a shop ordered 13 boxes marbles each box contains six 10s of marbles each tin holds 45 marbles how many marbles does a shop order

Answer:

Larry

Step-by-step explanation:

15divided by 2 is 7.5

Julie:4

Mike:6

Katie:6

Using trigonometry we obtain the bearing of the ship ≈ 41.8 degrees.

To obtain the bearing of the ship given the values of x and y, we can use trigonometry.

The bearing represents the angle in degrees measured clockwise from the north direction.

First, we need to determine the angle θ between the positive x-axis and the line connecting the origin (0,0) and the point (x, y).

We can use the inverse tangent function (arctan) to find this angle:

θ = arctan(y/x)

Substituting the values x = 9.4 and y = 10.1 into the equation:

θ = arctan(10.1/9.4)

Using a calculator, we find that θ is approximately 48.2 degrees.

However, this angle corresponds to the angle counterclockwise from the positive x-axis.

To convert it to the bearing (measured clockwise from the north direction), we subtract this angle from 90 degrees:

Bearing = 90 - θ = 90 - 48.2 = 41.8 degrees.

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The implicit equation for the plane through (3,-2,2) normal to the vector ⟨4,1,-5⟩ is: 4(x - 3) + 1(y + 2) - 5(z - 2) = 0.

To find the implicit equation for the plane, we need the normal vector and a point on the plane. The given normal vector is ⟨4,1,-5⟩, which represents the coefficients of x, y, and z respectively. A point on the plane is (3,-2,2). Using the point-normal form of the equation, we substitute the values into the equation: 4(x - 3) + 1(y + 2) - 5(z - 2) = 0. Simplifying the equation gives us the implicit equation for the plane through the given point and normal vector.

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Answer:

1. The equation isn't balanced because there aren't equal numbers of hydrogen or chlorine atoms on both sides of the equation. To correct this, a coefficient of 2 must be placed in front of HCl on the left-hand side of the equation.

Zn+2HCl→ZnCl2+H2

Zn and 2HCl are the reactants; ZnCl2 and H2 are the products. This is a substitution reaction because a free element (Zn) replaces another element (H) in a compound.

2. This is a balanced equation because the same types of atoms and the same numbers of each atom are present on both sides of the equation. 8 S atoms are found on both sides of the equation, and 48 F atoms are found on both sides of the equation. S8 and 24F2 are the reactants; 8SF6 is the product. This is a combination reaction because two substances (S8 and 24F2) undergo a chemical union to form a more complex substance (8SF6).

S8+24F2→8SF6

3. In ferric oxide (Fe3O4), there are 3 atoms of iron (Fe) and 4 atoms of oxygen (O). From the Periodic Table of Elements, we know that the atomic mass of iron is 55.8457 and the atomic mass of oxygen is 15.9994.

Fe3 = 55.8457 × 3 = 167.5371

O4 = 15.9994 × 4 = 63.9976

167.5371 + 63.9976 = 231.5347 (231.535 rounded)

Therefore, the molecular mass of ferric oxide is 231.535.

4. The percentage composition of chlorine in CaCl2 is derived as follows:

The molecular mass of the entire compound is:

Ca = 40.078 × 1 = 40.078

Cl2 = 35.4527 × 2 = 70.9054

40.078 + 70.9054 = 110.9834 (110.983 rounded)

The atomic mass of each element (or its multiple) is divided by the molecular mass of the compound:

Ca = 40.078 ÷ 110.983 = 0.361

Cl2 = 70.9054 ÷ 110.983 = 0.639

Multiplying each by 100 will turn these into percents. Therefore, the percentage composition of chlorine is 63.9%.

5. i. a, c, f, h

ii. e

iii. b, d, g, i

iv. i

Step-by-step explanation:

PENN FOSTER

The given chemical equation represents a type of reaction known as a single replacement (or displacement) reaction. In this reaction, zinc (Zn) displaces hydrogen (H) from hydrochloric acid (HCl) to form zinc chloride (\(ZnCl_2\)) and hydrogen gas (\(H_2\)).

