A service elevator takes a load of garbage, mass 10.0 kg, from a floor of a skyscraper under construction, down to ground level, accelerating downward at a rate of 1.2 m/s2 . Find the magnitude of the force the garbage exerts on the floor of the service elevator

Answers

Answer 1

Answer:

The magnitude of the force the garbage exerts on the floor of the service elevator is 12 N

Explanation:

Given;

mass of the garbage, m = 10.0 kg

acceleration of the elevator, a = 1.2 m/s²

The magnitude of the force the garbage exerts on the floor of the service elevator is given by;

F = ma

F = 10 x 1.2

F = 12 N

Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 12 N


Related Questions

If the 100 g mass is replaced by a 200 g mass, which variables in Tnet = la change, and which
remains constant? Justify your answer.

Answers

The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.

What is the changed variable in the equation?

The formula for net torque acting on an object is given as;

T(net) = Ia

where;

a is the angular accelerationI is the moment of inertiaT(net) is the net torque

The  moment of inertia of an object is given as;

I ∝ MR²

where;

M is the massR is the radius of the object

So mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.

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A jogger takes 30 s to run a total distance of 200 m by running 150 m [E] and then 50 m [W]. (a)

Calculate the jogger’s average speed (b) Calculate the jogger’s average velocity​

Answers

Answer:

(a) 6.67 m/s  (b) 3.33 m/s

Explanation:

if i understood your question correctly, the jogger goes 150m east before going in the opposite direction west for 50m. (see diagram)

in avg speed, we use the total distance (150m + 50m = 200m)  and total time (30s)

v = d/t =200/30 =6.67 m/s

in avg velocity, we use the total displacement  (150m - 50m = 100m) and total time (30s)

v= d/t = 100/30 = 3.33 m/s

A jogger takes 30 s to run a total distance of 200 m by running 150 m [E] and then 50 m [W]. (a) Calculate

true/false. Article 130, Work Involving Electrical Hazards, by definition, covers work involving four hazards caused by either proximity or equipment failure.

Answers

This statement is False, Article 130, Work Involving Electrical Hazards, by definition, covers work involving four hazards caused by either proximity or equipment failure.

Electrical hazards refer to the potential risks associated with the use of electricity, which can cause injury or even death. These hazards can arise from a variety of sources, including electrical systems, appliances, tools, and wiring.

Electrical hazards can include electrical shock, burns, and electrocution. Electrical shock occurs when a person comes into contact with an electrical current and can cause muscle contractions, respiratory failure, and cardiac arrest. Burns can result from direct contact with an electrical current or from an arc flash, which is a sudden release of electrical energy. Electrocution is a severe form of electrical shock that can result in death. It is essential to receive proper training and education on electrical safety and to always be aware of potential electrical hazards in the environment.

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When the Moon passes through Earth's penumbra, it is a:


a.Solar eclipse
b. Penumbral eclipse
c.Total lunar eclipse
d Partial eclipse

Answers

Answer: it is B

Explanation: A penumbral lunar eclipse occurs when the Moon passes through Earth's penumbra. The penumbra causes a subtle dimming of the lunar surface, which is only visible to the naked eye when about 70% of the Moon's diameter has immersed into Earth's penumbra.

B . penumbral eclipse

what is climate change?​

Answers

What Is Climate Change?

Climate change refers to long-term shifts in temperatures and weather patterns. These shifts may be natural, such as through variations in the solar cycle. But since the 1800s, human activities have been the main driver of climate change, primarily due to burning fossil fuels like coal, oil and gas.

Burning fossil fuels generates greenhouse gas emissions that act like a blanket wrapped around the Earth, trapping the sun’s heat and raising temperatures.

Examples of greenhouse gas emissions that are causing climate change include carbon dioxide and methane. These come from using gasoline for driving a car or coal for heating a building, for example. Clearing land and forests can also release carbon dioxide. Landfills for garbage are a major source of methane emissions. Energy, industry, transport, buildings, agriculture and land use are among the main emitters.

