Substituting the given values, we get:

L = (1000 / 1200) x 6 cm = 5 cm

Therefore, the length of the rod under the surface of the water when it floated in brine density is 5 cm.

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Answer: take less time to go the same distance

Explanation:

Because if it is going faster let’s say mph 60 mph is 60 miles per hour if you are going 40 miles per hour it will take you longer to get to your destination.

Okay, let's convert all the lengths to the same unit to compare:

(a) 100 m = 100 meters

(b) 104 μm = 104 micrometers = 104 × 10^-6 meters = 0.000104 meters

(c) 107 nm = 107 nanometers = 107 × 10^-9 meters = 0.000000000997 meters

(d) 102 mm = 102 millimeters = 102 × 10^-3 meters = 0.0102 meters

The longest length is:

(a) 100 m = 100 meters

The answer is option (a).

Answer: 100 m

Explanation:

1 μm = \(10^{-6}\) m = 0,000001 m

1 nm = \(10^{-9}\) m = 0,000000001 m

1 mm = \(10^{-3}\) m = 0,001 m

∴ 100 m es la mayor longitud

Given that,

Bulk modulus \(B= 2.6\times10^{10}\ N/m^2\)

Change in volume \(\Delta V=6.0\times10^{-10}\ m^3\)

Edge \(a= 5.4\times10^{-2}\ m\)

The volume of the cube at the ocean's surface will be

\(V_{0}=a^3\)

Where, a = edge

Put the value into the formula

\(V_{0}=(5.4\times10^{-2})^3\)

\(V_{0}=0.00016\ m^3\)

We need to calculate the change in pressure

Using formula of pressure

\(\Delta P=-B\dfrac{\Delta V}{V_{0}}\)

Put the value into the formula

\(\Delta P=-(2.6\times10^{10})\times\dfrac{(-6.0\times10^{-10})}{0.00016}\)

\(\Delta P=97500\ N/m^2\)

The pressure increases by \(1.0\times 10^{4}\ N/m^2\) for every meter of depth

We need to calculate the depth

Using formula for depth

\(depth=\dfrac{97500}{1.0\times10^{4}}\)

\(depth=9.75\ m\)

Hence,  The depth is 9.75 m.

Explanation:

t = t/v(1-v^2/c^2)

3.10- 1.03 = 1.03/v(1-v^2/c^2)

2.07 = 1.03/v(1-v^2/c^2)

v(1-v^2/c^2) = 0.49

squaring both sides

(1-v^2/c^2) = 0.24

0.76 = v^2/c^2

v^2 = 0.76 × (3×10^8)^2

v = 0.873×10^8

v = 2.61×10^8 m/s

s = vt

t = 3.10 years = 3.10×365×24×3600 seconds = 9.7×10^8

s = 2.61×10^8× 9.7×10^8

s = 25.31×10^16 m

According to research, development is always towards complexity.

The term research has to do with the process that we have to go through to obtain new knowledge or to confirm a piece of information. Let us say that we have some disconnected pieces of evidence that tend to point towards a particular fact, we would need to use the process of research to establish the truth in the research.

Now we can see that there is a movement towards the complexity of organisms at each particular level in the developmental process. We can then conclude that according to research, development is always towards complexity.

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Answer:

All compounds can be classified as molecules, but not all molecules can be called compounds. Molecules are formed by two or more atoms that are bonded by chemical bonding's. Compounds are constructed by two or more elements where the elements are mixed in fixed ratios.

Answer:

Molecules are formed by two or more atoms that are bonded by chemical bondings.
Compounds are constructed by two or more elements where the elements are mixed in fixed ratios

*All compounds can be classified as molecules, but not all molecules can be called compounds.

Explanation:

 pls brainliest if you don't mind

anyway i hope this helped have an awesome day bye byee

The formula y = - 1 2 g t 2 y = - frac 1 2 g t 2 y=-21gt2 describes the vertical distance from the ground, where g is the acceleration of gravity and h is a height.