The given chemical equation is:

\(Zn + HCl \rightarrow ZnCl_2 + H_2\)

To determine if the equation is balanced, we need to check if the number of atoms of each element is the same on both sides of the equation.

On the left side (reactant side):

Zinc (Zn) atoms: 1

Hydrogen (H) atoms: 1

Chlorine (Cl) atoms: 1

On the right side (product side):

Zinc (Zn) atoms: 1

Hydrogen (H) atoms: 2 (from\(ZnCl_2 + H_2\))

Chlorine (Cl) atoms: 2 (from \(ZnCl_2\))

The number of hydrogen (H) and chlorine (Cl) atoms is not balanced between the reactants and products. To balance the equation, we need to have the same number of atoms on both sides.

Balanced equation:

\(Zn + 2HCl → ZnCl_2 + H_2\)

Now, the equation is balanced with the following number of atoms on both sides:

On the left side (reactant side):

Zinc (Zn) atoms: 1

Hydrogen (H) atoms: 2

Chlorine (Cl) atoms: 2 (2 from HCl)

On the right side (product side):

Zinc (Zn) atoms: 1

Hydrogen (H) atoms: 2 (from H2)

Chlorine (Cl) atoms: 2 (from ZnCl2)

Identification of reactants and products:

Reactants: Zn (zinc) and HCl (hydrochloric acid)

Products: \(ZnCl_2\) (zinc chloride) and \(H_2\) (hydrogen gas)

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The relation's graph can be seen in the graphic at the bottom, where it is clear that it is   function.

The actual function can be specified using this "mapping" notation. Writing f:(x,y)x+y would allow us to define the above f(x, y). Real numbers are referred to as scalars to distinguish them from vectors. Each input is translated into a single output in a relation known as a function (input, output).

The horizontal axis is used for inputs, and the vertical axis is used for outputs. Here, we have the relationship shown below:

(-5,-1), (-4,1), (-3,3), (-1,5), (1,7) (1,7)

The figure below shows the graph of these points. Since there are no two points on the same vertical line, the relation is a function, as you can see.

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Answer:

D

Step-by-step explanation:

x=8*cos(34°)=6.632≈6.6

Answer:

Barlow School has the greater number of boys by  178.

Answer:

Barlow school by 178

Step-by-step explanation:

→ First let's work out the number of boys at Barlow school

\(\frac{4}{9}\)  of  \(873\)  \(=\)  \((873/9)*4\)  \(=\)  \(388\)

→ There is 388 boys in Barlow school. Now let's work out the number of boys at Willow school. Since we know that  \(\frac{2}{3}\)  of the school is girls, it must mean that the remaining part must be boys so the fraction of boys at Willow school is  \(\frac{1}{3}\)

\(\frac{1}{3}\)  of  \(630\)  \(=\)   \((630/3)*1\)  \(=\) 210

→ The question specifies to say which school has a greater number of boys and we can see Barlow school has more boys and the question says by how many so we take away the totals so 388 - 210 = 178

Answer:

46

Step-by-step explanation:wrhwefefewfoheqijfqwhfgq38fh

It takes 53 years until we run out of gas.

Given,

Reserves of natural gas = 6500 TCF

Consumption per year = 123 TCF

Therefore,

years left ( x )= Reserves of natural gas / Consumption per year  

                     = 6500/123

                     = 52.8 years

                  x = 53 years approximately

So, it takes 53 years until we run out of gas at this rate of consumption.

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We can estimate that Cho will sell around 100 servings of kakigori on a day when the high temperature is 29° Celsius.

Based on the line of best fit for the data, we can estimate the number of servings of kakigori Cho will sell on a day when the high temperature is 29° Celsius.

From the scatter plot, we can see that the line of best fit is increasing as the temperature increases.