The Earth is feeling the heat.

Greenhouse gas concentrations are at their highest levels in 2 million years

And emissions continue to rise. As a result, the Earth is now about 1.1°C warmer than it was in the late 1800s. The last decade (2011-2020) was the warmest on record.

Many people think climate change mainly means warmer temperatures. But temperature rise is only the beginning of the story. Because the Earth is a system, where everything is connected, changes in one area can influence changes in all others.

The consequences of climate change now include, among others, intense droughts, water scarcity, severe fires, rising sea levels, flooding, melting polar ice, catastrophic storms and declining biodiversity.

The Earth is asking for help.

People are experiencing climate change in diverse ways

Climate change can affect our health, ability to grow food, housing, safety and work. Some of us are already more vulnerable to climate impacts, such as people living in small island nations and other developing countries. Conditions like sea-level rise and saltwater intrusion have advanced to the point where whole communities have had to relocate, and protracted droughts are putting people at risk of famine. In the future, the number of “climate refugees” is expected to rise.

Every increase in global warming matters

In a series of UN reports, thousands of scientists and government reviewers agreed that limiting global temperature rise to no more than 1.5°C would help us avoid the worst climate impacts and maintain a livable climate. Yet policies currently in place point to a 2.8°C temperature rise by the end of the century.

The emissions that cause climate change come from every part of the world and affect everyone, but some countries produce much more than others. The 100 least-emitting countries generate 3 per cent of total emissions. The 10 countries with the largest emissions contribute 68 per cent. Everyone must take climate action, but people and countries creating more of the problem have a greater responsibility to act first.

Photocomposition: an image of the world globe looking worried to a thermometer with raising temperatures

We face a huge challenge but already know many solutions

Many climate change solutions can deliver economic benefits while improving our lives and protecting the environment. We also have global frameworks and agreements to guide progress, such as the Sustainable Development Goals, the UN Framework Convention on Climate Change and the Paris Agreement. Three broad categories of action are: cutting emissions, adapting to climate impacts and financing required adjustments.

Switching energy systems from fossil fuels to renewables like solar or wind will reduce the emissions driving climate change. But we have to start right now. While a growing coalition of countries is committing to net zero emissions by 2050, about half of emissions cuts must be in place by 2030 to keep warming below 1.5°C. Fossil fuel production must decline by roughly 6 per cent per year between 2020 and 2030.

Growing coalition

Adapting to climate consequences protects people, homes, businesses, livelihoods, infrastructure and natural ecosystems. It covers current impacts and those likely in the future. Adaptation will be required everywhere, but must be prioritized now for the most vulnerable people with the fewest resources to cope with climate hazards. The rate of return can be high. Early warning systems for disasters, for instance, save lives and property, and can deliver benefits up to 10 times the initial cost.

We can pay the bill now, or pay dearly in the future

Climate action requires significant financial investments by governments and businesses. But climate inaction is vastly more expensive. One critical step is for industrialized countries to fulfil their commitment to provide $100 billion a year to developing countries so they can adapt and move towards greener economies.

Climate finance

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if a kettle has a power rating of 3000kw how much energy is transferred every second

Answers

Power=3000kW=P

Time=1s=t

\(\\ \sf\longmapsto E=Pt\)

\(\\ \sf\longmapsto E=3000kW(1)\)

\(\\ \sf\longmapsto E=3000KJ\)

An intrepid hiker reaches a large crevasse in his hiking route. He sees a nice landing ledge 60.0 cm below his position but it is across a 2.3 m gap. He spends 1.2 s accelerating horizontally at 5.92 m/s2 [right] in an attempt to launch himself to the safe landing on the far side of the gap. Does he make it?

Answers

The hiker made it to a safe landing on the other side of the gap after travelling horizontally at 2.49 m.

What is the time motion from the vertical height?