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The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Answer:

D. equal to 1.2

Explanation:

on edg

The length of the power cord will be equal to 1.2 m.

The length of the power cord when shanti gets off the train is equal to 1.2 m.

The Correct answer is Option D.

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Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.

The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.

They are being affected by the kinetic frictional force, which is caused by:

f = μk * N

Therefore,

fB = μk * N = μk * mB * g

Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,

fC = μk * N = μk * mC * g

where mC is the mass of Car C.

For Car A, the x-component of the tangential acceleration is given by:

aA = (fB - fC) / mA

where mA is the mass of Car A.

We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:

aA = (μk * mB * g - μk * mC * g) / mA

aA = μk * g * (mB - mC) / mA

Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:

aA = (mB - mC) * 9.81 / mA

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Answer:

u dont have a question

Explanation:

?? bc i would gladly help u

Explanation : The average speed of a moving body can never be zero but the average velocity of a moving body can be zero.

The special and general theories of relativity and Albert Einstein's audacious theory that light is a particle are his most famous works as a physicist and Nobel winner. The most well-known scientist of the 20th century is perhaps him.

In March 1879, he was born in Ulm, Württemberg. He had a great interest in nature and the capacity to comprehend challenging mathematical ideas even as a young man in Munich. He had an unremarkable high school experience, doing exceptionally well in arithmetic but completely failing the classics, which were then thought to be crucial for anybody planning to attend college. He detested school's dreary regimentation and uncreative atmosphere.

The second study established a lot of information regarding the nature of molecules and explained Brownian motion, which is the random jostling of molecules floating in a fluid. 16 years later, this study helped him win the physics Nobel Prize.

However, his third work, "On the Electrodynamics of Moving Bodies," was left out of the award's wording. The third article was the one that would have the biggest impact on contemporary physics. It included Einstein's Special Theory of Relativity, which greatly simplified how we think about how radiation, like light, interacts with matter. Speaking about one body moving and another being motionless has no real significance, according to Einstein. Only in connection to one other can bodies be conceived of as moving;

This specifically implies that, regardless of the frame of reference, electromagnetic radiation's (such as light's) speed remains constant. Even well-known scientists struggled to comprehend this theory because of Einstein's insightful and audacious viewpoint. But over time, when the predictions made by his theory were repeatedly verified, the Special Theory of Relativity finally transformed how scientists thought about matter, space, time, and everything that interacts with them.

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The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.

Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.

Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.

Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.

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The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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Answer: So, if the forces are in the same direction, it'll be 50N+30N= 80N!

If the forces are in opprsite direction it'll be 50N-30N= 20N (or visa-versa)

Explanation: This is because if the forces are in the same direction, like 2 people are pushing a body with 0 mass (I know, weird but imagine it) and both the people are applying the force in the same direction, let's say East, so the total fore exerted on the body will add up to become 50N+30N=80N.

And if the forces are phusing the body in oposite direction, then, let's say the bigger guy is pushing on the West Direction with 50N  of force and the weaker guy is pushing on the opposite direction with 30N of force, so this time their forces cancel out and it becomes 50N-30N= 20N (or 30N-50N= -20N).

Answer:

of the net electric field at point P due to the two charges.

Explanation:

The work that must be done against the electric forces in order to move the charge Q from the position x= 30.00 cm to the position x= 20.00 cm on the x-axis is -1.09·10-5 J.

Work done is described as the multiplication of the magnitude of displacement d and the component of the force that is in the direction of displacement.

Work done = ΔU = qΔV

where V = σ/2ε₀ * |x|

At x = 30.00 cm, the potential is:

V₁ = σ/2ε₀ * |x1| = (11.0·10-6 C/m2)/(2 * 8.85·10-12 C2/N·m2) * 0.3 m

V₁ = 5.01 V

At x = 20.00 cm, the potential is:

V₂ = σ/2ε₀ * |x2| = (11.0·10-6 C/m2)/(2 * 8.85·10-12 C2/N·m2) * 0.2 m

V₂ = 3.34 V

ΔV = V₂ - V₁

ΔV = 3.34 V - 5.01 V

ΔV  = -1.67 V

We then calculate the work required as:

Work done = qΔV = (6.50·10-6 C)(-1.67 V)

Work done = -1.09·10-5 J

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At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Answer:

The final velocity of the cars if they stick together is 1.36 m/s.