By estimating the value on the line of best fit for the temperature of 29° Celsius, we can approximate the number of servings sold. Based on the scatter plot, it appears that the number of servings sold is around 100 when the temperature is 29° Celsius.

Therefore, we can estimate that Cho will sell around 100 servings of kakigori on a day when the high temperature is 29° Celsius.

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The count of letter f (any case) in ' if fred is from a part of france, then of course fred's french is good', is 8.

A word, phrase, or sentence in which no letter of the alphabet appears more than once is known as a heterogram (from the prefix hetero-, meaning "different," and the suffix -gram, meaning "written"). The same idea has also been denoted by the phrases isogram and nonpattern word.

Language on Vacation: An Olio of Orthographical Oddities, written by Dmitri Borgmann in 1965, mentions the idea, however he refers to it as an isogram. Borgmann asserts that he "introduced" the term "isogram" in a 1985 essay. Although he uses the term "isogram" in the paper itself, he also offers the name "asogram" to prevent confusion with lines of constant value like contour lines.

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a)  Frequency tree is mentioned below. b) P(Sonnet not shortlisted) = 0.477 c) P(Limerick not shortlisted) = 0.185.

In its simplest form, probability is represented as a number between 0 and 1, where 0 represents an impossible event and 1 represents a certain event. The probability of an event can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

Probability can be used to make predictions about the outcomes of random events. For example, in a game of chance like roulette, the probability of a particular number coming up is known and can be used to determine the odds of winning.

a) Frequency tree:

                Total: 1000

                        /            \

                   /                      \

   Sonnet (750)                    Limerick (250)

           /            \                                /         \

Shortlisted    Not Shortlisted   Shortlisted    Not Shortlisted

           /                  \                                /           \

        273              477                          65         185

b) Probability of a sonnet not shortlisted:

Number of sonnets not shortlisted = Total sonnets - Shortlisted sonnets

Number of sonnets not shortlisted = 750 - 273

Number of sonnets not shortlisted = 477

P(Sonnet not shortlisted) = 477 / 1000

P(Sonnet not shortlisted) = 0.477

c) Probability of a limerick not shortlisted:

Number of limericks not shortlisted = Total limericks - Shortlisted limericks

Number of limericks not shortlisted = 250 - 65

Number of limericks not shortlisted = 185

P(Limerick not shortlisted) = 185 / 1000

P(Limerick not shortlisted) = 0.185

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The lower temperature is 200∘C for (a) and 353∘F for (b). In order to determine the lower temperature between two measurements given in different temperature scales, we need to convert them to a common scale.

The common scale we can use is the Kelvin scale, as it is an absolute temperature scale.

(a) To compare 273∘C and 273∘F, we need to convert them to Kelvin. The conversion formula for Celsius to Kelvin is K = C + 273.15, and for Fahrenheit to Kelvin, K = (F - 32) × 5/9 + 273.15.

- For 273∘C, we have K = 273 + 273.15 = 546.15K.

- For 273∘F, we have K = (273 - 32) × 5/9 + 273.15 ≈ 523.15K.

Since 523.15K is lower than 546.15K, the lower temperature is 273∘F.

(b) To compare 200∘C and 353∘F:

- For 200∘C, we have K = 200 + 273.15 = 473.15K.

- For 353∘F, we have K = (353 - 32) × 5/9 + 273.15 ≈ 423.15K.

Since 423.15K is lower than 473.15K, the lower temperature is 353∘F.

In summary, the lower temperature is 200∘C for (a) and 353∘F for (b).

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A man runs for an hour and a half at 8 miles an hour due south. he then continues south on a bus traveling at 55 miles an hour for 24 minutes. He will traveled 34 miles.

He covered 8 miles the first hour, and then half of that in his next half hour,

So, 8+4 = 12 miles.

The bus took 24 minutes, which is \(\frac{2}{5}\) of an hour.

\(\frac{60}{5} = 12\)

So, after 12 minutes on the bus, he travelled \(\frac{55}{5} = 11\) miles

And after 24 minutes, 22 miles.