The time taken for the hiker to fall from the given height is calculated as follows;

h = vt + ¹/₂gt²

where;

v is the vertical velocity = 0t is the time of motiong is acceleration due to gravityh is the height of fall

h = ¹/₂gt²

t = √(2h/g)

t = √[(2 x 0.6) / (9.8)]

t = 0.35 seconds

The horizontal velocity of the hiker during the period of acceleration is calculated as follows;

Vₓ = at

Vₓ = (5.92 m/s²) x (1.2 s)

Vₓ = 7.104 m/s

The horizontal distance travelled during the time period of 0.35 seconds;

X = Vₓt

X = 7.104 x 0.35

X = 2.49 m

Thus, the hiker made it to a safe landing on the other side of the gap which is 2.3 m wide and smaller to his horizontal displacement of 2.49 m.

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g a uniform electric field has magnitude e and is directed in the negative x direction. the potential difference between point a (at x= 0.60 m) and point b (at x= 0.90 m) is 310 v. Part A Which point, a or b, is at the higher potential? Part B Calculate the value of E. Express your answer using two significant figures. Part C A negative point charge q = -0.200 mu C is moved from b to a. Calculate the work done on the point charge by the electric field. Express your answer using two significant figures.

Answers

A) Point A is the one with the highest potential.

B) The uniform electric field's magnitude E is equal to 1033.33 V/m.

Given that,

Potential difference at point A ( at x ) = 0.6 m

Potential difference at point B ( at x ) = 0.9 m

Potential difference = 310 volts

Point charge is -0.200 μC = - 0.2 * 10⁻⁶ C

A) The point with a larger potential is point A because the uniform electric field of magnitude (E) is not close to the positive charge and is farther away from point B by 0.9 m. This is because the uniform electric field is directed in the negative x direction. Additionally, the square of the distance from a point charge has an inverse relationship with the potential difference of an electric field.

B) In order to determine the size (E) of the uniform electric field:

The equation Vab = E* d determines the magnitude (E) of this electric field at a constant potential difference.

Where Vab is the potential difference between points A and B, and E is the uniform electric field's magnitude

E is the electric field's strength, and d is the separation between points A and B.

Let us determine the distance (d),

d = db - da

⇒ 0.9 - 0.6 = 0.3 m

By changing the values in the formula above, we arrive at

310 = 0.3 E

E = 1033.33 V/m

Therefore, the uniform electric field has a magnitude of 1033.33 V/m.

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A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?

Answers

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

What is Speed ?

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

h = 52 mu = 0Range R = 35 mg = 9.8 m/s²

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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why do astronauts weigh less on the moon than on earth

Answers

Answer:

Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.

Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.

3. Harris is putting in a three-phase Y-Y-
connected transformer bank and the
secondary line-to-line voltage is 208 V.
What's the line-to-neutral voltage?
O A. 120 V
O B. 359 V
C. 69 V
O D. 240 V

Answers

120V is the line-to-neutral voltage .

What is Line Voltage ?

It is defined as the voltage of a power transmission circuit or distribution circuit up to the point of transformation or utilization.

The secondary line voltage is \(V_{L} = 280 V\)

The notation AC indicates that the current is an alternating current.

The given formula is \(V_{ph} = \frac{V_{L} }{\sqrt{3} }\)

Substitute  208 V into the formula

\(V_{ph} = \frac{V_{L} }{\sqrt{3} } \\\\V_{ph} = \frac{208V}{\sqrt{3} } \\\\= 120 (Approx)\)

So, the line-to-neutral voltage is 120 V.

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1) An object located 33.9 cm in front of a lens
forms an image on a screen 8.57 cm behind
the lens.
Find the focal length of the lens.
Answer in units of cm
2) What is the magnification of the object?

Answers

Answer:

Explanation:

Given:

d = 33.9 cm

f = 8.57

___________

F - ?

G - ?