The final velocity of the cars if they  stick together is calculated by applying the principle of conservation of linear momentum as follows;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

1200(15 cos60) - 1000(6 x cos0) = v (1200 + 1000)

3000 = 2200v

v = 3000/2200

v = 1.36 m/s East of south.

Thus, The final velocity of the cars if they  stick together is 1.36 m/s.

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Answer:

24.132 m/s

Explanation:

Note

\(U\) = Initial Velocity

\(U_x\) = Initial Horizontal Velocity

\(U_y\) = Initial Vertical Velocity

\(V\) = Final Velocity

\(V_x\) = Final Horizontal Velocity

\(V_y\) = Final Vertical Velocity

\(B\) = launch angle

\(g\) = gravity

\(t\) = time

\(U_x=U*cos(B)\)

\(U_y=U*sin(B)\)

The horizontal component of the velocity is constant throughout the flight. So \(U_x=V_x\) It can be defined as

\(V_x=U*cos(B)\)

We can use the kinematics equation

\(V=U+at\)

Gravity is acting downwards; gravity would be negative

\(V_y=U_y-gt\)

The magnitude of the velocity can be defined as

\(V=\sqrt{V_x^2+V_y^2}\)

Inserting some of the other equations gives us an equation at a given time (t).

\(V=\sqrt{(U*cos(B))^2+(U*sin(B)-gt)^2}\)

\(V=\sqrt{(UcosB)^2+(UsinB)^2+(gt)^2-2gtU*sinB\)

\(V=\sqrt{U^2+g^2*t^2-2*t*g*U*sinB}\)

\(V(t)=\sqrt{U^2+g^2t^2-2tgUsinB}\)

We are given

\(U=34.6\)

\(B=80.2\)

\(t=1.09\)

\(g=9.81\)

\(V(1.09)=\sqrt{34.6^2+9.81^2*1.09^2-2*1.09*9.81*34.6*sin80.2}\)

\(V(1.09)=\sqrt{34.6^2+114.338-2*1.09*9.81*34.6*sin80.2}\)

\(V(1.09)=\sqrt{34.6^2+114.338-739.94868*sin80.2}\)

\(V(1.09)=\sqrt{34.6^2+114.338-729.151}\)

\(V(1.09)=\sqrt{1197.16+114.338-729.151}\)

\(V(1.09)=\sqrt{582.347}\)

\(V(1.09)=24.132\)

A rating/review would be much appreciated. Hope this helps!

Let me know if you have any questions about my work

Answer: 12,339

Explanation:

Answer:

Explanation:

We shall apply newton's law equation valid for rotational motion .

ωt = ω₀ + α t where ωt  is angular velocity after time t , ω₀ is angular velocity at t= 0 and α is angular acceleration

145 = 0 + α x 5.8

α = 25 rad / s²

B )

θ = ω₀ t +  1/2 α t²

= 0 + .5 x 25 x 5.8 x 5.8

= 420.5 rad .

Answer:

True

Explanation:

I looked it up for you it's true

Answer:

192.6N

Explanation:

Let's consider the forces acting on the beam:

Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.

Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.

Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.

Let's break down the forces acting on the beam:

Vertical forces:

W (weight of the beam) - T (vertical component of tension) = 0

T = W

Horizontal forces:

F_link (horizontal component of the force exerted by the link) = ?

To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.

Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:

F_link = W * sin(θ)

Let's substitute the given values:

W = 39.4 kg * 9.8 m/s^2

θ = 33.1 degrees

F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)

Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.