In total 12+22=34 miles.

Speed(v) is related to distance(d) and time(t) by

v= \(\frac{d}{t}\).

Equivalently, d= v×t

So, d= 8×1.5+55×24×\(\frac{1}{60}\)

= 34 miles.

Therefore, he traveled 34 miles.

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The time it take until 2000 people know about the rumor is 16 days.

The square root of a variety of is described because the value, which offers the variety while it's miles increased with the aid of using itself. The radical symbol √ is used to suggest the square root.  Radical is any other call given to the square root symbol. It is likewise called the surds. While Radicand is the variety gift beneath neath the square root symbol.

Find t, when N=200

N=5OO t^1/2

2000=500 t^1/2

t^1/2=4

t=16 days

Thus, the time it take until 2000 people know about the rumor is 16 days.

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Answer:

2x - 5 < 23

2x < 28

x < 14

Step-by-step explanation:

Petra gives Ian the clue below to help him guess a number.When the number (x) is doubled and the product is reduced by five, the final result is less than 23.Which inequality correctly represents this clue?

Answer:

2x - 5 < 23

Step-by-step explanation:

2x - 5 < 23

2x < 28

x < 14

Answer:

To create a perfect square of given expression,

On solving the above expression we get,

we have that,

To create a perfect square: add ( half the coefficient of the x- term )²

Coefficient of x term is 3

half the coefficient of the x- term is 1.5

( half the coefficient of the x- term )² is 2.25

Add 2.25 to the quadratic expression inside the bracket, we get,

In general, we adding 11.25 (that is, 2.25x5=11.25) to the given expression.

we get,

Multiply 5 to the above equation, we get

Based on the above calculation, we adding 11.25 and multiplying the expression by 5 in order to create a perfect square.

Adding 11.25 and multiplying the expression by 5 in order to create a perfect square.

__________

\( \: \)

\( \sqrt{1,69} = ...\)

\( = {1,69}^{ \frac{1}{2} } \)

\( = \bold{1,3}\)

Soo, asnwer for Question \(\sqrt{1,69} = 1,3\)

Answer:

The answer is 5 3/4

Step-by-step explanation:

13/4 = 3 1/4

3 1/4 + 2 2/4 = 5 3/4

Hope this helped you!

a. The standard error of the mean can be determined using the formula:

Standard error of the mean = population standard deviation / square root of sample size

Plugging in the given values, we get:

Standard error of the mean = 25 / square root of 250
Standard error of the mean = 25 / 15.8114
Standard error of the mean = 1.579 (rounded to 3 decimal places)


The standard error of the mean measures the amount of variability or error that is expected in the sample mean when compared to the true population mean. It is calculated by dividing the population

by the square root of the sample size. In this case, the standard error of the mean is 1.579, indicating that the sample mean of 20 is expected to be off by around 1.579 units from the true population mean.

c. To determine the 95% confidence interval for the population mean, we can use the formula:

Confidence interval = sample mean +/- (critical value) x (standard error of the mean)

The critical value can be obtained from a t-distribution table with n-1 degrees of freedom, where n is the sample size. For a 95% confidence interval and 249 degrees of freedom, the critical value is 1.96.

Plugging in the given values, we get:

Confidence interval = 20 +/- (1.96) x (1.579)
Confidence interval = 20 +/- 3.095
Confidence interval = (16.905, 23.095) (rounded to 3 decimal places)


The confidence interval is a range of values that is expected to contain the true population mean with a certain degree of confidence. In this case, we are 95% confident that the true population mean falls within the range of 16.905 to 23.095. This means that if we were to repeat this sampling process many times, 95% of the resulting confidence intervals would contain the true population mean.

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There is a 15.38% chance that the top three finishers will all be seniors.

The combination formula yields the following results:

The top three finishers, which include all seniors, are listed in 364 distinct orders.