The focal length of the lens:

F = d*f / (d + f) = 33.9*8.57 / (33.9 + 8.57) ≈ 6.84 cm

The magnification of the object:

M = f / d = 8.57 / 33.9 ≈ 0.25


d= 33.9 cm
f= 857
F-?
G-?
The focal length of the lens:
F= d* / (d + f) = 33.9*8.57 / (33.9 + 8.57) = 6.84 cm
The magnification of the object:
M=f/d =8.57 / 33.9 ÷ 0.25

A truck and a car are moving with equal velocity.on applying the same breaking Force,both will stop at a certain distance.then whether truck or car will cover less distance or both cover equal distance.?

Answers

If truck and car moving with same velocity then the car will cover less distance , if the force of breaking is same .

The velocity of the truck and car are given to have equal velocity ,

the braking force is also equal ,

we know that , the mass of the truck(M)  is greater than mass of the car(m) ;

So , the truck will have more momentum ;

we know that momentum is = mass × velocity ;

let the velocity of car and truck be "v" ;

substituting the values in the momentum formula ;,

we get ; Mv > mv ;

Therefore , the car will cover less distance .

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I can't seem to get the right angular acceleration and also not sure how to do part b. Help will be much appreciated.

I can't seem to get the right angular acceleration and also not sure how to do part b. Help will be much

Answers

Answer:It’s 5 I believe

Explanation: it says to round to the nearest thousandths, so it’ll be 5.

A car, initially traveling at 79.8 mi/h, slows to rest in 9.5 s. What is the car's acceleration?

Answers

Given:

The initial velocity of the car, u=79.8 mi/h

The final velocity of the car, v=-0 m/s

The time it takes for the car to come to rest, t=9.5 s

To find:

The acceleration of the car.

Explanation:

The initial velocity of the car in m/s is u=35.67 m/s

From the equation of motion,

\(v=u+at\)

On substituting the known values,

\(\begin{gathered} 0=35.67+a\times9.5 \\ \Rightarrow a=\frac{-35.67}{9.5} \\ =-3.75\text{ m/s}^2 \end{gathered}\)

Final answer:

The acceleration of the car is -3.75 m/s²

g if the distance between the Earth and the Sun were increased by a factor of 2.87, by what factor would the strength of the force between them change

Answers

We have that the  the strength of the force between the Sun and the moon  is mathematically given as

F2=0.12140F1N

Strength of the Force

Question Parameters:

Distance between the Earth and the Sun were increased by a factor of 2.87,

Generally the equation for the  Gravitational Force   is mathematically given as

\(F=\frac{Gm1m2}{d^2}\\\\Where\\\\f1/f2=d1^2/d2^2\\\\Therefore\\\\F2=\frac{F1*d1}{3.23^2}\\\\F2=\frac{F1*1}{2.87^2}\\\\\)

F2=0.12140F1N

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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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1- A soccer ball was kicked from the ground with an initial speed of 12m/s at an
angle 32° above the horizontal. What are the x and y positions of the ball
0.50s after it is kicked?

Answers

Answer:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

Explanation:

X and Y components:

Y = 6.36 m/s

X = 10.18 m/s

Position after 0.5 seconds:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

The x and y positions of the ball 0.50s after it is kicked are 5.09 meter and  1.95 meter respectively.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Initial speed of the soccer ball at an angle 32° above the horizontal is: u = 12m/s.

Time interval: t = 0.50 second.

Now, x component of initial velocity = u cosθ = 12 × cos 32° m/s = 10.17 m/s.

y component of initial velocity = u sinθ = 12 × sin32° =6.36 m/s.

Hence,

after 0.50 s, x-position of the ball =  u cosθ t

= 10.17 × 0.50 meter

= 5.09 meter.

after 0.50 s, y-position of the ball =  u sinθ t -gt²/2

= 6.36 × 0.50 - (9.8×0.50²/2) meter

= 1.95 meter.

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Which change of state is shown in the model?

-condensation
-deposition
-boiling
-freezing

Answers

Answer: what’s the model

Explanation:

it's B hope this help's

Why does a watched pot never boil?

Answers

This phrase means that time seems to slow down when one is waiting for something to happen desperately

Particles q₁, 92, and q3 are in a straight line.
Particles q₁ = -5.00 10-6 C,q2 = +2.50 10-6 C, and
q3= -2.50 10-6 C. Particles q₁ and q₂ are separated
by 0.500 m. Particles q2 and q3 are separated by
0.250 m. What is the net force on q2?

Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right

Particles q, 92, and q3 are in a straight line.Particles q = -5.00 10-6 C,q2 = +2.50 10-6 C, andq3= -2.50

Answers

When three particles q1, q2, and q3 are in a straight line, the force experienced by q2 depends on the distance between the particles, the magnitude of the charges of the particles, and the relative position of the particles. The electric force on a charge q1 from a charge q3, which is at a distance r3 from the first charge, is governed by Coulomb’s Law.

In mathematical notation, Coulomb’s Law is expressed as:F = kq1q3 / r3²where F is the electric force, q1 and q3 are the magnitudes of the charges, r3 is the distance between them, and k is the Coulomb’s Law constant which is equal to 8.99 × 109 N·m2 / C2. The direction of the electric force can be positive or negative. If q1 and q3 are of the same sign, the force between them is repulsive, while if they are of opposite sign, the force is attractive.The electric force experienced by q2 due to the other two particles is the vector sum of the forces F13 and F23, which are given by:F13 = kq1q3 / r13²andF23 = kq2q3 / r23²where r13 is the distance between q1 and q3, and r23 is the distance between q2 and q3. The net force on q2 is given by:Fnet = F13 + F23The magnitude and direction of Fnet depend on the charges of the particles and the distance between them. If the two charges are of the same sign, then the force is repulsive and the net force will be in the direction of the force between them. If the two charges are of opposite signs, then the force is attractive, and the net force will be in the direction of the force between them.

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What constant acceleration (in ft/s2) is required to increase the speed of a car from 27 mi/h to 50 mi/h in 5 seconds

Answers

Answer:

6.746 ft/s^2

Explanation:

v(t)=50

v(0)=27

t=5/3600 = 1/720 hours

v(t)-v(0)= a(t-0)

50-27= a(1/720)

a= 23*720= 16560 mi/h^2

16560mi/h^2 * 5280/3600^2 (ft/s^2) =6.746 ft/s^2

The acceleration required to increase the speed of a car from 27 mi/h to 50 mi/h in 5 seconds is 6.75 ft/s².

Acceleration is given by:

\( a =  \frac{\Delta v}{\Delta t} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}} \)

Where:

\( v_{f} \): is the final speed of the car = 50 mi/h

\( v_{i}\): is the initial speed of the car = 27 mi/h

\( \Delta t\): is the change in time = 5 seconds

The constant acceleration required is:

\( a = \frac{v_{f} - v_{i}}{\Delta t} \)

\( a = \frac{50 \frac{mi}{h}*\frac{1 h}{3600 s}*\frac{5280 ft}{1 mi} - 27 \frac{mi}{h}*\frac{1 h}{3600 s}*\frac{5280 ft}{1 mi}}{5 s} \)

\( a = 6.75 ft/s^{2} \)  

Therefore, the constant acceleration required is 6.75 ft/s².

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What constant acceleration (in ft/s2) is required to increase the speed of a car from 27 mi/h to 50 mi/h

30 points!
Which statement best describes the difference between strong nuclear forces and weak nuclear forces? (2 points)
Group of answer choices

Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms' nucleus together.

Weak nuclear forces hold bonds between atoms together. Strong nuclear forces hold together the nucleus of an atom.

Strong nuclear bonds prevent atoms from falling apart. Weak nuclear bonds prevent compounds from falling apart.

Strong nuclear forces are involved in breaking electrons from their shells. Weak nuclear forces hold protons in the nucleus.

Answers

Answer:

Since strong nuclear forces involve only nuclear particles (not electrons, bonds, etc)  items 3 and 4 are eliminated.

Again item 2 refers to bonds between atoms and is eliminated.

This leaves only item 1.

Nuclear forces are very short range forces between components of the nucleus.

Weak nuclear forces are trillions of times smaller than strong forces.