The combination formula is employed to answer this question because the players' selection order is irrelevant.

In total, three students are taken from a set of 14, hence:

¹⁴C₃ = 14! / (3!*11!)

= 364

Including only seniors, it would be three students from a set of 8, hence:

⁸C₃ = 8! / (3!* 5!)

=56

Hence the probability is given by:

p = 56/364

= 0.1538

= 15.38%.

Therefore, there is 15.38% chance that the top-three finishers will all be seniors.

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The values of x, y and z in the parallelogram 1 are x = 80, y = 100 and z = 80

Parallelogram 1

Adjacent angles of a parallelogram add up to 180

So, we have

x = 180 - 100

x = 80

Opposite angles are equal

So, we have

y = 100

z = 80

Using the above theorem, we have the values of x, y and z in the other parallelograms to be

Parallelogram 2

x = 180 - 50

x = 130

y = 130

z = 130 --- by corresponding angle theorem

Parallelogram 3

x = 90 --- by vertical angle theorem

Then, we have

y = 60 --- sum of angles in a triangle

z = 60 --- by corresponding angle theorem

Parallelogram 4

x = 100

y = 80

z = 80 --- by corresponding angle theorem

Parallelogram 5

y = 112

x = 180 - 112 - 40 --- sum of angles in a triangle

x = 28

z = 28  --- by corresponding angle theorem

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The remaining amount of the substance with the half life of 64.9 days after 100 days is 2.749.

To calculate the amount that remains  after 100 days, this formular can be used

amount remaining = \(a (0.50)^{\frac{t}{h} }\)

where t is the time that was required for the process to take place, where t is 100 days.

h is the halftime, which is been given as 64.9 days

where a is given as the initial amount that is present which is 8.

Then the values can be substituted to have

\(=a (0.50)^{\frac{100}{64.9} }\)

= 2.749

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Answer:

Trinomial: (2x² – 5x) + (4x – 10)

GCF: x (2x – 5) + 2 (2x – 5)

Step-by-step explanation:

2x² – x – 10

The equation above can be factorised as follow:

2x² – x – 10

Multiply the first term (i.e 2x²) and the last term (i.e –10) together.

2x² × (–10) = –20x²

Find two factors of –20x² such that when we add them together, it will result to the 2nd term in the equation (i.e –x).

The factors are 4x and –5x.

Next, replace –x in the equation above with 4x and –5x. This is illustrated below:

2x² – x – 10

2x² – 5x + 4x – 10

Next, factorise

2x² – 5x + 4x – 10

Trinomial: (2x² – 5x) + (4x – 10)

GCF: x (2x – 5) + 2 (2x – 5)

If all servers are kept busy, then the total service rate of the system is 3 times the service rate of a single server, which is 3 * 12 = 36 customers per hour. Therefore, if all servers are kept busy, then the system can complete 36 services per hour (rounded to the nearest whole number).

The utilization factor for this M/M/3 system can be calculated as the arrival rate divided by the product of the service rate and the number of servers. So, the utilization factor is 16 / (12 * 3) = 0.444 (rounded to 3 decimal places).

In an M/M/3 system with an arrival rate of 16 customers per hour and a service rate of 12 customers per hour per server, the utilization factor can be calculated as follows:

Utilization factor = (Arrival rate) / (Number of servers * Service rate) = 16 / (3 * 12) = 16 / 36.

Utilization factor = 0.444 (rounded to 3 decimal places).

If all servers are kept busy, the total services completed per hour can be calculated as:

Total services per hour = Number of servers * Service rate = 3 * 12 = 36 services.

So, in this system, the utilization factor is 0.444, and if all servers are kept busy, they will complete 36 services per hour (rounded to the nearest whole number).

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Answer:

the answer is D have a good day

\(~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ (4)^{\frac{-4}{2}} \implies (4)^{-2}\implies 4^{-2}\implies \cfrac{1}{4^2}\implies \cfrac{1}{16}\)