Gravitational forces are much much smaller than the weak nuclear force.

Answer:

The answer is D

Explanation:

A rocket blasts off from rest and attains a speed of 33.9 m/s in 12.7 s. An astronaut has a mass of 65.1 kg. What is the astronaut's
apparent weight during takeoff?

Answers

The apparent weight of the astronaut of mass 65.1 kg moving with a speed of 33.9 m/s in 2.7 s is 811.797 N.

What is weight?

Weight is the force with which a body is attracted toward the earth or a celestial body by gravitation and which is equal to the product of the mass and the local gravitational acceleration.

To calculate the astronaut's apparent weight, we use the formula below.

Formula:

W = m{[(v-u)/t]+g}............ Equation 1

Where:

W = The apparent weight of the astronautm = Mass of the astronautv = Final speedu = Initial speedt = Timeg = Acceleration due to gravity

From the question,

Given:

m = 65.1 kgv = 33.9 m/su = 0 m/s (from rest)t = 12.7 sg = 9.8 m/s²

Substitute these values into equation 1

W = 65.1{[(33.9-0)/12.7]+9.8]W = 65.1×12.47W = 811.797 N

Hence, the apparent weight of the astronaut is 811.797 N.

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A bag of shells weighs 1.5 N. What is its mass? approximately 1.5 kilograms approximately 1.5 pounds approximately 150 grams approximately 1.5 grams​

Answers

Answer:

approximately 150 grams

Explanation:

The weight of an object is a product of its mass and acceleration of gravity acting upon it. Since weight (W) is force, it is measured in Newtons (N) or Kgms-²

W = mg

Where;

W = weight (N)

m = mass (kg)

g = acceleration due to gravity

g is a constant, which is approximately 10m/s²

Therefore, according to this question, the mass of a bag of shells that weighs 1.5N can be calculated thus:

m = W/g

m = 1.5/10

m = 0.15 kg

Converting 0.15kg to grams, we multiply by 1000 i.e 0.15 × 1000 = 150 grams.

Hence, the mass of the object is approximately 150grams.

Mass in motion is another way to say

Answers

Answer:

Momentum - Momentum is a measurement of mass in motion. Momentum is equal to the mass times the velocity of an object.

Momentum ........//:////

A train approaching a crossing changes speed from 25 m/s to 10 m/s in 240 s. How can the train’s acceleration be described?
A. The train’s acceleration is positive.
B. The train is not accelerating.
C. The train will come to rest in 6 minutes.
D. The train’s acceleration is negative.

Answers

The acceleration of the train can be described as: The train’s acceleration is negative (Option D)

How do I know the nature of the acceleration?

To describe the acceleration of the train, we shall determine the acceleration of the train. Details below:

From the question given above, the following were obtained:

Initial velocity (u) = 25 m/sFinal velocity (v) = 10 m/sTime (t) = 240 sAcceleration (a) =?

a = (v - u) / t

a = (10 - 25) / 240

a = -15 / 240

a = -0.0625 m/s²

From the above calculation, we can see that the acceleration is -0.0625 m/s²

Thus, the correct answer to the question is: The train’s acceleration is negative (Option D)

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Summarize why psychology is considered a science.

Answers

because it uses a systematic method of asking and answering problems, and it attempts to develop solution to psychological problems.

Answer:

it uses a systematic method of asking and answering problems,

Explanation:

An 82kg male and 48kg female pari figure starting team are gliding across the ice of 7.4m/s preparing for a throw jump maneuver. The male starter tosses the female starter forward with a speed of 8.6n/s. Determine the speed of the male starter immediately after the throw.​

Answers

Answer:

Explanation:

(m1 + m2)*V1 = m2*V2 + m1*Vx

Vx = ((m1 + m2)*V1 -  m2*V2) / m1

Vx = ((82 + 48)*7.4 - 48*8.6) /82 = 6.7 m/s

Put the numbers in the right box

Put the numbers in the right box

Answers

Answer: 2134

Explanation:

I just had this question on my exam

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